Answer:
Explanation:
The Octane rating is the % Octane in the grade that you are buying. In the United States, the octane rating of the cheapest gas is around 85%. In Canada, it is about 87% which in the states is the mid grade.
As soon as you take out the nozzle from its container, you have to press a large colored button to pick the octane rating. The button is so large and the writing is so limited, that you cannot miss the grade. Usually they are put together on the pump like this
87 89 91
I've given you the Canadian numbers; I'm not sure what they are in the US, but the numbers I've used are pretty close.
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution
Answer:
16 Molarity
Step-by-step:
M= mols/L
M= 8mols/.5L
M= 16 Molarity
Answer:
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.
Explanation:
Molarity of the solution is the moles of compound in 1 Liter solutions.
[tex]Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}[/tex]
Moles of NaOH = 8 moles
Volume of the solution = 0.5 L
[tex]Molarity=\frac{8 mol}{0.5 L}=16.0 M[/tex]
The molarity of a solution that contains 8 moles of NaOH in 0.5 liters of solution is 16.0 M.
Five grams of sugar is mixed with 300 mL of water. In the solution, water would be classified as the —
solute
solvent
base
saline
Answer:Five grams of sugar is mixed with 300 mL of water. In the solution, water would be classified as the —
solvent
Explanation:
It is the solvent because it can dissolve the sugar.
Solvent- able to dissolve other substances.
The sugar has been dissolved in the water, sugar has been considered as solute. The water has been dissolving sugar in itself so it has been considered as solvent.
The mixture of solute and solvent has been termed as the solution. The solute has been the molecule that has been dissolved. The solvent is the molecule that dissolves the solute.The base has been the solution in which the alkaline character has been more. More alkalinity has been contributed by the increased hydroxide ion concentration.The saline is the solution of NaCl in water. When NaCl has been dissolved in the water, the solution formed has been known as saline.Since sugar has been dissolved in the water, sugar has been considered as solute. The water has been dissolving sugar in itself so it has been considered as solvent.
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Which graph is an inverse graph?
Answer:
there are no graphs
Explanation:
Answer:
The graph has to switch into the values.
Explanation:
So if you're asked to graph a function and its inverse, all you have to do is graph the function and then switch all x and y values in each point to graph the inverse. Just look at all those values switching places from the f(x) function to its inverse g(x) (and back again), reflected over the line y = x.
How many grams are in 2.06x10-4 moles of calcium phosphate
Answer:
63.86 mg
Explanation:
Molar mass is the mass of 1 mol of compound / atom.
molar mass of the compound is - 310 g/mol
mass of 1 mol is - 310 g
therefore mass of 2.06 x 10⁻⁴ mol is - 310 g/mol x 2.06 x 10⁻⁴ mol = 0.06386 g
mass of calcium phosphate is - 63.86 mg
Final answer:
To find the mass of 2.06 x 10⁻⁴ moles of calcium phosphate (Ca₃(PO₄)₂), calculate the formula mass using atomic masses of calcium, phosphorus, and oxygen. The formula mass of calcium phosphate is 310.18 g/mol. Multiplying this by the moles gives you 0.0639 grams of calcium phosphate.
Explanation:
To calculate the mass in grams of 2.06 x 10⁻⁴ moles of calcium phosphate (Ca₃(PO₄)₂), you must know the formula mass of calcium phosphate. The empirical formula indicates the compound contains three calcium ions (Ca⁺²) and two phosphate ions (PO₄⁻³). The formula mass is calculated by adding together the atomic masses of the constituent atoms: three calcium atoms, two phosphorus atoms, and eight oxygen atoms.
The atomic masses are approximately 40.08 g/mol for calcium, 30.97 g/mol for phosphorus, and 16.00 g/mol for oxygen. Calculating the formula mass, we have:
3(Calcium) + 2(Phosphorus) + 8(Oxygen) = 3(40.08 g/mol) + 2(30.97 g/mol) + 8(16.00 g/mol) = 310.18 g/mol
Now, to find the mass of 2.06 x 10-4 moles of calcium phosphate:
2.06 x 10⁻⁴ moles x 310.18 g/mol = 0.0639 grams
Therefore, there are 0.0639 grams of calcium phosphate in 2.06 x 10⁻⁴ moles of the compound.
Before the reaction occurs, the concentration of A is 0.071M. If the concentration of A at equilibrium is 0.03195M, what is the equilibrium constant? A(g) = 2B(g) + C(g)
Answer:
Assume that the initial concentration of both B and C are zero.
Kc = 7.5 × 10⁻³.
Explanation:
What's the expression for the equilibrium constant of this reversible reaction? Note that the steps here apply only to equilibriums where all species are either gaseous (g) or in an aqueous solution (aq). Solids and liquids (water in particular) barely influence the equilibrium; in many cases they should not appear in the expression for the equilibrium constant.
Raise the concentration of each product to their coefficient's power.
The coefficient in front of B is 2. Raise the concentration of B to the second power, which will give [tex][\text{B}]^{2}[/tex]. The coefficient in front of C is 1. Raise the concentration of C to the first power, which is the same as [tex][\text{C}][/tex].The product of these terms will be the numerator in the expression of the equilibrium constant. For this reaction, the numerator shall be [tex][\text{B}]^{2} \cdot[\text{C}][/tex].
Repeat these steps for the reactants:
The coefficient in front of A is 1. Raise the concentration of A to the first power, which is the same as [tex][\text{A}][/tex].If there are more than one reactants, multiple each of those terms. The product shall be the denominator of the expression for the equilibrium constant. For this reaction, the denominator shall be [tex][\text{A}][/tex].
Hence the equilibrium constant:
[tex]\displaystyle K_c = \frac{[\text{B}\;(g)]^{2} \cdot[\text{C}\;(g)]}{[\text{A}\;(g)]}[/tex],
where [tex][\text{A}][/tex], [tex][\text{B}][/tex], and [tex][\text{C}][/tex] are concentrations when the reaction is at equilibrium.
Construct a RICE table to find the equilibrium concentration of each species. R stands for reaction, I for initial conditions, C for change in concentration, and E for equilibrium conditions. Assume that only A is initially present in the system. Let the decrease in the concentration of [tex]\text{A}[/tex] be [tex]x\;\text{M}[/tex].
[tex]\begin{array}{c|ccccc}\text{R}&\text{A}\;(g) &\rightleftharpoons &2\;\text{B}\;(g)& +& \text{C}\;(g)\\ \text{I}& 0.071 \;\text{M} & & 0\;\text{M} && 0 \;\text{M} \\ \text{C} &-x \;\text{M}&&+2x\;\text{M} & & +x\;\text{M}\\\text{E}&0.071 - x\;\text{M} && 2x\;\text{M} & &x\;\text{M} \end{array}[/tex].
The coefficient in front of B is twice that in front of A. In other words, for each unit of A consumed, two units of B are produced. Assume that volume stays the same. The decrease in the concentration of [tex]\text{A}\;(g)[/tex] is [tex]x\;\text{M}[/tex]. Accordingly, the increase in the concentration of [tex]\text{B}\;(g)[/tex] shall be [tex]2x\;\text{M}[/tex].
The question states that the equilibrium concentration of [tex]A\;(g)[/tex] is [tex]0.03195\;\text{M}[/tex].
[tex]0.071 - x = 0.03195[/tex],
[tex]x = 0.03905[/tex].
At equilibrium:
[tex][\text{A}\;(g)] = 0.03195\;\text{M}[/tex] according to the question;[tex][\text{B}\;(g)] = 2 x \;\text{M}= 0.0781\;\text{M}[/tex] as in the RICE table;[tex][\text{C}\;(g)] = x = 0.03905\;\text{M}[/tex] as in the RICE table.Hence the equilibrium constant.
[tex]\displaystyle \begin{aligned}K_c &= \frac{[\text{B}\;(g)]^{2} \cdot[\text{C}\;(g)]}{[\text{A}\;(g)]}\\&=\frac{{0.0781}^{2} \times 0.03905}{0.03195}\\&=7.5\times 10^{3}\;\text{M}\end{aligned}[/tex].
If the concentration of A at equilibrium is 0.03195M,the equilibrium constant is Kc ≈ 0.0072 (option a).
To begin solving for the equilibrium constant (Kc), we first need to determine the changes in concentrations for each species.
Step-by-Step Solution:
1. Initial and equilibrium concentrations:
Initial concentration of A ([A]i) = 0.071 MEquilibrium concentration of A ([A]eq) = 0.03195 M
2. Change in concentration for A:
Change in [A] = 0.071 M - 0.03195 M = 0.03905 M
Since the reaction stoichiometry is 1A → 2B + 1C, the change in concentration will also affect B and C:
Change in [B] = 2 × 0.03905 M = 0.0781 MChange in [C] = 0.03905 M
3. Equilibrium concentrations:
Equilibrium concentration of A, [A]eq = 0.03195 MEquilibrium concentration of B, [B]eq = 0.0781 MEquilibrium concentration of C, [C]eq = 0.03905 M
4. Equilibrium constant expression:
The equilibrium constant expression for the reaction A(g) = 2B(g) + C(g) is:
Kc = [B]² [C] / [A]
5. Substituting the equilibrium concentrations:
Kc = (0.0781)² × 0.03905 / 0.03195
6. Calculating Kc:
Kc ≈ 0.0072
Therefore, the equilibrium constant for the reaction is approximately 0.0072.
Complete Question - Before the reaction occurs, the concentration of A is 0.071 M. If the concentration of A at equilibrium is 0.03195 M, what is the equilibrium constant? A(g) = 2B(g) + C(g) Select the correct answer below:
a. Kc - 0.0072
b. Kc - 0.095
c. Kc - 14
d. Kc - 130
For Part 1, describe the changes in the colors of the well, if any, as you go from well 1 to well 9—that is, as you go from the well with the least copper(II) nitrate to the well with the most copper(II) nitrate. Which wells had the most distinct precipitate?
For Part 2, describe the changes in the colors of the well, if any, as you go from well 1 to well 9—that is, as you go from the well with the least iron(II) sulfate to the well with the most iron(II) sulfate. Which wells had the most distinct precipitate?
For Part 3, describe the changes in the colors of the well, if any, as you go from well 1 to well 9—that is, as you go from the well with the least iron(III) nitrate to the well with the most iron(III) nitrate. Which wells had the most distinct precipitate?
Answer:
Nitrate is a polyatomic ion with the molecular formula NO⁻₃ and a molecular mass of 62.0049 u. Organic compounds that contain the nitrate ester as a functional group are also called nitrates.
The color of the precipitate intensifies on moving from well 1 to well 9, as there has been an increased concentration of reactant and thereby the product.
The reaction of part 1 has been the reaction of copper nitrate with NaOH resulting in the formation of a precipitate of copper hydroxide. The precipitate has a blue color.Thus, for the copper hydroxide moving from well 1 to well 9, the blue color intensifies.
The reaction of part 2 has been the formation of iron hydroxide with the reaction of iron sulfate with NaOH. The color of the precipitate has been dark green.Thus, for the iron hydroxide moving from well 1 to well 9, the blue color intensifies.
The reaction for part 3 has been the formation of ferric hydroxide, with the reaction of Iron (III) nitrate with NaOH. The color of the precipitate has been red-orange.Thus, for the ferric hydroxide moving from well 1 to well 9, the red-orange color intensifies.
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B. For the following questions, use the reaction NO2(g) N2(g) + O2(g), with ΔH = –33.1 kJ/mol and ΔS= 63.02 J/(mol·K).
i. Draw a possible potential energy diagram of the reaction. Label the enthalpy of the reaction.
ii. Is the reaction endothermic or exothermic? Explain your answer. (2 points)
iii. What is the Gibbs free energy of the reaction at 25°C?
iv. Is the reaction spontaneous or nonspontaneous at 25°C? Explain your answer.
Answer:
I. Kindly, see the attached image.
II. The reaction is exothermic.
III. - 51.88 kJ/mol.
IV. The reaction is spontaneous.
Explanation:
I. Draw a possible potential energy diagram of the reaction. Label the enthalpy of the reaction.
Since the sign of ΔH is negative, the reaction is exothermic reaction.In an exothermic reaction, the energy of the reactants is higher than that of the products.
Kindly see the attached image to show you the potential energy diagram of the reaction.
II. Is the reaction endothermic or exothermic? Explain your answer.
The reaction is exothermic reaction.The sign of ΔH indicates wither the reaction is endothermic or exothermic one:If the sign is positive, the reaction is endothermic.
If the sign is negative, the reaction is exothermic.
Herein, ΔH = - 33.1 kJ/mol, so the reaction is exothermic.
III. What is the Gibbs free energy of the reaction at 25°C?
∵ ΔG = ΔH - TΔS.
Where, ΔG is the Gibbs free energy change (J/mol).
ΔH is the enthalpy change (ΔH = - 33.1 kJ/mol).
T is the temperature (T = 25°C + 273 = 298 K).
ΔS is the entorpy change (ΔS = 63.02 J/mol.K = 0.06302 J/mol.K).
∴ ΔG = ΔH - TΔS = (- 33.1 kJ/mol) - (298 K)(0.06302 J/mol.K) = - 51.88 kJ/mol.
IV. Is the reaction spontaneous or nonspontaneous at 25°C?
The sign of ΔG indicates the spontaneity of the reaction:
If ΔG < 0, the reaction is spontaneous.
If ΔG = 0, the reaction is at equilibrium.
If ΔG > 0, the reaction is nonspontaneous.
Herein, ΔG = - 51.88 kJ/mol, so the reaction is spontaneous.
The reaction NO2(g) → N2(g) + O2(g) is exothermic as indicated by the negative ΔH. The Gibbs free energy (ΔG) at 25°C is calculated to be -51.9996 kJ/mol, which signifies that the reaction is spontaneous at this temperature.
Explanation:Understanding Chemical Reactions and ThermodynamicsFor the reaction NO2(g) → N2(g) + O2(g), with ΔH = –33.1 kJ/mol and ΔS = 63.02 J/(mol·K):
Potential energy diagram: Since this is a text-based response, we can describe the diagram. At the beginning we have the reactants at a higher potential energy level; then there's a peak representing the activation energy. Following this peak, the products are at a lower potential energy level by 33.1 kJ/mol, illustrating an exothermic reaction.Endothermic or exothermic: The reaction is exothermic since the enthalpy change (ΔH) is negative, indicating that energy is released.Gibbs free energy at 25°C: ΔG can be calculated using the equation ΔG = ΔH - TΔS. Plugging in the values we get ΔG = (-33.1 kJ/mol) - (298 K)(63.02 J/mol·K × 1 kJ/1000 J) = -33.1 kJ/mol - 18.8996 kJ/mol = -51.9996 kJ/mol.Spontaneity at 25°C: The reaction is spontaneous at 25°C since ΔG is negative, which implies that the reaction can occur without external energy input.Learn more about Exothermic Reactions here:https://brainly.com/question/10373907
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A substance has a high melting point and conducts electricity in the liquid phase The is substance is
Answer:
oxygen
Explanation:
?
Balance the following reaction. If a coefficient of "1" is required, choose "blank" for that box. C4H8 + Br2 → C4H8Br2
Please help fast
Answer:
C₄H₈ + Br₂ → C₄H₈Br₂
Explanation:
To balance a chemical equation, you need to ensure that the number of each element in the reactant side, matches the number of each element on the product side.
Reactants Product
C₄H₈ + Br₂ → C₄H₈Br₂
C = 4 C= 4
H = 8 H= 8
Br = 2 Br = 2
Since they match up on both sides, the chemical equation is balanced, so we keep it as is.
Answer:
blank for all
Explanation:
why blood capillary walls differ from veins and arteries
Answer: Capillary walls main function is to exchange materials between the blood and tissue cells, While Arteries carry blood away from the heart to parts of your body like your lungs for instance, and your Veins carry blood back to your heart.
I hope this helps :)
Explanation:
Determine the original amount of Ba-142 after 1.25 hours if 9.25 mg remains. The half-life of Ba-142 is 10.6 minutes.
Answer:
1246 mg = 1.246 g.
Explanation:
The decay of radioactive elements obeys first-order kinetics.For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).Where, k is the rate constant of the reaction.
t1/2 is the half-life time of the reaction (t1/2 = 10.6 minutes).
∴ k = ln2/(t1/2) = 0.693/10.6 = 6.54 x 10⁻² min⁻¹.
For first-order reaction: kt = lna/(a-x).
where, k is the rate constant of the reaction (k = 6.54 x 10⁻² min⁻¹.).
t is the time of the reaction (t = 1.25 hr x 60 = 75.0 min).
a is the initial concentration (original amount) (a = ??? mg).
(a-x) is the remaining concentration (a-x = 9.25 mg).
∴ kt = lna/(a-x)
(6.54 x 10⁻² min⁻¹)(75.0 min) = ln a/(9.25 mg)
4.903 = ln a/(9.25 mg)
Taking e for the both sides:
134.7 = a/(9.25 mg)
∴ a = (134.7)(9.25 mg) = 1246 mg = 1.246 g.
how long does the venus flytrap process take once it has its prey
After trapping its prey, the plant turns into a external stomach, sealing the trap so no air gets in or out. The digestion takes several days depending the size of the insect, and then the leaf re-opens.
If a student mixes 75 mL of 1.30 M HNO3 and 150 mL of 6.5 M NaOH. is the final solution acidic, basic, or neutral
Answer:
The solution is basic.
Explanation:
We can determine the nature of the solution via determining which has the large no. of millimoles (acid or base):
If no. of millimoles of acid > that of base; the solution is acidic.If no. of millimoles of acid = that of base; the solution is neutral.If no. of millimoles of acid < that of base; the solution is basic.We need to calculate the no. of millimoles of acid and base:no. of millimoles of acid (HNO₃) = MV = (1.3 M)(75.0 mL) = 97.5 mmol.
no. of millimoles of base (NaOH) = MV = (6.5 M)(150.0 mL) = 975.0 mmol.
∴ The no. of millimoles of base (NaOH) is larger by 10 times than the acid (HNO₃).
So, the solution is: basic.
Given the density of Au is 19.3 g/cm3. Determine the mass of gold in an ingot with the dimension of 10.0 cm x 4.00cm x 3.00cm.
Answer:
2.317 kg
Explanation:
Density = mass / vol
Vol = 10 x4 x 3 =120
Density=19.3 gm/cm3
Mass= density x vol =2316 gm or 2.317 kg
Answer: The mass of gold is 2316 grams.
Explanation:
To calculate the volume of cuboid, we use the equation:
[tex]V=lbh[/tex]
where,
V = volume of cuboid
l = length of cuboid = 10 cm
b = breadth of cuboid = 4 cm
h = height of cuboid = 3 cm
Putting values in above equation, we get:
[tex]V=10\times 4\times 3=120cm^3[/tex]
To calculate mass of a substance, we use the equation:
[tex]Density=\frac{Mass}{Volume}[/tex]
Putting values in above equation, we get:
[tex]19.3g/cm^3=\frac{\text{Mass of Gold}}{120cm^3}\\\\\text{Mass of osmium}=2316g[/tex]
Hence, the mass of gold is 2316 grams.
Which of the following is not equal to 0.1 centimeters?
0.000001 kilometers (km)
0.001 meters (m)
10 millimeters (mm)
1000 micrometers (µm)
Answer:
c) 10 millimeters (mm)
Explanation:
The unit conversions are as follows:
1 cm = 10 mm (millimeter)
1 cm = 0.01 m (meter)
1 cm = 0.00001 km (kilometer)
1 cm = 10000 μm (micrometer)
Based on the above conversions:
[tex]0.1 cm = \frac{10 mm*0.1 cm}{1 cm} = 0.1 mm[/tex]
[tex]0.1 cm = \frac{0.01 m*0.1 cm}{1 cm} = 0.001 m[/tex]
[tex]0.1 cm = \frac{0.00001 km * 0.1 cm}{1 cm} = 0.000001 km[/tex]
[tex]0.1 cm = \frac{10000 um*0.1cm}{1 cm} =1000 um[/tex]
Therefore, 0.1 cm = 10 mm is incorrect instead it is 0.1 mm
Answer:
Explanation:
the Americans maintained their control of Bunker Hill.
the British army sustained heavy casualties.
the Americans forced British soldiers to retreat to Boston.
the British army was forced to use most of its ammunition.The Battle of Bunker Hill in 1775 was considered a victory for the Continental army because
the Americans maintained their control of Bunker Hill.
the British army sustained heavy casualties.
the Americans forced British soldiers to retreat to Boston.
the British army was forced to use most of its ammunition.The Battle of Bunker Hill in 1775 was considered a victory for the Continental army because
What is the molar mass of aluminum chlorate, Al(ClO3)3?
The molar mass of Aluminium Chlorate is 277.3351
The molar mass of Aluminium Chlorate is 277.3351.
What is meant by Molar Mass?The molar mass (symbol M, SI unit kg·mol−1) is defined as the mass per unit amount of substance of a given chemical entity. In keeping with the definition of the mole, the chemical entity in question should always be specified.The molar mass of Aluminium Chlorate is 277.3351.
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A chemical equation that is balanced will help you to determine the.......
Answer:
A chemical equation that is balanced will help you to determine how much product they will produce from their reactants.
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Have a great day !
5INGH
Explanation:
A sample of argon has a volume of 6.0 cm 3 and the pressure is 0.87 atm. If the final temperature is 35 degrees celsius, the final volume is 10 cm 3 and the final pressure is 0.52 atm, what was the initial temperature of the argon
Answer:
= 36.185 °C
Explanation:
Using the combined gas law;
P1V1/T1 = P2V2/T2
In this case;
P1 = 0.87 atm
V1 = 6.0 cm³
T1 = ?
P2 = 0.52 atm
V2 = 10 cm³
T2 = 35 °C + 273 = 308 K
Therefore;
T1 = P1V1T2/P2V2
= ( 0.87 × 6.0 × 308)/( 0.52 ×10)
= 309.185 K
Therefore; Initial temperature = 309.185 K - 273 = 36.185 °C
0.5 moles of sodium chloride is dissolved to make 0.05 liters of solution
Answer:
= 10 M or 10 moles/liter
Explanation:
Molarity is calculated by the formula;
Molarity = Moles/volume in liters
In this case;
The number of moles = 0.5 moles
Volume = 0.05 liters
Therefore;
Molarity = 0.5 moles/0.05 liters
= 10 M or 10 moles/liter
Thus the molarity is 10 M or 10 moles/liter
Final answer:
To calculate the molarity, divide the number of moles of sodium chloride (0.5 moles) by the volume of the solution in liters (0.05 liters), resulting in a molarity of 10 M for the NaCl solution.
Explanation:
The question relates to the concept of molarity, which is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per liter of solution. The student's question involves calculating the molarity given a certain amount of solute (sodium chloride, NaCl) and the volume of the resulting solution. To calculate molarity, you would divide the number of moles by the volume in liters. In the case of the student's question, if 0.5 moles of NaCl are dissolved to make 0.05 liters of solution, the calculation would be:
Molarity = moles of solute / liters of solution
Molarity = 0.5 moles / 0.05 liters
Molarity = 10 M (molar)
This result indicates a 10 M NaCl solution, which signifies a highly concentrated solution.
what is the percentage of water in hydrated calcium chloride
Answer:
24.5%
Explanation:
You just add up the atomic masses.
Ca - 40.078
Cl2 - 35.4527 x 2 = 70.9054
------ 110.9834
H4 - 1.00794 x 4 = 4.03176
O2 - 31.9998
------ 36.03056
TOTAL - 147.01396
So the water is 36.03056/147.01396 = .245082576 but that is only accurate to three decimals (because the mass of Ca was only given to three decimals) so we write .245 and that is 24.5%
This is not my answer but I found it on Yahoo answers and it was answered by Anonymous.
Answer: 24.5%
Explanation: Molar mass of CaCl2 * 2 H2O = 40.078 + ( 2 x 35.453) + ( 2 x 18.02)=147.024 g/mol
% H2O = 2 x 18.02 x 100/ 147.024 =24.5
Calculate the pH of a solution with [OH−]=1.3×10−2M. (Hint: Begin by using Kw to find [H3O+].)
Answer:
12.11.
Explanation:
∵ pOH = - log[OH⁻]
∴ pOH = - log(1.3 x 10⁻²) = 1.886.
∵ pH + pOH = 14.
∴ pH = 14 - pOH = 14 - 1.886 = 12.11.
If the half life for the radioactive decay of zirconium 84 is 26 minutes and i start with a 175 gram sample, how much will be left over after 104 minutes? show work or explain your answer.
After 104 minutes, or 4 half-lives, of the radioactive isotope zirconium 84 with a half-life of 26 minutes, the remaining quantity from an initial 175-gram sample would be 10.9375 grams.
Explanation:The question concerns the calculation of the amount of a radioactive substance remaining after a certain period, based on its half-life. In this case, we are looking at zirconium 84, which has a half-life of 26 minutes. To calculate how much of the substance remains after 104 minutes, we need to determine how many half-lives have passed in that time frame. Since 104 minutes is 4 times 26 minutes, that's 4 half-lives.
The amount of substance remaining after each half-life is reduced by 50%. Therefore, after one half-life, we will have 50% of the initial amount, after two half-lives, 25%, and so on. Applying this knowledge:
After 1st half-life (26 minutes): 175g / 2 = 87.5gAfter 2nd half-life (52 minutes): 87.5g / 2 = 43.75gAfter 3rd half-life (78 minutes): 43.75g / 2 = 21.875gAfter 4th half-life (104 minutes): 21.875g / 2 = 10.9375 gramsSo after 104 minutes, there would be 10.9375 grams of zirconium 84 remaining.
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Calculate the mole fraction of each component in a solution with 6.87 g of sodium chloride (NaCl) dissolved in 65.2 g of water. Work must be shown in order to earn credit.
Answer:
mole fraction of NaCl = 0.03145.
mole fraction of water = 0.9686.
Explanation:
Mole fraction is an expression of the concentration of a solution or mixture.It is equal to the moles of one component divided by the total moles in the solution or mixture. The summation of mole fraction of all mixture components = 1.mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles).
no. of moles of NaCl = mass/molar mass = (6.87 g)/(58.44 g/mol) = 0.1176 mol.
no. of moles of water = mass/molar mass = (65.2 g)/(18.0 g/mol) = 3.622 mol.
∴ mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles) = (0.1176 mol)/(0.1176 mol + 3.622 mol) = 0.03145.
∵ mole fraction of NaCl + mole fraction of water = 1.0.
∴ mole fraction of water = 1.0 - mole fraction of NaCl = 1.0 - 0.03145 = 0.9686.
when 45 grams of copper (ii) carbonate are decomposed with heat how many grams of carbon dioxide will be produced
Answer:
16.02 g
Explanation:
the balanced equation for the decomposition of CuCO₃ is as follows
CuCO₃ --> CuO + CO₂
molar ratio of CuCO₃ to CO₂ is 1:1
number of CuCO₃ moles decomposed - 45 g / 123.5 g/mol = 0.364 mol
according to the molar ratio
1 mol of CuCO₃ decomposes to form 1 mol of CO₂
therefore 0.364 mol of CuCO₃ decomposes to form 0.364 mol of CO₂
number of CO₂ moles produced - 0.364 mol
therefore mass of CO₂ produced - 0.364 mol x 44 g/mol = 16.02 g
16.02 g of CO₂ produced
Which climate is most likely found in a high pressure belt
The climate most likely found in a high-pressure belt is a dry climate. An example of a high-pressure belt with a dry climate is the subtropical high-pressure belt.
Explanation:The climate most likely found in a high-pressure belt is a dry climate.
High-pressure systems are associated with sinking air, which inhibits the formation of clouds and precipitation. These areas tend to have clear skies and little moisture, resulting in dry conditions.
An example of a high-pressure belt with a dry climate is the subtropical high-pressure belt found around 30 degrees latitude in both the Northern and Southern Hemispheres, such as the Sahara Desert or the Mojave Desert.
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1.806*10^24 atoms of carbon is how many moles of carbon
The answer should be 3 moles of Carbon.
To convert the number of atoms of carbon to moles, divide the given number of atoms by Avogadro's number, which is 6.022 × 10^23 particles per mole. In this case, there are approximately 3 moles of carbon.
Explanation:To find the number of moles of carbon from the given number of atoms, we can use Avogadro's number. Avogadro's number is defined as 6.022 × 1023 particles per mole.
So, to convert the number of atoms of carbon to moles, we divide the given number of atoms by Avogadro's number:
Number of moles of carbon = (Number of atoms of carbon) / (Avogadro's number)
Plugging in the given values, we have:
Number of moles of carbon = (1.806 × 1024 atoms of carbon) / (6.022 × 1023 atoms/mol) ≈ 3 moles of carbon
when a substance donates a proton during a chemical reaction, that substance can be classified as a(an) ___ ?
Answer:
An acid
Explanation:
According to the Arrhenius theory of acids and bases "an Arrhenius acid is a compound that increases the concentration of H+ ions that are present when added to water"
which of the following is not a possible energy conversion for electricity?
a. mechanical
b. chemical
c. biological
d. thermal
please help me
A is the correct answer
Electrical energy may be produced from chemical energy. Heat energy may be produced from thermal energy. Electrical energy, potential energy, etc. can be created from mechanical energy. Mechanical energy is not a possible energy conversion for electricity
What is mechanical energy ?Potential energy plus kinetic energy are combined to form mechanical energy. According to the concept of mechanical energy conservation, mechanical energy remains constant in an isolated system when only conservative forces are acting on it.
If an object is moving or in a certain position in relation to the surface, it has mechanical energy.
A box placed vertically above the ground, for instance, will only contain potential energy. A moving object has mechanical energy, often known as kinetic energy, because of its motion.
Thus, option A is correct.
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What happens to the matter (bodies) of organisms after they die?
Answer:
they start to decompose
Explanation:
the easiest way to wxplain this is that all organic matter decomposees and turns into nutrients for other organisms, its a cycle. but after an organism dies then it starts to decompose and rot.
Answer:
they begin to rot
Explanation:
what did earth look like before life began
Answer:
Like a jungle with trees everywhere
Hope This Helps! Have A Nice Day!!
I would suggest reading Genesis chapter 1 to 2. It'll explain it all.