Starting from rest, a solid sphere rolls without slipping down an incline plane. at the bottom of the incline, what does the angular velocity of the sphere depend upon? check all that apply. check all that apply. the angular velocity depends upon the length of the incline. the angular velocity depends upon the mass of the sphere. the angular velocity depends upon the radius of the sphere. the angular velocity depends upon the height of the incline
A solid spherical rolls down an inclined plane from rest without slipping. The radius of the sphere affects the angular velocity.
What do you mean by angular velocity?
Angular velocity is the speed at which an object rotates or revolves around an axis or alters the angle between two bodies.
The angle between a line on one body and a line on the other in the illustration serves as a representation of this displacement.
The length of the inclination affects the angular velocity. The mass of the sphere affects the angular velocity.
Thus, A solid spherical rolls down an inclined plane from rest without slipping. The radius of the sphere affects the angular velocity.
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Final answer:
The angular velocity of a solid sphere rolling without slipping down an incline depends on the sphere's radius and the incline's height, but not on the sphere's mass or the length of the incline.
Explanation:
When a solid sphere rolls without slipping down an incline, its angular velocity at the bottom depends on several factors. These factors include the radius of the sphere, the height of the incline, but not directly upon the mass of the sphere or the length of the incline (assuming it is long enough for the sphere to reach its maximum velocity due to gravity). The height of the incline determines the potential energy at the start, which converts into kinetic energy at the bottom. From the kinetic energy, we can find the linear velocity, and consequently the angular velocity, which is inversely proportional to the radius of the sphere.
The mass of the sphere does not directly affect angular velocity because both gravitational potential energy and rotational kinetic energy depend on mass in a way that it cancels out when calculating velocity. Similarly, the specific length of the incline does not determine the angular velocity at the bottom; rather, it is the vertical height that dictates the potential energy available for conversion to kinetic energy.
How to determine the resultant velocity from horizontal and vertical velocity?
ASAP PLEASE HELP , Ill give you what you want
A rightward-moving truck skids to a stop from a very high speed with its wheels locked. What are the forces applied?
Force due to gravity
normal force
magnetic force
air resistance
force of friction
tension
spring force
applied forces
A computer is reading data from a rotating cd-rom. at a point that is 0.040 m from the center of the disc, the centripetal acceleration is 114 m/s2. what is the centripetal acceleration at a point that is 0.058 m from the center of the disc?
Final answer:
The centripetal acceleration at a point that is 0.058 m from the center of the disc is approximately 78.78 m/s^2.
Explanation:
To calculate the centripetal acceleration at a point that is 0.058 m from the center of the disc, we can use the formula for centripetal acceleration:
ac = (v^2) / r
Where ac is the centripetal acceleration, v is the velocity, and r is the distance from the center of the disc.
Given that the centripetal acceleration at a point 0.040 m from the center is 114 m/s^2, we can substitute the values into the formula:
114 = (v^2) / 0.040
Solving for v^2:
v^2 = 114 * 0.040
v^2 = 4.56
Taking the square root of both sides to find the velocity:
v ~ 2.14 m/s
Now we can calculate the centripetal acceleration at a point 0.058 m from the center:
ac = (v^2) / 0.058
ac = (2.14^2) / 0.058
ac ~ 78.78 m/s^2
Many automobile passengers have suffered neck injuries when struck by cars from behind.How does Newton's law of inertia apply here
_____________ is increasing the temperatures of Earth’s oceans and atmosphere, leading to more intense storms of all types, including hurricanes. Nutrient depletion Urbanization Desertification Global Warming
What forces below earth's surface shape landforms?
A boy throws a ball up into the air with a speed of 8.2 m/s. the ball has a mass of 0.3 kg. How much gravitational potential energy will the ball have at the top of its flight?
Answer:
Gravitational potential energy, PE = 10.08 J
Explanation:
It is given that,
Speed with which the ball is thrown, v = 8.2 m/s
Mass of the ball, m = 0.3 kg
We need to find the gravitational potential energy of the ball when it is at the top of flight. The ball is thrown up into the air.
As per law of conservation of energy, the kinetic energy at the top is converted to gravitational potential energy as :
[tex]PE=KE=\dfrac{1}{2}mv^2[/tex]
[tex]PE=\dfrac{1}{2}\times 0.3\times 8.2^2[/tex]
PE = 10.08 J
So, the gravitational potential energy at the top of the flight is 10.08 Joules. Hence, this is the required solution.
The total power input to a pumped storage power station is 600 MW
The useful power output is 540 MW calculate the efficiency of this pumped storage power station
The efficiency of this pumped storage power station will be "90%".
The given values are:
Total Input power,
I = 600 MWOutput power,
O = 540 MWAs we know the formula,
→ [tex]Efficiency = \frac{O}{I}\times 100[/tex]
By substituting the values, we get
→ [tex]= \frac{540}{600}\times 100[/tex]
→ [tex]= \frac{540}{6}[/tex]
→ [tex]= 90[/tex] (%)
Thus the above answer is appropriate.
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Newton's law of motion states that an net force acting of an object causes the object to accelerate in the
What is the wavelength of radiation with a frequency of 1.50x10^13 hz?
We have that for the Question "What is the wavelength of radiation with a frequency of 1.50x10^13 hz? " it can be said that the wavelength of radiation with a frequency of 1.50x10^13 hz
[tex]\lambda=2*10^{-5}m[/tex]
From the question we are told
What is the wavelength of radiation with a frequency of 1.50x10^13 hz?
Generally the equation for the wavelength is mathematically given as
[tex]\lambda=\frac{V}{f}\\\\\lambda=\frac{3*10^8}{1.50x10^{13} }\\\\\lambda=2*10^{-5}[/tex]
Therefore
the wavelength of radiation with a frequency of 1.50x10^13 hz
[tex]\lambda=2*10^{-5}m[/tex]
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Suppose you made some beef soup. you want to separate the extra fat from the soup before you eat it. how could you do that?
To remove the extra fat from beef soup, allow the soup to cool so that the fat solidifies and rises to the top. Then, use a spoon or ladle to skim off the fat.
Explanation:To separate the extra fat from the beef soup, you can use a simple method based on the principle of density. Fat is less dense than water, which causes it to float on the surface of the soup. Here are the steps you can follow:
Cool the soup: After cooking the soup, allow it to cool. As it cools, the fat will begin to solidify and rise to the top.Skim off the fat: Once the fat has risen to the top, you can remove it with a spoon or a ladle. Be careful not to remove too much of the soup along with the fat.If you want a more thorough fat removal, you can also place the cooled soup in the refrigerator. The fat will harden and can then be easily removed. This fat removal process ensures a healthier and lighter soup.
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A 1.0-kilogram ball is dropped from the roof of a building 40. meters tall. What is the approximate time of fall? [Neglect air resistance.]
Lincoln weighs 400 newtons. What’s his mass rounded to the nearest kilogram? Assume that acceleration due to gravity is 9.8 N/kg.
The mass of Lincoln to the nearest kilogram, if he has a weight 400 N is 41 kg.
What is mass?Mass can be defined as the quantity of matter a body contains.
To calculate Lincoln's mass, we use the formula below.
Formula:
m = W/g........... Equation 1Wher:
m = Licoln's massW = Lincoln's Weightg = Acceleration due to gravityFrom the question,
Given:
W = 400 Ng = 9.8 m/sSubstitute these values into equation 1
m = 400/9.8m = 40.82 kgm ≈ 41 kg to the nearest kilogram.Hence, the mass of Lincoln is 41 kg.
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Answer:
The mass of Lincoln to the nearest kilogram, if he has a weight 400 N is 41 kg.
Explanation:
plato
What does the statement what does the statement 10 m/s to the north describe
Answer:
10 m/s to the north shows the velocity of an object.
Explanation:
The statement ''10 m/s to the north'' shows the velocity of an object. We know that velocity is a vector quantity and speed is scalar.
In the given statement 10 m/s shows the speed of an object while north shows the direction of motion. We can say that,
Speed + direction = velocity
Hence, the given statement shows the velocity of an object.
You are driving along a straight path with 100km/h for 46 minutes. How far do you get?
To find the distance traveled at 100 km/h for 46 minutes, convert the time to hours (46/60 hours), then multiply by the speed (100 km/h) to get approximately 76.67 kilometers.
To calculate how far you get when driving along a straight path at 100 kilometers per hour for 46 minutes, first, we need to convert the minutes into hours because speed is in kilometers per hour (km/h).
Convert 46 minutes to hours:
There are 60 minutes in an hour, so 46 minutes would be
46 minutes = 46 / 60 = 0.7667 hours (approximately).
Use the formula for distance:
Distance = speed X time.
Plug in the values and calculate the distance:
Distance = 100 km/h X 0.7667 hours
Distance = 76.67 kilometers.
Therefore, you would travel approximately 76.67 kilometers in 46 minutes if you maintain a constant speed of 100 km/h.
Select the statement that best describes how the forces relate. (2 points)
Select one:
a. All forces begin equally and become varied. The object on which they are acting and the distance to that object determines the amount of force.
b. Weak nuclear and magnetic forces are different because magnetic forces are associated with unmoving charges, and weak nuclear forces are associated with moving charges.
c. All forces are related to the mass of the object on which they are acting. The larger the mass, the weaker the forces become.
d. Magnetic and electrical forces are similar because they are both related to the interactions between charged particles.
Help physics! 1. Was the object at rest during the time interval labeled "B"?
Yes
No
2. Was the object accelerating during the time interval labeled "B"?
Yes
No
Answer:
Q1: No
Q2: No
Explanation:
the slope of velocity time graph gives the value of acceleration.
In section B
the graph is parallel to X axis, it means it is moving with constant velocity. Here the slope of graph in section B is zero.
Q1: Object is moving with constant velocity
Q2: The acceleration is zero
A force has a magnitude of 575 newtons and points at an angle of 36.0 degrees below the positive x axis. What are the x scalar component and the y scalar component of the vector?
The magnitude of force F in x and y direction are 465.18 N adn 338 N respectively.
What is force ?
The ability to change shape, position, direction of a abject by an external mean is known as force in other words the push and pull of a body is also known as Force. It is a vector quantity and having unit in Newtons.
Here it is given that magnitude of force is 575 N and making an angle of 36 degree with x axis in counterclockwise direction as shown in figure below :
Now resolving Force F in x and y direction that is x component of F will be [tex]Fcos \theta[/tex] and y component will be [tex]Fsin \theta[/tex].
Now there magnitude will be :
[tex]\begin{aligned}Fcos\theta&= 575cos36^{o}=465.18 \text{\:N} \\ Fsin\theta&= 575sin36^{o}=465.18\approx 338\text{\:N}\end{aligned}[/tex]
It should be noted that [tex]Fsin \theta[/tex] is acting in negative y direction.
Therefore, the magnitude of force F in x and y direction are 465.18 N and 338 N respectively.
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A speck of dust on a spinning dvd has a centripetal accelera- tion of 20 m/s2.
a. what is the acceleration of a different speck of dust that is twice as far from the center of the disk?
b. what would be the acceleration of the first speck of dust if the disk's angular velocity was doubled?
Suppose astronomers built a 150-meter telescope. how much greater would its light-collecting area be than that of the 10-meter keck telescope?
The light-collecting area of a 150-meter telescope would be 225 times greater than that of a 10-meter Keck telescope.
Explanation:In order to calculate the difference in light-collecting area between a 150-meter telescope and a 10-meter Keck telescope, we need to compare the areas of their mirrors. The area of a circle is determined by the square of its diameter. The Keck telescope has a mirror diameter of 10 meters, so its area is 100 square meters. The 150-meter telescope, on the other hand, would have an area of 22,500 square meters. Therefore, the light-collecting area of the 150-meter telescope would be 225 times greater than that of the 10-meter Keck telescope.
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The light-collecting area of a telescope is directly proportional to the square of its diameter. To compare the light-collecting areas of two telescopes, we need to calculate the ratio of their areas.
Explanation:The light-collecting area of a telescope is directly proportional to the square of its diameter. To compare the light-collecting areas of two telescopes, we need to calculate the ratio of their areas. The area of a circular telescope is given by the formula A = πr², where r is the radius (which is half the diameter). So, for the 10-meter Keck telescope, the radius would be 5 meters, and its area would be A=π × (5)² m². For the 150-meter telescope, the radius would be 75 meters, and its area would be A=π × (75)² m². To find how much greater the light-collecting area of the 150-meter telescope is, we need to calculate the ratio A150/A10.
When an objects mass increases its gravitational pull ____ a.decreases b.increases c. Stays the same
As the mass of an object increases, its gravitational pull increases.
What is gravitational force?The gravitational force is the attractive force that one body applies on the other by virtue of its mass. For two objects of mass (M) and (m) separated by a distance (r) apart, the gravitational force of attraction exerted by mass(M) on the other mass (m) is -
F[G] = GMm/r²
Given is that an object whose mass is increased.
Suppose that the mass of the object is (m) and after increasing its mass becomes (M) such that M > m.
Now,
M > m
Multiplying both sides by -
Gm[t]/r² ( m[t] is the test mass placed at a distance r away]
We get -
Gm[t]/r² × M > Gm[t]/r² × m
Gravitational force by Mass (M) > Gravitational pull by mass (m)
Therefore, as the mass of an object increases, its gravitational pull increases.
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Who was the man that proposed the uncertainty principle
Final answer:
The uncertainty principle, a fundamental concept in quantum mechanics, was proposed by German physicist Werner Heisenberg, who was awarded the Nobel Prize in Physics in 1932.
Explanation:
The man who proposed the uncertainty principle was the German physicist Werner Heisenberg. Not only is Heisenberg renowned for his uncertainty principle, but he also received the Nobel Prize in Physics in 1932 for his fundamental contributions to quantum mechanics. The uncertainty principle is a fundamental concept in quantum mechanics which states that there is a limit to how precisely we can know both the position and momentum of a particle at the same time. This principle has further implications in variables such as energy and time, dictating that the product of uncertainties in these quantities is also subject to a minimum value determined by Planck's constant. The principle suggests that at a fundamental level, nature does not allow for the precise determination of certain pairs of physical properties simultaneously. While this principle may not be evident in everyday experiences due to the small scale of Planck's constant, it is essential for understanding the behavior of particles at the quantum level.
A rock at rest has weight 138 n. what is the weight of the rock when it is accelerating downward at 3.5 m/s2?
The weight of the rock when it is accelerating downward at 3.5 m/s² can be calculated using the formula Weight = Mass * Acceleration due to gravity.
Explanation:The weight of an object is equal to its mass multiplied by the acceleration due to gravity. In this case, the weight of the rock when it is at rest is 138 N. Since the rock is accelerating downward at 3.5 m/s², the weight can be calculated using the formula:
Weight = Mass × Acceleration due to gravity
Let's assume the mass of the rock is 'm'. The acceleration due to gravity is approximately 9.8 m/s² on Earth. So, when the rock is accelerating downward at 3.5 m/s², its weight can be calculated as:
Weight = m × 3.5 m/s²
In at least 150 words, discuss how Chang's use of personification, metaphor, or connotation express one his themes in "Garden of My Childhood." Use details from the poem to support your response.
Answer:
Poet Kuangchi Chang did not remain in China long enough to be "re-educated." Following the Communist takeover he fled to the United States. His poem "Garden of My Childhood" describes China before the revolution as a peaceful, idyllic garden with a violent horde rapidly approaching. A vine, the wind, and the sea are each personified, and each beckons for him to run. It is not until "eons later," when he is "worlds away," that his "running is all done," and he finds himself at his destination: another garden, just like the one he had left behind.
Assume that the moon is hit by about 25 million micrometeorite impacts each day, and that these impacts strike randomly around the moon's surface. also assume that after a footprint is hit by 20 micrometeorites it is erased. (a) roughly (order of magnitude) how long do we expect it would take, in years, for one of the footprints left by the apollo astronauts to be completely erased?
The time required for the footprint left by the Apollo astronaut to be erased is [tex]\fbox{\begin\\1010\,{\text{million}}\,{\text{yr}}\end{minispace}}[/tex].
Further explanation:
Some astronauts went to the moon to know about the moon. They walk on the surface of moon that’s why their footprints left there. It took time to erase the footprints.
Given:
The number of micrometeorites hitting the moon in one day is [tex]25 \times {10^6}[/tex].
The area of footprint is [tex]0.03\,{{\text{m}}^{\text{2}}}[/tex].
The surface area of moon is [tex]3.79 \times {10^{19}}\,{{\text{m}}^{\text{2}}}[/tex].
Concept used:
When footprints hit the surface of moon it got impacted.
The expression for the number of micrometeorites hitting the surface area of footprints in one day is given as.
[tex]\fbox{\begin\\n = \dfrac{N}{{{A_{{\text{moon}}}}}}{A_{{\text{footprint}}}}\end{minispace}}[/tex] …… (1)
Here, [tex]N[/tex] is the number of micrometeorites hitting the moon in one day, [tex]{A_{{\text{moon}}}}[/tex] is the surface area of moon and [tex]{A_{{\text{footprint}}}}[/tex] is the surface area of footprint.
The expression for the time to receive impacts on footprints.
[tex]\fbox{\begin\\T = \dfrac{{20}}{n}\end{minispace}}[/tex] …… (2)
Substitute [tex]25 \times {10^6}[/tex] for [tex]N[/tex], [tex]0.03\, {{\text{m}}^{\text{2}}}[/tex] for [tex]{A_{{\text{footprint}}}}[/tex] and in equation (1).
[tex]\begin{aligned}n &= \frac{{\left( {25 \times {{10}^6}} \right)}}{{\left( {3.79 \times {{10}^{19}}\,{{\text{m}}^{\text{2}}}}\right)}}\left({0.03\,{{\text{m}}^{\text{2}}}\right)\\&=1.979\times{10^{-8}}\\\end{aligned}[/tex]
This means that the footprints receive [tex]1.979 \times {10^{ - 8}}[/tex] number of micrometeorites or impacts per day.
[tex]20[/tex] Impacts are required to erase the footprint in one day.
The expression for the time required to erase the footprints is given in equation (2).
Substitute [tex]1.979 \times {10^{ - 8}}[/tex]for [tex]n[/tex] in equation (2).
[tex]\begin{aligned}T &= \frac{{20}}{{\left( {1.979 \times {{10}^{-8}}}\right)}}\\&=1.010\times{10^9}\,{\text{days}}\\\end{aligned}[/tex]
Thus, it can be given in million years as [tex]\fbox{1010\,{\text{million}}\,{\text{yr}}}[/tex].
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Answer Details:
Grade: College
Subject: Physics
Chapter: Astronomy
Keywords:
Moon, meteorites, footprints, impact, surface area, 20 impacts, micrometeorites, 25 million micrometeorites, 1010 million year,1.010*10^9 days .
Where is the highest electronegativity found?
The highest electronegativity is found in fluorine, located at the upper right corner of the periodic table with a value of 4.0.
Explanation:The highest electronegativity is found at the upper right corner of the periodic table, with fluorine having the highest electronegativity value. According to the Pauling scale, developed by the Nobel Prize-winning chemist Linus Pauling, fluorine has an electronegativity value of 4.0, which is the highest of all elements. The periodic trends indicate that electronegativity values increase as you move from left to right across a period and decrease as you move from top to bottom down a group. Therefore, nonmetals, particularly halogens like fluorine, are usually the elements with high electronegativities.
Helppp!
Energy transfer or energy transformation?
1) a boat rocked by the rhythm of waves =
2) heat from a fireplace =
The acceleration due to gravity on planet X is one fifth that on the surface of the earth. If it takes 4.1 s for an object to fall a certain distance from rest on earth, how long would it take to fall the same distance on planet X? Answer in units of s.
The kinematic we find the time it takes for the body to fall on the planet X is 9.17 s
Given parameters
Acceleration on planet x a = 1/5 g The time of fall on the Earth t = 4.1 sTo find
The fall time on planet X
Kinematics studies the movement of the carpus, establishing relationships between their position, speed and acceleration.
For this exercise we must solve it in parts:
1st part. We look for the distance that the body on the ground in the Earth
y = v₀ t - ½ g t²
Where y and, y₀ are the final and initial height, respectively, g the ground clearance and t the time
where as the body is released its initial velocity is zero
y- y₀ = - ½ g t²
Δy = - ½ 9.8 4.1²
Δy = - 82.4 m
2nd part. This same distance is the one that travels on planet X, we look for time
y - y₀ = - ½ a t²
indicates that the acceleration on planet X is
a = 1/5 g
we substitute
Δy = - ½ (1/5 g) t²
t = [tex]\sqrt{\frac{10 \ \Delta y}{g} }[/tex]
t = [tex]\sqrt{\frac{10 \ 82.4 }{9.8} }[/tex]Ra 10 82.4 / 9.8
t = 9.17 s
In conclusion using kinematics we find the time it takes for the body to fall on planet x is 9.17 s
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When you stand at rest on a bathroom scale, how does your weight compare with the support force by the scale?
When you stand at rest on a bathroom scale, your weight and the scale's support force are equal but opposite in direction, according to Newton's Third Law. Your weight, which is the force of gravity acting on your mass, presses down on the scale, and the scale pushes back up with equal force. This balance means that you are not accelerating, and the scale correctly reflects your actual weight.
Explanation:The question you're asking is really about the principles of Physics, particularly those involving forces and weight. When you stand at rest on a bathroom scale, your weight and the support force by the scale are equal in magnitude but opposite in direction. This is due to Newton's Third Law, which states that for every action, there is an equal and opposite reaction. Simply put, your body presses down on the scale (action), and the scale pushes back with equal force (reaction).
The weight we refer to here is actually the force of gravity acting on your mass. It's worth noting that this force would change if the force of gravity changes, for instance, if you were to stand on a scale on the moon. However, when you're standing on a scale on Earth, your weight and the scale's support force are balanced, meaning you are not accelerating and the reading on the scale reflects your actual weight.
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