Using the given function, select the correct set of ordered pairs for the following domain values.

Answer:

x=42

Step-by-step explanation:

Add by 26 from both sides of equation.

6x-26+26=58+4x+26

Simplify.

6x=4x+84

Subtract by 4x from both sides of equation.

6x-4x=4x+84-4x

Simplify.

2x=84

Divide by 2 from both sides of equation.

2x/2=84/2

Simplify, to find the answer.

84/2=42

x=42 is the correct answer.

I hope this helps you, and have a wonderful day!

For this case we have the following functions:

[tex]f (x) = 7x + 1\\g (x) = x ^ 2[/tex]

We must find[tex](g_ {0} f) (x).[/tex]

By definition of composition of functions we have to:

[tex](g_ {0} f) (x) = g (f (x))[/tex]

So:

[tex](g_ {0} f) (x) = g (f (x)) = (7x + 1) ^ 2 = 49x ^ 2 + 2 (7x) (1) + 1 = 49x ^ 2 + 14x + 1[/tex]

ANswer:

[tex](7x + 1) ^ 2 = 49x ^ 2 + 14x + 1[/tex]

Answer:

h= 12

Step-by-step explanation:

Given

66 = [tex]\frac{1}{2}[/tex] h(5 + 6)

Multiply both sides by 2 to eliminate the fraction

132 = h(5 + 6)

132 = 11h ( divide both sides by 11 )

12 = h

[tex]\bf 3x^3+27x^2-15x\div 3x\implies \cfrac{3x^3+27x^2-15x}{3x}\implies \stackrel{\textit{distributing the denominator}}{\cfrac{3x^3}{3x}+\cfrac{27x^2}{3x}-\cfrac{15x}{3x}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill x^2+9x-5~\hfill[/tex]

63-5x

So you do PEMDAS

There aren’t any parenthesis

There aren’t any exponents

So you multiply 3*3 and get 9

Multiply 27 by 2 and get 54

And divide 15x by 3x

Now moving on to addition/subtraction

The equation is now 9+54-5x

9+54 is 63

So the answer is 63+5x

Answer:

32

Step-by-step explanation:

The formula is base x hight.

The base is 8.

The hight is 4.

You just multiply the two.

8x4=32

Simple. :)

Hope this helps!

Answer: 42 inches squared

Step-by-step explanation:

To find the total area you will find the area of the rectangle and then add that to the area of the triangle. (Remember a triangle is half of a rectangle!) First we will find the area of the rectangle...

4x8=32 inches squares

Now let’s find the area of the triangle, find the rectangle then divide it in half...

5x4=20 inches squared

20/2=10 inches squared

Now add 32 to 10 and you’ll have your answer!

32+10=42 inches squared

Answer:

B 9/10

Step-by-step explanation:

3/5 ÷2/3

Copy dot flip

3/5 * 3/2

9/10

Answer:

First Option

Step-by-step explanation:

Given expression is:

[tex]\sqrt[4]{x^{10}}[/tex]

The radicand's exponent will be made multiple of 4 to make the calculations easy

So,

[tex]= \sqrt[4]{x^8 * x^2}[/tex]

The 4 outside the radical means that the power that will be multiplied with the exponents will be 1/4

So,

[tex]= x^{(8*\frac{1}{4})} * x^{(2*\frac{1}{4})}\\=x^2 \sqrt[4]{x^2}[/tex]

As x^2 couldn't be solved using radical, it will remain inside the radical.

So the correct answer is first option..

Answer: First option.

Step-by-step explanation:

Knwing that we must find which is the equivalent expression of the expression [tex]\sqrt[4]{x^{10}}[/tex], it is important to remember the Product of powers property, which states the following:

[tex](a^m)(a^n)=a^{(m+n)}[/tex]

The we can rewrite the expression:

 [tex]=\sqrt[4]{x^8x^2}[/tex]

Remember that:

[tex]\sqrt[n]{a^n}=a[/tex]

Then we get this equivalent expression:

 [tex]=x^2(\sqrt[4]{x^2})[/tex]

Answer:

[tex]\frac{3}{2}[/tex]

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

                   = - cos60cosx - sin60sinx

                   = - [tex]\frac{1}{2}[/tex] cosx - [tex]\frac{\sqrt{3} }{2}[/tex] sinx

squaring to obtain cos² (120 + x)

= [tex]\frac{1}{4}[/tex]cos²x + [tex]\frac{\sqrt{3} }{2}[/tex]sinxcosx + [tex]\frac{3}{4}[/tex]sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

                   = -cos60cosx + sin60sinx

                   = - [tex]\frac{1}{2}[/tex]cosx + [tex]\frac{\sqrt{3} }{2}[/tex]sinx

squaring to obtain cos²(120 - x)

= [tex]\frac{1}{4}[/tex]cos²x - [tex]\frac{\sqrt{3} }{2}[/tex]sinxcosx + [tex]\frac{3}{4}[/tex]sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + [tex]\frac{1}{4}[/tex]cos²x + [tex]\frac{\sqrt{3} }{2}[/tex]sinxcosx + [tex]\frac{3}{4}[/tex]sin²x + [tex]\frac{1}{4}[/tex]cos²x - [tex]\frac{\sqrt{3} }{2}[/tex]sinxcosx + [tex]\frac{3}{4}[/tex]sin²x

= cos²x + [tex]\frac{1}{2}[/tex]cos²x + [tex]\frac{3}{2}[/tex]sin²x

= [tex]\frac{3}{2}[/tex]cos²x + [tex]\frac{3}{2}[/tex]sin²x

= [tex]\frac{3}{2}[/tex](cos²x + sin²x) = [tex]\frac{3}{2}[/tex]

Answer:

7

Step-by-step explanation:

Givens

x = 4

y = 2

z =-3

equation

xy - z^y

Solution

(4)(2) - (-3)^2     be sure and add the brackets. Otherwise it won't come out correctly.

16 - (9) = 7

Answer:

no solution

Step-by-step explanation:

The solution to a system of equations given graphically is at the point of intersection of the 2 graphs.

The given lines are parallel ( both have a slope = 2 )

Hence the lines never intersect thus there is no solution.

Answer:

[tex]\boxed{\math{\frac{1}{9}\text{ lb}}}[/tex]

Step-by-step explanation:

[tex]\text{Size of one serving} = \dfrac{\text{Total size}}{\text{No of servings}} = \dfrac{\frac{2}{3}\text{ lb}}{\text{6 servings}}\\\\\text{Change the 6 to a fraction and change divide to multiply}\\\\\dfrac{2}{3} \div 6 = \dfrac{2}{3} \times \dfrac{1}{6}[/tex]

[tex]\text{Cancel the 2s}\\\\\dfrac{2}{3} \times \dfrac{1}{6} = \dfrac{1}{3} \times \dfrac{1}{3}\\\\\text{Multiply numerators and denominators}\\\\\dfrac{1}{3} \times \dfrac{1}{3} = \dfrac{1}{9}\\\\\text{Each serving contains }\boxed{\mathbf{\frac{1}{9}\textbf{ lb}}}[/tex]

[tex]\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\ \cline{1-1} A=452\frac{4}{7} \end{cases}\implies 452\frac{4}{7}=\pi r^2\implies \cfrac{3168}{7}=\pi r^2 \implies \cfrac{3168}{7\pi }=r^2 \\\\\\ \stackrel{\pi =\frac{22}{7}}{\cfrac{3168}{7\cdot \frac{22}{7}}}=r^2\implies \cfrac{3168}{22}=r^2\implies 144=r^2\implies \sqrt{144}=r\implies 12=r \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{diameter=2r}{d=24}~\hfill[/tex]

Answer:

The number line should look like this;

<---- -3 -------- 0 ------- 3 ----->

It must have both 3 and -3 shown

Step-by-step explanation:

Step-by-step explanation:how do you feguire this out because the left of a number line is always negative and the right is always posittive easy right i hope it helped you just like when i learned it it helped me.

Step-by-step explanation:

1. x = acceptable weight of candy bar

2. |x - 12| ≤ 0.45

3. x - 12 ≤ 0.45, x - 12 ≥ -0.45

x ≤ 12.45, x ≥ 11.55

4. The acceptable weight range for each candy bar is between 11.55 grams and 12.45 grams.

Answer:

Option C is correct.

Step-by-step explanation:

The x-intercepts of the function (x − 1)(x − 4)(x + 7) can be found by putting this function equal to zero

(x − 1)(x − 4)(x + 7) = 0

Now,

x-1 = 0

x-4 = 0

and x+7 = 0

Now finding the values of x

x-1 = 0 + 1

x - 1 + 1 = 1

=> x = 1

or (1,0)

x - 4 = 0

x -4 + 4 = 0 + 4

x = 4

or (4,0)

x + 7 = 0

x +7 -7 = 0 -7

x = -7

or (-7,0)

SO, the x-intercepts of the function (x − 1)(x − 4)(x + 7) are (1,0),(4,0) and (-7,0)

Option C is correct.

Answer:

+ 1  + 4   -7

Step-by-step explanation:

when they ask for x intercepts you simply have to set the function to 0 and then solve for x or in other words just reverse the number for example. here we have -1 -4 and +7 so just reverse the negative and positive signs

Answer:

A. concave hexagon

Step-by-step explanation:

It has 6 sides, so it's a hexagon. (A heptagon has 7 sides.)

If all interior angles are less than 180 deg, then it is convex. There is one interior angle on the left side that is more than 180 deg, so it is concave.

Answer: concave hexagon

Answer

AAS

Step-by-step explanation:

Step-by-step explanation:

Write the prime factorization for each:

22a² = 2×11×a²

32a = 2⁵×a

So the greatest common factor is 2a.

Answer:

[tex]\large\boxed{\dfrac{2s-6}{s+3}}[/tex]

Step-by-step explanation:

[tex]s^2-9=s^2-3^2\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\=(s-3)(s+3)\\\\s^2+6s+9=s^2+2(s)(3)+3^2\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\=(s+3)^2[/tex]

[tex]\dfrac{s^2-9}{2s}\div\dfrac{s^2+6s+9}{4s}=\dfrac{s^2-9}{2s\!\!\!\!\diagup_1}\cdot\dfrac{4s}{s^2+6s+9}\\\\=\dfrac{(s-3)(s+3)}{2s\!\!\!\!\!\diagup_{_1}}\cdot\dfrac{4s\!\!\!\!\!\diagup^{^2}}{(s+3)^2}=\dfrac{2(s-3)(s+3)}{(s+3)(s+3)}\qquad\text{cancel}\ (s+3)\\\\=\dfrac{2(s-3)}{s+3}=\dfrac{2s-6}{s+3}[/tex]

Answer:

[tex]a_8=-128x^8-384x^7[/tex]

Step-by-step explanation:

The terms of the sequence are:

[tex]x+3,-2x^2-6x,4x^3+12x^2,...[/tex]

We can rewrite the terms in factored form to get;

[tex]x+3,-2x(x+3),4x^2(x+3),...[/tex]

We can see that the subsequent terms are obtained by multiplying the previous term by [tex]-2x[/tex]. This is called the common ratio.

Therefore the first term of this geometric sequence is [tex]a_1=x+3[/tex] and the common ratio is [tex]r=-2x[/tex].

The nth term of a geometric sequence is given by: [tex]a_n=a_1(r^{n-1})[/tex].

Let us substitute the first term, the common ratio, and [tex]n=8[/tex] to obtain:

[tex]a_8=(x+3)(-2x)^{8-1}[/tex]

[tex]a_8=(x+3)(-2x)^{7}[/tex]

[tex]a_8=-128x^7(x+3)[/tex]

[tex]a_8=-128x^8-384x^7[/tex]

Answer:

see below

Step-by-step explanation:

2/3 ÷ 4

We use copy dot flip

The flip means make a reciprocal of the second number

2/3 * 1/4

Multiply the numerators

2*1 = 2

Multiply the denominators

3*4 =12

Put the numerator over the denominator

2/12

Simplify

1/6

To use equivalent fractions to find the quotient of \( \frac{2}{3} \) ÷ 4, follow these steps:

### Step 1: Understand the Operation
Division of fractions can be thought of as multiplying by the reciprocal. The reciprocal of a number a is simply \( \frac{1}{a} \).

### Step 2: Find the Reciprocal of the Divisor
The divisor here is the whole number 4. Its reciprocal is \( \frac{1}{4} \).

### Step 3: Multiply the Dividend by the Reciprocal of the Divisor
Instead of dividing \( \frac{2}{3} \) by 4, you can multiply \( \frac{2}{3} \) by \( \frac{1}{4} \).

### Step 4: Perform the Multiplication
Now, multiply the two fractions:

\[ \frac{2}{3} \times \frac{1}{4} = \frac{2 \cdot 1}{3 \cdot 4} \]

This results in a new fraction:

\[ \frac{2}{12} \]

### Step 5: Simplify the Resulting Fraction
Finally, you need to simplify the fraction to its simplest form. To do that, find the greatest common factor (GCF) of the numerator and the denominator and divide both by this number.

For \( \frac{2}{12} \), the greatest common factor is 2. So we divide both the numerator and the denominator by 2:

\[ \frac{2 \div 2}{12 \div 2} = \frac{1}{6} \]

### Conclusion
Therefore, the quotient of \( \frac{2}{3} \) ÷ 4 is \( \frac{1}{6} \). This is the simplest form of the fraction you obtain when \( \frac{2}{3} \) is divided by 4.

Answer:

the answer is x=0,-(3/7)

Step-by-step explanation:

Answer:

x = { - [tex]\frac{3}{7}[/tex], 0 }

Step-by-step explanation:

Given

7x² + 3x = 0 ← factor out x from each term

x(7x + 3) = 0

Equate each factor to zero and solve for x

x = 0

7x + 3 = 0 ⇒ 7x = - 3 ⇒ x = - [tex]\frac{3}{7}[/tex]

Answer:

D. 7.46  

Hope this helps and have a nice day!!

If I'm wrong pleaseeee tell me

Step-by-step explanation:

Let us check each Option :

[tex]\mathsf{First\;Option : \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m + 9}{m - 9}\right)}[/tex]

[tex]\mathsf{\implies \left(\dfrac{m + 9}{m - 9}\right)^2\;\neq\;1}[/tex]

[tex]\mathsf{Second\;Option : \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m - 9}{m + 9}\right)}[/tex]

[tex]\mathsf{\implies 1}[/tex]

[tex]\mathsf{Third\;Option : \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{9 + m}{9 - m}\right)}[/tex]

[tex]\mathsf{\implies \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m + 9}{-(m - 9)}\right)}[/tex]

[tex]\mathsf{\implies-\left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m + 9}{m - 9}\right)}[/tex]

[tex]\mathsf{\implies-\left(\dfrac{m + 9}{m - 9}\right)^2\;\neq\;1}[/tex]

[tex]\mathsf{Fourth\;Option : \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{9 - m}{9 + m}\right)}[/tex]

[tex]\mathsf{\implies \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{-(m - 9)}{9 + m}\right)}[/tex]

[tex]\mathsf{\implies -\left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m - 9}{9 + m}\right)}[/tex]

[tex]\mathsf{\implies -1\;\neq\;1}[/tex]

Answer : Option (2)

Answer:

B.⁽[tex](\frac{m}{m}\frac{+9}{-9} ) (\frac{m}{m} \frac{- 9}{+ 9} )[/tex]

Step-by-step explanation:

Answer:

A'(-4,4)

B'(-2,11)

Step-by-step explanation:

6 unit up and 3 unit left

A (-1,-2) : 6 unit up → (-1,4) → 3 unit left → (-4,4)

A'(-4,4)

B (1,5) : 6 unit up → (1,11) → 3 unit left → (-2,11)

B'(-2,11)

Answer:

Step-by-step explanation:

[tex]f(n+1)=f(n)-2\\\\f(1)=10\\f(2)=f(1)-2=10-2=8\\f(3)=f(2)-2=8-2=6[/tex]

Answer:

B) 6

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

dot

Answer:

a

Step-by-step explanation:

You're trying to find the distance between D and E so u use the distance formula.

sqrt (a+b-b^2)+(c-c)^2=sqrt a^2=a

Answer:

a

Step-by-step explanation:

We are given that

D is the mid-point of AB and E is the mid-point of AC.

We have to find the missing information in given proof of DE is equal to half of BC.

Proof:

D is the mid-point of AB and E is the mid-point of AC.

The coordinates of A are (2b,2c)

The coordinates of D are (b,c)

The coordinates of E are (a+b,c)

The coordinates of  B are (0,0)

The coordinates of  C are (2a,0)

Distance formula:[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using the formula

Length of BC=[tex]\sqrt{(2a)^2+(0-0)^2}=2a[/tex] units

Length of DE=[tex]\sqrt{(a+b-b)^2+(c-c)^2}=a[/tex] units

[tex]BC=2a=2\times DE[/tex]

[tex]DE=\frac{1}{2}BC[/tex]

Hence, proved.

Option A is true.

Answer: B and F

Hope it helps!!!

Answer: OPTION B AND OPTION D.

Step-by-step explanation:

Analyze  the triangle provided.

You can observe that the lenghts of its sides are: 10.9, 15, 14

Then the lenghts of its sides are not equal.

 By definition, when all sides of a triangle are different this is called: "Scalene".

You can notice that the measures of its angles are: 63°, 44° and 73°

Then, all its angles are less than 90 degrees.

By definition if all three angles of a triangle are less than 90 degrees, then is called: "Acute".