Use the variable t for the number of teeth in one row. Write an expression to determine the number of teeth in a sharks mouth.

Answer:

The LA theorem is a special case of the AAS theorem and the ASA postulate.

Step-by-step explanation:

The LA theorem is a special case of the AAS theorem and the ASA postulate.

LA(Leg - Acute) theorem states that if the leg and one acute angle of one right triangle are congruent to the corresponding leg and acute angle of another right triangle, then the triangles are congruent.

AAS (Angle Angle Side) states that if two angles and the non included side of one triangle are congruent to two angles and the non included side of another triangle, then these two triangles are congruent.

ASA (Angle Side Angle) postulate states that if two angles and one included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent.

The scientific notation of the decimal number 0.0013 is [tex]0.0013 \times 10^{-3}[/tex].

Scientific notation is a way to express numbers in a concise form, particularly useful for very large or very small numbers.

It consists of two parts: a coefficient and an exponent of 10.

In the case of 0.0013, we can convert it to scientific notation as follows:

[tex]0.0013 \times 10^{-3}[/tex].

Hence, the scientific notation of 0.0013 is [tex]0.0013 \times 10^{-3}[/tex].

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Priscilla and Herb would take approximately 44.44 hours to address 10,000 envelopes together, as Priscilla can address 100 envelopes per hour and Herb can address 125 envelopes per hour.

The question asks about the combined work rate of Priscilla and Herb in addressing 10,000 envelopes. To solve this, we calculate each of their rates of work and then combine them to find the total rate. Priscilla completes 10,000 envelopes in 100 hours, so her rate is 100 envelopes per hour. Herb completes 10,000 envelopes in 80 hours, so his rate is 125 envelopes per hour. Working together, their combined rate is 100 + 125 = 225 envelopes per hour. To address 10,000 envelopes at this rate, we divide 10,000 by 225, which equals approximately 44.44 hours.

The number in which the 6 has a value that is one-tenth the value of the 6 in 34,761 is 3,476.1

In the number 34,761, the digit 6 is in the tens place, giving it a value of 60. To find a number where the value of 6 is one-tenth of 60, we look for a place value that is one position to the right.

In 3,476.1, the 6 is in the ones place, making its value 6, which is one-tenth of 60. This shift from the tens place to the ones place decreases the value by a factor of ten.

Answer:

Approximately 83 bags each carrying 50 pounds of soil will carry 1 cubic yard of soil or 4,128 pounds of soil.

Step-by-step explanation:

We are given the following information in the question:

1 cubic yards is equal to 4128 pounds that is

[tex]1~yard^3 = 4,128~pounds[/tex]

Amount of soil 1 bag can hold = 50 pounds

Number of bags to hold 1 cubic yard of soil or 4,128 pounds of soil:

Formula:

[tex]\text{Number of bags} = \displaystyle\frac{\text{Total amount of soil}}{\text{Amount of soil 1 bag can hold}}[/tex]

[tex]= \displaystyle\frac{4128}{50} = 82.56[/tex]

Thus, approximately 83 bags each carrying 50 pounds of soil will carry 1 cubic yard of soil or 4,128 pounds of soil.

Using simple mathematical operations, we know that 201 bolts are produced in 21 minutes.

So, the bolts produced in 21 minutes are:

Calculate as follows:

Therefore, using simple mathematical operations, we know that 201 bolts are produced in 21 minutes.

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Final answer:

To find the number of bolts produced in 21 minutes, set up a proportion using the given information: 268 bolts / 28 minutes = x bolts / 21 minutes. Simplifying, we find that x = 201 bolts.

Explanation:

To find the number of bolts produced in 21 minutes, we can set up a proportion using the given information. We know that the machine produces 268 bolts in 28 minutes. Let x be the number of bolts produced in 21 minutes.

Using the proportion:

268 bolts / 28 minutes = x bolts / 21 minutes

Multiplying both sides by 21, we get:

(268 bolts / 28 minutes) * 21 minutes = x bolts

Simplifying, we find that x = 201 bolts.

Jose bought a bag of [tex]6[/tex] oranges for [tex]\$2.82[/tex] and Jose also bought [tex]5[/tex]  pineapples each cost [tex]\$3.15[/tex].

Explanation:

Given: Jose bought a bag of [tex]6[/tex] oranges for [tex]\$2.82[/tex]. He also bought [tex]5[/tex] pineapples. He gave the cashier [tex]\$20[/tex] and received [tex]\$1.43[/tex] change.

Let cost of a pineapple be [tex]x[/tex].

According to the question:

Cost of pineapple is calculated as [tex]20-(2.82+5x)=1.43[/tex]

                                                            [tex]20-2.82-5x=1.43\\[/tex]

                                                                               [tex]5x=17.18-1.43\\[/tex]

                                                                                 [tex]x=\frac{15.75}{5} \\x=3.15[/tex]

Therefore, cost of each pineapple is [tex]\$3.15[/tex].

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Answer:

c

Step-by-step explanation:

Answer:

The sum is fraction therefore rational

Step-by-step explanation:

Given two numbers

[tex]-2\frac{3}{4}\text{ and }\frac{5}{9}[/tex]

we have to tell that how their sum is rational.

we add the above two number

[tex]-2\frac{3}{4}+\frac{5}{9}[/tex]

[tex]\frac{-11}{4}+\frac{5}{9}[/tex]

[tex]\frac{-99+20}{36}=\frac{-79}{36}=-2.194444...[/tex]

Hence, the sum is we can say fraction or non-terminating but repeating which is the definition of a rational number.

∴ from the given options answer C is correct.

The sum is fraction therefore rational.

The common speed of the blocks just after the collision is 0.4 times the initial velocity of the first block (v₁).

To determine the common speed of the blocks just after the completely inelastic collision, we can use the principle of conservation of linear momentum.

According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

Let's denote the velocity of the first block (m = 0.050 kg) before the collision as v₁ and the velocity of the second block (m = 0.075 kg) before the collision as v₂. Since the second block is stationary, its initial velocity, v₂, is 0.

1. Before the collision, the total momentum is given by:

Initial momentum = m₁v₁ + m₂v₂

where m₁ and m₂ are the masses of the first and second blocks, respectively.

Plugging in the values, we have:

Initial momentum = (0.050 kg) v₁ + (0.075 kg) 0

Initial momentum = (0.050 kg)v₁

2. After the collision, the two blocks stick together and move as a single unit with a common velocity, denoted as vf.

The final momentum is given by:

Final momentum = (m₁ + m₂) vf

where (m₁ + m₂) is the total mass of the system.

Plugging in the values, we have:

Final momentum = (0.050 kg + 0.075 kg) × vf

Final momentum = 0.125 kg × vf

According to the principle of conservation of linear momentum, the total momentum before the collision is equal to the total momentum after the collision:

0.050 kg × v₁ = 0.125 kg × vf

To determine the common speed of the blocks just after the collision, we need to solve for vf:

vf = (0.050 kg × v₁) / (0.125 kg)

Calculating the numerical value, vf = 0.4 ×  v1

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