Answer:
Density=1.25g/dm^3
Explanation:
Density=mass/volume
Mass of nitrogen gas is 2(14)=28g
Volume at STP=22.4dm^3
Density=28/22.4=1.25g/dm^3
The mass is the molar mass of N₂ (28.01 g) and the volume is 1.25 L
To calculate the density of nitrogen gas at STP using the molar volume of a gas at STP, you can follow these steps:
1. Understand the concept: Molar volume of a gas at STP (Standard Temperature and Pressure) is 22.4 L/mol.
This means that one mole of any ideal gas occupies 22.4 liters at STP.2. Determine the molar mass of nitrogen: The molar mass of nitrogen (N2) is approximately 28.02 g/mol.
This means that one mole of nitrogen gas weighs 28.02 grams.3. Use the ideal gas law: The ideal gas law states that PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.
At STP, pressure (P) is 1 atm and temperature (T) is 273 K.4. Calculate the number of moles: Since the molar volume at STP is 22.4 L/mol, and the volume is equal to 22.4 liters, the number of moles of nitrogen gas is 1 mole.
5. Calculate the density: Density (ρ) is defined as mass divided by volume. Since we have one mole of nitrogen gas, which weighs 28.02 grams, we can calculate the density as follows:
ρ = [tex]\frac{m}{V}[/tex] ρ = [tex]\frac{28.02g}{22.4 L}[/tex] ρ = 1.25 g/LTherefore , the density of nitrogen gas at STP is 1.25 g/ L
If K3PO4= 0.250M, how many grams of K3PO4 are in 750.0ml of solution? Remember that M is the same as mol/L. Answer: 39.8g
please show work!
Answer:
See below
Explanation:
Molarity = moles/Volume in Liters = (grams/formula wt)/Vol in Liters
=> Grams of solute = Molarity x Vol in Liters x formula wt
= (0.250M)(0.750L)(212.3g/mol)
= 39.8 grams
Final answer:
To find the mass of K3PO4 in a 0.250 M solution with a volume of 750.0 mL, calculate the number of moles and then multiply by the molar mass, resulting in 39.8 grams.
Explanation:
To calculate the mass of K3PO4 in a 0.250 M solution with a volume of 750.0 mL, we need to follow these steps:
Convert the volume from mL to L: 750.0 mL is 0.750 L.Calculate the number of moles of K3PO4 using the molarity and volume of the solution: 0.250 M imes 0.750 L = 0.1875 moles.Find the molar mass of K3PO4 by adding the atomic masses of 3 potassium (K) atoms, 1 phosphorus (P) atom, and 4 oxygen (O) atoms. Using periodic table values: Molar mass of K3PO4 = (3 imes 39.10) + 30.97 + (4 imes 16.00) = 212.27 g/mol.Multiply the number of moles by the molar mass to get the mass in grams: 0.1875 moles imes 212.27 g/mol = 39.8 grams.Therefore, there are 39.8 grams of K3PO4 in 750.0 mL of a 0.250 M solution.
Calculate the mass of Cu deposited by the electrolysis of CuCl2 at 4A for 40 minutes.
Answer:
3.16g
Explanation:
Data obtained from the question include:
I = 4A
t = 40mins = 40 x 60 = 2400secs
Q =?
Q = It
Q = 4 x 2400
Q = 9600C
Now let us generate a balanced half equation to determine the number faraday needed to deposit metallic Cu. This is illustrated:
Cu^2+ + 2e —> Cu
From the equation,
2 faraday is needed to deposit metallic cu
1 faraday = 96500C
Therefore 2 faraday = 2 x 96500 = 193000C
Molar Mass of Cu = 63.5g/mol
193000C deposited 63.5g of Cu
Therefore, 9600C will deposit = (9600 x 63.5)/193000 = 3.16g of Cu
3 The volume of a gas is 50.0 mL at 20.0 K. What will be the new
temperature if the gas is compressed to 10.0 mL under constant pressure?
A 100 K
B 10.0 K
C4.00 K
D 5.00 K
Answer:
C. 4.00 K
Explanation:
We can solve this using Charles's Law of the ideal gas. The law describes that when the pressure is constant, the volume will be directly proportional to the temperature. Note that the temperature here should only use the Kelvin unit. Before compressed, the volume of the gas is 50ml(V1) and the temperature is 20K (T1). After compressed the volume becomes 10ml(V2). The calculation will be:
V1 / T1= V2 / T2
50ml / 20K = 10ml / T2
T2= 10ml/ 50ml * 20K
T2= 4K
Final answer:
The new temperature of the gas, when compressed from 50.0 mL to 10.0 mL under constant pressure, will be 4.00 K, following Charles's Law which relates temperature and volume of a gas under constant pressure.
Explanation:
The question involves the concept of how the volume of a gas changes with temperature, under constant pressure, following Charles's Law. This law states that the volume of a gas is directly proportional to its temperature (in Kelvin) when the pressure is kept constant. Given that the volume of a gas is 50.0 mL at 20.0 K and the volume is compressed to 10.0 mL under constant pressure, we want to find the new temperature. Applying Charles's Law, we set up the proportion (V1/T1) = (V2/T2) where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.
To solve for T2, we rearrange the formula to T2 = (V2/V1) * T1. Substituting the given values, T2 = (10.0 mL / 50.0 mL) * 20.0 K = 4.00 K. Therefore, the new temperature of the gas, when compressed to 10.0 mL under constant pressure, will be 4.00 K.
is jelly beans substance
Answer:Jelly Beans are a mixture
Explanation:
you cannot separate them
which term best describes the physical properties of a rainbow
Answer: meteorological phenomenon
Explanation: Hello, there! A rainbow is a meteorological phenomenon that is caused by reflection, refraction and dispersion of light in water droplets resulting in a spectrum of light appearing in the sky. It takes the form of a multicoloured circular arc. Rainbows caused by sunlight always appear in the section of sky directly opposite the sun.
I hoped i help and im here for any more questions you might have! thankyou!
How many protons are in a hydrogen Atom
Answer:
1
Explanation:
Its periodic number is 1.
Answer:
There are 1 plus that is the periodic number
Which structure of the respiratory system connects the pharynx to the trachea?
Answer:
Larynx
Explanation:
It is a cartilaginous structure inferior to the laryngopharynx that connects the pharynx to the trachea and helps regulate the volume of air that enters and leaves the lungs.
The larynx, also known as the voice box, is the structure in the respiratory system that connects the pharynx to the trachea. It serves as a conduit for air and also house the vocal cords, playing a crucial role in speech and vocalization.
Explanation:The structure of the respiratory system that connects the pharynx to the trachea is the larynx. The larynx, also known as the voice box, is a short passageway that connects the pharynx (the region that receives air from the nasal cavities and the mouth) to the trachea (the 'windpipe' that leads to the lungs). The larynx not only serves as a conduit for air, it also houses the vocal cords, and thus, plays a crucial role in speech and vocalization.
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The measurement 0.41006 gram, rounded to three significant figures, is expressed as
Answer:
0.410
Explanation:
Rounding 0.41006 gram to three significant figures results in 0.410 g.
To express the measurement 0.41006 gram rounded to three significant figures. When rounding to significant figures, we look at the digits from the left and count the first non-zero digit and the following digits up to the desired number of figures.
Here, the first three significant figures are 4, 1, and 0 (since this zero comes after a non-zero digit and before another non-zero digit, it counts as significant). Therefore, rounding 0.41006 to three significant figures gives us 0.410 g.
ANSWER BOTH ASAP AND I WILL GIVE BRAINLYEST!!!!
Answer:
For the first one it is C
Explanation:
Answer:
answer is: constant , direct solar radiation as the ocean influences weather and climate by storing solar radiation, distributing heat and moisture around the globe, and driving weather systems.
The Coriolis effect is the apparent curvature of global winds, ocean currents, and everything else that moves freely across the Earth's surface. The curvature is due to the rotation of the Earth on its axis. The effect was discovered by the nineteenth century French engineer Gaspard C.
how is a mole like a dozen?
Answer:
Answer in explanation.
Explanation:
The mole is a unit for counting 6.02 1023 representative particles. The dozen is used to count 12 items.
The mole is a unit for counting 6.02 1023 representative particles.
The dozen is used to count 12 items
Which factor most directly affects potential energy?
Answer:
Mass, gravitational force and height
Explanation:
Potential energy of body is the energy at rest in a body and it depends on the mass, acceleration due to gravity and height of a body;
Potential energy = mass x gravity x height = mgh
The more the mass, gravity and height of a body, the higher the potential energy a body will posses. This is why a stone at a height has more potential energy than one on the ground.
A piece of copper has a temperature of 73.6 C. When the metal is placed in 96.2 grams of water at 17.1 C, the temperature rises by 5.1 C. What is the mass of the metal?
Answer:
103.8 g
Explanation:
When the hot piece of copper is placed in the water at lower temperature, the piece of copper gives off thermal energy to the water; as a result, the temperature of the copper decreases while the temperature of the water increases, until they both reach the equilibrium temperature.
The heat given off by the piece of copper is equal to the heat absorbed by the water, so we can write:
[tex]Q_c=Q_w[/tex]
where:
[tex]Q_w=m_w C_w \Delta T_w[/tex] is the heat absorbed by the water, where
[tex]m_w = 96.2 g[/tex] is the mass of water
[tex]C_w=4.186 J/gC[/tex] is the specific heat of water
[tex]\Delta T_w=5.1C[/tex] is the rise in temperature of the water
Solving,
[tex]Q_w=(96.2)(4.186)(5.1)=2053.7 J[/tex]
[tex]Q_c=m_c C_c (T_c-T)[/tex] is the heat released by the copper, where
[tex]m_c[/tex] is the mass of copper
[tex]C_c=0.385 J/gC[/tex] is the specific heat of copper
[tex]T_c=73.6C[/tex] is the initial temperature of copper
[tex]T=17.1C+5.1C=22.2 C[/tex] is the equilibrium temperature
Solving for the mass,
[tex]m_c=\frac{Q_c}{C_c(T_c-T)}=\frac{2053.7}{(0.385)(73.6-22.2)}=103.8 g[/tex]
The correct answer is the mass of the copper piece is approximately 16.3 grams.
To solve this problem, we can use the principle of conservation of energy, which states that the heat lost by the copper will be equal to the heat gained by the water.
The heat transfer can be calculated using the formula:
[tex]\[ q = mc\Delta T \][/tex]
For the copper piece, the heat lost is given by:
[tex]\[ q_{copper} = m_{copper}c_{copper}(T_{final} - T_{initial,copper}) \][/tex]
For the water, the heat gained is given by:
[tex]\[ q_{water} = m_{water}c_{water}(T_{final} - T_{initial,water}) \][/tex]
Since the heat lost by the copper is equal to the heat gained by the water, we can set the two equations equal to each other:
[tex]\[ m_{copper}c_{copper}(T_{final} - T_{initial,copper}) = m_{water}c_{water}(T_{final} - T_{initial,water}) \][/tex]
Given that [tex]\( T_{final} \)[/tex] is the temperature of the water after the copper is added plus the temperature rise:
[tex](17.1C + 5.1C = 22.2C), \( T_{initial,copper} \) is 73.6C, and \( T_{initial,water} \) is 17.1C,[/tex]we can plug in the values:
[tex]\[ m_{copper}(0.385)(22.2 - 73.6) = (96.2)(4.184)(22.2 - 17.1) \][/tex]
Now, we solve for [tex]\( m_{copper} \)[/tex]:
[tex]\[ m_{copper} = \frac{(96.2)(4.184)(22.2 - 17.1)}{(0.385)(22.2 - 73.6)} \] \[ m_{copper} = \frac{(96.2)(4.184)(5.1)}{(0.385)(-51.4)} \] \[ m_{copper} = \frac{(96.2)(4.184)(5.1)}{(0.385)(-51.4)} \] \[ m_{copper} \approx \frac{(96.2)(4.184)(5.1)}{(-20.163)} \] \[ m_{copper} \approx -16.3 \text{ grams} \][/tex]
Since mass cannot be negative, the negative sign indicates a direction in heat transfer (the copper loses heat), but the magnitude of the mass is what we're interested in.
Therefore, the mass of the copper piece is approximately 16.3 grams.
over the course of two years the top layer of soil at a Michigan farm is blown away
For each of the situations below, state whether it describes erosion, weathering, or possibly both.
Answer:
Erosion
Explanation:
The blowing away of the top layer of the soil at a Michigan farm is best described as scenario that shows wind erosion.
Erosion is the removal of the top layer of the earth on which plant grows. In short is the washing away of soil by stream or blowing away by wind.
When soil is blow away, it is a pure case of erosion. The process of erosion usually follows weathering or sometime occurs together with it.
Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils.
Often times, the process of weathering and erosion occurs together. It is loose weathering products that are carried away during erosion.
In the soil layer at Michigan, the process of erosion by wind is current taking place by ablation.
Over the course of two years, there has been change in the concentration the top layer of soil at a Michigan farm due to natural forces, leading to potential agricultural challenges.
Erosion of the topsoil layer at a Michigan farm over two years can have detrimental effects on agricultural productivity and the environment. Topsoil is crucial for plant growth as it contains essential nutrients and organic matter. When it is blown away, as in this scenario, farmers face difficulties in cultivating crops as the soil becomes less fertile and less capable of retaining moisture. This can result in reduced crop yields and increased vulnerability to drought conditions.
Furthermore, the erosion of topsoil can lead to environmental issues such as water pollution, as sediment runoff can contaminate nearby water bodies. Soil conservation practices, such as planting cover crops and implementing erosion control measures, are essential to mitigate these negative consequences and maintain the long-term sustainability of the Michigan farm's agricultural activities.
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what is symmetry in chemistry
Answer:
A symmetry element is a line, a plane or a point in or through an object, about which a rotation or reflection leaves the object in an orientation indistinguishable from the original.
Explanation:
Symmetry in chemistry is a mathematical concept applied to molecular and crystalline structures, assisting in classifying molecules, predicting vibrational spectra, and understanding bonding.
Symmetry in chemistry refers to the balance and proportion found in molecular structures and crystals. Though it stems from mathematical concepts, symmetry and group theory serve as fundamental tools in understanding various aspects of chemical behavior.
Chemists leverage these concepts to classify molecular structures, predict vibrational spectra, and assess chemical bonding.
How can you increase the electrical output of a generator?
Decrease the speed of the spinning magnet.
Increase the turns of the wire.
O Decrease the turns of the wire.
Decrease the speed of the spinning solenoid.
O Decrease the size of the magnet.
Answer:
Increase the turns of the wire
Explanation:
By increasing the number of turns the wire has made, you are increase the inductive power of the coil in the generator, thereby giving rise to the output of the generator.
using the soubility curve what is the solubilityof nh4cl in 10 mL of water at a temperature of 60 degrees Celsius
Answer:
Please, see attached two figures:
The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.Answer: 5.5gExplanation:
The red arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the solubility of NH₄Cl.
From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.
Assuming density 1.0 g/mol for water, 10 mL of water is:
[tex]10mL\times 1.0g/mL=10g[/tex]
Thus, the solutibily is:
[tex]10gWater\times 55gNH_4Cl/100gWater=5.5gNH_4Cl[/tex]
Which of the following statements is most likely true about the solubilities of CF4 and CCl2F2 in water? CF4 is soluble in water; CCl2F2 is not. Both CF4 and CCl2F2 are insoluble in water. CF4 is insoluble in water; CCl2F2 is soluble in water. Both CF4 and CCl2F2 are soluble in water.
Answer:
Explanation:
CF4 is insoluble in water; CCl2F2 is soluble in water
According to the concept of solubility,CF₄ is insoluble in water; CCl₂F₂ is soluble in water.
What is solubility?Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.
The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.Concept of solubility is not valid for chemical reactions which are irreversible. The dependency of solubility on various factors is due to interactions between the particles, molecule or ions.
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Jayne's science teacher mixed a clear liquid with a blue liquid in a beaker. After a few minutes there was a white solid at the bottom of the beaker. What is most likely true about the white solid?
A.
It is a new substance with different properties.
B.
It is an organic compound.
C.
It will dissolve in water to form a blue solution.
Compared to size of earth, the atmosphere is very
Answer:
thin
Explanation:
Answer:
very thin
Explanation:
the atmosphere is actually very thin compared to the size of the earth.
How much Na2SO4 solution (in L) must be added to initiate the precipitation of CaSO4?
Final answer:
To initiate the precipitation of CaSO4, enough Na2SO4 solution must be added to increase the sulfate ion concentration just above 9.86 × 10-5 M in the presence of 0.50 M Ca2+ ions.
Explanation:
To determine how much Na2SO4 solution is needed to initiate the precipitation of CaSO4, we must consider the solubility product constant (Ksp) of calcium sulfate and the concept of reaction quotient (Q). Calcium sulfate will precipitate when the product of the concentrations of its ions in the solution exceeds its Ksp value. For calcium sulfate, this value is 4.93 × 10-5. The formula to calculate Q for calcium sulfate is Q = [Ca2+][SO42-]. Given that the concentration of Ca2+ ions is 0.50 M, we can rearrange the inequality for [SO42-] to determine the maximum concentration before precipitation occurs:
[0.50 M] [SO42-] < 4.93 × 10-5
[SO42-] < ¹⁹.86 × 10-5 M
To initiate precipitation, we need to add enough Na2SO4 solution to the Ca(NO3)2 solution to increase the sulfate ion concentration just above 9.86 × 10-5 M.
Which of these mixtures could be most easily separated by filtration ?
Explanation:
Filtration is a separation procedure where a mixture is gone through a filter that permits one segment to go through uninhibited yet hinders another segment from going through. We can utilize filtration to isolate a mixture of a solid in a fluid or a solid in a gas. When all is said in done this technique sorts by size, with the filter going about as a barrier that permits littler particles to experience, however, holds bigger particles back. Filtration works best when the solute isn't dissolved in the solvent. For example, sand and water can be separated through filtration as the two mixes don't dissolve up with one another. In any case, sugar and water would not be separated through filtration as they break down with one another.Two boxes are filled with air. The molecules that make up the air in Box A
have more kinetic energy than those in Box B. What can you say about these
boxes?
Answer:
box a is warmer than box b, so the molecules are moving around a lot more
Methane gas reacts with oxygen in a gas stove.
The reaction can be illustrated by the following equation:
Methane plus Oxygen leads to carbon dioxide plus water.
Identify the role of each substance participating in the reaction.
carbon dioxide:
methane:
oxygen:
water:
Hey there!
CH₄ + 2O₂ → CO₂ + 2H₂O
carbon dioxide: product
methane: reactant
oxygen: reactant
water: product
Methane and oxygen are reactants because they are the substances we start with. They are on the side of the equation that the arrow is pointing away from.
Carbon dioxide and water are products because they are the new substances that are the yields of the equation. They are on the side of the equation that the arrow is pointing towards.
Hope this helps!
Answer:
carbon dioxide: product
methane: reactant
oxygen: reactant
water: product
Explanation:
correct on edg
50g of an unknown metal at 100.0 degrees celsius is placed into 150g of water at 20.0 degrees Celsius and the final temperature of the metal and water is 23.3 degrees Celsius. What is the specific heat of the metal?
The specific heat of the unknown metal is approximately 0.36 J/g°C.
First, let's identify the variables given in the problem:
- Mass of the unknown metal (m1) = 50g
- Initial temperature of the metal (T1) = 100.0°C
- Mass of water (m2) = 150g
- Initial temperature of water (T2) = 20.0°C
- Final temperature of the metal and water ([tex]T_f[/tex]) = 23.3°C
To find the specific heat of the metal, we can use the formula:
[tex]\[ q = m \times c \times ΔT \][/tex]
Where:
- ( q ) is the heat absorbed or released
- ( m ) is the mass of the substance (either the metal or water in this case)
- ( c ) is the specific heat capacity of the substance
- ( ΔT ) is the change in temperature
First, we'll find the heat absorbed by the metal using the above formula:
[tex]\[ q_{\text{metal}} = m_{\text{metal}} \times c_{\text{metal}} \times ΔT_{\text{metal}} \]\[ q_{\text{metal}} = 50g \times c_{\text{metal}} \times (T_f - T_1) \]\[ q_{\text{metal}} = 50g \times c_{\text{metal}} \times (23.3°C - 100.0°C) \]\[ q_{\text{metal}} = 50g \times c_{\text{metal}} \times (-76.7°C) \][/tex]
Next, we'll find the heat released by the water as it cools down:
[tex]\[ q_{\text{water}} = m_{\text{water}} \times c_{\text{water}} \times ΔT_{\text{water}} \]\[ q_{\text{water}} = 150g \times 4.18 J/g°C \times (T_f - T_2) \]\[ q_{\text{water}} = 150g \times 4.18 J/g°C \times (23.3°C - 20.0°C) \]\[ q_{\text{water}} = 150g \times 4.18 J/g°C \times 3.3°C \][/tex]
Since the heat lost by the metal equals the heat gained by the water (assuming no heat is lost to the surroundings):
[tex]\[ q_{\text{metal}} = q_{\text{water}} \]\[ 50g \times c_{\text{metal}} \times (-76.7°C) = 150g \times 4.18 J/g°C \times 3.3°C \][/tex]
Now, solve for [tex]\( c_{\text{metal}} \):[/tex]
[tex]\[ c_{\text{metal}} = \frac{150g \times 4.18 J/g°C \times 3.3°C}{50g \times (-76.7°C)} \]\[ c_{\text{metal}} = \frac{2085.3 J}{-3835 J} \]\[ c_{\text{metal}} ≈ 0.36 J/g°C \][/tex]
So, the specific heat of the unknown metal is approximately 0.36 J/g°C.
Complete Question:
50g of an unknown metal at 100.0 degrees celsius is placed into 150g of water at 20.0 degrees Celsius and the final temperature of the metal and water is 23.3 degrees Celsius. What is the specific heat of the metal?
The specific heat of the metal is approximately [tex]\( 0.527 \, \text{J/g}^\circ \text{C} \)[/tex].
For the metal:
[tex]\[ q_{\text{metal}} = m_{\text{metal}} \cdot c_{\text{metal}} \cdot \Delta T_{\text{metal}} \][/tex]
where[tex]\( q_{\text{metal}} \)[/tex] is the heat lost by the metal, \( m_{\text{metal}} \) is the mass of the metal, [tex]\( c_{\text{metal}} \)[/tex] is the specific heat capacity of the metal, and \( \Delta T_{\text{metal}} \) is the change in temperature of the metal.
For the water:
[tex]\[ q_{\text{water}} = m_{\text{water}} \cdot c_{\text{water}} \cdot \Delta T_{\text{water}} \][/tex]
where [tex]\( q_{\text{water}} \)[/tex] is the heat gained by the water, [tex]\( m_{\text{water}} \)[/tex] is the mass of the water, [tex]\( c_{\text{water}} \)[/tex] is the specific heat capacity of water (which is approximately [tex]\( 4.184 \, \text{J/g}^\circ \text{C} \))[/tex], and [tex]\( \Delta T_{\text{water}} \)[/tex] is the change in temperature of the water.
Since the heat lost by the metal is equal to the heat gained by the water, we have:
[tex]\[ q_{\text{metal}} = -q_{\text{water}} \][/tex]
Substituting the expressions for [tex]\( q_{\text{metal}} \)[/tex] and [tex]\( q_{\text{water}} \)[/tex] into this equation gives us:
[tex]\[ m_{\text{metal}} \cdot c_{\text{metal}} \cdot \Delta T_{\text{metal}} = -m_{\text{water}} \cdot c_{\text{water}} \cdot \Delta T_{\text{water}} \][/tex]
Now we can plug in the known values:
[tex]\[ 50 \, \text{g} \cdot c_{\text{metal}} \cdot (23.3^\circ \text{C} - 100.0^\circ \text{C}) = -150 \, \text{g} \cdot 4.184 \, \text{J/g}^\circ \text{C} \cdot (23.3^\circ \text{C} - 20.0^\circ \text{C}) \][/tex]
Solving for [tex]\( c_{\text{metal}} \)[/tex]:
[tex]\[ 50 \cdot c_{\text{metal}} \cdot (-76.7) = -150 \cdot 4.184 \cdot 3.3 \] \[ c_{\text{metal}} = \frac{-150 \cdot 4.184 \cdot 3.3}{50 \cdot (-76.7)} \] \[ c_{\text{metal}} = \frac{-2020.2}{-3835} \] \[ c_{\text{metal}} \approx 0.527 \, \text{J/g}^\circ \text{C} \][/tex]
The answer is: 0.527 \,[tex]\text{J/g}^\circ \text{C}[/tex]"
Decide whether you agree or disagree with the statement, "New theories in science are
accepted quickly as soon as supporting evidence is reported." Justify your reasoning.
Answer:
Time is relative - and science is still arguing about singlet versus doublet Carbenes; they fought over whether Oxygen was “real”, and refused to believe in Radium until one by one they SAW that drop glow! (And affect photographic film).
Explatnation:
Oxidation is common because?
can you answer this for me
Answer:
Algebra is an area in mathematics that uses variables, in the forms of letters and symbols, to act as numbers or quantities in equations and formulas. Geometry is an area in mathematics that studies points, lines, varied-dimensional objects and shapes, surfaces, and solids.
Explanation:
It is your own opinion on which is more difficult. In my opinion, Geometry is more difficult.
Answer: I believe they want you to know the variables; and Newton described what? Force, action, mass.
I think you should read the Laws, and see how the variables, those important pieces, are shown in an equation. That will be of real help to you. Get the very basics down in your head (and on paper), and it will be much easier!
Explanation:
If 10.00 g of iron metal is burned in the presence of excess of O2 how many grams of Fe2O3 will form
14.292 grams of Fe2O3 is formed when 10 gram of iron metal is burned.
Explanation:
The balanced equation for the reaction is to be known so that number of moles taking part can be known.
The balanced chemical equation is
4Fe + 3[tex]O_{2}[/tex]⇒ 2 [tex]Fe{2}[/tex][tex]O{3}[/tex]
From the given weight of iron to be used for the production of [tex]Fe{2}[/tex][tex]O{3}[/tex], number of moles of Fe taking part in the reaction can be known by the formula:
Number of moles= mass ÷ Atomic mass of one mole of the element.
(Atomic weight of Fe is 55.845 gm/mole)
Putting the values in equation
Number of moles = 10 gm ÷ 55.845 gm/mole
= 0.179 moles
Applying the stoichiometry concept
4 moles of Fe gives 2 Moles of Fe2O3
0.179 moles will produce x moles of Fe2O3
So, 2÷ 4 = x ÷ 0.179
2/4 = x/ 0.179
2 × 0.179 = 4x
2 × 0.179 / 4 = x
x = 0.0895 moles
So from 10 grams of iron metal 0.0895 moles of Fe2O3 is formed.
Now the formula used above will give the weight of Fe2O3
weight = atomic weight × number of moles
= 159.69 grams × 0.0895
= 14.292 grams of Fe2O3 formed.
When 10.00 g of iron metal is burned in the presence of excess O2, 14.30 g of Fe2O3 will form.
Explanation:When iron metal reacts with oxygen in the presence of excess oxygen, it forms iron(III) oxide (Fe2O3). The balanced equation for this reaction is:
4Fe + 3O2 → 2Fe2O3
Using the molar mass of iron, we can calculate the number of moles of iron in 10.00 g:
10.00 g Fe ÷ (55.85 g/mol Fe) = 0.1787 mol Fe
Since the reaction ratio is 4:2, we can calculate the number of moles of Fe2O3 formed:
0.1787 mol Fe × (2 mol Fe2O3 ÷ 4 mol Fe) = 0.0894 mol Fe2O3
Finally, we can convert the number of moles of Fe2O3 to grams:
0.0894 mol Fe2O3 × (159.69 g/mol Fe2O3) = 14.30 g Fe2O3
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the solubility in mol/dm3 of 20.2g of potassium trioxonitrate(V)dissolved in 100g of water at room temperature is
Answer:
2.00 mol/dm³Explanation:
Potassium trioxonitrate(V) is KNO₃.
1. Find the molar mass of the solute
The molar mass of KNO₃ is 39.098g/mol + 14.007g/mol + 3×15.999g/mol = 101.102g/mol.
2. Convert the mass of solute, 20.02g, into number of moles
number of moles = mass in grams / molar mass number of moles = 20.2g / 101.102g/mol = 0.1998mol3. Assume that the volume of the solution is equal to the volume of water
This is a rough approximation, but it is necessary since you do not have the density of the solution:
density = mass / volume1.00 g/cm³ = 100g / volumevolume = 100g × 1.00g/cm³ = 100cm³Convert 100cm³ to dm³:
100cm³ × 1dm³ / 1,000cm³ = 0.1 dm³4. Calculate the solubility is mol/dm³
0.1998 mol / 0.1dm³ = 1.998mol/dm³ ≈ 2.00mol/dm³It is rounded to three significant digits to match the choices.
Final answer:
The solubility of potassium trioxonitrate(V) in water at room temperature is 2 mol/dm³, calculated by dividing the moles of the dissolved substance by the volume of the solvent in liters.
Explanation:
To calculate the solubility of potassium trioxonitrate(V), which is potassium nitrate (KNO3), we first need to find the molar mass of KNO3 to convert the given mass to moles. Potassium (K) has an atomic mass of approximately 39 g/mol, nitrogen (N) has an atomic mass of approximately 14 g/mol, and oxygen (O) has an atomic mass of approximately 16 g/mol. Therefore, the molar mass of KNO3 is 39 + 14 + (3 × 16) = 101 g/mol. Now, we take the mass of KNO3, 20.2 g, and divide it by its molar mass to find the number of moles:
Number of moles of KNO3 = 20.2 g / 101 g/mol = 0.2 mol
Since the solvent water has a mass of 100 g, and knowing that the density of water is approximately 1 g/cm³, we can assume that the volume of 100 g of water is approximately 100 mL or 0.1 L. Thus, the solubility of KNO3 in mol/dm³ can be calculated as:
Solubility = Number of moles / Volume in L = 0.2 mol / 0.1 L = 2 mol/dm³
Which is an example of radiation?
Your car parked in the sun is hot when you return.
Hot air rises and cool air moves in to take its place.
Heated water begins circulating in a fish tank.
An example of radiation is a car that gets hot when parked in the sun, as it involves the transfer of heat via infrared waves emitted by the sun. Heat transfer by radiation does not require a medium and is significantly influenced by the emitting object's surface area and temperature. Hence, option A is correct.
Examples of radiation involve the transfer of heat energy without the need for a medium, such as air, to facilitate the transfer. It occurs through electromagnetic waves, and an example of this is when your car parked in the sun is hot when you return. The sun emits infrared waves that transfer heat to the car's surfaces, warming them even without direct contact. Other forms of heat transfer, like convection and conduction, necessitate the movement of air or physical contact, respectively.
Electromagnetic radiation can come in various forms, including microwaves, infrared radiation, and visible light. The Earth is warmed by the sun through radiation, and even the human body emits thermal radiation. Understanding heat transfer by radiation is essential in many applications, from household heating to climate science. The power of radiation is significantly influenced by the emitting object's surface area and is dramatically affected by its absolute temperature (as per the relationship P × T⁴).