Use the equation below to identify the value fo each variable for the circle.

Standard form equation of a Circle
[tex](x-h)^2+(y-v)^2=r^2[/tex]
(h,v) = center
r = radius

h= ???
v = ???
r = ???

Then, write the standard form equation of the circle.

The phase shift is 7.2 right

Answer: Option A.

Step-by-step explanation:

You need to remember the Quotient property of powers, which states the following:

[tex]\frac{p^m}{p^n}=p^{(m-n)}[/tex]

Then, given the expression [tex]\frac{a^3b^2}{a^2b}[/tex], you need to apply this property to simplify this expression.

Therefore, you get:

[tex]=a^{(3-2)}b^{(2-1)}\\\\=a^1b^1\\\\=ab[/tex]

As you can observe, this matches with the option A.

Answer:

The correct answer is option A.  ab

Step-by-step explanation:

Points to remember

Identities

Xᵃ * Xᵇ = X⁽ᵃ ⁺ ᵇ⁾

X⁻ᵃ = 1/Xᵃ

Xᵃ/Xᵇ = X⁽ᵃ ⁻ ᵇ⁾

To find the correct answer

It is given that,

a³b²/a²b

By using above identities we can write,

a³b²/a²b = a⁽³ ⁻ ²⁾b⁽² ⁻ ¹⁾

 = a¹b¹ = ab

Therefore the answer is ab

The correct option is option A.  ab

Let [tex]z=-\sqrt3+i[/tex]. Then

[tex]|z|=\sqrt{(-\sqrt3)^2+1^2}=2[/tex]

[tex]z[/tex] lies in the second quadrant, so

[tex]\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6[/tex]

So we have

[tex]z=2e^{i5\pi/6}[/tex]

and the fourth roots of [tex]z[/tex] are

[tex]2^{1/4}e^{i(5\pi/6+k\pi)/4}[/tex]

where [tex]k\in\{0,1,2,3\}[/tex]. In particular, they are

[tex]2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}[/tex]

[tex]2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}[/tex]

[tex]2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}[/tex]

[tex]2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}[/tex]

Answer:

  4/r

Step-by-step explanation:

The side lengths s of an equilateral triangle inscribed in a circle of radius r will be ...

  s = r√3

The perimeter of the triangle will be 3s.

The area of the triangle will be s^2·(√3)/4.

Then the ratio P/A is ...

  P/A = (3s)/(s^2·(√3)/4) = (4√3)/s

Substituting the above expression for s, we have ...

  P/A = 4√3/(r√3)

  P/A = 4/r

The expression for the ratio of the perimeter to the area of an equilateral triangle, whose vertices lie on a circle with radius r, is 2√3/r.

The ratio of the perimeter to the area of an equilateral triangle is derived using the formulae related to the triangle and the circle on which it lies. Let's start with the formulas for the circumference of a circle C = 2πr, and the area of an equilateral triangle A = (√3/4)*s², where s is the side length of the triangle.

As the vertices of the triangle are on the circle, the side length s is equal to the diameter of the circle. Therefore, s = 2r. Also, the perimeter P = 3*s = 6r. Substituting the terms for A and P, we find that P/A = 6r/((√3/4)*(2r)²) = (24/√3)/4r = 6/√3r. This simplifies to 2√3/r after rationalizing the denominator.

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To find the exact length of the curve defined by [tex]\( x = 9 + 9t^2 \) and \( y = 6 + 6t^3 \) for \( 0 \leq t \leq 4 \):[/tex]

1. Compute derivatives: [tex]\( \frac{dx}{dt} = 18t \) and \( \frac{dy}{dt} = 18t^2 \).[/tex]

2. Substitute into arc length formula:

[tex]\[L = \int_{0}^{4} \sqrt{(18t)^2 + (18t^2)^2} \, dt = \int_{0}^{4} 18t \sqrt{1 + t^2} \, dt\][/tex]

3. Use substitution [tex]\( u = 1 + t^2 \), \( du = 2t \, dt \):[/tex]

[tex]\[L = 9 \int_{1}^{17} \sqrt{u} \, du = 9 \left[ \frac{2}{3} u^{3/2} \right]_{1}^{17} = 6 (\sqrt{4913} - 1)\][/tex]

Final answer: The exact length of the curve is [tex]\( \boxed{6 (\sqrt{4913} - 1)} \).[/tex]

To find the exact length of the curve defined by the parametric equations [tex]\( x = 9 + 9t^2 \) and \( y = 6 + 6t^3 \) for \( 0 \leq t \leq 4 \),[/tex] we use the arc length formula for parametric curves:

[tex]\[L = \int_{a}^{b} \sqrt{\left( \frac{dx}{dt} \right)^2 + \left( \frac{dy}{dt} \right)^2} \, dt\][/tex]

Here, ( a = 0 ) and ( b = 4 ). First, we need to find the derivatives

Given [tex]\( x = 9 + 9t^2 \):[/tex]

[tex]\[\frac{dx}{dt} = \frac{d}{dt}(9 + 9t^2) = 18t\][/tex]

Given [tex]\( y = 6 + 6t^3 \):[/tex]

[tex]\[\frac{dy}{dt} = \frac{d}{dt}(6 + 6t^3) = 18t^2\][/tex]

Next, we substitute these derivatives into the arc length formula:

[tex]\[L = \int_{0}^{4} \sqrt{(18t)^2 + (18t^2)^2} \, dt\][/tex]

Simplify the expression inside the square root:

[tex]\[(18t)^2 + (18t^2)^2 = 324t^2 + 324t^4 = 324t^2 (1 + t^2)\][/tex]

Therefore, the integrand becomes:

[tex]\[L = \int_{0}^{4} \sqrt{324t^2 (1 + t^2)} \, dt = \int_{0}^{4} \sqrt{324} \sqrt{t^2 (1 + t^2)} \, dt\][/tex]

[tex]\[L = \int_{0}^{4} 18 \sqrt{t^2 (1 + t^2)} \, dt = \int_{0}^{4} 18 t \sqrt{1 + t^2} \, dt\][/tex]

We can simplify this integral by using the substitution[tex]\( u = 1 + t^2 \), hence \( du = 2t \, dt \). When \( t = 0 \), \( u = 1 \), and when \( t = 4 \), \( u = 17 \):[/tex]

[tex]\[L = 18 \int_{0}^{4} t \sqrt{1 + t^2} \, dt = 18 \int_{1}^{17} \sqrt{u} \cdot \frac{1}{2} \, du\][/tex]

[tex]\[L = 9 \int_{1}^{17} \sqrt{u} \, du = 9 \int_{1}^{17} u^{1/2} \, du\][/tex]

Integrate[tex]\( u^{1/2} \):[/tex]

[tex]\[\int u^{1/2} \, du = \frac{2}{3} u^{3/2}\][/tex]

Evaluate the definite integral:

[tex]\[L = 9 \left[ \frac{2}{3} u^{3/2} \right]_{1}^{17} = 9 \left( \frac{2}{3} \left[ 17^{3/2} - 1^{3/2} \right] \right)\][/tex]

[tex]\[L = 9 \cdot \frac{2}{3} \left( 17^{3/2} - 1 \right) = 6 \left( 17^{3/2} - 1 \right)\][/tex]

[tex]\[L = 6 \left( \sqrt{17^3} - 1 \right) = 6 \left( \sqrt{4913} - 1 \right)\][/tex]

Thus, the exact length of the curve is:

[tex]\[\boxed{6 (\sqrt{4913} - 1)}\][/tex]

Answer:

Step-by-step explanation:

1/2log8,342 is almost correct.  Should enclose that "1/2" inside parentheses.  The "1/2" stems from our needing to find the value of the square root of 8342.

Answer:  The required answer is [tex]\dfrac{1}{2}\log 8342.[/tex]

Step-by-step explanation:  We are given to use the logarithmic equation to find [tex]\sqrt{8342}.[/tex]

We will be using the following logarithmic property :

[tex]\log a^b=b\log a.[/tex]

Let us consider that

[tex]x=\sqrt{8342}~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

Applying logarithm on both sides of equation (i), we have

[tex]\log x=\log{\sqrt{8342}\\\\\Rightarrow \log x=\log(8342)^\frac{1}{2}\\\\\Rightarrow \log x=\dfrac{1}{2}\log 8342.[/tex]

Thus, the required answer is [tex]\dfrac{1}{2}\log 8342.[/tex]

Answer:

I think the answer is "How much pineapple juice is needed to make 5 pitchers of punch?"

Step-by-step explanation:

I believe it's the second one, from 5 cups of juice, since you would divide 5 by 3 1/2

Answer:

Step-by-step explanation:

You need the 6th row of Pascal's triangle which contains the numbers 1, 5, 10, 10, 5, 1

Fill in the expansion as follows, using those numbers and the fact that a = 1 and b = 1:

[tex]1(1a)^5(1b)^0+5(1a)^4(1b)^1+10(1a)^3(1b)^2+10(1a)^2(1b)^3+5(1a)^1(1b)^4+1(1a)^0(1b)^5[/tex]

That simplifies down nicely to

[tex]a^5+5a^4b+10a^3b^2+10a^2b^3+5ab^4+b^5[/tex]

Those are fun!  Pascal's triangle is one of the coolest things ever!

To expand (a+b)^5 using Pascal's Triangle, we can use the Binomial Theorem. The expansion can be written as (a^5) + 5(a^4)(b) + 10(a^3)(b^2) + 10(a^2)(b^3) + 5(a)(b^4) + (b^5).

To expand the binomial (a+b)^5 using Pascal's Triangle, we will use the Binomial Theorem. According to the theorem, the expansion of (a+b)^n can be written as:

(a+b)^n = (nC0)(a^n)(b^0) + (nC1)(a^(n-1))(b^1) + (nC2)(a^(n-2))(b^2) + ... + (nCn)(a^0)(b^n)

For (a+b)^5, the expansion would be:

(a+b)^5 = (5C0)(a^5)(b^0) + (5C1)(a^4)(b^1) + (5C2)(a^3)(b^2) + (5C3)(a^2)(b^3) + (5C4)(a^1)(b^4) + (5C5)(a^0)(b^5)

Simplifying further, we get:

(a+b)^5 = (a^5) + 5(a^4)(b) + 10(a^3)(b^2) + 10(a^2)(b^3) + 5(a)(b^4) + (b^5)

i’m petty sure you add them all up

Answer:

$2,500

Step-by-step explanation:

The situation states that the employees earn vacation pay at the rate of one day per month and their daily wage is $100. Also, it states that in july 25 employees qualify for one vacation day. So, in order to determine the amount of vacation benefit expense for july, you need to multiply the daily wage for the number of employees that got the benefit:

$100*25= $2,500

Answer:

(6 , -3)

Step-by-step explanation:

Given in the question,

point J(8,-6)

x1 = 8

y1 = -6

point L(-2,9)

x2 = -2

y2 = 9

Location of point K which is 1/5 of the way from J to L

which means ratio of point K from J to L is 1 : 4

a : b

1 : 4

xk = [tex]x1+\frac{a}{a+b}(x2-x1)[/tex]

yk = [tex]y1+\frac{a}{a+b}(y2-y1)[/tex]

Plug values in the equation

xk = 8 + (1)/(1+4) (-2-8)

xk = 6

yk = -6 (1)/(1+4)(9+6)

yk = -3

Answer:

what he said

Step-by-step explanation:

The area of the cross section that is parallel to side PQRS in this rectangular box is: A. 12 square units.

In Mathematics and Geometry, the area of a rectangle can be calculated by using the following mathematical equation:

A = LW

Where:

A represent the area of a rectangle.

W represent the width of a rectangle.

L represent the length of a rectangle.

By substituting the given side lengths into the formula for the area of a rectangle (PQRS), we have the following;

Area of rectangle = PQ × QR

Area of rectangle = 4 × 3

Area of rectangle = 12 square units.

Complete Question:

What is the area of the cross section that is parallel to side PQRS in this rectangular box?

A. 12 square units

B. 16 square units C. 30 square units D. 40 square units

The volume of the rectangular box is 60 cubic units.

Given that the area of one side of the box is 12 and the area of another side is 15, and both dimensions are integers greater than 1, we can find the dimensions and the volume of the box as follows:

Possible dimensions:

For the side with area 12, the possible integer dimensions are (3, 4) and (4, 3) since 3 x 4 = 4 x 3 = 12.

For the side with area 15, the possible integer dimensions are (3, 5) and (5, 3) since 3 x 5 = 5 x 3 = 15.

Valid dimensions combination:

We need to find a combination of dimensions where the two sides mentioned above are not the same.

The only valid combination is (3, 4) for the side with area 12 and (5, 3) for the side with area 15.

Volume of the box:

The volume of the box is calculated by multiplying the length, width, and height.

In this case, the volume is 3 (length) x 4 (width) x 5 (height) = 60 cubic units.

Therefore, the volume of the rectangular box is 60 cubic units.

Question

The dimensions of a rectangular box are integers greater than 1. If the area of one side of this box is 12 and the area of another side 15, what is the volume of the box?

Answer:

The answer is the letter B.

The first column represents the x-values, and the second row represents the y-values.

For that reason, if we have:

2x - 7y = -1

x + 3y = -5

Then, the matrix will be given by:

[ 2      -7

 1        3]

Then, the third colum will be the equality:

[ -1

 -5]

So the correct option is the letter B.

B

[tex]2x - 7y = - 1 \\ \\ \\ 1. \: 2x = - 1 + 7y \\ 2. \: 2x = 7y - 1 \\ 3. \: x = \frac{7y - 1}{2} [/tex]

1.25 meters im pretty sure. i hope i helped

Answer:

  a.  12/37

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you ...

  Sin = Opposite/Hypotenuse

  sin(A) = BC/AB = 12/37

The value of sin A in triangle ABC, where AB = 37 and BC = 12, is 12/37.

In a right-angled triangle, the sine of one of the non-right angles (A in this case) is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse. The hypotenuse is the side opposite the right angle (side AB in this case).

To find the value of sin A in triangle ABC, we can use the formula:

sin A = BC / AB

Given that AB = 37 and BC = 12, we have:

sin A = 12 / 37

So, the correct answer is: a. 12/37

To know more about sin A, refer here:

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Answer:

c

Step-by-step explanation:

Answer:

The area is 154 cm²

Step-by-step explanation:

Since the formula for the area of a circle is pi times the radius squared, divide the diameter in half to get the radius (7). Then, square the radius (49). Next, multiply that by pi (153.938). After that round to the nearest whole number (154). Hope that helps!

-Kyra

Answer:

A = 154 cm^2

Step-by-step explanation:

We know the diameter of the circle

We need to find the radius

d = 2r

14 = 2r

Divide by 2

14/2 = 2r/2

7=r

Now we can use the formula for area

A = pi r^2

A = pi (7)^2

A = 49pi

Replace pi with 3.14

A = 49(3.14)

A = 153.83

Rounding to the nearest whole number

A = 154 cm^2

Answer: y=12.287

Step-by-step explanation:

Answer:

y = 12.3 cm

Step-by-step explanation:

Using the cosine ratio in the right triangle to solve for y

cos35° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{y}{15}[/tex]

Multiply both sides by 15

15 × cos35° = y, thus

y ≈ 12.3 cm

Answer:

174 cm²

Step-by-step explanation:

The figure is composed of a rectangle and a triangle, so

area of figure = area of rectangle + area of triangle

area of rectangle = 8 × 15 = 120 cm²

area of triangle = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the height )

here b = 12 and h = 15 - 6 = 9 cm

area of triangle = 0.5 × 12 × 9 = 6 × 9 = 54 cm²

Hence

area of figure = 120 + 54 = 174 cm²

The answer is:

The lowest term will be:

[tex]\frac{7}{8}[/tex]

Reducing a fraction to its lowest term means writing it its simplified form, so, performing the operation and simplifying we have:

[tex]\frac{1}{4}+\frac{5}{8}=\frac{(1*8)+(4*5)}{4*8}\\\\\frac{(1*8)+(4*5)}{4*8}=\frac{8+20}{32}=\frac{28}{32}[/tex]

Now, to reduce the fraction to its lowest term, we need to divide both numerator and denominator by a common number, for this case, it will be "4" since is the biggest whole number that both numerator and denominator can be divided by, so, we have:

[tex]\frac{\frac{28}{4} }{\frac{32}{4}}=\frac{7}{8}[/tex]

Hence, we have that the lowest term will be:

[tex]\frac{7}{8}[/tex]

Have a nice day!

Answer:

50 teachers

Step-by-step explanation:

step 1

Find the number of teachers for a ratio of 1:12

1/12=x/2,400

x=2,400/12=200 teachers

step 2

Find the number of teachers for a ratio of 5:48

5/48=x/2,400

x=2,400*5/48=250 teachers

step 3

Find the difference

250-200=50 teachers

The number of teachers who joined the school is 50.

Step 1:

Let's denote the number of teachers initially as x and the number of students initially as 12x, based on the initial ratio of 1 teacher to 12 students.

So, initially, the total number of people in the school is x + 12x = 13x.

Step 2:

After some teachers join the school, the new ratio becomes 5 teachers to 48 students.

Now, the number of teachers is [tex]\(x + \text{number of teachers who joined}\)[/tex], and the number of students remains 12x.

Step 3:

So, the new total number of people in the school becomes [tex]\(x + \text{number of teachers who joined} + 12x\).[/tex]

According to the new ratio, [tex]\(\frac{x + \text{number of teachers who joined}}{12x} = \frac{5}{48}\)[/tex].

We can set up the equation:

[tex]\[\frac{x + \text{number of teachers who joined}}{12x} = \frac{5}{48}\][/tex]

Step 4:

Cross-multiply:

[tex]\[48(x + \text{number of teachers who joined}) = 5 \times 12x\][/tex]

Simplify:

[tex]\[48x + 48(\text{number of teachers who joined}) = 60x\][/tex]

[tex]\[48(\text{number of teachers who joined}) = 12x\][/tex]

Divide both sides by 48:

[tex]\[\text{number of teachers who joined} = \frac{12x}{48} = \frac{x}{4}\][/tex]

Step 5:

Given that there are initially 2400 students, we can set up another equation:

[tex]\[12x = 2400\][/tex]

Solve for x:

[tex]\[x = \frac{2400}{12} = 200\][/tex]

Now, plug in the value of x to find the number of teachers who joined:

[tex]\[\text{number of teachers who joined} = \frac{x}{4} = \frac{200}{4} = 50\][/tex]

Therefore, the number of teachers who joined the school is 50.

The amount Malia earns can be shown as an addition sentence by multiplying the price of the wristbands by the quantity sold. The sum of this addition is $10, which is what Malia earned on the first day of the fundraiser. This sum can be visualized on a number line with four equal jumps of $2.50 leading to a sum of $10.

a. The amount Malia earns can be represented as an addition sentence by multiplying the price of the wristbands ($2.50) by the number of wristbands sold (4). The addition sentence would look like this: $2.50 + $2.50 + $2.50 + $2.50.

b. The sum of the addition sentence above is $10. This means that Malia has earned $10 on the first day of the fundraiser by selling 4 wristbands at $2.50 each.

c. The sum on a number line can be shown by marking off four equal jumps of $2.50 starting from zero, which leads you to the total sum of $10 at the fourth jump.

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ANSWER

[tex]a_ {10} = \frac{25}{32} [/tex]

EXPLANATION

The given geometric sequence is

400, 200, 100...

The first term is

[tex]a_1=400[/tex]

The common ratio is

[tex]r = \frac{200}{400} = \frac{1}{2} [/tex]

The nth term is

[tex]a_n=a_1( {r}^{n - 1} )[/tex]

We substitute the known values to get;

[tex]a_n=400( \frac{1}{2} )^{n - 1} [/tex]

[tex]a_ {10} =400( \frac{1}{2} )^{10 - 1} [/tex]

[tex]a_ {10} =400( \frac{1}{2} )^{9} [/tex]

[tex]a_ {10} = \frac{25}{32} [/tex]

Answer:

  5

Step-by-step explanation:

Among the 20 digits shown, each digit appears in the list twice except 0 and 1 appear 3 times and 6 and 9 appear once. That means ...

So, if 1 and 2 represent red candies, there are 3+2 = 5 red candies in the simulated random sample of 20 candies.

_____

Comment on the question

The simulation makes sense only if it represents taking a single candy from each of 20 packages (of unknown quantity of candies). That is, it seems we cannot answer the question, "how many red candies will be in the packages?" We can only answer the question, "how many of the simulated candies are red?"

Answer:

The height of the rectangular prism is [tex]58.36\ m[/tex]

Step-by-step explanation:

we know that

The surface area of the rectangular prism is equal to

[tex]SA=2B+PH[/tex]

where

B is the area of the rectangular base

P is the perimeter of the rectangular base

H is the height of the prism

Find the area of the base B

[tex]B=14.2*15=213\ m^{2}[/tex]

Find the perimeter of the base P

[tex]P=2(14.2+15)=58.4\ m[/tex]

we have

[tex]SA=3,834\ m^{2}[/tex]

substitute and solve for H

[tex]SA=2B+PH[/tex]

[tex]3,834=2(213)+(58.4)H[/tex]

[tex]3,834=426+(58.4)H[/tex]

[tex]H=(3,834-426)/(58.4)[/tex]

[tex]H=58.36\ m[/tex]

Answer:

x = 1 and y = 2

Step-by-step explanation:

Let apples are represented by x

and let oranges are represented by y

You purchase 5 pounds of apples and 2 pounds of oranges for $9. This line in equation format can be written as:

5x + 2y = 9

Your friend purchases 5 pounds of apples and 6 pounds of oranges for $17.

This line in equation format can be written as:

5x + 6y = 17

Now we have two equations:

5x + 2y = 9 -> eq (i)

5x + 6y = 17 -> eq(ii)

We can solve these equations to find the value of x and y.

Subtracting eq(i) from eq(ii)

5x + 6y = 17

5x + 2y = 9

-     -         -

_________

0+4y= 8

=> 4y = 8

y= 8/4

y = 2

Now, putting value of y in eq (i)

5x + 2y = 9

5x +2(2) = 9

5x +4 = 9

5x = 9-4

5x = 5

x = 1

so, x = 1 and y = 2

the answer Is B) 3c(3ab+a+4b)

Answer

B) 3c(3ab+a+4ab)

Step-by-step explanation:

First find the common factor of (9abc+3ac+12bc) (the common factor is 3c because 3 is the greatest common factor of the coeffecients given and c is in all the terms of the variables given)

then, put 3c outside the parenthesis and factor the terms.

3c(3ab+a+4ab)

when you multiply 3c(3ab+a+4ab) you should get the polynomial that the question gave you. (9abc+3ac+12bc)

Answer:

d

Step-by-step explanation:

Here the sum of 5+1 golf scores, divided by 6, must be 118:

120 + 112 + 130 + 128 + 124 + x

--------------------------------------------- = 118

                         6

Here, 120 + 112 + 130 + 128 + 124 + x is the total number of points needed to have an average of 118.  Answer d is the correct one.

Answer:

Jacob has golf scores of 120, 112, 130, 128, and 124.

He wants to have an average golf score of 118.

a. Find the sum of all the numbers in the problem, 120+112+130+128+124+118.

[tex]120+112+130+128+124+118[/tex]

= 732

b. Find the average score for the five golf games that Jacob has played.

[tex]\frac{120+112+130+128+124}{5}[/tex]

= 122.8

c. Determine the number of points that he needs in his next golf game.

Jacob will need a golf score of 94  in next game to achieve the average of 118.

Total score = [tex]120+112+130+128+124+x[/tex]

number of matches = 6

Average score = [tex]\frac{614+x}{6}=118[/tex]

[tex]614+x=708[/tex]

[tex]x=708-614[/tex]

x = 94

d. Determine how many total points are needed to have an average of 118.

Total points needed are [tex]614+94=708[/tex]

Perimeter = 2w+2l. 2(6)+2l = 36 subtract 12 to get 2l=24 then divide by 2 so the length is 12 inches

Answer:

B. 1/2 tespoon of salt per 1 teaspoon of baking soda.

Step-by-step explanation:

If you're starting with 1/2 tsp of baking soda and 1/4 tsp of salt, you can multiply that by two and still have the same ratio of salt to baking soda.

Answer:

B. 1/2 tespoon of salt per 1 teaspoon of baking soda.

Step-by-step explanation:

If you're starting with 1/2 tsp of baking soda and 1/4 tsp of salt, you can multiply that by two and still have the same ratio of salt to baking soda.

Answer:

The value of x is 45

Step-by-step explanation:

The value of x is 45 degrees as per the concept of the polygon's interior angle.

To find the value of x in the irregular pentagon with interior angles measuring 90 degrees, 112 degrees, x degrees, (3x + 10) degrees, and 148 degrees, we can use the fact that the sum of the interior angles in any pentagon is 540 degrees.

Summing up the given interior angles, we have:

90 + 112 + x + (3x + 10) + 148 = 540

Combine like terms:

4x + 360 = 540

Subtract 360 from both sides:

4x = 180

Divide both sides by 4:

x = 45

Therefore, the value of x is 45 degrees.

To learn more about the interior angles;

brainly.com/question/10638383

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