[tex]\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]
[tex]\bf \cfrac{small}{large}\qquad \stackrel{ratio}{\cfrac{3}{4}}\qquad \qquad \cfrac{3}{4}=\stackrel{areas}{\cfrac{\sqrt{a}}{\sqrt{100}}}\implies \cfrac{3}{4}=\cfrac{\sqrt{a}}{10}\implies 30=4\sqrt{a} \\\\\\ \cfrac{30}{4}=\sqrt{a}\implies \left( \cfrac{30}{4} \right)^2=a\implies \cfrac{900}{16}=a\implies \cfrac{225}{4}=a[/tex]
The area of the smaller figure is 225/4 or 56.25 square units if the two similar figures have a side ratio of 3:4.
What is the ratio?It is described as the comparison of two quantities to determine how many times one obtains the other. The proportion can be expressed as a fraction or as a sign: between two integers.
Let's suppose the area of the smaller figure is x
Area of larger figure = 100 square units
The ratio of the areas:
= x/100
We also have:
Two similar figures have a side ratio of 3:4
= 3/4
Square it we will get ratio of the area
= 9/16
x/100 = 9/16
x = 900/16 = 225/4 or 56.25 square units
Thus, the area of the smaller figure is 225/4 or 56.25 square units if the two similar figures have a side ratio of 3:4.
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The graph shows the commission earned for each week of employment.
Which statements are true?
Select EACH correct answer.
A. The amount of the commission earned decreases between the fifth and eleventh week of employment.
B. The commission earned increased in the beginning of employment and after week 11.
C. A commission of $320 for a week was earned three times over the first 10 weeks.
D. About $110 in commission were initially earned.
E. The end behavior is the same on both sides of the graph.
Answer:
A, B, D
Step-by-step explanation:
A is true. From week 5 to week 11, the curve goes down.
B is true. After week 11, the curve goes up.
C is false. The curve passes $320 twice in the first ten weeks, not three times.
D is true. The curve starts at about $110.
E is false. As time increases, the graph goes up. As time decreases, the graph goes down.
About $110 in commission were initially earned and The commission earned increased in the beginning of employment and after week 11.
What is a function?A function is an expression used to show the relationship between two or more numbers and variables.
From the graph:
About $110 in commission were initially earned and The commission earned increased in the beginning of employment and after week 11.
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What statement represents the reasonable time when the basketball is in the air
The ball hits the ground at 2.5sec
The answers aren’t all showing but neither of the top two showing are correct. Pick the answer that fits with the ball being in the air for 2.5sec.
A hypothetical population includes 1 million men and 1 million women. Suppose that a sample of this population of 100 included 20 men and 80 women. Identify the misuse of statistical data.
A) Sample bias
B) Loaded questions
C) Data manipulation
D) Overgeneralization
Answer:
A) Sample bias
Step-by-step explanation:
If a sample of 100 participants includes 20 men and 80 women, then the sample is biased. Women account for;
(80/100)*100 = 80% of the total participants while men only for 20%.
The sample does not represent the entire population in fair proportions hence the sample is biased
A cake has circumference of 25 1/7 inches. What is the area of the cake? Use 22/7 to approximate π. Round to the nearest hundredth. Enter your answer in the box.
Answer:
50.29 in^2
Step-by-step explanation:
From the circumference we need to find the radius.
Since C = 2*pi*r, r = C / (2*pi).
Here, with C = 25 1/7 in, r = (25 1/7 in) / [ 2(22/7) ], or r = 4 in
The area of the cake is A = pi*r^2, or (here) A = (22/7)(4 in)^2 = 50.29 in^2
let f(x)=3x+8 and g(x)=x^2 find (fxg)(x)
Final answer:
To find the product (f × g)(x), simply multiply the functions f(x) = 3x + 8 and g(x) = x^2 together. The result is (f × g)(x) = 3x^3 + 8x^2.
Explanation:
To find the product (f × g)(x), you need to multiply the function f(x) by the function g(x). Given f(x) = 3x + 8 and g(x) = x^2, the product (also known as the composition of functions) is obtained by multiplying these two functions together.
The product is calculated as follows:
(f × g)(x) = f(x)×g(x) = (3x + 8)×(x^2).
Now, distribute the x^2 term across the terms inside the parentheses:
(f × g)(x) = 3x^3 + 8x^2.
This is the simplified form of the product of the two functions.
Help asap
What is the approximate area of a sector given Θ≈212 with a radius of 45 m?
Question 1 options:
2613.59 m²
3744.45 m²
3371.26 m²
2928.36 m
Answer:
[tex]3,744.45\ m^{2}[/tex]
Step-by-step explanation:
we know that
The area of a sector is equal to
[tex]A=\frac{\theta}{360\°}\pi r^{2}[/tex]
where
[tex]\theta[/tex] ------> is the angle in degrees
r is the radius of the circle
In this problem we have
[tex]r=45\ m[/tex]
[tex]\theta=212\°[/tex]
assume
[tex]\pi =3.14[/tex]
substitute the values
[tex]A=\frac{212\°}{360\°}(3.14)(45)^{2}[/tex]
[tex]A=3,744.45\ m^{2}[/tex]
Each of
6
students reported the number of movies they saw in the past year. This is what they reported:
6, 8, 16, 7, 19, 20
Find the mean and median number of movies that the students saw.
The median is 12.
The arithmetic mean is 12.7
The geometric mean is 11.3
The drama club sold 65 fewer adult tickets at $5 each than they did student tickets for $3 each. The total value of all the tickets was $675. How many adult and children tickets were sold?
Answer:
adults ticket sold= 60
student tickets =125
Step-by-step explanation:
So we need to make a system of equations. Lets say the variable a stands for adults tickets and the variable s stands for student tickets. Our first equation is going to be
s-a=65
that is because there are 65 more student tickets than adults.
the second equation is going to be
3s+5a=675
that is because the tickets will add up 675.
Now we have to make sure one of the variable cancels out when we add them together. So we have to multiply the first equation by 5.
5[s-a=65]
3s+5a=675
So then we end up with
5s-5a=325
3s-5a=675
We need to add them together and we end up with.
8s=1000
We need to divide by 8
s then equals 125.
So there are 125 students tickets.
We now plug 125 back into one of the equations. To make things easy lets to the first equation.
s-a=65
125-a=65
move the 125 over
-a=-60
multiply by a negative
a=60
So you have 60 adults tickets
Final answer:
By setting up and solving a system of equations, it's determined that 125 student tickets and 60 adult tickets were sold.
Explanation:
The task involves solving a system of equations to find out how many adult and student tickets were sold. Let the number of student tickets be s and the number of adult tickets be a. We have two pieces of information: First, the drama club sold 65 fewer adult tickets than student tickets, which translates to a = s - 65. Second, the total revenue from ticket sales was $675, with student tickets selling at $3 each and adult tickets at $5 each, giving us the equation 3s + 5a = 675.
To solve for s and a, we substitute the first equation into the second to get 3s + 5(s - 65) = 675. Simplifying this equation yields 8s - 325 = 675, so s = 125. Substituting s = 125 back into the first equation, a = 125 - 65, we find a = 60. Therefore, 125 student tickets and 60 adult tickets were sold.
12 - 6x - 5 = -23 *
6
5
-5
-6
2x - 4 - 4x = 8 *
16
6
2
-6
4x + 4 - 8x = 16 *
1 point
5
3
-3
-5
-6 + 3x - 5x = 24 *
24
15
-6
-15
3x + 10 + 5x = 50 *
12
5
-5
-12
Answer:
1.) 5
2.) -6
3.) -3
4.) -15
5.) 5
Check math problem?
a vector has both a magnitude and a
Direction?
Scalar?
Reverse?
number?
I choose Direction, but not sure.
Answer:
Step-by-step explanation:
What sets a vector apart from a scalar is that the vector has both magnitude (length) and direction, whereas a scalar has only magnitude, no direction.
Answer:
Direction is correct
Step-by-step explanation:
A scalar quantity has magnitude but no direction while
a vector has both magnitude and direction
A sporting goods store received an order of 80 baseball caps, of which 12 were green. If 1 of the 80 caps is selected at random, what is the probability it will NOT be green?
15%
68%
85%
88%
Answer:
85%
Step-by-step explanation:
If the sporting goods store received a lot of 80 baseball caps... and 12 of them were green that means that 68 (80-12) were NOT green.
Thus, the probably to randomly pick up a cap that is NOT green is 68 out of 80...
68/80 = 17/20 = 85%
Find the product. 3(x + 4) (x - 5) A. 3x2 ? 20x B. 3x2 ? 11x ? 20 C. 3x2 ? 3x ? 60 D. 3x2 ? x ? 20
For this case we must find the product of the following expression:[tex]3 (x + 4) (x-5)[/tex]
We must apply distributive property to the terms of the first parenthesis:
[tex](3x + 12) (x-5) =[/tex]
Again we apply the distributive property:
[tex]3x ^ 2-15x + 12x-60 =\\3x ^ 2-3x-60[/tex]
ANswer:
[tex]3x ^ 2-3x-60[/tex]
Step 1: Distribute the 3 to x and 4
(3x + 12)(x - 5)
Step 2: FOIL (First, Outside, Inside, Last)
Multiply the first of the values in the parentheses together
(3x + 12) (x - 5)
[tex]3x^{2}[/tex]
Multiply the outside values in the parentheses together
(3x + 12)(x - 5)
-15x
Multiply the inside values of the parentheses together
(3x + 12)(x - 5)
12x
Multiply the last values of the parentheses together
(3x + 12)(x - 5)
-60
Step 3: Add all the FOIL values together
3[tex]x^{2}[/tex] + (-15x) + 12x + (-60)
Step 4: Combine like terms
3[tex]x^{2}[/tex] + (-15x) + 12x + (-60)
3[tex]x^{2}[/tex] - 3x - 60
Hope this helped!
What is the logarithmic function modeled by the following table? x f(x) 9 2 27 3 81 4
Answer:
Required logarithmic function is :
[tex]f\left(x\right)=\log_3\left(x\right)[/tex]
Step-by-step explanation:
We have been fiven that table for the logarithmic function is:
x f(x)
9 2
27 3
81 4
which can be rewritten as:
x f(x)
3^2 2
3^3 3
3^4 4
Which are basically powers of 3
So we can use logarithmic function as
[tex]\log_3\left(9\right)=\log_3\left(3^2\right)=2\log_3\left(3\right)=2(1)=2[/tex]
Hence required logarithmic function is :
[tex]f\left(x\right)=\log_3\left(x\right)[/tex]
HELP PLEASE! I’m having a hard time answering this.
Joshua has a ladder that is 17 ft long. He wants to lean the ladder against a vertical wall so that the top of the ladder is 16.5 ft above the ground. For safety reasons, he wants the angle the ladder makes with the ground to be no greater than 70*. Will the ladder be safe at this height? Show work.
The question is asking to solve a problem that'll "add up", or in other words, makes sense; through the use of Trigonometric functions. The leaning ladder is the hypotenuse of 17ft, adjacent to that is a wall that measures 16.5ft above the ground. The angle both sides make must be <=70°. The function here is Opposite over Hypotenuse i.e 16.5/17 . We use the inverse operation of Sin which is Sin^(-1) to find if the angle is < or = to 70°. Using a calculator, we find the angle to be 76.06°, which is > more than, 70°.
Thus, the ladder will not be safe for its height and therefore won't make sense.
How many different strings can be formed by rearranging the letters in the word troposphere?
Step-by-step explanation:
The letters of the word troposphere can be sorted to be:
ee h oo pp rr s t
with 7 distinct letters of which 4 are in pairs for a total of 11 letters.
The number of words that can be formed from n distinct letters
= n!/(1!1!1!....1!) [n times in the denominator]
The number of words that can be formed from n letters of which 2 are duplicated and the rest distinct is
= n!/(2!1!1!....1!) [n-1 times 1!]
Similarly, the number of words that can be formed from 11 letters, of which there are 4 pairs of duplicated letters is
N=11! / (2!2!2!2!1!1!1!)
= 39916800 / (2*2*2*2*1*1*1)
= 2494800
For the function given below, find a formula for the riemann sum obtained by dividing the interval [a,b] into n equal subintervals and using the right-hand endpoint for each c subscript k. then take a limit of this sum as n right arrow infinity to calculate the area under the curve over [a,b]. f(x)equals2x over the interval [2,4].
The Riemann sum for f(x) = 2x on [2,4] is evaluated as n approaches infinity to give the integral from 2 to 4 of 2x dx, resulting in an area of 12 square units under the curve.
Explanation:To find the Riemann sum for the function f(x) = 2x over the interval [2, 4], we start by dividing the interval into n equal subintervals, with each subinterval of width ∆x = (b - a) / n. For the right-hand endpoint, the kth point c at which f(x) is evaluated is given by c_k = a + k*∆x. Therefore, the Riemann sum is:
∑_{k=1}^{n}f(c_k)*∆x = ∑_{k=1}^{n}2(a + k*∆x)*∆x.
As n → ∞, the Riemann sum approaches the definite integral of the function. For the given function, the integral can be calculated directly, and the limit of the Riemann sum as n approaches infinity gives us the area under the curve, which in this case is equivalent to the area of a right triangle with base 2 and height 4.
Thus, we find that the area under the curve on the interval [2, 4] for f(x) = 2x is simply integral from 2 to 4 of 2x dx, which evaluates to 4^2 - 2^2, or 12 square units.
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A survey is targeted at 12-year-old children. Which questions are appropriate for the population? Choose all that apply.
What year did you graduate high school?What color was your first car?Where is your favorite vacation spot?What is the last book you read?Should taxes be increased to fund a new park?
Answer A, Answer C, Answer D
Hello there! The answers are:
Where is your favorite vacation spot?
What is the last book you read?
Let look at all the options:
What year did you graduate high school? - This is bad for 12 year olds since mot 12 year olds are 6-7th through 7th grade, and graduate when they are 17/18.
What color was your first car? - You can't get your drivers license until you are 16 (at least in the U) so a 12 year old would not own their own car.
Where is your favorite vacation spot? - You can co on vacation young as a baby, so this would be a suitable question.
What is the last book you read? - By 12 you should for sure be able to read, so this is a correct choice.
Should taxes be increased to fund a new park? - 12 year old are way to young to understand taxes so this is also incorrect.
I hope this helps and have a great rest of your day! :)
What is the coordinates of T' if T(-4,2) after a rotation of the triangle 180°about the origin?
Answer:
T'(4, -2)
Step-by-step explanation:
Rotation 180° about the origin (same as reflection across the origin) negates both coordinates:
T' = -T = -(-4, 2)
T' = (4, -2)
A village was founded four hundred years ago by a group of 20 people. In this village, the population triples every one hundred years. What is the population of the village today?
This is an example of exponential growth. The population of this village triples every hundred years. Given the village was founded 400 years ago by 20 people, the current population would be 1620 people.
Explanation:The given situation is an example of exponential growth, which can be found in various scenarios such as population growth. From the information provided, the population of the village triples every hundred years. Since the village was founded four hundred years ago and initially had 20 people, we can calculate the population today using the following steps:
The population after 100 years is 20 (initial population) x 3 (tripling) = 60.The population after the next 100 years is 60 (population after the first hundred years) x 3 (tripling) = 180.The population after three hundred years is 180 (population after two hundred years) x 3 (tripling) = 540.Finally, the population after the fourth hundred years, which is now, is 540 (population after three hundred years) x 3 (tripling) = 1620.So, the population of the village today would be 1620 people.
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The population of the village today is 720 people.
Explanation:To find the population of the village today, we need to calculate the number of population doublings that have occurred over the four hundred year period.
Since the population triples every one hundred years, it doubles twice in that time frame.
Doubling a number is the same as multiplying it by 2.
So, the population at the start was 20, then it doubled to 40 after one hundred years, and doubled again to 80 after two hundred years.
Finally, it tripled to 240 after three hundred years, and tripled again to 720 after four hundred years.
Therefore, the population of the village today is 720 people.
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Susie is participating in a bake sale for a fundraiser. She baked 8 pies to sell. Two pies weigh 105 g each, one pie weighs 106 g, two pies weigh 108 g each and the last three pies weigh 103.5 g, 102 g and 104.5 g.
What is the average weight of the pies rounded to two decimal places?
Enter your answer in the box.
Answer:
105.25 g
Step-by-step explanation:
The average weight is the sum of the weights divided by the number of pies.
(105 + 105 + 106 + 108 + 108 + 103.5 +102 +104.5) / 8
= 105.25
Answer:
Here for anybody at k12 :)
Step-by-step explanation:
Took it and got it correct :)
Angles that have a common vertex and side is called ______
ANSWER
Adjacent Angles
EXPLANATION
Angles that have a common vertex and side are called adjacent angles.
The vertex is the point of intersection of the arms of an angle.
A vertex can be formed by two more rays.
From the diagram, angle x and y and adjacent angles.
The common vertex is V.
The common side is VZ
Angles m and n are not adjacent angles because they do not have the same vertex.
CAN SOMEONE HELP ME WITH NUMBER 7??
I WILL GIVE BRAINLIEST!
Answer:
tanx-(\sqrt(11))/(5)cosx>0
Step-by-step explanation:
Because to do this kind of trig you first have to know how to do basic trg
For a limited time, Sammy’s gas station is offering a discount on the cost of gasoline when amounts greater than 5 gallons are purchased. The table below shows the cost for different amounts of gasoline.
Which of these could be used to determine c, the cost for purchasing g gallons of gasoline with the discount?
A: C=2.65g
B: C=2.65g-12
Answer:
C = 26.5g - 2
Step-by-step explanation:
We can plug in our given numbers for g and see if the C corresponds.
g = 7, C = 16.55
A) C = 2.65*7 --> C = 18.55
We know that C ≠ 18.55, so it should be B (I think you typed that one wrong, it is C = 2.65g - 2)
The equation C=2.65g could be used to determine the cost for purchasing g gallons of gasoline with the discount.
Explanation:To determine the cost for purchasing g gallons of gasoline with the discount, we need to examine the given options. Option A states that the cost, C, equals 2.65g, which means the cost is directly proportional to the number of gallons. This could be a valid equation for determining the cost with the discount. However, option B states that the cost, C, equals 2.65g-12. This equation subtracts a constant value of 12, which is not mentioned in the problem, so it is not a valid way to determine the cost with the discount. Therefore, option A could be used to determine the cost for purchasing g gallons of gasoline with the discount.
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The amount of time it takes Joel to check e-mail is directly proportional to the number of messages he has. If it takes him t minutes when there are n new e-mail messages, then how long does it take him (in terms of t and n) if there are 50 new messages?
A) 50tn
B) 50n t
C) 50t n
D) t n
Answer:
50t/n minutes.
Step-by-step explanation:
The equation of proportionality is t = kn where k is a constant.
So k = t/n.
So for 50 new message the time = 50k = 50 * t/n
= 50t/n minutes.
(1.) Solve for x. Show ALL work: -2x + 5 = 4x - 7
(2.) Solve for y. Show ALL work: 12y + 4 = 8y - 12
(3.) Solve for z. Show ALL work: 7z - 18 = -2z + 18
(4.) Solve for x. Show ALL work: 10x + 15 = 5x - 10
The answers are:
1
[tex]x=2[/tex]
2
[tex]y=-4[/tex]
3
[tex]z=4[/tex]
4
[tex]x=-5[/tex]
Why?Solving for each of the given equations and variable, we have:
1[tex]-2x + 5 = 4x - 7[/tex]
Solving for "x", we have:
[tex]-2x + 5 = 4x - 7\\\\-2x-4x=-7-5\\\\-6x=-12\\\\x=\frac{-12}{-6}=2[/tex]
So, we have that:
[tex]x=2[/tex]
2[tex]12y+4=8y-12[/tex]
Solving for "y", we have:
[tex]12y+4=8y-12\\\\12y-8y=-12-4\\\\4y=-16\\\\y=\frac{-16}{4}=-4[/tex]
So, we have that:
[tex]y=-4[/tex]
3[tex]7z-18 =-2z+18[/tex]
Solving for "z", we have:
[tex]7z-18 =-2z+18\\\\7z+2z=18+18\\\\9z=36\\\\z=\frac{36}{9}=4[/tex]
So, we have that:
[tex]z=4[/tex]
4[tex]10x+15 =5x-10[/tex]
Solving for "x", we have:
[tex]10x+15 =5x-10\\\\10x-5x=-10-15\\\\5x=-25\\\\x=\frac{-25}{5}=-5[/tex]
So, we have that:
[tex]x=-5[/tex]
Hence, the answers are:
1
[tex]x=2[/tex]
2
[tex]y=-4[/tex]
3
[tex]z=4[/tex]
4
[tex]x=-5[/tex]
Have a nice day!
What is the value of θ for the acute angle in a right triangle?
sin(θ)=cos(48°)
Enter your answer in the box.
θ=
°
Answer:
Step-by-step explanation:
cosΘ=sin(90-Θ)
cos(48)=sin(90-48)
cos(48)=sin(42)
Answer:
cosine (48) = 0.66913
The arc sine of (.66913) = 42 degrees
Step-by-step explanation:
Find the solution set of this inequality. Select
the correct graph.
18x + 161 > 16
Click on the correct answer.
Answer:
"first number line shown in the diagram"
Step-by-step explanation:
Whenever we have inequality of the form
| x + a | > b
we can write
1. x+a > b, and
2. -(x+a) > b
and solve both.
So we can write
1. 8x + 16 > 16
2. -(8x+16) > 16
Solving 1:
8x > 16 - 16
8x > 0
x > 0
Solving 2:
-(8x+16) > 16
-8x - 16 > 16
-16 -16 > 8x
-32 > 8x
-32/8 > x
-4 > x
Putting these together, we can say x is greater than 0 & x is less than -4
The first number line is right.
The answer is:
The first option.
[tex]-4>x>0[/tex]
Why?To solve absolute values inequalities, we need to remember that absolute value functions have a positive and a negative solution.
For example, we have that:
[tex]|x|>1[/tex]
The solution will be
[tex]-1>x>1[/tex]
So, we are given the inequality:
[tex]|8x+16|>16[/tex]
Isolating "x", we have:
[tex]-16>8x+16>16[/tex]
[tex]-16-16>8x+16-16>16-16[/tex]
[tex]-32>8x>0[/tex]
[tex]\frac{-32}{8}>\frac{8x}{32}>\frac{0}{32}\\\\-4>x>0[/tex]
Hence, we have that the correct option is the first option.
The solution is:
[tex]-4>x>0[/tex]
or
(-∞,-4)U(0,∞)
Have a nice day!
Jared has some quarters and dimes that total $5.50. If he has 8 more quarters that dimes, how much dimes does Jared have?
Final answer:
To determine the number of dimes Jared has, we set up an equation based on the total value of dimes and quarters equaling $5.50. After solving the equation, we find that Jared has 10 dimes.
Explanation:
The student's question asks how many dimes Jared has if he has a total of $5.50 consisting of quarters and dimes, with 8 more quarters than dimes. Let 'd' represent the number of dimes. Since a dime is worth $0.10, the total value of the dimes is 0.10d dollars. Jared has 8 more quarters than dimes, so he has 'd+8' quarters. A quarter is worth $0.25, so the total value of the quarters is 0.25(d+8). The sum of the values of the dimes and quarters is $5.50, so we can set up the equation 0.10d + 0.25(d+8) = 5.50.
Now, solving for d:
0.10d + 0.25(d+8) = 5.50
0.10d + 0.25d + 2 = 5.50
0.35d + 2 = 5.50
0.35d = 5.50 - 2
0.35d = 3.50
d = 3.50 / 0.35
d = 10
Jared has 10 dimes.
Given four functions, which one will have the highest y-intercept?
f(x) g(x) h(x) j(x)
Blake is tracking his
savings account with
an interest rate of 5%
and a original deposit
of $15.
x g(x)
1 6
2 8
3 12
the function h of x equals 4 to the x power, plus 3 j(x) = 10(2)x
f(x)
g(x)
h(x)
j(x)
Answer:
f(x)
Step-by-step explanation:
f(x) apparently has an initial value of 15.
g(x) apparently will have an initial value of 6 or less, since g(1) = 6 and it has increasing slope.
h(0) = 4^0 +3 = 3
j(0) = 10·2^0 = 10
The largest initial value among the initial values {15, <6, 3, 10} is 15.
f(x) has the largest y-intercept
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The graph shows two ways g(x) can be modeled. One is exponential with an initial value of 4; the other is quadratic with an initial value of 6.
Final answer:
Among the functions provided, j(x) = 10(2)^x has the highest y-intercept, which is 10, found by evaluating the function at x equals 0.
Explanation:
To determine which function has the highest y-intercept, we need to examine each function and look for the point where the graph crosses the y-axis (when x is 0). Unfortunately, the only function provided with enough information to determine the y-intercept directly is h(x) = 4^x + 3. Evaluating h at x equals 0 gives us h(0) = 4^0 + 3, which simplifies to 1 + 3, yielding a y-intercept of 4. The function j(x) = 10(2)^x would have a y-intercept of 10 when x is 0. However, without the specifics of f(x) and not enough points to determine a pattern in g(x), it is not possible to accurately determine their y-intercepts. Thus, between h(x) and j(x), j(x) has the highest y-intercept at 10.
Given a polynomial f(x), if (x − 2) is a factor, what else must be true?
A. f(0) = 2
B. f(0) = −2
C. f(−2) = 0
D. f(2) = 0
Answer:
D. f(2) = 0
Step-by-step explanation:
If x-2 is a factor of a function, then f(2) must be zero
f(x) = p(x) * (x-2) since (x-2) is a factor of f(x)
Substitute in x=2
f(2) = p(2) (2-2)
f(2) = p(2) *(0)
Anything times 0 = 0
f(2) = 0