Answer:false
Step-by-step explanation:
Integer contains only both positive and negative numbers digits but not decimal points.
Answer:False
Step-by-step explanation:The set of integers Z ={....-3,-2,-1,0,1,2,3....}
The names of 50 contestants are written on 50 cards. The cards are placed in a bag, and three names are picked from the bag. Identify which sampling technique is used?
The sampling technique described is called 'sampling without replacement'. In this case, names are drawn from the bag and not returned, decreasing the pool for subsequent draws. It's a type of 'simple random sampling'.
Explanation:The sampling technique used when 50 contestants’ names are written on 50 cards, placed in a bag, and three are chosen, is a method called sampling without replacement. In this process, once a name is chosen, it is not returned to the bag, reducing the pool of options for subsequent selections. As each card is drawn, the remaining pool of names shrinks, meaning the probability of drawing any remaining name changes with each draw. This process is often used when the desire is to avoid repetition in the selection.
In contrast, sampling with replacement would mean that after a card is drawn, it is put back into the bag before the next draw, ensuring that the same name could potentially be drawn more than once. Both methods are types of simple random sampling, a fundamental sampling method in statistics.
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Consider the following sample set of scores. Assume these scores are from a discrete distribution. 21 29 32 38 38 45 50 64 72 100 For the given data, the mean is ___ , the median is , and the mode is . Suppose the score 21 in the data is mistakenly recorded as 2 instead of 21. For the sample with this error, the mean is , the median is , and the mode is __ . The mean __ , the median ___ , and the mode ___ . Suppose the score 21 in the original sample is inadvertently removed from the sample. For the sample with this score removed, the mean is ___ , the median is __ , and the mode is __ . The mean ___ , the median __, and the mode ___
The mean, median, and mode of the original set of scores are 54.9, 41.5, and 38 respectively. When the score of 21 is recorded as 2, the mean decreases but the median and mode remain unchanged. When the score of 21 is removed, both the mean and median change but the mode stays the same.
Explanation:To answer these questions, we first need to find the mean, median, and mode of the original set of scores. The mean is the sum of the values divided by the total number of values. For the given set of numbers, the mean is 54.9. The median is the number that divides the set of values into two equal halves. In the given set, the median is 41.5. The mode is the number that appears most often, which in this case is 38.
When the score of 21 is mistakenly recorded as 2, the mean decreases to 51.3, the median remains the same, and the mode also stays the same as this change does not affect the frequency of the numbers.
When the score of 21 is removed from the set, the mean decreases to 55.3, and the median increases to 43. Still, the mode remains unchanged as removing a number 21 doesn't change the frequency distribution of the scores.
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Construct a stem-and-leaf plot of the test scores:67, 72, 86, 75, 89, 89, 87, 90, 99, 100.67, 72, 86, 75, 89, 89, 87, 90, 99, 100. How does the stem-and-leaf plot show the distribution of these data?
Answer:
Stem-and-leaf plot of the test scores is shown below.
Step-by-step explanation:
The given data set is
67, 72, 86, 75, 89, 89, 87, 90, 99, 100
Stem-and-leaf: Leaf is the last term and stem is other term. If a number is 32, then 3 is stem and 2 is leaf.
Stem-and-leaf plot of the test scores is
Stem leaf
6 7
7 2,5
8 6,7,9,9
9 0,9
10 0
The length of the rows are similar to the heights of bars in a histogram; longer rows of the data correspond to higher frequency.
Which of the exponential functions below has a y-intercept of 2?
Answer:
the correct answer is B. g(x)=3^x +1
Step-by-step explanation:
I just took the test
Hope this helps
The exponential function with a y-intercept of 2 is in the form y = 2b^x, where 'a' represents the y-intercept of the function. To find this, set x to 0 in the function, resulting in y = a(1), and thus y = a. If the function's y-intercept is 2, the value of 'a' is 2.
Explanation:To determine which exponential function has a y-intercept of 2, you need to recall the standard form of an exponential function, y = abx, where a is the y-intercept of the function. For an exponential function, the y-intercept occurs when x is 0. Thus, when x = 0, the function takes the form y = ab0, and since anything to the power of 0 is 1, the function simplifies to y = a. Therefore, if a function's y-intercept is 2, it means that the value of a must be 2, resulting in the function y = 2bx.
Additionally, understanding the relationship between exponential and logarithmic functions can be helpful. To rewrite a base number b in terms of natural logarithms, you can use the fact that b = eln(b). For example, 2 = eln(2). This is valuable for solving equations involving exponential growth or decay, especially when a y* calculator button is unavailable.
Find a formula for the described function.
A rectangle has perimeter 10 m. Express the area A of the rectangle as a function of the length, L, of one of its sides.
Answer:
The area of the rectangle is [tex]A=5L-L^2[/tex].
Step-by-step explanation:
The perimeter of a rectangle is
[tex]P=2(L+W)[/tex]
where, L is length and W is width.
It is given that perimeter of a rectangle is 10m.
[tex]10=2(L+W)[/tex]
Divide both sides by 2.
[tex]5=L+W[/tex]
Subtract L from both sides.
[tex]5-L=W[/tex]
Area of a rectangle is
[tex]A=L\times W[/tex]
Substitute W=(5-L) in the above formula.
[tex]A=L\times (5-L)[/tex]
[tex]A=5L-L^2[/tex]
Therefore, the area of the rectangle is [tex]A=5L-L^2[/tex].
Final answer:
The area A of a rectangle with a fixed perimeter of 10 meters is expressed as a function of the length L by the formula A(L) = L(5 - L), assuming 0 ≤ L ≤ 5 meters.
Explanation:
The question is asking us to express the area A of a rectangle as a function of the length L, one of its sides, given a fixed perimeter of 10 meters. The perimeter of a rectangle is given by the formula P = 2L + 2W, where L is the length and W is the width. For a rectangle with a perimeter of 10 meters, we have:
2L + 2W = 10
W = (10 - 2L) / 2 = 5 - L
The area A of the rectangle is A = L × W = L(5 - L)
This formula A = L(5 - L) gives the area as a function of the length.A: The rectangle's area is a function of its length, expressed as A(L) = L(5 - L), valid for 0 ≤ L ≤ 5, since the minimum possible width is 0 when the length equals 5, and the maximum possible length is 5 when the width equals 0.
Convert the integral ∫4√0∫x−xdydx to polar coordinates and evaluate it (use t for θ):
After converting the provided integral to polar coordinates, the value of integral is evaluated π/2.
What is polar form?When the Cartesian coordinates (x,y) are expressed in the polar coordinates (r, θ), then this form is called the polar form.
The given integral function in the problem is,
[tex]\int_0^{\sqrt{4}} \int\limits^x_{-x} dydx[/tex]
Let suppose, [tex]x=r\cos\theta[/tex] and [tex]y=r\sin\theta[/tex]. Thus,
[tex]\sin\theta=\dfrac{y}{r}\\\cos\theta=\dfrac{x}{r}[/tex]
Limits are y=x. From the trigonometry, the value of theta in the given triangle can be given as,
[tex]\dfrac{\sin\theta}{\cos\theta}=1\\\tan\theta=1\\\theta=\tan^{-1}1\\\theta=45^o\\\theta=\dfrac{\pi}{4}[/tex]
Similarly, for y=-x the value of angle,
[tex]\theta=-\dfrac{\pi}{4}[/tex]
Thus, the limits of theta are from -π/4 to π/4. From the Pythagoras theorem,
[tex]r^2=x^2+y^2\\r^2=(r\cos\theta)^2+(r\sin\theta)^2\\r^2=r^2(1)[/tex]
Thus, the limits of r is from 0 to 1. Convert the given integral in polar form as,
[tex]\int\limits^{\pi/4}_{-\pi/4} \int_0^{1} dt ds\\\int\limits^{\pi/4}_{-\pi/4} [1-0] dt \\\int\limits^{\pi/4}_{-\pi/4} dt \\\dfrac{\pi}{4}-\left(-\dfrac{\pi}{4} \right) \\\dfrac{\pi}{2} \\[/tex]
Hence, after converting the provided integral to polar coordinates, the value of integral is evaluated π/2.
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To convert the given Cartesian integral to polar coordinates, identify the bounds in polar terms, then rewrite the integral accordingly. After setting up the new limits for r and θ, use the relationship between Cartesian and polar coordinates to express the area element, and integrate step-by-step.
Explanation:To convert the integral ∫4√0∫x-xdydx to polar coordinates and evaluate it, we first need to describe the limits of integration and the region of integration in terms of polar coordinates (r, θ). The given integral ranges over a region bounded by the parabola y = √x and the x-axis from x=0 to x=4. Converted to polar coordinates, this region is bounded by the rays θ = 0 and θ = π/2 and the circles r = 0 and r = 4cos(θ).
So the double integral can be rewritten as ∫π/20∫4cos(θ)0 rdrdθ. To evaluate this integral, we integrate r from 0 to 4cos(θ), then integrate θ from 0 to π/2:
∫π/20 (∫4cos(θ)0 r dr) dθ = ∫π/20 [1/2 r^2]|^{4cos(θ)}_0 dθ = ∫π/20 8cos^2(θ) dθ
Using the double angle formula, cos^2(θ) = (1+cos(2θ))/2, the integral becomes:
8 ∫π/20 (1+cos(2θ))/2 dθ = 4 ∫π/20 (1+cos(2θ)) dθ
This can now be integrated directly to get the final result.
Rewrite the expression ab dc ef such that each variable is replaced by a different non- zero digit and the value of expression is 1. (The answer may not be unique.)
Answer:
ab dc ef is replaced by 12 43 56
Step-by-step explanation:
ab dc ef are replaced by the position they take when writing in an alphabetical order. a is 1, b is 2, c is 3, and so on.
So, ab dc ed is written as
12 43 56
and
56 - 43 - 12 = 1
Shortly after September 11th 2001, a researcher wanted to determine if the proportion of females that favored war with Iraq was significantly different from the proportion of males that favored war with Iraq. In a sample of 73 females, 28 favored war with Iraq. In a sample of 54 males, 29 favored war with Iraq.
a) Let pF represent the proportion of females that favor the war, pM represent the proportion of males that favor the war. What are the proper hypotheses?
A.)H0: pF = pM versus Ha: pF > pM
B.)H0: pF < pM versus Ha: pF = pM
C.)H0: pF = pM versus Ha: pF < pM
D.)H0: pF = pM versus Ha: pF ≠ pM
b) What is the test statistic? Compute the statistic using male statistics subtracted from female statistics. Give your answer to four decimal places.
c) What is the P-value for the test? Give your answer to four decimal places.
d) Using a 0.01 level of significance, what conclusion should be reached?
A.)The proportion of females that favor the war and the proportion of males that favor the war are significantly different because the P-value is less than 0.01.
B.)The proportion of females that favor the war and the proportion of males that favor the war are not significantly different because the P-value is greater than 0.01.
C.)The proportion of females that favor the war and the proportion of males that favor the war are significantly different because the P-value is greater than 0.01.
D.)The proportion of females that favor the war and the proportion of males that favor the war are not significantly different because the P-value is less than 0.01.
e) What is the lower endpoint of a 99% confidence interval for the difference between the proportion of females that favor the war and the proportion of males that favor the war? Give your answer to four decimal places.
f) What is the upper endpoint of a 99% confidence interval for the difference between the proportion of females that favor the war and the proportion of males that favor the war? Give your answer to four decimal places.
Answer:
a) D.)H0: pF = pM versus Ha: pF ≠ pM
b) [[tex]z=\frac{0.537-0.384}{\sqrt{0.449(1-0.449)(\frac{1}{73}+\frac{1}{54})}}=1.7138[/tex]
c) [tex]p_v =2*P(Z>1.7138)=0.0866[/tex]
d) B.)The proportion of females that favor the war and the proportion of males that favor the war are not significantly different because the P-value is greater than 0.01.
e) [tex](0.537-0.384) - 2.58 \sqrt{\frac{0.537(1-0.537)}{54} +\frac{0.384(1-0.384)}{73}}=-0.0755[/tex]
f) [tex](0.537-0.384) + 2.58 \sqrt{\frac{0.537(1-0.537)}{54} +\frac{0.384(1-0.384)}{73}}=0.3815[/tex]
Step-by-step explanation:
1) Data given and notation
[tex]X_{M}=28[/tex] represent the number of men that favored war with Iraq
[tex]X_{W}=29[/tex] represent the number of women that favored war with Iraq
[tex]n_{M}=73[/tex] sample of male selected
[tex]n_{W}=54[/tex] sample of female selected
[tex]p_{M}=\frac{28}{73}=0.384[/tex] represent the proportion of men that favored war with Iraq
[tex]p_{W}=\frac{29}{54}=0.537[/tex] represent the proportion of women that favored war with Iraq
[tex]\alpha=0.01[/tex] represent the significance level
z would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the value for the test (variable of interest)
Part a
We need to conduct a hypothesis in order to checkif the proportion of females that favored war with Iraq was significantly different from the proportion of males that favored war with Iraq , the system of hypothesis would be:
Null hypothesis:[tex]p_{M} = p_{W}[/tex]
Alternative hypothesis:[tex]p_{M} \new p_{W}[/tex]
The best option is:
D.)H0: pF = pM versus Ha: pF ≠ pM
Part b
We need to apply a z test to compare proportions, and the statistic is given by:
[tex]z=\frac{p_{W}-p_{M}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}[/tex] (1)
Where [tex]\hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{28+29}{73+54}=0.449[/tex]
Calculate the statistic
Replacing in formula (1) the values obtained we got this:
[tex]z=\frac{0.537-0.384}{\sqrt{0.449(1-0.449)(\frac{1}{73}+\frac{1}{54})}}=1.7138[/tex]
Part c
We have a significance level provided [tex]\alpha=0.01[/tex], and now we can calculate the p value for this test.
Since is a one two sided test the p value would be:
[tex]p_v =2*P(Z>1.7138)=0.0866[/tex]
Part d
If we compare the p value and the significance level given [tex]\alpha=0.01[/tex] we see that [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the best conclusion would be:
B.)The proportion of females that favor the war and the proportion of males that favor the war are not significantly different because the P-value is greater than 0.01.
Part e
The confidence interval for the difference of two proportions would be given by this formula
[tex](\hat p_W -\hat p_M) \pm z_{\alpha/2} \sqrt{\frac{\hat W_A(1-\hat p_W)}{n_W} +\frac{\hat p_M (1-\hat p_M)}{n_M}}[/tex]
For the 99% confidence interval the value of [tex]\alpha=1-0.99=0.01[/tex] and [tex]\alpha/2=0.005[/tex], with that value we can find the quantile required for the interval in the normal standard distribution.
[tex]z_{\alpha/2}=2.58[/tex]
And replacing into the confidence interval formula we got:
[tex](0.537-0.384) - 2.58 \sqrt{\frac{0.537(1-0.537)}{54} +\frac{0.384(1-0.384)}{73}}=-0.0755[/tex]
Part f
[tex](0.537-0.384) + 2.58 \sqrt{\frac{0.537(1-0.537)}{54} +\frac{0.384(1-0.384)}{73}}=0.3815[/tex]
The proper hypotheses are H0: pF = pM and Ha: pF ≠ pM. The test statistic is -0.087. The p-value is 0.1651.
Explanation:a) The proper hypotheses for this situation are:
H0: pF = pM
Ha: pF ≠ pM
Hence, the correct option is D.
b) The test statistic is computed by subtracting the male statistic from the female statistic:
Test statistic = pF - pM = 28/73 - 29/54 = -0.087
c) The p-value for the test is computed using the test statistic and the appropriate test statistic distribution. Based on the given values, the p-value is found to be 0.1651.
d) Using a 0.01 level of significance, the conclusion should be: The proportion of females that favor the war and the proportion of males that favor the war are not significantly different because the p-value is greater than 0.01. Hence, the correct option is D.
e) The lower endpoint of a 99% confidence interval for the difference between the proportion of females that favor the war and the proportion of males that favor the war is -0.2302.
f) The upper endpoint of a 99% confidence interval for the difference between the proportion of females that favor the war and the proportion of males that favor the war is 0.0566.
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Find the general solution of the given differential equation. cos(x) dy dx + (sin(x))y = 1
To solve the given differential equation, we employ the method of integrating factors, multiplying the equation by an integrating factor to simplify it. After manipulation, it involves integrating sec(x) to find the general solution, which includes trigonometric and possibly logarithmic functions.
Explanation:The differential equation given is cos(x) dy/dx + (sin(x))y = 1. To find its general solution, we will use the method of integrating factors. This method involves multiplying the entire equation by a function, called the integrating factor, that will allow the left side of the equation to be expressed as the derivative of a product of functions.
Firstly, the differential equation can be rewritten in the form dy/dx + (sin(x)/cos(x))y = 1/cos(x). Notice that the integrating factor, μ(x), can be found using the formula μ(x) = e^(∫ P(x) dx), where P(x) = sin(x)/cos(x). This evaluates to μ(x) = e^(ln|sec(x)|), which simplifies to μ(x) = sec(x).
Multiplying the entire original differential equation by sec(x) leads to sec(x)cos(x) dy/dx + sec(x)sin(x)y = sec(x). This simplifies to dy/dx + tan(x)y = sec(x). Integrating both sides with respect to x, we find the general solution involves an integration of sec(x), which may lead to a solution involving logarithmic and trigonometric functions, depending on the specifics of the integration.
Thus, the general solution to the differential equation involves integrating sec(x) on the right side after applying the integrating factor, leading to a solution of the form y(x) = C*sec(x) + f(x), where C is a constant and f(x) is an integral involving sec(x).
Under what circumstances is the median likely to produce a better measure of central tendency than the mean?
Answer:
With a skewed distribution and data with outliers.
Step-by-step explanation:
There are three measures of central tendency.
Mean: It is the average value of data and affected by presence of outliers.Median: It is the value that divides the data into two equal parts. It is a position based measure of tendency.Mode: It is the most frequent observation in the data.For a symmetrical distribution for continuous data, the mean, median, and mode are equal. For such case mean is a better measure of central tendency because it includes all of the data in the calculations. Median is the best measure of central tendency when the data is not symmetrical because the median is position based.Advantage of the median:The median is not affected by outliers and skewed data as compared to the mean.
Thus, median likely to produce a better measure of central tendency than the mean with a skewed distribution and data with outliers.
There are 15 numbers on a list, and the smallest number is changed from 12.9 to 1.29.
a. Is it possible to determine by how much the mean changes? If so, by how much does it change?
b. Is it possible to determine the value of the mean after the change? If so, what is the value?
c. Is it possible to determine by how much the median changes? If so, by how much does it changes?
d. Is it possible to determine by how much the standard deviation changes? If so, by how much does it change?
Answer:
Step-by-step explanation:
There are 15 numbers on a list, and the smallest number is changed from 12.9 to 1.29.
a. Is it possible to determine by how much the mean changes? If so, by how much does it change?
Yes. The total would decrease by 11.61. so mean would decrease by 11.61/15 =0.774
b. Is it possible to determine the value of the mean after the change? If so, what is the value?
No. new men would be old mean - 0.774
c. Is it possible to determine by how much the median changes? If so, by how much does it changes?
Though the smallest number is changed the position does not change.
Hence median will not change.
d. Is it possible to determine by how much the standard deviation changes? If so, by how much does it change?
The original variance would be average of square of deviations of the old mean.
Yes, it possible to determine by how much the mean changes. so, 0.7741 change in mean.
No, it is not possible to determine the value of the mean after the change because the value of mean is unknown before the mean
No, it possible to determine by how much the median changes. so, the value of mean will remain same.
No it is impossible to determine how much the standard deviation changes .
Given that,
There are 15 numbers on a list, and the smallest number is changed from 12.9 to 1.29.
We have to find,
All the statements about mean and median are correct or not.
According to the question,
The total would decrease by 11.61.Then,
Mean would decrease by,
[tex]= \dfrac{11.61}{15} \\\\= 0.774[/tex]1
Yes, it possible to determine by how much the mean changes. so, 0.7741 change in mean.
New men would be old mean - 0.7741.
No, it is not possible to determine the value of the mean after the change because the value of mean is unknown before the mean.
Though the smallest number is changed the position does not change.
Yes, It is possible to determine by how much the median changes because we have 15 numbers in a data set and doesn’t effect the median so the median didn’t change.
Hence median will not change.
No, it possible to determine by how much the median changes. so, the value of mean will remain same.
The original variance would be average of square of deviations of the old mean.No it is impossible to determine how much the standard deviation changes .
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What function do you know from calculus is such that its first derivative is a constant multiple k of itself
Answer:
Exponential function if the form [tex]e^{Kx}[/tex] is the constant multiple K of itself if.
[tex]y'=\frac{dy}{dx}=cKe^{Kx} \\y'=Ky[/tex]
Step-by-step explanation:
The exponential function of the form [tex]e^x[/tex] is the function which is the derivative of itself.
Where:
x is independent variable
Now if we talk about constant then again exponential function if the form [tex]e^{Kx}[/tex] is the constant multiple K of itself if we take the dervative.
Mathmatical Prove:
Consider the general equation
let [tex]y=ce^{Kx}[/tex]
Where:
K is a constant
c is the cofficient(could be any number)
Now:
Taking derivative of above equation w.r.t x:
[tex]y'=\frac{dy}{dx}=cKe^{Kx} \\y'=Ky[/tex]
Hence proved exponential function is a constant multiple K of it self.
The function is [tex]f(x) = Ae^kx[/tex]. This function is a solution of the differential equation y' = ky.
We know that the derivative of the exponential function is the function itself. Consider the function [tex]f(x) = Ae^kx[/tex], where A is a constant. Then, take the derivative of [tex]f(x) = Ae^kx[/tex], we get:
[tex]f'(x) = Ake^{kx} = k (Ae^{kx}) = k f(x)[/tex]
Thus, a function whose first derivative is a constant multiple k of itself is[tex]f(x) = Ae^{kx}[/tex], where A is a constant.
Since [tex]f'(x) = k f(x)[/tex] for the function [tex]f(x) = Ae^{kx}[/tex], this function must be the solution of the differential equation y' = ky.
Complete question:
What function do you know from calculus is such that its first derivative is a constant multiple k of itself? (Do not use the function f(x)=0.)
f(x)=____
The above function is a solution of which of the following differential equations?
[tex]y'=y^k[/tex]
[tex]y'=y+k[/tex]
[tex]y'=ky[/tex]
[tex]y'=e^{ky}[/tex]
[tex]y'=k[/tex]
The temperature, T , in degrees Fahrenheit, of a cold yam placed in a hot oven is given by T=f(t) , where t is the time in minutes since the yam was put in the oven.
What is the sign of f'(t)? Why?
What are the units of f'(20)? What is the practical meaning of the statement f' (20)=2?
Answer:
a) positive
b)
[tex]^\circ F\text{ per Minute}[/tex]
c) Interpretation of f'(20)=2
Step-by-step explanation:
We are given the following in the question:
[tex]T=f(t)[/tex]
where T is the temperature in degrees Fahrenheit of a cold yam placed in a hot oven and t is the time in minutes since the yam was put in the oven.
a) sign of f'(t)
f'(t) will represent the rate of change in temperature.
f'(t) will represent the change in temperature of yam when 1 minute has passed since it was kept in oven.
Since the temperature will always increase in oven, f'(t) will have a positive sign.
b) units of f'(20)
Since, f'(t) represent the rate of change in temperature. the unit will be
[tex]\dfrac{\text{degrees Fahrenheit}}{\text{Minute}}[/tex]
That is degrees Fahrenheit per minute.
c) f'(20)=2
f'(20) will tell the change in temperature when 20 minutes have passed after the yam has been kept in oven.
Thus, the given statement means that 20 minutes after the yam was kept for in the oven, the temperature of yam was increasing by 2 degree Fahrenheit per minute.
The sign of f'(t) is positive . The units of f'(20) are degrees Fahrenheit per minute. The statement f'(20)=2 means that at 20 minutes, the temperature of the yam is increasing at a rate of 2°F per minute.
The temperature, T, of a cold yam placed in a hot oven, as a function of time t is given by T=f(t), where t is the time in minutes since the yam was put in the oven.
Sign of f'(t)The sign of f'(t) is positive. This is because, as time t increases, the temperature of the cold yam increases due to the hot environment of the oven.
Units of f'(20)The units of f'(20) are degrees Fahrenheit per minute (°F/min). This is because f'(t) represents the rate of change of temperature with respect to time.
Meaning of f'(20)=2The practical meaning of the statement f'(20)=2 is that at t=20 minutes, the temperature of the yam is increasing at a rate of 2 degrees Fahrenheit per minute.
Seventeen percent of the plants in the greenhouse are broad leaf plants and the rest are grasses, What percentage of the plants are grasses?
Answer:The percentage of the plants that are grasses is 83%
Step-by-step explanation:
Seventeen percent of the plants in the greenhouse are broad leaf plants and the rest are grasses
The total number of grasses and broad leaf plants in the greenhouse is 100%. Therefore,
The percentage of the plants that are grasses would be
100% - 17% = 83%
Final answer:
By subtracting the percentage of broad-leaf plants (17%) from the total (100%), we find that 83% of the plants in the greenhouse are grasses.
Explanation:
If seventeen percent of the plants in the greenhouse are broad-leaf plants, then the remaining percentage of plants must be grasses. Since the total percentage must add up to 100%, we can subtract the percentage of broad-leaf plants from the total to find out the percentage of grasses.
To calculate the percentage of grasses, we use the following steps:
Start with the total percentage which is 100%.
Subtract the percentage of broad-leaf plants which is 17%.
The result is the percentage of grasses.
100% - 17% = 83%
Therefore, 83% of the plants in the greenhouse are grasses.