Answer:
Coefficients
Explanation:
Coefficients are used to balance chemical equations.According to the law of conservation of mass, the mass of the reactants in a chemical equation should be equivalent to the mass of the products.The conservation of mass is achieved in chemical equations is achieved through balancing chemical equations. Balancing chemical equations is a try and error of putting appropriate coefficients to the reactants or products to ensure that the number of atoms of each element are equal on the side of the reactants and that of products.A little bumblebee accelerates uniformly at 1.5 m/s² from rest to 22 m/s. Immediately upon reaching 22m/s, the brakes are applied, and it stops 2.5 s later. Find the total distance traveled.
Answer:
190 m
Explanation:
Displacement during acceleration:
v² = v₀² + 2a(x - x₀)
(22 m/s)² = (0 m/s)² + 2(1.5 m/s²)(x - 0 m)
x = 161.333 m
Displacement after deceleration:
x = x₀ + ½ (v + v₀)t
x = 161.333 m + ½ (0 m/s + 22 m/s)(2.5 s)
x = 188.833
Rounded to 2 sig-figs, the bumblebee travels a distance of 190 m.
How much current will flow through a 470-Ohm resistor if a 9-volt battery is used?
Answer:
For a 470-Ohm resistor connected to a 9-votl battery the current that will flow is 0.019A or 19mA
Explanation:
Ohm's law states that the voltage v along a resistor is directly proportional to the current i flowing through the resistor.
[tex]v = i R[/tex]
Clear i from the equation above
[tex]i = \frac{v}{R}[/tex]
[tex]i = \frac{9volt}{470ohm} =0.019A[/tex]
The current flowing through a 470-Ohm resistor with a 9-volt battery is approximately 0.0191 Amperes.
Explanation:In order to determine the current flowing through a resistor, we can use Ohm's Law, which relates voltage, current, and resistance. Ohm's Law states that current (I) is equal to the voltage (V) divided by the resistance (R). So, in this case, we can calculate the current flowing through a 470-Ohm resistor with a 9-volt battery using the formula:
I = V / R
Substituting the given values, we have:
I = 9 V / 470 Ohm
Simplifying the expression gives us the current:
I ≈ 0.0191 A
Therefore, approximately 0.0191 Amperes (or 19.1 milliamperes) of current will flow through the 470-Ohm resistor when a 9-volt battery is used.
Learn more about Current flow through a resistor here:https://brainly.com/question/33584481
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