Titanium (III) chloride, a substance used in catalysts for preparing polyethylene, is made by high-temperature reaction of TiCl4 vapor with H2 :

2TiCl4(g) + H2(g) --> 2TiCl3(s) + 2HCl(g)

a) how many grams of TiCl4 are needed for complete reaction with 155L if H2 at 430 degrees C and 780mmHg pressure?

b) How any liters of HCl gas at STP will result from the reaction described in part (a)?

Answer:

[OH⁻] → 1×10⁻¹⁰

Explanation:

pH = - log [H⁺]

pOH = - log [OH⁻]

pH + pOH = 14

4 + pOH = 14

14 - 4 = 10 → pOH

10^-pOH = [OH⁻]

10⁻¹⁰ = [OH⁻] → 1×10⁻¹⁰

The pOH of the lake is 10 (calculated by subtracting the pH from 14), and the hydroxide ion concentration of the lake is 10^(-10) moles per liter, obtained by raising 10 to the power of the negative pOH.

The pH of a solution is a measure of the hydrogen ion concentration, and the pOH is a measure of the hydroxide ion concentration. In water, pH and pOH are related to each other, and have a sum of 14 at room temperature. When the pH of the solution is given, you can find the pOH by subtracting the pH from 14. In this case, the pH of the lake is 4.0, so the pOH would be 14 - 4 = 10. The concentration of hydroxide ions in a solution can be calculated using the formula 10^(-pOH). So, the hydroxide ion concentration of the lake is 10^(-10) moles per liter.

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Answer:

Option b, Phosphodiester bond

Explanation:

Proteins are sequence of amino acids. Two amino acids are joined by peptide  bond. Therefore, proteins are also known as sequence of polypeptide chains.  These polypeptides chains have four level of structures:

Primary structure

secondary structure

Tertiary structure

Quaternary structure

Primary structure is simply a sequence of amino acids. In secondary, tertiary and Quaternary structure, various interactions are present.

Disulfide bond, hydrogen bond and salt bridge stabilizes tertiary structure of the protein.

Phosphodiester bond is present as link between two nucleotides and thus, present in the backbone of nucleic acid (RNA and DNA)

Therefore, the correct option is option b

Among disulfide bonds, hydrogen bonds, salt bridges, and phosphodiester bonds, the latter does not contribute to the stabilization of the tertiary structure of a protein. Instead, phosphodiester bonds are crucial in the formation of nucleic acids.

In regards to protein structure, the interaction types that contribute to the stabilization of the tertiary structure of a protein include disulfide bonds, hydrogen bonds, and salt bridges.

Disulfide bonds are covalent bonds between two sulfur atoms that stabilize the protein structure. Hydrogen bonds are weak forces of attraction between the hydrogen atom in one molecule and an electronegative atom in another. Salt bridges are ionic bonds between amino acid side chains that also stabilize the protein structure.

However, the phosphodiester bond does not play a role in tertiary protein structure. This type of bond is important in the formation of nucleic acids, such as DNA and RNA, where it links the 3' carbon of one nucleotide to the 5' carbon of another. It serves a different purpose in molecular biology and does not contribute to the stabilization of the tertiary structure of a protein.

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Answer:  the calculation of the number of atoms conserved in the desired product rather than in waste.

Explanation:

Atom economy gives how much desired product is obtained compared to amount of starting materials.

[tex]\text {Atom economy}=\frac{\text {molecular weight of desired product}}{\text {molecular weight of all products}}\times 100%[/tex]

For example:

[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]

[tex]\text {atom economy of water}=\frac{\text {molecular weight of desired product}}{\text {molecular weight of all products}}\times 100%[/tex]

[tex]\text {atom economy of water}=\frac{36}{44+36}\times 100%=45\%[/tex]

Thus atom economy for water is 45%

Answer:

9.1L

Explanation:

Firstly, to solve the problem, we need a balanced chemical equation.

2H2 + O2 ———> 2H2O

2 moles of hydrogen reacted one mole of oxygen. Now, we know that at STP, one mole of a gas occupies a volume of 22.4L, now let us get the number of moles in 4.55L of oxygen.

This means 4.55/22.4 = 0.203125 mole

Since in theory we have 2 moles of hydrogen reacting one mole of oxygen. Hence the number of moles of hydrogen we have is 0.203125 * 2 = 0.40625 mole

We now proceed to get the volume of hydrogen gas. Since 1 mole is 22.4L, then

0.40625 Is 0.40625 * 22.4 = 9.1L

To react with 4.55 L of oxygen gas completely, you need 9.10 L of hydrogen gas. This follows the balanced chemical equation 2H₂ + O₂ → 2H₂O, which indicates a 2:1 ratio between hydrogen and oxygen volumes.

To determine the volume of hydrogen gas needed to react completely with 4.55 L of oxygen gas to produce water vapor, we begin with the balanced chemical equation:

2H₂(g) + O₂(g) → 2H₂O(g)

This tells us that 2 volumes of hydrogen gas react with 1 volume of oxygen gas. Therefore, to find the necessary volume of hydrogen gas:

Recognize the stoichiometric ratio from the equation: 2 volumes of hydrogen gas (H₂) react with 1 volume of oxygen gas (O₂).  

Given that there are 4.55 L of oxygen gas, apply the ratio:

Volume of H₂ needed = 2 times the volume of O₂ = 2 x 4.55 L = 9.10 L

Thus, 9.10 L of hydrogen gas is required to react completely with 4.55 L of oxygen gas under the same conditions of temperature and pressure.

Answer: Option (4) is the correct answer.

Explanation:

Heat of vaporization is defined as the heat energy which is necessarily added to a liquid substance in order to transform the quantity of the substance into a gas.

For example, in [tex]H_{2}O[/tex] there will be presence of strong hydrogen bonding and in order to break this bond high amount of heat energy is required.

Whereas [tex]H_{2}[/tex], [tex]F_{2}[/tex] and [tex]SiF_{4}[/tex] are all covalent compounds which are bonded together by Vander waal forces. As these forces are weak in nature hence, they require less amount of heat energy to convert into vapor state.

Hence, they have low value of [tex]\Delta H_{vap}[/tex]. Also, Ar is a noble gas and it has only Vander waal forces. So, it will also have low value of [tex]\Delta H_{vap}[/tex].

Therefore, we can conclude that out of the given options [tex]H_{2}O[/tex] have the highest [tex]\Delta H_{vap}[/tex].

4. H₂O

Enthalpy of vaporization

The enthalpy of vaporization (symbol ∆Hvap), also known as the (latent) heat of vaporization or heat of evaporation, is the amount of energy (enthalpy) that must be added to a liquid substance to transform a quantity of that substance into a gas.

In terms of formula it can be written as:

[tex]\Delta H_\mathrm{vap}=\Delta U_\mathrm{vap}+p \Delta V[/tex]

Lets look at all the options one by one:

1. In case of H₂O molecule, there is a strong hydrogen bonding thus greatest energy is required to break this bonding.

2. While in case of H₂, F₂ and SiF₄ molecules are all covalent compounds that are bonded via weak vanderwaal forces thus it needs lesser heat energy to convert into vapor state.

3. Noble gases usually have weak vanderwaal forces thus Ar has lower ∆Hvap.

So, we can conclude that H₂O has the the highest ΔHvap.

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Answer:

Sum of coefficients in balanced equation is 18

Explanation:

Unbalanced equation: [tex]Mg_{3}(PO_{4})_{2}+C\rightarrow Mg_{3}P_{2}+CO[/tex]

Balance O: [tex]Mg_{3}(PO_{4})_{2}+C\rightarrow Mg_{3}P_{2}+8CO[/tex]

Balance C: [tex]Mg_{3}(PO_{4})_{2}+8C\rightarrow Mg_{3}P_{2}+8CO[/tex]

Balanced equation:[tex]Mg_{3}(PO_{4})_{2}+8C\rightarrow Mg_{3}P_{2}+8CO[/tex]

Sum of coefficients in balanced equation = (1+8+1+8) = 18

So, option (4) is correct.

Answer:

The root mean square speed of O2 gas molecules is

519.01 m/s

Explanation:

The root mean square velocity  :

[tex]v_{rms}=\sqrt{\frac{3RT}{M}}[/tex]

[tex]K.E_{avg}=\frac{3}{2}RT[/tex]

[tex]K.E =\frac{1}{2}mv_{rms}^{2}[/tex]

Molar mass , M

For He = 4 g/mol

For O2 = 2 x 16 = 32 g/mol

O2 = 32/1000 = 0.032 Kg/mol

First calculate the temperature at which the K.E of He is 4310J/mol

K.E of He =

[tex]K.E_{avg}=\frac{3}{2}RT[/tex]

[tex]T=\frac{2(K.E)}{3(R)}[/tex]

K.E of He = 4310 J/mol

[tex]T=\frac{2(4310J/mol)}{3(8.314J/Kmol)}[/tex]

[tex]T=345.60K[/tex]

Now , Use Vrms to calculate the velocity of O2

[tex]v_{rms}=\sqrt{\frac{3(8.314J/Kmol)(345.60K)}{0.032Kg/mol}}[/tex]

[tex]v_{rms}=\sqrt{\frac{8619.9552}{0.032}}[/tex]

[tex]v_{rms}=\sqrt{26935.001}[/tex]

[tex]v_{rms}=519.01m/s[/tex]

The root mean square speed of O2 gas molecules can be calculated using the average kinetic energy of He gas and the formula Urms = sqrt(3 * kB * T / m).

The root mean square speed (Urms) of gas molecules can be calculated using the equation:

Urms = sqrt(3 * kB * T / m)

Where kB is the Boltzmann constant (1.38 x 10^-23 J/K), T is the temperature in Kelvin, and m is the molar mass of the gas.

Since the average kinetic energy (KEavg) of helium gas (He) is given as 4310 J/mol, we can assume that the temperature is the same for He and oxygen gas (O2). We know that the root mean square speed of He gas is close to 500 m/s. By using the equation and the given data, we can calculate the root mean square speed of O2 gas molecules.

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Answer:

The new total body concentration would be 300 mOsM

Explanation:

In order to do this, we need to convert all concentrations to moles.

First, with the total body concentration, we have the initial volume of 3 liters and the concentration of 300 M (I will omit til the end the part of mOs)

The moles of the body concentration in this volume is:

moles = M * V

moles = 300 * 3 = 900 moles

To this moles, we add 150 moles of NaCL so, the total moles now is:

moles = 900 + 150 = 1050 moles

Finally, we can calculate the concentration with the new volume of 3.5 L (the sum of 3 and 0.5 liters added):

M = 1050 / 3.5

M = 300 mOsM

So the concentration remains the same as initial

Answer:

Kp and Kc are 0.01266 and 145.17, respectively.

Explanation:

Please check document attached.

Answer: Option (1) is the correct answer.

Explanation:

As per Le Chatelier's principle, any disturbance caused in an equilibrium reaction will tend to shift the equilibrium in a direction away from the disturbance.

For example, [tex]H_{2}O(g) + SO_{3}(g) \rightleftarrow H_{2}SO_{4}(g)[/tex]

As this given reaction is endothermic in the forward direction and exothermic in the backward direction. Thus, in order to shift the reaction on left side we need to decrease the temperature.

Also, the number of moles are more on reactant side as compared to product side. So, when we decrease the number of moles on reactant side then the equilibrium will shift on left side.

Therefore, we can conclude that for the given reaction decreasing the pressure of the system and lowering the temperature of the system would shift the reaction to the left.

Final answer:

Decreasing the pressure of the system and lowering the temperature for the reaction H₂O(g) + SO₃(g) ⇔ H₂SO₄(g) both shift the equilibrium to the left because Le Chatelier's Principle dictates that the system will counteract changes by shifting towards more gas molecules (when pressure decreases) and by absorbing heat (when temperature is lowered for an endothermic reaction).

Explanation:

To determine how changes in pressure and temperature affect the equilibrium of the reaction H₂O(g) + SO₃(g) ⇒H₂SO₄(g), Le Chatelier's Principle can be applied. This principle states that if a system at equilibrium is subjected to a change in conditions, the system will adjust to partially counteract the effect of the change.

For the reaction given, if we decrease the pressure, the equilibrium will shift towards the side with more gas molecules to increase the pressure again. Since the left side has two moles of gas and the right side has only one, decreasing the pressure will shift the equilibrium to the left.

Regarding temperature, since it's an endothermic reaction, heat can be considered a reactant. So, if we lower the temperature, the system will shift towards the side that absorbs heat to counteract the decrease in temperature, which would be shifting the equilibrium to the left. Therefore, the correct answer is 1. decreasing, lowering.

Answer:

They should obtain the same Rf for the same compounds.

Explanation:

The Rf is defined as A/B. Where A is the displacement of the substance of interest, and B is the solvent front.

By dividing the substance's displacement by B, we make it so that the Rf factor is equal for identical compounds in the same mobile phase, no matter what the solvent front is.

This is an incomplete question, here is a complete question.

For each trial, calculate the number moles of 6.0 M HCl used in the reaction?

Trial 1 : Volume of HCl = 15.0ml

Trial 2 : Volume of HCl = 14.9ml

Trial 3 : Volume of HCl = 15.2ml

Answer :

The number moles of HCl for trial 1, 2 and 3 is, 0.090 mol, 0.089 mol and 0.091 mol

Explanation :

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

[tex]\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]

In this question, the solute is HCl.

Now we have to calculate the number of moles of HCl for trial 1.

Volume of HCl = 15.0 mL = 0.015 L

[tex]6.0M=\frac{\text{Moles of HCl}}{0.015L}[/tex]

[tex]\text{Moles of HCl}=0.090mol[/tex]

Now we have to calculate the number of moles of HCl for trial 2.

Volume of HCl = 14.9 mL = 0.0149 L

[tex]6.0M=\frac{\text{Moles of HCl}}{0.0149L}[/tex]

[tex]\text{Moles of HCl}=0.089mol[/tex]

Now we have to calculate the number of moles of HCl for trial 3.

Volume of HCl = 15.2 mL = 0.0152 L

[tex]6.0M=\frac{\text{Moles of HCl}}{0.0152L}[/tex]

[tex]\text{Moles of HCl}=0.091mol[/tex]

Answer:

Phosphide ion

Explanation:

To achieve an octet, the phosphorus atom forms an ion. The name of this ion is Phosphide ion

Phosphorous have 15 electrons in shell. This means it has 5 electrons in its outer most shell well this means it requires 3 more electrons to complete its octate. Thus Phosphorus changes to phosphide ion with negative 3 sign  on it.

Answer:B

Explanation:

They have a full valence shell of 8

Answer:

Option B. 327°C

Explanation:

Absolute T° = T° in K

T° in K = T° in C + 273

T° in K - 273 = T° in C

600 K - 273 = 327°C

Answer:

The concentration of CaCl2 in this solution is 0.564 molar (option A)

Explanation:

Step 1: Data given

Mass of CaCl2 = 23.7 grams

Mass of water = 375 grams

Density of solution is 1.05 g/mL

Step 2: Calculate total mass

Total mass = mass of CaCl2 + mass of water

Total mass = 23.7 grams + 375 grams = 398.7 grams

Step 3: Calculate volume of the solution

Density = mass / volume

Volume = mass / density

Volume = 398.7 grams / 1.05 g/mL

Volume = 379.7 mL = 0.3797 L

Step 4: Calculate moles CaCl2

Moles CaCl2 = mass CaCl2 / molar mass CaCl2

Moles CaCl2 = 23.7 grams / 110.98 g/mol

Moles CaCl2 = 0.214 moles

Step 5: Calculate concentration

Concentration of CaCl2 = moles / volume

Concentration of CaCl2 = 0.214 moles / 0.3797 L

Concentration of CaCl2 = 0.564 mol / L = 0.564 molar

The concentration of CaCl2 in this solution is 0.564 molar (option A)

If an evaluating committee places the burden of proof of the safety of a new chemical on the manufacturer of the chemical, then the committee is using the precautionary principle

Explanation:

This is a method that is used to handle the problems that are related in affecting any person. This principle mainly aims in determining the safety of any new thing before it is released to the public. This will test whether the new thing does not make harm or destroy anything before it is introduced to public.

For instance let us take an example of a medicine introduction. Any new tablets when it is discovered must be tested. Without any testing, releasing it to public will only have adverse effect on them. The given scenario also relates with the precautionary principle since, the safety is considered as an important one by the evaluating committee.  

To calculate the enthalpy change for dissolving potassium bromide, use the equation q = mcΔT. Then divide the heat gained or lost by the mass of the substance to get the enthalpy change in J/g. To convert to kJ/mol, divide by the molar mass of potassium bromide.

To calculate the enthalpy change for dissolving the salt, we need to use the equation q = mcΔT, where q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. First, we calculate the heat gained by the water using m = 125g, c = 4.18J/goC, and ΔT = 24.2oC - 21.1oC. Next, we calculate the heat lost by the potassium bromide using m = 10.5g, c = 4.18J/goC, and ΔT = 24.2oC - 21.1oC. Finally, we can calculate the enthalpy change in J/g by dividing the heat gained or lost by the mass of the substance. To convert to kJ/mol, we need to use the molar mass of potassium bromide and divide the enthalpy change in J/g by the molar mass.

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Answer:

1.4moles

Explanation:

From the balanced equation below;

2H2 + O2 → 2H2O

2moles of hydrogen reacts with 1mole of oxygen to produce 2moles of water.

since we are only interested in comparing hydrogen and water, we can say 2moles of hydrogen will produce 2moles of water

Hence by comparism of moles;

1.4moles of hydrogen will produce 1.4moles of water

In the reaction 2H2 + O2 → 2H2O, the formation of water from hydrogen gas is a 1:1 ratio. Thus, 1.4 moles of hydrogen gas would produce 1.4 moles of water.

Analyzing balanced chemical equations is a fundamental approach to determine the stoichiometry of a chemical reaction. In this case, the equation 2H2 + O2 → 2H2O provides crucial information regarding the mole ratios of reactants and products. It signifies that 2 moles of hydrogen gas (H2) react completely with 1 mole of oxygen gas (O2) to yield 2 moles of water (H2O).

Therefore, when 1.4 moles of hydrogen gas are fully consumed in the reaction, the stoichiometry reveals that an equivalent amount, 1.4 moles, of water will be generated. This clear and direct correlation underscores the predictive power of balanced chemical equations in understanding the quantities of reactants and products in a chemical reaction.

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The mass of the magnesium that is produced is  [tex]2.1 * 10^{-8[/tex] g.

The ideal gas equation can also be expressed in different forms to solve for different parameters. For example, it can be rearranged to find the molar volume (V/n) or the number of moles (n) when other variables are known.

We have that;

PV = nRT

n = PV/RT

n = [tex]3.4 * 10^{-6[/tex] * 0.432/62.4 * 55

n = [tex]4.3 * 10^{-10[/tex] moles

If 2 moles of Mg produces 1 mole of oxygen

x moles of oxygen produces  [tex]4.3 * 10^{-10[/tex] moles of oxygen

x =[tex]8.6 * 10^{-10[/tex] moles

Mass of magnesium = [tex]8.6 * 10^{-10[/tex] moles * 24 g/mol

= [tex]2.1 * 10^{-8[/tex] g

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Answer : The new volume of was, 5.17 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.

Mathematically,

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

where,

[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.

[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.

We are given:

[tex]V_1=5.00L\\T_1=25^oC=(25+273)K=298K\\V_2=?\\T_2=35^oC=(35+273)K=308K[/tex]

Putting values in above equation, we get:

[tex]\frac{5.00L}{298K}=\frac{V_2}{308K}\\\\V_2=5.17L[/tex]

Therefore, the new volume of was, 5.17 L

Answer : The mass of [tex]CO_2[/tex] produced form the combustion is, 16.43 kg

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

[tex]Density=\frac{Mass}{Volume}[/tex]

First we have to calculate the mass of octane.

Given :

Density of octane = 0.703 g/mL

Volume = 2.00 gallons = 7570 mL

conversion used : 1 gallon = 3785 mL

Now put all the given values in the above formula, we get:

[tex]0.703g/mL=\frac{Mass}{7570mL}[/tex]

[tex]Mass=5321.71g[/tex]

Now we have to calculate the moles of octane.

[tex]\text{Moles of octane}=\frac{\text{Mass of octane}}{\text{Molar mass of octane}}[/tex]

Molar mass of octane = 114 g/mole

[tex]\text{Moles of octane}=\frac{5321.71g}{114g/mole}=46.68mole[/tex]

Now we have to calculate the moles of [tex]CO_2[/tex].

The balanced chemical combustion reaction of octane will be:

[tex]2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O[/tex]

From the balanced chemical reaction we conclude that:

As, 2 moles of [tex]C_8H_{18}[/tex] react to give 16 moles of [tex]CO_2[/tex]

So, 46.68 moles of [tex]C_8H_{18}[/tex] react to give [tex]\frac{46.68}{2}\times 16=373.44[/tex] moles of [tex]CO_2[/tex]

Now we have to calculate the mass of [tex]CO_2[/tex].

[tex]\text{ Mass of }CO_2=\text{ Moles of }CO_2\times \text{ Molar mass of }CO_2[/tex]

Molar mass of [tex]CO_2[/tex] = 44 g/mol

[tex]\text{ Mass of }CO_2=(373.44moles)\times (44g/mole)=16431.36g=16.43kg[/tex]

Thus, the mass of [tex]CO_2[/tex] produced form the combustion is, 16.43 kg

Answer:

Because of less weight kick ball has more acceleration.

Explanation:

Acceleration of kick ball:

5 m/s

Acceleration of soccer ball:

3 m/s

Newton's second law:

According to newton's second law the acceleration of object depends upon two variables.

1) Mass of object

2) Force acting on it

Mathematical expression:

a = f/m

a = acceleration

f = force

m = mass

The force on balls are same thus the acceleration is depend upon the masses of balls.

The soccer ball has more weight that's why its acceleration is less while kick ball is lighter and thus its acceleration will more.

Answer:

Based on Newton's second law, if the balls are kicked with the same force, the one with less mass will have a greater acceleration. Since the kickball accelerates more than the soccer ball, it has less mass.

Explanation:

Answer:

Diamond is burnt

Diamond (Carbon)+ Oxygen → CO2

Water electrolysed

2H2O → 2H2 + O2

Explanation:

Dalton atomic theory states that in a chemical reaction, the atoms of the elements join together or combine in simple whole number ratios

Hence when, at very high temperatures, diamond which consists of carbon is burnt we have

Diamond (Carbon)+ Oxygen → CO2

Also when water is electrolysed it decomposes as follows

2H2O → 2H2 + O2

Answer:

a. b + s = 26

b. b = 26 — s

Explanation:

Answer:

The coefficient of LiH is 1 (non written)

Explanation:

The equation is this:

LiH (s)  +  H₂O (l) → LiOH (aq)  +  H₂ (g)

Ratio is 1:1 between reactants and products.

The coefficient of LiH is 1

Li2O(s)+H2O(l)→2LiOH(aq)

Answer:

[C₆H₁₂O₆] = 0.17M

Explanation:

3% by mass, means 3 g of solute in 100 g of solution.

Density is mass / volume. This data always refers to solution.

Solution density = Solution mass / Solution volume

1.0097 g/mL = 100 g / Solution volume

Solution volume = 100 g / 1.0097 g/mL → 99.03 mL

Let's convert the mL to L, for molarity (mol/L)

99.03 mL = 0.09903 L

Now we have to find out the moles. Let's calculate them with the molar mass

(mass / molar mass)

3 g / 180 g/mol = 0.0166 mol

Molarity is mol/L → 0.0166 mol/0.09903 L → 0.17 M

The molarity of dextrose in a 3.00% by mass aqueous solution, with a density of 1.0097 g/mL, is calculated to be approximately 0.168 M by dividing the number of moles of dextrose (0.01665 mol) by the volume of the solution in liters (0.09903 L).

To calculate the molarity of dextrose in the solution, we'll first need to understand that molarity is defined as the number of moles of solute per liter of solution. Here, the solution is 3.00% by mass dextrose. This means that in 100 grams of the solution, there are 3 grams of dextrose.

Using the density of the solution (1.0097 g/mL), we'll calculate the volume that 100 grams of the solution occupies:

100 grams of solution contains 3 grams of dextrose. With the molar mass of dextrose (C6H12O6) being 180.16 g/mol, we calculate the number of moles in those 3 grams:

To find the molarity, we need the volume in liters:

Thus, the molarity (M) is:

The molarity of dextrose in the solution is approximately 0.168 M.

The equilibrium concentration of PCl5 is 0.0036 M.

The equation of the reaction is; PCl5(g) ⇄ PCl3(g) + Cl2(g)

The number of moles of PCl3 at equilibrium is = 0.27 M ×  1.00-L = 0.27 moles

Now;

Kc = [PCl3] [Cl2]/[PCl5]

Kc =  2.0 × 10^1 or 20

We can see that;

Number of moles  of PCl3 = Number of moles of Cl2 = 0.27 moles

Let the equilibrium concentration of PCl5 be x

20 = (0.27)^2/x

x =  (0.27)^2/20

x = 0.0036 moles

Since the volume does not change;

equilibrium concentration of PCl5 = 0.0036 moles/1.00-L = 0.0036 M

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For the given equilibrium, the reaction PCl5(g) PCl3(g) + Cl2(g) is staged. Given Kc = 2.0 x 101 and [PCl3] = 0.27M, we find that [Cl2] is also 0.27M due to a 1:1 ratio in the reaction. We can then solve for [PCl5], finally getting [PCl5] = 0.364 × 10-2 M.

The equilibrium for the reaction PCl5(g)  PCl3(g) + Cl2(g) is defined by the ratio of concentrations of the products to the reactants, expressed as Kc = [PCl3][Cl2] / [PCl5]. Given that Kc = 2.0 × 101 and [PCl3] = 0.27 M, we can solve for the equilibrium concentration of [Cl2] using the same Kc equation, resulting in [Cl2] = 0.27 M (since it's a 1:1 ratio in this particular reaction). Finally, substituting these concentrations back into the equilibrium constant expression, we can solve for [PCl5] by rearranging the equation to [PCl5] = [PCl3][Cl2] / Kc = 0.27 x 0.27 / 2.0 x 101 = 0.364 × 10-2 M.

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Answer:

The answer to your question is number 1. Pb

Explanation:

Data

10 grams of Na, C, Pb, and Ne

Process

Calculate the moles of each element

                        23 g of Na ----------------- 1 mol

                        10 g of Na ------------------- x

                               x = 0.43 moles of Na

                        20 g of Ne ---------------- 1 mol

                        10 g of Ne ----------------- x

                               x = 0.5 moles of Ne

                         64 g of Cu -------------- 1 mol

                          10 g of Cu -------------- x

                              x = 0.16 moles of Cu

                         207 g of Pb ------------- 1 mol

                            10 g of Pb -------------- x

                               x = 0.048 moles of Pb

Pb has the smallest number of moles

Answer:

Pb contains the smallest no of moles

Mole = mass/atomic mass

For lead no of mole = 10g/207.2g/mol

= 0.04826mol

For Cu no of mole = 10g/63.546g/mol = 0.1574mol

For Ne no of mole = 10g/20.1797g/mol = 0.4955mol

For Na no of mole = 10g/22.9898g/mol = 0.5350mol

Answer:

b. respiration

Explanation:

Food is converted into energy that can be used by the cells of the body by the process of cellular respiration. In cellular respiration, glucose and oxygen are combined and converted into water and carbon dioxide and energy. The produced energy is transferred to ATP.

In the presence of oxygen, cells convert glucose into energy through a process called aerobic metabolism, which is also referred to as cellular respiration. This process involves several stages and results in the formation of ATP, carbon dioxide, and water.

Cellular Respiration and Energy Conversion

In the presence of oxygen, cells convert glucose into energy via a process known as aerobic metabolism (option d), which is a type of cellular respiration. The term 'respiration' is often used to describe this process as well (option b). Aerobic metabolism involves the conversion of glucose and oxygen into carbon dioxide and water, releasing energy that is stored in molecules of ATP. This energy conversion process comprises several stages, including Glycolysis, Transformation of Pyruvate, the Krebs Cycle, and Oxidative phosphorylation. In contrast, anaerobic metabolism (a) occurs in the absence of oxygen and involves different pathways such as anaerobic glycolysis or fermentation.

Cellular respiration is a crucial part of energy metabolism for all aerobic organisms, allowing them to harness energy from food. It is a complex yet beautifully orchestrated series of chemical reactions that take place within the cells, more specifically within the mitochondria. The process ultimately results in the production of ATP, which is the primary energy carrier within the cell.