Answer:
Deposition
Explanation:
Answer:
Deposition...
Explanation:
Deposition is a process in which the water, ice and wind for layers of sediments when the fluid flow loses it's kinetic energy. After losing energy, the flow of soil in restricted and a layer over layer of soil is formed by deposition called sediments.
12.5M AgNO3 is made using 3.5L H2O. How many grams AgNO3 are needed to produce the solution?
Answer:
612 g
Explanation:
concentration or molarity is the number of moles of solute in 1 L of solution
the molarity of the solution is 12.5 M
therefore there are 12.5 mol in 1 L of solution
in 1 L of solution there are 12.5 mol
therefore in 3.5 L there are - 12.5 mol/L x 3.5 L = 3.6 mol
molar mass of AgNO₃ is 170 g/mol
mass of 3.6 mol of AgNO₃ is - 170 g/mol x 3.6 mol = 612 g
612 g of AgNO₃ is needed to make a 12.5 M solution
A __________ takes place when the sun, earth, and moon are in nearly a straight line with the earth being between the sun and the moon.
corona
lunar eclipse
solar eclipse
Lunar eclipse
A solar eclipse is when the Moon is between the Earth and the Sun, and a lunar eclipse is when the Earth is between the Moon and the Sun.
9) A 22.8 mL volume of argon gas is collected at 48.0o C. At constant pressure, what volume would this same sample of gas occupy at standard temperature?
Using Charles's Law, the volume of argon gas at standard temperature (0°C) after initial conditions of 22.8 mL at 48°C is calculated to be approximately 19.5 mL.
Explanation:The student is asking for help with the concept of how gas volume changes with temperature at constant pressure, a principle known as Charles's Law. Since the question involves argon gas, a noble gas, and relates to changes in temperature and volume, this is a Chemistry subject, typically studied in high school.
According to Charles's Law, the volume of a gas is directly proportional to its temperature when pressure is held constant. The formula relating initial and final volumes and temperatures is V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature. Here, T must be in Kelvin.
The standard temperature (STP) is defined as 0 degrees Celsius or 273.15 K. To find the volume at STP (V2) for the argon gas, we first convert the initial temperature from degrees Celsius to Kelvin:
T1 = 48.0 + 273.15 = 321.15 KV1 = 22.8 mL (initial volume)T2 = 0 + 273.15 = 273.15 K (STP)Now, we apply Charles's Law:
V1/T1 = V2/T2 -> (22.8 mL / 321.15 K) = V2 / 273.15 K
Multiplying both sides by 273.15 K to solve for V2 gives:
V2 = (22.8 mL * 273.15 K) / 321.15 K
V2 ≈ 19.5 mL
So, at standard temperature, this sample of argon would occupy approximately 19.5 mL.
2. At STP, how many liters of oxygen are required to react completely with 3.6 liters
of hydrogen to form water?
2H2(g) + O2(g)
2H20(g)
Answer:
1.8 L.
Explanation:
The balanced equation for the mentioned reaction is:2H₂(g) + O₂(g) → 2H₂O(g),
It is clear that 2.0 moles of H₂ react with 1.0 mole of O₂ to produce 2.0 moles of H₂O.
At STP, 3.6 L of H₂ reacts with (?? L) of oxygen gas:It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.
using cross multiplication:
1.0 mol of H₂ represents → 22.4 L.
??? mol of H₂ represents → 3.6 L.
∴ 3.6 L of H₂ represents = (1.0 mol)(3.6 L)/(22.4 L) = 0.1607 mol.
To find the no. of moles of O₂ nneded to react completely with 3.6 liters (0.1607 mol) of hydrogen:Using cross multiplication:
2.0 mol of H₂ react completely with → 1.0 mol of O₂, from stichiometry.
0.1607 mol of H₂ react completely with → ??? mol of O₂.
∴ The no. of moles of O₂ = (1.0 mol)(0.1607 mol)/(2.0 mol) = 0.08036 mol.
Again, using cross multiplication:1.0 mol of O₂ represents → 22.4 L, at STP.
0.08036 mol of O₂ represents → ??? L.
∴ The no. of liters of O₂ will be produced = (0.08036 mol)(22.4 L)/(1.0 mol) = 1.8 L.
Answer:
The answer is 1.8 L
Select the correct answer.
Which notation is used to represent gamma decay?
A.
B.
C.
D.
Gamma decay is usually represented by the Greek letter gamma (">gamma"). In the nuclear equation for the decay of boron-12, which emits a beta particle and a gamma ray, the resulting daughter isotope is carbon-12.
Explanation:In nuclear chemistry, gamma decay is often represented by the Greek letter gamma ">">">">">
^12B -> ^12C + e- + ">gamma">">The starting isotope is boron-12 (^12B). During the decay, a beta particle (e-) is emitted, which is essentially an electron, and a gamma ray is emitted as well. The resulting or daughter isotope is carbon-12 (^12C).
It's essential to memorize the symbols and notations for different types of radioactive decay, as they are commonly used in nuclear chemistry calculations. The emission of gamma rays typically accompanies other types of radioactive decay, such as alpha or beta decay, rather than occurring alone. Therefore, when writing nuclear equations, the presence of a gamma ray is shown by adding the gamma symbol to the equation.
a foce that pushes or pulls is known as
Answer:
Newton 3rd Law of Motion or the Law of Force Pairs
(An applied force)
Force is a phenomenon that creates a push or pull that has both magnitude and direction. No push or pull exists in isolation, and multiple forces interacting can have cumulative effects. The force can vary in magnitude and can manifest both as a contact force and a field force.
Explanation:A force is a push or pull that acts upon an object as a result of its interaction with another object. It has both magnitude and direction, therefore it's a vector quantity. Objects and systems are moved by forces. This area comes under the study of dynamics.
Examples of a force can include a person pushing a table (a contact force), or the gravitational pull of the Earth on a falling object (a field force). Forces have been categorized into many types such as push, pull, thrust, lift, weight, friction, and tension.
Keep in mind that no push or pull occurs in isolation (Newton's third law). For instance, when you are pushing a wall, the wall exerts an equal and opposite force on you.
When multiple forces act on an object, they add up like vectors. If two forces push in different directions on an object, the total force will be in the direction of the resultant force.
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Need help with this question
The answer is B.
Each of the points or vertex represent a carbon atom. Answer choice B is the only choice that has 8.
A gas has a volume of 450.0 mL. If the temperature is held constant, what volume would the gas occupy if the pressure were
a. doubled?
b. reduced to one-fourth of its original value?
a) Answer:
= 225 mL
Explanation:
Using Boyle's law of gases;
The volume of a fixed mass of a gas is inversely proportional to its pressure at constant temperature.
Therefore;
P1V1 = P2V2
in this case; let the initial pressure be P;
Therefore; V1 = 450 mL, P1 = P, V2 = ? and P2 = 2P
Thus;
V2 = P1V1/P2
= (P×450)/ (2P)
= 225 mL
Therefore, the new volume will be 225 mL
b) Answer;
=1800 mL
Explanation;
Let the initial pressure be P;
Therefore; V1 = 450 mL, P1 = P, V2 = ? and P2 = 1/4P
Thus;
V2 = P1V1/P2
= (P×450)/(0.25P)
= 1800 mL
Thus, when the pressure is reduced to one-fourth of its original, the new volume will be 1800 mL.
Given that the initial volume of the gas is 450 mL, the new volume of the gas obtained based on the given data are:
A. The new volume of the gas when the pressure is doubled is 225 mL
B. The new volume of the gas when the pressure is reduced to one-fourth of its original value is 1800 mL
A. How to determine the new volume Initial volume (V₁) = 450 mL Temperature = constant Initial pressure (P₁) = PNew pressure (P₂) = 2PNew volume (V₂) =?P₁V₁ / T₁ = P₂V₂ / T₂
Since the temperature is constant, we have:
P₁V₁ = P₂V₂
P × 450 = 2P × V₂
Divide both side by 2P
V₂ = (P × 450) / 2P
V₂ = 450 / 2
V₂ = 225 mL
B. How to determine the new volume Initial volume (V₁) = 450 mL Temperature = constant Initial pressure (P₁) = PNew pressure (P₂) = ¼PNew volume (V₂) =?P₁V₁ / T₁ = P₂V₂ / T₂
Since the temperature is constant, we have:
P₁V₁ = P₂V₂
P × 450 = ¼P × V₂
450P = PV₂ / 4
Cross multiply
450P × 4 = PV₂
Divide both side by P
V₂ = (450P × 4) / P
V₂ = 450 × 4
V₂ = 1800 mL
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Absolute zero is ______. the lowest possible volume occupied by a gas the lowest possible temperature of a gas the lowest possible pressure exerted by a gas none of the above
Answer:
Absolute zero is the lowest possible temperature of a gas.
Explanation:
Absolute zero is the lowest possible temperature where nothing could be colder and no heat energy remains in a substance. Absolute zero is the point at which the fundamental particles of nature have minimal vibrational motion, retaining only quantum mechanical, zero-point energy-induced particle motion.By international agreement, absolute zero is defined as precisely; 0 K on the Kelvin scale, which is a thermodynamic (absolute) temperature scale; and –273.15 degrees Celsius on the Celsius scale.Absolute zero is the lowest possible temperature, at which all molecular motion theoretically stops. Its actual implications, especially concerning the volume of a gas, don't fully comply with classical interpretations and delve into the realm of quantum physics.
Explanation:Absolute zero is the lowest possible temperature at which all molecular motion ceases. It is defined as 0 on the Kelvin scale and equivalent to -273.15 degrees Celsius. This temperature is theoretically the point at which a gas would have no kinetic energy.
It's important to understand that while at temperatures near absolute zero, the behavior of real gases deviates from that predicted by ideal gas laws like Charles's Law or Amonton's Law. These deviations occur because the volume of the gas molecules themselves becomes appreciable relative to the total volume occupied by the gas and the collisions between the molecules can no longer be ignored.
However, these assumptions become less valid as temperatures approach absolute zero. The volume of a gas at absolute zero is a matter of quantum physics, and doesn't strictly comply with classical interpretations of gas behavior.
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How does a catalyst speed up a chemical reaction? A. by lowering the activation energy B. by lowering the ΔH of the reaction C. by raising the energy of the products D. by raising the energy of the reactants
Answer:
A. by lowering the activation energy
Explanation:
Adding a catalyst has this effect on activation energy. A catalyst provides an alternative route for the reaction with a lower activation energy. As illustrated in the attached image.This means that more particles have the activation energy required for the reaction to take place (compared to without the catalyst) and so the speed of the reaction increases.Answer:
A. By Lowering the activation energy
Explanation
edmentum/plato family!
give me likes plz!
The circles in the model represent atmospheric layers. Make each description with the correct name of each layer.
Answer:
The bottom is troposhere the next is sratoshere,mesosphere,thermosphere then exoshere
Explanation:
The study of the atmosphere is called metrology. There are different types of components present in the atmosphere and these are gases and impure particles.
What is the atmosphere?An atmosphere is a layer of gas or layers of gases that envelope a planet and is held in place by the gravity of the planetary body. A planet retains an atmosphere when the gravity is great and the temperature of the atmosphere is low.
According to the question, the layers name is as follows:-
Troposphere StratosphereMesosphereThermosphere ExosphereHence, the answer is mentioned above.
For more information about the layers, refer to the link:-
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a sample of an unknown substance has a mass of .158 kg if 2,510 J of heat is required to heat the substance from 32°C to 61°C what is the specific heatt of the substance
.171
.548
15.9
86.6
Answer: 0.548J/g°C
Explanation:
Q = s × m × DeltaT
Q = Heat (J)
S = Specific Heat Capacity
M = mass (g)
DeltaT = Change in temperature (°C)
0.158Kg x 1000 = 158g
2.510J = s x 158g x (61°C-32°C)
2.510J/(158g x 29°C) = s
S = 0.54779.... J/g°C
S = 0.548 J/g°C
Need help !!!!! ASAP
The answer is:
The approximate volume is 9.84 L.
[tex]V=9.84L[/tex]
Why?Since we are given the numer of moles, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.
The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:
[tex]PV=nRT[/tex]
Where,
P is the pressure of the gas.
V is the volume of the gas.
n is the number of moles of the gas.
T is the absolute temperature of the gas (Kelvin).
R is the ideal gas constant, which is equal to:
[tex]R=0.082\frac{atm.L}{mol.K}[/tex]
So, we are given the information:
[tex]n=1.5mol\\Temperature=300K\\Pressure=3.75atm[/tex]
Now, substituting the given information and isolating the Volume from The Ideal Gas Law equation, we have:
[tex]PV=nRT[/tex]
[tex]V=\frac{nRT}{P}[/tex]
[tex]3.75atm*V=1.5mol*0.082*\frac{atm.L}{mol.K}*300K[/tex]
[tex]V=\frac{ 1.5mol*0.082*\frac{atm.L}{mol.K}*300K}{3.75atm}\\\\V=\frac{36.9atm.L}{3.75atm}=9.84L[/tex]
So, the approximate volume is 9.84 L.
[tex]V=9.84L[/tex]
Have a nice day!
how many atoms are in 63.5 grams of Hg
what best describes charles law
A) If volume increases, temperature increases
The law is V/T, meaning the two values are directly proportional, as one increases, the other increases too.
The statement which best describes Charles law is: A) If volume increases, temperature increases.
What is Charles law?Charles law states that when the pressure of an ideal gas is kept constant, the volume of a gas is directly proportional to the absolute temperature of the gas.
Mathematically, Charles law is given by this formula;
[tex]V\;\alpha \;T\\\\V=kT[/tex]
This ultimately implies that, as the volume of an ideal gas increases, its temperature also increases in accordance with Charles law.
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What is the mass of N2 in a 56 liter container at STP?
Answer:
Explanation:molar mass of N2=28
Volume occpied at stp=22.4 so 28/22.4=1.25 so mass nitrogen will be 56 multiply 1.25 =70g
Need help !!!!! ASAP
The answer is:
The new volume is 2.84 L.
[tex]V_{2}=2.84L[/tex]
Why?To solve the problem, we need to remember what STP means. STP means that the gas is at standard temperature and pressure, or 273.15 K (0°C) and 1 atm.
Also, we need to use the Combined Gas Law, since the temperature, the pressure and the volume are being changed.
The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using , Gay-Lussac's Law, Charles's Law, and Boyle's Law.
The law is defined by the following equation:
[tex]\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}[/tex]
Where,
[tex]P_{1}[/tex] is the first pressure.
[tex]V_{1}[/tex] is the first volume.
[tex]T_{1}[/tex] is the first temperature.
[tex]P_{2}[/tex] is the second pressure.
[tex]V_{2}[/tex] is the second volume.
[tex]T_{2}[/tex] is the second temperature.
So, we are given the following information:
[tex]V_{1}=2L\\P_{1}=1atm\\T_{1}=0\°C=273.15K\\P_{2}=80kPa=0.8atm\\T_{2}=37\°C=37+273=310K[/tex]
Then, isolating the new volume, and substituting, we have:
[tex]\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}\\\\V_{2}=\frac{P_{1}V{1}}{T_{1}}*\frac{T_{2}}{P_{2}}\\\\V_{2}=\frac{1atm*2L}{273.15K}*\frac{310K}{0.8kPa}=2.84L[/tex]
Hence, the new volume is 2.84 L.
[tex]V_{2}=2.84L[/tex]
Have a nice day!
how much heat is required to raise the temperature of 1.248kg of gold from 22.0°c to 45.0°c(c=0.129j/g°c)
Answer:
= 3,702.816 Joules
Explanation:
Heat absorbed by water is equivalent to heat released by copper.
Heat absorbed is given by:
Q = mcΔT
where m is the mass, c is the specific capacity and ΔT is the change in temperature.
Mass = 1248 g
ΔT = 45°C - 22°C = 23°C
c = 0.129j/g°c
Heat = 1248 g × 23°C × 0.129j/g°C
= 3,702.816 Joules
The heat required can be calculated using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change.
Explanation:The amount of heat required to raise the temperature of a substance can be calculated using the formula:
Q = mcΔT
Where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity, and ΔT is the temperature change. In this case, the mass of the gold is 1.248 kg, the specific heat capacity is 0.129 J/g°C, and the temperature change is from 22.0°C to 45.0°C. Converting the mass to grams (1.248 kg = 1248 g), we can calculate the heat energy:
Q = (1248 g)(0.129 J/g°C)(45.0°C - 22.0°C) = 19230.72 J
Therefore, the total amount of heat required to raise the temperature of 1.248 kg of gold from 22.0°C to 45.0°C is 19230.72 Joules.
How many moles of cesium xenon heptafloride can be produced from the reaction 12 mol cesium Floride with 14 mol xenon hexafloride
Answer:
12 moles of cesium xenon heptafluoride
Explanation:
The reaction of cesium fluoride with xenon hexafluoride is CeF + XeF6 -> CeXeF7 and the reaction is balanced as written. So the mole ratio is 1:1:1. We are given 12 moles of CeF and 14 moles of XeF6 are reacting, but after the 12 moles of CeF react completely, the reaction will stop as we have run out of one of our reactants. So only 12 moles of CeXeF7 will be produced.
Final answer:
12 moles of cesium xenon heptafluoride can be produced from the reaction of 12 mol cesium fluoride with 14 mol xenon hexafluoride, assuming a 1:1 molar ratio in the reaction and complete consumption of reactants.
Explanation:
To determine how many moles of cesium xenon heptafluoride (CsXeF₇) can be produced from 12 mol cesium fluoride (CsF) with 14 mol xenon hexafluoride (XeF₆), we first need to know the balanced chemical reaction. This reaction can be expressed as:
CsF + XeF₆ → CsXeF₇
If we assume 100% efficiency and that all reactants are used up completely, we would expect 12 moles of CsF to fully react with 12 moles of XeF6 since the reaction is in a 1:1 molar ratio. Therefore, the amount of product formed, CsXeF₇, would be 12 moles. The remaining 2 moles of XeF₆ will not react as there is no additional CsF to react with.
Identify the examples of diffusion in the list below. check all that apply
A) A teacher takes the cap off a permanent marker. A few minutes later, students at the back of the classroom complain about the odor of the marker
B) A cooking school students burns a piece of toast. Soon, the entire kitchen smells like burnt toast
C) An inflated balloon shrinks when it is placed in a cold freezer
D) Toxic fumes produced by chemical factory are detected in the air in a town several miles away
E) Heating a flexible container filled with gas causes it to expand
Answer: A, B, D
Explanation:
all of these examples show matter moving from a high volume of matter, to low volume of matter. When the molecules of the paint, toast, and chemicals were released, they will try to disperse away from the high concentration
Examples of diffusion include the spread of marker odor in a classroom, the smell of burnt toast in a kitchen, and the detection of toxic fumes in a town miles from a chemical factory. Diffusion is the movement of particles from an area of higher concentration to an area of lower concentration.
Explanation:Examples of diffusion in the list provided include:
A) A teacher takes the cap off a permanent marker. A few minutes later, students at the back of the classroom complain about the odor of the marker. This is diffusion because the odor molecules move from a region of higher concentration near the marker to a lower concentration throughout the classroom.B) A cooking school student burns a piece of toast. Soon, the entire kitchen smells like burnt toast. Again, this is an example of diffusion as the smell of burnt toast moves from the area of higher concentration around the toast to the rest of the kitchen.D) Toxic fumes produced by a chemical factory are detected in the air in a town several miles away. The movement of fumes from a high concentration near the factory to a lower concentration in the town is diffusion.Option C) is not an example of diffusion; it is an example of the gas contracting due to lower kinetic energy when cooled. Option E) concerns the expansion of a container with gas when heated due to increased pressure, not diffusion.
What do we call a product of a reaction that is an insoluble substance
Answer:
Precipitate.
Explanation:
Precipitation reaction is a reaction in which to a substance called a precipitate separate in solid form from a solution, as by means of a reagent called precipitant.For example:The reaction between AgNO₃ and NaCl:
AgNO₃ + NaCl → AgCl↓ + NaNO₃
It will produce insoluble substance (AgCl) which is considered as a precipitate.
How many moles of sulfur atoms are present in 2.00 moles of CS2 ?
Answer: 4 mol
C + 2S = CS2
1 mol of CS2 contains 2 mol of sulfur
So 2 mol of cs2 contains 2*2 mol of S
2mol CS2 x 2 mol S/ 1 mol CS2 =
4 mol S
Final answer:
In 2.00 moles of carbon disulfide (CS2), there are 4.00 moles of sulfur atoms because each molecule of CS2 contains two sulfur atoms.
Explanation:
The question asks how many moles of sulfur atoms are present in 2.00 moles of carbon disulfide (CS2). Carbon disulfide is a chemical compound made up of one carbon atom and two sulfur atoms per molecule (CS2).
To determine the moles of sulfur atoms, we use the mole ratio from the molecular formula, which is 1 mole of CS2 contains 2 moles of sulfur (S). Accordingly, for 2.00 moles of CS2, we would have:
2.00 moles CS2 × (2 moles S / 1 mole CS2) = 4.00 moles of sulfur atoms.
A cube 20 cm could contain how many millimeters of fluid
Answer:
The cube will contain 8000 mL of the fluid.
Explanation:
Knowing that the volume of the cube = L³.where, L is the edge length.
∴ V of the cube = L³ = (20.0 cm)³ = 8000 cm³.
Knowing that 1.0 cm³ = 1.0 mL.
∴ The cube will contain 8000 mL of the fluid.
Select all of the examples of an acid
Answer:
An acid would be soemthing that starts with H (hydrogen)
That is just the way it is written chemically.
Hope this helped!
Explanation:
which reaction releases the most energy
I believe the answer is A
Boyle's Law relates temperature to gas volume and Charles's Law relates pressure to gas volume.
True
False
False100% sure of it
What is the molar mass of Cu(OH)2
Answer:
97.54
Explanation:
Molar mas of cu (oh) 2
Cu = 63.54
O x 2 = 16 x 2 = 32
H x 2 = 1 x 2 = 2
TOTAL = 97.54
11th grade chemistry study guide need help
Answer:
45) the answer is C.
46) The calculation of quantities in chemical reaction is called Stoichiometry .
47) The phase changed from solid to gas so I think the answer is A.
48) The phase changed from solid to gas as well so I think that the answer is A again.
49) Applying the formula n = m/M, we have n = 1.5 moles, therefore the answer is D.
50) C2H4 + 3O2 -> 2H2O + 2CO2
The answer is C.
51) The answer is C.
52) 2NaHCO3 + CaCl2 -> CaCO3 + H2O + 2NaCl + CO2
Hopefully I got all of them correct.
When 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because
7.5 mol of hydrogen would be needed to consume the available nitrogen.
7.5 mol of nitrogen would be needed to consume the available hydrogen.
hydrogen would produce 7.5 mol more ammonia than nitrogen.
nitrogen would produce 7.5 mol more ammonia than hydrogen.
Answer:
7.5 mol of hydrogen would be needed to consume the available nitrogen.
Explanation:
The balanced equation of the reaction of hydrogen with nitrogen is:3H₂ + N₂ → 2NH₃
it is clear that 3mol of hydrogen react with 1 mol of Nitrogen to give 2 mol of ammonia.
firstly, we need to calculate the number of moles of bothfor H₂:
number of moles = mass / molar mass = (7.00 g) / (2.00 g/mol) = 3.5 mol.
for N₂:
number of moles = mass / molar mass = (70.00 g) / (28.00 g/mol) = 2.5 mol.
using cross multiplication
1 mol of N₂ needs → 3 mol of H₂
2.5 mol of N₂ needs → ??? mol of H₂
∴ the number of mol of H₂ needed = (3*2.5) / 1 = 7.5 mol
So, the right choice is:
7.5 mol of hydrogen would be needed to consume the available nitrogen.
Answer:
Its A
Explanation:
Solution X mixed with magnesium chloride solution to form a white precipitate. The white precipitate obtained and reacted with dil HCL to give colourless gas bubbles turn lime water milky
What is solution X?
Answer:
Solution X might be a solution of carbonate ions [tex]\text{CO}_3^{2-}\;(aq)[/tex].
The question doesn't tell much about the positive ion in solution X. The ion itself shall not react with carbonate ions [tex]\text{CO}_3^{2-}\;(aq)[/tex] to form a precipitate. For that, cations from group 1 metals will work. For example, X can be a solution of sodium carbonate, which contain a large number of sodium ions [tex]\text{Na}^{+}\;(aq)[/tex].
Explanation:
Start with the first observation:
"Solution X mixed with magnesium chloride solution to form a white precipitate."
A solution of magnesium chloride [tex]\text{MgCl}_2\;(aq)[/tex] contains both
[tex]\text{Mg}^{2+}\;(aq)[/tex] ions and[tex]\text{Cl}^{-}\;(aq)[/tex] ions.Both may react to form a white precipitate.
[tex]\text{Mg}^{2+}\;(aq)[/tex] ions:
[tex]\text{Mg}^{2+}\;(aq)[/tex] might react with hydroxide ions [tex]\text{OH}^{-}\;(aq)[/tex] to form the white-colored, weakly-soluble base magnesium hydroxide [tex]\text{Mg}(\text{OH})_2\;(s)[/tex]. [tex]\text{Mg}^{2+}\;(aq)[/tex] might also react with carbonate ions [tex]\text{CO}_3^{2-}[/tex] to form the white-colored, insoluble salt magnesium carbonate, [tex]\text{MgCO}_3\;(s)[/tex].[tex]\text{Cl}^{-}\;(aq)[/tex] ions:
[tex]\text{Cl}^{-}\;(aq)[/tex] ions might react with silver ions [tex]\text{Ag}^{+}\;(aq)[/tex] to form the white-yellowish insoluble salt silver chloride [tex]\text{AgCl}\;(s)[/tex].Second observation:
"The white precipitate obtained and reacted with [dilute] HCl to give [colorless] gas bubbles."
Indeed [tex]\text{Mg}(\text{OH})_2\;(s)[/tex] will react with dilute HCl, but no gas will be formed: [tex]\text{Mg}(\text{OH})_2\;(s) +2\;\text{HCl}\;(aq)\to\text{MgCl}_2\;(aq) + 2\;\text{H}_2\text{O}\;(l)[/tex].[tex]\text{MgCO}_3\;(s)[/tex] reacts with dilute HCl to produce the colorless gas carbon dioxide [tex]\text{CO}_2\;(g)[/tex]: [tex]\text{MgCO}_3\;(s) + 2\;\text{HCl}\;(aq) \to\text{MgCl}_2\;(aq)+\text{H}_2\text{O}\;(l) +\text{CO}_2\;(g)[/tex].Silver chloride [tex]\text{AgCl}\;(s)[/tex] does not react with dilute HCl.The carbon dioxide gas from the reaction between [tex]\text{MgCO}_3\;(s)[/tex] and dilute HCl reacts with lime water (saturated calcium hydroxide [tex]\text{Ca}(\text{OH})_2\;(aq)[/tex] solution in water) to form the white-colored, insoluble salt calcium carbonate [tex]\text{CaCO}_3\;(s)[/tex]. The [tex]\text{CaCO}_3\;(s)[/tex] precipitate will turn the lime water milky.
In summary,
[tex]\rm \underbrace{\text{Na}_2\text{CO}_3\;(\rm aq)}_{\text{White Precipitate}} + \text{MgCl}_2 \;(aq) \to 2\;\text{NaCl}\;(aq) + \underbrace{\text{MgCO}_3\;(\rm s)}_{\text{White Precipitate}[/tex].
[tex]\rm \underbrace{\text{MgCO}_3\;(\rm s)}_{\text{From Solution X}} + \text{HCl} \;(aq) \to \text{MgCl}_2\;(aq) + \rm H_2O\;( aq) + \underbrace{{\rm CO_2}\;(g)}_{\rm Colorless\;Gas}[/tex].
[tex]\rm Ca(OH)_2\;(aq)+CO_2\;(g)\to \underbrace{\rm CaCO_3\;(s)}_{\begin{aligned}&\small\text{Turns Lime}&\\[-0.5em]&\small\text{Water Milky}&\end{aligned}} + H_2O\;(l)[/tex].