the volume of the Box 4 inches wide 2 inches high and 5 in long is

Answer:

3 square units

Step-by-step explanation:

The formula is 1/2*b*h. You plug in and solve 1/2*10*3/5.

Answer:

6 < n < 56

Step-by-step explanation:

Let's translate that into a symbolic relationship:

1 < (56/n) < 7

This produces two inequalities to be solved:  1 < (56/n) and (56/n) < 7.

Dividing both sides of (56/n) < 7 by 7 results in (6/n) < 1

which can be rewritten as 6 < n or n > 6.

Multiplying both sides of 1 < (56/n) by n results in n < 56.

There's no one solution.  Rather, the solution set is 6 < n < 56.

The solution set is 8 < n < 56 for number so 56 divide n is greater than 1 but less than 7

A relationship between two expressions or values that are not equal to each other is called 'inequality.

Given,

a number so 56 divide n is greater than 1. But less than 7

56/n>1

56/n < 7

This sentence can be written as

1 < (56/n) < 7

Two inequalities to be solved:  

1 < (56/n) and (56/n) < 7.

n<56 and 56/7<n

n<56 and 8<n

Dividing both sides of (56/n) < 7 by 7 results in (8/n) < 1

which can be rewritten as 8 < n or n > 8.

Multiplying both sides of 1 < (56/n) by n results in n < 56.

There's no one solution.  

Hence, the solution set is 8 < n < 56.

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[tex]\text{Hey there!}[/tex]

[tex]\text{What is the greatest common factor of 86 and 43?}[/tex]

[tex]\text{Factors of 86}\rightarrow\text{1, 2, 43, 86}[/tex]

[tex]\text{Factors of 43}\rightarrow\text{1, 43}[/tex]

[tex]\text{Common factors of BOTH NUMBERS: 1, 2, 43}[/tex]

[tex]\text{Out all the common factors of those we listed just now, 43 is the biggest one}[/tex]

[tex]\boxed{\boxed{\text{Answer: 43}}}\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{LoveYourselfFirst:)}[/tex]

The Greatest Common Factor(GCF) of 86 and 43 is 1 because 43 is a prime number and does not have any other factors apart from 1 and itself, and 43 does not divide evenly into 86.

To find the Greatest Common Factor (GCF) of 86 and 43, we first need to understand what a GCF is. The GCF of two or more numbers is the largest number that divides evenly into each of the numbers. The GCF for these numbers is 1 because the number 43 is a prime number and does not have any other factors apart from 1 and itself. In addition, 43 does not divide evenly into 86, leaving us with 1 as the higher factor that divides both 43 and 86.

So, the Greatest Common Factor of 86 and 43 is 1.

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which is the radius and which one is the hieght??

The answer is:

The center of the circle is located on the point (-9,-2) and the radius is 6 units.

To solve the problem, we need to use the given equation which is in the general form.

We are given the circle:

[tex]x^{2}+y^{2}+18x+4y+49=0[/tex]

We know that a circle can be written in the following form:

[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]

Where,

h is the x-coordinate of the center of the circle

k is the y-coordinate of the center of the circle

r is the radius of the circle.

So, to find the center and the radius, we need to perform the following steps:

- Moving the constant to the other side of the equation:

[tex]x^{2}+y^{2}+18x+4y=-49[/tex]

- Grouping the terms:

[tex]x^{2}+18x+y^{2}+4y=-49[/tex]

- Completing squares for both variables, we have:

We need to sum to each side of the equation the following term:

[tex](\frac{b}{2})^{2}[/tex]

Where, b, for this case, will the coefficients for both terms that have linear variables (x and y)

So, the variable "x", we have:

[tex]x^{2} +18x[/tex]

Where,

[tex]b=18[/tex]

Then,

[tex](\frac{18}{2})^{2}=(9)^{2}=81[/tex]

So, we need to add the number 81 to each side of the circle equation.

Now, for the variable "y", we have:

[tex]y^{2} +4y[/tex]

Where,

[tex]b=4[/tex]

[tex](\frac{4}{2})^{2}=(2)^{2}=4[/tex]

So, we need to add the number 4 to each side of the circle equation.

Therefore, we have:

[tex](x^{2}+18x+81)+(y^{2}+4y+4)=-49+81+4[/tex]

Then, factoring, we have that the expression will be:

[tex](x+9)^{2}+(y+2)^{2}=36[/tex]

- Writing the standard form of the circle:

Now,  from the simplified expression (after factoring), we can find the equation of the circle in the standard form:

[tex](x+9)^{2}+(y+2)^{2}=36[/tex]

Is also equal to:

[tex](x-(-9))^{2}+(y-(-2))^{2}=36[/tex]

Where,

[tex]h=-9\\k=-2\\r=\sqrt{36}=6[/tex]

Hence, the center of the circle is located on the point (-9,-2) and the radius is 6 units.

Have a nice day!

The answer is:

The general form of the circle is:

[tex]x^{2} -2x+y^{2} +4y=0[/tex]

We are given the standard form of a circle, so, to calculate the general form, we need to solve notable products.

We must remember the way to solve the notable product:

[tex](a+b)^{2}=a^{2}+2ab+b^{2} \\\\(a-b)^{2}=a^{2}-2ab+b^{2}[/tex]

So,

We are given the equation:

[tex](x-1)^{2}+(y+2)^{2}=5[/tex]

Then, solving the notable products, and adding/subtracting like terms, we have:

[tex]x^{2} -2*1x+1+y^{2}+2*2y+4=5\\x^{2} -2x+1+y^{2} +4y+4=5\\\\x^{2} -2x+y^{2} +4y+1+4-5=0\\\\x^{2} -2x+y^{2} +4y=0[/tex]

Hence,  have that the general form of the circle is:

[tex]x^{2} -2x+y^{2} +4y=0[/tex]

Have a nice day!

Answer:

C, $3,555.63

Step-by-step explanation:

to answer this, we have to use the compound interest formula which is:

A = P(1 + r/n)^nt

the meanings of each variable are:

A = result

P = principal amount

r = rate (in decimal form)

n = the number of compound periods (eg: annually, quarterly, etc)

t = time

in the word problem, we need to solve for A. we are given P, r, n, and t.

P = 2,400

r = 0.0395 also known as 3.95%

n = 4 keyword being quarterly which is equal to the value of 4

t = 10

we can plug these values into the formula:

A = 2400(1 + 0.0395/4)^(4)(10)

we can use a calculator to calculate this easier but ill break it down:

A = 2400(1 + 0.0395/4)^(4)(10)

A = 2400(1 + 0.0395/4)^40

A = 800(1.009875)^40

A = 2400(1.48151088)

A ≈ 3555.626

we can round 3555.626 to the nearest hundredth which is $3555.63

you would have earned $3555.63 in 10 years

our answer would be C

y = 3x + 2

When you graph this line, it goes across every single point, so it is the line of best fit. See the attached graph.

Answer:

12+4/8

Step-by-step explanation:

sum means add and you need to divide 8 by whatever 12 and 4 equal

12+4= 16

16/8=2

2

For this case we must represent the expression given above algebraically.

We have that the sum of 8 and 12 is represented as:

[tex]8 + 12[/tex]

We must divide the sum by 4:

[tex]\frac {8 + 12} {4} =\\\frac {20} {4} =\\5[/tex]

Finally, the result of the expression is 5.

ANswer:

5

Answer:

Changing value of "b" changes the period of the cosine graph.

Step-by-step explanation:

Question says to find about how does the b-value affect your cosine graph.

General equation of cosine function can be given as:

[tex]y=a\cdot\cos\left(bx-c)\right)+d[/tex]

In that formula, value of  "[tex]\frac{2 \pi}{b}[/tex]" gives period.

So changing value of "b" changes the period of the cosine graph.

Answer:

11 : 15

Step-by-step explanation:

Given

$5.5 : 7.5 ← divide both parts by 5

= 1.1 : 1.5 ← multiply both parts by 10

= 11 : 15 ← in simplest form

Answer:

The value of b is 55

The value of c is 28

The expression for the height of the ball at time t is h(t) = -16t² + 55t + 28

Step-by-step explanation:

* Lets discus the situations in the problem

- The ball was lunched up from a tower of height 28 feet above

  the ground

∴ The initial height = 28 feet ⇒ (initial means time is zero)

- The ball launched with an initial velocity 55 feet/second

∴ The initial velocity = 55 feet/second ⇒ (at t = 0)

- The equation of the height of the ball after t second is:

  h = ut + 1/2 at² + hi, where u is the initial velocity, a is the acceleration of

  gravity, t is the number of seconds since the ball was lunched

  hi is the initial height which the ball was lunched from it  and h is the

  height above the ground

∵ The ball was lunched up

∴ The gravity acceleration is -16 feet/second²

∵ The initial velocity is upward

∴ u = 55 feet/second

∵ The tower is 28 feet above the ground

∴ hi = 28 feet

- Substitute these values in the equation

∴ h = 55t + 1/2(-32)t² + 28 ⇒ simplify

∴ h = 55t - 16t² + 28 ⇒ start with t²

∴ h = -16t² + 55t + 28

* Now compare between the two equation

∵ h = -16t² + bt + c

∵ h = -16t² + 55t + 28

∴ b = 55 ⇒ coefficient of t

∴ c = 28

∴ h(t) = -16t² + 55t + 28

Answer:

which fraction equals -9/16--------->An equivalent fraction is nothing but, when the numerator and denominator of the fraction are equal when written in lowest terms. The fraction 3/9 is equal to 1/3 when reduced to lowest terms.

Step-by-step explanation:

-18/32, -27/48 are the fractions which are equivalent fractions of -9/16.

Numerical value that is a part of a whole is called as Fraction. It is evaluated by dividing a whole into number of parts.

We have to find an equivalent fraction of -9/16

To find the equivalent fraction  multiply both the numerator and denominator by the same number.

Multiply both the denominator and numerator of -9/16 by 2

(-9 x 2)/(16 x 2)

= -18/32

Now let us multiply both the numerator and denominator of -9/16 by 3, we get:

(-9 x 3)/(16 x 3)

= -27/48

Therefore,  -18/32, -27/48 are the fractions which are equivalent fractions of -9/16.

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Answer

$1.38

OR 11.5 cents per bag

Ok lets start

the bulk chips has a total of 10.50

the individual cost 0.99 each

Multiply 0.99 by 12 so everything is fair

0.99 x 12 =11.88

The bulk chips ae 10.50

To find the difference we subtract

10.50 from 11.88  (remember, 10.50 is the cost of buying in bulk!)

11.88-10.50 = 1.38

divide 1.38 by 12

We save $1.38 by buying in bulk or

11.5 cents per bag by buying bulk

Hope this answers your question,

~Jeron

Answer:

Step-by-step explanation:

Given that the bulk chips has a total of 10.50

The individual cost 0.99 each

To compare both

Multiply 0.99 by 12

[tex]0.99 x 12 =11.88[/tex]

The bulk chips ae 10.50

11.88 is more than 10.50

Hence purchasing in bulk is cheaper by 1.38 dollars.

To find the difference we subtract

10.50 from 11.88

[tex]11.88-10.50 = 1.38[/tex]

Answer:

Putting 5x^2 +2 = 4x into standard form:

5x^2 -4x  +2 = 0

a=5 b= -4 c=2

Step-by-step explanation:

Answer

A= 5

B= -4

C= 2

Hello! :)

While they don't give nearly enough information on sampling size to be credible data or how many kids vs how many adults, the simplistic answer is (B) a greater percentage of kids experienced side effects among their peers than the adults among their peers.  The sneaky thing about statistics is you can make the data say anything you want. 

Hope I helped and answered in time!

Good luck!

~ Destiny ^_^

A greater percentage of kids experienced side effects among their peers than the adults among their peers.

The relative frequency helps us to see the number of the population studied that can be associated with a particular class.

From the relative frequency table, we can see that; a greater percentage of kids experienced side effects among their peers than the adults among their peers.

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Answer:

A scale drawing is a drawing that shows the size of an object reduced or enlarged by a certain amount. The most common example is a map.

If we were to create a real size map of a house it would be a HUGE map. We wouldn't be able to grab it using our hands, and it wouldn't be useful either. The idea of a map is to have a diagrammatic representation of something.

Intead, we create maps where the size of the house is reduced by a certain scale. So we can see the distribution of the house, and -at the same time- know the measures of it.

I am attaching an example of a map. It's the map of mexico, and you can see the scale of the map at the bottom.

Answer:

Full question attached below.

Yes, the system of equations on line 4 has the same solution set as the system of equations on line 1

Step-by-step explanation:

There is no difference between the systems of line 1 and 4

1st system

5x + 3y = 14

4x - 2y = -2

4th system

10x + 6y = 28

12x - 6y = -6

In the fourth system, we factor number 2 from the first line, and number 3 from the second line

4th system

2[5x + 3y] = 2[14]

3[4x - 2y] = 3[-2]

If we simplify,

4th system

[5x + 3y] = [14]

[4x - 2y] = [-2]

We get the same system as the 1st

Therefore, the solution is the same.

Answer: Its C

Step-by-step explanation: its equivalent

D, C, 432, 3112, and C :)

Answer:

y=-5x-2

Step-by-step explanation:

y=mx+b

where m is the slope

y=-5x+b

to solve for b, which is the y intercept, plug in (1,-7)

-7=-5(1)+b

-7=-5+b

-2=b

y=-5x-2

Answer:1

Step-by-step explanation:

Answer:

11.7 cm

Step-by-step explanation:

10^2 + 6^2 = c^2

100+36= 136

find the square root of 136 and you get 11.7 cm

Answer:

I just took my math test and used the answer already provided which came up as wrong, the correct answer is 1.250. Sorry I don't know how to get to the answer.

A ratio shows us the number of times a number contains another number. The size of unknown scale size will be 1.25.

A ratio shows us the number of times a number contains another number.

As it is given the size of the first row is 1.954, while the size of the second row is 1.563. therefore, the ratio of the first row to the second row will be,

[tex]\rm \dfrac{First\ row}{Second\ row} = \dfrac{1.954}{1.563}\\\\\\\rm \dfrac{First\ row}{Second\ row} =1.25[/tex]

Similarly, if the ratio of the second row and the third row is taken then the size of the third row can be written as,

[tex]\rm \dfrac{Second\ row}{Third\ row} =1.25\\\\\\\rm \dfrac{1.563}{Third\ row} =1.25\\\\\\Third\ row=1.2504 \approx 1.25[/tex]

Similarly, if the ratio of the third row and the fourth row is taken to verify the ratio, we will get,

[tex]\rm \dfrac{Third\ row}{Fourth\ row} = \dfrac{1.25}{1}\\\\\\\rm \dfrac{Third\ row}{Fourth\ row} = 1.25[/tex]

Thus, the size of unknown scale size will be 1.25.

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Answer:

5/6

Step-by-step explanation:

Only 5 is not divisible by 12

Answer:

I don't know if this is right but I hope it helped

Step-by-step explanation:

5-2+9-8

3+1

4

Answer:

4

Step-by-step explanation:

5-2+9-8

3+9-8

12-8

4

hope it helped :)

Answer:

797

Step-by-step explanation:

Answer:

C) Regular Octagon.

Step-by-step explanation:

First let's see what a tessellation is.

Tessellation is a floor made by regular types of tiles without overlapping and gap.

We cannot use all shape of tiles to tessellate a plane.

We are given Regular pentagon, irregular triangle and regular octagon.

The pentagon has 5 sides, all sides are in the same length. We cannot tessellate a plane using pentagon.

The second figure is a irregular triangle, we cannot make tessellate a plane using irregular shapes.

The third figure is a regular octagon. We can tessellate a plane using a regular octagon.

Therefore, answer is C) Regular Octagon.

Answer:

a)

[tex]4x {}^{2} - 9 = (2x + 3)(2x - 3)[/tex]

b) g - 3m = am + 5

am + 3m = 5 - g

m (a + 3) = 5 - g

m =

[tex] \frac{5 - g}{a + 3} [/tex]

Step-by-step explanation:

[tex]a {}^{2} - b {}^{2} = (a + b)(a - b)[/tex]

Answer:

see explanation

Step-by-step explanation:

(a)

4x² - 9 ← is a difference of squares which factors in general as

a² - b² = (a + b)(a - b)

4x² = (2x)² ⇒ a = 2x and 9 = 3² ⇒ b = 3, thus

4x² - 9 = (2x + 3)(2x - 3)

----------------------------------------------

(b)

g - 3m = am + 5 ( collect the terms in m together )

Add 3m to both sides

g = am + 3m + 5 ( subtract 5 from both sides )

g - 5 = am + 3m ← factor out m from each term

g - 5 = m(a + 3) ← divide both sides by (a + 3)

m = [tex]\frac{g-5}{a+3}[/tex]

12x^2y^2+2xy-2 with problems like these use the app “Photomath” it will help you a lot.

The answer is:

[tex](3xy-1)(4xy+2)=12(xy)^{2}+2xy-2[/tex]

or

[tex](3xy-1)(4xy+2)=12x^{2}y^{2}+2xy-2[/tex]

To solve the problem and identify the resultant expression, we need to apply the distributive property, and the, add or subtract like terms.

Describing the distributive property:

[tex](a+b)(c+d)=a*c+a*d+b*c+b*d[/tex]

Remember, like terms are the terms that share the same variable and same exponent, for example:

[tex]a^{2} +3a^{2}+a^{3}=4a^{2}+a^{3}[/tex]

We were able to add only the terms that have the same exponent (2).

We are given the expression:

[tex](3xy-1)(4xy+2)[/tex]

Now, solving we have:

[tex](3xy-1)(4xy+2)=(3xy*4xy)+(3xy*2)-(1*4xy)-2\\\\(3xy*4xy)+(3xy*2)-(1*4xy)-2=12(xy)^{2}+6xy-4xy-2\\\\12(xy)^{2}+6xy-4xy-2=12(xy)^{2}+2xy-2[/tex]

Hence, we have that:

[tex](3xy-1)(4xy+2)=12(xy)^{2}+2xy-2[/tex]

or

[tex](3xy-1)(4xy+2)=12x^{2}y^{2}+2xy-2[/tex]

Have a nice day!

Answer:

The answer is $63.6 for a coat

Step-by-step explanation:

80 (times) 0.75 = 60

60 (times) 1.06 = 63.6

25% = 0.75

adding 6% = 1.06

Answer:

The answer is $63.6 for a coat

Step-by-step explanation:

Answer:

The unit price for the 7.03 kg bag is about $1.78 per kg. The unit price for the 7.98 kg bag is about $1.83 per kg. The 7.03 kg is a better deal because you pay less per kg.

Step-by-step explanation:

1) To find the unit price, you need to find the price per unit. The unit here being kg. So, you need to divide the price by the number of units.

2) Here is this written out...

7.03 kg bag:

$12.53 / 7.03 kg = 1.78236130868 dollars per kg, or about $1.78 per kg

7.98 kg bag:

$14.64 / 7.98 kg = 1.83458646617 dollars per kg, or about $1.83 per kg

3) As you can see, if Joe purchases the 7.98 kg bag of dog food, he is paying more for every kg of dog food than if he were to purchase the 7.03 kg bag of dog food. This makes the 7.03 bag of dog food a better deal.

Hopefully this helps.

The unit price for the first bag of dog food is $1.78/kg, and the unit price for the second bag is $1.83/kg. Therefore, the first bag is cheaper and thus the better buy based on unit price.

To find the unit price of the dog food, we need to divide the total cost of the bag by its weight. For the first bag, we take the total cost of $12.53 divided by its weight of 7.03 kg. For the second bag, we take the total cost of $14.64 divided by its weight of 7.98 kg.

For example, using these calculations, the unit price for the first bag is $1.78/kg and the unit price for the second bag is $1.83/kg .

Therefore based on unit price, the first bag of dog food is the better buy as it is cheaper per kilogram.

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So a basic function is y=mx+b where m is a rate and b is the constant. His goal is 150 so y is 150 and the rate of his baking is 16 so m is 16, finally he has already 22 done so 22 remains constant. Plugging all these in you should get the following equation:

150=16x+22

Final answer:

Hou's goal is to bake at least 150 cookies, and he has already baked 22. If he bakes an average of 16 cookies every half hour, the equation representing the total cookies baked is Cookies baked = 16t + 22. The inequality to ensure he meets his goal is 16t + 22 >= 150.

Explanation:

Hou has set a goal to bake 150 cookies for a fundraiser and has already baked 22 cookies. He averages about 16 cookies every half hour. To represent this situation mathematically, we can use an equation related to the number of cookies baked over time.

Let's define the variable t to represent the number of half-hour segments Hou bakes. The total number of cookies Hou will have baked after t half-hour segments can be calculated by multiplying the number of segments by the average number of cookies baked in each half-hour segment and then adding the 22 cookies already baked.

The equation representing this situation is:

Cookies baked = 16t + 22

Hou's goal is to bake at least 150 cookies, so we create an inequality to represent the situation:

16t + 22 ≥ 150