The velocity acquired by a body moving with uniform acceleration is 12 m/s in 2 s and 18 m/s in 4 s. Find the initial velocity of the body.

A) The forward force is equal to the backward force

In this problem:

- the forward force is the force that Megan applies to the pedal to go forward

- the backward force is due to the air resistance and the friction between the wheels and the track

In this case, Megan is travelling at constant speed. This means that her acceleration is zero:

a = 0

According to Newton's second law, the resultant of the forces acting on Megan is equal to the product between mass (m) and acceleration (a):

[tex]\sum F = ma[/tex]

However, a = 0, so the resultant of the forces is also zero:

[tex]\sum F =0[/tex]

and this implies that the forward force and the backward force are equal in magnitude and opposite in direction.

B) The forward force is larger than the backward force

In this case, Megan crouched down in order to make herself more streamlined. As a result, the air resistance acting on Megan will decrease: so, the backward force will decrease, and therefore the forward force (which has remained the same) will be larger than the backward force.

So, the resultant force

[tex]\sum F[/tex]

will be no longer zero, and therefore the acceleration will be different from zero, which means that Megan will increase her speed.

If we approximate the orbit of the planets around the Sun to circular orbits with a uniform circular motion, where the velocity [tex]\vec{V}[/tex] is a vector, whose direction is perpendicular to the radius [tex]r[/tex] of the trajectory; the acceleration [tex]\vec{a}[/tex] is directed towards the center of the circumference (that's why it's called centripetal acceleration).  

Now, according to Newton's 2nd law, the force [tex]\vec{F}[/tex] is directly proportional and in the same direction as the acceleration:  

[tex]\vec{F}=m.\vec{a}[/tex]  

Therefore the net force resulting from the movement of a planet orbiting the Sun points towards the center of the circle, this is called Centripetal Force which is a central force that in this case is equal to the gravity force.

Answer:

Nothing

Explanation:

The radius of the orbit of the Earth does not depend on the radius of the sun.

In fact, the gravitational attraction between the Earth and the Sun provides the centripetal force that keeps the Earth in orbit:

[tex]G\frac{Mm}{r^2} = m\frac{v^2}{r}[/tex]

where

G is the gravitational constant

M is the mass of the sun

m is the mass of the Earth

r is the radius of the orbit of the Earth

v is the orbital speed of the earth

Re-arranging the equation for r:

[tex]r=\frac{GM}{v^2}[/tex]

Also,

[tex]v=\omega r[/tex]

where [tex]\omega[/tex] is the angular velocity of the Earth's orbit. So we can rewrite the equation as

[tex]r=\frac{GM}{\omega^2 r^2}\\r^3 = \frac{GM}{\omega^2}[/tex]

As we see, the radius of the orbit of the Earth, r, does not depend on the mass of the Sun, so if the sun shrank in size, the orbit remains the same.

Final answer:

The Earth's orbit would remain unchanged if the Sun's size decreased but its mass remained the same since gravitational force depends on mass, not size. The orbital period would also be unchanged if the Sun turned into a black hole with the same mass. However, if the Sun shrank to a certain point, it would become a black hole.

Explanation:

If the Sun shrank in size while its mass remained the same, the Earth's orbit would not change. This is because the gravitational force between two objects depends on their masses and the distance between them, not their sizes. According to Newton's law of universal gravitation, the force is directly proportional to the product of the masses and inversely proportional to the square of the distance between their centers. Therefore, as long as the mass of the Sun and the distance between the Earth and the Sun remains constant, the gravitational force and thus the orbit would remain unaffected.

If the Sun were to collapse into a black hole of the same mass, the Earth's orbital period would remain the same. That's because the Earth's orbit depends on the mass of the Sun, as described by Kepler's third law, which relates the period of an orbit to the distance from the focus (in this case, the Sun or black hole) and the mass of the object being orbited.

However, if the Sun collapsed beyond a particular point, general relativity tells us that the curvature of spacetime would get larger. If it shrank to a diameter of about 6 kilometers, it would become a black hole, and only light beams sent out perpendicular to the surface would escape. Even a slight further shrinkage would trap all light, rendering the Sun a black hole.

it is the vertical distance between the waterline and the bottom of hull and determines the minimum depth of water

Applying Kepler's third law and considering the decrease in Planet X's mass, the orbital period of the satellite in the same radius orbit would double, from T to 2T.

The question involves the satellite's orbital period in the context of Kepler's third law, which states that the square of a planet's orbital period is directly proportional to the cube of the semi-major axis of its orbit. In the special case of a circular orbit, the semi-major axis is equal to the orbit's radius R. To find the impact of the reduced mass of Planet X, we need to understand the mass influences on the satellite's orbital period.

When the mass of the planet decreases by a factor of 4, the orbital velocity also decreases by the same factor as vorbit is proportional to the square root of Planet X’s mass. Consequently, with a quarter of the orbital velocity, the period must be twice as long. Hence, if the original period was T, the new period would be 2T. So, the correct choice is: A) 2T.

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Answer:

Force increases nine times its initial value

Explanation:

For charges, charged bodies very small compared to the distance [tex]r[/tex] that separates them, Coulomb discovered that the electric force is proportional to [tex]\frac{1}{r^{2}}[/tex]

So, if the distance is made a third of what it was, the force will be increased nine times its initial value

density..................your welcomr

The complete statement is "The best method for separating an oil and water mixture would be density". This is further explained below.

Generally, Separation techniques are simply defined as methods for separating two distinct matter states.

In conclusion, The best method for separating an oil and water mixture would be through their density

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Answer:

B. 4 m/s

Explanation:

v=d/t

Running for 300 m at 3 m/s takes 100 seconds and running at 300 m at 6 m/s takes 50 seconds. 100 s + 50 s = 150 s (total time). Total distance is 600 m, so 600 m/ 150 s = 4 m/s.

The average speed of the runner for the entire journey is 4 m/s.

The given parameters;

The average speed of the runner is obtained by diving the total distance covered by the runner by the total time of motion as shown below;

[tex]average \ speed = \frac{total \ distance }{total \ time \ of \ motion} \\\\[/tex]

The time of motion during the first distance covered;

[tex]t_1 = \frac{300}{3} = 100 \ s[/tex]

The time of motion during the second distance covered;

[tex]t_2 = \frac{300}{6} = 50 \ s[/tex]

The average speed is calculated as;

[tex]average \ speed = \frac{600}{100 + 50} \\\\average \ speed = 4 \ m/s[/tex]

Thus, the average speed of the runner for the entire journey is 4 m/s.

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Answer:

B

Explanation:

Energy at the top of the hill = energy at the bottom of the hill + energy lost

PE = KE + E

mgh = 1/2 mv² + E

(52 kg) (9.8 m/s²) (50.0 m) = 1/2 (52 kg) (25 m/s)² + E

25480 J = 16250 J + E

E = 9230 J

Density [tex]D[/tex]  is a characteristic property of a substance, material or object and is defined as the relationship between the mass and volume of that specific substance or material.

This is due the fact that any object or material has mass and volume, however the mass of different substances occupy different volumes.  As shown in the following equation:

[tex]D=\frac{m}{V}[/tex]

Where:

[tex]m[/tex] is the mass of the object

[tex]V[/tex] is the volume of the object

This is why changing the shape of an object not affect its density.

Final answer:

The density of an object, being mass per unit volume, does not change when its shape is altered because both the object's mass and volume remain consistent, keeping density constant. This property is intrinsic to the material, and unrelated to shape or thermal conductivity. Only changes in temperature can affect the density by affecting the volume while keeping the mass constant.

Explanation:

Changing the shape of an object does not affect its density because density is defined as the mass per unit volume. This property, how much mass there is in one unit of volume, is an intrinsic characteristic of a material and does not depend on the object's shape. When you change the shape of an object, you do not change its mass or the amount of space it occupies, hence the density remains constant.

Even when an object undergoes a shape transformation, like clay being molded from a lump into a boat, its mass and volume stay the same which keeps the density unchanged. However, this transformation can affect the object's ability to float or sink due to the principle of displacement as stated in Archimedes' Principle. A lump of clay sinks because it displaces less water, whereas the same lump shaped like a boat displaces more water and can float.

It's also important to understand that while volumes and densities can change with temperature changes, the mass remains constant with temperature. According to the US Department of the Interior, the true density of water depends on its temperature, emphasizing the influence of temperature on density rather than shape.

Answer:

D) Decreases by 4

Explanation:

The mass number of a nucleus is equal to the number of protons and neutrons in the nucleus:

A = p + n

where

p is the number of protons

n is the number of neutrons

An alpha particle is a nucleus of helium, consisting of 2 protons and 2 neutrons. This means that when an unstable nucleus emits an alpha particle, it loses 2 protons and 2 neutrons. Therefore, the new mass number of the nucleus will be

A' = (p-2) + (n-2) = p + n - 4 = A - 4

So, it will decrease by 4 units.

Answer : The correct option is, (C) 45 degrees Celsius.

Explanation :

Endothermic reaction : It is defined as the chemical reaction in which the energy is absorbed from the surrounding.

In the endothermic reaction, the energy of reactant are less than the energy of product.  During endothermic reaction, initially the temperature of the reaction is high because initially amount of heat is given to the system and after the reaction, the temperature of the reaction is low.

Exothermic reaction : It is defined as the chemical reaction in which the energy is released into the surrounding.

In the exothermic reaction, the energy of reactant are more than the energy of product. During exothermic reaction, initially the temperature of the reaction is low because initially there is no heat is given to the system and after the reaction, the temperature of the reaction is high because after ther reaction, more amount of energy is released.

As per question, a student performs an exothermic reaction in a beaker and measures the temperature. Initially, the thermometer reads 35 degrees Celsius. After the reaction, the thermometer temperature will be more that initial temperature that is, 45 degrees Celsius.

Hence, correct option is, (C) 45 degrees Celsius.

Answer:

4

Explanation:

In order for the current to continue flowing through the circuit (and for the bulbs to continue shining), there must be a closed path containing the battery where current can flow. Let's see the effect of removing each bulb on the circuit:

- 1: when removing bulb 1 only, the current can still flow through the path battery-bulb 3- bulb 4

- 2: when removing bulb 2 only, the current can still flow through the path battery-bulb 3- bulb 4

- 3: when removing bulb 3 only, the current can still flow through the path battery-bulb 1-bulb 2- bulb 4

- 4: when removing bulb 4 only, the current can no longer flow. In fact, there is no closed path that contains the battery now, so the current will not flow and all the bulbs will stop shining.

Answer:

4

Explanation:

It is a parrallel circuit

Explanation:

In an isobaric process the pressure remains constant, which means the initial pressure and the final pressure will be the same.

In addition, during this thermodynamic process, the volume of the ideal gas expands or contracts in such a way that the variation of pressure [tex]\Delta P[/tex] is neutralized.

Now, according to the First law of Thermodynamics that establishes the conservation of energy:

[tex]\Delta U=\Delta Q-\Delta W[/tex]   (1)

Where:

[tex]\Delta U[/tex] is the internal energy

[tex]\Delta Q[/tex] is the heat transferred

[tex]\Delta W[/tex] is the work

Now, for an isobaric process:

[tex]\Delta W=P\Delta V[/tex]    (2)

Where:

[tex]P[/tex] is the pressure (always positive)

[tex]\Delta V[/tex] is the volume variation of the gas

Here we have two possible results:

-If the gas expands (positive [tex]\Delta V[/tex]), the work is positive.

-If the gas compresses (negative [tex]\Delta V[/tex]), the work is negative.

In this case we are talking about the first result (work is positive).

Then, according to the above, equation (1) can be written as follows:

[tex]\Delta U=\Delta Q - P\Delta V[/tex]   (3)

Clearing [tex]\Delta Q[/tex]:

[tex]\Delta Q=\Delta U+P \Delta V[/tex]    (4)

Then, for an ideal gas in an isobaric process, part of the heat ([tex]Q[/tex]) added to the system will be used to do work (positive in this case) and the other part will increase the internal energy, hence the temperature will increase as well.

Final answer:

In an isobaric expansion of an ideal gas, the gas does work and if heat is added, the temperature may increase, making options A, B, C, and E incorrect. The pressure remains constant by definition.

Explanation:

When a fixed amount of ideal gas goes through an isobaric expansion, it is essential to understand that the pressure remains constant by definition. In option A, if the process was isothermal, the internal energy would indeed not change since internal energy for an ideal gas is a function of temperature, but this isn't necessarily true for an isobaric process where temperature can change. Hence, option A is incorrect. Option B states the gas does no work, which is also incorrect; during an isobaric expansion, the gas does work as it expands against a constant external pressure. Option C would describe an adiabatic process, not an isobaric one, so this is incorrect in this context. Option D suggests that the temperature must increase, which could be true because when an ideal gas expands isobarically, heat is often added to keep the pressure constant, thereby increasing the temperature. Finally, option E states that the pressure must increase, which cannot happen in an isobaric process by definition.

Considering the context and mechanisms of thermodynamics, the correct answer is not explicitly stated among the choices but can be inferred. The most accurate answer regarding an isobaric expansion of an ideal gas would be that the gas does work and if heat is added to maintain constant pressure, the temperature is likely to increase.

Answer:

a few hundred thousand years after the Big Bang

Explanation:

Answer:

A. paths of the planets follow an elliptical orbit around the sun.

Explanation:

Nicolás Copernicus formulated the heliocentric theory of the solar system, where the Sun is the one in the center with the planets moving around it, contradicting what was believed for the time that it was that the Earth was in the center and both the Sun and the planets revolved around him (geocentrism).

This was the basis for Kepler finally describing the planetary movement based on 3 mathematical expressions. These expressions start by saying that the orbits were not circular, if not elliptical, so that the planets are governed by the Pythagorean laws of harmony. His studies showed that the distances of the planets to the Sun drew parallel spheres, being the first to draw the concentric orbits of the planets in their orbits around the Sun.

Kepler's laws are the following:

  - First law. The planets move in elliptical orbits, the sun being one of the foci.

  - Second law. The radius vector that joins the center of the Sun with the center of a planet describes equal areas in equal times.

  - Third law. The squares of the periods of the planets are proportional to the cubes of their distance from the Sun.

1) [tex]6.11\cdot 10^{10} m/s^2[/tex]

The force experienced by the proton is

[tex]F=qE[/tex]

where

[tex]q=1.6\cdot 10^{-19}C[/tex] is the proton charge

[tex]E=635 N/C[/tex] is the strength of the electric field

Substituting into the equation,

[tex]F=(1.6\cdot 10^{-19} C)(635 N/C)=1.02\cdot 10^{-16}N[/tex]

The acceleration of the proton is given by Newton's second law:

[tex]a=\frac{F}{m}[/tex]

where

[tex]F=1.02\cdot 10^{-16}N[/tex] is the force exerted on the proton

[tex]m=1.67\cdot 10^{-27} kg[/tex] is the proton's mass

Substituting,

[tex]a=\frac{1.02\cdot 10^{-16}N}{1.67\cdot 10^{-27}kg}=6.11\cdot 10^{10} m/s^2[/tex]

2)  [tex]2.13\cdot 10^{-5} s[/tex]

We can use the following equation:

[tex]a=\frac{v-u}{t}[/tex]

where

[tex]a=6.11\cdot 10^{10} m/s^2[/tex] is the acceleration of the proton

[tex]v=1.30\cdot 10^6 m/s[/tex] is the final velocity

u = 0 is the initial velocity

t is the time

Solving the equation for t, we find

[tex]t=\frac{v-u}{a}=\frac{1.30\cdot 10^6 m/s -0}{6.11\cdot 10^{10} m/s^2}=2.13\cdot 10^{-5} s[/tex]

3) 13.86 m

The distance travelled by the proton is given by the equation

[tex]d=ut + \frac{1}{2}at^2[/tex]

where

u = 0 is the initial velocity

[tex]t=2.13\cdot 10^{-5} s[/tex] s the time

[tex]a=6.11\cdot 10^{10} m/s^2[/tex] is the acceleration of the proton

Substituting,

[tex]d=0 + \frac{1}{2}(6.11\cdot 10^{10}m/s^2)(2.13\cdot 10^{-5} s)^2=13.86 m[/tex]

4) [tex]1.41\cdot 10^{-15} J[/tex]

The final kinetic energy of the proton is given by

[tex]K=\frac{1}{2}mv^2[/tex]

where we have

[tex]m=1.67\cdot 10^{-27} kg[/tex] is the proton's mass

[tex]v=1.30\cdot 10^6 m/s[/tex] is the final velocity

Substituting into the formula,

[tex]K=\frac{1}{2}(1.67\cdot 10^{-27}kg)(1.30\cdot 10^6 m/s)^2=1.41\cdot 10^{-15} J[/tex]

The magnitude of the proton's acceleration can be found using Newton's second law. The time it takes for the proton to reach a given speed can be calculated using the equation for linear motion. The distance the proton moves can be determined using the equation for distance traveled. The kinetic energy of the proton can be calculated using the equation for kinetic energy.

To find the magnitude of the acceleration of the proton, we can use the equation F = ma, where F is the force exerted on the proton and m is its mass. In this case, the force is given by F = qE, where q is the charge of the proton and E is the electric field. Since the charge of the proton is known, we can calculate the force and then use Newton's second law to find the acceleration.

Once we have the acceleration, we can use the equation v = u + at to find the time it takes for the proton to reach the given speed, where v is the final velocity, u is the initial velocity (0 in this case), a is the acceleration, and t is the time.

To find the distance the proton has moved, we can use the equation s = ut + (1/2)at², where s is the distance, u is the initial velocity, t is the time, and a is the acceleration.

To calculate the kinetic energy of the proton, we can use the equation KE = (1/2)mv², where KE is the kinetic energy, m is the mass of the proton, and v is its velocity.

Final answer:

In comparing isobaric, isothermal, and adiabatic processes for an expanding ideal gas, the isobaric process involves the greatest work done by the gas and the largest heat flow into the system, while the adiabatic process leads to a decrease in internal energy, indicating no heat flow into the gas.

Explanation:

An ideal gas expands through three different processes: isobaric, isothermal, and adiabatic, with its volume increasing to four times the original. Here's how each process impacts the work done, internal energy, and heat flow into the gas:

Isobaric (constant pressure): This process results in a significant work done by the gas and sees a large amount of heat flow into the gas due to the direct relationship between heat added and work done at constant pressure.

Isothermal (constant temperature): In this process, the internal energy of the gas does not change since any heat added to the system is entirely converted into work. Therefore, this process neither increases nor decreases the internal energy but can involve significant work done if heat is supplied.

Adiabatic (no heat exchange): This process results in a decrease in internal energy since the work done by the gas comes from its internal energy reservoir. No external heat is added to the system.

Answers to specific questions:

The work done by the gas is greatest during the isobaric process due to the direct relationship between pressure, volume, and work in this scenario.

The smallest amount of work done is a bit nuanced since all processes involve work, but the adiabatic process might be seen as involving 'less effective' work since it leads to a reduction in internal energy without heat intake.

The internal energy increases during isobaric expansion due to the heat flow into the gas.

The internal energy decreases during the adiabatic process as the gas does work on its surroundings at the expense of its internal energy.

The largest amount of heat flows into the gas during the isobaric process because work done on the gas directly translates to heat intake at constant pressure.

Answer:

A

Explanation:

Nasty, but doable.

I = 2 amps

R = 8 ohms

V = I * R

V = 2 * 8

V = 16 volts.

========

The 4 ohm resistor sees the same voltage -- 16 volts.

V = 16

R = 4ohms

I = V/R

I = 16/4

I = 4 amps.

The current seen by the unknown resistor R is

It = 4 amps + 2 amps

It = 6 amps

Answer A.

Initial current = 0

Final current = (15 V) / (60 ohms) = 0.25 Ampere

Current along the way = 0.25 · (1 - e^- time / time-constant)

"time-constant" = L/R = (0.045 / 60) =  7.5 x 10⁻⁴ second

Current = 0.25 · (1 - e^-10,000t/7.5)

When t = 7 ms,

Current = 0.25 · ( 1 - e^-70/7.5)

Current = 0.25 · (1 - e^-9.33)

Current = 0.25 · (1 - 8.84 x 10⁻⁵)

Current = 0.25 · (0.9999)

Current = so close to 250 mA that you can't tell the difference.

The reason is that 7.0 mS is 9.3 time-constants, and during EVERY time-constant, the current grows by 37% of the distance it still has left to go. So after 9.3 of these, it's practically AT the target.

I have a feeling that the time in the question is SUPPOSED TO BE 7 microseconds.  If that's true, then

Current = 0.25 · (1 - e^-[ 7 x 10⁻⁶ / 7.5 x 10⁻⁴ ]

Current = 0.25 · (1 - e^-0.00933)

Current = 0.25 · (1 - 0.9907)

Current = 0.25 · (0.0093)

Current = 2.32 mA  ?

No, that can't be it either.

Well !  Now, I'm going to determine the true and correct final answer in the only cheap and sleazy way I have left ... by looking at all the choices offered, and eliminating the absurd ones.

The effect of an inductor in the circuit is to resist any change in current.  The final current in this circuit is when it's not trying to change any more.  So the final current is just the battery with a resistor across it ... (12 V) / (60 ohms).  That's 0.25 Ampere, or 250 mA.  The current starts at zero when the switch closes, and it builds up and builds up to 250 mA.  It's never more than 250 mA.  

So look at the choices !  The only one that not more than 250 mA is choice-A .

THAT has to be it.  7.0 mS is a no-brainer.  It's 9.3 time-constants after the switch closes, the current has built up to 99.99% of its final value by then, it's not really trying to change much any more, the inductor is just about finished having any effect on the current, and the current is essentially at its final value of 250 mA.  The action is all over.

Now, I fully realize that Mister "Rishwait" is a bot and all, and nobody really needs the answer to this question.  But every cloud has a silver lining.  It's a numskull question, but it earned me 10 points, and it's been a truly fascinating trip down Memory Lane.

the current approximately 7.0 ms after closing the switch is about 250 mA, which is option (a).

To find the current through the circuit 7.0 ms after the switch is closed, we can use the concept of an RL circuit. The current in an RL circuit follows an exponential growth equation, given by:

I(t) = (V/R)(1 - e^(-t/τ))

Where:

I(t) is the current at time t.

V is the voltage from the power supply (15 V in this case).

R is the resistance (60 Ω).

τ (tau) is the time constant of the circuit, given by L/R, where L is the inductance (45 mH = 0.045 H).

First, calculate the time constant τ:

τ = L/R = 0.045 H / 60 Ω = 0.00075 s.

Now, plug in the values into the equation to find I(7.0 ms):

t = 7.0 ms = 0.007 s.

I(0.007 s) = (15 V / 60 Ω) * (1 - e^(-0.007 s / 0.00075 s))

I(0.007 s) = (0.25 A) * (1 - e^(-9.333...))

Now, calculate the current:

I(0.007 s) ≈ (0.25 A) * (1 - e^(-9.333...))

I(0.007 s) ≈ (0.25 A) * (1 - 0.0000962) [Using e^(-9.333...) ≈ 0.0000962]

I(0.007 s) ≈ (0.25 A) * (0.9999038)

I(0.007 s) ≈ 0.24998 A

I(0.007 s) ≈ 250 mA

So, the current approximately 7.0 ms after closing the switch is about 250 mA, which is option (a).

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Answer:

15.1°

Explanation:

The horizontal velocity of the hockey puck is constant during the motion, since there are no forces acting along this direction:

[tex]v_x = 23.2 m/s[/tex]

Instead, the vertical velocity changes, due to the presence of the acceleration due to gravity:

[tex]v_y(t)= v_{y0} -gt[/tex] (1)

where

[tex]v_{y0}=0[/tex] is the initial vertical velocity

g = 9.8 m/s^2 is the gravitational acceleration

t is the time

Since the hockey puck falls from a height of h=2.00 m, the time it needs to reach the ground is given by

[tex]h=\frac{1}{2}gt^2\\t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(2.00 m)}{9.8 m/s^2}}=0.64 s[/tex]

Substituting t into (1) we find the final vertical velocity

[tex]v_y = -(9.8 m/s^2)(0.64 s)=-6.3 m/s[/tex]

where the negative sign means that the velocity is downward.

Now that we have both components of the velocity, we can calculate the angle with respect to the horizontal:

[tex]tan \theta = \frac{|v_y|}{v_x}=\frac{6.3 m/s}{23.2 m/s}=0.272\\\theta = tan^{-1} (0.272)=15.1^{\circ}[/tex]

Final answer:

Using the kinematic equations for projectile motion, the final angle below the horizontal of the velocity of the puck just before it hits the ground is calculated to be 31.8° based on the given height of the fall and the initial horizontal velocity.

Explanation:

To find the angle below the horizontal of the velocity of the puck just before it hits the ground, we can use the kinematic equations for projectile motion. Considering that the puck experiences no air resistance, its horizontal velocity component remains constant at 23.2 m/s, and the vertical velocity component increases due to gravity (9.81 m/s2). First, we calculate the time it takes for the puck to fall 2.00 m using the vertical motion equation:

h = v0yt + (1/2)gt2

Since the puck slides off the table, the initial vertical velocity v0y is 0, so the equation simplifies to:

h = (1/2)gt2

Solving for t, we get:

t = sqrt((2h)/g)

Now that we have the time of fall, we can find the vertical velocity component just before impact using:

vy = gt

Finally, the angle θ can be calculated using the vertical and horizontal components:

tan(θ) = vy/vx

Plugging in the values:

θ = arctan(vy/vx)

After performing the calculations with the given numbers, we find that the angle is 31.8° below the horizontal just before the puck hits the ground. Therefore, the correct answer is 31.8°.

A.Ganerators

is the answer

Agree with previous answer.

A. Generators

Hi

The total displacement is 2 m south

I hope this helps

Answer:

2 m south

Explanation:

Displacement is measure of change in the position of an object. It is a vector quantity, that is, it has both magnitude and direction.

When the child walked 4 m south, its displacement is 4 m south.

Then it moved 2 m back opposing direction to the north. The resultant displacement is 4 - 2 = 2 m south.

Then it moved 5 m south, same direction, displacement becomes 2 + 5 = 7 m south.

And finally, it moved 5 m north, opposing direction. 7 - 5 = 2 m south.

The final displacement of the child is 2 m south.

I'm not positive but if I'm reading the question right it would be the big bang sorry if I'm wrong

Physical sciences study nonliving matter, including fields like geology, astronomy, physics, and chemistry, with a focus on matter and energy interactions.

The term physical sciences pertains to the study of matter and energy. The field of physical science includes subjects like geology, astronomy, physics, and chemistry, which all explore various aspects of nonliving matter. Physics, being the most fundamental of these sciences, deals with concepts of energy, matter, space and time, and their interactions. It is essential for understanding the general truths of nature that are expressed through scientific laws and theories, which describe the rules that all natural processes appear to follow.

Answer:

The atomic number increases by 1.

Explanation:

The beta minus decay is a process in which a neutron decays into a proton, emitting an electron and an anti-neutrino:

[tex]n \rightarrow p + e + \bar{\nu}[/tex]

If this process occurs inside an unstable nucleus, we notice that:

- a neutron is converted into a proton, therefore

- the number of neutrons decreases by 1 and the number of protons increases by 1

Keep in mind that the atomic number of a nucleus corresponds to the number of protons it contains: therefore, since this number increases by 1, then the atomic number increases by 1.

Answer:

A metal sphere is neutral because it has an equal number of protons and electrons. Draw how the charges in the sphere are redistributed when a negatively charged rod is brought near it.

Answer:

two opposite charges: The force between them would be attractive. In the electric field the lines pointing outward from the positively charged particle would go toward the negatively charged particle  

two like charges: The force would repulse each other. In the electric field the lines would avoid each other.  

Explanation:

in the answer hope this helps!

Answer:

120.0v drop across the 20.0 resistor

Explanation:

Answer: i believe it is conserved or stays the same.

Explanation: energy cant be destroyed no matter what and no energy is being created

I hope this helps a thank and a brainlist would be greatly appreciated

Answer: Nor

Explanation: In any energy transformation, energy is nor created destroyed or conserved

Answer:

4.5 V

Explanation:

The electric potential produced around a single point charge is:

[tex]V=k \frac{q}{r}[/tex]

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

We see that the electric potential is inversely proportional to the distance, r, so we can write:

[tex]V_1 r_1 = V_2 r_2[/tex]

where

V1 = 9 V

r1 = 1 m

V2 = ?

r2 = 2 m

Solving the equation, we find the voltage 2 m away from the charge:

[tex]V_2 = \frac{V_1 r_1}{r_2}=\frac{(9 V)(1 m)}{2 m}=4.5 V[/tex]

Final answer:

The voltage 2 m away from the charged object is 36 V.

Explanation:

The electric potential (voltage) at a distance of 1 m from the charged object is 9 V. To find the voltage at a distance of 2 m, we can use the inverse square law for electric potential:

V = kQ/r

Where V is the voltage, k is the electrostatic constant, Q is the charge, and r is the distance. Since the charge is unknown, we can use the ratio of the squares of the distances to find the voltage:

V₂/V₁ = (r₁/r₂)²

Substituting the given values, we have:

9/V₁ = (1/2)²

V₁ = 36 V

Therefore, the voltage 2 m away from the charge is 36 V.