Where is the answer to the expression 4 − 8 located on a horizontal number line? 4 units to the left of 4
4 units to the right of 4
8 units to the left of 4
8 units to the right of 4
I need the answer asap whoever answers first and gets it right gets brainliest
The temperature at 9 a.m. is 2 degrees. The temperature rises 3 more degrees by noon. Which expression describes the temperature at noon?
2 + 3
2 + (–3)
–2 + (–3)
–2 + 3
it starts at 2 degrees which is not a negative number and temperature rises so it isn't a negative number either
so it would be 2+3
An expression is defined as a set of numbers, variables, and mathematical operations. The correct option is A, 2+3.
What is an Expression?In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.
Given that the temperature at 9 a.m. is 2 degrees. Further, the temperature rises 3 more degrees by noon.
As two whole numbers are added together, the total quantity or sum of those values is obtained. Therefore, the expression that describes the temperature at noon is 2 + 3.
This is because the temperature is positive and after the temperature rises, the temperature will be added.
Hence, the expression that describes the temperature at noon is 2 + 3.
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A sphere has a radius of 3 and a hemisphere has a radius of 6. Compare the ratio of the volume of the sphere to the volume of the hemisphere.
Jennifer can clean her room in 2 hours, while John can clean the same room in 5 hours. How many hours would it take for them to clean the room together?
7
10
seven tenths
ten sevenths
I think the answer is tenth sevenths but im not sure! Please Help ASAP
Answer: ten sevenths
Step-by-step explanation:
Given: Time taken by Jennifer to clean her room [tex]t_1= 2 \text[ hours}[/tex]
Time taken by John to clean same room [tex]t_2= 5\text[ hours}[/tex]
If they work together to clean the room , then the total time taken by them is given by :-
[tex]\dfrac{1}{t}=\dfrac{1}{t_1}+\dfrac{1}{t_2}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{1}{2}+\dfrac{1}{5}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{5+2}{10}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{7}{10}\\\\\Rightarrow\ t=\dfrac{10}{7}\text{ hours}[/tex]
In a casino, the chance of winning a certain game is 14.5%. If you play the game 20 times, what’s your best estimate for the number of times you would win? Round off your answer to the nearest whole number.
Evaluate the expression : (0.4)^3=
The expression when evaluated, can be found to be 0. 064.
How to evaluate the expression ?( 0 . 4 ) ³ means raising the number 0. 4 to the power of 3 , which is the same as multiplying 0. 4 by itself three times. This is how the expression is evaluated.
Start with:
0 . 4 * 0 . 4 * 0 . 4
Calculate each multiplication step:
1st multiplication: 0 . 4 * 0 . 4 = 0 . 16
2nd multiplication: 0 . 16 * 0 . 4 = 0 . 064
So, when you multiply 0. 4 by itself three times ( 0 . 4 * 0 . 4 * 0 . 4), you get the result of 0 . 064.
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Suppose you roll two standard number cubes once. Find the probability. P(7 or even)
To roll a seven you could have (1,6) (6,1) (2,5) (5,2) (3,4) (4,3)
6 different ways so 6/36 reduces to 1/6 way of getting a 7
For getting an even number as sum, we can have (1,1) or (1.3) or (1,5) or (2,2) or (2,4) or (2,6) or (3,1) or (3,3) or (3,5) or (4,2) or (4,4) or (4,6) or (5,1) or (5,3) or (5,5) or (6,2) or (6,4) or (6,6) 18 ways, probability is 18/36 reduces to ½
So for either one you now have 1/6 + 1/2 = 6+2/12 = 8/12 reduced to 2/3
Of the 240 shirts on a rack, 40 percent are size medium. How many shirts on the rack are size medium?
First, let’s check for the given:
Shirts on the rack = 240
Medium size shirts = 40% of 240
With the following given, we can now solve for the total
number of shirts on the rack that are size medium.
So, in order to solve for the problem, we multiply 40% to 240:
The decimal equivalent of 40% is 0.4.
240 shirts * .4 = 96 shirts
Therefore, out of 240 shirts on the rack, there are 96 shirts on the rack that are size medium.
To add, the number or ratio that represents a fraction of 100 is called a percentage.
Ralph sold brownies for $0.27 a piece in order to earn money to buy baseball cards. If the cards cost $0.54 per pack, and if Ralph had no money left over after buying them, what is the least number of brownies he must have sold?
Answer this please image below
A baseball was pitched at a speed of 75.2 miles per hour. a tennis ball was served at a speed 1.5 times faster than this. how much faster was the speed of the tennis ball than the speed of the baseball?
Answer:
75.2*1.5=112.8
112.8+75.2=188
188-75.2=112.8
Find the area of the composite figure.Use 3.14 for pi.
area for the triangle section is 1/2 x b x h: 1/2 x 16 x 10 = 80 square m
area for half circle = 1/2 x 3.14 x 8^2 = 100.48 square m
100.48 + 80 = 180.48 square meters
A bicycle wheel makes 5 revolutions. Determine how far the bicycle travels in feet. The diameter of the wheel is 32in.
25/150 in simplest form
If f(x)=6x and g(x) = 4x+1, find ( f o g)(x)
Daisy works at an ice-cream parlor. She is paid $10 per hour for the first 8 hours. She works for x hours in a day and x is greater than 8, the expression giving her net earnings for the day is
A. x(80+1.5)
B. (x-8)1.5
C. 80+15 (x-8)
D. (8)(15)(x-8)
the answer is option C
If matrix A has dimensions 3 x 2 and matrix B has dimensions 3 x 2, can matrix A and matrix B be multiplied?
Answer:
we can not multiply matrix A and B.
Step-by-step explanation:
We have been given that
dimension of matrix A = 3 x 2
dimension of matrix B = 3 x 2
Rule of multiplying two matrices:
Two matrix can be multiplied if the column of first matrix is equal to the row of second matrix.
column of first matrix = row of second matrix
Here, we have
Column of first matrix A = 2
Row of second matrix b = 3
Since,, column of matrix A ≠ Row of matrix B
Hence, we can not multiply matrix A and B.
Five scouts took a white water rafting trip. The total cost of the trip was $721. Each person in the group received a student discount of $6. Write and solve an equation to find out how much each student paid before discount.
cost per student before discount = 721/5+6
721/5 = 144.20 +6 = 150.20
-cz+6z=tz+83 solve for z
Answer:
The value of the equation for z is [tex]z=\frac{83}{6-c-t}[/tex].
Step-by-step explanation:
Consider the provided equation.
[tex]-cz+6z=tz+83[/tex]
Subtract tz from both the sides.
[tex]-cz+6z-tz=tz-tz+83[/tex]
[tex]-cz+6z-tz=83[/tex]
Take z common.
[tex]z(-c+6-t)=83[/tex]
[tex]z(6-c-t)=83[/tex]
Divide 6-c-t from both the sides.
[tex]\frac{z(6-c-t)}{6-c-t}=\frac{83}{6-c-t}[/tex]
[tex]z=\frac{83}{6-c-t}[/tex]
Thus, the value of the equation for z is [tex]z=\frac{83}{6-c-t}[/tex].
Determine the range of: f(x) = 13 - 20x - x^2 -3x^4. Also, find the max. And min. Values and state where those values occur
Use the law of cosines to find the missing third side
The missing third side BC is approximately 16.93 units. To use the Law of Cosines to find the missing third side (BC), we'll use the formula:
[tex]c^2 = a^2 + b^2 - 2ab * cos(C)[/tex]
where:
c is the side opposite angle C (BC in this case)
a and b are the known sides (AC and AB, respectively)
C is the angle opposite side c (angle BAC in this case)
Given values:
Angle BAC (C) = 54 degrees
AC (a) = 7.4
AB (b) = 15.8
Now, we can plug the values into the formula and solve for BC (c):
[tex]BC^2 = 7.4^2 + 15.8^2 - 2 * 7.4 * 15.8 * cos(54)[/tex]
To find cos(54), we can use a calculator:
[tex]cos(54 degrees) \approx 0.5878[/tex]
Now, we can continue the calculation:
[tex]BC^2 = 54.76 + 249.64 - 2 * 7.4 * 15.8 * 0.5878\\BC^2 = 54.76 + 249.64 - 17.44\\BC^2 = 286.96[/tex]
Now, find the square root of both sides to get the value of BC:
[tex]BC = \sqrt{286.96} \\BC \approx 16.93[/tex]
So, the missing third side BC is approximately 16.93 units.
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Daniel and Sofia both solve this system of equations: y = -1.5x + 5.7 y = 0.5x + 0.3 Daniel's solution is (1.1, 2.4). Sofia's solution is (2.7, 1.65). They graph the equations to check their work. Based on the graph, whose solution is more likely to be correct?Daniel is more likely to be correct. The x-coordinate of the intersection is between 1 and 2 and the y-coordinate of the intersection is between 2 and 3. Sofia is more likely to be correct. The x-coordinate of the intersection is between 2 and 3 and the y-coordinate of the intersection is between 1 and 2. or niether
Answer:
Sofia is more likely to be correct
=)
Step-by-step explanation:
find the area of the circle with diameter of 11mm leaving answer in terms of pi
need help, thank you!
2x+3y=5x−y
y=0
x=?
Answer:
X=4\3
Step-by-step explanation:
Stuart is buying a pair of jeans that regularly cost $40. They are on sale for 20% off. If the tax rate is 8%,what is the sale price of the jeans including tax?
if a polynomial has one root in the form a+√b , it has a second root in the form of a_√b
Answer:
a - √b
Step-by-step explanation:
If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.x = (1/2) [ 2a +/- √(4a² - 4(a² - b)] = a +/- (1/2)*√(4b) = a +/- √bx = a + √b, or x = a - √b, as expected.
help someone plz
A student needs to make a rectangular cardboard piece that is 12 inches long. The area of the cardboard piece should be between 60 square inches to 300 square inches. The function f(w) relates the area of the cardboard, in square inches, to the width w in inches. Which of the following shows a reasonable domain for f(w)?
A: 2 ≤ w ≤ 5
B: 5 ≤ w ≤ 25
C: 25 ≤ w ≤ 60
D: 60 ≤ w ≤ 300
area = L x w
60 = 12 x w
w=60/12 = 5
300 = 12 x w
w = 300/12 = 25
so B is the correct answer
Answer:
Option B
[tex]5 \leq w \leq 25[/tex]
Step-by-step explanation:
Let
L------> the long of the cardboard piece
W-----> the width of the cardboard piece
The area of cardboard piece is equal to
[tex]A=L*W[/tex]
In this problem we have
[tex]L=12\ in[/tex]
so
[tex]A=12W[/tex]
[tex]f(W)=12W[/tex]------> equation A
[tex]f(W)\geq 60\ in^{2}[/tex] ------> inequality B
[tex]f(W)\leq 300\ in^{2}[/tex] ------> inequality C
Substitute equation A in the inequality B
[tex]12W\geq 60\ in^{2}[/tex]
[tex]W\geq 60/12[/tex]
[tex]W\geq 5\ in[/tex]
Substitute equation A in the inequality C
[tex]12W\leq 300\ in^{2}[/tex]
[tex]1W\leq 300/12[/tex]
[tex]1W\leq 25\ in[/tex]
The domain for the function f(W) is equal to the interval------> [tex][5,25][/tex]
PLease Answer!
The Mali Empire of West Africa was known far and wide for the great wealth of its rulers. The empire fell in the year 1610.
Let x represent any year. Write an inequality in terms of x and 1610 that is true only for values of x that represent years after the year the Mali Empire fell.
the answer is x>1610
how do you reduce the fraction of 28/49
Please help :) :) :)
A motorboat
travels 222 km in 6 hours going upstream.
Rate = distance/time = 222/6 = 37 km/hr
----------------------
It travels 390 km going downstream in the same amount of time.
Rate = distance/time = 390/6 = 65 km/hr
---------
What is the rate of the boat in still water and what is the rate of the
current?
Equations:
Upstream: b-c = 37 km/hr
Downstrm: b+c = 65 km/hr
Add and solve
for "b":
(2)b = 102 km/hr
b = 51 km/hr (speed of the boat in still water)
-----
Solve for "c":
b+c = 65
51 + c = 65
c = 14 km/hr (speed of the current)