The top of an antenna tower is 125 ft. above level ground. The tower is to be guyed 20 ft. from its top to a point on the ground 80 ft. from the base of the tower· What is the length of the guy wire?

Answers

Answer 1

o see what is going on, we simply draw a triangle. Since the tower is 125 feet high, but the guy wire is 20 feet from the top, the triangle is 125 - 20 = 105 feet high, then 80 feet long.

Using the pythagorean theorem, 105^2 + 80^2 = g^2

g^2 = 11025 + 6400 = 17425

g = sqrt(17425)

g = 132.0038 feet = 132 feet

Hope this helps!

Answer 2

The length of the guy wire is 132 ft, determined by using the Pythagorean theorem with the given vertical and horizontal distances.

The Pythagoras theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

First, note that the height from the ground to the attaching point of the guy wire is 125 ft - 20 ft = 105 ft.The horizontal distance from the base of the tower to the point where the guy wire is attached on the ground is 80 ft.Use the Pythagorean theorem: a² + b² = c², where a = 105 ft and b = 80 ft.Calculate: 105² + 80² = c²11025 + 6400 = c² => 17425 c = √17425 => c ≈ 132 ft.

Therefore, the length of the guy wire is 132 ft.

Complete question:

The top of an antenna tower is 125 ft. above level ground. The tower is to be guyed 20 ft. from its top to a point on the ground 80 ft. from the base of the tower· What is the length of the guy wire?

68 ft132 ft148 ft

Related Questions

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Suppose the velocities of golf swings for amateur golfers are normally distributed with a mean of 95 mph and a standard deviation of 3.9 mph.

What is the difference in velocities between a golfer whose z-score is 0 and another golfer whose z-score is −1?

Answers

Answer:  c) 3.9

Step-by-step explanation:

The mean is 95 so it has a z-score of 0

The standard deviation is 3.9 so a z-score of -1 is a velocity of 95 - 3.9

So, the difference in the their velocities is: 3.9

The scatter plot and table show the number of grapes and blueberries in 10 fruit baskets.

When you use the two data points closest to the line, which is the equation of the regression line?

A.
y = 2/3x + 1/3

B.
y = 2/3x - 8/3

C.
y = 7/24x + 7/3

D.
y=7/24x + 13/6

Answers

c is the correct answer i believe

I need to find the arc of GFE, next, I need to find the circumference AND area with a radius of 5 mm. Then the final questions ask to Write the equation of a circle with a center at (-1,2) and a diameter of 12.


I will be very thankful for your help, this is a required assignment of mine and I have been struggling to get it done. Thank you :)

Answers

Arc GHE is 40 + 80 or 120 so arc GFE is 360 (total measurement in a circle) - 120 which is 240. The circumference of a circle is 2*pi*r so in this case it will be 2*pi*5 or 10pi (you can also write it as approximately 31.4). The area of a circle is pi*r² so it'll be pi*5² or 25pi (you can write it as approximately 78.5 also). The equation of a circle is (x-h)² + (y-k)² = r² where (h,k) is the center of the circle and r is the radius. Input your values. The equation of this circle is (x+1)² + (y-2)² = 6² (The radis is 6 because the diameter is 12)

I hope this helps!

A full circle is 360 degrees.

You are given the angles for GH, HE and FE, subtract those from 360 to find the angle for FG:

360 - 110 - 80 - 40 = 130 degrees.

Now for the arc GFE add FG and FE:

Arc GFE = 130 + 110 = 240 degrees.

Circumference = 2 x PI x r

Using 3.14 for PI:

Circumference  = 2 x 3.14 x 5 = 31.4 mm or 10PI

Area = PI x r^2 = 3.14 x 25 = 78.5 mm^2 or 25PI mm^2

Equation of a circle with center at (-1,2) and diameter of 12:

The equation is written as (x-x1)^2 + (y-y1)^2 = r^2

x1 and y1 are the values of the center (-1,2) and r is the radius, which would be half the diameter.

The equation is: (x+1)^2 + (y-2)^2 = 36

A taut clothesline extends between the points (–4.2, –6.4, 4.5) and (7.1, 2.2, 5.8), where the coordinates are in units of feet. What is the length of the clothesline?

Answers

Answer:

17.54 ft

Step-by-step explanation:

Moving along the line from (–4.2, –6.4, 4.5) to (7.1, 2.2, 5.8), x increases by 11.3, y by 8.6 and z by 10.3.

Applying the Pythagorean Theorem twice, we get

(length of clothesline) = √( 11.3² + 8.6² + 10.3²), or 17.54 ft.

In trei rezervoare sunt 1672 l de benzina dacã in primele doua rezervoare sunt 123100 cl iar in ultimele doua sunt 15 hl sa se afle câ?i l sunt in fiecare rezervor

Answers

the answer is

615500

hope this helps

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

The weights of bags of ready-to-eat salad are normally distributed with a mean of 290 grams and a standard deviation of 10 grams.

What percent of the bags weigh less than 280 grams?

Answers

Answer:  b) 16%

Step-by-step explanation:

The mean is 290 so on a normal bell curve that would be a z-score of 0.

The standard deviation is 10 so 290 - 10 = 280 is a z-score of -1.

A z-score from the left to -1 is 15.9%

Can you help with answer this and if there’s work to be shown please let me know. Thank you!

Answers

f(x) = /x - 2/

f(-1) = /-1 - 2/ = /-3/ = 3

f(0) = /0 - 2/ = /-2/ = 2

f(1) = /1 - 2/ = /-1/ = 1

f(2) = /2 - 2/ = /0/ = 0

Anthony spend $34.56 at the shopping mall. Brad was also shopping at the mall with Anthony. The value of the digit 6 in the amount of money he spent is 100 times more than the value of the digit 6 in the amount Anthony spent. Did Brad spend $56.71 or $57.61? Show all work. Explain how you know which number is correct

Answers

Answer:

$56.71

Step-by-step explanation:

with Anthony's spendings of $34.56, the 6 is in the hundredth place. If the value of the six is 100 times more in Brad's spending, the six would be in the ones place. You would move the six over two place values (because of 100) and end up with 6 dollars. If it was 10 times more, than you would only move one place value over and it would be 57.61.

Answer:

$56.71

Step-by-step explanation:

The value of the 6 in which Anthony spent is the hundredth value, or 0.06

Brad spent 100x more than the value of the digit 6 in which Anthony spent. Multiply 0.06 with 100: 100 x 0.06 = 6

6 is in the ones place value, & $56.71 is the only answer choice with 6 in the ones place value, so it is your answer.

~

(99 POINTS) Please help ASAP! What is a net? What can we use a net for? How can a net be used to find surface area?

Answers

A net can be used to find the area of a specific side or the entire surface area. It can also help to find the perimeter. To find the surface area with a net, solve for the area of each shape in the net and add them together to get the total area (surface area).

Hope this helps!

A flat three dimensional solid like a cube, a prism or a pyramid. When you cut out the "net", fold it and glue it together you can see what the three dimensional shape looks like. (It can be used in math)Draw a net of the polyhedron. Calculate the area of each face. Add up the area of all the faces.

Greg drove 522 miles in 9 hours. At the same rate, how long would it take him to drive 754 miles?

Answers

Answer:

It would take 13 hours

Step-by-step explanation:

522/9 = 58

754/58= 13

Please help me with this....

Answers

Answer:

[tex]3\sqrt{13}[/tex]

Step-by-step explanation:

Using the Theorem of the side of a triangle:

[tex]x^2 = 4 * (4 + 9) = 42\\x = \sqrt{42}[/tex]

And using the Height Theorem:

y = [tex]\sqrt{4 \cdot 9}  = \sqrt{36} = 6[/tex]

And by the Pythagorean Therorem:

z = [tex]\sqrt{6^2 + 9^2} = \sqrt{117} = 3\sqrt{13}[/tex]

What is the inverse of the function shown in this image?

Answers

Answer:

D

Step-by-step explanation:

1.  Replace "f(x)" with "y:"  y = (x + 1)/x

2.  Interchange x and y:  x = (y + 1)/y

3.  Solve this result for y:                                     1

     xy = y + 1, or xy - y = 1, or y(x -1) = 1, or y = --------

                                                                            x-1

4.  Replace "y" with:

        -1               x

      f     (x) = -----------   This matches answer choice D.

                       x - 1

Answer:

D

Step-by-step explanation:

There are 8 people on the debate team. In how many ways can the coach choose 4 members to send to competition?

Answers

he can either send one half or the other half.

Answer:

70

Step-by-step explanation:

Given : There are 8 people on the debate team.

To Find: In how many ways can the coach choose 4 members to send to competition?

Solution:

We will use combination over here

Formula : [tex]^nC_r=\frac{n!}{r!(n-r)!}[/tex]

Now There are 8 people on the debate team and the coach have to choose 4

So, n = 8

r = 4

So, number of ways of choosing 4 people out of 8 = [tex]^8C_4[/tex]

                                                                                    = [tex]\frac{8!}{4!(8-4)!}[/tex]  

                                                                                    = [tex]\frac{8!}{4!4!}[/tex]  

                                                                                    = [tex]70[/tex]  

Hence there are 70 ways of choosing 4 members out of 8 to send to competition

An office has 80 employees and 24 of the employeeshoes are managers. What percent of the employees are mamagers

Answers

Please ignore the x above,,

Answer: 30%

Step-by-step explanation:

Given: the number of employees in the office = 80

The number of employees are managers = 24

Then, the percent of employees are manger is given by :-

[tex]\dfrac{\text{Number of mangers}}{\text{Total employees}}\times100\\\\=\dfrac{24}{80}\times100\\\\=30\%[/tex]

Hence, the percent of the employees are managers = 30%

Which statements are true?

If all angles of a quadrilateral are right angles, then the quadrilateral must be a square.

Two shapes are similar if and only if their corresponding angles are equal.

All quadrilaterals have four sides, and the sum of all angles in a quadrilateral is 180°.

If the diagonals of a quadrilateral are perpendicular bisectors, then the quadrilateral must be a rhombus.

There are three vertices in a triangle, or there are four sides in a pentagon.

Any two triangles are either similar or congruent.

Answers

Answer:

The statement which is true is, If the diagonals of a quadrilateral are perpendicular bisectors, then the quadrilateral must be a rhombus.

Step-by-step explanation:

In a rhombus, the diagonals bisect at perpendicular angles to form 4 triangles.Because the diagonals bisect at right angles, then it is possible to prove that the four small formed triangles are similar using the SAS theorem: two triangles are equal if two sides are equal and the angles between the two sides are equal.In your case, the sides are that on the base and that forming a height of the triangles with both having angle 90° between the sides.So you see if these the two are congruent, the hypotenuse of these triangles are congruent, making this quadrilateral a rhombus.

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Keywords : quadrilateral, rhombus, perpendicular bisector, angles

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Sean used the $1,200 he got from his graduation party to open a savings account. If the account earns 1% interest each month and he makes no additional deposits, how much money will be in the account in 5 years?

Answers

Answer:

[tex]\$1,920[/tex]

Step-by-step explanation:

we know that

The simple interest formula is equal to

[tex]A=P(1+rt)[/tex]

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

[tex]t=5*12=60\ months\\ P=\$1,200\\r=0.01[/tex]

substitute in the formula above

[tex]A=\$1,200(1+0.01*60)[/tex]

[tex]A=\$1,200(1.6)=\$1,920[/tex]

Which best describes the transformation from the graph of f(x) = x2 to the graph of f(x) = (x – 3)2 – 1? left 3 units, down 1 unit left 3 units, up 1 unit right 3 units, down 1 unit right 3 units, up 1 unit

Answers

Answer:

The best describes the transformation is right 3 units, down 1 unit ⇒ 3rd answer

Step-by-step explanation:

* Lets talk about some transformation

- If the function f(x) translated horizontally to the right  

 by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  

 by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up  

 by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down  

 by k units, then the new function g(x) = f(x) – k

* Now lets solve the problem

∵ f(x) = x²

- The change from x² to (x - 3)² means the graph shifted 3 units

  to the right

- The value -1 means the graph shifted down 1 unit

∴ The graph of f(x) = x² is shifted 3 units to the right and 1 unit

   down and the resulting function is f(x) = (x - 3)² - 1

* The best describes the transformation is right 3 units, down 1 unit

Answer:

C

Step-by-step explanation:

The length of a rectangle is 4 times its width. The rectangle's width is 8 m. What is the area of the rectangle? Enter your answer in the box. _______m2

Answers

Answer:

256 m²

Step-by-step explanation:

If the length of a rectangle is 4 times its width, and you know the width is 8, that must mean the length is 32. Now you know the width and the length, multiply those two values to get your area.

PLEASE HELP ME. I NEED YOUR HELP.
Emma's yard needs some work, so she decides to hire a landscaper. The Garden Expert charges a $50 consultation fee plus $36 per hour for the actual work. After working for x hours Emma owed The Garden Expert $212.

Which equation symbolizes the above situation, and how many hours did the landscapers work?

A) $50 - $36x = $212; 4 hours
B) $50 + $36x = $212; 4.5 hours
C ) $50x + $36 = $212; 3.52 hours
D) $212 + $50 = $36x; 7.28 hours

Answers

B) 50+36×=$212 ; 4.5. That is the answer.

The equation symbolizes the above situation is $50 + $36x = $212 and the landscapers work at 4.5 hours

Let's use "x" to represent the number of hours The Garden Expert worked in Emma's yard. We know that the landscaper charges $36 per hour for the actual work and a $50 consultation fee. Therefore, the total cost "C" for the service can be represented as:

C = 36x + 50

Emma owes the landscaper $212, so we can set up the equation as follows:

212 = 36x + 50

Now, let's solve for "x":

First, subtract $50 from both sides to isolate 36x:

212 - 50 = 36x

162 = 36x

Next, divide both sides by 36 to solve for x:

x = 162 / 36

x = 4.5

Hence the correct option is (b).

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Can someone please help with this?!! I will mark brainliest

Answers

Answer:

It is parallel

Step-by-step explanation:

See the first equation equals the last equation, I just realized that.

Volume of cylinder help??? PLEASE HURRY EXAMPLES DOWN BELOW WILL VOTE BRAINLIEST VERY URGENT

Answers

Answer:

Here I leave an example that you will understand more easily  so that you understand the process better but it is easy.

First you must substitute the values ​​for the letters, and then you multiply it so basic remember to change the Pi by 3.14

Determine the length (to 1 decimal place) of the arc that subtends an angle of 2.8 radians at the centre of a circle with radius 12 cm.

13.3 cm

33.6 cm

148.0 cm

16.8 cm

Answers

Answer:

33.6 cm

Step-by-step explanation:

We can use the formula for arc length to solve this.

[tex]s=r\theta[/tex]

Where

s is the arc length

r is the radius

[tex]\theta[/tex] is the angle subtended by the arc (in radians)

The problem gives us theta = 2.8 radians and radius of the circle as 12 cm. We plug these into the formula and figure out the arc length (to 1 decimal place):

[tex]s=r\theta\\s=(12)(2.8)\\s=33.6[/tex]

2nd answer choice is right.

Name four coplanar points

Answers

Four possible coplanar points based on the image are B,E,D; Q,B,E; D,Q,B; and, E,D,Q.

What is the meaning of coplanar?

This word refers to points that share the same plane. Remember a plane is a surface that goes in one direction.

What are some coplanar points?

In the image, all points over the surface are coplanar. Based on this, some coplanar points are:

B,E,DD,Q,BQ,B,EE,D,Q

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1. Which reason completes the proof below?
Given: BC is tangent to Circle A at D
Prove: AB = AC

Answers

Answer:

(C)

Step-by-step explanation:

Given: BC is tangent to the circle A at D.

To prove: AB is congruent to AC

Proof:

Statements                                                            Reason

1. BC is tangent to the circle A at D.                     Given

2. DB≅DC                                                               Given

3.AD⊥BC               If a line is tangent to a circle then it is perpendicular to the radius at the point of tangency.

4. ∠ADB and ∠ADC are right angles     Definition of perpendicular lines

5. ∠ADB≅∠ADC                                      Right angles are congruent

6. AD≅AD                                                Reflexive property of congruence

7. ΔADB≅ΔADC                                      SAS rule

8. AB≅AC                                                CPCTC

Hence, option (C) is correct.

Tangent to a circle is straight line just touching the circle at one point. The reason to complete the proof is: If a line is tangent to a circle,  then it is perpendicular to the point of tangency

What is tangent to a circle?

A line segment which touches a circle specified to only one point is called a tangent to that circle.


How are radius and tangent to a circle related?

There is a theorem in mathematics that:

If there is a circle O with tangent line L intersecting the circle at point A, then the radius OA is perpendicular to the line L.

For the given case, the missing statement for the proof is:

If a line is tangent to a circle,  then it is perpendicular to the point of tangency(the point on circle where the tangent intersects it).

Hence, the reason to complete the proof is: If a line is tangent to a circle,  then it is perpendicular to the point of tangency


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Find the derivative of f(x) = 4 divided by x at x = 2.

Answers

Hello!

The answer is:

[tex]f'(2)=-1[/tex]

Why?

To solve this problem, first we need to derivate the given function, and then, evaluate the derivated function with x equal to 2.

The given function is:

[tex]f(x)=\frac{4}{x}[/tex]

It's a quotient, so, we need to use the following formula to derivate it:

[tex]f'(x)=\frac{d}{dx}(\frac{u}{v}) =\frac{v*u'-u*v'}{v^{2} }[/tex]

Then, of the given function we have that:

[tex]u=4\\v=x[/tex]

So, derivating we have:

[tex]f'(x)=\frac{d}{dx}(\frac{4}{x}) =\frac{x*(4)'-4*(x)'}{x^{2} }[/tex]

[tex]f'(x)=\frac{d}{dx}(\frac{4}{x}) =\frac{x*0-4*1}{x^{2} }[/tex]

[tex]f'(x)=\frac{d}{dx}(\frac{4}{x}) =\frac{0-4}{x^{2} }[/tex]

[tex]f'(x)=\frac{d}{dx}(\frac{4}{x}) =\frac{-4}{x^{2} }[/tex]

Hence,

[tex]f'(x)=\frac{d}{dx}(\frac{4}{x}) =\frac{-4}{x^{2} }[/tex]

Now, evaluating with x equal to 2, we have:

[tex]f'(2)=\frac{-4}{(2)^{2} }[/tex]

[tex]f'(2)=\frac{-4}{4}[/tex]

[tex]f'(2)=-1[/tex]

Therefore, the answer is:

[tex]f'(2)=-1[/tex]

Have a nice day!

ANSWER

[tex]f'(2) = -1[/tex]

EXPLANATION

The given function is

[tex]f(x) = \frac{4}{x} [/tex]

Recall that:

[tex] \frac{c}{ {a}^{ m} } = c {a}^{ - m} [/tex]

We rewrite the given function using this rule to obtain,

[tex]f(x) = 4 {x}^{ - 1} [/tex]

Recall again that,

If

[tex]f(x)= a {x}^{n} [/tex]

then

[tex]f'(x)=n a {x}^{n - 1} [/tex]

We differentiate using the power rule to obtain,

[tex]f'(x) = - 1 \times 4 {x}^{ - 1 - 1} [/tex]

[tex]f'(x) = - 4 {x}^{ - 2} [/tex]

We rewrite as positive index to obtain,

[tex]f'(x) = - \frac{4}{ {x}^{2} } [/tex]

We plug in x=2 to obtain,

[tex]f'(2) = - \frac{4}{ { (2)}^{2} } = - \frac{4}{4} = - 1[/tex]

Need help as soon as possible!

Answers

Answer:

[tex]\boxed{ \text{8 p.m.}}[/tex]

Step-by-step explanation:

First, we must plot the graph of your system of equations (see below).

The two lines cross at (12, 360).

Thus, machine A had been going for 12 h. It started at 8 a.m., so it ended at 8 p.m.

Both machines had made 360 ft of wire by [tex]\boxed{ \text{8 p.m.}}[/tex]

Check:

360 = 30 × 12     360 = 40(12 – 3)

360 = 360          360 = 40 × 9

                          360 = 360

OK.

Find the exact value of the following expression (without using a calculator): tan(Sin^-1 x/2)

Answers

ANSWER

[tex]\tan(\sin^{ - 1}( \frac{x}{2} )) = \frac{x}{ \sqrt{4 - {x}^{2} } } \: \:where \: \: x \ne \pm2[/tex]

EXPLANATION

We want to find the exact value of

[tex] \tan( \sin^{ - 1}( \frac{x}{2} ) ) [/tex]

Let

[tex]y = \sin^{ - 1}( \frac{x}{2} )[/tex]

This implies that

[tex] \sin(y) = \frac{x}{2} [/tex]

This implies that,

The opposite is x units and the hypotenuse is 2 units.

The adjacent side is found using Pythagoras Theorem.

[tex] {a}^{2} + {x}^{2} = {2}^{2} [/tex]

[tex]{a}^{2} + {x}^{2} = 4[/tex]

[tex]{a}^{2} = 4 - {x}^{2}[/tex]

[tex]a= \sqrt{4 - {x}^{2}} [/tex]

This implies that,

[tex] \tan(y) = \frac{opposite}{adjacent} [/tex]

[tex]\tan(y) = \frac{x}{ \sqrt{4 - {x}^{2} } } [/tex]

But

[tex]y = \sin^{ - 1}( \frac{x}{2} )[/tex]

This implies that,

[tex]\tan(\sin^{ - 1}( \frac{x}{2} )) = \frac{x}{ \sqrt{4 - {x}^{2} } } \: \:where \: \: x \ne \pm2[/tex]

Josh leans the ladder against a side of her house which is 10 feet. If the base of the latter is 3 feet away from the house, how tall is the ladder? ( use Pythagorean theorem )

Answers

Answer:

[tex]\sqrt{109}[/tex]

Step-by-step explanation:

The side of the house is a side of the right triangle.

The ladder is 3 feet away, so it forms a triangle with sides 3, 10, x.

We're trying to find the hypotenuse, which is given by Pythagoras' Theorem:

[tex]a^2 + b^2 = c^2\\3^2 + 10^2 = x^2\\109 = x^2\\x = \sqrt{109}[/tex]

Based on a poll of 200 citizens, a community action group claims that 40% of the population is in favor of a curfew for children under 18 on weekday nights. A local parent group claims that the poll is not valid and that only 22% of the citizens favor a curfew. To determine whether this sample supports the population proportion of 0.40, a simulation of 100 trials is run, each with a sample size of 50 and a point estimate of 0.22. The minimum sample proportion from the simulation is 0.15, and the maximum sample proportion from the simulation is 0.27. The margin of error of the population proportion is found using an estimate of the standard deviation. What is the interval estimate of the true population proportion?
(0.18, 0.26)
(0.14, 0.30)
(0.06, 0.38)
(0.16, 0.28)

Answers

Final answer:

The interval estimate of the true population proportion is (0.16, 0.28) that is option D is correct.

Explanation:

The interval estimate of the true population proportion is (0.16, 0.28).

A simulation of 100 trials with a sample size of 50 was conducted to determine whether the sample supports the population proportion of 0.40. The minimum sample proportion from the simulation is 0.15 and the maximum sample proportion is 0.27. Based on this simulation, the interval estimate for the true population proportion can be calculated.

Interval estimate formula: (point estimate - margin of error, point estimate + margin of error)

Point estimate = 0.22

Margin of error = (maximum sample proportion - minimum sample proportion) / 2 = (0.27 - 0.15) / 2 = 0.06

Interval estimate = (0.22 - 0.06, 0.22 + 0.06) = (0.16, 0.28)

The correct interval estimate of the true population proportion is (0.14, 0.30).

To determine the interval estimate of the true population proportion, we use the following formula for a 95% confidence interval:

[tex]\[ \text{Confidence Interval} = \text{Point Estimate} \pm (Z_{\alpha/2} \times \text{Standard Error}) \][/tex]

where[tex]\( Z_{\alpha/2} \)[/tex] is the Z-score corresponding to the desired confidence level (for a 95% confidence interval, [tex]\( Z_{\alpha/2} \)[/tex] is approximately 1.96), and the Standard Error (SE) is calculated using the formula:

[tex]\[ \text{SE} = \sqrt{\frac{\text{Point Estimate} \times (1 - \text{Point Estimate})}{\text{Sample Size}}} \][/tex]

Given the point estimate from the simulation as 0.22 and the sample size as 50, we calculate the standard error as follows:

[tex]\[ \text{SE} = \sqrt{\frac{0.22 \times (1 - 0.22)}{50}} \] \[ \text{SE} = \sqrt{\frac{0.22 \times 0.78}{50}} \] \[ \text{SE} = \sqrt{\frac{0.1716}{50}} \] \[ \text{SE} = \sqrt{0.003432} \] \[ \text{SE} \approx 0.0586 \][/tex]

Now, we calculate the margin of error (ME):

[tex]\[ \text{ME} = Z_{\alpha/2} \times \text{SE} \] \[ \text{ME} = 1.96 \times 0.0586 \] \[ \text{ME} \approx 0.1146 \][/tex]

The margin of error is approximately 0.1146. Therefore, the 95% confidence interval for the population proportion is:

[tex]\[ \text{Point Estimate} \pm \text{ME} \] \[ 0.22 \pm 0.1146 \][/tex]

Lower bound:

[tex]\[ 0.22 - 0.1146 \approx 0.1054 \][/tex]

Upper bound:

[tex]\[ 0.22 + 0.1146 \approx 0.3346 \][/tex]

However, the simulation results provide a range for the sample proportion from 0.15 to 0.27. Therefore, the interval estimate should be adjusted to reflect this range while still incorporating the margin of error.

Lower bound (adjusted for simulation range):

[tex]\[ 0.15 - 0.1146 \approx 0.0354 \][/tex]

Upper bound (adjusted for simulation range):

[tex]\[ 0.27 + 0.1146 \approx 0.3846 \][/tex]

Since the lower bound of the confidence interval cannot be less than the minimum sample proportion from the simulation (0.15), and the upper bound cannot exceed the maximum sample proportion from the simulation (0.27), we adjust the interval to:

Lower bound:

0.15

Upper bound:

0.27

Now, we apply the margin of error to these bounds:

Lower bound with ME:

[tex]\[ 0.15 - 0.1146 \approx 0.0354 \][/tex]

Since the lower bound cannot be less than 0, we round up to the nearest reasonable value, which is 0.14.

Upper bound with ME:

[tex]\[ 0.27 + 0.1146 \approx 0.3846 \][/tex]

Since the upper bound cannot exceed 1, we round down to the nearest reasonable value, which is 0.30.

Therefore, the interval estimate of the true population proportion, taking into account the simulation results and the margin of error, is (0.14, 0.30).

Help Picture below ..........

Answers

Answer:

A

Step-by-step explanation:

Multiply them according to the problem.

[tex]6x+2y=6 \\ \\ -3(6x+2y)=(6)*-3 \\ \\ -18x-6y=-18 \\ \\ \\ 7x+3y=9 \\ \\ 2(7x+3y)=(9)*2 \\ \\ 14x+6y=18[/tex]

As you can see, the only terms in the two equations that can cancel out are [tex]-6y[/tex] and [tex]6y[/tex].

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