The speed of cars on a stretch of road is normally distributed with an average 48 miles per hour with a standard deviation of 5.9 miles per hour. What is the probability that a randomly selected car is violating the speed limit of 50 miles per hour? (a) 0.37 (b) 0.48 (c) 0.21 (d) 0.63

Answers

Answer 1

Answer: (a) 0.37

Step-by-step explanation:

Given: The speed of cars on a stretch of road is normally distributed with an average 48 miles per hour with a standard deviation of 5.9 miles per hour.

i.e. Mean : [tex]\mu = 48\text{ miles per hour} [/tex]

Standard deviation : [tex]\sigma = 5.9\text{ miles per hour}[/tex]

The formula to calculate z is given by :-

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For the probability that a randomly selected car is violating the speed limit of 50 miles per hour (X≥ 50).

For x= 80

[tex]z=\dfrac{50-48}{5.9}=0.338983050847\approx0.34[/tex]

The P Value =[tex]P(z>0.34)=1-P(z<0.34)=1-0.6330717\approx0.3669283\approx0.37[/tex]

Hence, the probability that a randomly selected car is violating the speed limit of 50 miles per hour =0.37

Related Questions

Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the
domain x ≥ 2.
will mark brainliest

Answers

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

[tex]F(x)=\sqrt{x-2}[/tex]

[tex]G(x)=(x-2)^2[/tex]

[tex]H(x)=x^2+2[/tex]

We compose F(x) and G(x) to get:

[tex](F\circ G)(x)=F(G(x))[/tex]

[tex](F\circ G)(x)=F((x-2)^2)[/tex]

[tex](F\circ G)(x)=\sqrt{(x-2)^2-2}[/tex]

[tex](F\circ G)(x)=\sqrt{x^2-4x+4-2}[/tex]

[tex](F\circ G)(x)=\sqrt{x^2-4x+2}[/tex]

[tex](F\circ G)(x)\ne x[/tex]

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

[tex](F\circ H)(x)=F(H(x))[/tex]

[tex](F\circ H)(x)=F(x^2+2)[/tex]

[tex](F\circ H)(x)=\sqrt{x^2+2-2}[/tex]

We simplify to get:

[tex](F\circ H)(x)=\sqrt{x^2}[/tex]

[tex](F\circ H)(x)=x[/tex]

Since [tex](F\circ H)(x)=x[/tex], H(x) is an inverse of F(x)

Klassen Toy Company, Inc., assembles two parts (parts 1 and 2): Part 1 is first processed at workstation A for 10 minutes per unit and then processed at workstation B for 20 minutes per unit. Part 2 is simultaneously processed at workstation C for 30 minutes per unit. Work stations B and C feed the parts to an assembler at workstation D, where the two parts are assembled. The time at workstation D is 15 minutes. a) The bottleneck of this process is workstation D , at 4 minutes per unit (enter your response as a whole number).

Answers

Answer:

The bottleneck of this process is Workstation C, at 30 minutes per unit.

Step-by-step explanation:

The throughput of each workstation is ...

A: 6 per hourB: 3 per hourC: 2 per hourD: 4 per hour

Since each process must be executed once per finished product, the bottleneck is the station with the lowest throughput. It is clearly Workstation C.

Final answer:

The bottleneck of this process is workstation D, where the time per unit is 15 minutes.

Explanation:

The bottleneck of this process is workstation D, where the time per unit is 15 minutes. This means that workstation D takes the longest time to complete one unit compared to other workstations. The bottleneck determines the maximum output rate of the entire process, as the other workstations cannot work faster than the slowest one.

Learn more about Bottleneck in production process here:

https://brainly.com/question/32721320

#SPJ3

An ellipse has vertices at (0, #17) and foci at (0, ±15). Write the equation of the ellipse in standard form. Graph the ellipse.

Answers

ANSWER

[tex]\frac{ {x}^{2} }{ 64 } + \frac{ {y}^{2} }{ 289 } = 1[/tex]

See attachment for the graph

EXPLANATION

The standard equation of the vertical ellipse with center at the origin is given by

[tex] \frac{ {x}^{2} }{ {b}^{2} } + \frac{ {y}^{2} }{ {a}^{2} } = 1[/tex]

where

[tex] {a}^{2} \: > \: {b}^{2} [/tex]

The ellipse has its vertices at (0,±17).

This implies that:a=±17 or a²=289

The foci are located at (0,±15).

This implies that:c=±15 or c²=225

We use the following relation to find the value of b²

[tex] {a}^{2} - {b}^{2} = {c}^{2} [/tex]

[tex] \implies \: 289 - {b}^{2} = 225[/tex]

[tex] - {b}^{2} = 225 - 289[/tex]

[tex] - {b}^{2} = - 64[/tex]

[tex] {b}^{2} = 64[/tex]

We substitute into the formula for the standard equation to get:

[tex]\frac{ {x}^{2} }{ 64 } + \frac{ {y}^{2} }{ 289 } = 1[/tex]

A probability experiment is conducted in which the sample space of the experiment is S={7,8,9,10,11,12,13,14,15,16,17,18}, event F={7,8,9,10,11,12}, and event G={11,12,13,14}. Assume that each outcome is equally likely. List the outcomes in F or G. Find P(F or G) by counting the number of outcomes in F or G. Determine P(F or G) using the general addition rule.

Answers

Answer:

F or G = {7,8,9,10,11,12,13,14}

n(F or G) = 8

n(S) = 12

By counting the no. of outcome

P(F or G) = n(F or G) / n(S)

P(F or G) = 8 /12

P(F or G) = 2/3

By using the general addition rule

P(F or G) = P(F) + P(G) - P(F and G)

= 6/12 + 4/12 - 2/12

= 2/3

32a³b²
_____

8ab²

Simplify the following expression.

Answers

Answer:

[tex]4a^{2}[/tex]

Step-by-step explanation:

We need to simplify the following expression:

[tex]y=\frac{32a^{3}b^{2}}{8ab^{2}}[/tex]

We know that: [tex]\frac{x^{a}}{x^{b}}=x^{a-b}[/tex]. Applying this rule, we have that:

[tex]y = \frac{32a^{3}b^{2}}{8ab^{2}} = 4a^{3-1}b^{2-2} = 4a^{2}[/tex]

Then, the solution is: [tex]4a^{2}[/tex]

Lester Hollar is vice president for human resources for a large manufacturing company. In recent years, he has noticed an increase in absenteeism that he thinks is related to the general health of the employees. Four years ago, in an attempt to improve the situation, he began a fitness program in which employees exercise during their lunch hour. To evaluate the program, he selected a random sample of eight participants and found the number of days each was absent in the six months before the exercise program began and in the six months following the exercise program. Below are the results. At the .05 significance level, can he conclude that the number of absences has declined? Estimate the p-value.

Answers

Final answer:

Lester Hollar can assess the impact of the fitness program on absenteeism by conducting a paired samples t-test at a 0.05 significance level. If the p-value is less than 0.05, the program effectively reduced absences; otherwise, there is insufficient evidence to conclude its effectiveness.

Explanation:

Evaluating the Exercise Program’s Impact on Employee Absenteeism

Lester Hollar wishes to assess if the company’s fitness program led to a decline in employee absences. With a sample of eight participants, he analyzed absenteeism before and after the program’s implementation. To determine if absences have decreased, a hypothesis test at the 0.05 significance level (alpha) is conducted.

To evaluate the change in absences, two sets of absenteeism data are compared using a statistical test, such as the paired samples t-test. This test examines if the mean difference in absences before and after the program is statistically significant. If the p-value obtained from the test is less than the significance level of 0.05, the null hypothesis (no change in absences) would be rejected, suggesting that the exercise program was effective in reducing absences.

If Lester Hollar finds a p-value greater than 0.05, he would not reject the null hypothesis, indicating that there isn’t sufficient evidence to conclude the program's impact. It’s also important to estimate the p-value precisely as it gives a measure of the strength of evidence against the null hypothesis. However, without the specific data, we cannot calculate the p-value or make a definitive conclusion here.

According to a study, 86% of K-12 schools or districts in a country use digital content such as ebooks, audiobooks, and digital textbooks. Of these 86%, 11 out of 20 use digital content as part of their curriculum. Find the probability that a randomly selected school or district uses digital content and uses it as part of their curriculum. The probability that a randomly selected school or district uses digital content and uses it as part of their curriculum is nothing.

Answers

Answer: Our required probability is 47.3%.

Step-by-step explanation:

Since we have given that

Probability of schools or district in a country use digital content = 86% = 0.86

Probability of schools or district uses digital content as a part of their curriculum out of 86% = [tex]\dfrac{11}{20}[/tex]

So, Probability that a selected school or district uses digital content and uses it as a part of their curriculum is given by

[tex]\dfrac{86}{100}\times \dfrac{11}{20}\\\\=0.86\times 0.55\\\\=0.473\\\\=47.3\%[/tex]

Hence, our required probability is 47.3%.

The probability that a randomly selected school or district uses digital content and uses it as part of their curriculum is 47.3% and this can be determined by using the given data.

Given :

The probability that a randomly selected school or district uses digital content and uses it as part of their curriculum is given by:

[tex]=\dfrac{11}{20}\times \dfrac{86}{100}[/tex]

Now, multiply 11 by 86 and also multiply 20 by 100 in the above expression.

[tex]=\dfrac{11\times 86}{20\times 100}[/tex]

SImplify the above expression.

[tex]=\dfrac{946}{2000}[/tex]

= 0.473

So, the probability that a randomly selected school or district uses digital content and uses it as part of their curriculum is 47.3%.

For more information, refer to the link given below:

https://brainly.com/question/21586810

In testing whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows:
Brand X n2=20 xbar 2=6.80 s2=1.15
Brand Y n1=20 xbar1=7.30 s1=1.10
Assume that the population variances are equal. Then, the standard error of the sampling distribution of the sample mean difference xbar1−xbar2 is equal to: Question 2 options: (a) 1.1275 (b) 0.1266 (c) 1.2663 (d) 0.3558.

Answers

Answer: (d) 0.3558.

Step-by-step explanation:

We know that the standard error of sample mean difference is given by:-

[tex]S.E.=\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}[/tex]

Given : [tex]n_1= 20\ ,\ n_2=20[/tex]

[tex]s_1=1.10\ ,\ \ s_2=1.15[/tex]

Then , the standard error of the sampling distribution of the sample mean difference [tex]\overline{x_1}-\overline{x_2}[/tex] is equal to :-

[tex]S.E.=\sqrt{\dfrac{1.10^2}{20}+\dfrac{1.15^2}{20}}\\\\\Rightarrow\ S.E.=0.355844066973\approx0.3558[/tex]

Hence, the standard error of the sampling distribution of the sample mean difference [tex]\overline{x_1}-\overline{x_2}[/tex] is equal to 0.3558.

Final answer:

The standard error of the sampling distribution of the sample mean difference is calculated using the formula involving standard deviations and sample sizes of the independent samples; the correct answer, after computation, is 0.3558.

Explanation:

The standard error of the sampling distribution of the sample mean difference (ëxbar1 - ëxbar2) when assuming population variances are equal can be computed using the formula for the standard error of the difference of two independent sample means, which is the square root of the sum of their variances divided by their respective sample sizes. The formula is:
SE = √((s1²/n1) + (s2²/n2))

Given the summary statistics:

n1 = n2 = 20 (sample sizes)s1 = 1.10 (standard deviation of sample 1)s2 = 1.15 (standard deviation of sample 2)

The calculation of the standard error would be:

SE = √((1.10²/20) + (1.15²/20))

SE = √((1.21/20) + (1.3225/20))

SE = √(0.0605 + 0.066125)

SE = √(0.126625)

SE = 0.3558 (when rounded to four decimal places)

Hence, the correct answer is option (d) 0.3558.

a ball is shot straight upward. with it's height, in feet, after t seconds given by the function f(t)=-16t^2+192t. Find the average velocity of the ball from t=1 to t=6

Answers

ANSWER

[tex]80 {ms}^{ - 1} [/tex]

EXPLANATION

The average velocity of the ball is the rateof displacement over the total time.

The height of the ball, in feet, after t seconds is given by the function:

[tex]f(t)=-16t^2+192t[/tex]

At time t=1, the height of the ball is

[tex]f(1)=-16(1)^2+192(1)[/tex]

[tex]f(1)=-16+192 = 176ft[/tex]

At time t=6, the height of the ball is

[tex]f(6)=-16(6)^2+192(6)[/tex]

[tex]f(6)=-16(36)+192(6)[/tex]

[tex]f(6)=-576+1152 = 576[/tex]

The average velocity

[tex] = \frac{f(6) - f(1)}{6 - 1} [/tex]

[tex]= \frac{576- 176}{6 - 1} [/tex]

[tex]= \frac{400}{5} [/tex]

[tex] = 80 {ms}^{ - 1} [/tex]

Find the area under the curve y =f( x) on [a,b] given f(x)=tan(3x) where a=0 b=pi/12

Answers

Answer:

The area under the curve y=f(x) on [a,b] is [tex]\frac{1}{6}\ln(2)[/tex] square units.

Step-by-step explanation:

The given function is

[tex]f(x)=\tan(3x)[/tex]

where a=0 and b=pi/12.

The area under the curve y=f(x) on [a,b] is defined as

[tex]Area=\int_{a}^{b}f(x)dx[/tex]

[tex]Area=\int_{0}^{\frac{\pi}{12}}\tan (3x)dx[/tex]

[tex]Area=\int_{0}^{\frac{\pi}{12}}\frac{\sin (3x)}{\cos (3x)}dx[/tex]

Substitute cos (3x)=t, so

[tex]-3\sin (3x)dx=dt[/tex]

[tex]\sin (3x)dx=-\frac{1}{3}dt[/tex]

[tex]a=\cos (3(0))=1[/tex]

[tex]b=\cos (3(\frac{\pi}{12}))=\frac{1}{\sqrt{2}}[/tex]

[tex]Area=-\frac{1}{3}\int_{1}^{\frac{1}{\sqrt{2}}}\frac{1}{t}dt[/tex]

[tex]Area=-\frac{1}{3}[\ln t]_{1}^{\frac{1}{\sqrt{2}}[/tex]

[tex]Area=-\frac{1}{3}(\ln \frac{1}{\sqrt{2}}-\ln (1))[/tex]

[tex]Area=-\frac{1}{3}(\ln 1-\ln \sqrt{2}-0)[/tex]

[tex]Area=-\frac{1}{3}(-\ln 2^{\frac{1}{2}})[/tex]

[tex]Area=-\frac{1}{3}(-\frac{1}{2}\ln 2)[/tex]

[tex]Area=-\frac{1}{6}\ln 2[/tex]

Therefore the area under the curve y=f(x) on [a,b] is [tex]\frac{1}{6}\ln(2)[/tex] square units.

Help on this ALGEBRA QUESTIONS !!!
Simplify the expression, if possible. 512 ^1/2

A. 32
B. 16√ 2
C. 64
D. It's not a real number.

Answers

Note that [tex]x^{\frac{1}{2}}=\sqrt[2]{x}[/tex]

Which means that:

[tex]512^{\frac{1}{2}}=\sqrt[2]{512}=\sqrt[2]{16^2\cdot2}=\boxed{16\sqrt[2]{2}}[/tex]

the answer is B.

Hope this helps.

r3t40

The window shown is the shape of a semicircle with a radius of 6 feet. The distance from F to E is 3 feet and the measure of = 45°. Find the area of the glass in region BCIH, rounded to the nearest square foot.

Answers

Answer:

The area of the glass in region BCIH is 11 to the nearest feet²

Step-by-step explanation:

* Lets explain the figure

- The window is a semicircle with center G and radius 6 feet

- There is a small semicircle with center G and radius GF

∵ GE is 6 feet and EF is 3 feet

∵ GE = GF + FE

∴ 6 = GF + 3 ⇒ subtract 3 from both sides

∴ 3 = GF

∴ The radius of the small semicircle is 3 feet

∵ m∠BGC = 45°

- The area of sector BGC is part of the area of the semicircle

∵ The area of semi-circle is 1/2 π r²

∵ The measure of the central angle of the semicircle is 180°

∵ The measure of the central angle of the sector BGC is 45°

∴ The sector = 45°/180° = 1/4 of the semi-circle

∴ The area of the sector is 1/4 the area of the semicircle

∵ The area of the semicircle = 1/2 π r²

∵ r = 6 feet

∴ The area of the semicircle = 1/2 π (6)² = 1/2 π (36) = 18 π feet²

∴ Area of the sector = 1/4 (18 π) = 4.5 π feet²

- The small sector HGI has the same central angle of the sector BGC

∴ The area of the sector HGI is 1/4 The area of the small semicircle

∵ The area of the small semicircle = 1/2 π r²

∵ r = 3 feet

∴ The area of the small semicircle = 1/2 π (3)² = 1/2 π (9) = 4.5 π feet²

∴ Area of the sector HGI= 1/4 (4.5 π) = 1.125 π feet²

- The area of the glass in region BCIH is the difference between the

area of sector BGC and the area of the sector HGI

∴ The area of the glass in region BCIH = 4.5 π - 1.125 π ≅ 11 feet²

Answer:

11 feet to the nearest square foot.

Step-by-step explanation:

The area of sector BCG

= 45/180 * 1/2 π r^2

= 1/4 * 1/2 π r^2

= 1/8 * π * 6^2

= 4.5 π ft^2.

The radius of the inner semicircle is 6 - 3 = 3 feet.

The area of sector HIG = 1/4 * 1/2 π 3^2

= 1.125 π ft^2.

So the area of BCIH

= area of BCG - area HIG

= 4.5 π - 1.125 π

= 3.375 π

= 10.6 square feet.

A quality control inspector has drawn a sample of 1414 light bulbs from a recent production lot. If the number of defective bulbs is 22 or more, the lot fails inspection. Suppose 20%20% of the bulbs in the lot are defective. What is the probability that the lot will fail inspection? Round your answer to four decimal places.

Answers

Answer: 0.8021

Step-by-step explanation:

The given problem is a binomial distribution problem, where

[tex]n=14,\ p=0.2, q=1-0.2=0.8[/tex]

The formula of binomial distribution is :-

[tex]P(X=r)=^{n}C_{r}p^{r}q^{n-r}[/tex]

The probability that the lot will fail inspection is given by :_

[tex]P(X\geq2)=1-(P(X\leq1))\\\\=1-(P(0)+P(1))\\\\[/tex]

[tex]=1-(^{14}C_{0}(0.2)^{0}(0.8)^{14-0}+^{14}C_{1}(0.2)^{1}(0.8)^{14-1})\\\\=1-((1)(0.8)^{14}+(14)(0.2)(0.8)^{13})\\\\=0.802087907\approx0.8021[/tex]

Hence, the required probability = 0.4365

An actor invests some money at 7%, and $24000 more than four times the amount at 8%. The total annual interest earned from the investment is $29220. How much
did he invest at each amount? Use the six-step method.

He invested $_____at 7% and ____at 8%.

Answers

Answer:

$70,000 at 7%$304,000 at 8%

Step-by-step explanation:

Given:

Total interest earned on two investments is $29,220.

An amount is invested at 7%.

$24,000 more than 4 times that amount is invested at 8%.

Find:

The amount invested at each rate.

Solution:

Our strategy will be to define a variable representing the amount invested at 7%, use that variable to write an expression for the amount invested at 8%, then write an equation for the total return on the investments.

Let x represent the amount invested at 7%. Then (24,000+4x) will be the amount invested at 8%. The total interest earned will be ...

interest on 7% account + interest on 8% account = total interest

0.07x + 0.08(24000+4x) = 29220

0.39x + 1920 = 29220 . . . . . . . . . . . simplify

0.39x = 27300 . . . . . . . . . . . . . . . . . .subtract 1920

x = 27300/0.39 = 70000 . . . . . . . . . divide by the coefficient of x

24,000 +4x = 24,000 +280,000 = 304,000 . . . . amount invested at 8%

He invested $70,000 at 7% and $304,000 at 8%.

Check

The answer must satisfy ...

7% interest + 8% interest = 29,220

0.07×70,000 +0.08×304,000 = 4,900 +24,320 = 29,220 . . . . as required

_____

Comment on 6-step method

We have tried to hit the highlights. Your steps appear to be ...

Identify the given information (Given)Identify the question you are asked to answer (Find)Identify the useless information in the problem statement (is none)Decide on a strategy. Make a model or drawing. (model equation shown)Solve and show work (Solution)Explain why the answer makes sense (Check)

2. An investment company pays 9% compounded semiannually. You want to have $8,000 in the future. How much should you deposit now to have that money 5 years from now?

Answers

Answer:

$5151.42

Step-by-step explanation:

The formula you need is

[tex]A(t)=P(1+\frac{r}{n})^{(n)(t)}[/tex]

where A(t) is the amount after the compounding, P is the initial investment, r is the interest rate in decimal form, n is the number of compoundings per year, and t is time in years. The info we have is

A(t) = 8000

P = ?

r = .09

t = 5

Filling in we have

[tex]8000=P(1+\frac{.09}{2})^{(2)(5)}[/tex]

Simplifying a bit and we have[tex]8000=P(1+.045)^{10}[/tex]

Now we will add inside the parenthesis and raise 1.045 to the 10th power to get

8000 = P(1.552969422)

Divide away the 155... on both sides to solve for P.

P = $5151.42

100 people responded to a survey about their ice cream preferences, and listed below are the results. 55 liked vanilla 30 liked chocolate 40 liked strawberry 10 liked both vanilla and strawberry 10 liked both strawberry and chocolate 15 liked both vanilla and chocolate 5 liked all three flavors How many did not like any of the three flavors?

Answers

Final answer:

To find the number of people who did not like any of the three flavors, we need to subtract the number of people who liked at least one flavor from the total number of people.

Explanation:

To find the number of people who did not like any of the three flavors, we need to subtract the number of people who liked at least one flavor from the total number of people.

From the given information, we can create a Venn diagram to represent the preferences:

Picking it up from the explanation above, it becomes clear that 10 people liked both vanilla and strawberry, 10 people liked both strawberry and chocolate, and 15 people liked both vanilla and chocolate. We also know that 5 people liked all three flavors. Using this information, we can determine the number of people who liked at least one flavor by adding up the numbers in the overlapping circles: 10 + 10 + 15 + 5 = 40 people.

To find the number of people who did not like any of the three flavors, we subtract 40 from the total number of people who responded to the survey: 100 - 40 = 60 people.

Learn more about Ice cream survey here:

https://brainly.com/question/18427332

#SPJ3

To find out how many people did not like any of the three flavors, we use the principle of inclusion-exclusion, resulting in 5 people who did not like vanilla, chocolate, or strawberry.

The student has asked a question related to combinations without repetition and the interpretation of survey results. To determine how many people did not like any of the three flavors (vanilla, chocolate, strawberry), we can use the principle of inclusion-exclusion. Here are the steps to solve this:

First, add the number of people who liked each flavor: 55 (vanilla) + 30 (chocolate) + 40 (strawberry) = 125.Next, subtract the numbers who liked each combination of two flavors: 125 - (10 + 10 + 15) = 125 - 35 = 90.Now, add back those who liked all three flavors because they were subtracted twice: 90 + 5 = 95.Finally, since there were 100 people surveyed, subtract the number who liked at least one flavor from the total: 100 - 95 = 5.

Therefore, 5 people did not like any of the three flavors.

A certain group of women has a 0.640.64%

rate of red/green color blindness. If a woman is randomly selected, what is the probability that she does not have red/green color blindness?

What is the probability that the woman selected does not have red/green color blindness?

nothing

(Type an integer or a decimal. Do not round.)

Answers

Answer:

the probability that the woman selected does not have red/green color blindness is 0.9936.

Step-by-step explanation:

Final answer:

The probability that a randomly selected woman does not have red/green color blindness is 99.36%.

Explanation:

If the rate of red/green color blindness among a certain group of women is 0.64%, this means that out of every 100 women, 0.64 women on average would have red/green color blindness.

The complement of a probability event occurring is equal to 1 minus the probability of the event.

Therefore, the probability that a randomly selected woman does not have red/green color blindness is :

1 - 0.0064

which is 0.9936 or 99.36%.

An experimenter has prepared a drug dosage level that she claims will induce sleep for 80% of people suffering from insomnia. After examining the dosage, we feel that her claims regarding the effectiveness of the dosage are inflated. In an attempt to disprove her claim, we administer her prescribed dosage to 20 insomniacs and we observe Y , the number for whom the drug dose induces sleep. We wish to test the hypothesis H0 : p = .8 versus the alternative, Ha : p < .8. Assume that the rejection region {y ≤ 12} is used.

Answers

Answer:

cool

Step-by-step explanation:

you begin playing a new game called hooville. You are King of Hooville, a city of owls that is located in the treetops near Fords of Beruna. In order to know how much food to produce each year, you must predict the population of Hooville. History shows that the population growth rate of Hooville is 3.5%. The current population of owls is 80,000. Using the monetary growth formula that you used in the Uncle Harold problem, write a new function for the population of hooville. (let n=1.) PLEASE HELP. I HAVE NO IDEA WHAT IM DOING!!

Answers

Answer:

Part 1) [tex]y=80,000(1.035)^{x}[/tex]

Part 2) The table in the attached figure

Part 3) The graph in the attached figure

Step-by-step explanation:

Part 1) Find the population function

In this problem we have a exponential function of the form

[tex]y=a(b)^{x}[/tex]

where

y ----> is the population

x ----> the time in years

a is the initial value (a=80,000 people)

b is the base (b=100%+3.5%=103.5%=1.035)

substitute

[tex]y=80,000(1.035)^{x}[/tex]

Part 2) Construct the table

For x=0 years