The soccer team collected $800 at a car wash fundraiser. They charged $5 00 for small vehicles and $10 00 for larger
vehicles. The amount collected can be modeled by the equation 5x+10y 800, where x represents the number of small
vehicles and y represents the number of larger vehicles. If the number of larger vehicles washed was 50, how many small
vehicles were washed in total?

Answer:

0,-9

Step-by-step explanation:

To solve [tex]x^2[/tex] + 9x = 0, we factor out the common x to get x(x + 9) = 0 and set each factor equal to zero, which gives us the solutions x = 0 and x = -9.

To solve the equation x2 + 9x = 0, we can apply factoring techniques. The first step is to factor out the common factor x from both terms in the equation. This yields:

x(x + 9) = 0

Then you have to realize that a product of two multiplicands is equal to zero if either multiplicand is equal to zero. Setting either multiplicand equal to zero and solving for x yields the solutions. Therefore, we have two multiplicands:

x = 0

x + 9 = 0, which simplifies to x = -9

The solutions to the equation are x = 0 and x = -9. As a check, we can substitute these values back into the original equation and confirm that both satisfy the equation.

Answer:

C. s= 75

Step-by-step explanation:

One radian is the angle subtended by an arc length equal to the radius of the circle.

∅=s/r where s is the arc length ∅ the angle and r the radius of the circle.

Thus s=∅×r

In the circle provided arc s subtends and angle of 5 radians.

s= 5 radians× 15

=75

Answer:

-3, -2, -1, 0, 1, 2

Step-by-step explanation:

Note that "integer" means whole numbers, and "consecutive" means continuously following. Also, note that you are starting with -3:

-3 , -2 , -1 , 0 , 1 , 2, is your answer, because you just need to add 1 each time until you have 6 numbers.

~

Your answer is the first option, "One is a factor of every whole number since every number is divisible by itself".

This is true because whenever you multiply 1 by anything you always get the thing you multiplied by, which makes it a factor of every number.

You can also find this by eliminating the other options, for example a prime number is any number whose factors are 1 and itself, 2 factors, so since 1 only has 1 factor it is not prime and option 3 is eliminated.

This also eliminates option 4 because 1 cannot be a composite number if it only has 1 factor.

I hope this helps!

The true statement among the given options is that one is a factor of every whole number since every number is divisible by itself.

A prime number is that number that is only fully divisible by 1 and that number itself.

Since we know that every number is divisible by 1. Thus 1 is also a factor of every number.

Thus one is a factor of every number.

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-4 times -2 equals 8.

8 times -1 equals -8.

Therefore, the point on your number line that is on -8 is your answer!

Answer: 0 is the answer, the 1/7 and -1/7 cancel each other out. Leaving zero as the answer!

Answer:

4 cups of candies and 8 cups of nuts

Step-by-step explanation:

Cost per cup = $1.29

Total number of cups = 12

Total cost of cups = 12 x $1.29

                              = $15.48

Cost of candies = $2.49 per cup

Total number of candies = x

Cost of nuts = $0.69 per cup

Total number of nuts = y

Equations :

x + y = 12 (because total cups of nuts and candies will be equal to 12)

2.49x + 0.69y = 15.48 (Total cost of the 12 cups should be 15.48)

Step 1 : Find x in terms of y

x = 12 - y

Step 2 : substitute x in terms of y from step 1 in the second equation

2.49x + 0.69y = 15.48

2.49 ( 12 - y) + 0.69y = 15.48

29.88 - 2.49y + 0.69y = 15.48

-1.8y = -14.4

y = 14.4/1.8

y = 8

Step 3 : Find x

x + y = 12

x = 12 - y

x = 12- 8

x = 4

Yumi should use 4 cups of candies and 8 cups of nuts.

!!

The number of cups of candies and nuts, Yumi should use is 4 and 8 cups respectively.

Given the following data:

Translating the word problem into an algebraic expression, we have;

For total number of cups:

[tex]C + N = 12[/tex]  .....equation 1

For cost of candies and nuts:

[tex]2.49C + 0.69N = 1.29(12)\\\\2.49C + 0.69N = 15.48[/tex].....equation 2

From equation1:

[tex]C = 12 - N[/tex]   ....equation 3

Substituting eqn 3 into eqn 1, we have:

[tex]2.49(12 - N) + 0.69N = 15.48\\\\29.88 - 2.49N + 0.69N = 15.48\\\\1.8N = 29.88 - 15.48\\\\1.8N = 14.4\\\\N = \frac{14.4}{1.8}[/tex]

Number of nuts, N = 8 cups

For candies:

[tex]C = 12 - N\\\\C = 12 - 8[/tex]

Number of candies, N = 4 cups

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The greater common divisor between 10 and 15 is 5, so we can factor it out:

[tex]10x^2-15x = 5(2x^2-3x)[/tex]

The greater common exponent between 1 and 2 is 1, so we can factor x out:

[tex]10x^2-15x = 5x(2x-3)[/tex]

The area of a parallelogram is the base times the height.

Area = 14 x 8 = 112 square inches.

Step-by-step explanation:

formula of square= width x length

width = length

each sides = √ 64

= 8 cm

area of the rectangle = 1 & 1/2 x 64

= 96 cm²

formula for area of rectangle = " square

8 x length = 96 cm²

length= 96/8

= 12 cm

perimeter= 4 (8 + 12 + 12)

= 128 cm

*multiple with 4 cuz issa cross (??) i hope you get what i mean(??)

correct me if i'm wrong i'm learning too

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

[tex]\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}[/tex]

[tex]\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}[/tex]

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

Answer:

Third Option

Step-by-step explanation:

Given expression is:

[tex]\sqrt{\frac{55x^7y^6}{11x^11y^8}}[/tex]

Simplifying

[tex]=\sqrt{\frac{11*5*x^7*y^6}{11*x^11*y^8}}\\=\sqrt{\frac{5*x^7*y^6}{x^11*y^8}}\\Combining\ exponents\ with\ same\ base\\=\sqrt{\frac{5}{11*x^{(11-7)}*y^{(8-6)}}}\\=\sqrt{\frac{5}{x^{4}*y^{2}}}\\Applying\ radical\\=\frac{5^{\frac{1}{2}}}{x^{(4*\frac{1}{2})}*y^{(2*\frac{1}{2})}}}\\=\frac{\sqrt{5}}{x^2y}[/tex]

As 5 cannot be taken out of the square root, it will remain inside the square root.

Hence, Third option is the correct answer ..

Answer:

B  (the second graph)

Step-by-step explanation:

3.55g<-28.4

Divide each side by 3.55

3.55g/3.55<-28.4/3.55

g < -8

This would be an open circle at 8  (because g is less than not less than or equal to)  and it goes to the left ( since g is less than)

Answer:

Look to the attached graph

Step-by-step explanation:

* Lets explain the difference between the graphs of f(x) and g(x)

∵ f(x) = IxI

∵ g(x) = IxI - 4

- If we add are subtract f(x) by k, where k is a constant that means

 we translate f(x) vertically

- If g(x) = f(x) + k

∴ f(x) translated vertically k units up

- If g(x) = f(x) - k

∴ f(x) translated vertically k units down

∵ g(x) = IxI - 4

∵ f(x) = IxI

∴ g(x) = f(x) - 4

∴ f(x) translated vertically 4 units down

∴ The graph of f(x) will translate down 4 units

∵ The origin point (0 , 0) lies on f(x)

∴ The origin point (0 , 0) will translate down by 4 units

∴ Its image will be point (0 , -4)

∴ Point (0 , -4) lies on the graph of g(x)

- So you can translate each point on the graph of f(x) 4 units down to

 graph g(x)

# Two point on the left part

∵ Point (-2 , 2) lies on f(x)

∴ Its image after translation 4 units down will be (-2 , -2)

∴ Point (-2 , 2) lies on g(x)

∵ Point (-7 , 7) lies on f(x)

∴ Its image after translation 4 units down will be (-7 , 3)

∴ Point (-7 , 3) lies on g(x)

# Two point on the right part

∵ Point (3 , 3) lies on f(x)

∴ Its image after translation 4 units down will be (3 , -1)

∴ Point (3 , -1) lies on g(x)

∵ Point (8 , 8) lies on f(x)

∴ Its image after translation 4 units down will be (8 , 4)

∴ Point (8 , 4) lies on g(x)

* Now you can draw the graph with these 5 points

For this case we must find the inverse of the following function:

[tex]g (x) = 2x + 4[/tex]

Replace g(x) with y:

[tex]y = 2x + 4[/tex]

We exchange the variables:

[tex]x = 2y + 4[/tex]

We solve for "y":

We subtract 4 on both sides of the equation:

[tex]x-4 = 2y[/tex]

We divide between 2 on both sides of the equation:

[tex]y = \frac {x} {2} -2[/tex]

We change y by [tex]g ^ {-1} (x)[/tex]:

[tex]g ^ {- 1} (x) = \frac {x} {2} -2[/tex]

Answer:

[tex]g ^ {- 1} (x) = \frac {x} {2} -2[/tex]

Answer:

[tex]f^{-1}=\frac{x}{2} -2[/tex]

Step-by-step explanation:

the inverse function of g(x) = 2x + 4

To find the inverse of a function we replace g(x) with y

[tex]y=2x+4[/tex]

Replace x with y and y with x

[tex]x=2y+4[/tex]

Solve the equation for y

Subtract 4 from both sides

[tex]x-4= 2y[/tex]

Divide both sides by 2

[tex]\frac{x}{2} -2=y[/tex]

[tex]y=\frac{x}{2} -2[/tex]

Replace y with f inverse

[tex]f^{-1}=\frac{x}{2} -2[/tex]

The requried, to make the game fair, the first place prize should be worth 4n - 13 dollars. None of the options are correct.

Probability can be defined as the ratio of favorable outcomes to the total number of events.

Here,
The second place prize is worth $8 and the third place prize is worth $5, so the total value of these two prizes is $8 + $5 = $13.

If the game is fair, then the total amount of prize money awarded should be equal to the total amount of entry fees collected. If n players enter the game, then the total entry fees collected will be 4n.

Let x be the value of the first-place prize, which we want to find. The probability of winning any of the three prizes is 1/n, so the total amount of prize money awarded is,

1/n × x + 1/n × $8 + 1/n × $5 = ($4)n
x + 8 + 5 = 4n
x = 4n - 13

Therefore, to make the game fair, the first place prize should be worth 4n - 13 dollars.

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Answer:

Step-by-step explanation:

To create a system of equations, write an equation to model each condition that must be satisfied in the given situation.

It is given that x represents the width of the flower bed and that y represents the area of the base of the birdbath.

Write an equation to represent the condition regarding the planting area in the flower bed. It is given that there is 35 square feet of planting area. The flower bed is 3 feet longer than the width.

x(x+3) - y = 35

Write an equation to represent the condition regarding the cost of the soil and the birdbath. The question gives that the soil will cost $5 per square foot and the birdbath will cost $18 per square foot of the base.

5x(x+3)+18y=150

Combining both of the equations gives the following system of equations.

x(x+3)-y=35

5x(x+3)+18y=150

Answer:

last choice

Step-by-step explanation:

sin(theta) is positive

tan(theta)=sin(theta)/cos(theta) is negative

If sin(theta) is positive and tan(theta) is negative, then cos(theta) is negative because +/-=-

So we are looking for the quadrant where sine is positive and cosine is negative or when x is negative and y is positive.

This is in quadrant 2 so our angle theta is between 90 and 180 degrees.

Answer:

C

Step-by-step explanation:

Given that the triangles are congruent then corresponding sides are congruent.

YZ = BC = 12 and XZ = AC = 13, thus

cosZ = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{YZ}{XZ}[/tex] = [tex]\frac{12}{13}[/tex]

The solution is, the value of cos(z) is C.) 12/13.

Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles

here, we have,

The six trigonometric functions are sin , cos , tan , cosec , sec and cot

Let the angle be θ , such that

sin θ = opposite / hypotenuse

cos θ = adjacent / hypotenuse

tan θ = opposite / adjacent

here, we have,

Given that the triangles are congruent then corresponding sides are congruent.

YZ = BC = 12

and XZ = AC = 13,

thus,

we get,

cosZ = base/hypotenuse

        =YZ/XZ  

        = 12/13

Hence, The solution is, the value of cos(z) is C.) 12/13.

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Answer:

D) 5 7/9

Work Shown:

-52/-9 = 5 7/9 = 5.7777777778

Answer:

y - 2 = 2(x - 3).

Step-by-step explanation:

The point -slope form of a line is:

y - y1 = m(x - x1) where m = the slope and (x1, y1) is a point on the line.

Here m = 2, x1 = 3 and y1 = 2. So we have the equation:

y - 2 = 2(x - 3).

Answer:

[tex]y=2x-4[/tex]

Step-by-step explanation:

Given: The line passes through (3, 2) and has a slope of  2.

To find: Point slope form of the equation.

Solution: We know that the point slope form of the line passing through [tex]\left ( x_{1},y_{1}\right )[/tex] and slope m is [tex]y-y_{1}=m\left ( x-x_{1} \right )[/tex]

Here, [tex]x_{1}=3,\ y_{1}=2, \text{and} \:\:m=2[/tex]  

So we have,

[tex]y-2=2(x-3)[/tex]

[tex]y-2=2x-6[/tex]

[tex]y=2x-4[/tex]

Hence, the point slope form of the line is [tex]y=2x-4[/tex].

The steps are shown below. From here, we can write:

[tex]\frac{x^3-2x^2-14x+3}{x+3}=x^2-5x+1+\frac{0}{x+3} \\ \\ \therefore \boxed{\frac{x^3-2x^2-14x+3}{x+3}=x^2-5x+1}[/tex]

Answer:

x^2-5x+1

Step-by-step explanation:

this is correct

Answer:

Part 1) The vertex is the point (-83,-9)

Part 2) The focus is the point (-82.75,-9)

Part 3) The directrix is [tex]x=-83.25[/tex]

Step-by-step explanation:

step 1

Find the vertex

we know that

The equation of a horizontal parabola in the standard form is equal to

[tex](y - k)^{2}=4p(x - h)[/tex]

where

p≠ 0.

(h,k) is the vertex

(h + p, k) is the focus

x=h-p is the directrix

In this problem we have

[tex]x=y^{2} +18y-2[/tex]

Convert to standard form

[tex]x+2=y^{2} +18y[/tex]

[tex]x+2+81=y^{2} +18y+81[/tex]

[tex]x+83=(y+9)^{2}[/tex]

so

This is a horizontal parabola open to the right

(h,k) is the point (-83,-9)

so

The vertex is the point (-83,-9)

step 2

we have

[tex]x+83=(y+9)^{2}[/tex]

Find the value of p

[tex]4p=1[/tex]

[tex]p=1/4[/tex]

Find the focus

(h + p, k) is the focus

substitute

(-83+1/4,-9)

The focus is the point (-82.75,-9)

step 3

Find the directrix

The directrix of a horizontal parabola is

[tex]x=h-p[/tex]

substitute

[tex]x=-83-1/4[/tex]

[tex]x=-83.25[/tex]

Answer:

Step-by-step explanation:

[tex]z-2+8=24\\\\z+(-2+8)=24\\\\z+6=24\qquad\text{subtract 6 from both sides}\\\\z+6-6=24-6\\\\z=18[/tex]

Answer:

Z = 18

Step-by-step explanation:

Z- 2 + 8 = 24

Combine like terms

Z +6 = 24

Subtract 6 from each side

Z+6-6 =24-6

Z = 18

The equations are as follows where x represents the number of minutes the cell phone is used.

For plan one: Total cost = $20 + $0.15x

For plan two: Total cost = $35 + $0.10x

For both the costs to be the same, we need to use the cell phone for

300 minutes.

Equations are relations showing the value of one quantity related to another quantity when it can change. The changing value is the variable.

We are informed that one cell phone plan charges $20 per month plus $0.15 per minute used. A second cell phone plan charges $35 per month plus $0.10 per minute used.

We are asked to write and solve an equation to find the number of minutes you must talk to have the same cost for both calling plans.

Let the number of minutes the cell phone is used be x minutes.

Now we solve for equations for both plans in the following way:-

Plan one:

Charges $20 per month plus $0.15 per minute used.

When the use is for x minutes, the additional charge = $0.15*x = $0.15x

∴ Total cost = Fixed cost + Additional cost

or, Total cost = $20 + $0.15x.

Plan two:

Charges $35 per month plus $0.10 per minute used.

When the use is for x minutes, the additional charge = $0.10*x = $0.10x

∴ Total cost = Fixed cost + Additional cost

or, Total cost = $35 + $0.10x.

We are asked to find the number of minutes used so that the costs in both the plans are equal. To find this we equate the equation of total costs in both the cases to get:

$20 + $0.15x = $35 + $0.10x.

Subtracting ($20 + $0.10x) from both sides of the equation, we get

$20 + $0.15x - ($20 + $0.10x) = $35 + $0.10x - ($20 + $0.10x).

or, $20 + $0.15x - $20 - $0.10x = $35 + $0.10x - $20 - $0.10x.

or, $0.05x = $15

Dividing both sides of the equation by $0.05, we get

$0.05x/$0.05 = $10/$0.05

or, x = 300.

∴ We must talk for 300 minutes for both the plans to cost the same to us.

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So the x-axis represents the age of the car and the y represents the value of the car

As you can see as the x values increase the y value decreases

This means that the answer is C. As the age of the car increases the value of the car decreases

Hope this helped!

~Just a girl in love with Shawn Mendes

Answer:

3

Step-by-step explanation:

Answer:

the one on the bottom left

Step-by-step explanation:

Note that the cube on the bottom left is composed of

4 × 4 × 4 = 64 ← unit cubes

Thus the volume of the cube = 64 units³

The volume of a cube = s³ ← where s is the side length

Thus s³ = 64

To find s given the volume take the cube root of both sides, that is

s = [tex]\sqrt[3]{64}[/tex] = 4

Answer:

C

Step-by-step explanation:

Girls - 28-12 = 16

16:12 = 4:3 - so answer choice C

We know that out of the 28 students 12 of them are boys. To find how many girls there are subtract 12 from 28

28 - 12 = 16

That means that there are 16 girls in the class

Now you need a ratio of girls : boys so...

16 : 12

This can be further simplified to the following...

4 : 3 (C)

This means that for every four girls there are 3 boys

Hope this helped!

~Just a girl in love with Shawn Mendes

Answer:

maybe

[tex] y = \frac{1}{2} x + 0.5[/tex]

Answer:

x - 2y = - 1

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Obtain the equation in slope- intercept form

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 3, - 1) and (x₂, y₂ ) = (3, 2) ← 2 points on the line

m = [tex]\frac{2+1}{3+3}[/tex] = [tex]\frac{3}{6}[/tex] = [tex]\frac{1}{2}[/tex]

y = [tex]\frac{1}{2}[/tex] x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (3, 2), then

2 = [tex]\frac{3}{2}[/tex] + c ⇒ c = [tex]\frac{1}{2}[/tex]

y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{1}{2}[/tex] ← in slope- intercept form

Multiply all terms by 2

2y = x + 1 ( subtract 2y from both sides )

0 = x - 2y + 1 ( subtract 1 from both sides )

- 1 = x - 2y , that is

x - 2y = - 1 ← in standard form

Answer:

1.25

Step-by-step explanation:

Calculate the scale factor as the ratio of the corresponding sides of the image to the original.

here the image is 6.25 and the original is 5

scale factor = [tex]\frac{6.25}{5}[/tex] = 1.25

This represents an enlargement