The Smith family drove 1580 miles during their seven-day vacation in the rented recreational vehicle, calculated by subtracting the flat rental fee from the total cost, and then dividing by the cost per mile.
Explanation:This question centers on simple algebra. To calculate the number of miles driven, you need to first understand that the total cost consists of a flat rental fee and the cost per mile driven. First, we take the total cost, $1350, and subtract the flat fee of $560 from it. This leaves us with $790.
We then divide that $790 by the price per mile, which is $0.50. The calculation would then be as follows: $790 ÷ $0.50 = 1580 miles. Therefore, the Smith family drove 1580 miles during their seven-day vacation in the recreational vehicle.
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Hey Is anyone really good at math? I need help with this one.
What is the average of 96, 49 , 68 and 75?
Please Help
Which rational number equals 0.6 with bar over 6?
Select one:
a. 2 over 3
b. 6 over 10
c. 4 over 5
d. 6 over 5
3 4 6 9 1 3 1 8 2 4 what would be the next number
What two numbers multiply to -30 and add to 1?
The products of two numbers involves multiplying them.
The two numbers are -5 and 6
Let the numbers be x and y.
So, we have:
[tex]\mathbf{x \times y = -30}[/tex]
[tex]\mathbf{x + y = 1}[/tex]
Make x the subject in [tex]\mathbf{x + y = 1}[/tex]
[tex]\mathbf{x = 1 - y}[/tex]
Substitute [tex]\mathbf{x = 1 - y}[/tex] in [tex]\mathbf{x \times y = -30}[/tex]
[tex]\mathbf{(1 - y)y = -30}[/tex]
Expand
[tex]\mathbf{y - y^2 = -30}[/tex]
So, we have:
[tex]\mathbf{y^2 -y - 30 = 0}[/tex]
Expand
[tex]\mathbf{y^2 -6y + 5y - 30 = 0}[/tex]
Factorize
[tex]\mathbf{y(y -6) + 5(y - 6) = 0}[/tex]
Factor out y - 6
[tex]\mathbf{(y + 5) (y - 6) = 0}[/tex]
Solve for y
[tex]\mathbf{y = -5\ and\ 6}[/tex]
Hence, the two numbers are -5 and 6
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1. A log cabin in the shape of a rectangular prism is modeled using a scale of 1 to 0.5 meter. If the model is 14x19x11 centimeters, what is the volume of the actual log cabin?
a) 182.875 m^3
b) 365.75 m^3
c) 548. 625 m^3
d) 1463 m^3
2. A circle graph below represents a family's monthly budget. If the total monthly income is $2000, how much money is spent on food?
(graph) food=35% other=25% housing=40%
a) $700
b) $800
c) $350
d) $400
3. solve the equation. round the result to two decimal places.
4.8x-1.3=1.7
a) 0.83
b) -1.80
c) 0.63
d) 0.08
If the sum of the interior angles in a regular polygon is 1440°, then what kind of polygon is it?
The function p(x)= -2000x^2 + 16000x - 5000 models the monthly profit P of a smoothie company, where x represents the price per smoothie. Identify the price range that will generate a monthly profit of at least 25,000?
a. between $3 and $5, inclusive
b. less than $3
c. more than $5
Answer: Between $3 and $5, inclusive
Step-by-step explanation:
Rachel drove 804 miles in 12 hours. at the same rate, how long would it take her to drive 335 miles?
The area of a square with sides of length s is given by a = s2. find the rate of change of the area with respect to s when s = 4 meters.
PLEASE HELP MEEHH...
Divide. −3/8 ÷ −6/7
In fraction form please.
8x = 2y + 5 3x = y + 7
Solve the system of equations by substitution.
(-9/2, -41/2), (-1, -9/2), no solution, coincident
PLEASE HELP!!!!
Suppose the tree diagram below represents all the students in a high school and that one of these students were chosen at random. If the student is known to be a girl, what is the probability that the student is right-handed?
A. 1/4
B. 3/4
C. 5/6
D. 1/6
The Answer is C 5/6
250/300 reduced and simplified is 5/6
Answer:
The probability that the student is right-handed given that the student is a girl is:
[tex]\dfrac{5}{6}[/tex]
Step-by-step explanation:
From the tree diagram we have to find the probability that the students is right handed given that the student is a girl.
Let A denote the event that the student is a girl.
and B denote the event that the student is right handed.
We are asked to find the probability:
P(B|A)
We know that P(B|A) is calculated as:
[tex]P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}[/tex]
There are a total of 500 students.
Out of which 300 are girls.
( i.e. [tex]P(A)=\dfrac{300}{500}=\dfrac{3}{5}[/tex] )
and out of 300 girls 250 are right handed.
( i.e. [tex]P(A\bigcap B)=\dfrac{250}{500}=\dfrac{1}{2}[/tex] )
Hence,
[tex]P(B|A)=\dfrac{\dfrac{1}{2}}{\dfrac{3}{5}}\\\\\\P(B|A)=\dfrac{5}{6}[/tex]
Hence,The probability that the student is right-handed given that the student is a girl is:
[tex]\dfrac{5}{6}[/tex]
PLZ Help fast. It's Pre Calculus. This is the only day i get to spend time with my baby sister. please help fast. WILL MARK BRAINLIEST.
Which of the following is a root of the polynomial shown below? Look at the graph of the function and find the solutions.
f(x)=x^3+2x^2-x-2
a.1
b.0
c.3
d.2
Which of the following represents the set of possible rational roots for the polynomial shown below? This question is a review from Algebra 2. Remember that possible rational roots take the form of p/q. Where p is a factor of the constant and q is a factor of the leading coefficient.
2x^3+5x^2-8x-20=0
Answer:
Step-by-step explanation:
Given is the polynomials as
1) [tex]f(x) = x^3+2x^2-x-2[/tex]
The graph of this function has x intercepts as
-2, -1 and 0
Since f(x) =0 has solutions equivalent to x intercepts we see that the roots are
-2,-1 and 0
2) Given is a polynomial as
[tex]f(x) = 2x^3+5x^2-8x-20 =0[/tex]
Using rational roots theorem we find that
the roots possible are ±1.±2,±4,±5,±10,±20,±1/2,±5/2
Using remainder theorem we see that
f(2) =f(-2)=0
By using division, we find that the other factor is 2x+5
Hence roots are 2,-2, -2.5
joy is planning to purchase a sweater that costs 30$ dollars at her local department store. The sweaters are on sale for for 20% off.
Which steps are needed to find the sale price of the sweater in words?
PLEASE HELP! ill give you brainliest
Which answers are examples of the Law of Detachment? Select each correct answer.
If two angles are linear pairs, the angles are supplementary. The two angles are linear pairs. Therefore, the angles are supplementary.
If an object is a square, it is a parallelogram. The object is a square. The object is a parallelogram.
If it is snowing, the play will be cancelled. It is snowing. Therefore, the play is cancelled.
If it is snowing, the play will be cancelled. If the play is cancelled, the theater will refund the cost of admission. Therefore, if it is snowing, the theater will refund the cost of admission to the play.
Answers:
A. If two angles are linear pairs, the angles are supplementary. The two angles are linear pairs. Therefore, the angles are supplementary.
B. If an object is a square, it is a parallelogram. The object is a square. The object is a parallelogram.
C. If it is snowing, the play will be cancelled. It is snowing. Therefore, the play is cancelled.
These are right.
Answer:
Law of detachment:
Statement 1: If a, then b
Statement 2: a
Conclusion: b
(A)
1. If two angles are linear pairs, then the angles are supplementary.
2. The two angles are linear pairs.
Let a be the statement " two angles are linear pairs"
let b be the statement "the angles are supplementary"
then, 1 and 2 can be written as;
1. if a , then b
2. a
So, by the law of detachment we can deduce that b is true.
i.e, The angles are supplementary.
(B)
1. If an object is a square, then it is a parallelogram.
2. The object is a square.
Let a be the statement " an object is a square"
let b be the statement "The object is a square"
then, 1 and 2 can be written as;
1. if a , then b
2. a
So, by the law of detachment we can deduce that b is true.
i.e, The object is a parallelogram.
(C)
1. If it is snowing, then the play will be cancelled.
2. It is snowing.
Let a be the statement "it is snowing"
let b be the statement "the play will be cancelled"
then, 1 and 2 can be written as;
1. if a , then b
2. a
So, by the law of detachment we can deduce that b is true.
i.e, The play is cancelled.
Only option A, B and C are examples of the Law of Detachment.
Diane works mowing lawns and babysitting. she earns $8.50 an hour for mowing and $7.10 an hour for babysitting. how much will she earn for 5 hours of mowing and 7 hours of babysitting?
Naomi went on a 6.5-mile hike. Im the morning, she hiked 1.75 miles, rested, and then hiked 2.4 more miles. She completed the hike in the afternoon. How much farther did she hike in the morning than the afternoon?
Let f (x) = 2x - 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following: f (g (x)) and h (f (x))
Please help having a lot of trouble :(
There is 4 inches of water in the swimming pool before the day started. The rainfall is falling at 3 inches per minute.
a. Write an inequality for how much water is in the pool, let x represent the minutes.
b. Graph the Inequality
(could help if you give me the graph points)
the two way table represents data from a survey asking schoolchildren whether
In
kite WXYZ, m∠ZWY=43°and m∠XYW=12°.
What is m∠WXY?
Enter your answer in the box.
photo:
Answer: [tex]\angle WXY=125^{\circ}[/tex]
Explanation: Since, a kite has one pair of congruent angles and its main diagonal bisects its opposite angles.
Therefore, According to the given figure,
[tex]\angle WXY=\angle WZY[/tex]
And, WY is the main diagonal which bisects angles ZWX and XYZ.
So, [tex]\angle ZWX =2\times \angle ZWY= 2\times 43^{\circ}=86^{\circ}[/tex]
And, [tex]\angle XYZ =2\times \angle XYW= 2\times 12^{\circ}=24^{\circ}[/tex]
Since, Sum of all angles of a quadrilateral is equal to [tex]360^{\circ}[/tex]
Therefore, [tex]\angle WXY+\angle WZY+\angle XYZ+\angle ZWX=360^{\circ}[/tex]
⇒[tex]2\times \angle WXY+ 86^{\circ}+24^{\circ}=360^{\circ}[/tex]
⇒[tex]2\times \angle WXY=360^{\circ}-110^{\circ}=250{\circ}[/tex]
⇒ [tex]\angle WXY=125^{\circ}[/tex]
A box contains 10 transistors, 4 of which are defective. If 3 are sold at random, find the probability that exactly 1 are defective.
Has grades of 71 and 87 on her first two algebra tests. if she wants an average of at least 75, what possible scores can she make on her third test
PLEASE HELP WITH THIS
Sawyer has triple the number of Hot Wheels cars as Fisher. If Fisher has x number of cars, how many does Sawyer have?
A) x + 3
B) 3x
C) 3/x
D) 2x
fisher has x cars
sawyer has 3 times as many so he has 3x cars
Answer is B
−7x−50≤−1 AND−6x+70>−2
Answer:
[tex]-7\geq x<12[/tex] and [tex][-7,12)[/tex] in interval notation.
Step-by-step explanation:
We have been given a compound inequality [tex]-7x-50\leq -1\text{ and }-6x+70>-2[/tex]. We are supposed to find the solution of our given inequality.
First of all, we will solve both inequalities separately, then we will combine both solution merging overlapping intervals.
[tex]-7x-50\leq -1[/tex]
[tex]-7x-50+50\leq -1+50[/tex]
[tex]-7x\leq 49[/tex]
Dividing by negative number, flip the inequality sign:
[tex]\frac{-7x}{-7}\geq \frac{49}{-7}[/tex]
[tex]x\geq -7[/tex]
[tex]-6x+70>-2[/tex]
[tex]-6x+70-70>-2-70[/tex]
[tex]-6x>-72[/tex]
Dividing by negative number, flip the inequality sign:
[tex]\frac{-6x}{-6}<\frac{-72}{-6}[/tex]
[tex]x<12[/tex]
Upon merging both intervals, we will get:
[tex]-7\geq x<12[/tex]
Therefore, the solution for our given inequality would be [tex]-7\geq x<12[/tex] and [tex][-7,12)[/tex] in interval notation.
If 9 is a factor of 63, then what other number must also be a factor of 63? Explain your reasoning.
A wise man once said 400 reduced by 3 times my age is 112. what is his age
Sound a measures 25 decibels and sound b is 8 times as loud as sound
a. what is the decibel rating of sound b to the nearest integer?
Final answer:
To find the decibel rating of sound b, we calculate the decibel difference between sound a and sound b, which is 9.031 decibels. Adding this to the decibel rating of sound a gives us an approximate decibel rating of 34 for sound b.
Explanation:
To find the decibel rating of sound b, we need to determine how many decibels louder it is compared to sound a. We know that sound b is 8 times as loud as sound a, so we can use the formula for decibel difference:
Decibel difference = 10 * log10(intensity ratio)
Since sound b is 8 times as loud as sound a, the intensity ratio is 8. Plugging this into the formula gives:
Decibel difference = 10 * log10(8) = 10 * 0.9031 = 9.031 decibels
To find the decibel rating of sound b, we add the decibel difference to the decibel rating of sound a:
Decibel rating of sound b = Decibel rating of sound a + Decibel difference = 25 + 9.031 ≈ 34 decibels
Forty-eight divided by (two plus six)