The sea water has 8.0x10^-1 cg of element strontium. Assuming that all strontium could be recovered, how many grams of strontium could be obtained from 9.84x10^8 cubic meter of seawater. Assuming the density of sea water is 1.0g/mL.

Answer:

It does not dissolve readily.

Explanation:

The statement which best describes the path of the gas particles in the sample of gas is the straight path which changes upon collisions with other particles.

Gaseous state is one of the state of matter in which particles are present at great distance from each other with random arrangement.

In a sample of gas, firstly gases particles will move in a straight line till then collision with another gas particle takes place. After the collision path of the gas particle changes and keeps on changes with the additional collision.

Hence firstly gas particles are move in a straight line.

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Answer:

V₂ = 648.53 mL

Explanation:

Given data:

Initial volume of gas = 490. mL

Initial temperature = -35°C (-35 + 273 = 238 k)

Final temperature = 42°C =  (42+273 = 315 k)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 490 mL × 315 K / 238 k

V₂ = 154350 mL.K / 238 K

V₂ = 648.53 mL

Answer:

It will decrease

Explanation:

As the snowball gets bigger, the kinetic energy of the body begins to reduce appreciably.

The condition given in this problem is constant speed.

At constant speed, the snowball is not accelerating and there is no external force acting appreciably on the ball.

   Now, we know that;

        K.E = [tex]\frac{1}{2}[/tex] m v²

m is the mass of the ball

v is the velocity of the ball

  In this scenario, the velocity of the ball is constant and not changing. But the mass of the ball begins to increase, eventually, the kinetic energy of the ball will reduce.

The increasing mass without an appreciable increase in velocity will bring the body to rest as a result of increase inertia of the body.

Answer:

mass = 25.03 g

Explanation:

Given data:

Initial temperature = 67.5°C

Final temperature = 25.2°C

Heat released = -4425 j

Mass of water = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 25.2°C - 67.5°C

ΔT = -42.3°C

Specific heat of water = 4.18 j/g.°C

Q = m.c. ΔT

-4425 j = m × 4.18 j/g.°C × -42.3°C

-4425 j = m × -176.81 j/g

m = -4425 j /  -176.81 j/g

m = 25.03 g

The mass of the sample of water is approximately 250 grams.

To find the mass of the water sample, we can use the formula for the heat released or absorbed by a substance undergoing a temperature change:

[tex]\[ q = m \cdot c \cdot \Delta T \][/tex]

where:

[tex]- \( q \)[/tex] is the heat released or absorbed (in joules),

[tex]- \( m \)[/tex] is the mass of the substance (in grams),

[tex]- \( c \)[/tex] is the specific heat capacity of the substance (in joules per gram per degree Celsius),

[tex]- \( \Delta T \)[/tex] is the change in temperature (in degrees Celsius).

For water, the specific heat capacity [tex]\( c \)[/tex] is approximately [tex]\( 4.184 \, \text{J/g}^\circ \text{C} \)[/tex].

Given:

[tex]- \( q = -4425 \, \text{J} \)[/tex] (the negative sign indicates heat is released),

[tex]- \( \Delta T = 67.5^\circ \text{C} - 25.2^\circ \text{C} = 42.3^\circ \text{C} \),[/tex]

[tex]- \( c = 4.184 \, \text{J/g}^\circ \text{C} \).[/tex]

We can rearrange the formula to solve for [tex]\( m \)[/tex]:

[tex]\[ m = \frac{q}{c \cdot \Delta T} \][/tex]

Now, plug in the values:

[tex]\[ m = \frac{-4425 \, \text{J}}{4.184 \, \text{J/g}^\circ \text{C} \cdot 42.3^\circ \text{C}} \] \[ m = \frac{-4425}{4.184 \times 42.3} \] \[ m \approx \frac{-4425}{177.3172} \] \[ m \approx -25 \][/tex]

Since mass cannot be negative, we take the absolute value of the result:

[tex]\[ m \approx 250 \, \text{g} \][/tex]

Therefore, the mass of the sample of water is approximately 250 grams.

Answer:

A. Air

Explanation:

Lignin which has a glucos link is a unique hydrocarbon comprising 8-20% of the cell wall of plants. It is a complex, dense, amorphous, secondary cell wall polymer found in the trachea elements and sclerenchyma of terrestrial plants.

Since plant absorbs carbon dioxide from air to form glucose and hence, starch; That is the source of carbon to build other macromolecules.

Water which it absorbs from soil is not of carbon content neither do plant take in microorganisms.

Plants obtain the majority of the carbon necessary for building these structural molecules from air

General, plants that have a very strong internal structure can grow larger than other plants because their structure can support their size. They absorbs carbon dioxide from air to form those carbon-containing molecules

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Answer:

it is option b

Explanation:

this is because neutralisation reaction takes place only between a base and an acid.

now, in OPTION A it is a neutral and base

OPTIONB  it is acid and base

OPTION C both are base

OPTION D  IT IS NOT POSSIBLE

A neutralization reaction involves an acid and a base, with pH levels generally below and above 7 respectively. To identify a combination that would result in such a reaction, we require an acidic and a basic substance. Thus, the correct combination would be option B: a substance with a pH of 2 (acid) and a substance with a pH of 10 (base).

The subject in question pertains to neutralization reactions in chemistry. A neutralization reaction typically involves a strong acid and a strong base reacting to form water and a type of salt. The pH scale measures how acidic or basic a solution is, and ranges from 0 to 14. If we remember that a pH of 7 is neutral, acids are typically represented with a pH less than 7, and bases are represented with a pH greater than 7, we can use that to find our answer.

Based on these principles, options A and C wouldn't yield a neutralization reaction because they both involve a neutral or basic substance with another base. Option D does not guarantee a neutralization reaction either as the two solutions could be both acidic or basic. Therefore, the correct choice would be option B: a substance with a pH of 2 (which would be an acid) and a substance with a pH of 10 (which would be a base). The acid-base combination would result in a neutralization reaction.

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Answer:

Use Hooke's law

Explanation:

Answer:

101333.33mmHg

Explanation:

The following were obtained from the question:

P1 = at stp = 760mmHg

V1 = 400.0cu.ft

V2 = 3cu.ft

P2 =?

Using Boyle's law equation, we obtained:

P1V1 = P2V2

760 x 400 = P2 x 3

Divide both side by the 3

P2 = (760 x 400) /3

P2 = 101333.33mmHg

The gas must b compressed to a pressure of 101333.33mmHg

Gallium, because is a post-transition metal

Final answer:

The molar mass of Strontium nitride (Sr3N2) is calculated by multiplying the molar masses of strontium and nitrogen by their respective number of atoms in the formula and adding the products together, resulting in 290.88 g/mol.

Explanation:

To find the molar mass of Strontium nitride (Sr3N2), you must first determine the molar masses of strontium (Sr) and nitrogen (N) from the periodic table. The molar mass of strontium is 87.62 g/mol. Since there are three strontium atoms in Sr3N2, you would multiply 87.62 g/mol by 3. The molar mass of nitrogen is 14.01 g/mol, and there are two nitrogen atoms in Sr3N2, so multiply 14.01 g/mol by 2.

Then you add the molar masses of strontium and nitrogen together:

Finally, sum these values to find the molar mass of Sr3N2:

Molar mass of Sr3N2 = 262.86 g/mol + 28.02 g/mol = 290.88 g/mol.

Answer:

1600/27 cubic yards

Explanation:

Convert each of the dimensions into yards, getting 10/3, 20/3, and 8/3. Multiply them all to get 1600/27

The pressure exerted by 0.57 moles of CO2 at a temperature of 25°C and a volume of 500 ml is 28 atm.

Explanation:

According to ideal gas law,

                                      PV = nRT

where P represents the pressure of a gas,

          V  represents the volume of a gas,

          n represents the number of moles,

          R represents the gas constant = 0.0821 L atm / mol K.

          T represents the temperature of a gas.

Given V = 500 ml = 0.5 l,           T = 25°C = 298 K,   n = 0.57 mol

                                        PV = nRT

                                           P = nRT / V

                                              = (0.57 [tex]\times[/tex] 0.0821 [tex]\times[/tex] 298) / 0.5

                                          P = 28 atm.

The pressure of a gas is 28 atm.

Final answer:

Using the ideal gas law, the pressure exerted by 0.57 moles of CO₂ gas at a temperature of 25°C and a volume of 500 mL is calculated to be 28.56 atm.

Explanation:

To calculate the pressure exerted by 0.57 moles of CO₂ gas at a temperature of 25°C (which is 298K when converted to Kelvin) and a volume of 500 mL (which is 0.5 L), we can use the ideal gas law equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/K·mol), and T is temperature in Kelvin.

To find the pressure (P), we rearrange the equation to P = nRT/V.

Substituting the values into the equation we get: P = (0.57 · 0.0821 · 298) / 0.5

Now, we perform the calculation:

P = (0.57 · 0.0821 · 298) / 0.5 = 28.56 atm

Therefore, the pressure exerted by the CO₂ gas is 28.56 atm.

Answer:

The nucleus

Explanation:

The nucleus controls the metabolic functions of the cell by producing mRNA which encodes for enzymes e.g. insulin. The nucleus controls the structure of the cell by transcribing DNA which encodes for structural proteins such as actin and keratin.

Answer:

3L

Explanation:

The following data were obtained from the question:

V1 (original volume) = 6L

P1 (original pressure) = 1.5 atm

P2 (new pressure) = 2 x P1 ( since the new pressure is doubled)

P2 = 2 x 1.5

P2 = 3 atm

V2 (new volume) =?

Using the Boyle's law equation P1V1 = P2V2, the new volume can be obtain as follow:

P1V1 = P2V2

1.5 x 6 = 3 x V2

Divide both side by 3

V2 = (1.5 x 6)/3

V2 = 3L

From our calculations, the new volume will be half the original volume and this will be 3L

Answer:

gravitational potential

Explanation:

The form of energy that is stored in large objects because of its position above the ground is gravitational potencial energy.

Answer: m= 22.2 g Ne

Explanation: First find the moles of Ne using Ideal Gas Law and derive for n. So from PV= nRT the mole is derived as n = PV /RT

n = PV / RT

= 1 atm ( 25 L ) / 0.0821 L.atm /

mole.K ( 273 K )

= 1.11 moles Ne

Convert it to mass using the molar mass of Neon

1.11 moles Ne x 20 g Ne / 1 mole Ne

= 22.2 g Ne

Final answer:

The mass of 25.0 L of neon at STP is approximately 22.43 grams, calculated by using the molar volume of a gas at STP and the molar mass of neon.

Explanation:

To calculate the mass of neon at standard temperature and pressure (STP), we can use the molar mass of neon and the ideal gas law. At STP, one mole of any ideal gas occupies 22.4 L. Since we are given the volume of neon gas as 25.0 L, we can calculate the number of moles (n) of neon first:

n = Volume / Molar Volume at STP
n = 25.0 L / 22.4 L mol⁻¹ = 1.116 mol

The molar mass of neon (Ne) is approximately 20.11 g mol⁻¹. We use the calculated moles to find the mass:

mass = n × molar mass
mass = 1.116 mol × 20.11 g mol⁻¹ = 22.43 g

So, the mass of 25.0 L of neon at STP is approximately 22.43 grams.

Answer:

44.01 g/mol because its basically the weight

Explanation: 12.0107 + 15.9994*2

The gfm (Gram Formula Mass) or molar mass of CO₂ (Carbon Dioxide) is calculated by adding the atomic masses of its constituents: one Carbon atom (12.01 g/mol) and two Oxygen atoms (32 g/mol). This adds up to 44.01 g/mol.

You asked for the gfm (Gram Formula Mass) of CO₂. Gram Formula Mass is another term for molar mass, which is calculated by adding up the atomic masses of all the atoms in the molecule. In the case of CO₂, we have one atom of Carbon and two atoms of Oxygen.

The atomic mass of Carbon (C) is approximately 12.01 g/mol, and that of Oxygen (O) is approximately 16.00 g/mol. Since there are two Oxygen atoms, their combined mass is 2 * 16.00 = 32.00 g/mol.

Adding the atomic masses of Carbon and Oxygen together gives us the total gfm of CO2: 12.01 g/mol (Carbon) + 32.00 g/mol (Oxygen) = 44.01 g/mol (for CO₂).

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Answer:

Electron Geometry describes arrangement is electron groups & Molecular Geometry describes the arrangement of atoms

Explanation:

The picture above better explains it, hopefully this helps :)

Answer:

1258 grams of AgN03

Explanation:

We calculate the weight of 1 mol of AgN03:

Weight 1 mol AgN03= Weight Ag + Weight N +( Weight 0)x3=108g+ 14g+16gx3=170 g/mol

1 mol----170 g AgN03

7,4mol---x= (7,4 mol x170 g AgN03)/1 mol=1258 g AgN03

Final answer:

The mass of a single water molecule is approximated to be 2.99 × 10^-23 grams, using its molar mass of 18.015 g/mol and Avogadro's number, which indicates the number of molecules in one mole.

Explanation:

To calculate the mass in grams of a single water molecule, we first look at the molar mass of water (H2O) which is 18.015 g/mol. This is because one mole (6.022 × 1023 entities) of water molecules weighs 18.015 grams. The mass of a single water molecule is therefore:
(1 molecule / 6.022 × 1023 molecules/mol) × 18.015 g/mol

Performing the calculation, we find the mass of a single water molecule to be approximately:
(1 / 6.022 × 1023) × 18.015 g

= 2.99 × 10-23 g

The mass of a single water molecule is 2.99 × 10-23 grams.

Answer :

(1) The number of cups needed are, 0.45 cups.

(2) The number of cups needed are, 5 cups.

Explanation :

Part 1:

First we have to calculate the moles of NaCl.

[tex]\text{Moles of NaCl}=\frac{\text{Mass of NaCl}}{\text{Molar mass of NaCl}}[/tex]

[tex]\text{Moles of NaCl}=\frac{520g}{58.5g/mol}=8.89mol[/tex]

Now we have to calculate the number of cups needed.

As, the number of cups needed for 8.89 mole of NaCl = 1 cups

So, the number of cups needed for 4 mole of NaCl = [tex]\frac{4}{8.89}=0.45[/tex] cups

Thus, the number of cups needed are, 0.45 cups.

Part 2:

Given:

Mass of ice cubes = 1 kg = 1000 g

Now we have to calculate the number of cups needed.

As, the number of cups needed for 220 g of ice = 1 cups

So, the number of cups needed for 1000 g of ice = [tex]\frac{1000}{220}=4.5\approx 5[/tex] cups

Thus, the number of cups needed are, 5 cups.

Answer:

Fe(s) + 3H2O2(aq) ................. FeO3(s) + 3H2O (l)​

Explanation:

Fe(s) + H2O2(aq) ----------------   FeO3(s) + H2O (l)​

To balance the equation put coefficient of 3 at back of H2O and H2O2

Fe(s) + 3H2O2(aq) ................. FeO3(s) + 3H2O (l)​

To check, the number of atoms of each element on the left must be equal to that of the right.

Element                       Left.                            Right

Fe.                               1                                    1

H.                            3×2=6                                  2×3=6

O.                           3×2 =6.                            3+3 = 6

This shows that the equation is balanced

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80 ml or 0.08 L of 1M HCl is needed to make 12 M HCl.

Explanation:

We have to use the law of Volumetric Analysis, to find the volume of the 12M solution using the volume and the molarity of the known solution of hydrochloric acid, using the law as,

V₁M₁ = V₂M₂

The above equation can be rewritten to find the volume as,

[tex]$ V2 = \frac{V1M1}{M2}[/tex]

Plugin the given values as,

[tex]$ V2 = \frac{1L\times 1M}{12 M}[/tex]  = 0.08 L or 80 ml

Answer:

18 g of gaseous water

Explanation:

We are given the equation;

2H2O (g) ----> 2H2 (g) + O2 (g) ∆H = 483.6 kJ

We are required to determine the mass of gaseous water decomposed when the amount of heat absorbed is 241.8 kJ.

From the equation;

2 moles of water are decomposed when 483.6 kJ is absorbed

Therefore;

241.8 kJ will be absorbed to decompose;

 = (2 × 241.8 kJ) ÷ 483.6 kJ

= 1 mole

But; molar mass of water is 18 g /mol

Therefore;

Mass of gaseous water decomposed is 18 g

Answer:

266.67 J/s

Explanation:

Work is said to be done when a force is applied to a certain object. It is given by the expression:

Workdone = Force × distance

However, the power (P) is the quantity or amount of work-done per time which is mathematically expressed as:

P = [tex]\frac{Workdone}{time}[/tex]

Given that:

time = 2.5 hours = (2.5 × 3600) seconds  = 9000 seconds

Force = 32 N

distance = 75 km = (75 × 1000) m = 75, 000 m

∴ Workdone = 32 × 75, 000

  Workdone  = 2,400,000 Joules

Power = [tex]\frac{2,400,000}{9000}[/tex]

Power = 266.67 J/s

Answer:

Explanation:

Given:

Force, f = 32 N

Distance, d = 75 km

1 km = 1,000 m

75 km × 1000 m/1 km

= 75,000 m

Time, t = 2.5 hours

60 secs = 1 min

60 mins = 1 hour

2.5 hours × 60 mins/ 1 hour × 60 sec/1 min

= 9,000 secs

Power = energy/time

Energy = force × distance

Power = (32 × 75,000)/9,000

= 266.67 W

Galaxy Formation.  One says that galaxies were born when vast clouds of gas and dust collapsed under their own gravitational pull, allowing stars to form. The other, which has gained strength in recent years, says the young universe contained many small "lumps" of matter, which clumped together to form galaxies.

Answer:

NaOH(aq) is a Base.

Explanation:

Those substances which give or release [tex]OH^{-}[/tex] ions in aqueous solution are called as the Arrhenius Bases.

In the aqueous solution, NaOH dissociates as follows -

[tex]NaOH^{}[/tex] ↔ [tex]Na^{+} + OH^{-}[/tex]

If it reacts with a strong acid HCl, the chemical equation for this reaction will be as follows -

[tex]HCl + NaOH = NaCl + H_{2} O[/tex]

The chemical equation that shows how NaOH is a base according to the Arrhenius definition is

NaOH(aq) → Na⁺(aq) + OH⁻(aq)

According to Arrhenius definition

Now, we will write a chemical equation that shows the dissociation of NaOH in water.

The chemical equation for the dissociation of NaOH in water is

NaOH(aq) → Na⁺(aq) + OH⁻(aq)

Since, NaOH dissociates in water to the hydroxide ion (OH⁻), then it is a base according Arrhenius definition.

Hence, the chemical equation that shows how NaOH is a base according to the Arrhenius definition is

NaOH(aq) → Na⁺(aq) + OH⁻(aq)

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Hey there!

Na + FeBr₂ → NaBr + Fe

Firstly, balance Br.

Two on the left, one on the right. Add a coefficient of 2 in front of NaBr.

Na + FeBr₂ → 2NaBr + Fe  

Next, balance Na.

One on the left, two on the right. Add a coefficient of 2 in front of Na.

2Na + FeBr₂ → 2NaBr + Fe

Lastly, balance Fe.

One on the left, one on the right. Already balanced.

Our final balanced equation:

2Na + FeBr₂ → 2NaBr + Fe

Hope this helps!

Answer:

Potential energy

Explanation:

The thrown baseball is converting from kinetic energy into potential energy. When it finally stops at a particular height, it attains its maximum potential energy at the position or point.

The more a body speeds, the higher its kinetic energy attained.

As a body comes to rest, at a height, it attains potential energy.

The body during flight decreases in kinetic energy but increases its potential energy due to gravity pulling it to rest.

The answer is Potential Energy.

Reasoning:

The thrown baseball is converting from kinetic energy into potential energy. When it finally stops at a particular height, it attains its maximum potential energy at the position or point. Potential energy is the energy at rest of body. Kinetic energy is the energy due to the motion of body. The more a body speeds, the higher its kinetic energy attained. As a body comes to rest, at a height, it attains potential energy. The body during flight decreases in kinetic energy but increases its potential energy due to gravity pulling it to rest.