Final answer:
To calculate the rate of delivery of aminophylline for a 40-lb child, convert the weight to kg and multiply by the recommended dose. Then, divide the dose by the concentration of the aminophylline solution to find the rate of delivery in mL/h.
Explanation:
To find the rate of delivery for a 40-lb child, we need to first convert the weight of the child to kilograms. Since 1 pound is equal to approximately 0.4536 kilograms, a 40-lb child would weigh 18.14 kg. The recommended maintenance dose of aminophylline for children is 1 mg/kg/h, so for a 40-lb child, the dose would be 18.14 mg/h.
To find the rate of delivery in milliliters per hour, we need to consider the concentration of the aminophylline solution. In this case, 10 mL of a 25-mg/mL solution of aminophylline is added to a 100 mL bottle of dextrose injection. This gives us a total volume of 110 mL of aminophylline solution. Since we want a rate of delivery in milliliters per hour, we divide the dose (18.14 mg/h) by the concentration (25 mg/mL) to get the volume per hour. This gives us a rate of delivery of approximately 0.74 mL/h.
Provide the most likely dominant bonding mechanism in the following solid compounds:a.CaO b. InAs c. Al2O3 d.Bronze
Answer:
CaO- ionic
InAs-covalent
Al2O3-ionic
Bronze- metallic
Explanation:
CaO and Al2O3 are mostly ionic even though the posses a little covalent character but ionic bonding is the main bonding scheme. Bronze is an alloy of two metals hence it contains a metallic bond. InAs has an electro negativity difference of 0.4 between the atoms so it is a polar covalent bond.
Which potential component in the synthetic pain relief mixture could be separated from the mixture using liquid-liquid extraction with sodium bicarbonate solution?
Answer: The acetaminophen
Explanation: Liquid-Liquid is a very important and commercial separation method used for the chemical separation and analyst of chemical mixtures. It is also known as PARTITIONING. In this technique the solute is transferred from one solvent to another of which both solvents are IMMISCIBLE OR PARTLY MISCIBLE. example in the mixture involving sodium bicarbonate,acetylsalicylic acid and acetaminophen and a binder after the binder is removed and you mix the two other components with the sodium bicarbonate the solution the acetylsalicylic acid dissolved but the acetaminophen did not meaning you could separate it from the other.
If an 900.0 g sample of radium-226 decays to 225.0 g of radium-226 remaining in 3,200 years, what is the half-life of radium-226? (3 points)
Answer:
1600 yr
Explanation:
The half-life of radium-226 is the time it takes for half of it to decay.
After one half-life, half of the original amount will remain.
After a second half-life, half of that amount will remain, and so on.
We can construct a table as follows:
[tex]\begin{array}{cccc}\textbf{No. of} &\textbf{Fraction} &\textbf{Mass}\\ \textbf{Half-lives} & \textbf{Remaining}&\textbf{Remaining/g}\\0 & 1 &900.0\\\\1 & \dfrac{1}{2} &450.0\\\\2 & \dfrac{1}{4} & 225.0\\\\3 & \dfrac{1}{8} & 112.5\\\\\end{array}[/tex]
We see that the mass will drop to 225.0 g after two half-lives.
The mass dropped to 225.0 g in 3200 yr.
If 3200 yr = 2 half lives,
1 half-life = 1600 yr
The decay curve for your sample is shown below. The mass has dropped to half its original value (450 g) after 1600 yr and to one -fourth (225.0 g) after 3200 yr.
A cable raises a mass of 158.0 kg with an acceleration of 1.8 m/s2. What force (in N) of tension is in the cable?
Answer:
Force of Tension = 1832.8 N
Explanation:
Any mass of object supported or pulled by a rope or cable is subject to a force of tension. Since the mass is raised by a cable, tension is involved.
Mathematically,
Tension = mass × gravity(9.8 m/s²)
Tension can be represented as
T = (m × g) + (m × a)
Where g is the acceleration due to gravity of the object the cable is supporting and a is the acceleration on the object the cable is supporting. And m is the mass of the object.
mass = 158 kg
a = 1.8 m/s²
g = 9.8 m/s²
T = mg + ma
T = m(g + a)
T = 158(9.8 + 1.8)
T = 158 × 11.6
T = 1832.8 N
Some organisms are not able to live in an environment where there is oxygen; these types of organisms are called obligate anaerobes. Which explanation is most plausible for how they survive without oxygen?
Obligate anaerobes survive without oxygen by using anaerobic respiration or fermentation as their energy-producing processes. They lack normal cellular defenses against oxidative stress, which makes oxygen lethal to them. For example, Clostridium perfringens bacteria are obligate anaerobes that cannot survive in the presence of oxygen and use molecules other than oxygen as terminal electron acceptors.
Explanation:Obligate anaerobes are organisms that cannot live in an environment where there is oxygen. They survive without oxygen by using anaerobic respiration or fermentation as their energy-producing processes. These organisms lack normal cellular defenses against oxidative stress, which makes oxygen lethal to them. For example, Clostridium perfringens bacteria are obligate anaerobes that cannot survive in the presence of oxygen and use molecules other than oxygen as terminal electron acceptors.
Iron has a work function (Φ) of 4.50 eV. What is the longest wavelength of light that will cause the ejection of electrons? (1 eV=1.6 × 10⁻¹⁹ J)
Answer: 2.75×10^-7m
Explanation:
The work function refers to the smallest energy a photon must posses in order to cause the ejection of electrons from a metal surface.
If Eo= hfo
Eo=work function of the metal
fo=threshold frequency
h= Plank's constant
But Eo= hf= hc/wavelength
Wavelength= hc/Eo
We convert Eo to joules
4.50×1.6×10^-19=7.2×10^-19J
c=3×10^8ms-1
h=6.6×10^-34Js
Wavelength= 3×10^8×6.6×10^-34/7.2×10^-19
2.75×10^-7m
The longest wavelength of light ejecting electrons from iron can be computed using Planck's equation, where the energy of the photon is sufficient to overcome the work function of the metal. Given the work function of iron, insert appropriate constants and solve for the wavelength.
Explanation:The calculation of the wavelength associated with the ejection of electrons involves the use of the photoelectric effect equation. The photoelectric effect equation states that the energy of a photon (E) is equal to the work function of the metal (φ), plus the kinetic energy of the ejected electron.
In this case, where kinetic energy is not considered, the energy of the incoming photon must be sufficient to overcome the work function φ. The energy of a photon (E), can be calculated using Planck's equation, E=hc/λ, where 'h' is Planck's constant, 'c' is the speed of light, and 'λ' is the wavelength of the light. In this specific problem, 'E' is equal to the work function φ of iron, which is 4.50eV (or 4.50 x 1.6 x 10^-19 Joules).
Substituting the values of 'E', 'h', and 'c' into Planck's equation, and solving for 'λ', you'll be able to compute for the longest wavelength of light capable of ejecting electrons from an iron surface.
Learn more about Photoelectric effect here:https://brainly.com/question/12732631
#SPJ3
How many atoms are in 1.00 moles of He
Answer:
1.00 mole of He have [tex]6,02x10^{23}[/tex] atoms.
Explanation:
To solve this exercise it is important to know the definition of Avogadro's number
Avogadro's number is the proportional factor that relates the molar mass of a substance to the number of elementary units (atoms, molecules, particles, ions, electrons) that constitute it and its magnitude is equal to 6.022 140 857 × 10²³
One mole of helium we have [tex]6,02x10^{23}[/tex] atoms.
One mole of helium (He) contains 6.02 × 10^23 atoms, as this is Avogadro's number, which defines the number of entities per mole of a substance.
Explanation:The student is asking how many atoms are in 1.00 moles of helium (He). To answer this question, we need to use Avogadro's number, which is 6.02 × 1023 atoms/mole. Since one mole of any substance contains Avogadro's number of atoms, molecules, or ions, we can easily calculate the number of atoms in one mole of helium.
Therefore, 1.00 mole of He contains 6.02 × 1023 atoms of He. This is a direct conversion using the definition of a mole.
As shown in the figure below, EBT solution is blue when pH is adjusted to 10. When calcium chloride is added to EBT solution, the color turns red due to the formation of EBT-metal complex. If you use your standard EDTA solution to titrate/quantify a calcium chloride (CaCl2) solution with unknown concentration, what is the color of the solution at end point?
Answer:
The color of solution at the end point will be blue.
Explanation:
EBT is used as an indicator for complexometric titrations and acts as a chelating agent. It has a blue color, in its free form, when the pH is adjusted to 10.
On the addition of CaCl₂, EBT binds with Ca(II) and gives a red color, due to its EBT-Ca (II) complex. So, the color at the start of the titration is red.
When EDTA is added, it starts to form EDTA-Ca(II) complex. Near the endpoint, it starts to replace EBT bound to Ca, because it has a higher formation constant (Kf) for its EDTA-Ca(II) complex than EBT-Ca(II) complex. The EDTA-Ca(II) has no color so the solution shows the colour of free EBT, which is blue. Hence the color at the endpoint will be blue.
Which of the following would NOT be a conversion factor for mole to mole calculations for the following reaction: 2Al 3Cl2 --> 2AlCl3?
Answer:the mole ratio gives 2:3
Explanation:
From the reaction we can see that Al has 2 moles reacting with Clothes with 3 mole which gives a product of 2 moles Aluminium chloride.
1. Summarize the rules for naming binary molecular compounds. 2. Define a binary molecular compound. 3. Describe the difference between a binary acid and an oxyacid. 4. Apply Using the system of rules for naming binary molecular compounds, describe how you would name the molecule N₂O₄. 5. Apply Write the molecular formula for each of these compounds: iodic acid, disulfur trioxide, dinitrogen monoxide, and hydrofluoric acid.
Answer:
Explanation:
Question 1.
1. Name in same order as formula.
2. Drop the last syllable (or two) of last element and add -ide.
3. Add prefixes to each element to show how many of each.
Question 2.
A binary molecular compound is a substance composed of exactly two different elements, that cannot be simplified further by chemical means. Examples of binary compounds include H2O, H2S, and NH3.
Question 3.
The Major difference between binary acids and oxyacids is that oxyacids contain at least one oxygen atom in the molecule and binary acids do not contain oxygen. Binary acids have hydrogen and another non-metal element in the molecule. Examples of oxyacids are H2SO4, HNO3 etc. Examples of binary acids are HCl, HBr etc.
Question 4.
Step 1 - Nitrogen Oxygen
Step 2 - Nitrogen Oxide
Step 3 - Dinitrogen Tetraoxide
Question 5.
Iodic Acid - HIO3
Disulphur Trioxide - S2O3
Dinitrogen Monoxide - N2O
HydroFluoric Acid - HF
1. Binary molecular compounds are named using the more metallic element followed by the more nonmetallic element with -ide as the suffix, with prefixes indicating the number of atoms of each element.
2. A binary molecular compound is a compound consisting of two nonmetallic elements.
3. A binary acid contains hydrogen and one other element, while an oxyacid contains hydrogen, oxygen, and one other element.
4. The molecule N₂O₄ is named dinitrogen tetroxide using the system of rules for naming binary molecular compounds.
5. The molecular formula for each compound is: iodic acid (HIO₃), disulfur trioxide (S₂O₆), dinitrogen monoxide (N₂O), hydrofluoric acid (HF).
Binary molecular compounds are named using a naming method similar to that used for ionic compounds. The name of the more metallic element is written first, followed by the name of the more nonmetallic element with its ending changed to -ide. Prefixes are used to specify the numbers of atoms of each element in the molecule.
A binary molecular compound is a compound that consists of two nonmetallic elements bonded together.
A binary acid is an acid that contains hydrogen and one other element. An oxyacid is an acid that contains hydrogen, oxygen, and one other element. The names of binary acids are formed by using the prefix hydro- and changing the -ide suffix to -ic, while the names of oxyacids are formed by changing the ending of the anion (-ate to -ic and -ite to -ous), and adding "acid".
To name the molecule N₂O₄, we first identify the more metallic element, which is nitrogen. The more nonmetallic element is oxygen. Since the molecule contains two nitrogen atoms and four oxygen atoms, we use the prefix di- for nitrogen and tetra- for oxygen. Therefore, the name of the molecule is dinitrogen tetroxide.
- Iodic acid: HIO₃
- Disulfur trioxide: S₂O₆
- Dinitrogen monoxide: N₂O
- Hydrofluoric acid: HF
https://brainly.com/question/33516951
#SPJ3
Given the reaction: 2 Na(s) + Cl 2(g) → 2 NaCl(s) The conversion factor for chlorine gas to sodium chloride is: 1 mol Cl 2 ≡ 2 mol NaCl. True or false?
Answer:
True
Explanation:
From the equation of reaction, one mole of chlorine gas molecule was consumed to produce two moles of sodium chloride
Answer: True
Explanation: The mole to mole ration is for 1 mole of Cl2 to produces 2 moles of NaCl. So the stoichiometric ratio is 1 is to 2.
When the procedure calls for making a more dilute solution of an acid, or mixing an acid with other solutions, what is the correct order of steps?
Explanation:
Whenever we need to make a dilute solution of an acid then it is necessary to add water or non-acidic component into the acid first. This is because addition of water or non-acidic component directly into the acid could be highly exothermic in nature.
As a result, the acid can splutter and can cause burning of skin and other serious damage.
So, in order to avoid such type of damage the addition of water or non-acidic component into the acid actually helps to minimize the heat generated.
Thus, we can conclude that correct order of steps for making a more dilute solution of an acid is that either add all of the water or non-acid component first, or add a significant portion, before adding the acid to the mixture.
The complete combustion (reaction with oxygen) of liquid octane (C8H18) a component typical of the hydrocarbons in gasoline, produces carbon dioxide gas and water vapor. What is the coefficient of octane in the balanced equation for the reaction? (Balance the equation with the smallest possible whole number coefficients.) A.2 B.15 C.4 D3 E. 24 F. 20 G. 25
Answer:
The answer to your question is letter A. 2
Explanation:
Data
Octane = C₈H₁₈
Oxygen = O₂
Carbon dioxide = CO₂
Water = H₂O
Reaction
C₈H₁₈ + O₂ ⇒ CO₂ + H₂O
Reactants Elements Products
8 C 1
18 H 2
2 O 3
This reaction is unbalanced
C₈H₁₈ + 25/2O₂ ⇒ 8CO₂ + 9H₂O
Reactants Elements Products
8 C 8
18 H 18
25 O 25
Multiply the reaction by 2
2C₈H₁₈ + 25O₂ ⇒ 16CO₂ + 18H₂O
Reactants Elements Products
16 C 16
36 H 36
50 O 50
Now, the reaction is balanced
How many valid electron dot formulas—having the same number of electron pairs for a molecule or ion—can be written when a resonance structure occurs?
Answer:
2 or more
Explanation:
There are 2 or more valid electron dot formulas—having the same number of electron pairs for a molecule or ion—can be written when a resonance structure occur as we know that Sharing of electrons takes place so that atoms achieve noble gas configurations. So, How is it that an electron dot arrangement reflects a covalent bond? An electron dot arrangement represents a pair of dots with the mutual electrons of a covalent bond. A great energy of dissociation from bonds leads to a solid covalent bond.
Answer: 2 or more
Explanation:
The atomic number of calcium (Ca) is 20, and it's mass number is 40. What is true about the subatomic particles that make up a neutral atom of calcium?
A) It has 20 protons, 20 neutrons and 20 electrons.
B) the total number of subatomic particles in Ca is 40.
C) The number of electrons cannot be determined from the information given.
Answer: A. It has 20 protons, 20 neutrons and 20 electrons
Explanation: The atomic number of an atom is equal to the number of protons inside the nucleus. In a neutral atom the number of electrons and protons are equal.
The number of neutrons can be determined by this formula
Atomic Mass - Atomic Number = n
40 - 20 = 20 neutrons
Protons = 20
Electrons = 20
Neutrons = 20
A 547-mLmL sample of unknown HCl HCl solution reacts completely with Na2CO3Na2CO3 to form 17.1 gg CO2CO2. What was the concentration of the HClHCl solution?
Answer:
the required concentration is 1.52 M
2 HCl + Na2CO3 -----> CO2 + H2O + NaCl
2 moles HCl reacts to form 1 mole of CO2 .
no. of moles of CO2 = 20.1/ 44.1 = 0.455
no. of moles of HCl = 0.455* 2 = 0.911 mole (molar ratio =2 from equation)
con. of HCl =no. of moles/volume in liter
=0.911/ 0.597 = 1.52 M
Final answer:
To find the concentration of an HCl solution from the mass of CO₂ produced in a reaction, we first calculate the moles of CO₂ and then use the molar ratio between HCl and CO₂ to find the moles of HCl. Finally, we find the concentration by dividing the moles of HCl by the volume of the solution in liters, resulting in a concentration of 0.7102 M for the HCl solution.
Explanation:
To determine the concentration of the HCl solution, we must first calculate the number of moles of CO₂ produced from the given mass. CO₂ has a molar mass of 44.01 g/mol, so the number of moles of CO₂ can be calculated as follows:
Number of moles of CO₂ = 17.1 g CO2 ÷ 44.01 g/mol = 0.3885 mol CO₂
According to the balanced chemical equation for the reaction between HCl and Na₂CO₃:
HCl(aq) + Na₂CO₃(aq) → H₂O(l) + CO₂(g) + 2NaCl(aq)
We can see there is a 1:1 molar ratio between HCl and CO₂. This means the number of moles of HCl is also 0.3885 mol. Now we can calculate the concentration of HCl in the 547 mL solution by using the number of moles and the volume in liters (0.547 L):
Concentration of HCl = Moles of HCl ÷ Volume of solution in liters
Concentration of HCl = 0.3885 mol ÷ 0.547 L = 0.7102 M
Therefore, the concentration of the HCl solution is 0.7102 M.
The acid-dissociation constant, Ka, for benzoic acid is 6.5 × 10-5. Which will you use to calculate the base-dissociation constant, Kb, for the conjugate base of benzoic acid?
Answer:
The base-dissociation constant, Kb,for the conjugate base of benzoic acid is :
[tex]K_{b}=1.54\times 10^{-10}}[/tex]
Explanation:
The product of acid dissociation constant and base dissociation constant is equal to the water dissociation constant.The general formula for the reaction is:
[tex]K_{w}=K_{a}K_{b}[/tex]
For the acid dissociation reaction:
[tex]HA + H_{2}O\rightleftharpoons H^{+}+A^{-}[/tex]
The conjugate base for the acid is A-
The acid is HA . and its Ka is given.
The value of Kw is fixed at a given temperature , which is equal to:
[tex]K_{w}=10^{-14}[/tex]
[tex]K_{a}=6.5\times 10^{-5}[/tex]
[tex]K_{b}=\frac{10^{-14}}{6.5\times 10^{-5}}[/tex]
[tex]K_{b}=1.54\times 10^{-10}}[/tex]
Answer:
Ka*kb=kw
Explanation:Got it right
Substances dissolve through three processes: I. ionization II. dissociation III. dispersion Which lists the dissolving processes that change the identity of a substance?
Answer:
I and II
Ionization and. Dissociation
Explanation:
Dissociation,
Is to unbundle a compound into smaller, less complex constituents that are generally able to recombine under different conditions.
Ionization or ionisation,
Is the process in which an atom or a molecule accepts or loses electrons to become negatively or positively charged, it often is accompanied by with chemical changes.
Dispersion
The act of distributing things over a wide area.
The dissolving processes that change the identity of a substance in chemistry are ionization and dissociation.
Explanation:Dissolving Processes in ChemistryThe dissolving processes that change the identity of a substance are ionization and dissociation.
Ionization occurs when a substance forms ions in a solution. For example, when hydrochloric acid (HCl) dissolves in water, it ionizes into hydrogen ions (H+) and chloride ions (Cl-).
Dissociation happens when a compound breaks apart into its constituent ions in a solution. One example is table salt (NaCl) dissociating into sodium ions (Na+) and chloride ions (Cl-) when dissolved in water.
Dispersion is the process of solute particles spreading evenly throughout a solvent, without forming ions or breaking apart into ions. Dispersion does not change the identity of the substance.
Learn more about dissolving processesThe sculpted pinnacles in Bryce Canyon National Park are the result of _____. A. differential weathering B. frost wedging C. exfoliation D. unloading
Answer:
B. frost wedging Hope i helped!
Explanation:
Answer:
B
Explanation:
If 7.400 g C 6 H 6 is burned and the heat produced from the burning is added to 5691 g of water at 21 ∘ C, what is the final temperature of the water?
The question is incomplete, the complete question is
The following equation is the balanced combustion reaction for C6H6
[tex]2C_6H_6(l)+15O_2(g) \rightarrow 12CO_2(g)+6H_2O(l)+6542 kJ[/tex]
If 7.400 g of [tex]C_6H_6[/tex] is burned and the heat produced from the burning is added to 5691 g of water at 21°C. What is the final temperature of the water?
Answer:
34.45°C is the final temperature of the water.
Explanation:
Moles of benzene = [tex]\frac{7.400 g}{78 g/mol}=0.09487 mol[/tex]
According to reaction, 2 moles of benzene on combustion gives 6542 kJ of heat. Then 0.09487 moles of benzene will give:
[tex]\frac{1}{2}\times 6542 kJ\times 0.09487 mol=310.325 kJ[/tex]
Heat added to water = Q = 310.325 kJ = 310,325 J
(1 kJ = 1000 J)
Specific heat of water = C = [tex]4.18 J/g^oC[/tex]
Mass of the water = m = 5691 g
Initial temperature of the water =[tex]T_1[/tex] = 21°C
Final temperature of the water =[tex]T_2[/tex] =?
Change in temperature of the substance =ΔT =[tex]T_2-T_1[/tex]
[tex]Q=mc\times \Delta (T_2-T_1)[/tex]
[tex]310,325 J=5691 g\times 4.18 J/g^oC\times (T_2-21^oC)[/tex]
[tex]T_2=34.45^oC[/tex]
34.45°C is the final temperature of the water.
Answer:
The final temperature of the water is 34.0 °C
Explanation:
Step 1: Data given
Mass of C6H6 burned = 7.400 grams
Mass of water = 5691 grams
Temperature of water = 21 °C
Specific heat of water = 4.184 K/g°C
2C6H6+15O2→12CO2+6H20+6542KJ
Heat released with combustion of C6H6 = 6542KJ
Step 2: Calculate moles of C6H6
Moles C6H6 = mass C6H6 / molar mass C6H6
Moles C6H6 = 7.400 grams / 78.11 g/mol
Moles C6H6 = 0.09474
Step 3: Calculate heat transfered
Q = 0.09474 moles * 6542 kJ/2 mol = 309.89 kJ
Step 3: Calculate finam temperature
Q = m * c * ΔT
⇒ with Q = the heat transfered =309.9 kJ = 309890 J
⇒ with m = the mass of water = 5691 grams
⇒ with c = the specific heat of water = 4.184 J/g°C
⇒ with ΔT = The change in temperature
ΔT = Q /(m*c)
ΔT = 309890 / ( 5691 * 4.184)
ΔT =13.0 °C
Step 4: Calculate the final temperature
T2 = T1 + ΔT
T2 = 13.0 + 21.0°C
T2 = 34.0 °C
The final temperature of the water is 34.0 °C
The equilibrium constant for the equation Ag+(aq)+2NH3(aq)↽−−⇀[Ag(NH3)2]+(aq) is Kf=2.5×103 M−2 at 25.0 ∘C . Calculate the value of Δ????∘rxn at 25.0 ∘C . Δ????∘rxn= kJ/mol Is the reaction spontaneous under standard conditions? yes noCalculate the value of Δ????rxn at 25.0 ∘C when [Ag+]=0.00850 M , [NH3]=0.156 M , and [[Ag(NH3)2]+]=0.00632 M . Δ????rxn= kJ/mol Is the reaction spontaneous under these conditions?
The ΔG°rxn at 25.0 °C for the given reaction is -4.184 KJ/mol, which means the reaction is spontaneous under standard conditions. When actual concentrations are provided, the ΔGrxn at 25.0 °C is -2.81 kJ/mol, indicating that the reaction remains spontaneous.
Explanation:To calculate the ΔG°rxn at 25.0 °C, we'll be utilizing the formula ΔG° = -RT ln K, where R is the gas constant (8.314 J/mol K), T is the temperature in Kelvin (25.0 °C = 298.15 K), and K is the equilibrium constant Kf (2.5 × 10³ M^-2). The R needs to be converted to kJ from J by dividing it by 1000. Following these conversions, we can substitute these values:
ΔG° = - (8.314 x 10^-3 kJ/mol K) x (298.15 K) x ln (2.5 × 10³ M^-2) = -4.184 KJ/mol
The spontaneity of the reaction is determined by the sign of ΔG. In this case, since ΔG is negative, it indicates that the reaction is indeed spontaneous under standard conditions.
For evaluating ΔGrxn at 25.0 °C when [Ag^+]=0.00850 M, [NH₃]=0.156 M, and [[Ag(NH₃)2]^+]=0.00632 M, we must resort to the equation ΔG = ΔG° + RT ln Q, where Q is the reaction quotient. We substitute the actual concentrations into the equilibrium expression to get Q = {[Ag(NH₃)2]^+} / ([Ag^+] x [NH₃]^2) = 0.00632 / (0.00850 x (0.156)^2) = 2.666. Thus, the ΔGrxn can be calculated as ΔG = -4.184 kJ/mol + 8.314 x 10^-3 kJ/mol K x 298.15K x ln(2.666) = -2.81 kJ/mol.
As ΔGrxn remains negative even with these conditions, the reaction still remains spontaneous.
Learn more about Chemical Equilibrium here:https://brainly.com/question/3920294
#SPJ11
Describe what subatomic particle is involved in light emission.
Please help
Answer: Photons
Explanation: These are packet of light. These subatomic particles have no electrical charge and rest mass. Photons are also considered as field particles in which they are to be carriers of electromagnetic fields.
Will the pH at the equivalence point of the 50 mL titration of 0.10 M HCl be the same, more, or less than the pH at the equivalence point of the 50 mL titration of 0.10 M acetic acid?
It will be less
Explanation:When equivalence point is achieved the acid or base is completely neutralized, but its salt (conjugate acid or base) can alter the pH of the solution. In the comparison of two different acidic or basic species, their conjugate is evaluated. If the base dissociation coefficient (Kb) of one conjugate base is greater than other, then the pH change due to it will be more basic.
The neutralization of HCl can be given as
HCl + OH⁻ -------------- > H₂O + Cl⁻
Here Cl⁻ is the remaining ion at the equivalence point, and it is the conjugate base of HCl. It has a Kb value of 1.0 X 10⁻²⁰ (that is why it is not considered basic).
The neutralization of acetic acid is given as
CH₃COOH + OH⁻ -------------- > H₂O + CH₃COO⁻
Here CH₃COO⁻ is the remaining ion at the equivalence point, and it is the conjugate base of acetic acid. Its Kb value is 5.6 X 10⁻¹⁰, which is higher than the Kb value of Cl⁻. As the amount of HCl and acetic acid is the same, so the solution containing chloride ions will have a lower pH than the solution containing acetate ions.
The pH at the equivalence point of the 50 mL titration of 0.10 M HCl will be less than the pH at the equivalence point of the 50 mL titration of 0.10 M acetic acid.
Hydrochloric acid (HCl) is a strong acid, which means it dissociates completely in water to form [tex]H_3O+[/tex] ions and Cl- ions. At the equivalence point of the titration of HCl with NaOH, all the [tex]H_3O+[/tex] ions from HCl have been neutralized by OH- ions from NaOH, resulting in a solution of its conjugate base, Cl-.
Therefore, the pH at the equivalence point is determined by the autoionization of water, which gives a pH of 7.0 at 25°C.
On the other hand, acetic acid [tex](CH_3COOH)[/tex] is a weak acid. It does not dissociate completely in water, and at the equivalence point of its titration with NaOH, the solution contains the conjugate base of acetic acid, the acetate ion [tex](CH_3COO-)[/tex].
The acetate ion is a moderately strong base, and it can react with water to form OH- ions, which increases the pH of the solution above 7.0. Therefore, the pH at the equivalence point of the titration of acetic acid is basic, typically around 8.7 for a 0.10 M acetic acid solution.
Using this information together with the standard enthalpies of formation of O2(g), CO2(g), and H2O(l) from Appendix C, calculate the standard enthalpy of formation of acetone.
The question is incomplete, here is the complete question:
Using this information together with the standard enthalpies of formation of [tex]O_2(g)[/tex], [tex]CO_2(g)[/tex], and [tex]H_2O(l)[/tex] from Appendix C. Calculate the standard enthalpy of formation of acetone.
Complete combustion of 1 mol of acetone [tex](C_3H_6O)[/tex] liberates 1790 kJ:
[tex]C_3H_6O(l)+4O_2(g)\rightarrow 3CO_2(g)+3H_2O(l);\Delta H^o=-1790kJ[/tex]
Answer: The enthalpy of the formation of [tex]CO_2(g)[/tex] is coming out to be -247.9 kJ/mol
Explanation:
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as [tex]\Delta H^o[/tex]
The equation used to calculate enthalpy change is of a reaction is:
[tex]\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}][/tex]
For the given chemical reaction:
[tex]C_3H_6O(l)+4O_2(g)\rightarrow 3CO_2(g)+3H_2O(l)[/tex]
The equation for the enthalpy change of the above reaction is:
[tex]\Delta H^o_{rxn}=[(3\times \Delta H^o_f_{(CO_2(g))})+(3\times \Delta H^o_f_{(H_2O(l))})]-[(1\times \Delta H^o_f_{(C_3H_6O(l))})+(4\times \Delta H^o_f_{(O_2(g))})][/tex]
We are given:
[tex]\Delta H^o_f_{(H_2O(l))}=-285.8kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_{rxn}=-1790kJ[/tex]
Putting values in above equation, we get:
[tex]-1790=[(3\times {(-393.5)})+(3\times (-285.8))]-[(1\times \Delta H^o_f_{(C_3H_6O(g))})+(4\times (0))]\\\\\Delta H^o_f_{(C_3H_6O(g))}=-247.9kJ/mol[/tex]
Hence, the enthalpy of the formation of [tex]C_3H_6O(g)[/tex] is coming out to be -247.9 kJ/mol.
A 0.10 M aqueous solution of sodium sulfate, Na2SO4, is a better conductor of electricity than a 0.10 M aqueous solution of sodium chloride, NaCl. Which of the following best explains this observation?
A) NazSO4 is more soluble in water than NaCl is.
B) NazSO4 has a higher molar mass than NaCl has.
C) To prepare a given volume of 0.10 M solution, the mass of NazSO4 needed.
D) More moles of ions are present in a given volume of 0.10 M NazSO4 than in the same volume of 0.10 M NaCl.
E) The degree of dissociation of NazSO4 in solution is significantly greater than that of NaCl.
Answer: D) More moles of ions are present in a given volume of 0.10 M [tex]Na_2SO_4[/tex] than in the same volume of 0.10 M NaCl.
Explanation:
A electrolyte is a solution that dissociates completely when dissolved in water. The ions act as good conductors of electric current in the solution.
More is the number of ions , more will be the conductance and hence the solution will be a better conductor of electricity.
0.10 M aqueous solution of [tex]Na_2SO_4[/tex] is a better conductor of electricity as it dissociates to give three ions whereas 0.10 M aqueous solution of [tex]NaCl[/tex] dissociates to give two ions only.
[tex]Na_2SO_4\rightarrow 2Na^++SO_4^{2-}[/tex]
[tex]NaCl\rightarrow Na^++Cl^{-}[/tex]
Thus 0.10 M aqueous solution of sodium sulfate, [tex]Na_2SO_4[/tex] , is a better conductor of electricity as more moles of ions are present in a given volume of 0.10 M [tex]Na_2SO_4[/tex] than in the same volume of 0.10 M [tex]NaCl[/tex]
In addition to specific heat capacity and density, could yo use another physical property such as color to determine the identity of a metal?
Answer:
The answer to your question is below
Explanation:
Melting point is the temperature at which solid changes into liquid.
Boiling point is the temperature at which a liquid changes into a gas.
Viscosity is a measure of the resistance of a liquid to flow.
Solubility is a property of a solid to dissolve in a liquid.
Conductivity is a measure of the ease at which an electric charge flows through a material.
Refer to Animation: Kinetic and Potential Energy. Which of the factors accounts for the higher potential energy of C-C and C-H bonds compared to C-O and H-O bonds?
A) The C-C and C-H bonds are strong, thus requiring a lot of energy to hold together.
B) The CO and H-O bonds are weak, thus requiring less energy to hold together.
C) The C-C and C-H bonds are weak, thus requiring a lot of energy to hold together.
D) The CO and wo bonds are strong, thus requiring a lot of energy to hold together.
Explanation:
The electronegativity difference in C-C and C-H atoms is quite low. This means smaller the electron cloud. This further means larger bond length that is electron's are further from the nucleus. hence, higher potential energy of C-C and C-H bonds.
On the contrary, C-O and H-O have large difference in electronegativity( O is high electronegative element) . This means smaller bond length. Electron's near the nucleus. Thus, lower potential energy of bonds.
Harmful chemicals released directly into the atmosphere due to either human activities or natural processes are ___ air pollutants.
a) primary
b) secondary
c) tertiary
d) quaternary
Answer:
correct answer is a) primary air pollutants
Explanation:
solution
primary air pollutants material are that material which release pose health risk in the unmodified form and they emitted directly from identifiable source not react so they are primary air pollutant
and some major material released directly into the atmosphere as unmodified are given below
Carbon monoxide Nitrogen oxides Sulfur dioxideParticulate matterHydrocarbonsthey all are primary air pollutants
so correct answer is is a) primary air pollutants
Write an equation for the reaction of phosphoric acid (H3PO4) and calcium hydroxide. What is the coefficient of calcium hydroxide in this equation?
Answer:
The answer to your question is " 3 "
Explanation:
Equation = ?
Phosphoric acid = H₃PO₄
Calcium hydroxide = Ca(OH)₂
This is an acid base reaction because there is an exchange of hydrogens.
Reaction
H₃PO₄ + Ca(OH)₂ ⇒ Ca₃(PO₄)₂ + H₂O
Balance
Reactants Elements Products
1 P 2
1 Ca 3
5 H 2
6 O 9
The reaction is unbalanced
2H₃PO₄ + 3Ca(OH)₂ ⇒ Ca₃(PO₄)₂ + 6H₂O
Balance
Reactants Elements Products
2 P 2
3 Ca 3
12 H 6
14 O 14
Now, the reaction is balanced, the coefficient of Calcium hydroxide is 3
Chlorine has two isotopes, 35Cl and 37Cl; 75.77 % of chlorine is 35Cl and 24.23 % is 37Cl. The atomic mass of 35Cl is 34.969 amu and the atomic mass of 37Cl is 36.966 amu . What is the atomic weight of chlorine?
Answer:
35.4528731 amu
Explanation:
To appropriately get the atomic mass unit of chlorine, we can get the answer using the masses from the isotopes. This can be obtained as follows. What we do is that we multiply the percentage compositions by the masses.
Now let’s do this.
[75.77/100 * 34.969] + [24.23/100 * 36.966]
= 26.4960113 + 8.9568618 = 35.4528731
Answer: the atomic weight of chlorine is 35.5
Explanation:Please see attachment for explanation