The potential difference between a storm cloud and the ground is 100 million V.If a charge of 1.2 C flashes in a bolt from cloud to Earth, what is the change of potential energy of the charge?Express your answer to two significant figures and include the appropriate units.

Answer: Machanical advantage of the machine is 1.86

Explanation: Machanical advantage of a machine is the ratio of the Force to overcome which is the load in this case 24kg * 10= 240N to the force exerted(Effort) to overcome the load in this case 129N.

So, we have

MA = load/effort

= 240N/129N

= 1.86.

The mechanical advantage of the pulley system is equal to 1.82.

Given the following data:

Scientific data:

To determine the mechanical advantage of the pulley system:

First of all, we would calculate the force acting on the load as follows;

[tex]Force = mg\\\\Force = 24 \times 9.8[/tex]

Force = 235.2 Newton

Now, we can solve for mechanical advantage:

[tex]M.A = \frac{Load}{Effort} \\\\M.A=\frac{235.2}{129}[/tex]

Mechanical advantage = 1.82.

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Answer:

C. 2205 J

Explanation:

First we need to find the final velocity of skater at the bottom.

We, have:

Height lost = h = 4 m - 1 m = 3 m

Initial Velocity = Vi = 0 m/s (since, it starts from rest)

acceleration due to gravity = g = 9.8 m/s²

using third equation of motion:

2gh = Vf² - Vi²

2(9.8 m/s²)(3 m) = Vf² - (0 m/s)²

Vf² = 58.8 m²/s²

Now, for kinetic energy at bottom:

K.E = (1/2) m Vf²

K.E = (1/2)(75 kg)(58.8 m²/s²)

K.E = 2205 J

Hence, the correct option is C. 2205 J

Answer:

Explanation:

When the ball is thrown upwards it's velocity is pointing upwards while acceleration i.e. acceleration due to gravity is pointing downwards.

As the ball moves upwards it's velocity is decreasing and the ball reaches maximum height it's velocity becomes zero while the acceleration is still pointing downwards.

During downward motion, both velocity and acceleration are pointing downward.

Answer:

Wen we place a cold alcohol in glass in a hot tub of water then the glass will be warmed first so it will expand a little due to which the level of alcohal decreases. After some time when thermal equilibrium is achevied then the alcohol will expand more then glass as the alcohol has the greater coeficient of expansion then glass so there will be an incerease in the level of alcohol which will indicate how much high the temperature is.

Explanation:

The alcohol level in a thermometer initially drops when placed in hot water because the glass expands first, temporarily increasing the volume before the alcohol heats up and rises. This illustrates the principle of thermal expansion.

When a cold alcohol-in-glass thermometer is initially placed in a hot tub of water, the column of alcohol first descends slightly before rising. This phenomenon can be explained by the principles of thermal expansion.

Explanation:

We have equation of motion v = u + at

     Initial velocity, u =  0 m/s

     Final velocity, v = 50 miles/hr = 80 km/hr = 22.22 m/s    

     Time, t = 2.22 s

     Substituting

                      v = u + at  

                      22.22 = 0 + a x 2.22

                      a = 10 m/s²

     Acceleration is 10 m/s²

Acceleration of cheetah is 10 m/s²

Answer:

(a) 4.0334Ω

(b)parallel

Explanation:

for resistors connected in parallel;

[tex]\frac{1}{R_{eq} } =\frac{1}{R1}+\frac{1}{R2}[/tex]

Req =3.03Ω , R1 =12.18Ω

[tex]\frac{1}{3.03 } =\frac{1}{12.18}+\frac{1}{R2}[/tex]

[tex]\frac{1}{R2}=\frac{1}{3.03 }-\frac{1}{12.18}[/tex]

[tex]\frac{1}{R2}=0.2479[/tex]

R2=1/0.2479

R2=4.0334Ω

(b)parallel connection is suitable for the desired total resistance. series connection can not be used to achieve a lower resistance as the equation for series connection is.

Req = R1+R2

To achieve a total resistance of 3.03 Ω when an unknown resistor is connected in parallel with a 12.18 Ω resistor, the unknown resistance must be 4.03 Ω.

To determine the unknown resistance that needs to be connected to a 12.18 Ω resistor to produce a total resistance of 3.03 Ω, we can use the formula for resistors in parallel, since the total resistance is given and is less than the resistance of the known resistor. The formula is:

1 / Rtotal = 1 / R1 + 1 / R2

We can arrange the formula to solve for R2, the unknown resistance:

1 / R2 = 1 / Rtotal - 1 / R1

By plugging in the given values (Rtotal = 3.03 Ω, R1 = 12.18 Ω), we get:

1 / R2 = 1 / 3.03 - 1 / 12.18

Calculating the right side of the equation:

1 / R2 = 0.330 - 0.0821

1 / R2 = 0.2479

Finally, we take the reciprocal of both sides to find R2:

R2 = 1 / 0.2479

R2 = 4.03 Ω

So, the unknown resistance must be 4.03 Ω to achieve the specified total resistance when connected in parallel with a 12.18 Ω resistor.

Answer:

Work done, W = 0

Explanation:

Given that, a container of water is lifted vertically 3.0 m then returned to its original position.The total weight of the container is 30 N. We need to find the total work done by the container. We know that the work done by an object is given by :

W = F × d

Where

F is the applied force

d is the displacement of the object

It is mentioned that the container returns to its original position, the displacement of the container is equal to 0. Hence, no work was done by the container of water.

Answer: No work was done when a container of water is lifted vertically 3.0 m and then returned to its original position.

Explanation:

Work is defined as a force causing the movement or displacement of an object.

work=[tex]f\times s[/tex]

Given: f = force = 30N

s = displacement = 0.0 m (as the initial and final position is same, there is no displacement)

Putting in the values we get,

work=[tex]30N\times 0m=0J[/tex]

Thus amount of work will be 0 J.

Answer:

Peer to peer network

Explanation:

Peer-to-peer networks are designed to connect similar computers allowing them to share data and software. These networks have played a crucial role in the formation of the internet as we know it today. AOL is an example of a commercial service provider that adopted this networking model.

The networks that are designed to connect similar computers that share data and software with each other are called peer-to-peer networks. Peer-to-peer networks allow all computers, termed nodes, to share resources amongst each other without the need for a central server. Every computer on a peer-to-peer network can function as both a server and a client, sharing and receiving files simultaneously.

Examples of this can be found in early internet developments like the Advanced Research Projects Agency Network (ARPANET). As technologies improved, commercial online service providers like America Online (AOL) adopted this networking model, serving as gateways to the burgeoning internet.

Prior to the existence of more sophisticated network infrastructure like cable and fiber optics, these peer-to-peer networks provided a means for computers to communicate and share data, laying the groundwork for the commercial internet as we understand it today.

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The lift in the wing is similar to the Bernoulli's equation. The pressure on the one side of the ball makes it to mover faster than the other side. In heart attack As the blood rushes through the constricted artery, the internal pressure  drops and again the artery closes.

Explanation:

The determination of the relation between the pressure, density and velocity at each point of a fluid can be done with Bernoulli's principle.The lift of the aircraft makes it to move forward and upward. This is achieved based on relationship between the angle of the wing and the turbulent flow that helps whether to increase or decrease the lift of the wing. This is similar to the Bernoulli's equation and hence they are associated with each other.  

A ball contains stitches on the middle. While a ball spins the pressure is induced by the ball stitches. This will increase the pressure to decrease one side when compared to the pressure of the other side of the ball. This enables it to move faster.  The pressure must be increased for maintaining a constant rate flow of blood in artery. Heart muscle is very essential factor for increasing this pressure. The person will have heart attach when there is dislodging of the plaque occurs.    

Answer:

First law of thermodynamics.

Explanation:

The first law of thermodynamics states that the change in internal energy of a system ΔE equals to the amount of heat energy supplied to the system H  , minus the work done by the system on its surroundings. W.

The above definition can be expressed mathematically as: ΔE = H - W

This can also be restarted as energy of a close or isolated system is constant.

Answer:

[tex]I=12.5\ kg.m^2[/tex]

Explanation:

Given that

Stored energy ,[tex]E=1\times 10^6[/tex]

Angular speed ,[tex]\omega =400\ rad/s[/tex]

Lets take moment of inertia of the flywheel = I

As we know that stored energy in the flywheel is given as

[tex]E=\dfrac{1}{2}\omega^2 I[/tex]

[tex]I=\dfrac{2\ttimes E}{\omega^2}[/tex]

Now by putting the values in the above equation we get

[tex]I=\dfrac{2\times 1\times 10^6}{400^2}\ kg.m^2[/tex]

[tex]I=12.5\ kg.m^2[/tex]

Therefore the moment of inertia of the flywheel will be [tex]I=12.5\ kg.m^2[/tex]

The answer will be C.

[tex]I=12.5\ kg.m^2[/tex]

Answer:

The player and the ball have the same displacement

Explanation:

Displacement is the distance between the final position and initial position, When the ball is hit upwards, it is caught at the same height. The vertical displacement of the ball is zero. The horizontal displacement of the ball would be equal to the displacement of the player because the player runs in a straight line to catch the ball.

Final answer:

The racket is moving at a speed of 15 m/s immediately after the impact. The average force that the racket exerts on the ball is 0.189 N.

Explanation:

Part A:

To calculate the racket's speed immediately after the impact, we can use the principle of conservation of momentum. The momentum before the impact is equal to the momentum after the impact.

The momentum before the impact is given by the product of the racket's mass and its initial speed:

Momentum before = (0.001 kg)(15.0 m/s) = 0.015 kg·m/s

The momentum after the impact is equal to the product of the racket's final speed (which is what we need to find) and its mass:

Momentum after = (0.001 kg)(v)

Since the momentum is conserved, we can equate the two expressions:

0.015 kg·m/s = (0.001 kg)(v)

Simplifying this equation gives:

v = 15 m/s

Therefore, the racket is moving at a speed of 15 m/s immediately after the impact.

Part B:

To find the average force that the racket exerts on the ball, we can use the impulse-momentum principle. The impulse exerted on the ball is equal to the change in momentum of the ball:

Impulse = change in momentum

The change in momentum can be calculated using the formula:

change in momentum = (final momentum) - (initial momentum)

The initial momentum of the ball is given by the product of its mass and its initial speed:

Initial momentum = (0.060 kg)(18.0 m/s) = 1.08 kg·m/s

The final momentum of the ball is given by the product of its mass and its final speed:

Final momentum = (0.060 kg)(40.0 m/s) = 2.4 kg·m/s

Substituting these values into the formula, we have:

Impulse = 2.4 kg·m/s - 1.08 kg·m/s

Impulse = 1.32 kg·m/s

Since impulse is equal to the average force multiplied by the time of contact, we can rearrange the formula to solve for the average force:

Average force = Impulse / Time of contact

Substituting the values for impulse and the given time of contact, we have:

Average force = 1.32 kg·m/s / 7.00 s

Average force = 0.189 N

The student's question concerns the calculation of the stalling speed for a Piper Super Cub airplane at sea level based on the maximum gross weight, wing area, and the maximum lift coefficient. By using the lift equation and rearranging it to solve for velocity, we can find the stalling speed that must be maintained for the airplane to generate enough lift to balance its weight.

The student is asking to calculate the stalling speed of a Piper Super Cub airplane at sea level. The stalling speed is the minimum speed at which an airplane can maintain level flight. To find this, we can use the equation for lift, which at the stalling point must equal the weight of the airplane. The lift equation is L = (1/2) ∙ ρ ∙ V² ∙ S ∙ Cl where L is the lift force, ρ is the air density, V is the velocity, S is the wing area, and Cl is the maximum lift coefficient.

Given that:

We can rearrange the lift equation to solve for velocity (V) and then plug in the numbers to calculate the stalling speed.

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Answer:

cultural

Explanation:

Cultural anthropology studies the characteristics of the behavior learned in human societies, that is, science of human culture. In general, it is the science that studies the origin, development, structure, characteristics and variations of human culture in both past and present societies. Ethnography, ethnology, archeology, linguistics and physical anthropology are the disciplines on which cultural anthropology is founded.

Answer:

In the Mediterranean sea

Explanation:

The water present in the deeper part of the North Atlantic ocean is warm and comprised of high salinity, and abundance in oxygen as well as rich in terms of nutrient ones. On the other hand, the opposite occurs in the southern part of the Atlantic ocean. This warm water is typically found up to a depth of about 1000 meters below the mean sea level.

This Atlantic ocean is directly connected to the Mediterranean sea through the Gibraltar Strait.

Therefore, this mass of water that is comprised of higher salinity and higher temperature that is found at a depth of 1000 meters in the northern part of the Atlantic ocean has been formed in the Mediterranean sea.

Answer:

Neglecting air resistance, the only force acting on a projectile is gravity.

This force causes the object to accelerate.

Explanation:

As a projectile moves upward, there is a downward force and a downward acceleration due to force of gravity. That is, as the object is moving upward, force of gravity acting on the projectile is causing a steady slowing down of the projectile.

Hence, Gravity is the downward force upon a projectile that influences its vertical motion and causes the parabolic trajectory that is characteristic of projectiles.

From Newton's law of motion, it suggest that force is required to cause an acceleration and not motion. Therefore, force of gravity causes the object to accelerate downwards.

Answer:

You are right. The answer to this question is option A. The metallic sphere is a conductor and can allow electric charges flow through it from one region to another. The reason the sphere is insulted from the ground is to block out the transfer of charges from the sphere to the ground or from the ground to the sphere. The ground itself can serve as infinitely large sink or source for electric charges.

The act of touching the sphere with the charged rod deposits some electric charge on the sphere. These charges in the absence of an insulator between the sphere and the ground will flow straight into the ground. But because there is an insulator connected to the sphere the charges remain on the sphere with no way of getting out of the sphere.

These charges are the same with that on the rod as they were conducted and not induced by polarization (in general if the shepre became charged by polarization, it would have a charge opposite that on the rod). Since like charges repeatedly and unlike charges attract. The sphere would always repel the rod.

Thank you for reading and I hope this was helpful to you.

When the plastic rod is charged and brought close to the neutral metallic sphere, charges are redistributed. After touching and separating, the rod is repelled by the sphere due to the imbalance of charges. Insulating the sphere from the ground prevents charge redistribution.

When the plastic rod is rubbed with a wool cloth, it becomes charged and gains electrons. The charged rod is brought close to the initially neutral metallic sphere, which causes a redistribution of charges on the sphere's surface. Electrons in the sphere are attracted to the positively charged rod, causing an imbalance of charges.

When the rod touches the sphere, electrons from the sphere are transferred to the rod, neutralizing the rod's charge. The sphere gains a negative charge due to the excess electrons it lost to the rod. When the rod is separated from the sphere, it is now negatively charged and repelled by the negatively charged sphere.

Insulating the sphere from the ground means that the sphere is not in contact with any conductive material that can provide or receive charge. This ensures that the charge on the sphere remains constant and does not redistribute to the ground, allowing for the charge redistribution between the rod and the sphere.

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Answer:

Explanation:

Given

mass of bullet [tex]m=5\ gm[/tex]

speed of bullet [tex]v=355\ m/s[/tex]

bullet is stopped by building and heat produced is shared between building and bullet

Kinetic Energy of bullet is converted into Thermal energy

Kinetic Energy of bullet [tex]K=\frac{1}{2}mv^2[/tex]

[tex]K=0.5\times 5\times 10^{-3}\times (355)^2[/tex]

[tex]K=315.06\ J[/tex]

So 315.06 J of Energy is converted in to thermal energy

Answer:

0.0072 m³/s

Explanation:

Using Bernoulli's law

P₁ + 1/2ρv₁² = P₂ + 1/2ρv₂ since the pipe is horizontal

1/2ρv₂² - 1/2ρv₁² = P₁ - P₂

flow rate is constant

A₁v₁ = A₂v₂

A₁ = πr₁² = π (0.06/2)² = 0.0028278 m²

A₂ = πr₂² = π (0.0225)² = 0.00159 m²

v₁  = (A₂ / A₁)v₂

v₁  = (0.00159 m²/ 0.0028278  m²) v₂ = 0.562  v₂

substitute v₁  into the Bernoulli's equation

1/2ρv₂² - 1/2ρv₁² = P₁ - P₂

500 ( 1 - 0.3161 ) v₂²  = (31.0 - 24 ) × 10³ Pa

341.924 v₂² = 7000

v₂² = 20.472

v₂ = √ 20.472 = 4.525 m/s

volume follow rate = 0.00159 m² ×  4.525 m/s = 0.0072 m³/s

[tex]0.0072 \;\rm m^{3}/s[/tex]The volume flow rate at the exit of the pipe is [tex]0.0072 \;\rm m^{3}/s[/tex].

Given data:

The  initial diameter of horizontal pipe is, d = 6.0 cm.

The final diameter of pipe is, d' = 4.5 cm.

The gauge pressure at inner section is, P = 31.0 kPa.

The gauge pressure at outer section is, P' = 24.0 kPa.

Applying the Bernoulli's concept, which says the total pressure energy and kinetic energy throughout the flow remains constant .

So, for the horizontal pipe, the expression is,

[tex]P + \dfrac{1}{2} \rho v^{2} = P' + \dfrac{1}{2} \rho v'^{2}[/tex] ............................................(1)

Here, [tex]\rho[/tex] is the density of water throughout the flow, which remains constant.

Now, apply the continuity equation as,

[tex]A\times v = A' \times v'\\\\(\pi/4 \times d^{2}) \times v = (\pi/4 \times d'^{2}) \times v'\\\\ d^{2} \times v = d'^{2} \times v'\\\\v/v' = 0.045^{2}/0.006^{2}\\\\v = 0.5625\times v'[/tex]

Now substitute the value in equation (1) as,

[tex]P -P' = \dfrac{1}{2} \rho v'^{2} - \dfrac{1}{2} \rho v^{2}\\\\(31 -24) \times 10^{3} \;\rm Pa = \dfrac{1}{2} \times 1000 v'^{2} - \dfrac{1}{2} \times 1000 (0.5625 v')^{2}\\v' = 4.52 \;\rm m/s[/tex]

Then the flow rate is calculated as,

[tex]Q' = A' \times v'\\\\Q' = (\pi /4) d'^{2} \times v'\\Q' = (\pi /4) \times 0.06'^{2} \times 4.52\\\\Q' = 0.0072 \;\rm m^{3}/s[/tex]

Thus, the required value of volume flow rate is, [tex]0.0072 \;\rm m^{3}/s[/tex].

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Answer:

764.7 N/C, the direction is upward

Explanation:

E electric field of  the electron = F / charge

F force of the electron = Eq

acceleration of the body = change in velocity / time = 140 m / 2.10 s = 66.67 m/s² since the electron is from rest.

F upward = F of electron - force of gravity

F upward = Eq - mg

ma = Eq -mg

divide through with m

a = E (q/m) - g

(a + g) / (q/m) = E

(66.67 + 9.8) / 0.100 = 764.7 N/C, the direction is upward

g and the electric field in this region is constant and uniform.What are the magnitude and direction of the electric field?



Answer: 83%

Explanation:

Efficiency of the process = work output/work input × 100%

Work input is the energy used up in the process = 720,000Joules

Work output = Force × distance

= (3000×10)× 20

= 600000 Joules

Efficiency= 600000/720000 × 100

= 0.83×100

= 83%

Incomplete question.The complete question is here

An energy storage system based on a flywheel (a rotating disk) can store a maximum of 4.1 MJ when the flywheel is rotating at 14000 revolutions per minute.What is the moment of inertia of the flywheel?

Answer:

Moment of inertia=3.82 kg.m²

Explanation:

Given data

Energy E=4.1 MJ=4.1×10⁶J

Angular speed ω= 14000 rev/min= 14000×2π/60=1465.3 rad/s

To find

Moment of Inertia

Solution

A rotating flywheel must store its energy as kinetic energy

Let I be moment of inertia of the flywheel.We Know

[tex]E(Energy)=\frac{1}{2}Iw^{2}\\  I=\frac{2E}{w^{2} }\\ I=\frac{2(4.1*10^{6}) }{(1465.3)^{2} }\\ I=3.82 kgm^{2}[/tex]

The subject of this question is Physics and it relates to an energy storage system based on a flywheel.

The subject of this question is Physics. The question relates to an energy storage system based on a flywheel.

A flywheel is a rotating disk that can store energy in the form of rotational kinetic energy. The maximum energy that can be stored in the flywheel depends on its moment of inertia and the square of its angular velocity.

In this case, the flywheel can store a maximum of 4.1 MJ when it is rotating at 14000 revolutions per minute.

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According to the question,

Object's relative speed,

[tex]v_{rel} = 1.30+1.30[/tex]

      [tex]= 2.60 \ m/s[/tex]

Time taken by the two steamrollers,

[tex]t = \frac{d}{v_{rel}}[/tex]

  [tex]= \frac{105}{2.60}[/tex]

  [tex]= 40.39 \ seconds[/tex]

hence,

The distance of fly travel will be:

→ [tex]s = vt[/tex]

By putting the values,

     [tex]= 2.40\times 40.39[/tex]

     [tex]= 96.94 \ m[/tex]

Thus the above response is right.

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Answer:

ACO cable mate

Explanation:

Answer:

Convection cell

Explanation:

The convection current refers to the upward rising of the hot molten and less dense magma in the mantle. These currents are formed due to the heat supplied from the core of the earth. This upward movement of magma results in the movement of the lithospheric plates over the less dense viscous layer of the asthenosphere.

As the magma at the greater depth gets heated up, due to the increasing heat and pressure, it gets heated up and rises upward in the form of convection cells. As it rises upward, it cools and slowly moves laterally and eventually sinks after its density increases. This cycle repeats and forms the main mechanism for the plate tectonic movement.

Answer:

98.15 lb

Explanation:

weight of plane (W) = 5,000 lb

velocity (v) = 200 m/h =200 x 88/60 = 293.3 ft/s

wing area (A) = 200 ft^{2}

aspect ratio (AR) = 8.5

Oswald efficiency factor (E) = 0.93

density of air (ρ) = 1.225 kg/m^{3} = 0.002377 slugs/ft^{3}

Drag = 0.5 x ρ x [tex]v^{2}[/tex] x A x Cd

we need to get the drag coefficient (Cd) before we can solve for the drag

Drag coefficient (Cd) = induced drag coefficient (Cdi) + drag coefficient at zero lift (Cdo)

where

        where lift coefficient (Cl)= [tex]\frac{2W}{pAv^{2} }[/tex]=[tex]\frac{2x5000}{0.002377x200x293.3^{2} }[/tex] = 0.245

        therefore

       induced drag coefficient (Cdi) = [tex]\frac{Cl^{2} }{n.E.AR}[/tex] = [tex]\frac{0.245^{2} }{3.14x0.93x8.5}[/tex] = 0.0024

Now that we have the coefficient of drag (Cd) we can substitute it into the formula for drag.        

 Drag = 0.5 x ρ x [tex]v^{2}[/tex] x A x Cd

Drag = 0.5 x 0.002377 x (293.3 x 293.3) x 200 x 0.0048 = 98.15 lb

The total drag on the airplane is approximately 376.4 pounds (lb).

To calculate the total drag on the airplane, we'll use the following formula for total drag:

[tex]\[D = \frac{W^2}{q \cdot S \cdot \pi \cdot e \cdot AR}\][/tex]

Where:

- \(D\) is the total drag in pounds (lb).

- \(W\) is the weight of the airplane in pounds (lb), which is 5000 lb in this case.

- \(q\) is the dynamic pressure in lb/ft^2, given by [tex]\(q = 0.5 \cdot \rho \cdot V^2\)[/tex], where[tex]\(\rho\)[/tex] is the air density at standard sea level (0.002377 lb/ft^3) and \(V\) is the velocity in ft/s (200 mi/h converted to ft/s).

- S is the wing area in square feet (ft^2), which is 200 ft^2.

- pi is approximately 3.1416.

- e is the Oswald efficiency factor, which is 0.93 in this case.

- AR is the aspect ratio, which is 8.5 in this case.

Let's calculate it step by step:

1. Convert the velocity from miles per hour (mi/h) to feet per second (ft/s):

 [tex]\[V = 200 \, \text{mi/h} \times \frac{5280 \, \text{ft/mi}}{3600 \, \text{s/h}} = 293.33 \, \text{ft/s}\][/tex]

2. Calculate the dynamic pressure (\(q\)):

  [tex]\[q = 0.5 \cdot \rho \cdot V^2 = 0.5 \cdot 0.002377 \, \text{lb/ft}^3 \cdot (293.33 \, \text{ft/s})^2 = 21.81 \, \text{lb/ft}^2\][/tex]

3. Now, plug the values into the total drag formula:

[tex]\[D = \frac{5000 \, \text{lb}^2}{21.81 \, \text{lb/ft}^2 \cdot 200 \, \text{ft}^2 \cdot 3.1416 \cdot 0.93 \cdot 8.5} \approx 376.4 \, \text{lb}\][/tex]

So, the total drag on the airplane is approximately 376.4 pounds (lb).

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Answer:

0.43 s

Explanation:

speed (s) = 95 mi/h = 95 x 1600/3600 = 42.5 m/s  (converting to m/s)

distance (d) = 60 ft 6 inches = (60 x 0.3048) + (6 x 0.025) = 18.44 m (converting to meters)

speed = distance / time

time = distance / speed = 18.44 / 42.5 = 0.43 s

Answer:

The answer is 3597501.48 km

Explanation:

The speed of light is 299792 km/s.

The speed of sound is 0.343 km/s

The difference is 299791.76 km/s

and of there is 12 second difference between sound and the light. The distance will be:

[tex]299791.76*12=3597501.48[/tex]

It should be far from the storm is the observer is 3597501.48 km.

It measured how hot or cold the air should be. It explained the kinetic energy, or energy of motion, of the gases that make up air. Since gas molecules move faster due to which there is an increment in the air temperature

Since the temperature of the air is 20c and there is 12 seconds.

Also,

The speed of light is 299792 km/s.

The speed of sound is 0.343 km/s

The difference is 299791.76 km/s

Now it is

[tex]= 299791.76 km/s \times 12[/tex]

= 3597501.48 km

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Answer:

(d)  −7 C

Explanation:

Like charges attracts and unlike charges repel. When the three charges are are agitated, the +3 C and +4 C will repel to give of +7 C. To create a balance in the system, the third charge will -7 C to give an algebraic sum of zero in the system.