The mass of an electron is 9.11×10−31 kg. If the de Broglie wavelength for an electron in a hydrogen atom is 3.31×10−10 m, how fast is the electron moving relative to the speed of light? The speed of light is 3.00×108 m/s.

Answer:

2 m/s and -2 m/s

Explanation:

The object travels with an angle of

60.0°

with the positive direction of the y-axis: this means that it lies either in the 1st quadrant (positive x) or in the 2nd quadrant (negative x).

If it lies in the 1st quadrant, the value of vx (component of v along x direction) is:

[tex]v_x = v cos \theta = (4.0 m/s) cos 60.0^{\circ}=2 m/s[/tex]

If it lies in the 2nd quadrant, the value of vx (component of v along x direction) is:

[tex]v_x = -v cos \theta = -(4.0 m/s) cos 60.0^{\circ}=-2 m/s[/tex]

Answer:

2.34 L

Explanation:

Assuming the pressure inside the balloon remains constant, then we can use Charle's law, which states that for a gas kept at constant pressure, the ratio between the volume of the gas and its temperature remainst constant:

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

where in this problem we have:

[tex]V_1 = 2.50 L[/tex] is the initial volume

[tex]V_2 [/tex] is the final volume

[tex]T_1 = 30.0^{\circ}C+273 = 303 K[/tex] is the initial temperature

[tex]T_2 = 11.0^{\circ}C+273 = 284 K[/tex] is the final temperature

Substituting into the equation and solving for V2, we find the final volume:

[tex]V_2 = \frac{V_1 T_2}{T_1}=\frac{(2.50 L)(284 K)}{303 K}=2.34 L[/tex]

Final answer:

The volume of a balloon filled to 2.50 L at 30.0°C will decrease to approximately 2.34 L when the temperature drops to 11.0°C, as calculated using Charles's Law.

Explanation:

To determine the new volume of a balloon when the temperature drops from 30.0°C to 11.0°C, we can use Charles's Law which states that the volume of a gas is directly proportional to its temperature in kelvins. First, we convert the temperatures from Celsius to Kelvin by adding 273.15:

With an initial volume (V1) of 2.50 L, we can set up the proportionality:

V1/T1 = V2/T2
Solving for the new volume (V2):

V2 = V1 · (T2/T1)
V2 = 2.50 L · (284.15 K / 303.15 K)
V2 = 2.50 L · 0.9373
V2 ≈ 2.34 L
The volume of the balloon will decrease to approximately 2.34 L when the temperature drops to 11.0°C.

The Mariner 10 probe was launched by NASA on November 3rd, 1973, with the purpose of exploring the characteristics of two planets in the solar system that were closest to the Sun, Mercury and Venus.  

In addition, it was launched to explore the atmosphere and surface of both planets and prove that it was possible to use gravitational assistance (also called slingshot effect, a special orbital maneuver in order to use the gravitational field energy of a planet or massive body to accelerate or slow the probe and change the direction of its trajectory) in long interplanetary trips to save fuel.  

In this case, Mariner 10 first arrived at Venus and succeded in using its gravitational field to accelerate its trajectory towards Mercury.

The planet visited by Mariner 10 in 1974 was Mercury.

Explanation:

During the 19th century the accepted atomic model, was Dalton's atomic model, which postulated the atom was an "individible and indestructible mass".

However, at the end of 19th century J.J. Thomson began experimenting with cathode ray tubes and found out that atoms contain small subatomic particles with a negative charge (later called electrons).  This meant the atom was not indivisible as Dalton proposed. So, Thomson developed a new atomic model.

Taking into consideration that at that time there was still no evidence of the atom nucleus, Thomson thought the electrons (with negative charge) were immersed in the atom of positive charge that counteracted the negative charge of the electrons. Just like the raisins embedded in a pudding or bread.

That is why this model was called the raisin pudding atomic model.

D)

It has played a role throughout the Sun's history, but it was most important right after nuclear fusion began in the Sun's core. What do we mean when we say that the Sun is in gravitational equilibrium? ... There is a balance within the Sun between the outward push of pressure and the inward pull of gravity.

When we say that the sun is in gravitational equilibrium, it simply means that there's a balance within the sun between the outward push of pressure and the inward pull of gravity.

In conclusion, the amount of energy that's released by fusion in the core of the sun will then be equal to the amount of energy that radiated from the surface of the sun into space.

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Answer:

r = 0.1217 nm

Explanation:

r^2 = (RT) / ( 4 * pi *P * A* L)

r^2 = 8.314 * 273 / ( 4 * pi * (1.01*10^5) * (6.022*10^23) * (0.2*10^-6))

r = 1.217*10^-10

r = 0.1217 nm

The radius of the helium atom in helium gas can be determined using the mean free path and the concept of cross-sectional area.

The radius of a helium atom can be determined using the mean free path and the concept of cross-sectional area. The mean free path is the average distance a molecule travels between collisions. In this case, the mean free path of a helium atom in helium gas at standard temperature and pressure is given as 0.2 um.

To find the radius of the helium atom, we can relate the cross-sectional area, which is 4r², to the mean free path using the formula (N/V)(4r²)(λ) = 1. Rearranging this formula, we have r = sqrt(1 / (4 * N / V * λ)), where N/V is the molar density of helium gas at standard temperature and pressure.

Since we are given the mean free path as 0.2 um, we can substitute this value into the formula. The molar density of helium gas at standard temperature and pressure is approximately 1.78 x 10^25 atoms/m³. Plugging in these values, we can calculate the radius of the helium atom in nanometers.

Using the formula, r = sqrt( 1 / (4 * 1.78 x 10^25 * 0.2 x 10^-6)), we can simplify and convert to nanometers to get r ≈ 0.109 nm. Therefore, the radius of the helium atom is approximately 0.109 nanometers.

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The wavelength of objects like baseballs is extremely small compared to the size of atoms, rendering such wavelengths undetectable in the macroscopic world. However, for subatomic particles like electrons, their wavelength can be comparable to the size of atoms, influencing their behavior and energy levels within the atom. X-rays have wavelengths comparable to the size of the structures they interact with, allowing them to be effective in observing atomic and molecular structures.

When considering the size of an atom, which is typically on the order of 0.1 nanometers (10-10 meters), and comparing it to the wavelengths of various particles or types of radiation, we can make several observations. For instance, the diameter of an atom's nucleus is approximately 10⁻¹⁴ meters.

If we calculate the wavelength of a 0.145 kg baseball moving at 40 m/s, the resultant wavelength would be about 10-34 meters. This is immeasurably small compared to the size of an atom, indicating Their wavelength is very small compared to the object's size.

However, for subatomic particles like electrons, the wavelength is of the same order of magnitude as the size of an atom. The wavelike behavior of electrons is significant when they are confined within the atom, as this affects their possible energy levels. In the case of X-rays, the wavelength is comparable to the size of the structures it interacts with, such as the distances between atoms in a molecule, allowing X-rays to 'see' these structures.

If we scale an atom up to a size comparable to a mid-sized campus, the nucleus would be only a tiny fraction of that size, possibly comparable to a small familiar object like a marble.

Final answer:

Wavelengths of everyday large objects are considerably smaller than the size of atoms, and thus their wave properties are not detectable. However, for subatomic particles like electrons, their wavelengths can be of the same order as the size of atoms, indicating observable wavelike behavior. X-rays have wavelengths comparable to atomic dimensions and can effectively image atomic structures.

Explanation:

When considering the scale of wavelengths to the size of atoms, it's important to understand that typically the wavelength of everyday large objects, such as a baseball, is considerably smaller than atomic dimensions. If we calculate the wavelength of a 0.145 kg baseball moving at a speed of 40 m/s, we would get a wavelength of approximately 10-34 m. This is so short that it is undetectable even with the most advanced scientific instruments and is much smaller than the size of an atom, which is in the order of 10-10 m.

In contrast, the phenomena of wave-particle duality, as demonstrated by electrons, shows that wavelike behavior becomes prominent when the wavelength of particles is on the order of magnitude of atoms. The classic example involves the wave nature of electrons showing quantized wavelengths that fit just right around an atom, explaining why they can only occupy specific energy levels within an atom.

The significance of wavelengths being comparable to atomic sizes comes into focus especially in fields involving the electromagnetic spectrum, such as when using X-rays to probe structures at the atomic or molecular level. Here, the fact that the wavelength of X-rays is comparable to the spacing between atoms allows for the detailed imaging of such structures through diffraction patterns.

Weight = (mass) x (gravity)

so

Mass = (weight) / (gravity)

Mass = (3000N) / (9.8 m/s^2)

Mass = 306.1 kg

But he could never stand on one foot balanced on a step stool. The poor kid weighs 675 pounds ! !

The mass of a student can be calculated using the formula F = m*g. Hence the mass is approximately 305.81 kg.

To find the mass of the student, we need to convert the weight to force using the formula, F = m * g where F is the force or weight, m is the mass, and g is the acceleration due to gravity (g = 9.8 m/s² on Earth)  or Using the relationship between weight and mass, which is expressed by the formula W = m*g, where W is weight.

To calculate the mass (m), we rearrange the formula to m = W/g.

m = 3000 N / 9.81 m/s^2 =  305.81 kg

Therefore, the mass of the student who exerts a force of 3000N due to gravity on the step stool while balancing on one foot is 305.81 kilograms.

Final answer:

The toy on a spring converts energy between elastic potential energy, kinetic energy, and gravitational potential energy, demonstrating the principles of the Law of Conservation of Mechanical Energy. So the correct option is a.

Explanation:

The toy on a spring illustrates energy conversion among different forms of energy. The correct answer is a. Gravitational potential energy, kinetic energy, and elastic potential energy. Initially, the toy has elastic potential energy due to the compression of the spring. When the spring is released, this energy is converted into kinetic energy as the toy begins to move. As the toy moves up a slope, kinetic energy is gradually converted into gravitational potential energy. The toy's energy transitions between these forms without any loss if we assume negligible friction and air resistance, consistent with the Law of Conservation of Mechanical Energy.

Yes the formula of resistivity is:

[tex]R=\dfrac{\rho l}{A}[/tex]

Where [tex]\rho[/tex] is relativistic resistance with units [tex]\dfrac{\Omega}{m}[/tex], each metal has different relativistic resistance you must find the relativistic resistance of your material using the table of relativistic resistances.

[tex]l[/tex] stands for the length of a wire.

[tex]A[/tex] stands for the area of the wire. Usually it is equal to [tex]\pi r^2[/tex] because.

So now we have data [tex]A=1cm^2[/tex] but nothing else was specified so we are unable to calculate anything.

Hope this helps.

r3t40

Answer:

Your answer is going to be 1 cm.

Explanation:

Answer:

The center of the Milky Way most likely contains a supermassive black hole.

Explanation:

Because it is  an eleptical galaxy, it has a little rotation to it but not enough to flatten out so the center will contain a supermassive black hole.

Projectile motion refers to an object in motion in the air, affected only by gravity. Attributes of such motion include gravity pulling the object down, inertia propelling it forward, and a parabolic trajectory resulting from these forces.

Projectile motion describes the movement of an object thrown or projected into the air and is influenced solely by gravity, which is the only force acting upon it accelerating the object downwards. The aspects that describe this motion include the following: Gravity acts to pull the object down, the object's inertia carries it forward in the direction it was thrown, and the path of the object is indeed curved due to the gravity acting on it. Option A and D

An object in projectile motion does not move in a straight path (therefore, option B is incorrect), and the forward velocity of the object is not 0 m/s as it has initial velocity in the horizontal direction (thus, option C is also incorrect). The combination of the forward motion and the acceleration due to gravity results in a parabolic trajectory, which signifies a two-dimensional motion.

Explanation:

The Work [tex]W[/tex] done by a Force [tex]F[/tex] refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  

Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:  

[tex]W=(F)(d)[/tex] (1)  

In this case both (the force and the distance in the path) are parallel (this means they are in the same direction), so the work [tex]W[/tex] performed is the product of the force exerted to push the box [tex]F=45N[/tex] by the distance traveled [tex]d=12m[/tex].

Hence:  

[tex]W=(45N)(12m)[/tex]   (2)

[tex]W=540Nm=540J[/tex]

Answer: W

Explanation:

For Edmentum the answer is simply   W

Answer:

The two integers are 28 and 9

Explanation:

Let's call the two integers x and y.

We have:

- The largest of the 2 integers is one more than three times the smaller: this means

x = 3y + 1 (1)

- The sum of the two integers is 37:

x + y = 37 (2)

It's a system of two equations that we can solve. Substituting directly (1) into (2),

3y + 1 + y = 37

4y + 1 = 37

4y = 36

y = 9

And so,

x = 3y + 1 = 3(9) + 1 = 27 +1 = 28

So the two integers are 28 and 9.

Answer:

D or 49.7°

Explanation:

You are given the equation and all the information you need, so you simply need to understand what the question asks for and answer appropriately. Notice that the light wave travels from the water to air. This means that water should be labelled with a "1" as it comes prior to air, which should be labeled "2". Thus, all you need to do, is plug and chug:

[tex]\theta_2 = sin^{-1}(\frac{n_1sin(\theta_1)}{n_2}) = sin^{-1}(\frac{(1.33)sin(35)}{1})[/tex]

[tex]\theta_2 = sin^{-1}(0.763) = 49.7^o[/tex]

And, therefore, your answer is D, 49.7°.

Answer: [tex]3.524(10)^{22}N[/tex]

Explanation:

According to Newton's law of Gravitation, the force [tex]F[/tex] exerted between two bodies of masses [tex]m1[/tex] and [tex]m2[/tex]  and separated by a distance [tex]r[/tex]  is equal to the product of their masses and inversely proportional to the square of the distance:

[tex]F=G\frac{(m1)(m2)}{r^2}[/tex]   (1)

Where:

[tex]G[/tex] is the Gravitational Constant and its value is [tex]6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}[/tex]

[tex]m1=1.99(10)^{30}kg[/tex] is the mass of the Sun

[tex]m2=5.972(10)^{24}kg[/tex] is the mass of the Earth

[tex]r=1.50(10)^{11}m[/tex]  is the distance between the Sun and the Earth

Substituting the values in (1):

[tex]F=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.99(10)^{30}kg)(5.972(10)^{24}kg)}{(1.50(10)^{11}m)^2}[/tex]   (2)

Finally:

[tex]F=3.524(10)^{22}N[/tex]   This is the gravitational force of the Sun on the Earth.

Final answer:

The resulting force is approximately 3.54  times [tex]10^{22}[/tex] N.

Explanation:

The question pertains to calculating the gravitational force exerted by the Sun on Earth which can be found using Newton's law of universal gravitation. The formula for the gravitational force F between two masses m1 and m2 separated by a distance r is given by F = G * (m1 * m2) / [tex]r^2[/tex], where G is the gravitational constant (6.67430 times [tex]10^{-11}[/tex]N times[tex](m/kg)^2[/tex]).

Given the mass of the Sun (m1) is 1.99 times [tex]10^{30}[/tex]kg, the mass of the Earth (m2) is 5.972 times [tex]10^{24}[/tex] kg (approximately, for ease of calculation), and the average distance (r) between the Earth and Sun is 1.50 times [tex]10^{11}[/tex] m, we can substitute these values into the gravitational force formula to generate accurate answer.

Therefore, the gravitational force of the Sun on the Earth is calculated to be approximately 3.54 times [tex]10^{22}[/tex]N.

Answer:

B. Slow down to the speed that allows you to have complete control of your vehicle.

Explanation:

Your life is very important, and driving at the same speed as others or even closely behind could endanger your life. Being directly behind someone else, if they stop immediately you will hit them because you can't stop fast enough. If something feels unsafe never continue doing it.

Answer:

B.  slow down to the speed that allows you to h ave complete control of  your vehicle.

Explanation:

You can also reduce the risk of external factors by slowing down and keeping a safe distance from the vehicle in front of you.

Answer:

B. A large cross sectional area,

Explanation:

To permit a large flow of water in a pipe, the cross sectional area of the pipe must be significantly large. According to the flow rate equation:

                    V = [tex]\frac{Q}{A}[/tex]

Where:

           Q is the Volume flow rate and it is the volume of fluid that flows              through the pipe

            V is the velocity of the fluid in the pipe

            A is the cross sectional area of the pipe.

From the equation, we see that for a larger amount of water to flow in a pipe, the cross-sectional area must be very large. In short, Q varies directly as A.

Answer:

a large cross-sectional area

Explanation:

Answer:

D. -m

Explanation:

The magnification of an image is equal to the following ratio:

[tex]m = \frac{y'}{y}[/tex]

where

y' is the size of the image

y is the size of the real object

We have two situations:

- When m is positive, it means that y' has the same sign of y --> so the image has same orientation of the object (= image is upright)

- When m is negative, it means that y' has opposite sign to y --> so the image has opposite orientation to the object (= image is upside down)

So, the correct answer that describes an upside-down image is

D. -m

Final answer:

The representation of an upside-down image in optical physics is given as option D. -m, indicating a negative magnification, which means the image is inverted relative to the object.

Explanation:

The question is related to the formation of images by mirrors or lenses in physics and specifically refers to the sign conventions used to describe the nature of images. An upside-down image is produced when the magnification (m) is negative. This negative magnification indicates that the image is inverted relative to the object. In optics, a real image (produced by a single lens or mirror that can be displayed on a screen) is considered to be upside down if its magnification is negative. Thus, the option that represents an upside-down image is D. -m.

Answer:

energy cannot be created or destroyed

Explanation:

Energy can't be created nor destroyed; rather, it transforms from one form to another.

Answer:

The law of conservation of energy states that energy  cannot be  created or destroyed.

(a) 0.439

The potential energy of a satellite in orbit is given by

[tex]U=-\frac{GmM}{R+h}[/tex]

where

G is the gravitational constant

m is the mass of the satellite

M is the mass of the Earth

R is the Earth's radius

h is the altitude of the satellite

If we call

[tex]U_A=-\frac{GmM}{R+h_A}[/tex]

the potential energy of satellite A, with

[tex]h_A = 6380 km = 6.38\cdot 10^6 m[/tex]

being its altitude, and

[tex]U_B=-\frac{GmM}{R+h_B}[/tex]

the potential energy of satellite B, with

[tex]h_B = 22700 km = 22.7\cdot 10^6 m[/tex]

being the altitude of satellite B

and

[tex]R=6370 km = 6.37 \cdot 10^6 m[/tex] being the Earth's radius

The ratio between the potential energy of satellite B to that of satellite A will be

[tex]\frac{U_B}{U_A}=\frac{R+h_A}{R+h_B}=\frac{6.37\cdot 10^6 m+6.38\cdot 10^6 m}{6.37\cdot  10^6 m+22.7\cdot 10^6 m}=0.439[/tex]

(b) 0.439

The kinetic energy of a satellite in orbit has a similar expression to the potential energy

[tex]K=\frac{1}{2} \frac{GmM}{R+h}[/tex]

As before, if we call

[tex]K_A=\frac{1}{2} \frac{GmM}{R+h_A}[/tex]

the kinetic energy of satellite A, with

[tex]h_A = 6380 km = 6.38\cdot 10^6 m[/tex]

being its altitude, and

[tex]K_B=\frac{1}{2} \frac{GmM}{R+h_B}[/tex]

the kinetic energy of satellite B, with

[tex]h_B = 22700 km = 22.7\cdot 10^6 m[/tex]

being the altitude of satellite B,

the ratio between the kinetic energy of satellite B to that of satellite A is

[tex]\frac{K_B}{K_A}=\frac{R+h_A}{R+h_B}=\frac{6.37\cdot 10^6 m+6.38\cdot 10^6 m}{6.37\cdot  10^6 m+22.7\cdot 10^6 m}=0.439[/tex]

(c) Satellite B

The total energy of each satellite is given by the sum of the potential energy and the kinetic energy:

[tex]E= U+K = -\frac{GMm}{R+h}+\frac{1}{2} \frac{GMm}{R+h}=-\frac{1}{2}\frac{GMm}{R+h}[/tex]

For satellite A we have:

[tex]E_A = -\frac{1}{2}\frac{GMm}{R+h_A}[/tex]

While for satellite B we have

[tex]E_B = -\frac{1}{2}\frac{GMm}{R+h_B}[/tex]

We see that the total energy is inversely proportional to the altitude of the satellite: therefore, the higher the satellite, the smaller the energy. So, satellite A will have the greater total energy (in magnitude), since [tex]h_A < h_B[/tex]; however, the value of the total energy is negative, so actually satellite B will have a greater energy than satellite A.

(d) [tex]3.07\cdot 10^8 J[/tex]

The total energy of satellite A is

[tex]E_A = -\frac{1}{2}\frac{GMm}{R+h_A}[/tex]

with

[tex]h_A = 6380 km = 6.38\cdot 10^6 m[/tex]

while the total energy of satellite B is

[tex]E_B = -\frac{1}{2}\frac{GMm}{R+h_B}[/tex]

with

[tex]h_B = 22700 km = 22.7\cdot 10^6 m[/tex]

So the difference between the two energies is

[tex]E_B - E_A = -\frac{1}{2}\frac{(6.67\cdot 10^{-11}(35 kg)(5.98\cdot 10^{24} kg)}{6.37\cdot 10^6 m +22.7\cdot 10^6 m}-(-\frac{1}{2}\frac{(6.67\cdot 10^{-11}(35 kg)(5.98\cdot 10^{24} kg)}{6.37\cdot 10^6 m +6.38\cdot 10^6 m})=3.07\cdot 10^8 J[/tex]

Ionic compounds have high melting points due to the strong electrostatic forces of attraction between ions, which require a great deal of energy to break.

The high melting points of ionic compounds are best explained by the B option: ionic bonds require a great deal of energy to break. This is because ionic compounds are formed by the strong electrostatic forces of attraction between positively charged cations and negatively charged anions. This strong inter-ionic bonding makes ionic compounds hard, requiring substantial energy to overcome and result in a high melting point.

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Answer: Protons

Explanation: The number of protons corresponds to the atomic number.

Explanation:

Atomic number is defined as the total number of protons present in an element.

Each element of the periodic table has different atomic number because each of them have different number of protons.

For example, atomic number of Na is 11, and atomic number of Ca is 20.

On the other hand, atomic mass is the sum of total number of protons and neutrons present in an atom.

For example, atomic mass of nitrogen is 14 that is, it contains 7 protons and 7 neutrons.

Thus, we can conclude that all atoms of the same element must have the same number of protons.

Answer:

Renewable Resources

Explanation:

This is because wind is almost infinite and doesn't pollute.

Answer: Renewable resources

Explanation:

Answer:

Mass will remain constant...

Explanation:

All will change but not mass in gas phase...

Answer:

1.11×10⁶ J

Explanation:

75 mi/hr × (1609.34 m / mi) × (1 hr / 3600 s) = 33.5 m/s

4345 lbf × (1 lbm / lbf) × (1 kg / 2.2 lbm) = 1975 kg

KE = 1/2 mv²

KE = 1/2 (1975 kg) (33.5 m/s)²

KE = 1.11×10⁶ J

The kinetic energy of the automobile weighing 4345lb and with a speed of 75mph is 1.1077 × 10⁶J

Given the data in the question;

[we convert from pound to kilogram]

[ we convert from miles per hour to meter per second]

Kinetic energy; [tex]K.E = ?[/tex]

We know that, Kinetic Energy ( K.E ) is a form of energy that a matter possesses by reason of its motion.

It is directly proportional to the mass of the matter and to the square of its velocity.

That is; [tex]K.E = \frac{1}{2} mv^2[/tex]

To find the Kinetic Energy, we simply substitute our given values into the equation

[tex]K.E = \frac{1}{2}\ * 1970.859kg\ *\ ( 33.528m/s)^2\\\\K.E = 1107747.69 kg.m^2/s^2\\\\K.E = 1.1077 * 10^6 J[/tex]

Therefore, the kinetic energy of the automobile weighing 4345lb and with a speed of 75 mph is 1.1077 × 10⁶J

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Answer: 1

Explanation: The highest eccentricity an ellipse can have is '1', a straight line.

The maximum eccentricity an ellipse can have is 1.0, which makes the ellipse appear 'flat' or extremely elongated. Eccentricity is the ratio of the distance between the foci and the length of the major axis.

In the world of Mathematics, specifically within the context of Geometry, an Ellipse is a particular shape that can be modified by altering its eccentricity. The eccentricity of an ellipse is determined by the ratio of the distance between the two foci and the length of the major axis.

The eccentricity thus dictates the roundness of the ellipse. For instance, if the eccentricity is zero, the ellipse is indeed a circle. As the eccentricity increases, the ellipse becomes more elongated. The maximum eccentricity an ellipse can have is 1, beyond which the ellipse would be considered a line. When the eccentricity is exactly 1, the ellipse is at its most elongated state, appearing almost 'flat'.

To make it more precise, eccentricity is calculated as e = f/a where 'f' is the distance from the center of the ellipse to one of the foci, and 'a' is half the long axis.

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Answer:

1. The source of power

2. Connection and accessories including, the power cable condition, switches and light bulbs

Explanation:

The items listed above should be tested with a suitable probe and any identified defective component should be replaced

Answer:

8,000 miles and for 2 years

Explanation:

from May 14, 1804, to September 23, 1806, from St. Louis, Missouri, to the Pacific Ocean and back Lewis and Clark traveled. They traveled nearly 8,000 miles (13,000 km). There expedition was called Corps of Discovery.

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-A.Hazle