The difference between 2 times x and y is less than or equal to 1

Answer:

( f + g ) (x) = [tex] 2 x^{2}  + x - 4[/tex]

g(x) - f(x) = [tex] x^{2}  - 2 x - 4[/tex]

Step-by-step explanation:

( f + g ) (x) = f(x) + g(x)

                = [tex] 4 x - 4 + 2  x^{2}  - 2 x[/tex]

                = [tex] 2 x^{2} + x -4[/tex]

   2.  g(x) = [tex] x^{2}  + 1[/tex] and f(x) = 2 x + 5

g(x) - f(x) = [tex] x^{2}  + 1 - (2 x + 5)[/tex]

              = [tex] x^{2}  + 1 - 2 x - 5[/tex]

              = [tex] x^{2}  - 2 x - 4[/tex]

Answer:
B: 180.3

Step-by-step explanation:

A^2 + B^2 = C^2
150^2 + 100 ^2 = 32500
square root of 32500
180.3

+ 10 is the missing step in the given chart.

Step-by-step explanation:

Given data from the Flow chart,

Start = 20,

End = 6,

Second Step is ÷ 5.

Let us form the given information into two equations,

Consider the missing value as X.

20+X=Y  ⇒1

Y÷5=6   ⇒2

where Y is the value of middle box.

From equation 1,

Y=6×5

Y=30.

From equation 2,

20+X=30.

X=30-20.

X= 10.

Thus + 10 is the missing step.

did you ever complete this?  

Step-by-step explanation:

If you ddi please send it to me

Answer:

3

Step-by-step explanation:

Give me brainliest

Answer:

54 sandwiches were Turkey.

60 x .94 = 54

Step-by-step explanation:

Answer:

Adrian would make $196000 in his 26th year working.

Step-by-step explanation:

Adrian salary in first year = $66,000

As Adrian is expected to get raises of $5,000 every year going forward.

Here is the sequence of Adrian's raises:

5,000, 10000, 15000, 20000, 25000 .....

As the common difference between consecutive terms is constant.

d = 10000 -  5,000 = 5,000 ⇒ d = 15000 -  10000 = 5,000

So, Adrian's raises is in Arithmetic sequence.

a₁ = 5,000

n = 26

[tex]{\displaystyle \ a_{n}=a_{1}+(n-1)d}[/tex]

Put n = 26 to get the total amount of salary raises in Adrian's 26th year.

[tex]{\displaystyle \ a_{26}=5000+(26-1)5000}[/tex]

[tex]{\displaystyle \ a_{26}=5000+(25)5000}[/tex]

[tex]{\displaystyle \ a_{26}=5000+125000}[/tex]

[tex]{\displaystyle \ a_{26}=130000}[/tex]

Total raises amount after 26th year = $130000

Adding total raises after 26th year to the initial salary would let us figure out the total salary Adrian would make in his 26th year.

So,

Total Salary after 26th year = initial salary + total raises of 26 years

                                              = 66000 + 130000

                                              = $196000

So, Adrian would make $196000 in his 26th year working.

Keywords: arithmetic sequence, salary, raises, common difference

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Answer:

256a^20b^24

Step-by-step explanation:

[tex]\dfrac{x+6}{x+2}=\dfrac{x+3}{x-5}\qquad\qquad\text{cross multiply}\\\\(x+6)(x-5)=(x+2)(x+3)\\\\x^2-5x+6x-30=x^2+3x+2x+6\\\\x^2+x-30=x^2+5x+6\\\\x^2+x-x^2-5x=6+30\\\\-4x=36\quad|:(-4)\\\\\boxed{x=-9}[/tex]

Answer C.

Answer:

The system has no solution.

Step-by-step explanation:

Write the system as

y - 4x =3

2y - 8x = 3

The 2nd equation can be written as

2(y - 4x)

and the system would be

y - 4x =3

2(y - 4x) = 3

Now, call y -4x = z. Then we would have the system

z = 3

2z = 3

But if z =3 then 2z = 6 and we have a contradiction.

We conclude that the system has no solution.

Answer: b - 8

Step-by-step explanation:

Answer:

same

Step-by-step explanation:

Answer:

The numbers of weeks for which both Ava and Addison have same amount of money saved is 100 weeks .

Step-by-step explanation:

Given as :

The amount of money having with Ava at starting = $100

The money that Ava is saving each week = $5

The amount of money having with Addison at starting = $200

The money that Addison is saving each week = $4

Now, Let The numbers of weeks for which both Ava and Addison have same amount of money saved = n weeks

Now, According to question

The amount of money having with Ava at starting + (The money that Ava is saving each week × numbers of weeks) = The amount of money having with Addison at starting + (The money that Addison is saving each week × numbers of weeks)

Or, $100 + $5 × n = $200 + $4 × n

Or, $5 × n - $4 × n = $200 - $100

Or, n = 100

So,  The numbers of weeks for which both Ava and Addison have same amount of money saved = n = 100 weeks

Hence,The numbers of weeks for which both Ava and Addison have same amount of money saved is 100 weeks . Answer

Answer:

-7

Step-by-step explanation:

The question is a mathematics problem related to evaluating functions, but it cannot be answered without additional information about the functions f and g.

The question asks for the result when evaluating two functions f and g at given arguments and then combining these evaluated results with given coefficients. Specifically, it asks to compute the value of − 1 ⋅ f(− 8) minus 4 ⋅ g(4). However, without additional information about the functions f and g, it's not possible to calculate the exact numeric answer. Students usually encounter this type of problem while learning about functions and their evaluations in algebra.

Answer:

x= -12.6/7. you may try this

Good evening ,

Answer:

The solutions of the equation 7x(x+1.8)=0 are -1.8 and 0.

Step-by-step explanation:

7×(0)×[(0)+1.8] = 0×[1.8] = 0×1.8 = 0

7×(-1.8)×[(-1.8)+1.8] = 7×(-1.8)×[0] = 7×(-1.8)×0 = 0.

:)

Answer:

2,1

Step-by-step explanation:

y=-3x+7

y=-3(2)+7

y=-6+7

y=1

so (2,1)

Answer:

$6 to sweep 1 walk

Step-by-step explanation:

$24 : 4 walks can be simplified by dividing both sides by 4.

24/4:4/4=6:1

Answer:

Width [tex]10y^6[/tex] units

Length [tex]7y^2+3[/tex] units

Step-by-step explanation:

The rectangle has an area of [tex]70y^8+30y^6.[/tex]

The width of the rectangle is equal to the greatest common monomial factor of [tex]70y^8[/tex] and [tex]30y^6.[/tex] Find this monomial factor:

[tex]70y^8=2\cdot 5\cdot 7\cdot y^8\\ \\30y^6=2\cdot 3\cdot 5\cdot y^6\\ \\GCF(70y^8,30y^6)=2\cdot 5\cdot y^6=10y^6[/tex]

Hence, the width of the rectangle is [tex]10y^6[/tex] units.

The area of the rectangle can be rewritten as

[tex]10y^6(7y^2+3).[/tex]

The area of the rectangle is the product of its width by its length, then the length of the rectangle is [tex]7y^2+3[/tex] units.

Answer:

3.  (4+5)+5 = 4 +10  expresses the ASSOCIATIVE PROPERTY OF ADDITION.

Step-by-step explanation:

The associative property of addition is given as:

For any three numbers A, B and C

(A +B) + C = A + ( B+ C)

Here, the ORDER OF ADDITION is not important, answer is always the SAME.

Now, in the following given expressions:

1.  (3+7)+(2+8)=(7+3)+(8+2)

Here, ( 3+ 7)in L H S is replaced with ( 7 + 3) in R H S

Similarly,  ( 2+ 8)in L H S is replaced with (8 + 2) in R H S

Hence, the given expression is expresses the Commutative PROPERTY OF ADDITION.

2. (5)(3-4)=(5-3)(4)

Here, the operation between 5 and (3-4) is MULTIPLICATION

Hence, the given expression DO NOT expresses the ASSOCIATIVE PROPERTY OF ADDITION.

3.  (4+5)+5 = 4 +10

Here, the form of ASSOCIATIVE PROPERTY OF ADDITION is

(4 +5 )+5  = 4 + (5 + 5)  = 4 + (10)

So, the given expression expresses the ASSOCIATIVE PROPERTY OF ADDITION.

4.  2(5+4)=10+8

Here, the operation between 2 and (5 + 4) is MULTIPLICATION

Hence, the given expression DO NOT expresses the ASSOCIATIVE PROPERTY OF ADDITION.

The associative property of addition means the way numbers are grouped in an addition does not change the sum. From the given equations, equation (1) illustrates this property as shown by the same results 20 in both groupings (3+7)+(2+8) or (7+3)+(8+2).

The associative property of addition is a property in Mathematics that states that the way in which numbers are grouped when added does not change the sum. From the given equations, equation (1) (3+7)+(2+8)=(7+3)+(8+2) perfectly shows this property. It demonstrates that it doesn't matter how we group the numbers when we're adding them - the result will be the same.

For example, in equation (1), (3+7)+(2+8), if we add the numbers in brackets first, we get 10 + 10 = 20. This is the same result we get if we re-group the numbers like this: (7+3)+(8+2), that is, 10 + 10 = 20.

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Answer:

1242

Step-by-step explanation:

[tex]1. \: 6(15 - 5 + 3)4 \times 4 - 6 \\ 2. \: 6(10 + 3)4 \times 4 - 6 \\ 3. \: 6(13)4 \times 4 - 6 \\ 4. \: 78 \times 4 \times 4 - 6 \\ 5. \: 312 \times 4 - 6 \\ 6. \: 1248 - 6 \\ 7. \: = 1242[/tex]

$5.99 divided by 100 = 0.0599

0.0599 x 237 = $14.19

Answer:

a. 5/30 and 1/6 ---> are equal

b.4/12 and 21/60 ---> are not equal

c. 17/34 and 41/82 ---> are equal

d. 6/9 and 25/36​ ---> are not equal

Step-by-step explanation:

case a) we have  5/30 and 1/6

equate the fractions

[tex]\frac{5}{30}=\frac{1}{6}[/tex]

using cross multiplication

[tex](5)(6)=(30)(1)[/tex]

[tex]30=30[/tex] ----> is true

therefore

The fractions are equal

case b) we have  4/12 and 21/60

equate the fractions

[tex]\frac{4}{12}=\frac{21}{60}[/tex]

using cross multiplication

[tex](4)(60)=(21)(12)[/tex]

[tex]240=252[/tex] ----> is not true

therefore

The fractions are not equal

case c) we have  17/34 and 41/82

equate the fractions

[tex]\frac{17}{34}=\frac{41}{82}[/tex]

using cross multiplication

[tex](17)(82)=(41)(34)[/tex]

[tex]1,394=1,394[/tex] ----> is true

therefore

The fractions are equal

case d) we have  6/9 and 25/36​

equate the fractions

[tex]\frac{6}{9}=\frac{25}{36}[/tex]

using cross multiplication

[tex](6)(36)=(25)(9)[/tex]

[tex]216=225[/tex] ----> is not true

therefore

The fractions are not equal

Answer:

a. The fractions are equal.

b. The fractions are not equal

c. The fractions are equal.

d. The fractions are not equal

Step-by-step explanation:

By definition, equivalent fractions have the same value, but they look different.

In order to verify if two fractions are equivalent, you can use Cross multiplication.

The procedure is: multiply the numerator of the first fraction by the denominator of the second fraction, and the numerator of the second fraction by the denominator of the first fraction.

Then:

[tex]a.\ \frac{5}{30}=\frac{1}{6}\\\\5*6=1*30\\\\30=30\ (The\ fractions\ are\ equal)[/tex]

[tex]b.\ \frac{4}{12}=\frac{21}{60}\\\\4*60=21*12\\\\240=252\ (FALSE.\ The\ fractions\ are\ not\ equal)[/tex]

[tex]c.\ \frac{17}{34}=\frac{41}{82}\\\\17*82=41*34\\\\1394=1394\ (The\ fractions\ are\ equal)[/tex]

[tex]d.\ \frac{6}{9}=\frac{25}{36}\\\\6*36=25*9\\\\216=225\ (FALSE.\ The\ fractions\ are\ not\ equal)[/tex]

Answer:

(-8 - 4)/(-4 - 0) = -12/-4= 3

y - 4 = 3(x - 0)

y - 4 = 3x - 0

y = 3x + 4

the answer is c

Answer:

4

Step-by-step explanation:

Consecutive integers are  e.g.  1, 2, 3, 4, ...

So they are 1 units apart.

If we let one of the integers be "x", then the next consecutive one would be "x + 1".

x is the smaller

x + 1 is the larger

of the two...

Now,

The sum of smaller (x) and 2 TIMES larger (x + 1) is 14, so we can write:

[tex]x+2(x+1)=14[/tex]

We use algebra and solve for x:

[tex]x+2(x+1)=14\\x+2x+2=14\\3x=14-2\\3x=12\\x=4[/tex]

So, the two numbers is 4  &  5

smaller of the two numbers is "4"

To find the smaller of two consecutive integers where the sum of the smaller and two times the larger is 14, set up the equation x + 2(x + 1) = 14 and solve for x to find that the smaller integer is 4.

To find the smaller of two consecutive integers x, when the sum of the smaller and two times the larger is 14, we can set up a simple algebraic equation. Let x be the smaller integer; then the larger integer is x+1. The equation based on the given information is:

x + 2(x + 1) = 14

Now, let's solve for x:

Therefore, the smaller consecutive integer is 4.

Answer:

The Area of land is 30 × [tex]10^{7}[/tex] meters² .

Step-by-step explanation:

Given as :

The length of rectangular wheat farm land = L = 5 × [tex]10^{4}[/tex]  meter

The width of rectangular wheat farm land = w = 6 × [tex]10^{3}[/tex]  meter

Let The Area of land = A meters²

Now, According to question

∵ Land is in rectangular shape

And we know, Area of rectangle = length × width

∴ Area of land =  Area of rectangle = length × width

Or, A = L × w

Or, A = 5 × [tex]10^{4}[/tex]  meter × 6 × [tex]10^{3}[/tex]  meter

Or , A = 30 × [tex]10^{4+3}[/tex]

i.e A = 30 × [tex]10^{7}[/tex]  meters²

So, The Area of land = A  = 30 × [tex]10^{7}[/tex] meters²

Hence,The Area of land is 30 × [tex]10^{7}[/tex] meters² . Answer

Answer:

-2475

Step-by-step explanation:

Answer:

Step-by-step explanation:

a.) Let x be the number of tickets sold before the event and y the number of tickets sold on the day of the event. Then x + y =< 800 and 6x + 9y >= 5000. (b.) Suppose the club sold 440 tickets before the event, i.e. x = 440, maximum number of tickets remaining to be sold = 800 - 440 = 360. Maximum amount realized from the sales supposing all tickets were sold = 6(440) + 9(360) = 2640 + 3240 = $5880 which is greater than $5000. Therefore, it is possible for the club to sell enough additional tickets on the day of the show to meet the expenses of the show.

HOPE THIS HELPED ;3

Answer:

The annual premium will be =  $1080

Step-by-step explanation:

Total life insurance term amount = $200,000

The term life insurance rate per $1000 = $5.40

Let’s divide total term amount i.e. $200,000 by $1000 unit to get the total number  of $1000 units in $200,000

So, $200,000 ÷ $1000 = 200

So, it is clear that 200 would be the total number of $1000 units in total term life  insurance amount of $200,000.

Therefore, if rate per unit $1000 is $5.40, then we must have to multiply $5.40 by 200 to find the  annual premium as the total number of $1000 units in total term life insurance amount  

of $200,000 is 200.  

So, $5.40 × 200 = $1080

Hence, the annual premium will be = $1080

Keywords: insurance, premium, annual premium

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Answer:

50 Minutes.

Step-by-step explanation:

The function c approximates the total number of calls made after m minutes since the start of the phone tree.

[tex]c(m)=\frac{2}{3}\times (3^{\frac{m}{10}}-1)[/tex]

We need to find the number of minutes after which the total number of calls will 363.

Substitute c(m)=363 in the given function.

[tex]363=\frac{2}{3}\times (3^{\frac{m}{10}}-1)[/tex]

Multiply 3/2 both sides.

[tex]363\times \frac{3}{2}=(3^{\frac{m}{10}}-1)[/tex]

[tex]242=3^{\frac{m}{10}}-1[/tex]

Add 1 on both sides.

[tex]243=3^{\frac{m}{10}}[/tex]

[tex]3^5=3^{\frac{m}{10}}[/tex]

On comparing both sides we get

[tex]5=\frac{m}{10}[/tex]

Multiply both sides by 10.

[tex]50=m[/tex]

Therefore, the total number of calls will 363 after 50 minutes since the start of the phone tree.

Answer:

50 minutes

Step-by-step explanation:

Answer:

n=-4

Step-by-step explanation:

n=56/-14

n=-4