Answer:
False
Explanation:
In an entity relationship (ER) model, which is the conceptual illustration of certain entities and the relationships that exist between them, the cardinality of a relationship is the possible (minimum and maximum) number of entity occurrences that can be associated or involved in it.
Note: An entity is a real world object that is being modeled.
For example, a school has many staff members. The school and the staff members are the objects while the relationship between the school and the staff members is one-to-many.
One, many, zero are all values of cardinality.
Using a script (code) file, write the following functions:
1. Write the definition of a function that take one number, that represents a temperature in Fahrenheit and prints the equivalent temperature in degrees Celsius.
2. Write the definition of another function that takes one number, that represents speed in miles/hour and prints the equivalent speed in meters/second.
3. Write the definition of a function named main. It takes no input, hence empty parenthesis, and does the following:
O prints Enter 1 to convert Fahrenheit temperature to Celsius
O prints on the next line, Enter 2 to convert speed from miles per hour to meters per second.
O take the input, lets call this main input, and if it is 1, get one input then call the function of step 1 and pass it the input.
O if main input is 2, get one more input and call the function of step 2.
O if main input is neither 1 or 2, print an error message.
After you complete the definition of the function main, write a statement to call main.
Below is an example of how the code should look like:
#Sample Code by Student Name #Created on Some Date #Last Edit on Another Date
def func1(x):
print(x)
def func2(y):
print(y)
print(' ')
print(y)
def main():
func1('hello world')
func2('hello again')
#below we start all the action
main()
Remember to add comments, and that style and best practices will counts towards the points. A program that just "works" is not a guarantee for full credit. Submit your source code file.
Answer:
def func1(x):
return (x-32)*(5/9)
def func2(x):
return (x/2.237)
def main():
x = ""
while x != "x":
choice = input("Enter 1 to convert Fahrenheit temperature to Celsius\n"
"Enter 2 to convert speed from miles per hour to meters per second: ")
if choice == "1":
temp = input("please enter temperature in farenheit: ")
print(func1(float(temp))," degrees celcius.")
elif choice == "2":
speed = input("please enter speed in miles per hour: ")
print(func2(float(speed))," meters per second")
else:
print("error... enter value again...")
x = input("enter x to exit, y to continue")
if __name__ == "__main__":
main()
Explanation:
two function are defines func1 for converting temperature from ferenheit to celcius and func2 to convert speed from miles per hour to meters per second.
Which of the following will equal the average time that a customer is in the system?
a. The average number in the system divided by the arrival rate.
b. The average number in the system multiplied by the arrival rate.
c. The average time in line plus the average service time.
Answer:
C. The average time in line plus the average service time.
Explanation:
Customer services is a skill in business that requires interactivity with customers, and an approach to gaining their trust and loyalty.
A queue is a straight line arrangement of entities. Customer service queueing system is a queue of customers, taking turns for a product or service.
The average time a customer spends in a system is equivalent to the average time on queue plus the average time for services rendered to customers before him and including him.
Given numRows and numColumns, print a list of all seats in a theater. Rows are numbered, columns lettered, as in 1A or 3E. Print a space after each seat, including after the last. Ex: numRows = 2 and numColumns = 3 prints:
1A 1B 1C 2A 2B 2C
#include
using namespace std;
int main() {
int numRows;
int numColumns;
int currentRow;
int currentColumn;
char currentColumnLetter;
cin >> numRows;
cin >> numColumns;
/* Your solution goes here */
cout << endl;
return 0;
}
The summary of the missing instructions in the program are:
Looping statements to iterate through the rows and the columnA print statement to print each seatThe solution could not be submitted directly. So, I've added it as attachments.
The first attachment is the complete explanation (that could not be submitted)The second attachment is the complete source file of the corrected codeRead more about C++ programs at:
https://brainly.com/question/12063363
If you think a query is misspelled, which of the following should you do? Select all that apply.
A) Assign a low utility rating to all results because misspelled queries don't deserve high utility ratings.
B) Release the task.
C) For obviously misspelled queries, base the utility rating on user intent.
D) For obviously misspelled queries, assign a Low or Lowest Page Quality (PQ) rating.
Answer:
The answer is: letter C, For obviously misspelled queries, base the utility rating on user intent.
Explanation:
The question above is related to the job of a "Search Quality Rater." There are several guidelines which the rater needs to consider in evaluating users' queries. One of these is the "User's Intent." This refers to the goal of the user. A user will type something in the search engine because he is trying to look for something.
In the event that the user "obviously" misspelled queries, the rate should be based on his intent. It should never be based on why the query was misspelled or how it was spelled. So, no matter what the query looks like, you should assume that the user is, indeed, searching for something.
Rating the query will depend upon how relevant or useful it is and whether it is off topic.
Answer:
C) For obviously misspelled queries, base the utility rating on user intent.
Explanation:
Query is the term used to describe a language that the computer uses to perform query activities in different databases. It is important that the query is done correctly, or the data found by it may not be ideal for what the user is looking for. However, if the user suspects that a query is showing inefficient results, or that the query is incorrect, the ideal thing to do is to make sure that the query is incorrect and obtain results based on the utility rating on user intent.
Write a program that prompts the user to input the number of quarters, dimes, and nickels. The program then outputs the total value of the coins in pennies.
Final answer:
The question asks for a program to calculate the total value in pennies of a given number of quarters, dimes, and nickels, with a solution presented in Python.
Explanation:
Each quarter is worth 25 pennies, each dime is worth 10 pennies, and each nickel is worth 5 pennies. To calculate the total value, you multiply the number of each type of coin by its value in pennies and sum up these values.
For example, if a user inputs 3 quarters, 2 dimes, and 1 nickel, the program will calculate the total value as (3 * 25) + (2 * 10) + (1 * 5) = 95 pennies.Sample Python code:
quarters = int(input('Enter the number of quarters: '))A sysadmin is looking to use Pre Booth Execution over a network by keeping operating system installation files on a server. Which type of server is this most likely to be?
SFTP server
TFTP server
FTP server
DNS server
Answer:
The correct answer is letter "B": TFTP server.
Explanation:
A TFTP server allows the system administrator to install programs on other computers from the same network and keeping a registry. This is mainly done to prevent loss of information in the case the network is corrupted or if one of the computers is infected with malicious software.
In this warm up project, you are asked to write a C++ program proj1.cpp that lets the user or the computer play a guessing game. The computer randomly picks a number in between 1 and 100, and then for each guess the user or computer makes, the computer informs the user whether the guess was too high or too low. The program should start a new guessing game when the correct number is selected to end this run (see the sample run below).
Check this example and see how to use functions srand(), time() and rand() to generate the random number by computer.
Example of generating and using random numbers:
#include
#include // srand and rand functions
#include // time function
using namespace std;
int main()
{
const int C = 10;
int x;
srand(unsigned(time(NULL))); // set different seeds to make sure each run of this program will generate different random numbers
x = ( rand() % C);
cout << x << endl;
x = ( rand() % C ); // generate a random integer between 0 and C-1
cout << x << endl;
return 0;
}
Answer:
#include <iostream>
#include <time.h>
using namespace std;
int main()
{
// Sets the random() seed to a relatively random number
srand(time(0));
// Variables are defined
int RandomNumber = rand() % 100 + 1, UserSelection, Tries = 5;
// Gets a number from the user
cout << " Guess a number between 1 and 100, you have five tries to find the correct number.\n :";
cin >> UserSelection;
// Prevents the user from selecting a number out of bounds
while (UserSelection > 100 || UserSelection < 1)
{
cout << " I said between 1 and 100. select a new number BETWEEN 1 AND 100!\n :";
cin >> UserSelection;
}
// Stuck in while till they guess right, or run out of tries
while (UserSelection != RandomNumber)
{
// kicks user from the loop when they run out of tries
Tries -= 1;
if (Tries == 0)
{
break;
}
// Tells the user they got the wrong number and how many tries they have left
cout << " The Number was not correct, you have " << Tries << " more Guess(es) left.";
// Tells the user if they are above the number
if (UserSelection > RandomNumber)
{
cout << " Try guessing a little lower\n :";
}
// Tells the user if they are bellow the number
else if (UserSelection < RandomNumber)
{
cout << " Try guessing a little higher\n :";
}
// User input if the number is wrong they stay in the loop, if they are right they fail the condition for the loop and get dialogue according to how many tries they have left
cin >> UserSelection;
// Prevents the user from selecting a number out of bounds
// If the number is greater than 100 or less than 1 they are prompted to select a new number
while (UserSelection > 100 || UserSelection < 1)
{
cout << " I said between 1 and 100. select a new number BETWEEN 1 AND 100!\n :";
cin >> UserSelection;
}
}
// The amount of tries the user has left determines what dialogue they get
// First try win
if (Tries == 5)
{
cout << " That's not luck, that's skill. you got the number right on the first try.\n ";
system("pause");
}
// Second try win
else if (Tries == 4)
{
cout << " That's pretty good luck, you guessed it right on the second try.\n ";
system("pause");
}
// Third try win
else if (Tries == 3)
{
cout << " Could be better, but it could also be way worse. You got it right on the third try.\n ";
system("pause");
}
// Fourth try win
else if (Tries == 2)
{
cout << " Could be worse, but it could also be a lot better. You got it right on your fourth try.\n ";
system("pause");
}
// Fifth try win
else if (Tries == 1)
{
cout << " I hope you don't gamble much. You got it right on your last guess.\n ";
system("pause");
}
// Losing dialogue
else
{
cout << " You guessed wrong all five times, the right number was " << RandomNumber << "\n ";
system("pause");
}
return 0;
}
Explanation
C++, console based guessing game.
Int Tries at the top of main is linked to how many tries the user has
Read the comments in the code they roughly explain whats going on.
Why is it important that your case and motherboard share a compatible form factor?
When might you want to use a slimline form factor?
What advantages does ATX have over Micro-ATX?
What are two operating systems that can be installed in systems using Mini-ITX motherboard?
Is it possible to identify the form factor without opening the case?
Answer:
It is important for your case to share a compatible form factor because different cases have different compatibilities. For example if you have a Micro-ATX case, a full ATX motherboard would be too large to fit into that case.
You might want to use a slimline form factor if you have limited space.
With a full ATX you will be able to add more as well as larger components, where as if you get a Micro-ATX, you would be limited.
The two OS are Linux and Windows.
Normally you can eye ball it by determining the size and shape of the case.
Explanation:
Suppose a host has a 1-MB file that is to be sent to another host. The file takes 1 second of CPU time to compress 50%, or 2 seconds to compress 60%.
(a) Calculate the bandwidth at which each compression option takes the same total compression + transmission time.
(b) Explain why latency does not affect your answer.
Answer: bandwidth = 0.10 MB/s
Explanation:
Given
Total Time = Compression Time + Transmission Time
Transmission Time = RTT + (1 / Bandwidth) xTransferSize
Transmission Time = RTT + (0.50 MB / Bandwidth)
Transfer Size = 0.50 MB
Total Time = Compression Time + RTT + (0.50 MB /Bandwidth)
Total Time = 1 s + RTT + (0.50 MB / Bandwidth)
Compression Time = 1 sec
Situation B:
Total Time = Compression Time + Transmission Time
Transmission Time = RTT + (1 / Bandwidth) xTransferSize
Transmission Time = RTT + (0.40 MB / Bandwidth)
Transfer Size = 0.40 MB
Total Time = Compression Time + RTT + (0.40 MB /Bandwidth)
Total Time = 2 s + RTT + (0.40 MB / Bandwidth)
Compression Time = 2 sec
Setting the total times equal:
1 s + RTT + (0.50 MB / Bandwidth) = 2 s + RTT + (0.40 MB /Bandwidth)
As the equation is simplified, the RTT term drops out(which will be discussed later):
1 s + (0.50 MB / Bandwidth) = 2 s + (0.40 MB /Bandwidth)
Like terms are collected:
(0.50 MB / Bandwidth) - (0.40 MB / Bandwidth) = 2 s - 1s
0.10 MB / Bandwidth = 1 s
Algebra is applied:
0.10 MB / 1 s = Bandwidth
Simplify:
0.10 MB/s = Bandwidth
The bandwidth, at which the two total times are equivalent, is 0.10 MB/s, or 800 kbps.
(2) . Assume the RTT for the network connection is 200 ms.
For situtation 1:
Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize
Total Time = 1 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.50 MB
Total Time = 1.2 sec + 5 sec
Total Time = 6.2 sec
For situation 2:
Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize
Total Time = 2 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.40 MB
Total Time = 2.2 sec + 4 sec
Total Time = 6.2 sec
Thus, latency is not a factor.
Final answer:
The bandwidth at which each compression option (50% and 60%) takes the same total compression plus transmission time is 10 MBps. Latency does not impact this calculation because it is a separate factor from compression and transmission rates.
Explanation:
To calculate the bandwidth at which each compression option takes the same total compression + transmission time:
For 50% compression: The file size becomes 0.5 MB (50% of 1 MB) which requires 1 second of compression time. This gives a total of 0.5 MB to be transmitted.For 60% compression: The file size becomes 0.4 MB (40% of 1 MB) which requires 2 seconds of compression time. This gives a total of 0.4 MB to be transmitted.Let t be the transmission time and B be the bandwidth in MBps. The total time for both scenarios needs to be equal, so:
For 50% compression: 1 second (compression time) + (0.5 MB / B) = tFor 60% compression: 2 seconds (compression time) + (0.4 MB / B) = tSetting the equations equal to each other gives us:
1 + (0.5 / B) = 2 + (0.4 / B)
After solving, B = 10 MBps.
(b) Latency does not affect the answer because it refers to the delay before the transfer begins and does not impact the rate of data transmission or compression time.
secops focuses on integrating the need for the development team to provide iterative and rapid improvement to system functionality and the need for the operation team to improve and security and minimize the disruption from software release cyces_____________.
A. True.B. False.
Answer:
A. True.
Explanation:
Secops or security- operation is a mechanism that focus on merging and collaborating the security team and the development operation team. It is made to prevent, sacrificing one for the other like the security of an application for the functionality and development of the application.
It tries to create communication between both teams, for every decision made to equally and positively affect both teams operation and result.
Given the multiplication 65535 x 32768, will the result cause overflow on a 32-bit system? Will the result need more than 32 bits to be stored in?
Answer:
65535 x 32768 =214 7450880
which is in the range of 32 bit unsigned integers, so there will be no overflow and we wont be in a need of more bits than 32 bit.
Explanation:
An overflow error indicates that software attempted to write down data beyond the bounds of memory.
Each program features a section of memory allocated for a stack. The stack is employed to store internal data for the program and is extremely fast and keep track of return addressing. A program may jump to a neighborhood that reads some data from the disk drive, then it returns from that routine to continue processing the info. The stack keeps track of the originating address, and therefore the program uses that for the return. Kind of like leaving breadcrumbs to seek out your way back. The stack features a limited amount of space for storing. If software attempts to access a neighborhood of the stack beyond its limits, an overflow error occurs.
• signed 32-bit integers support the range [-2147483648,2147483647]
• unsigned 32-bit integers support the range [0,4294967295]
And if you go outside this range, even temporarily, you would like to be very careful. Most cases handle the overflow technically and provide you "wraparound" or "modulo" behavior where carry bits outside the range just disappear and you're left with the low-order bits like the precise result.
In computer architecture of 32 bit, memory addresses, or other data units are those who are 32 bits (4 octets) wide. Also, 32-bit CPU and ALU architectures are those who have supported registers, address buses, or data buses of that size. 32-bit microcomputers are computers during which 32-bit microprocessors are the norm.
What is the decimal equivalent of the largest binary integer that can be obtained with
a. 11 bits and
b. 25 bits
Answer:
2047 for 11 bits, and 33554431 for 25 bits
Explanation:
The decimal equivalent of the largest binary integer that can be gotten with:
11 bits is 2047 25 bits is 33554431 What is Equivalent decimals?These are known to be to be decimal numbers that is said to have the same value.
Some other Maximum Decimal Value for N Bit are:
Number of Bits Highest States
20 1,048,576
24 16,777,216
32 4,294,967,296, etc.
Learn more about decimal equivalent from
https://brainly.com/question/24797446
Which sort algorithm does the following outline define? for i between 0 and number_used-1 inclusivea. sequential b. non-sequential
Final answer:
The question outline suggests a sequential, iterative approach, consistent with various sorting algorithms like bubble sort, insertion sort, or selection sort, but it is not possible to determine exactly which algorithm is defined without more details.
Explanation:
The algorithm described in the question is not fully detailed, but the mention of for i between 0 and number used-1 inclusive suggests that elements are being processed sequentially, implying an iterative approach. This could be consistent with various sorting algorithms that traverse elements in a sequence, such as bubble sort, insertion sort, or selection sort. However, without additional information on what is specifically happening within the loop or any other steps of the algorithm, it is impossible to definitively determine which sort algorithm is being outlined.
In the following data definition, assume that List2 begins at offset 2000h. What is the offset of the third value (5)?
List2 WORD 3,4,5,6,7
a. 20008h
b. 2002h
c. 2000h
d. 2004h
Answer:
The offset of the third value (5) is 2004h
Explanation:
Offset is the distance from a starting point, either the start of a file or the start of a memory address.
The value is added to a base value to derive the actual offset value.
In the question above,
The base value = 3 because the item is at the 3rd position
Hence, the offset position = 3 + 1 = 4
Note that the offset begins at 2000
So, the offset value of 5 = 2000 + 4
Offset = 2004h
The offset of the third value (5) in the array List2, which begins at offset 2000h, is 2004h because each WORD value occupies 2 bytes, and the index of the third value is 2.
Explanation:The data definition given is for an array of WORD values starting at offset 2000h. In assembly language or low-level programming, a WORD typically represents a 16-bit (2-byte) value. Since the array starts at offset 2000h and each value in the array occupies 2 bytes, we can calculate the offset for each value by adding 2 times the index of the desired value (since indexing starts at 0) to the starting offset.
The third value in the array (which is the value 5) has an index of 2 (as we start counting from 0). Thus, the offset for the third value is computed as:
Starting offset + (Index of value * Size of each value)
2000h + (2 * 2) = 2000h + 4 = 2004h
Hence, the correct offset for the third value in the array is 2004h.
Write a Python function called simulate_observations. It should take no arguments, and it should return an array of 7 numbers. Each of the numbers should be the modified roll from one simulation. Then, call your function once to compute an array of 7 simulated modified rolls. Name that array observations.
Final answer:
The 'simulate_observations' Python function simulates rolling a six-sided die 7 times, storing the results in an array named 'observations'.
Explanation:
To write a Python function called simulate_observations which returns an array of 7 simulated modified rolls, we can use the random module's randint function to simulate the rolling of a six-sided die. The code snippet below defines the function that generates 7 random numbers, each representing the outcome of a die roll, and stores them in an array called observations.
import random
def simulate_observations():
results = []
for _ in range(7):
roll = random.randint(1, 6)
results.append(roll)
return results
observations = simulate_observations()
print(observations)
Each number in the array would be between 1 and 6, representing each side of a fair, six-sided die. Note that the modification mentioned in the question is not specified, thus the standard roll result is used.
The Python function simulate_observations generates an array of 7 modified dice rolls and returns it. The example provided shows step-by-step how to implement and modify the rolls. The resulting array is stored in 'observations'.
To create a Python function called simulate_observations that returns an array of 7 modified dice rolls, you can follow these steps:
Define the function simulate_observations that uses the random module to generate random numbers simulating dice rolls.
Modify each simulated dice roll as specified (for example, by adding a constant to each roll).
Return the array of modified rolls.
Here's an implementation of the function:
import randomThis code will generate 7 random dice rolls, modify each by adding 1, and store them in the observations array. The mean expectation for dice rolls, centered around 3.5 for a fair six-sided die, is slightly adjusted due to modification.
Your program Assignment This game is meant for tow or more players. In the same, each player starts out with 50 points, as each player takes a turn rolling the dice; the amount generated by the dice is subtracted from the player's points. The first player with exactly one point remaining wins. If a player's remaining points minus the amount generated by the dice results in a value less than one, then the amount should be added to the player's points. (As a alternative, the game can be played with a set number of turns. In this case the player with the amount of pints closest to one, when all rounds have been played, sins.) Write a program that simulates the game being played by two players. Use the Die class that was presented in Chapter 6 to simulate the dice. Write a Player class to simulate the player. Enter the player's names and display the die rolls and the totals after each round. I will attach the books code that must be converted to import javax.swing.JOptionPane; Example: Round 1: James rolled a 4 Sally rolled a 2 James: 46 Sally: 48 OK
Answer:
The code is given below in Java with appropriate comments
Explanation:
//Simulation of first to one game
import java.util.Random;
public class DiceGame {
// Test method for the Dice game
public static void main(String[] args) {
// Create objects for 2 players
Player player1 = new Player("P1", 50);
Player player2 = new Player("P2", 50);
// iterate until the end of the game players roll dice
// print points after each iteration meaning each throw
int i = 0;
while (true) {
i++;
player1.rollDice();
System.out.println("After " + (i) + "th throw player1 points:"
+ player1.getPoints());
if (player1.getPoints() == 1) {
System.out.println("Player 1 wins");
break;
}
player2.rollDice();
System.out.println("After " + (i) + "th throw player2 points:"
+ player2.getPoints());
if (player2.getPoints() == 1) {
System.out.println("Player 2 wins");
break;
}
}
}// end of main
}// end of the class DiceGame
// Player class
class Player {
// Properties of Player class
private String name;
private int points;
// two argument constructor to store the state of the Player
public Player(String name, int points) {
super();
this.name = name;
this.points = points;
}
// getter and setter methods
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getPoints() {
return points;
}
public void setPoints(int points) {
this.points = points;
}
// update the points after each roll
void rollDice() {
int num = Die.rollDice();
if (getPoints() - num < 1)
setPoints(getPoints() + num);
else
setPoints(getPoints() - num);
}
}// end of class Player
// Die that simulate the dice with side
class Die {
static int rollDice() {
return 1 + new Random().nextInt(6);
}
Workspace Remember for a moment a recent trip you have made to the grocery store to pick up a few items. What pieces of data did the Point of Sale (POS) terminal and cashier collect from you and what pieces of data about the transaction did the POS terminal pull from a database to complete the sale? In addition to the data collected and retrieved what information was generated by the POS terminal at the end of the order, as it is being completed?
Answer:
ATM card and the pin number, the status of the bank account and the total of the purchase and the account and method of payment.
Explanation:
The POS or point of service is a device that allows the purchase of product from a commercial store to be done wirelessly and cashless.
It promotes The cashless policy to reduce the circulating physical currency. The POS electromagnetic wave to wirelessly access bank database to retrieve bank account information.
It takes in the smart card, and with the command, retrieves the bank account information addressed on the card. The cashier types the total price of purchased product and it is automatically minus and updated on the account database. Then the invoice of the transaction is issued to the customer.
Modify songVerse to play "The Name Game" (OxfordDictionaries), by replacing "(Name)" with userName but without the first letter. Ex: If userName
Answer:
The Java code for the problem is given below.
Your solution goes here is replaced/modified by the statement in bold font below
Explanation:
import java.util.Scanner;
public class NameSong {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
String userName;
String songVerse;
userName = scnr.nextLine();
userName = userName.substring(1);
songVerse = scnr.nextLine();
songVerse = songVerse.replace("(Name)", userName);
System.out.println(songVerse);
}
}
Print person1's kids, call the incNumKids() method, and print again, outputting text as below. End each line with a newline.Sample output for below program with input 3:Kids: 3New baby, kids now: 4// ===== Code from file PersonInfo.java =====public class PersonInfo { private int numKids; public void setNumKids(int setPersonsKids) { numKids = setPersonsKids; } public void incNumKids() { numKids = numKids + 1; } public int getNumKids() { return numKids; }}// ===== end =====// ===== Code from file CallPersonInfo.java =====import java.util.Scanner;public class CallPersonInfo { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); PersonInfo person1 = new PersonInfo(); int personsKid; personsKid = scnr.nextInt(); person1.setNumKids(personsKid); /* Your solution goes here */ }}// ===== end =====
Answer:
System.out.println("Kids: " + person1.getNumKids());
person1.incNumKids();
System.out.println("New baby, kids now: " + person1.getNumKids());
Explanation:
Reminder: To be able to call a function that is inside a class, we need to use an object of that class. In this case, person1 is our object. If we would like to access any function, we need to type person1.functionName().
1) We need to call getNumKids() to get how many kids they have (It is 3 because user inputs 3 and it is set to the this value using setNumKids() function). To call this function, we need to use person1 object that is created earlier in the main function. To be able to print the result, we call the function inside the System.out.println().
2) To increase the number of kids, we need to call incNumKids() method with person1 object again. This way number of kids are increased by one, meaning they have 4 kids now.
3) To get the current number of kids, we need to call getNumKids() function using person1 object. To be able to print the result, we call the function inside the System.out.println().
Answer:
System.out.println("Kids: " + person1.getNumKids());
person1.incNumKids();
System.out.println("New baby, kids now: " + person1.getNumKids());
Explanation:
Write a statement that outputs variable userNum. End with a newline.
Answer:
System.out.println(userNum);
Explanation:
Using Java programming language, lets assume the variable userNum is entered by a user. The code snippet below will prompt the user to enter a number and output the the variable:
import java.util.Scanner;
public class TestClass {
public static void main(String[] args) {
System.out.println("Enter a number");
Scanner input = new Scanner(System.in);
int userNum = input.nextInt();
System.out.println(userNum);
}
}
Assume a system uses five protocol layers. If the application program creates a message of 100 bytes and each layer (including the fifth and the first) adds a header of 10 bytes to the data unit, what is the efficiency (the ratio of application layer bytes to the number of bytes transmitted) of the system?
Answer:
66.7 %
Explanation:
If the message created by the application layer, is 100 bytes size, and any of the five protocol layers add 10 bytes to the data unit, when transmitted, the packet will have 150 bytes, from which, 50 bytes are overhead bytes.
So, the efficiency (ratio of application layer bytes (excluding the header) to the number of bytes transmitted) of the system is as follows:
E = 100 / 150 = 66.7 %
The efficiency is the ratio of the application later bytes to the total bytes transmitted. Hence, the efficiency is 66.67%.
Application layer bytes = 100 bytes
The number of bytes transmitted can be calculated thus :
(Number of protocol layers × header size) + message size (5 × 10) + 100 = 150 bytesThe efficiency can be calculated thus :
Application layer bytes / number of bytes transmittedEfficiency = (100 ÷ 150) × 100%
Efficiency = 0.666 × 100% = 66.67%
Therefore, the efficiency is 66.67%
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A way to develop a program before actually writing the code in a specific programming language is to use a general form, written in natural English, called __________.
Answer:
The correct answer to the following question will be "Pseudocode".
Explanation:
Pseudocode is indeed an unofficial high-level definition of a software program or other algorithm's operating theory.This uses a standard programming language's formal rules but is designed for individual interpretation instead of computer reading.Therefore, It's the right answer.
Final answer:
Pseudocode is a tool used to develop programs before coding, offering a readable and language-independent way to organize and plan an algorithm. It bridges the gap between human thought and machine code, enabling the logical construction of programs.
Explanation:
A way to develop a program before actually writing the code in a specific programming language is to use a general form, written in natural English, called pseudocode. Pseudocode helps tremendously in organizing thoughts and is particularly useful for complex programs.
It provides a bridge between human logic and machine instructions, enabling developers to outline their algorithms in a readable format before converting them into actual code. This method captures the essence of programming logic without getting bogged down by the syntax of a specific programming language.
Open Comments.java and write a class that uses the command window to display the following statement about comments:
Program comments are nonexecuting statements you add to a file for the purpose of documentation.
Also include the same statement in three different comments in the class; each comment should use one of the three different methods of including comments in a Java class.
Answer:
Answers to the code are given below with appropriate guidelines on definitions and how to properly run the code
Explanation:
//3 ways to comment are as follows:
//1. This is a one line comment.
/**
* 2. This is a documentation comment.
* @author Your name here
*
*/
/*
*3. This is a multiple line comment
* */
public class Comments {
//Driver method
public static void main(String[]args) {
/*
* All the text written inside the
* sysout method will be displayed on
* to the command prompt/console*/
System.out.println("Program comments are nonexecuting statements you add to a file for the purpose of documentation.\n");
System.out.println("3 ways to add comments in JAVA are as follows: \n");
System.out.println("1. One line comment can be written as:\n//Program comments are nonexecuting statements you add to a file for the purpose of documentation.\n");
System.out.println("2. MultiLine comment can be written as:\n/* Program comments are nonexecuting \n * statements you add to a file for the \n * purpose of documentation.\n */\n");
System.out.println("3. Documentation comment can be written as follows:\n/**\n * Program comments are nonexecuting statements you add to a file for the purpose of documentation.\n **/");
}
}
Steps to Run:
1. Make file named Comments.java, and copy paste the above code.
2. Open command prompt and then go to the directory where you have saved the above created file.
3. The before running compile the code by using command
javac Comments.java
4. Now, run the code by the below command
java Comments.
Congrats your assignment is done!!
which is a set of techniques that use descriptive data and forecasts to identify the decisions most likely to result in the best performance?
Answer: Prescriptive analytics
Explanation:
Prescriptive analytics is analysis of data that is based on descriptive analysis and well as predicative analysis.It helps in finding best data pattern and trends that can be implement for action.It helps in predicting future outcome of data.
Thus, it is more purposeful than monitoring the data as it provides various services in signal processing, business field,operation research,image processing etc.
In which type of modulation is a 1 distinguished from a 0 by shifting the direction in whichthe wave begins?
a.bandwidth modulation
b.amplitude modulation
c.frequency modulation
d.phase modulation
e.codec modulation
Answer:
E. Codec modulation
Explanation:
Codec is used to encode digital signals for transmission.
Amplitude modulation uses the amplitude of the carrier wave to encode or modulate the information for transmission.
The phase of a wave changes with respect to the amplitude, so information is modulated with the phase angle as amplitude changes in phase modulation.
Bandwidth modulation is a form of modulation that encode the information of a fixed bit size based on the frequency of the carrier wave. It is similar to frequency modulation, but frequency modulation modulate a signal wave information.
Phase modulation is a type of modulation where one (1) is distinguished from zero (0) by shifting the direction in which the wave begins (Option d).
Analog transmission refers to a methodology of transmission that transmits information by a continuous signal, which can vary in amplitude, phase, and other characteristics related to the proportion of such information.Phase modulation is a pattern used for conditioning communication signals and then for the transmission of that signals.This type of modulation (phase modulation) employs variations in phase and amplitude for carrying out the modulation and it is used for analog transmission.In conclusion, phase modulation is a type of modulation where one (1) is distinguished from zero (0) by shifting the direction in which the wave begins (Option d).
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Suppose that Smartphone A has 256 MB RAM and 32 GB ROM, and the resolution of its camera is 8 MP; Smartphone B has 288 MB RAM and 64 GB ROM, and the resolution of its camera is 4 MP; and Smartphone C has 128 MB RAM and 32 GB ROM, and the resolution of its camera is 5 MP. Determine the truth value of each of these propositions.
Answer:
Explanation:
1 True Smartphone B has 288 MB RAM, which is the most out of the other two phones.
2 True Either the ROM has to be greater or the resolution has to be greater. The resolution is greater in this example so it is true.
3 False It is false because the resolution is larger in Smartphone A.
4. False It may have more RAM and ROM, but Smartphone B's resolution is less making the statement false
5. False It is a biconditional statement which is F - T making the statement false.
With the rapid advance in information technologies, people around the world can access information quickly. Information takes the form of text, still pictures, video, sound, graphics, or animations, which are stored and transferred electronically through these computational technologies.
Answer: Word-for-word plagiarism
Explanation:
The student uses 7 straight words from the original text without applying quotations.
Final answer:
The Information Age is characterized by revolutionary technological advancements that have shifted economies from industrial to information-based. Information technology has facilitated the production, analysis, and dissemination of data, transforming it into valuable information. This era is marked by computer miniaturization and the growth of the Internet, which heavily influences daily life and potential ecological benefits.
Explanation:
In the Information Age, we have witnessed a monumental shift in how information is processed and disseminated, thanks to the rapid advancement of information technologies. This epoch is highlighted by the transition from the industrial economy to an information economy, greatly influenced by the advent of the personal computer in the late 1970s and the proliferation of the Internet in the early 1990s. The revolution in information technology has led to the miniaturization of electronics, integrating circuits and processing units, which are foundational to modern computing devices. These technological advancements have streamlined data collection, processing, and analysis, allowing vast amounts of data to be transformed into valuable information with applications spanning various fields and industries.
Data can be utilized repeatedly to generate new information when placed in context, answering questions, or providing insights, making it a significant commodity in today's world. The continuous evolution of computers and communications networks is a testament to how deeply embedded technology has become in daily life. Importantly, information and communications technology (ICT) not only encompasses traditional devices such as computers and smartphones but also potential future technologies like augmented reality glasses and virtual reality headgear.
The ecological benefits of these technological changes are also noteworthy. The Information Age may contribute to reduced natural resource consumption as societal functions such as shopping and working becomes increasingly digitized, potentially decreasing human energy consumption even as the economy grows. Overall, information technology continues to shape and redefine how we live, communicate, and interact with the world, marking a lasting impact on modern society.
Which of the following instructions should be allowed only in kernel mode? (a) Disable all interrupts. (b) Read the time-of-day clock. (c) Set the time-of-day clock. (d) Change the memory map.
Answer:
A, B and D
Explanation:
The kernel is the central core of the computer's operating system, that has total control of all the activities of the computer. The kernel is a very small program in memory and runs first during the boot of the system. It is the interactive link between the hardware and operating system and other system softwares.
The uses a command line to receive and execute command for various system configurations like storage and memory mapping, enable and disable interrupts, set timers or allocate time slice to run programs etc.
How are signals clocked and how does that affect data transmission? What does it mean when a signal is self-clocking? How does baud rate differ from bits per second? Explain the relationship between frequency and Baud Rate.
Answers:
- Clock signal with clock generator or self-clock.
- self clocking is automatically synchronized.
- Baud-rate is the signal change per second, while BPS is number of bits sent per second.
- Frequency = Baud-rate/ 1000 .
Explanation:
Signals are clocked using neither a clock generator on the signal to synchronize it to the click generator time frame or self-clocking the signal. A self-clocking signal is a signal that does not need a clocking signal or clock generator to decode it. Baud rate is the number if signal change per time, while but per second is the number of bits sent at a second. Frequency is the baud rate divided by 1000.
Final answer:
Signals are clocked using a reference timing signal that coordinates data transmission. A self-clocking signal embeds timing information, allowing synchronization without a separate clock. Baud rate, differing from bits per second, measures the number of signal units sent per second, which could represent multiple bits, depending on the encoding scheme.
Explanation:
Signals are clocked by using a reference timing signal, allowing the synchronization of data transmission across systems. In digital electronics, a clock signal is a particular type of signal that oscillates between a high and a low state and is used primarily to coordinate the actions of circuits.
A self-clocking signal includes timing information within the signal itself, which allows the receiver to synchronize with the transmitter without the need for a separate clock signal.
The baud rate is a measure of the number of signal units per second. Each signal unit may represent more than one bit of information, which is why baud rate and bits per second can be different. For instance, in the case of a signal which uses four different phase angles, each angle (signal unit) can represent two bits, so the baud rate would be half the bitrate.
The frequency of a signal is the rate at which the waveform repeats itself, whereas baud rate refers to the number of symbols per second. In digital communications, the carrier wave frequency is typically much higher than the baud rate.
____ is the risk control approach that attempts to reduce the impact caused by the exploitation of vulnerability through planning and preparation.
Answer: mitigation
Explanation:
Answer:
The correct word for the blank space is: Mitigation.
Explanation:
Mitigation is the set of actions taken to reduce the impact of vulnerability after a threat has exploited it. How effective mitigation will depend on the speed of detection and response to the threat. Part of mitigation also comprehends setting up plans of contingency in front of the attacks to protect the information of the company that could be compromised.