The BEST example of diffraction is the image of A) your face as it appears in a mirror. B) a pencil that appears broken in a glass of water. C) a ring around the Sun caused by particles in the air. D) a fingerprint that appears to be enlarged under a magnifying glass.

Given data :

Velocity of radar signal, v = Velocity of light = 3 x 10^8 m/s

Greatest distance between Venus and Earth d1 = 0.47 AU = 0.47 AU (a.5 x 10^11 m / 1 AU) = 7.1x10^10 m

Closest distance between Venus and Earth, d2 = 0.28 AU = 0.28 AU (1.5 x 10^11 m / 1 AU)= 4.2 x 10^10 m

The time take by radar signal to travel from Earth to Venus and back when Venus is brightest is calculated as

T1 = 2d1/v = 2(7.a x 10^10 m / 3 x10^8 m/s) = 473 s

The time taken by radar signal to travel from Earth to Venus and back when Venus is closest is calculated as

T2 = 2d1/v = 2 (4.2 x 10^10 m) / 3 x 10^8 m/s = 280 s

Answer: 13.5

Explanation: Obtained from this

C) ω = 0 = ωo + αt = 6.3rad/s - 0.74rad/s² * t

t = 8.5 s ← after the given 5 s, or 13.5s total

-- alternate: --

ω = 0 = ωo + αt = 10rad/s - 0.74rad/s² * t

t = 13.5 s

The time taken for the fan to stop after it has been turned off is 7 s.

The given parameters;

The angular acceleration of the fan is calculated as;

[tex]\alpha = \frac{\Delta \omega }{t} = \frac{\omega _2 - \omega _1}{t} \\\\\alpha = \frac{7-12}{5} \\\\\alpha = -1 \ rad/s^2[/tex]

The angular displacement of the blades  before stopping is calculated as;

[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta \\\\\0 = \omega_i^2 + 2\alpha \theta\\\\-2\alpha \theta = \omega_i^2 \\\\\theta = \frac{\omega_i^2}{-2\alpha } \\\\\theta = \frac{(7)^2}{-2(-1)} \\\\\theta = 24.5 \ rad[/tex]

The time taken for the blade to make this angular displacement is calculated as;

[tex]\theta = \omega_it + \frac{1}{2} \alpha t^2\\\\24.5 = 7t + (0.5)(-1)(t)^2\\\\24.5 = 7t - 0.5t^2\\\\0.5t^2 -7t + 24.5 = 0\\\\solve \ the \ quadratic \ equation \ using \ formula \ method\\\\a = 0.5, \ \ b = -7, \ \ c = 24.5 \\\\t = \frac{-b \ \ +/- \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-(-7) \ \ +/- \ \sqrt{(-7)^2 - 4(0.5\times 24.5)} }{2(0.5)}\\\\t = 7 \ s[/tex]

Thus, the time taken for the fan to stop after it has been turned off is 7 s.

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The example of positive feedback is, " warmer temperatures on earth's surface decrease the evaporation of water."

     Warmer temperature on the earth's surface decreases the evaporation of water.

Because, the temperature of the earth will become hot , cold, warm etc.. this happens due to the evaporation of water.

Hence, Option A is the correct answer.

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The two pieces of pure copper must have the same temperature. The correct option is A.

The density is the ratio of the mass and the volume of the object. It is denoted by ρ.

ρ = mass/Volume = m/V

Given are the two pieces of pure copper. One is cube in shape and another is cuboid.

Both will have different volume. As volume is related to the mass and density. So, they are also different for the two pieces of copper. But, the temperature does not depends on the remaining parameters.

Thus, the correct option is A.

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The scientist Kepler was known to have relied on observations and data of Tycho Brahe to formulate his laws of planetary motion.

Kepler is the scientist who is credited with the three laws of planetary motion. These laws set the tone fro the advances in the study of astronomy today.

However, the scientist Kepler was known to have relied on observations and data of Tycho Brahe to formulate his laws of planetary motion.

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Answer: The heavy truck

Explanation: Momentum is defined as the amount of movement.

It can be written as P = m*v

Where P is the momentum, m is the mass of the object and v is the velocity.

So you can see that if the mass increases, also does the momentum, so if both trucks move at the same velocity, then the truck with the bigger mas will have a bigger momentum.

Then the correct answer is the heavy truck

The calculation of 2 x 10^-3 cm ÷ 2.5 x 10^4 cm, translated in scientific notation ends up with a result of 8 x 10^-8 cm.

To calculate 2 x 10^-3 cm ÷ 2.5 x 10^4 cm, you start by performing the multiplication and division operations separately. That gives us (2*10^-3) cm and (2.5*10^4) cm. Before dividing these two results, make sure they're expressed in the same scientific notation. It's important to note that multiplying or dividing quantities in scientific notation involves separately multiplying or dividing the coefficients and adding or subtracting the exponents, respectively.

In this case, the calculation would be (2 ÷ 2.5) x 10^(-3-4), which simplifies to 0.8 x 10^-7. This can also be represented as 8 x 10^-8 cm.

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Answer:the answer is C. PLATO

Explanation:

1. D) 300 J

The work done by a constant force is given by:

[tex]W=Fdcos \theta[/tex]

where F is the force applied, d is the distance, and [tex]\theta[/tex] is the angle between the direction of the force and the direction of motion.

In this problem, F=200 N, d=1.5 m while [tex]\theta=0^{\circ}[/tex], because the force is parallel to the motion of the box, therefore the work done is

[tex]W=(200 N)(1.5 m)(cos 0^{\circ})=300 J[/tex]

2. C) 48,000 J

We can use the same formula used in the previous part of the problem:

[tex]W=Fdcos \theta[/tex]

In this case:

F=480 N

d=100 m

[tex]\theta=0^{\circ}[/tex]

So the work done is

[tex]W=(480 N)(100 m)(cos 0)=48,000 J[/tex]

Common force fields are the gravitational field, generated by masses (like the Earth), and the electromagnetic field, generated by charged particles. These force fields can exert influence over distances without direct physical contact, such as the gravitational influence of the Sun on Earth's orbit. These concepts are crucial understanding tools in the study of physics.

Common examples of force fields include the gravitational field and the electromagnetic field. The source of the gravitational field is any object with mass- an example being the Earth, whose gravitational field is what gives objects weight. The electromagnetic field is generated by charged particles- for instance, a charged rubber comb generates an electromagnetic field that attracts neutral bits of paper via the Coulomb force.

These field forces act at a distance, meaning they can exert influence without physical contact. For example, the Sun's gravitational field influences the Earth's orbit, despite the vast distance between these two celestial bodies. Similarly, stationary electric charges can generate electric fields that exert force on other distant charges.

Understanding fields is crucial in the study of physics, as it helps to visualise forces and how they are transmitted. They also connect with the concept of elementary particles and their interactions in the macroscopic world, making the fields concept an essential tool for grasping complex physical phenomena.

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A rock salt crystal shatters when struck because it is an ionic compound that is hard and brittle. Force causes a shift in ion layers, bringing like-charged ions next to each other, which repel and cause shattering. Rock salt cleaves along smooth planes due to the regular ion arrangement.

A rock salt crystal, which is primarily composed of sodium chloride, is likely to shatter when struck because it's an ionic compound with a lattice structure. In their solid state, the positively charged sodium ions and negatively charged chloride ions are arranged in a regular, repeating pattern. When mechanical force such as a hammer strike is applied, it can cause layers of ions to shift.

If ions with the same charge are forced next to each other, their repulsive forces will cause the crystal to rapidly separate along its cleavage planes, resulting in a shattering effect. Moreover, because of the regular arrangement of the ions, when an ionic crystal like rock salt breaks, it does so along smooth planes. This tendency is epitomized by the mineral halite, which often cleaves into cubes.

The breakage of polycrystalline aggregates like rocks is complex due to the varied strength at grains and grain boundaries, however, for homogeneous ionic crystals like rock salt, the cleaving and shattering are more predictable and result from the inherent brittleness and repulsion of like-charged ions under stress.

Answer:

B. 4

Explanation:

Beat frequency (fb) is calculated as follows:

fb = |f1 - f2|

where f1 and f2 are two sounds frequencies, in this case, 24 Hz and 20 Hz. Replacing in the equation:

fb = |24 - 20| = 4 Hz

Then, they should produce they 4 beats per second

Using Kepler's Third Law, the period of Satellite A, which has an orbital radius 3 times greater than that of Satellite B with a period of 120 minutes, is calculated to be approximately 519.6 minutes.

The period of Satellite A, with an orbital radius 3 times greater than Satellite B, can be found using Kepler's Third Law, which relates the orbital period of a satellite to its orbital radius. Kepler's Law states that the square of the orbital period is proportional to the cube of the radius of its orbit. Since Satellite B has an orbital period of 120 minutes, we can set up the proportion (T_A/T_B)^2 = (R_A/R_B)^3, where T_A is the unknown period of Satellite A, T_B is the known period of Satellite B, R_A is the orbital radius of Satellite A and R_B is the orbital radius of Satellite B. Because R_A is 3 times R_B, the proportion becomes (T_A/120 min)^2 = 3^3. Therefore, T_A = 120 min x √(3^3), which simplifies to T_A = 120 min x 3√3. After calculating, T_A's period is found to be approximately 519.6 minutes.

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Work = 125 joules

Thus; kinetic energy = work done

Kinetic energy = 1/2mv²

                       = 1/2 × 10× 5²

                       = 5 × 25

                       = 125 joules

Hence, work done is 125 joules.

From the calculations, the work done by the dog is 600 J.

Work is done when the force applied covers a distance in the direction of the force.

Using the equations of motion;

v^2 = u^ - 2as

since v =0

u^2 = 2as

But

v = u - at

u = at

a = u/t

a = 5/2.4

a = 2.1m/s^2

s = u^2 /2a

s = (5)^2/2 *  2.1

s= 6 m

Work done = 10 Kg * 10ms-2 * 6 = 600 J

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Final answer:

The centripetal accelerations of two identical cars rounding banked curves at the same speed, radius, and angle on Earth and the Moon are the same since the formula for centripetal acceleration, which is velocity squared divided by radius, does not depend on the local acceleration due to gravity.

Explanation:

When comparing the centripetal accelerations of two identical cars rounding banked curves with the same speed, radius, and angle, one on Earth and one on the Moon, an important factor to consider is the acceleration due to gravity on each body. The formula for centripetal acceleration (ac) is ac = v²/r, where v is the velocity of the car and r is the radius of the circular path.

Given that both cars have the same speed (v) and radius (r), and that the centripetal acceleration is not directly dependent on gravity, the centripetal accelerations will be the same for both cars. It is essential to note that the gravitational force would affect the normal force and the friction available, but this does not change the centripetal acceleration required to keep the cars on their paths. Therefore, the correct answer is: c. the centripetal accelerations are the same for both cars.

To find the resultant displacement of the bear, we can use trigonometry. First, we break down the bear's displacements into their respective components. Then, we add the x-components and y-components separately to find the resultant displacement in each direction. Finally, we use the Pythagorean theorem and inverse tangent function to find the magnitude and angle of the resultant displacement.

To find the resultant displacement of the bear, we can use trigonometry. First, we break down the bear's displacements into their respective components. The first displacement, heading 55.0º north of west for 15.0 m, can be represented as 15.0 m at an angle of 55.0º north of west. The second displacement, heading to the west for another 7.00 m, can be represented as 7.00 m at an angle of 90.0º west of north.

We can now add the x-components and y-components of these displacements separately to find the resultant displacement in each direction. The x-components are -15.0 m (negative because it is westward) and -7.00 m respectively, and the y-components are 0.00 m and 7.00 m. Adding these components gives us a resultant displacement of -22.0 m in the x-direction and 7.00 m in the y-direction.

Finally, we can find the magnitude and angle of the resultant displacement using trigonometry. The magnitude can be found using the Pythagorean theorem: magnitude = sqrt((-22.0 m)^2 + (7.00 m)^2) = 23.4 m. The angle can be found using the inverse tangent function: angle = arctan((7.00 m)/(-22.0 m)) = -17.4º (measured counterclockwise from the positive x-axis).

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Answer:

Explanation:

X-Rays are ''minor'' electromagnetic waves than Gamma Rays.

Gamma rays are the strongest waves in the electromagnetic spectrum with a length order of [tex]10^{-12}[/tex], which indicates a really intensive frequency, those characteristics allow to display a high energy amount.

The second most intense electromagnetic waves are X-Rays, stronger that ultraviolet, visible, infrared, microwaves and radio waves; but weaker than Gamma Rays.

Answer:

Newton's 3rd Law

Explanation:

Justin travels a total distance of 17 km. His displacement is approximately 11.7 km, 20° west of south from his starting point.

To determine the total distance travelled by Justin, we simply add all the distances travelled:

Total distance = 12 km + 4 km + 1 km = 17 km.

To find the displacement, we need to consider the initial and final positions. Justin's final position relative to the starting point involves a vector calculation.

Vertical displacement (south - north): 12 km (south) - 1 km (north) = 11 km south.

Horizontal displacement (west): 4 km west.

Using the Pythagorean theorem, the displacement can be calculated as follows:
Displacement= √((11 km)² + (4 km)²) = √(121 km² + 16 km²) = √137 km² ≈ 11.7 km.

Using trigonometry to find the direction, the angle θ from the south direction is:

tan(θ) = opposite/adjacent = 4/11 ≈ 0.364.

θ ≈ atan(0.364) ≈ 20° west of south.

Displacement = 11.7 km, 20° west of south.

Yes, an object can have both kinetic energy and potential energy at the same time, such as a ball during its flight. These forms of energy can transform into each other without external work in a closed system.

An object can indeed have both kinetic energy and potential energy at the same time. For instance, a ball thrown in the air has kinetic energy due to its motion and potential energy due to its height above the ground. As it rises, its kinetic energy decreases while its potential energy increases, and vice versa when it falls back down. Energy transformation between kinetic and potential energy occurs without the need for external work if no friction or air resistance is present. In a closed system where no energy is lost to the environment, the sum of potential and kinetic energy remains constant according to the conservation of energy principle.

Answer:

Increased plant growth and damage to drinking water

Explanation:

Nitrogen-enhanced fertilizers aid in plant growth and improve agricultural yield, but excessive or improper use can cause eutrophication, harming aquatic ecosystems.

Nitrogen-enhanced fertilizers have both positive and negative impacts on the environment. On the positive side, such fertilizers boost the growth of crops by providing them with an ample supply of necessary nutrients, including nitrogen. In particular, plants benefit from an abundant supply of nitrogen; soils are ultimately enriched, providing higher yields in agriculture.

However, these fertilizers, when used excessively or improperly, can cause significant harm to both freshwater and marine ecosystems. The nitrogen and phosphorus from the fertilizers can enter drainage systems and accumulate in water bodies, causing eutrophication- an overgrowth of algae that depletes dissolved oxygen levels, negatively affecting aquatic organisms. This process eventually creates inhospitable conditions for many forms of marine and freshwater life, culminating in areas known as dead zones. This overuse and negligence in the application of such fertilizers is a major cause of such detrimental effects.

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