Answer:
(A) 0.15625
(B) 0.1875
(C) Can't be computed
Step-by-step explanation:
We are given that the amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 32 and 64 minutes.
Let X = Amount of time taken by student to complete a statistics quiz
So, X ~ U(32 , 64)
The PDF of uniform distribution is given by;
f(X) = [tex]\frac{1}{b-a}[/tex] , a < X < b where a = 32 and b = 64
The CDF of Uniform distribution is P(X <= x) = [tex]\frac{x-a}{b-a}[/tex]
(A) Probability that student requires more than 59 minutes to complete the quiz = P(X > 59)
P(X > 59) = 1 - P(X <= 59) = 1 - [tex]\frac{x-a}{b-a}[/tex] = 1 - [tex]\frac{59-32}{64-32}[/tex] = [tex]1-\frac{27}{32}[/tex] = 0.15625
(B) Probability that student completes the quiz in a time between 37 and 43 minutes = P(37 <= X <= 43) = P(X <= 43) - P(X < 37)
P(X <= 43) = [tex]\frac{43-32}{64-32}[/tex] = [tex]\frac{11}{32}[/tex] = 0.34375
P(X < 37) = [tex]\frac{37-32}{64-32}[/tex] = [tex]\frac{5}{32}[/tex] = 0.15625
P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875
(C) Probability that student complete the quiz in exactly 44.74 minutes
= P(X = 44.74)
The above probability can't be computed because this is a continuous distribution and it can't give point wise probability.
What is not a problem modular division is used for?
Modular division, also known as modular arithmetic, has various applications in cryptography, computer science, and number theory. It is used in encryption algorithms like RSA and in solving congruence equations.
Explanation:Modular division, also known as modular arithmetic, is a mathematical operation that involves finding the remainder when one number is divided by another. Modular division is commonly used in various mathematical applications such as cryptography, computer science, and number theory.
One application of modular division is in the encryption and decryption of data using modular arithmetic. For example, the RSA encryption algorithm relies on modular division to encode and decode messages.
Another application of modular division is in solving congruence equations. Congruence equations represent the idea of equivalence of numbers modulo a given number. By using modular division, we can determine the solutions to these equations.
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Modular division is used to find remainders in mathematics, but it is not used for dividing polynomials or dividing by zero. It's also not useful for dividing vectors in physics.
Modular division is a mathematical method used to find the remainder of a division problem, but it is not necessarily applicable in all contexts. For example, dividing a polynomial by a polynomial generally does not result in a polynomial, indicating that other methods must be used in this situation. Furthermore, it's important to note that modular division cannot be used to divide by zero, since this is undefined in mathematics. Additionally, within the discipline of physics, modular division is not applicable for operations such as dividing a vector by another vector component by component, as there are no useful physics applications for this type of operation.
Find the value of variable x. If your answer is not an integer, write it in simplest radical form with the denominator rationalized.
Answer:
the answer is 7
Step-by-step explanation:
angle 30°
x=14/2
x=7
The value of x is 7 cm.
How to solve the variable?If you have the hypotenuse, multiply it by sin(θ) to get the length of the side opposite to the angle.
y = 14* sin 30°
y = 14* 0.5
y = 7
y = 7cm
What's the base of a triangle?
The bottom line of a triangle is the base of the triangle, and it can be one of the three sides of the triangle. In a triangle, one side is the base side and the remaining two sides can be the height or the hypotenuse side.
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The coordinates for the L-shaped are given to you. And number one. Where will the L shape be if it is. . .(find the new coordinates and then draw the image of the L-Shape)
Answer:
see below
Step-by-step explanation:
As always, the coordinate transformations are ...
a. 180° — (x, y) ⇒ (-x, -y)
b. 270° CCW or 90° CW — (x, y) ⇒ (y, -x)
c. 90° CCW or 270° CW — (x, y) ⇒ (-y, x)
___
It can be quick and easy to use a transparency or tracing paper to locate the rotated position of the image.
Mary collected $2.75 in nickels and dimes. Ten less than twice the number of nickels represents the number of dimes she has. How many of each kind of coin does she have?
Answer: There are 15 nickles and 20 dimes.
Step-by-step explanation:
Since we have given that
Let the number of nickles be 'x'
Let the number of dimes be '2x-10'.
Total amount = $2.75
According to question, we get that
[tex]0.1(2x-10)+0.05x=2.75\\\\0.2x-1+0.05x=2.75\\\\0.25x=2.75+1\\\\0.25x=3.75\\\\x=\dfrac{3.75}{0.25}\\\\x=15[/tex]
Hence, there are 15 nickles and [tex]2x-10=2(15)-10=30-10=20[/tex] dimes.
Therefore, there are 15 nickles and 20 dimes.
Final answer:
Mary has 15 nickels and 20 dimes.
Explanation:
Let's solve this problem step-by-step:
Let's assume the number of nickels as N and the number of dimes as D.According to the given information, the value of the nickels is 0.05N and the value of the dimes is 0.10D.The total amount collected is $2.75, so we can write the equation: 0.05N + 0.10D = 2.75According to the second piece of information, ten less than twice the number of nickels represents the number of dimes. So, we can write another equation: D = 2N - 10We now have a system of two equations with two variables:0.05N + 0.10D = 2.75D = 2N - 10Solve the system of equations to find the values of N and D.Substitute the value of D from the second equation into the first equation: 0.05N + 0.10(2N - 10) = 2.75Expand and simplify the equation: 0.05N + 0.20N - 1 = 2.750.25N - 1 = 2.750.25N = 3.75N = 3.75/0.25N = 15Substitute the value of N into the second equation to find the value of D: D = 2(15) - 10D = 30 - 10D = 20Therefore, Mary has 15 nickels and 20 dimes.:Juan purchased an antique that had a value of \$200$200dollar sign, 200 at the time of purchase. Each year, the value of the antique is estimated to increase 10\, percent over its value the previous year. The estimated value of the antique, in dollars, 222 years after purchase can be represented by the expression 200a200a200, a, where aaa is a constant. What is the value of aaa?
Final answer:
The antique purchased by Juan increases in value by 10% each year. The value of the antique after 2 years can be found by calculating the expression $200a, where a is a constant. The value of [tex]\( a \) is \( 1.21 \).[/tex]
Explanation:
To find the value of a, we need to represent the annual increase of 10% in terms of multiplication.
After the first year, the value of the antique increases by [tex]\( 10\% \) of its previous value, which is \( 0.10 \times 200 \) dollars.[/tex]
After the second year, the value of the antique increases by [tex]\( 10\% \) of its value at the end of the first year, which is \( 0.10 \times (200 + 0.10 \times 200) \) dollars.[/tex]
Generally, after \( n \) years, the value of the antique will be [tex]\( 200 \times (1 + 0.10)^n \) dollars.[/tex]
The expression given for the value of the antique 2 years after purchase is 200a , where a is a constant. This represents the value of the antique after 2 years.
Equating the expression to the value of the antique after 2 years, we have:
[tex]\[ 200a = 200 \times (1 + 0.10)^2 \][/tex]
Now, let's solve for \( a \):
[tex]\[ 200a = 200 \times (1.10)^2 \][/tex]
200a = 200 \times 1.21
200a = 242
Dividing both sides by 200:
[tex]\[ a = \frac{242}{200} \][/tex]
[tex]\[ a = 1.21 \][/tex]
Therefore, the value of [tex]\( a \) is \( 1.21 \).[/tex]
9-114. While setting up a mathematical sentence to solve a problem, Paulina and Aliya came up with the equations below. Since the equations did not look alike, the girls turned to you for help. Paulina: 4x+2y=6 Aliya: 12x+6y=18
Step-by-step explanation:
Below is an attachment containing the solution.
Paulina and Aliya's equations, 4x+2y=6 and 12x+6y=18, are multiples of each other. This means they represent the same line and indicate an infinite number of solutions rather than a single intersection point typically sought after in a system of distinct linear equations.
Explanation:Paulina and Aliya have created linear equations to solve a mathematical problem. Paulina has the equation 4x+2y=6 and Aliya has 12x+6y=18. At a glance, these equations may look different, but upon closer inspection, Aliya's equation is actually just Paulina's equation multiplied by 3. This realization is pertinent because it suggests both equations represent the same line. Therefore, these two equations should have the same solution set.
To analytically solve simultaneous equations, one could use methods such as substitution, elimination, or matrix and determinant-based approaches. Using elimination or substitution, we aim to isolate one variable and solve for it. For example, because Aliya's equation is a multiple of Paulina's, if they were meant to be a system of separate lines, one way to solve them would be to simplify Aliya's equation by dividing by 3, revealing it to be identical to Paulina's, which indicates that this system has an infinite number of solutions (all points on the line represented by the equation).
If a system has two distinct equations, elimination involves adding or subtracting equations from one another to eliminate one of the variables, and substitution involves solving for one variable in terms of the other and then substituting this expression into the other equation. When equations are actually multiples of each other, this indicates either an infinite number of solutions or no solutions dependant if the equations are consistent or inconsistent respectively.
A plastic rod 1.5 m long is rubbed all over with wool, and acquires a charge of -9e-08 coulombs. We choose the center of the rod to be the origin of our coordinate system, with the x-axis extending to the right, the y-axis extending up, and the z-axis out of the page. In order to calculate the electric field at location A = < 0.7, 0, 0 > m, we divide the rod into 8 pieces, and approximate each piece as a point charge located at the center of the piece. 1. What is the length of one of these pieces? 2. What is the location of the center of piece number 2? 3. How much charge is on piece number 2?
Answer:
Answer:
a) k = 0.1875 m
b) r2 = 0.46875 m
c) q = -1.125*10^-8 C
Step-by-step explanation:
Given:
- The total Length of rod L = 1.5 m
- The total charge of the rod Q = -9 * 10^8 C
- Total section of a rod n = 8
Find:
1. What is the length of one of these pieces?
2. What is the location of the center of piece number 2?
3. How much charge is on piece number 2?
Solution:
- The entire rod is divided into 8 pieces, so the length of each piece would be k:
k = L / n
k = 1.5 / 8
k = 0.1875 m
- The distance from center of entire rod and center of section 2 is 2.5 times the section length
r2 = 2.5*k
r2 = 2.5*(0.1875)
r2 = 0.46875 m
- Assuming the charge on the rod is uniformly distributed. The the charge for each section of rod is given by q:
q = Q / n
q = -9 * 10^8 / 8
q = -1.125*10^-8 C
The length of one of the eight pieces of the rod is 0.1875 m. The center of piece number 2 is at <0.28125, 0, 0> m. The charge on piece number 2 is -1.125e-08 Coulombs.
Explanation:The problem involves the concepts of electric field, charge distribution, and coordinate system in Physics. Let's answer the question part by part:
The length of one of these pieces is the total length divided by the number of pieces. That is, 1.5 m / 8 = 0.1875 m.The center of piece number 2 would be one and a half times the length of one piece, to the right of the origin in the x-direction; hence, it is at <0.28125, 0, 0> m.The charge on piece number 2 is the total charge divided by the number of pieces. That is, -9e-08 C / 8 = -1.125e-08 Coulombs.Learn more about Electric Field Calculation here:https://brainly.com/question/34817608
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Give a big-O estimate for the number of operations, where an operation is a comparison or a multiplication, used in this segment of an algorithm (ignoring comparisons used to test the conditions in the for loops, where a1, a2, ..., an are positive real numbers). m :
Answer:
O(n2)
Step-by-step explanation:
the first iteration algorithm of the i-for loop (the outer loop), the j-for loop (the inner loop) will run 2 to
n times which is represented as
(n − 1 times).
the second iteration algorithm of the i-for loop, the j-for loop will run 3 to n times represented as
(n − 2 times).
the third to the last iteration algorithm of the i-for loop, the j-for loop will run n − 1 to n times (2 times).
And the second to the last iteration of the i-for loop, the j-for loop will run from n to n times (1 time)
For the last iteration of the i-for loop, the j-for loop will run 0 times because i + 1 > n.
Now we know that the number of times the loops are run is
1 + 2 + 3 + . . . + (n − 2) + (n − 1) = n(n − 1)/2
So we can express the number of total iterations as n(n − 1)/2.
Since we have two operations per loop (one comparison and one multiplication), we have
2 ·n(n−1)/2 = n
2 − n operations.
So f(n) = n2 − n
f(n) ≤ n2
for n > 1.
Therefore, the algorithm is O(n2) with
C = 1 and k = 1.
Is the product of 25 and 3/5 more or less than 14? Explain your answer. Write the product of 3/5 and 25.
Answer:
More. The product of 25 and 3/5 is 15 which is greater than 14.
Step-by-step explanation:
The data shown represent the number of runs made each year during Bill Mazeroski’s career. Check for normality.
30 59 69 50 58 71 55 43 3
66 52 56 62 36 13 29 17 31
Answer:
The given data is not normal.
Step-by-step explanation:
We are given the following data:
30, 59, 69, 50, 58, 71, 55, 43, 3, 66, 52, 56, 62, 36, 13, 29, 17, 31
Condition for normality:
Mean = Mode = Median
[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]
[tex]Mean =\displaystyle\frac{800}{18} = 44.44[/tex]
Mode is the most frequent observation of the data.
Since all the value appeared once, there is no mode.
[tex]Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}[/tex]
Sorted data: 3, 13, 17, 29, 30, 31, 36, 43, 50, 52, 55, 56, 58, 59, 62, 66, 69, 71
Median =
[tex]=\dfrac{9^{th}+10^{th}}{2} = \dfrac{50+52}{2}=51[/tex]
Since the mean, mode and median of data are not equal, the data is not normal.
The second side of a triangular deck is 3 feet longer than the shortest side, and the third side is 3 feet shorter than twice the length of the shortest side. If the perimeter of the deck is 80 feet, what are the lengths of the three sides?
Answer: the lengths are 20 feet, 23 feet and 37 feet
Step-by-step explanation:
Let x represent the length of the shorter side of the triangular deck.
The second side of a triangular deck is 3 feet longer than the shortest side. This means that the length of the second side is (x + 3) feet.
The third side is 3 feet shorter than twice the length of the shortest side. This means that the length of the third of the triangle is (2x - 3) feet.
If the perimeter of the deck is 80 feet, it means that
x + x + 3 + 2x - 3 = 80
4x = 80
x = 80/4
x = 20
The length of the second side is
20 + 3 = 23 feet
The length of the third side is
20 × 2 - 3 = 40 - 3 = 37 feet
I really need help oof-
Angle α lies in quadrant II, and tanα=−12/5 . Angle β lies in quadrant IV, and cosβ=3/5.
What is the exact value of cos(α−β) ?
Enter your answer in the box.
cos(α−β) = __
From the given info (and the linked question) we find
[tex]\cos\alpha=-\dfrac5{13}[/tex]
[tex]\sin\alpha=\dfrac{12}{13}[/tex]
[tex]\sin\beta=-\dfrac45[/tex]
Then using the angle-sum identity for cosine, we have
[tex]\cos(\alpha-\beta)=\cos\alpha\cos\beta+\sin\alpha\sin\beta[/tex]
[tex]\cos(\alpha-\beta)=\left(-\dfrac5{13}\right)\dfrac35+\dfrac{12}{13}\left(-\dfrac45\right)=-\dfrac{63}{65}[/tex]
Final answer:
To find the exact value of cos(α-β), we use the cosine sum and difference identity and the respective sine and cosine values calculated from the given tangent and cosine values for angles α and β. Using this approach, we find that cos(α-β) equals 63/65.
Explanation:
The exact value of cos(α-β) can be found by using the sum and difference identities for cosine. Since tanα = -12/5, in quadrant II, we can find the corresponding sine and cosine values for α using the Pythagorean identity sin²α + cos²α = 1. For cosβ = 3/5, in quadrant IV, we do a similar procedure to find the sine of β. With both sine and cosine for α and β, we use the identity cos(A-B) = cosA cosB + sinA sinB to find cos(α-β).
To find the sine and cosine for α, given that tanα = -12/5, we know that the opposite side is -12, and the adjacent side is 5, so the hypotenuse using the Pythagorean theorem is √(12² + 5²) = √(144+25) = √169 = 13. Thus sinα = -12/13 (negative because α lies in the second quadrant where sine is negative) and cosα = 5/13 (positive because cosine in the second quadrant is positive).
For β, we already have cosβ = 3/5. The sine can be found using the Pythagorean identity 1 - cos²β = sin²β, which gives sinβ = -√(1 - (3/5)�) = -√(1 - 9/25) = -√(16/25) = -4/5 (negative because β is in the fourth quadrant where sine is negative).
Now, we can find the exact value of cos(α-β) by plugging in the values:
cos(α-β) = cosα cosβ + sinα sinβ = (5/13)*(3/5) + (-12/13)*(-4/5)
= 15/65 + 48/65 = 63/65.
Therefore, the exact value of cos(α-β) is 63/65.
A tank holds 50 gal of water, which drains from a leak at the bottom, causing the tank to empty in 20 min. The tank drains faster when it is nearly full because the pressure on the leak is greater. Torricelli's Law gives the volume of water remaining in the tank after t minutes as V(t)=50(1−t20)20≤t≤20 (a) Find V(0) and V(20). (b) What do your answers to part (a) represent? (c) Make a table of values of V(t) for t = 0, 5,10, 15, 20. (d) Find the net change in the volume V as t changes from 0 min to 20 min.
Answer:
(a) V(0) = 50 gal, V(20) = 0 gal
(b)At t= 0 the tank is full.
At t=0 the tank is empty
(c)
Time volume
0 50 gal
5 37.5 gal
10 25 gal
15 12.5 gal
20 0 gal
(d)
Net change of volume = 50 gal
Step-by-step explanation:
Given that the capacity of the tank is 50 gal.
Torricelli's Law gives the volume of water remaining in the tank after t minutes as
[tex]V(t)=50(1-\frac{t}{20})^2[/tex]
(a)
To find V(0), we put t = 0 in the above equation
[tex]V(0)=50(1-\frac{0}{20})^2[/tex]
[tex]=50(1-0)^2[/tex]
= 50 gal
To find V(20), we put t =2 0 in the above equation
[tex]V(20)=50(1-\frac{20}{20})^2[/tex]
[tex]=50(1-1)^2[/tex]
= 0 gal
(b)
At t= 0 the tank is full.
At t=0 the tank is empty.
(c)
Time V(t)
0 [tex]50(1-\frac{0}{20})^2=50 \ gal[/tex]
5 [tex]50(1-\frac{5}{20})^2=37.5 \ gal[/tex]
10 [tex]50(1-\frac{10}{20})^2=25 \ gal[/tex]
15 [tex]50(1-\frac{15}{20})^2=12.5 \ gal[/tex]
20 [tex]50(1-\frac{20}{20})^2=0[/tex]
(d)
Net change of volume = V(0) -V(20)
=(50-0) gal
= 50 gal
The volume V(t) of water remaining in the tank after t minutes is given by V(t) = 50(1−t/20). V(0) represents the initial volume of water in the tank, which is 50 gallons. V(20) represents the volume of water remaining in the tank after 20 minutes, which is 0 gallons.
Explanation:(a) To find V(0), substitute t = 0 into the equation V(t) = 50(1−t/20).
V(0) = 50(1−0/20) = 50(1−0) = 50(1) = 50
Similarly, to find V(20), substitute t = 20 into the equation V(t) = 50(1−t/20).
V(20) = 50(1−20/20) = 50(1−1) = 50(0) = 0
(b) V(0) represents the initial volume of water in the tank, which is 50 gallons. V(20) represents the volume of water remaining in the tank after 20 minutes, which is 0 gallons.
(c) Creating a table of values of V(t) for t = 0, 5, 10, 15, 20:
t | V(t)
--------------------
0 | 50
5 | 37.5
10 | 25
15 | 12.5
20 | 0
(d) The net change in volume V as t changes from 0 min to 20 min is V(20) - V(0).
V(20) - V(0) = 0 - 50 = -50 gallons
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hey, help me with this pls i only have 10 minutes. 30 points each :)
Answer:
y=-2x
Step-by-step explanation:
First you want to remember rise over run. Your rise is -2 and your run is 1. So -2/1 is your answer. And -2/1 is equal to -2.
Answer:
[tex]\frac{2} {-1}[/tex]=-2
Step-by-step explanation:
_____ requires constructing and applying statistical models that predict labor demand for the next year, given relatively objective statistics from the previous year. Select one: a. Propensity analysis b. A leading indicator c. A yield ratio d. Transitional matrix e. Trend analysis
Answer:
e) Trend Analysis
The term is 'trend analysis'. This refers to a statistical method used to evaluate and predict future trends based on historical data. This technique is specifically referenced in prediction of labor demand using prior year’s data.
Explanation:The concept referred to in the question is e. Trend analysis. Trend analysis is a statistical method used to evaluate and predict future trends based on historical data. In the context of labor demand, a trend analysis would involve examining labor demand data from the previous year, identifying patterns and trends within that data, and using statistical models to make predictions about labor demand for the upcoming year.
For example, suppose a company has seen a steady increase in labor demand over the past five years. Based on this trend, they can build a statistical model that predicts an increase in labor demand for the next year as well. This strategy helps companies plan for their future staffing needs, ensuring they have the necessary resources to meet their objectives.
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X-1 0 1 2 fx 18 6 2 2/3 what is the decay factor of the exponential function represented by the table 1/3 2/3 2 6
The decay factor of the exponential function represented by the provided table is 1/3 as the ratio of the consecutive y-values of the function is consistently 1/3.
Explanation:The decay factor of an exponential function can be found by comparing the ratio of the y-values of the function.
In the given question, a table of x/f(x) values is provided.
A decay happens if the ratios of the consecutive y-values (outputs) are consistently less than 1.
Let's find the ratio between successive y-values. Between 18 and 6, the ratio is 6/18 = 1/3. Going from 6 to 2, the ratio is 2/6 = 1/3. Lastly, transitioning from 2 to 2/3, the ratio is (2/3)/2 = 1/3.
Since we find the ratio of successive outputs (y-values) to consistently be 1/3, it is safe to say that 1/3 is the decay factor for the exponential function represented by the given table.
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A telemarketer calls people and tries to sell them a subscription to a daily newspaper. On 22% of her calls, there is no answer or the line is busy. She sells subscriptions to 10% of the remaining calls. For what proportion of calls does she make a sale? Give your answer as a decimal, and do not round.
Answer:
She makes 7.8% portion of sales collectively.
Step-by-step explanation:
Let us assume she makes total of 100 calls.
The percentage of calls which are busy or unanswered = 22 %
So, now calculating 22% of 100 , we get:
[tex]\frac{22}{100} \times 100 = 22[/tex]
So, 22 of her calls are UNANSWERED.
Now, let us find out the number of calls successfully made by telemarketer.
Total successful calls = Total Calls made - Number of unanswered calls
= 100 - 22 = 78
So, she makes a total of 78 calls successfully.
Now, he sells subscriptions to 10% of the 78 calls made successfully.
So, now calculating 10% of 78 , we get:
[tex]\frac{10}{100} \times 78 = 7.8[/tex]
So, she sold 7.8 subscriptions in total out of 100 attempts.
Also, as we know 7.8 out of 100 = 7.8% of 100.
Hence, she makes 7.8% portion of sales collectively.
Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?
5.7 units
4 units
6.3 units
1 unit
Answer:
The distance is 6.3 units
If a standard dartboard's diameter is 17.75 inches, what is the area of once sector?
Answer:
12.37 square inches
Step-by-step explanation:
The area of the dartboard can be figured from the diameter as ...
A = (π/4)d² = (π/4)(17.75 in)² ≈ 247.4495 in²
There are 20 sectors, all the same size, so the area of one of them is ...
sector area = (1/2)(247.4495 in²) ≈ 12.37 in²
). Bees are one of the fastest insects on Earth. They can fly 22 miles in 2 hours, and 55 miles in 5 hours. Write an algebraic expression to show how many miles a bee can fly in h hours. If a bee flies 4 hours at this speed, how many miles will it travel?
Answer:
Step-by-step explanation:
Look at the info given as (x, y) coordinates with the number of hours as x and the number of miles as y. The first coordinate then is (2, 22) and the second is (5, 55). The rate at which the bee flies is the same as the slope of the coordinates.
[tex]\frac{55-22}{5-2}=11[/tex]
This means that the bee flies 11 miles per hour. Use either one of the coordinates now to find the equation for the line. I pick (2, 22) and point-slope form:
y - 22 = 11(x - 2) and
y - 22 = 11x - 22 so
y = 11x
That's the equation. If we want to use it as a model, we can find how many miles it will fly in a given time, or how long it will take to fly a given number of miles. We are asked to find how far it can fly in 4 hours. So we will use our equation and replace x with 4:
y = 11(4) so
y = 44 miles
tickets for a harlem globetrotter show cost $28 general admission, $43 courtside, or $173 bench seats. Nine times as many general admission tickets were sold as bench tickets, & the number of general admission tickets sold was 55 more than the sum of the number of courtside tickets & bench tickets. Sales of all three kinds of ticks totaled $97,605. How many of each kind of ticket were sold algebra
Answer:
general admission tickets 1170
courtside tickets 985
tickets bench seats. 130
Step-by-step explanation:
To solve the problem, it is necessary to generate a system of equations with the information provided by the statement.
First be
x = # general admission tickets
y = # courtside tickets
z = # tickets bench seats.
The first equation would be that they sold nine times more general admission tickets than bench seats tickets.
That is: x = 9 * z (1)
And the second equation is that the number of general admission tickets sold was 55 more than the sum of the number of courtside tickets and bench seats tickets.
That is: x = 55 + y + z (2)
Now the third equation would be the money raised.
28 * x + 43 * y + 173 * z = 97605 (3)
Now if I replace I rearrange (1):
z = x / 9 (4) and replacement in 2, I have:
x = 55 + y + x / 9, rearranging:
y = (8/9) * x - 55 (5)
Now replacing (4) and (5) in 3, we have:
28 * x + 43 * ((8/9) * x - 55) + 173 * (x / 9) = 97605
Solving the above:
x = 1170, therefore
y = (8/9) * 1170 55 = 985
z = 1170/9 = 130
We can confirm this with equation (3)
28 * x + 43 * y + 173 * z = 97605
28 * 1170 + 43 * 985 + 173 * 130 = 97605
450 general admission tickets, 171 courtside tickets, and 50 bench tickets were sold for the Harlem Globetrotter show.
Explanation:Let's assign variables to represent the number of tickets sold for each category:
Lets x = number of general admission tickets sold
Lets y = number of courtside tickets sold
Lets z = number of bench tickets sold
According to the given information:
The cost of the general admission ticket = $28
The cost of the courtside ticket = $43
The cost of the bench ticket = $173
There were 9 times as many general admission tickets sold as bench tickets: x = 9z
The number of general admission tickets sold was 55 more than the sum of the courtside and bench tickets: x = y + z + 55
The total sales for all three types of tickets was $97,605: 28x + 43y + 173z = 97605
Now, we have a system of three equations with three variables:
x = 9z
x = y + z + 55
28x + 43y + 173z = 97605
We can use substitution or elimination method to solve this system of equations. Solving this system, we find that x = 450, y = 171, and z = 50. Therefore, 450 general admission tickets, 171 courtside tickets, and 50 bench tickets were sold for the Harlem Globetrotter show.
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Need help on problem 40 part b for integrating in respect to y! Thanks!
Answer: [tex]\bold{(a)\quad \dfrac{32}{3}\qquad (b)\quad \dfrac{32}{3}}[/tex]
Step-by-step explanation:
(a) First, find the x-coordinates where the two equations cross
y = -1 and y = 3 - x²
-1 = 3 - x²
-4 = -x²
4 = x²
± 2 = x → These are the upper and lower limits of your integral
Then subtract the two equations and integrate with upper bound of x = 2 and lower bound of x = -2
[tex]\int_{-2}^{+2}[(3-x^2)-(-1)]dx\\\\\\=\int_{-2}^2(4-x^2)dx\\\\\\=4x-\dfrac{x^3}{3}\bigg|_{-2}^{+2}\\\\\\=\bigg(8-\dfrac{8}{3}\bigg)-\bigg(-8+\dfrac{8}{3}\bigg)\\\\\\=\large\boxed{\dfrac{32}{3}}[/tex]
(b) We know the upper and lower bounds of the y-axis as y = 3 and y = -1
Next, find the equation that we need to integrate by solving for x.
y = 3 - x²
x² + y = 3
x² = 3 - y
x [tex]=\pm\sqrt{3-y}\\[/tex]
[tex]\rightarrow \qquad x=\sqrt{3-y}\quad and \quad x=-\sqrt{3-y}[/tex]
Now, subtract the two equations and integrate with upper bound of y = 3 and lower bound of y = -1
[tex]\int_{-1}^{+3}[(\sqrt{3-y})-(-\sqrt{3-y})]dy\\\\\\=\int_{-1}^{+3}(2\sqrt{3-y})dy\\\\\\=\dfrac{-4\sqrt{(3-y)^3}}{3}\bigg|_{-1}^{+3}\\\\\\=\bigg(0\bigg)-\bigg(-\dfrac{32}{3}\bigg)\\\\\\=\large\boxed{\dfrac{32}{3}}[/tex]
PLS HELP What is the value of cos (sin−1(−0.435))?
Answer:
0.900
Step-by-step explanation:
The easiest way to solve this problem is by putting it into a calculator.
When put into a calculator, the answer comes out to be 0.9004304526, which can be rounded to 0.900, or just 0.9.
Good morning ☕️
Answer:
0.900
Step-by-step explanation:
using a calculator you’ll find:
sin⁻¹(-0.435) = -25.785293878311
now
cos(sin⁻¹(-0.435)) = cos(-25.785293878311)
= 0.900430452617
If we round 0.900430452617 to nearest thousandth we get: 0.900
:)
Find the indicated sum for each sequence. S9 of –9, 36, –144, 576, ...
Answer:
-471,861
Step-by-step explanation:
The sum of 9 terms in the sequence –9, 36, –144, 576, ... is -471861.
What is a sequence?An ordered collection of objects that allows repetitions is referred to as a sequence. It has members, just like a set does. The length of the sequence is determined by the number of items.
Given:
–9, 36, –144, 576, ...
Calculate the ratio of the sequence as shown below,
ratio = 36 / -9
ratio = -4
Calculate the sum of 9 terms as shown below,
S₉ = -9 (1 - (-4)⁹) / (1 - (-4))
S₉ = -9 (1 + 262144) / 5
S₉ = -9 (262145) / 5
S₉ = -2359305 / 5
S₉ = -471861
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A boat is spotted in the water with an angle of depression of 25° from the top of a lighthouse that is 89 feet tall. To the nearest foot, how far away is the boat from the base of the lighthouse?A)37 feetB)42 feetC)98 feetD)191 feet
Answer:
D)191 feet
Step-by-step explanation:
Let the height of the light house be |AB| and the Boat be at point C as shown in the diagram.
The angle of depression of the boat from the top A of the lighthouse is given as 25 degrees
Angle BCA = 25 degrees (Alternate Angles are Equal)
We want to determine the distance of the boat C from the base of the lighthouse B i.e. |BC|
[tex]Tan\alpha =\frac{opposite}{adjacent}[/tex]
Tan 25=[tex]\frac{89}{|BC|}[/tex]
Cross multiply
|BC| X tan 25 =89
|BC| = [tex]\frac{89}{tan 25}[/tex]=190.86 feet
The distance of the boat C from the base of the lighthouse B is 191 feet (to the nearest feet).
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Bob placed three regular pentagons together at a vertex, thinking he might be able to form a tessellation. However, they left a gap. What is the number of degrees in the measure indicated?
Answer:
36
Step-by-step explanation:
The angles of a pentagon sum to 180(5-2) = 540 degrees, so each angle of a regular pentagon is 540/5 = 108. Therefore, three of these angles sum to $3 * 108 = 324, which means the indicated angle measures 360 - 324 = 36.
Answer:
36
Step-by-step explanation:
The angles of a pentagon sum to 180(5-2) = 540 degrees, so each angle of a regular pentagon is 540/5 = 108. Therefore, three of these angles sum to 3* 108 = 324, which means the indicated angle measures 360 - 324 = 36
Andy is thinking of a number that has a digit less than 5 in the tens place. It has a digit greater than 7 in the ones place. Fill in the bubble next to all the numbers that could be Andy's number
Step-by-step explanation:
Here, given:
Let us assume the number on Tens place = M
The number in Units place = N
So, the actual value of the number = 10 M + N
The number can be written as MN.
Now, The value of M ( Tens digit) is Less than 5.
So, M = 1, 2 , 3 or 4 ( 0 not included)
Also, The value of N(Unit digit) is greater than 7.
So, N = 8, 9 or 0 ( 0 included)
So, by combining all possibilities for M and N , the possible number chosen by Andy can be expressed as MN :
Number = {18,19,10,28,29,20,38,39,30,48,49 or 40}
Any number can be chosen from the above set as all the numbers match the given restrictions.
find the coordinate of U' after a 90° counterclockwise rotation of the triangle about the origin and then a translation of 2 units down and 5 units left.
Answer: U' = (0, 1)
Step-by-step explanation:
U = (3, -5)
rotate 90° counterclockwise means (x, y) = (-y, x)
new U = (5, 3)
down 2 units means subtract 2 from the y-coordinate
newer U = (5, 1)
left 5 units means subtract 5 from the x-coordinate
U' = (0, 1)
Jolene drove to a state park. She drove 1/4 of the distance the first day. She drove farther the second day. What pat of the distance might Jolene have driven the second day?
Answer: [tex]\frac{2}{4}[/tex] or [tex]\frac{3}{4}[/tex]
Step-by-step explanation:
You need to analize the information given in the exercise.
Let be "x" represents the whole distance part that Jolene have driven to the state park.
According the the explained in the problem, in the first day Jolene drove [tex]\frac{1}{4}[/tex] of the distance.
Knowing that, you can identify that the whole distance (or the value of "x"), is the following:
[tex]x=\frac{4}{4}[/tex]
(If you simplify it, you get: [tex]x=1[/tex])
You also know that the second day Jolene drove farther than the first day; therefore, there are two possible cases for the part of the distance she might have driven the second day. These cases are:
Case 1: [tex]\frac{2}{4}[/tex] of the distance the second day.
Case 2: [tex]\frac{3}{4}[/tex] of the distance the second day.
1. The difference of a number and 3 equals 5
added to twice the number. Find the number.
Answer:
-8
Step-by-step explanation:
Let n represent the number. Then we have ...
n -3 . . . . the difference of a number and 3
= . . . . . . equals
5 +2n . . . 5 added to twice the number
Adding -n-5 to both sides of the equation gives ...
n -3 -n -5 = 5 +2n -n -5
-8 = n . . . . . simplify
The number is -8.