suppose you have 192 marbles in groups of 15 marbles each. find the number of groups of marbles that you have. write the quotient with the remainder written as a fraction. explain what the fraction part of your answer means

Answer:

A

Step-by-step explanation:

4 1/2  + 8 3/4

4+8 = 12

1/2 + 3/4 = 2/4 + 3/4 = 5/4 = 1 1/4

12 + 1 1/4 = 13 1/4

 Answer is C

Final answer:

To find the x and y components of a vector, use the cosine and sine functions, respectively, with the given angle. For a vector of 60m at 38°, the components are approximately 47.28m (x) and 36.96m (y).

Explanation:

To find the x and y components of a vector given its magnitude and a direction, you can use trigonometric functions. Assuming the vector Δr is the one you're referring to, with a magnitude of 60m and an angle of 38° (from the x-axis, presumed direction), you can apply the cosine function for the x-component and the sine function for the y-component of the vector.

For the x-component: x = magnitude × cos(angle) = 60m × cos(38°) = 60m × 0.788 = 47.28m

For the y-component: y = magnitude × sin(angle) = 60m × sin(38°) = 60m × 0.616 = 36.96m

Therefore, the x and y components of the vector are approximately 47.28m and 36.96m, respectively.

Answer:

The answer is 50 students

Step-by-step explanation:

There are 1,984 students in total at Palmer Elementary School and Palmer Middle School combined, showing an example of increasing school enrollments. This is calculated by simply adding the number of students from both schools.

Calculating the Total Number of Students

To find out how many students are in all at both Palmer Elementary School and Palmer Middle School, we add the number of students at each school together. Palmer Elementary School has 691 students, and Palmer Middle School has 1,293 students.

To determine the total, we perform the following addition:

Therefore, there are approximately 1,984 students in total at both schools combined. This calculation helps us understand the scale of student populations within a small section of the education system, reflecting broader national trends where school enrollments are increasing.

Twice the sum of a number and 3 is the same as 5 subtracted from the number. Then the number will be -11.

Sum refers to the addition of terms, while subtraction means removal.

Let the number be x

Following the given information:

sum of a number and 3 = x+3

Expression 1

Twice the sum of a number and 3 =2(x+3)

Expression 2

5 subtracted from the number=x-5

On equating both the expressions as follows:

2(x+3)=x-5

Solving the equation to get the value of x:

2x+6=x-5

2x-x=-5-6

x=-11

Thus, the number is -11.

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The value of the multiplication of the fractions will be equal to 27 / 70.

Multiplication is the process of determining the product of two or more numbers in mathematics. A product, or an expression that specifies factors to be multiplied, is what happens when you multiply two numbers in mathematics

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the fractions are 3/7 and 9/10. The multiplication of the number will be calculated as,

M = 3 / 7 x 9 / 10

M = 27 / 70

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The percentage of 47% can be expressed as the fraction 47/100 in simplest form. This means that 47 out of every 100 units can be represented by the fraction 47/100.

The percentage is given as 47%.

To write 47% as a fraction in simplest form, we can interpret the percent symbol as meaning "per 100."

Recognize that percent means "per 100." Therefore, 47% can be written as 47 per 100 or 47/100.

Simplify the fraction by finding the greatest common divisor (GCD) of the numerator and denominator. In this case, the GCD of 47 and 100 is 1.

Divide both the numerator and denominator by their GCD to simplify the fraction:

(47 ÷ 1) / (100 ÷ 1) = 47/100

The resulting fraction, 47/100, is already in its simplest form.

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The length of the height triangle ABC is BD i.e., [tex]15\;units[/tex].

According to the question, In isosceles [tex]∆ABC[/tex]  the segment BD is the median to the base AC . Also, the perimeter of ∆ABC is 50m, and the perimeter of the triangle [tex]ABD[/tex] is 40m.

Let the length of the equal sides of the isosceles triangle be [tex]x \;meters[/tex] and the length of the base of the isosceles triangle is [tex]2y\;meters[/tex].

[tex]Perimeter_{ABC}=x+x+2y\\2x+2y=50\\x+y=25\\x=25-y----(i)[/tex]

Also,

[tex]Perimeter_{ABD}=x+y+BD\\x+y+\sqrt{x^2-y^2}=40\\x+y+\sqrt{(25-y)^2-y^2}=40\\25+\sqrt{625-50y}=40\\\sqrt{625-50y}=15\\625-50y=225\\y=8\;units[/tex]

So,

[tex]x=25-8\\x=17\;units[/tex]

Now,

[tex]BD=40-x-y\\BD=40-17-8\\BD=15\;units[/tex]

Hence, the length of the height triangle ABC is BD i.e., [tex]15\;units[/tex].

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The equation that can be used to represent the number of three-pose and six-pose portrait packages is: 35x + 60y = 690

Word problems in mathematics are methods and approaches applied in solving real-life scenarios. Data can be modeled from the certain information given.

From the parameters given, Let us assume that:

Now, on Saturday a total amount of 690 was collected. This data can be modeled as:

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The critical numbers of the function f(θ) = 8sec(θ) + 4tan(θ) are where the derivative is undefined, specifically at θ = π/2 and θ = 3π/2.

To find the critical numbers of the function f(θ) = 8sec(θ) + 4tan(θ), we need to take its derivative and set it equal to zero or find where the derivative does not exist. First, we compute the derivative of the function. Recall that the derivative of sec(θ) is sec(θ)tan(θ) and the derivative of tan(θ) is sec2(θ).

Thus, the derivative f'(θ) is 8sec(θ)tan(θ) + 4sec2(θ). We look for where this derivative is undefined or equal to zero. The derivative is undefined when sec(θ) is undefined, which occurs at θ = π/2 and θ = 3π/2. To find where the derivative is zero, we can factor out 4sec(θ):

4sec(θ)(2tan(θ) + sec(θ)) = 0

The second factor will never be zero because sec(θ) and tan(θ) will not be zero for the same θ in the interval given. Therefore, the critical numbers are where the derivative is undefined, which is θ = π/2 and θ = 3π/2.

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Answer:

According to the distributive property of multiplication,

a . (b + c ) = (a . b) + (a . c)

Given: 7 × 6

which can be rewritten as: a)  7 . (4 + 2), b)   7 . (3 + 3), c)   7 . (1 + 5)

Rewriting the given expression using the distributive property of multiplication:

a)   7 . (4 + 2) = (7 . 4) + (7 . 2)

7 . (6) = 28 + 14

42 = 42

b)   7 . (3 + 3) = (7 . 3) + (7 . 3)

7 . (6) = 21 + 21

42 = 42

c)   7 . (1 + 5) = (7 . 1) + (7 . 5)

7 . (6) = 7 + 35

42 = 42

As the left hand side is equal to the right hand side in each case, therefore, it proves the distributive property.

The value of Equation is y = -3.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

We have Equation,

-3(y-5) = 24

Now, solving for y

Divide both side by (-3) we get

-3(y-5) / (-30= 24/ (-3)

y-5 = -8

Add 5 to both side

y- 5 +5 = -8 + 5

y = -3

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Answer:

B

Step-by-step explanation:

Answer:

The sum of the given expression is (m+1).

Step-by-step explanation:

The given expression is

[tex]\frac{1}{3}(9-6m)+\frac{1}{4}(12m-8)[/tex]

Use distributive property to to simplify the given expression.

[tex]\frac{1}{3}(9-6m)+\frac{1}{4}(12m-8)=\frac{1}{3}(9)+\frac{1}{3}(-6m)+\frac{1}{4}(12m)+\frac{1}{4}(-8)[/tex]

[tex]\frac{1}{3}(9-6m)+\frac{1}{4}(12m-8)=3-2m+3m-2[/tex]

Add like terms.

[tex]\frac{1}{3}(9-6m)+\frac{1}{4}(12m-8)=(3-2)+(-2m+3m)[/tex]

[tex]\frac{1}{3}(9-6m)+\frac{1}{4}(12m-8)=(1)+(m)[/tex]

[tex]\frac{1}{3}(9-6m)+\frac{1}{4}(12m-8)=m+1[/tex]

The sum of the given expression is (m+1).

Answer:

4:1

Step-by-step explanation:

We are given that

Point L(-2,5) and M(2,-3).

Point Q([tex]\frac{6}{5},\frac{-7}{5})[/tex] partitions LM .

We have to find the ratio in which Q divides the LM.

Let point Q divides the LM in the ratio K:1.

Section formula;[tex]x=\frac{m_1x_2+m_2x_1}{m_1+m_2},y=\frac{m_1y_2+m_2y_1}{m_1+m_2}[/tex]

Substitute the values in the given formula  then we get

[tex]\frac{6}{5}=\frac{2k-2}{k+1}[/tex]

[tex]6k+6=10k-10[/tex]

[tex]6+10=10k-6k[/tex]

[tex]16=4k[/tex]

[tex]k=\frac{16}{4}=4[/tex]

Hence, the point Q divides the LM in the ratio 4:1.

divide:

28 / 0.32 = 87.5