Suppose two hosts, A and B, are separated by 15,000 kilometers and are connected by a direct link of R = 5 Mbps. Suppose the propagation speed over the link is 2.5 * 108 meters/sec.How long does it take to send a 1,500,000 bit file, assuming it is sent continuously?

Answer:

maxWithdraw = 500; //Initialise maximum withdrawal amount

Charges = 0; // Initialise Charges

Input Amount; //Customer input amount to withdraw

Get AvailableAmount; // System reads customer available amount

if (Amount >= 300)

{

Charges = (Amount -300) * 0.04; //Calculate charges when amount to withdraw is greater than or equal to 300

}

if (AvailableAmount <= 0)

{

Amount = 0; //Initialise amount to 0 if customer balance is less than or equal to 0

}

if (AvailableAmount < Amount) {

Print “You do not have sufficient funds";

Charges = 25;

}

if (Amount > 500) {

Print "Maximum withdrawal amount is $500"

}

if (Charges > 0) {

AvailableAmount -= Amount;

AvailableAmount-= Charges);

}

if (Charges = 0) {

AvailableAmount -= Amount; }

Dispense Cash.

Answer:

Answer is provided in the Explanation section

Explanation:

#include &lt;stdio.h&gt;

// Function to find the nth integer of Fibonnaci sequence

int fib(int n)

{

 if( n &lt;= 1)

   return n;

 int prev_num = 0, curr_num =1;

 for(int i =0; i &lt; n-1 ; i++)

 {

     int newnum=prev_num + curr_num;

     prev_num=curr_num;

     curr_num=new_num;

 }  

 return curr_num;

}

int main(void)

{

   printf(&quot;%d&quot;,fib(8));

   return 0;

}

Output = 21

Answer:

In centralized method, the authorized sender is known, but the transmission line is dominated by the control station, while in decentralized method, one station can not dominate the line but collision on the transmission line may occur.

Explanation:

Centralized method of communication requires for a control station to manage the activities if other stations in the network. It assigns turns to one known station at a time, for transmission.

Decentralized method allows stations in a network to negotiate and take turns in transmitting data. When a station is done with the transmission line, another station on the queue immediately claims the line.

Answer:

Option(d) i. e "Data Source Configuration"  is the correct answer for the given question.

Explanation:

In the ADO.Net of Visual basic 2012 when we want to create the dataset we used the Data Source Configuration wizard. The Data Source Configuration wizard helps to connect with the database in the visual basic of the 2012 application. The Following are the step when we want to create the Dataset.

Final answer:

In complex microservices architectures, the Client-side discovery pattern is often recommended due to the control it offers clients. However, the Server-side discovery pattern is more suitable for systems with many services or frequent changes. The Self-registration pattern is typically used with one of the other two patterns.

Explanation:

The question pertains to service registration patterns in microservices architectures. In a complex architecture, the most recommended registration pattern is often the A) Client-side discovery pattern. This pattern allows clients to query a service registry, which holds the locations of various service instances. The client-side discovery pattern enables the clients to handle the discovery logic, providing a high degree of control over service invocation.

However, in a system with many services or frequent changes, the Server-side discovery pattern might be more suitable. Here, a server-side service registry is responsible for tracking service instances, and clients make requests via a router that queries the registry and directs each call to the appropriate service. This pattern offloads discovery responsibility from the client, simplifying the client-side logic.

Finally, the Self-registration pattern is where each service instance is responsible for registering and de-registering itself with the service registry. It is often used in combination with either the client-side or server-side discovery pattern.Ultimately, the choice depends on the specific requirements and constraints of the architecture in question, including scale, complexity, and the ability to handle failure scenarios.

Final answer:

In complex architectures, the Third-Party Registration Pattern is typically better suited compared to the Client-Side Discovery Pattern or Self-Registration as it centralizes service information and simplifies the discovery process.

Explanation:

When dealing with complex architecture within a microservices or distributed systems context, the Client-Side Discovery Pattern may not be ideal due to its inherent complexity and the need for each client to manage discovery logic.

The Third-Party Registration Pattern, also known as the Service Registry pattern, is oftentimes more suited for complex architectures. In this pattern, services register themselves with a third-party registry, which clients then query to discover network locations of available service instances.

This decouples the discovery process from the client and the service, centralizing service information and simplifying the overall architecture.

The Self-Registration pattern can be used in conjunction with the Third-Party Registration Pattern; however, it requires that each service instance has the logic to register and deregister itself with the service registry, which could become cumbersome in a system that is very large or highly dynamic.

Answer:

A. the processes, methods, and techniques to ensure that data is of high quality, reliable, and unique (not duplicated), so that downstream uses in reports and databases are more trusted and accurate

Explanation:

Data governance consists of the processes, methods, and techniques to ensure that data is of high quality, reliable, and unique (not duplicated), so that downstream uses in reports and databases are more trusted and accurate. Master data management (MDM) tools can assist in this effort.

Once the definitions of these three information-related governance disciplines are clear, their differences become more distinct.

Answer:

The answer to this question as follows:

Explanation:

The answer & explanation for this question is given in the attachment below.

Answer:

The algorithm to this question as follows:

Algorithm:

finding_small_element(element,Key xa) //defining method that accepts parameter

{

if (element.value>= xa) //check value

{

//skiping node

return;  

}

print(element.value);//print value

if (element.left != NULL) //check left node value

{

finding_small_element(element.left,xa); //using method

}

if (element.right != NULL) //check right node value

{

finding_small_element(element.right,xa); //using method

}

}

Explanation:

In the above pre-order traversing algorithm a method  "finding_small_element" is defined, that accepts two parameter, that is "element and ax', in which "element" is node value and ax is its "key".

Final answer:

An efficient algorithm to find keys in a min heap smaller than a given value X is to use DFS, starting at the root and adding each key less than X to a result list, with the time complexity being O(n) in the worst case.

Explanation:

Finding Keys Smaller Than X in a Min Heap

To find all keys in a min heap that are smaller than a provided value X, we can use a depth-first search (DFS) algorithm. Since a min heap is a complete binary tree where the key at the root is less than or equal to the keys in its children, and this property applies recursively to subtrees, we can traverse the min heap efficiently with the following approach:

The time complexity of this algorithm is O(n), where n is the number of elements in the min heap, because in the worst case, we might have to visit every node. However, thanks to the properties of the min heap, we can often avoid exploring all nodes, making the algorithm more efficient in practice than O(n).

Answer:

The correct expression for the following question is :s[0 : 4]

Explanation:

The string is the collection of characters It terminated by the NULL character in the c programming language. The s[0 : 4] expression holds the first four characters of string s. In the expression it starts to the position "0" and goes to the index value "4"  .in this string it holds the value up to the four characters.

We can store the four-character in the string:s[0 : 4].

To extract the first four characters of a string in Python, you can use string slicing with the syntax string_name[start:end].

To retrieve the first four characters of a string, you can use string slicing. In Python, you can use the syntax string_name[start:end] to extract a portion of a string. In this case, you would use s[0:4] to get the first four characters of the string s. Here's an example:

Answer: Procedural software

Explanation:

Procedural software programming is the programming mechanism that functions through splitting the data and functions of the program.This programming focuses on subroutines or action for functioning as per call of procedure.

Answer:

Option A 0 is best option

No desktop and server software application are installed on the target Windows server.

Explanation:

The MAP Inventory used for monitoring the server to make sure it does not install any other applications. That’s why there is no desktop and server software application is installed on it.  So best option for this question is A

Answer:

C

Explanation:

To access any database you of course need to establish a connection with it, which then proceeds to the user verification process of the data implemented.

Answer:

Method:- This is related to hackers technique and way of accessing to copy other data. It also includes the skill, knowledge, tools and other things with which to be able to pull off the attack.

Opportunity:- this is related to how a user gives way to access to the hackers. It includes the time, the chance, and access to accomplish the attack.

Motive:- This may relate to the hacker to destroy the reputation of another or for money. It is reason to want to perform this attack against this system

Final answer:

Authentication attacks leverage the method, opportunity, and motive paradigm to breach security systems. Employing stronger authentication measures, reducing security vulnerabilities, and understanding potential motives can significantly enhance protection against these attacks.

Explanation:

Understanding Authentication Attacks Through Method, Opportunity, and Motive

Authentication attacks are sophisticated efforts to bypass security measures and access unauthorized information. These attacks thrive on the method, opportunity, and motive paradigm, making it vital for users and organizations to understand these concepts to bolster their defenses.

Let’s delve into how these three factors play a crucial role.

In conclusion, defending against authentication attacks requires a comprehensive strategy that addresses the method, opportunity, and motive. By understanding and mitigating these aspects, organizations and individuals can significantly enhance their digital security.

Answer:

Answer is provided in the explanation section

Explanation:

Convert 8-bit 2’s complement form into 16-bit 2’s complement form.

First write value in binary then check for 8 th bit value. If it is positive the upper 8 bits will  be zero otherwise will be 1s.

8-bit number   Binary of number    Insert 8 bits                  16-bit number

0X94                1001-0100                 1111-1111-1001-0100            0XFF94

0XFF                1111-1111                       1111-1111-1111-1111                 0XFFFF

0X23                0010-0011                 0000-0000-0010-0011    0X0023

0XBC               1011-1100                    1111-1111-1011-1100              0XFFBC

Which of the following 16-bit 2’s complement form can be shortened to 8-bits?

16-bit number        8-bit number

0X00BA                  0XBA

0XFF94                   MSB bits are not zero so we can’t  truncate it to 8-bit No

0X0024                  0X24

0XFF3C                   MSB bits are not zero so we can’t  truncate it to 8-bit No

Answer:

Cloud Computing        

Explanation:

Cloud Computing is basically an infrastructure to deliver various computing resources and services  to the users online (via Internet). These resources include networks, applications, servers, databases, software, storage etc.

These services are mostly utilized by organizations for recovery and backup of data, using virtual hardware and other computing resources such as desktops, memory etc. Cloud computing is also used for developing software, for securing data by providing with access control and for storing bulk of data.

The benefits of cloud computing are as following:

Because of cloud computing the customers do not have to buy hardware or install software on their computer which might be very costly to maintain and update. Servers and data centers are provided by cloud service providers and experts are available for managing the services and resources.

These services are scalable and can be adjusted as per the users requirements.

Cloud computing offers a variety of protocols, tools, and access controls that improve security and protects confidential data, applications, and networks against security threats and attacks. It also provides with data backup, disaster recovery.

A degree supplemented by a Certifications provides greater competencies in the field and makes a candidate even more marketable to a potential employer.

Explanation:

Computer forensics is field of digital evidences.In a civil or Criminal case computer forensics technology is used to study the digital evidences(like retrieval of deleted files,encrypted files,usage of various disk)

Answer:

package healthcare;

import java.util.Calendar;

public class HealthProfile {

  private String firstName;

  private String lastName;

  private char gender;

  private int day;

  private int month;

  private int year;

  private double height;

  private double weight;

  public HealthProfile(String firstName, String lastName, char gender, int day, int month, int year, double height,

          double weight) {

      super();

      this.firstName = firstName;

      this.lastName = lastName;

      this.gender = gender;

      this.day = day;

      this.month = month;

      this.year = year;

      this.height = height;

      this.weight = weight;

  }

  public String getFirstName() {

      return firstName;

  }

  public void setFirstName(String firstName) {

      this.firstName = firstName;

  }

  public String getLastName() {

      return lastName;

  }

  public void setLastName(String lastName) {

      this.lastName = lastName;

  }

  public char getGender() {

      return gender;

  }

  public void setGender(char gender) {

      this.gender = gender;

  }

  public int getDay() {

      return day;

  }

  public void setDay(int day) {

      this.day = day;

  }

  public int getMonth() {

      return month;

  }

  public void setMonth(int month) {

      this.month = month;

  }

  public int getYear() {

      return year;

  }

  public void setYear(int year) {

      this.year = year;

  }

  public double getHeight() {

      return height;

  }

  public void setHeight(double height) {

      this.height = height;

  }

  public double getWeight() {

      return weight;

  }

  public void setWeight(double weight) {

      this.weight = weight;

  }

  public int calculateAge() {

      Calendar dateOfBirth = Calendar.getInstance();

      dateOfBirth.set(year, month, day);

      Calendar now = Calendar.getInstance();

      return now.get(Calendar.YEAR) - dateOfBirth.get(Calendar.YEAR);

  }

  public int maximumHeartRate() {

      return 220 - calculateAge();

  }

  public double[] targetHeartRateRange() {

      double[] range = new double[2];

      // Calculate Stating range(50 % of maximumHeartRate)

      range[0] = 0.5 * maximumHeartRate();

      // Calculate End range(85 % of maximumHeartRate)

      range[1] = 0.85 * maximumHeartRate();

      return range;

  }

  public double calculateBMI() {

      return (weight * 703)/(height * height);

  }

  public String getBMIValue()

  {

      double bmi=calculateBMI();

      if(bmi < 18.5)

      {

          return "Underweight";

      }

      else if (bmi>18.5 && bmi<24.9)

      {

          return "Normal";

      }

      else if (bmi>25 && bmi<29.9)

      {

          return "Normal";

      }

      else if (bmi>=30)

      {

          return "Obese";

      }

      return "DafultValue"; //you can give any default value of your choice here if no condition meets the given criteria

  }

  @Override

  public String toString() {

      return "HealthProfile [firstName=" + firstName + ", lastName=" + lastName + ", gender=" + gender + ", Date Of Birth="

              + day + "-" + month + "-" + year + ", height=" + height + ", weight=" + weight + "]";

  }

}

package healthcare;

import java.util.Scanner;

public class TestHealthCare {

  private static Scanner sc;

  public static void main(String[] args) {

      sc = new Scanner(System.in);

      System.out.println("Please enter following details of the Patient");

      System.out.println("First Name");

      String firstName=sc.nextLine();

      System.out.println("Last Name");

      String lastName=sc.nextLine();

      System.out.println("Gender ...... M or F ?");

      char gender=sc.next().charAt(0);

      System.out.println("Date of Birth");

      System.out.println("Day");

      int day=sc.nextInt();

      System.out.println("Month");

      int month=sc.nextInt();

      System.out.println("Year");

      int year=sc.nextInt();

      System.out.println("Height in inches");

      double height =sc.nextDouble();

      System.out.println("weight (in pounds)");

      double weight =sc.nextDouble();

      HealthProfile obj=new HealthProfile(firstName, lastName, gender, day, month, year, height, weight);

      int age=obj.calculateAge();

      System.out.println("Patient age is   "+age + " Years");

      int maxHeartRate=obj.maximumHeartRate();

      System.out.println("Patient Maximum Heart Rate is   "+maxHeartRate + " beats per minute");

      //Call targetHeartRateRange

      double targetHeartRateRange []=obj.targetHeartRateRange();

      System.out.println("Target Heart Range is   "+targetHeartRateRange [0] + " - " +targetHeartRateRange [1]);

      //Call calculateBMI

      double bmi=obj.calculateBMI();

      System.out.println("Patient BMI is   "+bmi);

      //call getBMIValue

      System.out.println("Patient BMI Value is   "+obj.getBMIValue());

  }

}

Explanation:

The completed function "PrintPopcornTime()" can be referred to as given below.

We have,

The completed function "PrintPopcornTime()" as requested:

void PrintPopcornTime(int bagOunces) {

   if (bagOunces < 2) {

       System.out.println("Too small");

   } else if (bagOunces > 10) {

       System.out.println("Too large");

   } else {

       int time = 6 * bagOunces;

       System.out.println(time + " seconds");

   }

   System.out.println();

}

In this function, we check the value of "bagOunces" using conditional statements.

If it's less than 2, we print "Too small".

If it's greater than 10, we print "Too large".

Otherwise, we calculate the time by multiplying 6 with "bagOunces" and print it followed by " seconds".

Finally, we print a new line to end the output.

Thus,

The completed function "PrintPopcornTime()" can be referred to as given above.

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Final answer:

The question involves creating a function, PrintPopcornTime(), that uses conditional logic to print different messages based on the provided parameter value, demonstrating fundamental programming concepts such as if-else statements and arithmetic operations.

Explanation:

The question asks to complete a function named PrintPopcornTime() in a programming context, which requires conditional logic to print different outputs based on the value of the parameter bagOunces. The function is supposed to print "Too small" if the value of bagOunces is less than 2, "Too large" if the value is greater than 10, and compute the time in seconds (by multiplying bagOunces by 6) to print for any value between 2 and 10 inclusive.

To fulfill this requirement, a combination of if-else statements can be used to check the size of bagOunces and print the corresponding message. The computation and print statement for values between 2 and 10 inclusive uses the logic of 6 * bagOunces followed by appending " seconds" to the result. Here's an example in pseudocode:

void PrintPopcornTime(int bagOunces) {
 if (bagOunces < 2) {
   print("Too small");
 } else if (bagOunces > 10) {
   print("Too large");
 } else {
   print(6 * bagOunces + " seconds");
 }
 print("\n"); // Prints a newline
}

This function demonstrates basic control structures like conditional statements which are fundamental in programming.

Answer:

Hi! The requirement of this question is a simple shell script that makes a copy of a file if it exists in the directory. The main command for this is "cp <file_to_copy> <copy_filename>"  

Explanation:

We can write a code below to implement this in a file called "backup_script". The first argument to the script is taken as the fie_name. Then a check is done to see if the file exists with the "[-f file_name]" code, and the file is copied with a ".bak" if true. A success message is finally printed out to the user.

./backup_script

#! /bin/bash

set file_name = $1

if [ -f file_name ]; then

 cp file_name file_name.bak

fi

if [ -f file_name.bak ]; then

 echo "File successfully copied"

fi

Answer:

Python program is given below

Explanation:

def output_ints_less_than_or_equal_to_threshold(user_values, upper_threshold):

   print("The integers that are less than or equal to", upper_threshold, "are:")

   for value in user_values:

       if value < upper_threshold:

           print(value)

def get_user_values():

   n = int(input("Enter the number of integers in your list: "))

   lst = []

   print("Enter the", n, "integers:")

   for i in range(n):

       lst.append(int(input()))

   return lst

if __name__ == '__main__':

   userValues = get_user_values()

   upperThreshold = int(input("Enter the threshold value: "))

   output_ints_less_than_or_equal_to_threshold(userValues, upperThreshold)

The question is about writing a Python program that filters a list of integers, outputting only those less than or equal to the last integer in the list, based on user input.

Python Program to Filter Integers

To write a Python program that filters integers from a list based on a specific condition, you'll first need to capture user input. Since the user will indicate the number of integers followed by the integers themselves, you can use a loop to collect these values. Afterward, you can compare each integer to the last value obtained from the input and output all integers less than or equal to this last value.

Here's an example code:

num_of_integers = int(input())
integers_list = []

for _ in range(num_of_integers):
   integers_list.append(int(input()))

threshold = integers_list[-1]

for value in integers_list[:-1]:
   if value <= threshold:
       print(value)

This program stores all integers in a list, then iterates over the list except the last element and prints out those integers that are less than or equal to the last value in the list.

To prevent errors in spreadsheet software, improve the interface by providing clear input validation, formula assistance, error messages, data validation, version control, incorporating user testing and feedback.

One piece of software that often involves errors is spreadsheet software, such as Microsoft Excel.

These errors can range from simple calculation mistakes to more complex issues in formulas, references, and data input.

To improve the interface and prevent errors in spreadsheet software, consider the following suggestions:

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Microsoft Excel is a software where it is easy to make errors due to its complex nature. Improvements could be made to the interface such as effective tool-tips, a simplified menu, a comprehensive help guide, and an 'undo' button.

A piece of software I often use where it is easy to produce an error is Microsoft Excel. The complex, multifunctional nature of Excel means that users can easily input incorrect formulae or make errors in data entry.

To improve the interface, Microsoft could improve tool-tips that explain the function of each tool more effectively, simplify the menu by grouping related functions together and develop a more comprehensive and easily accessible help guide. Also, adding an 'undo' button that has more stages would be helpful, as errors could be quickly rectified.

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Answer:

Hackers can snoop on data sent over your network.

Hackers can use your network to access your computer's files and system information.

Explanation: Unsecured Wireless connections are wireless connections which are have no passwords they are open to the general public,such networks can be very risky to use as it gives easy access to dishonest persons who can manipulate that opportunity to SNOOP ON DATA SENT OVER YOUR NETWORKS. They can use this hacking to fraudulently steal from your bank account and obtain your private information.

When connecting to an unsecured wireless network, dishonest or unscrupulous computer users may try to eavesdrop, intercept data, and gain unauthorized access to personal information.

When connecting to an unsecured wireless network, dishonest or unscrupulous computer users may attempt to carry out various malicious activities such as eavesdropping, data interception, and unauthorized access to your devices and personal information.

For example, they may use packet sniffing techniques to capture sensitive data transmitted between your devices and the network, such as passwords or credit card information. They can also launch man-in-the-middle attacks, where they intercept data between your device and the network to gain unauthorized access or manipulate the information exchanged.

To protect yourself, it is important to always connect to a secure and encrypted network, use a virtual private network (VPN) for added security, and avoid transmitting sensitive information over unsecured networks.

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Answer/Explanation:

Answer:

C. Symptoms of malware mutation

Explanation:

They are signs that could indicate that ones system is infected by virus.

Such signs includes:

1.Slow booting or startup.

2.Low space storage.

3.Blue screen of death.

4.Slow Internet performance.

5.Sending of spam messages.

6.Disabled security.

7.Browsing error.

8.Pop-up messages.

9.Renaming of files.

10.Loss of certain files, music, messages, etc.

Answer:

Option c: Symptoms of malware mutation

Explanation:

The most common symptom of a malware mutation is a slow running computer. The main activity of malware programs is to slow down your operating system and cause problems with your local applications even you are not using the internet. Event log reports unusual alerts and RAM is consumed by virus programs which makes RAM unavailable for your tasks.

Answer:

The codes for the respective blanks are given below with appropriate comments for better understanding

Explanation:

FOR 1 TO 4

Void StackType::Push(ItemType item)

{

if(top == MAX_STACK - 1) // means stack is full so we need to throw the PushOnFullStack exception

throw PushOnFullStack ; // You can use this class and appropriate method to deal with exception like printing that stack is full so can not push the current item

top ++ ;// increment the top to accumulate the next item

items[top] = item; // put the item into the place identified

}

FOR 5 AND 6

Void Quetype::enqueue(itemType item)

{

if (rear==MAX_QUEUE && front==0) // queue is full so can not enqueue

//Handle the queue full exception here, may be print this

}else

{

items[rear] = item;

rear ++;

}

Answer and Explanation:

The information revolution has had profound impacts on decision-making allowing more informed decision as a result of "stone throw" information reach- in our pockets, the desk, the TV, and the vast number of technologies that make this possible.

Standardized data which involves data formatted to bring uniformity and be easily understood and compared by programs and people , access to rich, outsider dataset and less tasking and flexible plus powerful programming have all contributed to empowering another time of information driven decision-making that are less prone to errors and mistakes.

Answer:

Following is given the code step-by-step with all necessary decsription as comments in it. I hope it will help you!

Explanation:

Answer:

Option C is the correct option.

Explanation:

In the above scenario, Advancements in storage technologies and fast-declining storage prices are undermining growth in the mobile device because current mobile devices have many useful features of data storage and it can also use in other fields such as cloud storage, also in word processing and many other areas which are useful for the users.

Answer:

Java program is explained below with appropriate comments

Explanation:

Temperature.java

import java.util.Scanner;

public class Temperatures {

public static Scanner keyboard = new Scanner(System.in);

private static int highTemperature, lowTemperature,averageHigh, averageLow;

private static int index;//keeps track of months

private static int indexOfHighestTemp=0, indexOfLowestTemp=0;

private static int[][] highAndLowTemps = new int [12][2];//array for highs and lows

private static String[] months = new String[12];//array of monthss

public static void main(String[] args) {

inputTempForYear();

calculateAverageHigh(highAndLowTemps);

calculateAverageLow(highAndLowTemps);

findHighestTemp(highAndLowTemps);

findLowestTemp(highAndLowTemps);

//outputs results

System.out.println("Average High: "+averageHigh);

System.out.println("Average Low: "+averageLow);

System.out.println("Highest Temp and Month: "+highAndLowTemps[indexOfHighestTemp][0]+" "+months[indexOfHighestTemp]);

System.out.println("Lowest Temp and Month: "+highAndLowTemps[indexOfLowestTemp][1]+" "+months[indexOfLowestTemp]);

}

private static void inputTempForMonth(int[][] highAndLowTemps)

{

System.out.println("Input the high temperature for "+months[index]+":");

highTemperature = keyboard.nextInt();//inputs months high temp

highAndLowTemps[index][0]=highTemperature;

System.out.println("Input the low temperature for "+months[index]+":");

lowTemperature = keyboard.nextInt();//inputs months low temp

highAndLowTemps[index][1]=lowTemperature;

}

private static int[][] inputTempForYear()

{

months[0]="January";

months[1]="Febuary";

months[2]="March";

months[3]="April";

months[4]="May";

months[5]="June";

months[6]="July";

months[7]="August";

months[8]="September";

months[9]="October";

months[10]="November";

months[11]="December";//fills month array

for (index=0;index<=11;index++)//fills array with highs and lows

{

inputTempForMonth(highAndLowTemps);

}

return highAndLowTemps;

}

private static int calculateAverageHigh(int[][] highAndLowTemps)

{

for(int i=0;i<=11;i++)//finds sum of high temps

{

averageHigh=averageHigh+highAndLowTemps[i][0];

}

averageHigh/=12;//calculates average

return averageHigh;

}

private static int calculateAverageLow(int[][] highAndLowTemps)

{

for(int i=0;i<=11;i++)//finds sum of low temps

{

averageLow=averageLow+highAndLowTemps[i][1];

}

averageLow/=12;//calculates average

return averageLow;

}

private static int findHighestTemp(int[][] highAndLowTemps)

{

double max=highAndLowTemps[0][0];

int indexHigh;//index for highest

for(indexHigh=0;indexHigh<11;indexHigh++)//find highest high temp

{

if(highAndLowTemps[indexHigh][0]>max)

{

max=highAndLowTemps[indexHigh][0];

indexOfHighestTemp=indexHigh;

}

}

return indexOfHighestTemp;

}

private static int findLowestTemp(int[][] highAndLowTemps)

{

double min=highAndLowTemps[0][1];

int indexLow;//index for lowest

for(indexLow=0;indexLow<11;indexLow++)//finds lowest low temp

{

if(highAndLowTemps[indexLow][1]<min)

{

min=highAndLowTemps[indexLow][1];

indexOfLowestTemp=indexLow;

}

}

return indexOfLowestTemp;

}

}