Answer:
m=13 b=17
Step-by-step explanation:
Answer:
m=13 b=17
hope this helps
What is the probability that 2 cards selected from a standard deck of 52 cards without replacement are both non-face cards?
A. 0.412
B. 0.588
C. 1.534
D. 0.408
Answer:
B. 0.588
Step-by-step explanation:
There are 40 non-face cards in the deck, so the probability of drawing the first one is 40/52. After doing that, the probability of drawing the second one is 39/51, since the number of non-face cards is 1 fewer, as is the size of the deck.
The joint probability is then ...
(40/52)·(39/51) ≈ 0.588
a student drawer the net below to show the dimensions of a container that Is shaped like a right rectangular prism
What is the surface area in square inches of the container
Give me a few minutes and ill tell you the answer : )
39.9875 rounded to the nearest thousandth
the answer is.... 39.988
Your favorite breakfast cereal contains a toy dinosaur in each box. There are four different dinosaur toys in the complete collection, and each one has an equal chance of being in each box.
You want to figure out what the probability is that you will get more than one tyrannosaurus rex if you buy five boxes of cereal. Which experiment could be used to simulate this situation?
A) You flip a coin 5 times and record the number of times you get tails. You do 10 trials of the experiment, then calculate the percentage of trials that resulted in 2 or more tails.
B) You draw 5 cards from a deck of cards and record how many spades you get. You do 10 trials of the experiment, then calculate the percentage of trials that resulted in 2 or more spades.
C) You spin a 5-color spinner 4 times and record how many times you get a blue. You do 10 trials of the experiment, then calculate the percentage of trials that resulted in 2 or more blue spins.
D) You put 5 different colored marbles in a bag. You draw 4 marbles out and record how many are red. You do 10 trials of the experiment, then calculate the percentage of trials that resulted in 2 or more red marbles.
Answer:
The correct answer on USATestprep is B.
Step-by-step explanation:
Final answer:
To simulate the probability of obtaining more than one tyrannosaurus rex toy in five cereal boxes, we can use a deck of cards (Option B). Drawing five cards in 10 trials and counting the number of spades mirrors the conditions of the cereal box toy scenario. The law of large numbers ensures that this simulation's results will approach the actual probability with enough trials.
Explanation:
The question asks about the probability of obtaining more than one tyrannosaurus rex toy when buying five cereal boxes, each with an equal chance of containing one of four different dinosaur toys. To simulate this situation accurately, the experiment must mimic the conditions of the actual scenario by having four equally likely outcomes and a sample size of five.
Option B is the most suitable simulation for this situation because it replicates these conditions using a deck of cards. If we consider each dinosaur to be analogous to a suit in a standard deck of cards, then drawing five cards and recording the number of a particular suit (such as spades) simulates the probability of getting a particular dinosaur toy. We then repeat this simulation in multiple trials to estimate the probability based on the relative frequency of getting more than one spade, which would represent obtaining more than one tyrannosaurus rex toy.
Through simulations and the law of large numbers, we can acquire an empirical probability that approximates the theoretical probability. However, it's crucial to conduct a sufficient number of trials to ensure a sound approximation of the probability.
is y=(x-4)(x+5) a quadratic formula
Answer:
yes
Step-by-step explanation:
It is the factored form of a 2nd-degree polynomial, so is a quadratic function.
Please I need help with these 3 questions with explanation. See attached below.
Please help!
Answer:
18. compound interest
19. simple interest
20. simple interest
Step-by-step explanation:
For these problems, the initial balance is irrelevant. All that matters is the multiplier of that balance. For simple interest at rate r for t years, the multiplier is ...
simple interest multiplier = (1 +rt)
For interest compounded annually, the multiplier of the initial balance is ...
compound interest multiplier = (1 +r)^t
A spreadsheet can do the computations for you.
___
As an example of the computations involved, consider problem 19:
simple interest multiplier = 1 + 0.13·6 = 1.78
compound interest multiplier = 1.10^6 = 1.771561
The latter is less than the former, so the simple interest account will have the (slightly) greater balance at the end of 6 years.
If I have a C (70.76%) and get a zero on a test that is 10% of my grade, would I be passing or failing
Answer:
Your average would drop to 63.68%. Ask your grader if that is passing.
Step-by-step explanation:
If 10% of your grade is zero, the remaining amount is 90% of 70.76%, ...
0.90·70.76% = 63.684% ≈ 63.68%
The letter grade associated with this depends on class or school standards. Ask your grader what it is.
Can someone please help me on this
Answer:
See attached
Step-by-step explanation:
The graphs marked with a red X do not pass the vertical line test, so are not functions. (A vertical line must intersect the graph of a function in only one point.)
The curve at lower right is a function, but it isn't clear if it meets the requirement for "lines that represent functions", since it is not a straight line.
The number of seats in each row of a theater forms an arithmetic sequence. The fifth row contains 22 seats. The tenth row contains 37 seats . How many seats are in the first row?
Let [tex]s_n[/tex] denote the number of seats in the [tex]n[/tex]-th row. [tex]s_n[/tex] is arithmetic, so
[tex]s_n=s_{n-1}+d[/tex]
for some constant [tex]d[/tex].
We're told [tex]s_5=22[/tex] and [tex]s_{10}=37[/tex], so that
[tex]s_{10}=s_9+d[/tex]
[tex]s_{10}=(s_8+d)+d=s_8+2d[/tex]
[tex]s_{10}=(s_7+d)+2d=s_7+3d[/tex]
and so on up to
[tex]s_{10}=s_5+5d\implies37=22+5d\implies5d=15\implies d=3[/tex]
The pattern continues:
[tex]s_5=s_4+3[/tex]
[tex]s_5=(s_3+3)+3=s_3+2\cdot3[/tex]
and so on up to
[tex]s_5=s_1+4\cdot3\implies22=s_1+12\implies\boxed{s_1=10}[/tex]
Answer:
8
Step-by-step explanation:
HELP PLEASE
must show work
I have the answer just need to show work
Answer:
Step-by-step explanation:
To solve these equations involving variables and exponents we need to follow these steps.
1) We need to find out the factor that is common in the equation.
2) After taking common, solve the equation. We can add or subtract only those values that have same bases.
1) [tex]8+6x^4[/tex]
here we can see, both numbers are divisible by 2, so taking 2 common
[tex]=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)[/tex]
It cannot be further simplified because both number donot have same bases.
3.[tex]4n^9 + 12 n[/tex]
We can take 4n common
[tex]=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)[/tex]
5. -12a -3
Here -3 cam be taken common
= -3(-12a/-3 -3/-3)
= -3(4a +1)
7. [tex]12n^5 + 16n^3[/tex]
here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common
[tex]4n^3( 3n^2 + 4)[/tex]
9. [tex]5k^2 - 40k+10[/tex]
Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common
[tex]=5(k^2 - 8k + 2)[/tex]
11.[tex]-60 + 60n^2 +50n^3[/tex]
Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common
[tex]=10(-6 + 6n^2 +5n^3)[/tex]
13. [tex]-36n^3 -12n-28[/tex]
Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common
[tex]=-4(9n^3 + 3n +7)[/tex]
15. [tex]63n^3+81n+18[/tex]
Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common
[tex]=9(7n^3 + 9n + 2)[/tex]
17. [tex]-24a^2b^2 + 36ab-60a[/tex]
[tex]=6a(-4ab^2+6b-10)[/tex]
Jack is 5 1/2 feet tall and casts a 9-ft shadow. At the same time, a basketball hoop casts a 24-foot Shadow. How tall is the basketball hoop?
ANSWER
The height of the basketball hoop is
[tex]14 \frac{2}{3} ft[/tex]
EXPLANATION
Let the height of the basketball hoop be x feet.
The shadow of the basketball hoop is 9 ft long.
The height of Jack is 5.5 feet.
Jack's shadow is 9 ft long.
By similar triangles,
[tex] \frac{x}{5.5} = \frac{24}{9} [/tex]
Multiply both sides by 5.5
This gives us,
[tex]x = \frac{24}{9} \times 5.5[/tex]
[tex]x = \frac{132}{9} [/tex]
[tex]x = 14 \frac{2}{3} [/tex]
The height of the basketball hoop is 14⅔ feet
Find the slope of the line if its exists.
Answer:
5/4
Step-by-step explanation:
slope is rise/run, 5 is the amount rising or going up and is running straight
A swimming pool in the shape of a right rectangular prism is filled with water. The pool is 25 yards long, 10 yards wide, and 2 feet deep. Water has an approximate density of 62.4 pounds per cubic foot. What is the weight of the water in the pool to the nearest pound? Enter the number only.
The weight of the water in the pool to the nearest pound is 280,800 pounds.
To find the weight of the water in the swimming pool, we need to calculate the volume of the pool in cubic feet and then use the density of water to determine the weight.
Convert dimensions to consistent units:
The depth of the pool is given in feet (2 feet), so we need to convert the length and width from yards to feet.
1 yard = 3 feet
Length = 25 yards × 3 feet/yard = 75 feet
Width = 10 yards × 3 feet/yard = 30 feet
Calculate the volume of the pool:
Volume = length × width × depth
Volume = 75 feet × 30 feet × 2 feet = 4,500 cubic feet
Calculate the weight of the water:
Weight of water = volume × density
Density of water = 62.4 pounds per cubic foot
Weight = 4,500 cubic feet × 62.4 pounds/cubic foot = 280,800 pounds
Kay is a student in Mrs. Hudson’s class. Assuming you know nothing else about Kay, what is the probability that Kay’s birthday will fall on a weekday in any given year?
1. List the sample space for this problem.
2. Which outcome (or outcomes) of the sample space composes the event?
3. Express the probability of Kay’s birthday falling on a weekday as a fraction and as a decimal.
4. Describe the probability of Kay’s birthday falling on a weekday as impossible, unlikely, neither likely nor unlikely, likely or certain. Justify your response.
In a given week, there are seven possible outcomes for Kay's birthday falling on a particular day. Five of these outcomes are weekdays, so the probability of Kay's birthday falling on a weekday is 5/7 or 0.714, making the event likely.
Explanation:In this problem, we are dealing with the concept of probability in mathematics. Probability refers to the branch of mathematics that deals with the likelihood of occurrence of particular events.
1. List the sample space for this problem:
The sample space, which is the set of all possible outcomes, is all the days in a week. Therefore, the sample space in our case consists of these seven outcomes: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
2. Which outcome (or outcomes) of the sample space composes the event?
The event in this case is Kay’s birthday falling on a weekday. Thus, the outcomes that compose the event are: Monday, Tuesday, Wednesday, Thursday and Friday.
3. Express the probability of Kay’s birthday falling on a weekday as a fraction and as a decimal:
The probability of an event is the ratio of the favorable outcomes to the total outcomes in the sample space. Here, the favorable outcomes are 5 (number of weekdays) and the total outcomes are 7 (total number of days in a week). As a fraction, the probability is 5/7. This can be expressed as a decimal by dividing 5 by 7, giving approximately 0.714.
4. Describe the probability of Kay’s birthday falling on a weekday as impossible, unlikely, neither likely nor unlikely, likely, or certain:
Given that the probability is 5/7 or 0.714, this event is likely to occur because the probability value is more than 0.5 or 50%.
Learn more about Probability here:https://brainly.com/question/32117953
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If M is midpoint of UT, name a segment parallel to RU
The parallel line of RU would need to be the mid point S and midpoint M
Segment SM would be the parallel line.
Answer:
Though I'm not quite sure (as this is a bit of a trick Question) the only Parallel to Line/segment to RU would MS. Given the question they are asking MS are the only two points that run adjacent/parallel to RU. Hope this helps
Step-by-step explanation:
Each person in a group of students was identified by year asked
Answer:
0.184
Step-by-step explanation:
There are 38 seniors, of which 7 prefer evening classes.
7/38 ≈ 0.184
The question involves mathematical sampling techniques to generate categorical data from a high school population, which is shown in a pie chart and involves creating a stratified sample by selecting students from each year.
Explanation:The question pertains to a mathematical concept used in the selection of a sample from a population, which in this scenario, is a group of high school students. This involves using a random number generator to select two class years (freshman, sophomore, junior, or senior) and then including all students from those two years in the sample. The sampling process will result in categorical data, which can be represented in a pie chart as shown in Solution 1.10.
Moreover, organizing the students' names by classification and selecting 25 students from each (a, d) ensures a stratified sample of high school students across different academic stages.
In the context of the presented educational tasks, students might explore how their learning experiences have intersected with personal and global changes, engaging in an analysis of polymorphism, continuous variation, and clinal distribution based on surveyed traits among their peers (Conclusion).
Adrian, Ben and Charlie share some sweets in the ratio of 8:5:10.
Charlie got 24 more sweets than Adrian.
Work out the total number of sweets.
Answer:
the answer is in the image attached
Hope this helps
A circle is centered at the point (5, -4) and passes through the point (-3, 2).
he equation of this circle is (x +__ )∧2 + (y +___ )∧2 = ____.
Answer:
The equation of the circle is (x + -5)² + (y + 4)² = 100
Step-by-step explanation:
* Lets revise the standard form of the equation of the circle
- If the center of the circle is point (h , k) and the length of its radius is r,
then the equation of the circle is (x - h)² + (y - k)² = r² in standard form
* Now lets solve the problem
- The center of the circle is point (5 , -4)
∴ h = 5 and k = -4
∴ The equation of the circle is (x - 5)² + (y - -4)² = r²
∴ The equation of the circle is (x - 5)² + (y + 4)² = r²
- The circle passes through the point (-3 , 2)
- To find r substitute the x-coordinate and the y-coordinate of the
point in the equation of the circle
∵ Point (-3 , 2) is on the circle
∴ x = -3 and y = 2
∴ (-3 - 5)² + (2 + 4)² = r² ⇒ simplify it
∴ (-8)² + (6)² = r² ⇒ solve power 2
∴ 64 + 36 = r² ⇒ add the like terms
∴ 100 = r²
∵ The equation of the circle is (x - 5)² + (y + 4)² = r²
∴ The equation of the circle is (x - 5)² + (y + 4)² = 100
- To complete the form
∴ The equation of the circle is (x + -5)² + (y + 4)² = 100
A diameter of a circle has endpoints p(-10,-2) and Q(4,6)
a find the center of the circle.
b. Find the radius radical form
c.write an equation for the circle
Answer:
a) center: (-3, 2)
b) radius: √65
c) equation: (x +3)² +(y -2)² = 65
Step-by-step explanation:
a) The center (point A) is the midpoint of the diameter, so its coordinates are the average of the endpoint coordinates:
A = (P +Q)/2 = ((-10, -2) +(4, 6))/2
= (-10+4, -2+6)/2 = (-6, 4)/2
A = (-3, 2)
__
b) The radius is the distance from the center to one end of the diameter. The distance formula can be used to find that.
r = √((x2 -x1)² +(y2 -y1)²) = √((4-(-3))² +(6 -2)²) = √(49+16)
r = √65
__
c) The circle centered at (h, k) with radius r has formula ...
(x -h)² +(y -k)² = r²
So the formula for this circle is ...
(x +3)² +(y -2)² = 65
Jack has three coins C1, C2, and C3 with p1, p2, and p3 as their corresponding probabilitiesof landing heads. Jack flips coin C1 twice and then decides, based on the outcome, whetherto flip coin C2 or C3 next. In particular, if the two C1 flips come out the same, Jack flips coinC2 three times next. However, if the C1 flips come out different, he flips coin C3 three timesnext. Given the outcome of Jack’s last three flips, we want to know whether his first two flipscame out the same. Describe a Bayesian network and a corresponding query that solves thisproblem. What is the solution to this problem assuming that p1 = .4, p2 = .6, and p3 = .1and the last three flips came out as follows:(a) tails, heads, tails(b) tails, tails, tails
Let [tex]X[/tex] denote the event that the two [tex]C_1[/tex] flips yield the same faces (1 if the same faces occur, 0 if not), so that
[tex]P(X=x)=\begin{cases}2{p_1}^2-2p_1+1&\text{for }x=1\\2p_1-2{p_1}^2&\text{for }x=0\\0&\text{otherwise}\end{cases}[/tex]
For example,
[tex]P(X=1)=P(C_1=\mathrm{HH}\lor C_1=\mathrm{TT})=P(C_1=\mathrm{HH})+P(C_1=\mathrm{TT})={p_1}^2+(1-p_1)^2[/tex]
Let [tex]Y[/tex] denote the outcome (number of heads) of the next three flips of either [tex]C_2[/tex] or [tex]C_3[/tex]. By the law of total probability,
[tex]P(Y=y)=P(Y=y\land X=1)+P(Y=y\land X=0)[/tex]
[tex]P(Y=y)=P(Y=y\mid X=1)P(X=1)+P(Y=y\mid X=0)P(X=0)[/tex]
and in particular we have
[tex]P(Y=y\mid X=1)=\begin{cases}\dbinom3y{p_2}^y(1-p_2)^{3-y}&\text{for }y\in\{0,1,2,3\}\\\\0&\text{otherwise}\end{cases}[/tex]
[tex]P(Y=y\mid X=0)=\begin{cases}\dbinom3y{p_3}^y(1-p_3)^{3-y}&\text{for }y\in\{0,1,2,3\}\\\\0&\text{otherwise}\end{cases}[/tex]
Then
[tex]P(Y=y)=\begin{cases}\dbinom3y{p_2}^y(1-p_2)^{3-y}(2{p_1}^2-2p_1+1)+\dbinom3y{p_3}^y(1-p_3)^{3-y}(2p_1-2{p_1}^2)&\text{for }y\in\{0,1,2,3\}\\\\0&\text{otherwise}\end{cases}[/tex]
Jack wants to find [tex]P(X=1\mid Y=y)[/tex] for some given [tex]y[/tex].
a. With [tex]y=1[/tex], we have
[tex]P(X=1\mid Y=1)=\dfrac{P(X=1\land Y=1)}{P(Y=1)}[/tex]
[tex]P(X=1\mid Y=1)=\dfrac{P(Y=1\mid X=1)P(X=1)}{P(Y=1)}[/tex]
[tex]P(X=1\mid Y=1)=\dfrac{\binom31p_2(1-p_2)^2(2{p_1}^2-2p_1+1)}{\binom31p_2(1-p_2)^2(2{p_1}^2-2p_1+1)+\binom31p_3(1-p_3)^2(2p_1-2{p_1}^2)}[/tex]
[tex]P(X=1\mid Y=1)\approx\dfrac{0.1498}{0.2376}\approx0.6303[/tex]
b. With [tex]y=0[/tex], we'd get
[tex]P(X=1\mid Y=0)=\dfrac{P(X=1\land Y=0)}{P(Y=0)}[/tex]
[tex]P(X=1\mid Y=0)=\dfrac{P(Y=0\mid X=1)P(X=1)}{P(Y=0)}[/tex]
[tex]P(X=1\mid Y=0)\approx\dfrac{0.0333}{0.1128}\approx0.295[/tex]
Red, blue, yellow, and green marbles are in a bag, with 14 marbles of each color. One white marble is added to the bag for a total of 57 marbles. What is the probability of choosing the white marble or a yellow marble from the bag?
Answer:
[tex]\dfrac{15}{57}[/tex] or 0.2632 or 26.32%
Step-by-step explanation:
Choosing a white or a yellow marble from the bag are two mutually exclusive events. So we can say that:
[tex]P(W or Y) = P(W) + P(Y)[/tex]
To get the probability of each we divide the favorable outcomes by the all possible outcomes.
Probability of choosing white:
[tex]P(W) = \dfrac{1}{57}[/tex]
Probability of choosing yellow:
[tex]P(W)=\dfrac{14}{57}[/tex]
[tex]P(WorY)=P(W)+P(Y)[/tex]
[tex]P(WorY)=\dfrac{1}{57}+\dfrac{14}{57}[/tex]
[tex]P(WorY)=\dfrac{15}{57}[/tex]
If you need it in decimal, just divide and you will get 0.2632.
If you need it in percent, just multiply the decimal by 100% and you will get 26.32%.
Answer:
15/57
Step-by-step explanation:
Given
Total sample space=57 (as one marble was also added to the bag)
Now,
Let P(A) be the probability of drawing a white marble
Let P(B) be the probability of drawing a yellow marble
So,
P(A)=1/57
P(B)=14/57
As we have to calculate the probability of white or yellow marble
P(A or B)=P(A)+P(B)
=1/57+14/57
=(1+14)/57
=15/57
So the probability of drawing a white or yellow marble is 15/57 ..
Mark, his sister, and his 4 friends are sharing a box of mini pizzas. Each person will get5 mini pizzas.
What is the total number of mini pizzas in the box
Final answer:
To determine the total number of mini pizzas, multiply the number of people sharing the pizzas (Mark, his sister, and 4 friends, totaling 6) by the number of pizzas per person (5). Thus, there are 30 mini pizzas in total.
Explanation:
The student's question involves a basic arithmetic calculation related to multiplication. Mark, his sister, and his 4 friends add up to a total of 6 people (Mark + Mark's sister + 4 friends). Each of these 6 individuals will receive 5 mini pizzas each. To find the total number of mini pizzas, we need to multiply the number of people by the mini pizzas each person receives.
Therefore, the calculation is as follows:
Total number of mini pizzas = Number of people × Mini pizzas per person
Now, we execute the multiplication:
Total number of mini pizzas = 6 × 5 = 30 mini pizzas
So, the total number of mini pizzas in the box is 30.
Drag the tiles to the boxes to form correct pairs. Not all tiles will be used.
In the figure, is divided into equal parts. The coordinates of point A are (2, 4), and the coordinates of point B are (10, 6). Match each pair of coordinates to the corresponding point on .
(4, 4.5)
D
(4, 4.75)
E
(9, 5.75)
H
(8, 5.75)
I
(8, 5.5)
(5, 4.75)
(7, 5.25)
Using the mid point formula
(x1 +x2)/2 , (y1 +y2)/2
F is the midpoint of A and B
F = (2+10)/2 , (4+6)/2 = 12/2 , 10,2 = 6,5
F should be (6,5)
Now you have A, F and B, use the midpoint formula to find the other coordinates:
D is the midpoint of A and F and is (4,4.5)
C is the midpoint of A and D and is (3,4.25)
E is the mid point of D and F and is (5,4.75)
H is the midpoint of F and B and is (8,5.5)
G is the midpoint of F and H and is (7, 5.25)
I is the midpoint of H and B and is (9,5.75)
The following are matched coordinates:
D is the midpoint of A and F and is (4,4.5)
C is the midpoint of A and D and is (3,4.25)
E is the mid point of D and F and is (5,4.75)
H is the midpoint of F and B and is (8,5.5)
G is the midpoint of F and H and is (7, 5.25)
I is the midpoint of H and B and is (9,5.75)
Complete the identity
Answer:
sin(α+β)/sin(α-β) ==(tan α+tan β)/(tan α-tan β )
Step-by-step explanation:
We have to complete
sin(α+β)/sin(α-β) = ?
The identities that will be used:
sin(α+β)=sin α cos β+cos α sin β
and
sin(α-β)=sin α cos β-cos α sin β
Now:
= sin(α+β)/sin(α-β)
=(sin α cos β+cos α sin β)/(sin α cos β-cos α sin β)
In order to bring the equation in compact form we wil divide both numerator and denominator with cos α cos β
= (((sin α cos β+cos α sin β))/(cos α cos β ))/(((sin α cos β-cos α sin β))/(cos α cos β))
=((sin α cosβ)/(cos α cos β )+(cos α sin β)/(cos α cos β ))/((sin α cos β)/(cos α cos β )-(cos α sin β)/(cos α cos β))
=(sin α/cos α + sin β/cos β )/(sin α/cos β - sin β/cos β)
=(tan α+tan β)/(tan α-tan β )
So,
sin(α+β)/sin(α-β) ==(tan α+tan β)/(tan α-tan β)
(WILL GIVE BRAINLIEST)
Identify the domain of the exponential function shown in the following graph:
−5 ≤ x ≤ 5
0 ≤ x ≤ 5
All real numbers
All positive numbers
domain for a graph as shown (where the lines never stop) is always (Negative Infinity,Positive Infinity).
Answer:
Step-by-step explanation:
The domain of an exponential function is "the set of all real numbers."
[WILL MARK BRAINIEST] What is the amplitude of the function?
Answer:
B. 1
Step-by-step explanation:
The amplitude is the measure from the midline (0) to the peak (1). It is ...
1 - 0 = 1
A 20% increase in price led the quantity supplied of pencils in a competitive market to increase from 380.00 to 410.00. What is the price elasticity of supply for pencils?
Answer:
about 0.39 (inelastic)
Step-by-step explanation:
Elasticity of supply is the ratio of percentage supply change to a corresponding percentage of price change. Here, that is ...
eos = (410/380 -1)/(0.20) = 0.78947/0.2 ≈ 0.3947
Values below 1 are said to correspond to an inelastic supply, one not very sensitive to price.
what is answer to this equation 2/5=m/7? what does m =
Answer:
m = 2.8
Step-by-step explanation:
Multiply both sides of the equation by the inverse of the coefficient of m. That coefficient is 1/7, so its inverse is 7/1 = 7. Then you have ...
7·2/5 = 7·m/7
14/5 = m . . . . . . . . simplify
m = 2 4/5 = 2.8 . . express the number in a manner that makes sense to you
Answer:
2.8
Step-by-step explanation:
Given that
[tex]\dfrac{2}{5}=\dfrac{m}{7}[/tex]
Multiply both sides by 7 to isolate m
[tex]\dfrac{2}{5}\times7=\dfrac{m}{7}\times7[/tex]
You'll be left with:
[tex]\dfrac{2}{5}\times7=m[/tex]
Then simply do the operations to get the value of m:
[tex]\dfrac{2}{5}\times7=m[/tex]
[tex]\dfrac{2\times7}{5}=m[/tex]
[tex]\dfrac{14}{5}=m[/tex]
2.8 = m
find the perimeter of this figure
it is made up of semicircles and quarter circles
Answer:
16.84
Step-by-step explanation:
For perimeter, you are basically solving 2 different 1/2 circles
for the larger one, you do the equation: 3.14 x 4 = 12.56
For the smaller one, you do the equation: 3.14 x 2 = 6.28
12.56 + 6.28 = 18.84
and since I think you are putting em together you are supposed to remove 2 so the answer would be : 16.84
So, for the calculations (if doing area), you are gonna have to split the figures apart.
ok, for the first part, the 1/4 circles
Pi*2^2=12.566
12.566/4=3.1415
Since there is 2 of the same figure, you can do 1 of 2 ways
A. 3.1415x2 = 6.283
B. 12.566 / 2 = 6.283
Now for the 1/2 circle:
pi*1^2=3.142
3.142/2 = 1.571
Now to add:
1.571 + 6.283 = 7.854
Add and simplify
12 yd 2 ft 10 in
6 yd 1 ft 8 in
16 yd 2 ft 9 in
=
8 yr 9 mo 23 da
12 yr 11 mo 16 da
19 yr 7 mo 28 da
=
15 lb 12 oz
19 lb 15 oz
23 lb 7 oz
=
Answer:
36 yd 1 ft 3 in41 yr 5 mo 7 da59 lb 2 ozStep-by-step explanation:
1. Use the conversions 1 yd = 3 ft, 1 ft = 12 in.
(12 yd +2 ft +10 in) +(6 yd +1 ft +8 in) +(16 yd +2 ft +9 in)
= (12 +6 +16) yd + (2 +1 +2) ft + (10 +8 +9) in
= 34 yd + 5 ft + 27 in
= 34 yd +5 ft + (2 ft +3 in) . . . . convert 27 in to feet and inches
= 34 yd + 7 ft + 3 in . . . . . . . . . add feet
= 34 yd + 2 yd + 1 ft + 3 in . . . . convert 7 ft to yards and feet, then add yards
= 36 yd + 1 ft + 3 in
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2. Use the conversions 1 yr = 12 mo, 1 mo = 30 da. (To be more accurate, we need to know the starting date of each time period.)
(8 yr +9 mo +23 da) +(12 yr +11 mo +16 da) +(19 yr +7 mo +28 da)
= (8 +12 +19) yr +(9 +11 +7) mo +(23 +16 +28) da
= 39 yr +27 mo +67 da
= 39 yr + 27 mo + 2 mo +7 da . . . . . convert 67 da to mo and da
= 39 yr + 2 yr + 5 mo + 7 da . . . . . . . convert 29 mo to yr and mo
= 41 yr +5 mo +7 da
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3. Use the conversion 1 lb = 16 oz.
(15 lb +12 oz) +(19 lb +15 oz) +(23 lb +7 oz)
= (15 +19 +23) lb +(12 +15 +7) oz
= 57 lb +34 oz
= 57 lb +2 lb + 2 oz . . . . . convert 34 ounces to pounds and ounces
= 59 lb +2 oz