Solve the following using the crossing-graphs method. (Round your answer to two decimal places.) 5 + 69 × 0.96t = 32

A) 3x²-5x-28. The area of the rectangle  with length 3x+7 and width x-4 can be represented as 3x²-5x-28.

The equation to find the area of ​​the rectangle is simply A = l * w. This means that the area of ​​a rectangle is equal to the product of its length (l) by its width (w), or of its length by its width.

A = w*l

A = (3x + 7)(x -4) = (3x)(x) + (3x)(-4) + (7)(x) + (7)(-4)

A = 3x² - 12x + 7x - 28

A = 3x² -5x - 28

Answer:  The required result is 15.

Step-by-step explanation:  We are given to evaluate the following :

"6 choose 4".

Since we are to choose 4 from 6, so we have to use the combination of 6 different things chosen 4 at a time.

We know that

the formula for the combination of n different things chosen r at a time is given by

[tex]^nC_r=\dfrac{n!}{r!(n-r)!}.[/tex]

For the given situation, n = 6  and  r = 4.

Therefore, we get

[tex]^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6!}{4!2!}=\dfrac{6\times5\times4!}{4!\times2\times1}=15.[/tex]

Thus, the required result is 15.

Answer:

b. (-3, -4) and (2, 6)

Step-by-step explanation:

By the transitive property of equality, if y equals thing 1 and y also equals thing 2, then thing1 and thing 2 are also equal.  So we will set them equal to each other and factor to solve for the 2 values of x:

[tex]2x+2=x^2+3x-4[/tex]

Get everything on one side of the equals sign, set the whole mess equal to 0, and combine like terms to get:

[tex]0=x^2+x-6[/tex]

Because this is a second degree polynomial, a quadratic to be precise, it has 2 solutions.  We need to find those 2 values of x and then use them in either one of the original equations to solve for the y values that go with each x.  

Factoring that polynomial above gives you the x values of x = -3 and 2.  Sub in -3 first:

y = 2(-3) + 2 and

y = -6 + 2 so

y = -4

Therefore, the coordinate is (-3, -4).

Onto the next x value of 2:

y = 2(2) + 2 and

y = 4 + 2 so

y = 6

Therefore, the coordinate is (2, 6)

F* you B*!!!!!! Your so S*! That's the easiest thing in the world!!

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

[tex]f(x) = \frac{x^2+4x+3}{x^2-x-2}[/tex]

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial [tex]x^2-x-2[/tex]

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

[tex](x-2) (x + 1)[/tex]

We do the same with the numerator

[tex]x^2+4x+3[/tex]

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

[tex](x+3)(x + 1)[/tex]

Therefore

[tex]f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}[/tex]

Note that [tex]\frac{(x+1)}{(x+1)}=1[/tex] only if [tex]x \neq -1[/tex]

So since [tex]x = -1[/tex] is not included in the domain the function has a discontinuity in [tex]x = -1[/tex]

Final answer:

The function f(x) = (x²+4x+3)/(x²-x-2) is not continuous at x = -1 because the denominator becomes zero at that point, rendering the function undefined.

Explanation:

The function f(x) = (x²+4x+3)/(x²-x-2) is not continuous at x = -1 primarily because the denominator of the function becomes zero at x = -1.

Specifically, the denominator factors as (x-2)(x+1), and when x equals -1, the denominator equals zero, which makes the function undefined at that point.

Therefore, the function has a discontinuity at x = -1, and by definition, a function is not continuous at points where it is not defined.

Answer:

[tex]\large\boxed{f^{-1}(x)=9x+18}[/tex]

Step-by-step explanation:

[tex]f(x)=\dfrac{1}{9}x-2\to y=\dfrac{1}{9}x-2\\\\\text{Exchange x to y and vice versa}\\\\x=\dfrac{1}{9}y-2\\\\\text{solve for}\ y:\\\\\dfrac{1}{9}y-2=x\qquad\text{add 2 to both sides}\\\\\dfrac{1}{9}y=x+2\qquad\text{multiply both sides by 9}\\\\9\!\!\!\!\diagup^1\cdot\dfrac{1}{9\!\!\!\!\diagup_1}y=9x+(9)(2)\\\\y=9x+18[/tex]

Answer:

Step-by-step explanation:

-2.7(13)^2 + 72.4(13) + 1911

1,232.01 + 941.2 + 1911 = 4084.21

Answer: 0.02

Step-by-step explanation:

Given: Sample size : [tex]n= 525[/tex]

The population proportion [tex]P=0.3[/tex]

Then, [tex]Q=1-P=1-0.3=0.7[/tex]

The formula to calculate the standard error is given by :-

[tex]S.E.\sqrt{\dfrac{PQ}{n}}[/tex]

[tex]\Rightarrow\ S.E.=\sqrt{\dfrac{0.3\times0.7}{525}}=0.02[/tex]

Hence, the standard deviation of the sample proportions (i.e., the standard error of the proportion) is 0.02.

Answer:

i cant see the picture

Step-by-step explanation:

The probability distribution of the number of female children in a family with 4 children, assuming male and female children are equally likely, is calculated by enumerating combinations for each possible number of girls and dividing by the total number of outcomes.

This problem involves understanding the concept of probability distribution. Let's denote 'G' for girl and 'B' for boy. In a family with 4 children, every child can be either a boy or a girl which gives us 2*2*2*2 = 16 possible combinations which we see listed in the problem.

Let's represent 'X' as the number of girls in the family. X could be 0, 1, 2, 3 or 4. For each of these values of X, we need to calculate the probability, i.e., the number of combinations which satisfy each X, divided by 16 (the total possibilities).

So the probability distribution of X is: P(X=0) = 1/16, P(X=1) = 1/4, P(X=2) = 3/8, P(X=3) = 1/4, P(X=4) = 1/16.

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The probability distribution of the number of girls in a family with four children is as follows: P(X = 0) = 1/16, P(X = 1) = 4/16, P(X = 2) = 6/16, P(X = 3) = 4/16, P(X = 4) = 1/16.

The probability distribution of the number of girls in a family with four children can be determined by analyzing the possible outcomes. There are 16 possible outcomes, ranging from all boys (BBBB) to all girls (GGGG) and various combinations in between. To find the probability distribution, we need to calculate the probability of each outcome. Since all outcomes are equally likely, the probability of each outcome is 1/16. Therefore, the probability distribution is as follows:

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Answer: 2.71

Step-by-step explanation:

We know that the formula to calculate the standard error is given by :-

[tex]S.E.=\dfrac{\sigma}{\sqrt{n}}[/tex], where [tex]\sigma[/tex] is the standard deviation and 'n' is the sample size.

Given : Standard deviation : [tex]\sigma=\$9[/tex]

Sample size : [tex]n=11[/tex]

Then , the standard error of the mean is given by :-

[tex]S.E.=\dfrac{9}{\sqrt{11}}=2.7136021012\approx2.71[/tex]

Hence, the standard error of the mean = 2.71

Final answer:

The standard error of the mean for the size of individual customer orders with a standard deviation of $9 and a sample size of 11 is approximately $2.71.

Explanation:

The Ransin Sports Company is looking to calculate the standard error of the mean for the size of individual customer orders. The standard error of the mean (SEM) is found by dividing the standard deviation by the square root of the sample size. Given a standard deviation of $9 and a sample size of 11 players (the soccer team), the standard error of the mean can be calculated using the formula SEM = σ / √n, where σ is the standard deviation and n is the sample size.

SEM = $9 / √11
SEM = $9 / 3.316...
SEM = approximately $2.71.

Therefore, the standard error of the mean is $2.71.

Answer: 0.21

Step-by-step explanation:

We know that if two events A and B are independent , then the probability of A and B is given by :-

[tex]\text{P and B}=P(A)\times P(B)[/tex]

Given: The probability that an adult possesses a credit card P(A)= 0 .70

The probability that an adult  does not possess a credit card[tex]P(B)= 1-P(A)=0 .30[/tex]

By assuming the independence, the probability that the first adult possesses a credit card and the second adult does not possess a credit card is given by :-

[tex]0.70\times0.30=0.21[/tex]

Hence, the probability that the first adult possesses a credit card and the second adult does not possess a credit card is 0.21.

Final answer:

To find the probability that the first adult selected at random has a credit card and the second does not, multiply the probability of the first event (0.70) by the probability of the second event (0.30), which yields 0.21 or 21%.

Explanation:

The subject of this question is Mathematics, specifically dealing with probability. The question is at a High School level, focusing on the concept of independent events in probability. To calculate the probability that the first adult possesses a credit card and the second adult does not possess a credit card, we use the rule of independent events:

The probability of the first adult having a credit card is 0.70 (given).

The probability of the second adult not having a credit card is 1 - 0.70 = 0.30.

Since these two events are independent, we multiply the probabilities of each event occurring:

P(First has a credit card AND Second does not have a credit card) = P(First has a credit card) * P(Second does not have a credit card) = 0.70 * 0.30

The answer is therefore 0.21 or 21%

Answer: Hence, the distance covered in a straight line from the starting point is 13 miles.

Step-by-step explanation:

Since we have given that

Distance between AB = 5 miles

Distance between BC = 12 miles

We need to find the distance covered from the starting point.

We will use "Pythagorean Theorem":

[tex]H^2=P^2+B^2\\\\AC^2=AB^2+BC^2\\\\AC^2=5^2+12^2\\\\AC^2=25+144\\\\AC^2=169\\\\AC=\sqrt{169}\\\\AC=13\ miles[/tex]

Hence, the distance covered in a straight line from the starting point is 13 miles.

The area of a square that measures 3.1 m on each side will be 9.61 m².

The area of the square is found as the square of the length of its side. If the length of a side is a;

Area of a square = side²

Given data;

S is the length of the side= 3.1 m

Area of a square = a²

A=a²

A= (3.1 m)²

A = 9.61 m²

Hence, the area of a square will be 9.61 m².

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The area of a square With each side measuring 3.1 m is 9.61 m², and this answer is provided with three significant figures.

The area of a square is calculated as the product of its side lengths. Since all sides of a square are equal, if a square measures 3.1 m on each side, the area will be:

Area = side × side = 3.1 m × 3.1 m

To find this product, you multiply 3.1 by itself:

3.1 m × 3.1 m = 9.61 m²

To report this area, we express it in square meters (m²) and use the correct number of significant figures, which in this case is three, based on the given measurements of the sides of the square.

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Final answer:

The parameter in this question refers to the population proportion. To compute a 95% confidence interval for the proportion, you can use the formula: p ± z × √(p × (1-p) / n). The sample proportion is 0.53 and the sample size is 98. By plugging these values into the formula, you can calculate the confidence interval.

Explanation:

The parameter in this question refers to the population proportion. In statistics, a parameter is a measure that describes a characteristic of a population. In this case, the parameter is the proportion of all adults living in the US who have been active in a veteran's group. To compute a 95% confidence interval for this proportion, you can use the formula:  p ± z × √(p × (1-p) / n), where p is the sample proportion, z is the z-score corresponding to the desired confidence level, and n is the sample size.

Using the provided information, the sample proportion is 52/98 = 0.53. To find the z-score for a 95% confidence level, you can use a standard normal distribution table or a calculator with the function invNorm(0.975). The z-score for a 95% confidence level is approximately 1.96. The sample size is 98. Plugging these values into the formula, you can calculate the confidence interval for the population proportion.

Confidence interval = 0.53 ± 1.96 × √(0.53 × (1-0.53) / 98) = 0.53 ± 0.0907

The parameter p is the true proportion of adults in the US who have ever been active in a veteran's group, and the 95% confidence interval for this parameter is (0.4317, 0.6295).

The formula for a 95% confidence interval for a proportion is given by:

[tex]\[ \hat{p} \pm z \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \][/tex]

where z is the z-score corresponding to the desired confidence level. For a 95% confidence interval, the z-score is approximately 1.96.

Let's calculate the confidence interval:

 1. Calculate the sample proportion [tex]\( \hat{p} \)[/tex]:

[tex]\[ \hat{p} = \frac{52}{98} \approx 0.5306 \][/tex]

2. Calculate the standard error of the proportion:

[tex]\[ SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} = \sqrt{\frac{0.5306(1 - 0.5306)}{98}} \approx \sqrt{\frac{0.2503}{98}} \approx \sqrt{0.002554} \approx 0.0505 \][/tex]

3. Find the z-score for a 95% confidence interval, which is approximately 1.96.

4. Calculate the margin of error:

[tex]\[ ME = z \times SE \approx 1.96 \times 0.0505 \approx 0.0989 \][/tex]

5. Calculate the confidence interval:

[tex]\[ \text{Lower bound} = \hat{p} - ME \approx 0.5306 - 0.0989 \approx 0.4317 \] \[ \text{Upper bound} = \hat{p} + ME \approx 0.5306 + 0.0989 \approx 0.6295 \][/tex]

Therefore, the 95% confidence interval for the proportion p of all adults living in the US who have ever been active in a veteran's group is approximately (0.4317, 0.6295).

Triangles with height [tex]h[/tex] and base [tex]b[/tex], with [tex]b=h[/tex] have area [tex]\dfrac{b^2}2[/tex].

Such cross sections with the base of the triangle in the disk [tex]x^2+y^2\le25[/tex] (a disk with radius 5) have base with length

[tex]b(x)=\sqrt{25-x^2}-\left(-\sqrt{25-x^2}\right)=2\sqrt{25-x^2}[/tex]

i.e. the vertical (in the [tex]x,y[/tex] plane) distance between the top and bottom curves describing the circle [tex]x^2+y^2=25[/tex].

So when [tex]x=4[/tex], the cross section at that point has base

[tex]2\sqrt{25-16}=6[/tex]

so that the area of the cross section would be 6^2/2 = 18.

In case it's relevant, the entire solid would have volume given by the integral

[tex]\displaystyle\int_{-5}^5\frac{b(x)^2}2\,\mathrm dx=4\int_0^5(25-x^2)\,\mathrm dx=\frac{1000}3[/tex]

The question is about finding the volume of a solid with a circular base and equilateral triangular cross-sections, and the area of a cross section at x = 4. The base is defined by the circle equation x2 + y2 = 25 and the height and base of triangles are equal.

The question relates to the calculation of the volume of a solid object and the area of its cross section. The base of the solid is a circle defined by x2 + y2 = 25, which is a circle of radius 5. As the cross sections perpendicular to the x-axis are equal in height and base, they form equilateral triangles.

So the area A of the triangle at x = 4 is given by A = 1/2 * Base * Height. But in an equilateral triangle, the base and height are equal, so A = 1/2 * b2. From the equation of circle, the value of 'b' at x = 4 can be calculated as √(25 - 42) = 3. To get the volume we integrate the area A over the x domain of [-5,5].

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click on picture, sorry if it's hard to read, but my phone messed up the typing

The phrase 'Nine times the difference of a number and 8' is translated into the algebraic expression 9(n - 8) and simplified to 9n - 72.

The phrase 'Nine times the difference of a number and 8' translates to an algebraic expression by following specific mathematical operations. To represent an unknown number, we use a variable, such as 'n', and the phrase 'the difference of a number and 8' would be written as 'n - 8'. To adhere to the phrase 'nine times', we multiply the difference by 9, leading to the expression 9(n - 8).

When we simplify the expression, we need to distribute the 9 to both terms within the parentheses: 9 × n and 9 × (-8), which gives us 9n - 72. Thus, the simplified algebraic expression for the phrase 'Nine times the difference of a number and 8' is 9n - 72.

The functions F(x) and G(x) are not inverses of each other.

The correct answer is B. No, because the functions contain different operations.

Given are composition of functions, F(x) = √(x) -6G(x) = (x+6)²

We need to determine if the two functions are inverses of each other.

To determine if the functions F(x) = √(x) - 6 and G(x) = (x + 6)² are inverses of each other using composition of functions, we need to check if their compositions result in the identity function.

Let's calculate the composition:

F(G(x)) = F((x + 6)²) = √((x + 6)²) - 6 = |x + 6| - 6

Now, let's calculate the composition in the reverse order:

G(F(x)) = G(√(x) - 6) = (√(x) - 6 + 6)² = (√(x))² = x

Since F(G(x)) = |x + 6| - 6 and G(F(x)) = x, we can see that they are not equal for all values of x.

Therefore, the functions F(x) and G(x) are not inverses of each other.

The correct answer is B. No, because the functions contain different operations.

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Two functions are inverses if both (f o g)(x) and (g o f)(x) are equal to x. If they are, their composition will yield x, indicating that the two functions are indeed inverses.

To determine if two functions are inverses of each other using composition of functions, you should perform the operation (f o g)(x) and (g o f)(x). If f and g are inverse functions, both of these compositions will yield x.

Let's take the example of functions f(x) = 2x + 3 and g(x) = (x - 3) / 2. To check if they are inverses:

Since both (f o g)(x) and (g o f)(x) equals x, so f(x) and g(x) are inverses of each other.

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Answer:

this is the answer with steps

hope it helps!

Answer:

The solution is:

[tex](0, 1)[/tex]

Step-by-step explanation:

We have the following equations

[tex]9x + 4y = 4[/tex]

[tex]-5x + 7y = 7[/tex]

To solve the system multiply by [tex]\frac{9}{5}[/tex] the second equation and add it to the first equation

[tex]-5*\frac{9}{5}x + 7\frac{9}{5}y = 7\frac{9}{5}[/tex]

[tex]-9x + \frac{63}{5}y = \frac{63}{5}[/tex]

[tex]9x + 4y = 4[/tex]

---------------------------------------

[tex]\frac{83}{5}y=\frac{83}{5}[/tex]

[tex]y=1[/tex]

Now substitute the value of y in any of the two equations and solve for x

[tex]9x + 4(1) = 4[/tex]

[tex]9x +4 = 4[/tex]

[tex]9x = 4-4[/tex]

[tex]9x = 0[/tex]

[tex]x=0[/tex]

The solution is:

[tex](0, 1)[/tex]

Answer:

200

Step-by-step explanation:

Goal 57600 heaters per year

160 hr per 1 month

so 160(12)hr per 1 year

that is 1920 hr per 1 year

We also have that .15 heaters are produced every 1 hour

so multiply 1920 by .15 and you have your answer

160(12)(.15)=288 heaters are produced per one person per year

so we need to figure how many people we need by dividing year goal by what one person can do

57600/288=200 people needed

200 laborers are employed at the plant.

First find out the number of hours each worker will have to work in a year:

= Number of hours per month x 12 months

= 160 * 12

= 1,920 hours

Find out the number of units each worker will produce in those hours:

= Annual number of hours x Units per hour

= 1,920 * 0.15

= 288 heaters

The number of laborers employed is:

= Yearly demand of heaters / Number of heaters produced per worker

= 57,600 / 288

= 200 laborers

The plant employs 200 laborers.

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Answer:

Step-by-step explanation:

1st one is x=26

2nd one is x=4

3rd is x=4

4th is x=-1

Hope that helps!

Answer:

so the answers are 26, 4, 4, and -1

Step-by-step explanation:

If you want me to solve all of them it is: Your getting x by itself

so do the opposite of each problem i'll do the first one

2x - 20 = 32

     + 20   +20

2x = 52 divide the 2

2       2

x  = 26

Hope my answer has helped you if not i'm sorry.

To calculate the time required for an investment of $1000 at 3% interest compounded monthly to grow to $1500, use the compound interest formula. Solve for 't' using natural logarithms and rounding to the nearest month.

To determine how long it takes for $1000 invested at 3% interest compounded monthly to grow to $1500, we use the formula for compound interest:

Final Amount = Principal (1 + (Interest Rate / Number of Compounding Periods in a Year))^(Total Number of Compounding Periods)

Plugging in the values we have:

$1500 = $1000 (1 + 0.03/12)^(12t)

Where 't' is in years. To find 't', we need to isolate it in the equation:

1.5 = (1 + 0.03/12)^(12t)

Take the natural logarithm of both sides:

ln(1.5) = 12t * ln(1 + 0.03/12)

Then, solve for 't' by dividing both sides by 12 * ln(1 + 0.03/12), and round to the nearest month:

t = ln(1.5) / (12 * ln(1 + 0.03/12))

Answer:

[tex] log_{a}(x) + log_{a}(y) = log_{a}(xy) [/tex]

In this high school level mathematics problem, the Product Rule of Logarithms is applied to rewrite the given expression using the appropriate property.

The property used to rewrite the expression is the Product Rule of Logarithms. According to this property, when adding two logarithms with the same base, it is equivalent to multiplying the values inside the logarithms.

So, log base 4 of 7 + log base 4 of 2 can be rewritten as log base 4 of (7*2), which simplifies to log base 4 of 14.

Answer:

The face value would be $75,000

Step-by-step explanation:

Maturity value = $76,386.99

Time = 90 days

Rate of interest = 7.5%

Let face value be 'x'

By using the formula [tex]A=P(1+\frac{RT}{100})[/tex]

                      $76,386.99 = [tex]x(1+\frac{7.5\times \frac{90}{365}}{100})[/tex]

Time in years = [tex]\frac{90}{365}[/tex]

⇒ $76,386.99 = x( 1 + 0.01849315 )

⇒ x = [tex]\frac{76,386.99}{1.01849315}[/tex]

x = $75,000

The face value would be $75,000

Answer:

a^2bc

Step-by-step explanation:

The GCF of the expression a2b2c2 + a2bc2 - a2b2c is a2bc.

The greatest common factor (GCF) of an algebraic expression is the largest polynomial that divides each of the terms without leaving a remainder. To find the GCF of the expression a2b2c2 + a2bc2 - a2b2c, first identify the common factors in each term.

Inspecting each term we see that a2 is a common factor for all of them, and the smallest power of b and c present in all terms is b and c, respectively. Therefore, the GCF is a2bc.

Question 1:

For this case we have the following expression:

[tex]\frac {\frac {y-1} {y ^ 2-36}} {\frac {1-7y} {y + 6}} =\\\frac {(7y-1) (y + 6)} {(y ^ 2-36) (1-7y)} =[/tex]

We have to:

[tex]y ^ 2-36 = (y + 6) (y-6)[/tex]

Rewriting:

[tex]\frac {(7y-1) (y + 6)} {(y + 6) (y-6) (1-7y)} =\\\frac {7y-1} {(y-6) (1-7y)} =[/tex]

We take common factor "-" in the denominator:

[tex]\frac {7y-1} {(y-6) * - (- 1 + 7y)} =\\\frac {7y-1} {- (y-6) * (7y-1)} =\\- \frac {1} {(y-6)}[/tex]

ANswer:

[tex]- \frac {1} {(y-6)}[/tex]

Question 2:

For this case we must simplify the following expression:

[tex](3n ^ 4 + 1) + (- 8n ^ 4 + 3) - (- 8n ^ 4 + 2) =[/tex]

We eliminate parentheses keeping in mind that:

[tex]+ * - = -\\- * - = +\\3n ^ 4 + 1-8n ^ 4 + 3 + 8n ^ 4-2 =[/tex]

We add similar terms:

[tex]3n ^ 4-8n ^ 4 + 8n ^ 4 + 1 + 3-2 =\\3n ^ 4 + 2[/tex]

Answer:

[tex]3n ^ 4 + 2[/tex]

Answer: 0.7021

Step-by-step explanation:

Let D be the event that team plays in day , N be the event that the team plays in night and W be the event when team wins.

Then , [tex]P(D)=0.40\ \ \ P(N)=0.60[/tex]

[tex]P(W|D})=0.35\ \ \ \ P(W|N)=0.55[/tex]

Using the law of total probability , we have

[tex]P(W)=P(D)\timesP(W|D)+P(N)\timesP(W|N)\\\\\Rightarrow\ P(W)=0.40\times0.35+0.60\times0.55=0.47[/tex]

Using Bayes theorem ,

The required probability :[tex]P(N|W)=\dfrac{P(N)P(W|N)}{P(W)}[/tex]

[tex]=\dfrac{0.60\times0.55}{0.47}=0.702127659574\approx0.7021[/tex]

Answer:

16%

Step-by-step explanation:

Eight shots were missed. Take half of eight; 4. You now have 4\25, which is 160‰ [16%].

Answer:

%16

Step-by-step explanation:

Step 1:  Find the shots missed

25 - 17 = 8

Step 2:  Find half of the shots missed

8 / 2 = 4

Step 3:  Divide 4 by 25

4/25 = 0.16

Step 4:  Convert to Percent

0.16 * 100 = %16

Answer:  %16

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Answer:

y = 17x + 130

For 9 days, you would pay $283.

Step-by-step explanation:

y = 17x + 130

Total cost = 17$ a day, plus the 130$ fee.

x = 9

y = (17)(9) + 130

y = 153 + 130

y = 283

The required cost of renting a car for 9d days with the company is $283.

The equation model is defined as the model of the given situation in the form of an equation using variables and constants.

here,
At The Car rental Company, You must pay a rate of $ 130 and then a daily fee of $ 17 Per day.
Let the number of days be x for renting a car,
According to the question,
Total cost(y) = 130 + 17x
Put x = 9

Total cost = 130 + 17×9
               = $283

Thus, the required cost of renting a car for 9d days with the company is $283.

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