Solve for X-4 1/6 = 9 1/3

Answer:

Zeros: x = 1 , − 2 , 2 End Behavior: Falls to the left and rises to the right.

Y-intercept: (0,4)

Step-by-step explanation:

mark me brainliest

Answer:

672m

Step-by-step explanation:

L*W*H

8*6*14

672m

Answer:

hjjjkkkkk(hmmmm jhhjjjjjjuu

Answer: x=15

Step-by-step explanation: use distributive property:

2x + 40=4x + 10

40=2x + 10

30= 2x

15=x

Answer:

The second option shows the correct translation of 3 units to the right and 1 unit down.

Answer:

d. 0.2590

Step-by-step explanation:

In this problem, we have that:

A sample of 2027 adults.

920 overweight, and of those, 300 said they drink mostly diet soda.

1107 right weight, of those 225 said that they mostly drink diet soda.

Of 2027 adults, 300+225 = 525 said that they mostly drink diet soda.

The pooled sample proportion of individuals who mostly drink diet soda is:

525 of 2027

525/2027 = 0.2590

So the correct answer is:

d. 0.2590

Answer:

0.5 or 1/2

Step-by-step explanation:

Step 1.  40/50−15/50

Step 2.  40-25= 25/50

Step 3.  25/50÷ 5 =5/10

5/10÷ 5 =1/2

4/5−3/10=1/2

Answer:

x ↑2 + ( y − 1 )↑ 2 = 16

Step-by-step explanation:

Standard form.

Mark me as brainliest please!

Answer:

[tex]t=\frac{15.5-18.7}{\frac{5.7}{\sqrt{11}}}=-1.862[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=11-1=10[/tex]  

The p value would be given by:

[tex]p_v =2*P(t_{(10)}<-1.862)=0.0922[/tex]  

We see that the p value is higher than the significance level so we don't have enough evidence to ocnclude that the true mean is different from 18.7 months in jail at 5% of significance.

Step-by-step explanation:

Information given

[tex]\bar X=15.5[/tex] represent the sample mean for the jail time

[tex]s=5.7[/tex] represent the sample standard deviation

[tex]n=11[/tex] sample size  

[tex]\mu_o =18.7[/tex] represent the value that we want to compare

[tex]\alpha=0.05[/tex] represent the significance level

t would represent the statistic

[tex]p_v[/tex] represent the p value for the test

System of hypothesis

We want to check the hypothesis if the true mean for the jail time is equal to 18.7 or no, the system of hypothesis are:

Null hypothesis:[tex]\mu = 18.7[/tex]  

Alternative hypothesis:[tex]\mu \neq 18.7[/tex]  

Since we don't know the population deviation the statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

Rreplacing we got:

[tex]t=\frac{15.5-18.7}{\frac{5.7}{\sqrt{11}}}=-1.862[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=11-1=10[/tex]  

The p value would be given by:

[tex]p_v =2*P(t_{(10)}<-1.862)=0.0922[/tex]  

We see that the p value is higher than the significance level so we don't have enough evidence to ocnclude that the true mean is different from 18.7 months in jail at 5% of significance.

Answer:

Your answer would be Triangle B is a reflection of triangle A across the x-axis. Triangle C is not a reflection of triangle A.

Explanation

B is a reflection of the x-axis.

But triangle C is not a reflection because if you fold the image with the y-axis line in the middle then you would see that triangle C doesnt match the placement of triangle A.

hope this helps

give brainliest if you please

Answer:

Without the picture of diagram, based on your description:

Triangle A is reflected across the x-axis to form triangle B.

Triangle A is rotated to form triangle C.

Option A: Triangle B is a reflection of triangle A across the x-axis.

It is correct because "Triangle A is reflected across the x-axis to form triangle B" => Triangle B is a reflection of triangle A across the x-axis

Option B: Triangle C is not a reflection of triangle A

It is correct because "Triangle A is rotated to form triangle C"

Option C: Triangle B is a reflection of triangle A across the y-axis

It is incorrect, because "Triangle A is reflected across the x-axis to form triangle B" => Triangle B is a reflection of triangle A across the x-axis, not y-axis.

Option D: Triangle C is a reflection of triangle A across the line y = x + 3

It is incorrect, because "Triangle A is rotated to form triangle C" => triangle C is a result of rotation, not reflection.

Hope this helps!

:)

Answer:

4

Step-by-step explanation:

Garden area: 10 yd²

Each watermelon plant area: 2.5 yd²

No. of plants:

10/2.5 = 4

Answer:

3 * 4 * height = 48

height = 48 / (3*4)

height = 4 feet

Step-by-step explanation:

The height is 4 feet of the box if the volume is 48 cubic feet.

The volume of a rectangular box can be calculated if you know its three dimensions: width, length, and height.

The formula is then volumebox = width x length x height.

The base of a rectangular box measures 3 feet by 4 feet.

The volume is 48 cubic feet.

Substitute all the values in the formula

Volume box = width x length x height

48 = 3 x 4 x height

48 = 12 x height

Height = 48/12

Height = 4

Hence, the height is 4 feet of the box if the volume is 48 cubic feet.

Learn more about volume here;

https://brainly.com/question/16210249

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Answer:

A) (-2, 8), (4, 8)

B) See attachment.

C) 36 square units

Step-by-step explanation:

Given functions:

[tex]\begin{cases}f(x)=x^2-2x\\g(x)=8\end{cases}[/tex]

To find the x-coordinates of the points where the two functions intersect, set the equations equal to each other and solve for x:

[tex]f(x)=g(x)\\\\x^2-2x=8\\\\x^2-2x-8=0\\\\x^2-4x+2x-8=0\\\\x(x-4)+2(x-4)=0\\\\(x+2)(x-4)=0\\\\\\x+2=0 \implies x=-2\\\\x-4=0 \implies x=4[/tex]

As points on the function g(x) have a y-coordinate of 8, the solutions to f(x) = g(x) are:

[tex]\Large\boxed{(-2,8)\;\textsf{and}\;(4,8)}[/tex]

[tex]\dotfill[/tex]

The function g(x) is a horizontal line parallel to the x-axis that intercepts the y-axis at (0, 8).

We are given that function f(x) is a concave up parabola with roots at (0, 0) and (2, 0). From Part A, we know that the parabola intersects g(x) at points (-2, 8) and (4, 8).

To help sketch the graph of function f(x), we can find its vertex and y-intercept.

The x-coordinate of the vertex of a quadratic function in the form y = ax² + bx + c is x = -b/2a. In this case, a = 1 and b = -2, so the x-coordinate of the vertex is:

[tex]x = -\dfrac{-2}{2(1)}=\dfrac{2}{2}=1[/tex]

To find the y-coordinate of the vertex, substitute x = 1 into f(x):

[tex]f(1)=(1)^2-2(1)=1-2=-1[/tex]

Therefore, the vertex of f(x) is at point (1, -1). The axis of symmetry of a parabola is the x-coordinate of the vertex, so in this case, the axis of symmetry is x = 1.

To find the y-intercept, substitute x = 0 into the function and solve for y:

[tex]f(0)=(0)^2-2(0)=0-0=0[/tex]

Therefore, the y-intercept of f(x) is the origin (0, 0).

[tex]\dotfill[/tex]

The area of the region R bounded by f(x) and g(x) on the interval [-2, 4] is given by the integral:

[tex]\displaystyle R = \int_{-2}^{4} \left[ g(x) - f(x) \right] \; dx[/tex]

Substitute g(x) = 8 and f(x) = x² - 2x:

[tex]\displaystyle R = \int_{-2}^{4} \left[8-(x^2-2x)\right] \; dx \\\\\\ R = \int_{-2}^{4} \left[8-x^2+2x\right] \; dx[/tex]

Evaluate the Integral

[tex]\displaystyle R = \left[8x-\dfrac{x^{2+1}}{2+1}+\dfrac{2x^{1+1}}{1+1}\right]^4_{-2} \\\\\\ R = \left[8x-\dfrac{x^{3}}{3}+x^2\right]^4_{-2} \\\\\\ R=\left(8(4)-\dfrac{(4)^{3}}{3}+(4)^2\right)-\left(8(-2)-\dfrac{(-2)^{3}}{3}+(-2)^2\right) \\\\\\ R=\left(32-\dfrac{64}{3}+16\right)-\left(-16+\dfrac{8}{3}+4\right) \\\\\\ R=\dfrac{80}{3}+\dfrac{28}{3} \\\\\\ R=\dfrac{108}{3}\\\\\\ R=36[/tex]

Therefore, the area of the region R bounded by f(x) and g(x) is:

[tex]\Large\boxed{\textsf{$36$ square units}}[/tex]

Answer:

6 cm

Step-by-step explanation:

3 is the radius

the radius is half of the diameter

to find the diameter from the radius you have to multiply it by 2

3×2

=6

Answer:

15% of 8.95 is 1.3425

Step-by-step explanation:

Answer:

$1.34

Hope this helped :)

Answer:

We conclude that the mean Ohio score is below the national average.

Step-by-step explanation:

We are given that a random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used.

A survey of 500 randomly selected Ohio scores showed a mean of 20.8. The population standard deviation is 3.

Let [tex]\mu[/tex] = mean Ohio scores.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] [tex]\geq[/tex] 21.1      {means that the mean Ohio score is above or equal the national average}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 21.1      {means that the mean Ohio score is below the national average}

The test statistics that would be used here One-sample z test statistics as we know about population standard deviation;

                    T.S. =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]  ~ N(0,1)

where, [tex]\bar X[/tex] = sample mean Ohio score = 20.8

            [tex]\sigma[/tex] = population standard deviation = 3

            n = sample of Ohio = 500

So, test statistics  =  [tex]\frac{20.8-21.1}{\frac{3}{\sqrt{500}}}[/tex]  

                              =  -2.24

The value of z test statistics is -2.24.

Now, at 0.1 significance level the z table gives critical value of -1.2816 for left-tailed test. Since our test statistics is less than the critical values of z as -2.24 < 1.2816, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean Ohio score is below the national average.

The hypotheses for the given survey are; Null Hypothesis; H₀: μ₁ = μ₂

Alternative Hypothesis; Hₐ: μ₁ > μ₂ (claim)

We are given;

Population Size; N = 1000

Sample size; n = 500

Population mean; μ = 21.1

Sample Mean; x' = 20.8

Population Standard Deviation; σ = 3

Let us first define the hypotheses;

Null Hypothesis; H₀: μ₁ = μ₂

Alternative Hypothesis; Hₐ: μ₁ > μ₂

Since the population mean was not used, then it means that the Alternative Hypothesis is the claim.

We are told that significance value is α = 0.1. Using F-distribution table attached with; α = 0.1; dF₁ = 20 and dF₂ = 20, we have;

Critical Value = 1.79

Read more about Hypotheses at; https://brainly.com/question/16112320

Answer:

Step-by-step explanation:

You have to look up (google) the number of ml in a fluid ounce. It equals 29.57 ml approximately.

Next you must look up the number of mL in a teaspoon. The conversion factor turns out to be 4.93 mL = 1 teaspoon.

1 fluid ounce = 29.57 mL

20 fluid ounces = x mL

1/20 = 29.57 /x

x = 20*29.57

x = 591.4 mL

1 teaspoon = 4.93 mL

x teaspoons = 591.4

4.93 * x = 591.4

4.93 * x/4.93 = 591.4 / 4.93

x = 119.96

Answer: $69.30 per share (rounded up to the nearest penny)

Step-by-step explanation:

51.33 x 0.35 = 17.9655 (this is the increased value in the stock)

51.33 + 17.9655 = 69.2955

Answer:

Descriptive

Step-by-step explanation:

Descriptive statistics uses the data that helps to analyse, describe, and elaborate data accurately. It also provides information regarding the population through graphs or tables. Four types of descriptive statistics are measures of frequency, measures of central tendency, measures of dispersion, and measures of position.

The given example in question is descriptive statistics.

Answer:

We conclude that the proportion of women who smoke cigarettes is smaller than or equal to the proportion of men at 0.01 significance level.

95% confidence interval for the difference in population proportions of women and men who smoke cigarettes is [0.0062 , 0.1298].

Step-by-step explanation:

We are given that random samples of 125 women and 140 men reveal that 13 women and 5 men smoke cigarettes.

Let [tex]p_1[/tex] = population proportion of women who smoke cigarettes

[tex]p_2[/tex] = population proportion of men who smoke cigarettes

So, Null Hypothesis, [tex]H_0[/tex] : [tex]p_1\leq p_2[/tex]      {means that the proportion of women who smoke cigarettes is smaller than or equal to the proportion of men}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]p_1> p_2[/tex]      {means that the proportion of women who smoke cigarettes is higher than the proportion of men}

The test statistics that will be used here is Two-sample z proportion test statistics;

                               T.S. = [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex]  ~ N(0,1)

where, [tex]\hat p_1[/tex] = sample proportion of women who smoke cigarettes= [tex]\frac{13}{125}[/tex] =0.104

[tex]\hat p_2[/tex] = sample proportion of men who smoke cigarettes = [tex]\frac{5}{140}[/tex] = 0.036

[tex]n_1[/tex] = sample of women = 125

[tex]n_2[/tex] = sample of men = 140

So, the test statistics  =  [tex]\frac{(0.104-0.036)-(0)}{\sqrt{\frac{0.104(1-0.104)}{125}+ \frac{0.036(1-0.036)}{140}} }[/tex]

                                     =  2.158

Now, at 0.01 significance level, the z table gives critical value of 2.3263 for right tailed test. Since our test statistics is less than the critical value of z as 2.158 < 2.3263, so we have insufficient evidence to reject our null hypothesis due to which we fail to reject our null hypothesis.

Therefore, we conclude that the proportion of women who smoke cigarettes is smaller than or equal to the proportion of men.

Now, coming to 95% confidence interval;

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportions is given by;

                    P.Q. =  [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex]  ~ N(0,1)

where, [tex]\hat p_1[/tex] = sample proportion of women who smoke cigarettes= [tex]\frac{13}{125}[/tex] =0.104

[tex]\hat p_2[/tex] = sample proportion of men who smoke cigarettes = [tex]\frac{5}{140}[/tex] = 0.036

[tex]n_1[/tex] = sample of women = 125

[tex]n_2[/tex] = sample of men = 140

Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.

So, 95% confidence interval for the difference between population proportions, [tex](p_1-p_2)}[/tex] is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                    of significance are -1.96 & 1.96}  

P(-1.96 < [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] < 1.96) = 0.95

P( [tex]-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] < [tex]{(\hat p_1-\hat p_2)-(p_1-p_2)}[/tex] < [tex]1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] ) = 0.95

P( [tex](\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] < [tex](p_1-p_2)}[/tex] < [tex](\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] ) = 0.95

95% confidence interval for [tex](p_1-p_2)}[/tex] =

[[tex](\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex],[tex](\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex]]

= [ [tex](0.104-0.036)-1.96 \times {\sqrt{\frac{0.104(1-0.104)}{125}+ \frac{0.036(1-0.036)}{140}} }[/tex] , [tex](0.104-0.036)+1.96 \times {\sqrt{\frac{0.104(1-0.104)}{125}+ \frac{0.036(1-0.036)}{140}} }[/tex] ]

 = [0.0062 , 0.1298]

Therefore, 95% confidence interval for the difference in population proportions of women and men who smoke cigarettes is [0.0062 , 0.1298].

Answer:

Step-by-step explanation:

a) Since x+2 is a factor, we know P(-2) = 0.

  P(x) = (((x +2)x +a)x +b)x -60

Then the value of P(-2) is ...

  P(-2) = 0 = (((0)(-2) +a)(-2) +b)(-2) -60 = (-2a +b)(-2) -60 = 4a -2b -60

We know the remainder from division by (x+3) is 60, so

  P(-3) = 60 = (((-3+2)(-3) +a)(-3) +b)(-3) -60 = ((3+a)(-3) +b)(-3) -60

     = (-9 -3a +b)(-3) -60 = 27 +9a -3b -60

  93 = 9a -3b

These two equations can be put into standard form:

  2a -b = 30

  3a -b = 31

Then we have the solution ...

  a = 1 . . . . . (by subtracting the first equation from the second)

  -28 = b . . . by substituting into the first equation

__

b) To show that (x-3) is a factor we need to evaluate P(3).

  P(3) = (((3 +2)(3) +1)(3) -28)(3) -60 = (48 -28)(3) -60 = 0

The function value is 0, so (x -3) is a factor.

__

c) We want to find Q(x) = x^2 +cx +d such that ...

  (x +2)(x -3)Q(x) = P(x)

  (x^2 -x -6)(x^2 +cx +d) = x^4 +2x^3 +x^2 -28x -60

  x^4 +(c-1)x^3 +(-6-c+d)x^2 +(-6c-d)x -6d = x^4 +2x^3 +x^2 -28x -60

This gives rise to the equations ...

  c -1 = 2   ⇒   c = 3

  -6d = -60   ⇒   d = 10

Then P(x) can be factored as ...

  P(x) = (x +2)(x -3)(x^2 +3x +10)

_____

Comment on the attached graph

I like to use a graphing calculator to find real roots of higher-degree polynomials. This graph shows the real zeros to be -2 and +3, so we know that (x +2) and (x -3) are factors. The green curve is P(x) with those factors divided out, so is a graph of Q(x). The vertex of that graph tells us that ...

  Q(x) = (x +1.5)^2 +7.75 = x^2 +3x +10

Answer:

no because

Step-by-step explanation:

the results were not tested enough

Answer:

The number of times a run of 5 trues appears in each set of 20 is what you record. You do this 50 times. Are your results unusual? Explain.

C) Their results were typical. Almost half of the simulations had runs of five or more true answers.

Step-by-step explanation:

Answer:

2100 Watt Hours

Step-by-step explanation:

600 Watt hours is consumed by the bulb every day.

3 Days and 12 Hours = 3 1/2 Days

To find how many Watt hours was consumed in 3 1/2 days we must multiply both of the numbers.

600 x 3 1/2 = 2100

Therefore, we can conclude that 2100 Watt Hours are consumed in 3 Days and 12 Hours.

Answer:

  3.50

Step-by-step explanation:

The attached shows the long division with zeros filled where necessary.

Answer:

Step-by-step explanation:

The appropriate journal entries to record the bond issue on January 1, 2021, and the first two semiannual interest payments on June 30, 2021, and December 31, 2021 are:

White Water journal entries

1-Jan-21

Debit Cash $382,141

Credit Discount on Bonds Payable $27,859

($410,000-$382,141)

Credit Bonds payable  $ 410,000

30-Jun

Debit Interest Expenses $ 15,286

($382,141 x 8%/2)  

Debit Discount on Bonds Payable $736

Credit Cash $14,350

($410,000 x 7%/2)  

31-Dec

Debit Interest Expenses $15,315.08

[($382,141 + 736) x 8%/2]

Credit Discount on Bonds Payable $965.08

($15,315.08-$14,350)

Credit Cash $14,350

($410,000 x 7%/2)

Learn more here:

https://brainly.com/question/16890108

Answer:

Step-by-step explanation:

a) you have that:

[tex]f'(x)=\frac{(x-2)(x+8)}{(x+1)(x-5)},\ \ x\neq -1,5[/tex]

The derivative of a function equals to zero allows you to find the critical points:

[tex]f'(x)=0\\\\(x-2)(x+8)=0\\\\x_1=2\\\\x_2=-8[/tex]

x=2,8 are the critical points

b) To know the behavior if f it is necessary to know where are f is indeterminated. The derivative give to you information about the slope of f. For x=-1,5 you have an infinite slope. Hence, for that values of x you have two indetermination s of f(x.)

However, if you see the atacched images you can obser that the original function (that is obtained with the intgegral) does not have available values for x<5 due to the logrithms. Hence, there are no critical points

The function only increases after x=5 from -infinity to +infinity

c) there are no local maximum neither local minimum

Answer:

f(x) = (x + 2) (x − 5) (x − 6)

Step-by-step explanation:

f(x) = (x − (-2)) (x − 5) (x − 6)

f(x) = (x + 2) (x − 5) (x − 6)

Answer:

Total length of the elastic band in this stretched position = 61.43 mm

Step-by-step explanation:

The complete Question with the image is attached to this solution

The second image shows the break down of the angle subtended by the elastic band over the crayons at the centre of the circle formed by the crayon's circular shape.

The elastic band extends over 3 of such length of an arc and covers a length of 2 × radius in the spaces between the contact with each crayon. This is also shown in the second attached image.

So, the length of the band will be a sum of 3 diameters and 3 of those arc lengths

Length of an arc is given by

L = (θ/360) × πD

θ = 120°

D = 10 mm

L = (1/3) × 10π = (10π/3) mm

But there are 3 of those, So, total length of the arcs = 3 × (10π/3) = (10π) mm

Length of those 3 diameter regions = 3×10 = 30 mm

Total length of the elastic band in this stretched position = 30 + 10π = 30 + 31.43 = 61.43 mm

Hope this Helps!!!

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability is  [tex]P(X < 5) = 0.80[/tex]

Step-by-step explanation:

The probability that Miguel’s score on the Water Hole is at most 5 is mathematically evaluated as

     [tex]P(X < 5) = P(X = 3) + P(X = 4 ) + P(X = 5)[/tex]

  Substituting values from the table

        [tex]P(X < 5) = 0.15 + 0.40 + 0.25[/tex]

        [tex]P(X < 5) = 0.80[/tex]