Solve for N , I can’t get this , I’ll give brainliest to who gets it!!!

Answer:

yes

Step-by-step explanation:

Answer: The five exponent properties are

Product of Powers: When you are multiplying like terms with exponents, use the product of powers rule as a shortcut to finding the answer. It states that when you are multiplying two terms that have the same base, just add their exponents to find your answer.

Power to a Power.: When raising a power to a power in an exponential expression, you find the new power by multiplying the two powers together. ... Then multiply the two expressions together. You get to see multiplying exponents (raising a power to a power) and adding exponents (multiplying same bases).

Quotient of Powers.:  When you are dividing like terms with exponents, use the Quotient of Powers Rule to simplify the problem. This rule states that when you are dividing terms that have the same base, just subtract their exponents to find your answer. The key is to only subtract those exponents whose bases are the same.

Power of a Product: The Power of a Product rule is another way to simplify exponents. ... When you have a number or variable raised to a power, it is called the base, while the superscript number, or the number after the '^' mark, is called the exponent or power.

Power of a Quotient.: The Power of a Quotient rule is another way you can simplify an algebraic expression with exponents. When you have a number or variable raised to a power, the number (or variable) is called the base, while the superscript number is called the exponent or power

You can use these any way you want to rewrite an equation.

Hope this helped

:D

The properties of exponents are rules to simplify expressions with powers, which include adding exponents when multiplying like bases, multiplying exponents when raising powers to powers, and subtracting exponents when dividing like bases.

The properties of exponents are mathematical rules used to rewrite expressions involving powers in simpler or alternative forms. These properties are essential for performing operations with exponents and include rules for multiplying, dividing, and raising powers to powers.

Examples of Exponent Properties

Multiplying Powers with the Same Base: 10³ × 10² = 10³+2 = 10µ.

Raising a Power to a Power: (5³)⁴ = 5³×4 = 5¹², or 5 multiplied by itself 12 times.

Negative Exponents: 2.4 x 10⁻² tells you to move the decimal point to the left twice, which equals 0.024.

Application of Exponent Properties

To apply these properties, you would systematically use the appropriate rule based on the operation you're performing. For multiplication, add the exponents when the bases are the same. For powers, multiply the exponents. For division, subtract the exponents when the bases are the same. Using these rules simplifies complex expressions and makes it easier to work with exponents in algebra and science.

Answer: x=279,936

Step-by-step explanation:

See attachment

Answer:

[tex]6x^{3} +14x^{2} +6x-12[/tex]

Step-by-step explanation:

distribute

Answer:

Step-by-step explanation:

increase density of seawater

Answer:

C

Step-by-step explanation:

if you multiply 2.3 times pi you get the answer

Answer:

3. A

4. D

Step-by-step explanation:

r : radius

area of a circle = 3.14×r²

3,14×11^2 = 379,94

3,14×(2,3÷2)^2 = 4,15265

Answer:

253.75

Step-by-step explanation:

Answer:

see here our answer is 60 degrees now how I will tell u see u know the sum of triangle that is 180 degrees now add up. y +y + 60 = 180 and solve it u will get ur correct answer

comment if u have doubt

Answer:

60

Step-by-step explanation:

Because you would 180/3 and will get 60

Answer:

Step-by-step explanation:

point slope form

y + 6 = -3(x - 4)

point slope to y-intercept

y + 6 = -3x + 12

y = -3x + 6

Answer:

QUESTION NOT CLEARLY STATED

Step-by-step explanation:

Answer: 41

Step-by-step explanation: I just took the test

To determine the value of x, various methods are used depending on the context, including setting up proportions for scale models, applying the quadratic formula, solving linear equations, and establishing ratios.

To find the value of x, we have various scenarios illustrating different mathematical concepts, such as proportions, the quadratic formula, and linear equations. Each scenario requires specific steps to solve for x, but they all center on mathematical problem-solving skills.

When dealing with proportions, such as a scale model, you set up a proportion correlating the scale size to the actual size and then cross multiply to solve for x. In the situation where a quadratic equation is involved, you apply the quadratic formula to determine the value of x, taking care to discard any solutions that do not make sense in the physical context of the problem, such as negative distances.

For linear equations, you enter the given data into a calculator or computer and solve for x, while ensuring you round off to the accuracy required, typically four decimal places. Ratios and scale factors also play a role in determining x, where you establish a ratio based on given dimensions and solve for the unknown.

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5x^2 + 7x -6

Rewrite the middle term whose product equals first term x last term: 5 x -6 = -30 and whose sum equals the middle term.

Rewrite 7 as -3 + 10

5x^2 +(-3+10)x -6

Use distributive property:

5x^2 -3x + 10x -6

Group the first two terms and last two terms:

(5x^2 -3x) (10x -6)

Factor out greatest common factor of each group to get final answer:

(5x-3)(x+2)

Answer:

It is 5 to 3

Step-by-step explanation:

Answer: 50 words per minute

Step-by-step explanation: You need to find the unit rate, so you solve 150=3x to get x=50

Answer:

The 4th Image

Step-by-step explanation:

Answer:

Please check the answer below.

Step-by-step explanation:

Considering the statement

[tex]2^?<3^?[/tex]

If [tex]?[/tex] is an whole number.

Set of whole number = {0, 1, 2, 3, ....}

Example 1:

When statement is always true:

For x > 0, the statement will be always be true.

Lets put x = 1

[tex]2^1<3^1[/tex]

2 < 3

So, the statement is true when x = 1

Example 2:

When statement is always true:

For x > 0, the statement will be always be true.

Lets put x = 2

[tex]2^2<3^2[/tex]

4 < 9

So, the statement is true when x = 2

Example 3:

When statement is Never true:

For x = 0, the statement will never be true.

Lets put x = 0

[tex]2^0<3^0[/tex]

[tex]\mathrm{Apply\:rule}\:a^0=1,\:a\ne \:0[/tex]

[tex]2^0=1, 3^0=1[/tex]

So,

[tex]1<1[/tex]

Therefore, the statement is False.

Keywords: exponential number, whole number

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You divide 20 by 100

Answer:

equation of line m is x=3

equation of line n is y=-4

Step-by-step explanation:

Line m has no y intercept, and its x-intercept is (3,0).

When a line has no y intercept then it is a vertical line

for any vertical line the equation is x= x1

(3,0) is (x1,y1)

so equation of line m is x=3

Line n has no x intercept and its  y -intercepts is (0-4).

When a line has no x intercept then it is a horizontal  line

for any horizontal line the equation is y= y1

(0,-4) is (x1,y1)

so , the equation of line n is y=-4

Answer: x=−3 or x=−5

Step-by-step explanation:

Step 1: Factor left side of equation.

(x+3)(x+5)=0

Step 2: Set factors equal to 0.

x+3=0 or x+5=0

x=−3 or x=−5

Answer:

These are the answers

Step-by-step explanation:

x > –5

Solution:

Given expression is –5 < 2x + 5.

Step 1: Let us first switch the sides.

⇒ 2x + 5 > –5

Step 2: Subtract 5 from both side of the inequality.

⇒ 2x + 5 –5 > –5 –5

⇒ 2x > –10

Step 3: Divide by 2 on both sides of the inequality.

[tex]$\Rightarrow\frac{2x}{2} >\frac{-10}{2}[/tex]

⇒ x > –5

Step 4: That is the values of x are greater than –5.

Hence x > –5.

Answer:

1/4

Step-by-step explanation:

It is 1/4 because you divide the fraction by its highest multiple for 6 and 24 its 6, so you divide the numerator and denominator by 6.

Answer:

15(3+2x)

Step-by-step explanation:

15 multiplies to both 3 and 2x amd the result is 45+2x

Final answer:

To write an expression equivalent to 45 + 30x using the distributive property, factor out the common factor of 15 to get 15(3 + 2x).

Explanation:

To write an expression equivalent to 45 + 30x using the **distributive property**, we can factor out the common factor. This can be done as follows:

Factor out 15, so 45 + 30x becomes 15(3 + 2x).

Therefore, an expression equivalent to 45 + 30x using the distributive property is 15(3 + 2x).

Answer:a=3.6 and b=4.8

Step-by-step explanation:(a^2)+(b^2)=(c^2)

Where c is hypotenuse is equal to 6. A right triangle is also known as a 3,4,5 triangle where the 2 legs are 3 and 4 and hypotenuse is 5. Find the factor in size difference by dividing your hypotenuse of 6 by the hypotenuse of 5 you get 1.2. Now multiply the 3 and 4 by 1 2 to get your answers of 3.6 and 4.8.

To check work simply plug in your legs as a and b

(3.6^2)+(4.8^2)=(6^2)

(12.96)+(23.04)=(36)

Option C

Math teacher would need to buy 130 prizes

Solution:

Given that,

Math teacher currently has 109 students and the box has 88 prizes in it

The math teacher likes to keep at least twice as many prizes in the box as she has students

So, she wants the number of prizes to be twice the number of students

Therefore,

number of prizes = 2 x 109 students

number of prizes = 2 x 109 = 218 prizes

The box has 88 prizes in it

Therefore, number of prizes she would need to buy is:

⇒ 218 - 88 = 130

Thus she would need to buy 130 prizes

Answer:

17576 Combinations.

Step-by-step explanation:

There are 26 letters in the Current English Lexicon (Alphabet), If there are 3 letters in a person's initials, then our equation would turn out to be "26³ =  17576". So, There are 17576 different possible combinations.

Final answer:

The total number of possible initials a person can have, using the first letters of their first name, middle name, and last name in the English alphabet, is 17,576. This is calculated by multiplying the number of alphabet letters (26) for each initial, resulting in a product of 26 x 26 x 26.

Explanation:

To calculate the number of possible initials a person can have from their first name, middle name, and last name, we must consider that each initial can be any letter from the English alphabet, which has 26 letters. Since each initial is independent of the others, the total number of possible initials is found by multiplying the number of options for each initial together.

The calculation is as follows:

First name initial: 26 possibilities (A-Z)

Middle name initial: 26 possibilities (A-Z)

Last name initial: 26 possibilities (A-Z)

So, the total number of possible initials would be:

26 (for the first name) x 26 (for the middle name) x 26 (for the last name) = 17,576 possible initials.

Answer:

a

Step-by-step explanation:

Answer:

133

Step-by-step explanation:

Evaluate g(- 5) then substitute the value obtained into f(x)

g(- 5) = - 5 - 3 = - 8, then

f(- 8) = 2(- 8)² + 5 = 2(64) + 5 = 128 + 5 = 133

Answer:

y = 2.50 , x = 1.25

Step-by-step explanation:

x = soft tacos

y = double deckers

Dory:

3x + 3y = 11.25 

Nemo:

4x + 2y = 10.00

---Now to solve for x and y---

---We find LCM of either x or y then make them cancel each other---

Dory multiply by 2:

6x + 6y = 22.50

Nemo multiply by 3:

12x + 6y = 30.00

--eliminate y--- 

Nemo subtract Dory:

6x = 7.50

Therefore x = 7.50 ÷ 6 = 1.25

---Now substitute x = 1.25 in either equation.---

Dory:

3.75 + 3y = 11.25

Therefore 3y = 11.25 - 3.75

therefore 3y = 7.50

there fore y = 2.50

y = 2.50 , x = 1.25

Answer:

x= $2.50, y= $1.25

Step-by-step explanation:

X= soft taco

Y= double deckers

$11.25= 3x+3y

$10.00= 4x+2y

first eliminate 1 variable, lets say d, to do this we must cancel them out, to do this multiply the top by -2 and the bottom by 3

 -2 ($11.25= 3x+3y)                                      -$22.50= -6x-6y

 3 ($10.00= 4x+2y)     which becomes.          $30.00=12x+6y

then the -6y and the positive 6y cancel out and you are left with 1 variable  

after this add the remaining parts to get.

$7.50=6x  divide by 6, then put x back into one of your original equations and solve for d then you have found how much each item costs and are finished with the system of equations