Answer:
[tex]\frac{\sqrt{x} }{2x}[/tex]
Step-by-step explanation:
Rationalize the denominator first (keep in mind we are NOT solving this because there is no equals sign here. We are merely simplifying.)
[tex]\frac{\sqrt{5x} }{x\sqrt{20} } *\frac{\sqrt{20} }{\sqrt{20} } =\frac{\sqrt{100x} }{20x}[/tex]
Now simplify by taking the square root of 100 to get:
[tex]\frac{10\sqrt{x} }{20x}[/tex]
Divide numerator and denomiator by 10 to get:
[tex]\frac{\sqrt{x} }{2x}[/tex]
Can someone help me with translation
Answer:
P' = (4, 4)
Step-by-step explanation:
T(x, y) is a function of x and y. Put the x- and y-values of point P into the translation formula and do the arithmetic.
P' = T(8, -3) = (8 -4, -3 +7) = (4, 4)
_____
Comment on notation
The notation can be a little confusing, as the same form is used to mean different things. Here, P(8, -3) means point P has coordinates x=8, y=-3. The same form is used to define the translation function:
T(x, y) = (x -4, y+7)
In this case, T(x, y) is not point T, but is a function named T (for "translation function") that takes arguments x and y and gives a coordinate pair as a result.
Translation is the process of transferring text from one language into another, aiming to maintain the original message's style, tone, and nuances. This practice requires a solid understanding of both the source and target languages.
Explanation:Translation refers to the process of converting text from one language into another. The goal of translation is to accurately convey the meaning of the source language into the target language, while preserving the style, tone, and nuances. For example, if you want to translate the English phrase 'Hello, how are you?' into French, the translation would be 'Bonjour, comment ça va?'.
Handling translations can be tricky due to cultural differences, idiomatic expressions, and grammatical rules of the different languages. Practice and immersion in both languages can help improve translation skills.
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You have a circular rug with a circumference of 40.82 feet that you are trying to fit in your perfectly square room. What is the minimum width that your room needs to be for the rug to fit
Answer:
13.0 feet
Step-by-step explanation:
The circumference of a circle is given by the formula ...
C = πd . . . . . . where d represents the diameter
Then the diameter is ...
d = C/π = 40.82 ft/π ≈ 12.9934 ft
Rounded to the nearest tenth foot, the width of the room must be 13.0 ft.
A quadrilateral has one pair of parallel sides with lengths 1 3/4 inches and 1 1/4 inches, and two angles that measure 36 degrees. What is the mane of the quadrilateral you drew?
Answer:
The name of the quadrilateral is isosceles trapezoid.Explanation:
1) The two parallel sides of different legths [tex]1\frac{3}{4}[/tex] and [tex]1\frac{1}{4}[/tex] constitute the bases of a trapezoid.
2) The two equal anglesare the base angles of the trapezoid, and mean that it is an isosceles trapezoid.
An isosceles trapezoid is truncated isosceles triangle.
The definition of trapezoid is a quadrilateral with at least two parallel sides.
The drawing is attached: only the green lines represent the figure, the dotted lines just show how this is derived from an isosceles triangle.
Answer:
trapezoid
Step-by-step explanation:
BRAINLIEST! find the LCM of the set of polynomials.
121x^2-9y^2,11x^2+3yx
Answer:
[tex]\large\boxed{LCM(121x^2-9y^2,\ 11x^2+3xy)=121x^3-9xy^2}[/tex]
Step-by-step explanation:
[tex]121x^2-9y^2=11^2x^2-3^2y^2=(11x)^2-(3y)^2\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=(11x-3y)\underline{(11x+3y)}\\\\11x^2+3yx=x\underline{(11x+3y)}\\\\LCM(121x^2-8y^2,\ 11x^2+3yx)=\underline{(11x+3y)}(11x-3y)(x)\\\\=(121x^2-9y^2)(x)=121x^3-9xy^2[/tex]
Is the work shown in the simplification below correct? explain. csc(t) sec(t) = 1 cos(t) ÷ 1 sin(t) = 1 cos(t) • sin(t) 1 = 1 sin(t) = tan(t)?
Answer:
The work shown in the simplification below is incorrect.
Step-by-step explanation:
To start; we have to know what csc(t) and sec(t) is.
csc(t) = 1/sin(t) and sec(t)= 1/cos(t)
So in the above simplification it was all mixed up, csc(t) was substituted with 1/cos(t) instead of 1/sin(t) and sec(t) was substituted with 1/sin(t) instead of 1/cos(t).
So, we are going to solve it the right way;
csc(t) sec(t) = [tex]\frac{1}{sin(t)}[/tex] ÷ [tex]\frac{1}{cos(t)}[/tex]
= [tex]\frac{1}{sin(t)}[/tex] × [tex]\frac{cos(t)}{1}[/tex]
=[tex]\frac{cos(t)}{sin(t)}[/tex]
= cot(t)
Therefore csc(t) sec(t) = cot(t) and not tan(t).
The simplification shown is not correct because the steps used are incorrect and the resulting expression is not equivalent to the original. The correct simplification is csc(t) sec(t) = 1/(sin(t) * cos(t)).
Explanation:The simplification shown is not correct. Let's break it down step by step:
csc(t) sec(t) = 1/sin(t) * 1/cos(t) = (1/cos(t)) * (1/sin(t)).Using the commutative property of multiplication, we can switch the order: (1/sin(t)) * (1/cos(t)) = (1/cos(t)) * (1/sin(t)).Multiplying the fractions together, we get 1/(cos(t) * sin(t)).However, 1/(cos(t) * sin(t)) is not equal to 1/sin(t). Therefore, the simplification is incorrect.To simplify the expression correctly, we can use the reciprocal identities: csc(t) = 1/sin(t) and sec(t) = 1/cos(t). When multiplying these together, we get:
csc(t) * sec(t) = (1/sin(t)) * (1/cos(t)) = 1/(sin(t) * cos(t)).
So, the correct simplification is csc(t) sec(t) = 1/(sin(t) * cos(t)).
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Data is often displayed using numbers and categories. Which types of graphs are most appropriate for displaying categorical data? Check all of the boxes that apply. bar graphs histograms pie charts or circle graphs stem-and-leaf plots
Answer:
A. bar graphs
C. pie charts or circle graphs
Step-by-step explanation:
The most suitable graphs for displaying categorical data are bar graphs and pie charts, as bar graphs are used to compare categories or show changes over time, while pie charts are ideal for displaying parts of a whole.
Explanation:The most appropriate types of graphs for displaying categorical data are bar graphs and pie charts or circle graphs. In a bar graph, the length of each bar represents the number or percent of individuals in each category. Bars in a bar graph can be vertical or horizontal and are used to compare categories or show changes over time. Pie charts show categories of data as wedges in a circle, with each wedge representing a percentage of the whole, making it ideal for showing parts of a whole.
A stem-and-leaf plot, on the other hand, is useful for showing all data values within a class and mainly represents quantitative data rather than categorical data. Histograms, while similar to bar graphs, are used for displaying the distribution of quantitative, not categorical, data. Therefore, for categorical data, bar graphs and pie charts are most suitable.
Jan takes a sales job that pays 4.15% commission. He typically sells $48,500 worth of merchandise per month. What is his gross annual income?
Answer:
$24,153
Step-by-step explanation:
Jan's monthly income from commissions is ...
4.15% × $48,500 = $2012.75
Multiplied by 12 months in the year, that is ...
$2012.75 × 12 = $24,153 . . . . gross annual income from commissions
The question is in the picture.
Answer:
42 = (3 +x)(4 +x)
Step-by-step explanation:
The only equation that has the existing dimensions increased by x is the first one.
y-9/5 = 3 solve for y
a. 24
b. 6
c. -6
d. -24
Answer:
[tex]\large\boxed{a.\ y=24}[/tex]
Step-by-step explanation:
[tex]\dfrac{y-9}{5}=3\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{y-9}{5\!\!\!\!\diagup_1}=5\cdot3\\\\y-9=15\qquad\text{add 9 to both sides}\\\\y-9+9=15+9\\\\y=24[/tex]
Will markk the brainliest
1. If the domain of a function f(x) is the set {10, 20, 30}. What does the information tell you about f-1(x)?
2. If the graph of a function f(x) includes the point (3, 0), what point must the graph of f-1(x) include? Explain.
3.The first term in an arithmetic sequence is 2. The twelfth term is 211. Find the value of n so that an = 135.
Answer:
1. the range of f^-1(x) is {10, 20, 30}.
2. the graph of f^-1(x) will include the point (0, 3)
3. n = 8
Step-by-step explanation:
1. The domain of a function is the range of its inverse, and vice versa. The range of f^-1(x) is {10, 20, 30}.
__
2. See above. The domain and range are swapped between a function and its inverse. That means function point (3, 0) will correspond to inverse function point (0, 3).
__
3. The n-th term of an arithmetic sequence is given by ...
an = a1 +d(n -1)
You are given a1 = 2, a12 = 211, so ...
211 = 2 + d(12 -1)
209/11 = d = 19 . . . . . solve the above equation for the common difference
Now, we can use the same equation to find n for an = 135.
135 = 2 + 19(n -1)
133/19 = n -1 . . . . . . . subtract 2, divide by 19
7 +1 = n = 8 . . . . . . . . add 1
135 is the 8th term of the sequence.
The Anza-Borrego Desert State Park is one of the best places in the United States for viewing stars. During one 50-day period, cloud cover obstructed nighttime views just 6% of the time. Based on that sample, how many days a year would you predict that clouds there will interfere with stargazing? Complete the explanation.
The clouds wlll interfere for 21 ⁹/₁₀ days in a year
What are percentages?A percentage is a number or ratio that can be expressed as a fraction of 100. If we have to calculate the percent of a number, divide the number by the whole and multiply by 100. Hence, the percentage means, a part per hundred. The word percent means per 100. It is represented by the symbol “%”
Given here one 50-day period, cloud cover obstructed nighttime views just 6% or for the 50 day period the cloud obstructed t = 6% of 50
= 3 days
the number of 50 days period in a year = 365/50
= 350/50 + 15/50
= 7 + 15/50
Therefore the number of days the cloud will obstruct is = (7 + 15/50)×3
= 21⁹/₁₀
Hence the clouds will obstruct 21⁹/₁₀ days in a year.
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Final answer:
Based on a 50-day sample with 6% cloud coverage, one would predict that at Anza-Borrego Desert State Park, clouds will interfere with stargazing for approximately 22 days out of the year.
Explanation:
The Anza-Borrego Desert State Park had cloud coverage that obstructed nighttime views 6% of the time during a 50-day period. To predict how many days a year clouds would interfere with stargazing, you would use this percentage. The calculation is as follows:
Find the total number of days in a year, which is 365.
Calculate 6% of 365 days to find the number of days with cloud coverage. This is done by multiplying 365 by 0.06.
The result gives you the predicted number of days with cloud coverage obstructing stargazing. In numbers: 365 days/year × 0.06 (6%) = 21.9 days/year.
Therefore, based on the given sample, you would predict that clouds will interfere with stargazing at Anza-Borrego Desert State Park for approximately 22 days each year (rounding 21.9 up to the nearest whole number).
Given the lease terms below, what monthly lease payment can you expect on this vehicle?
Terms:
•Length of Lease: 60 months
•MSRP of the car: $28,500
•Purchase value of the car after lease: $12,900
•Down Payment:$1900
•Lease Factor:0.0005
•Security Deposit:$375
•Aquisition Fee: $300
A.$232.50
B.$279.99
C.$227.50
D.$248.08
Answer:
D. $248.08
Step-by-step explanation:
Your question does not involve any taxes, so we'll compute the lease payment based on car value. We presume the Down Payment, Security Deposit, and Acquisition Fee are paid at the time the lease is signed, so are not part of the financing.
Then we have ...
lease payment = depreciation fee + financing fee
where these fees are calculated from ...
depreciation fee = ((net capitalized cost) - (residual value))/(months in lease)
and ...
financing fee = ((net capitalized cost) + (residual value))×(lease factor)
___
Using the given numbers, we have ...
net capitalized cost = MSRP - Down Payment = $28,500 -1,900 = $26,600
depreciation fee = ($26,600 -12,900)/60 = $13,700/60 = $228.33
financing fee = ($26,600 +12,000)×0.0005 = $39,500×0.0005 = $19.75
lease payment = $228.33 + 19.75 = $248.08
_____
In the attached, the "new car lending rate" is 2400 times the lease factor, so is 1.2. This is an equivalent APR.
Effectively, the monthly lease fee is the average of the depreciating car value over the life of the lease multiplied by this APR. The depreciation for this purpose is assumed to be linear.
It’s D because you add all of them up
The weekly incomes of trainees at a local company are normally distributed with a mean of $1,100 and a standard deviation of $250. If a trainee is selected at random, what is the probability that he or she earns less than $1,000 a week?
Select one:
a. 0.8141
b. 0.1859
c. 0.6554
d. 0.3446
Answer:
d. 0.3446
Step-by-step explanation:
We need to calculate the z-score for the given weekly income.
We calculate the z-score of $1000 using the formula
[tex]z=\frac{x-\mu}{\sigma}[/tex]
From the question, the standard deviation is [tex]\sigma=250[/tex] dollars.
The average weekly income is [tex]\mu=1,100[/tex] dollars.
Let us substitute these values into the formula to obtain:
[tex]z=\frac{1,000-1,100}{250}[/tex]
[tex]z=\frac{-100}{250}[/tex]
[tex]z=-0.4[/tex]
We now read from the standard normal distribution table the area that corresponds to a z-score of -0.4.
From the standard normal distribution table, [tex]Z_{-0.4}=0.34458[/tex].
We round to 4 decimal places to obtain: [tex]Z_{-0.4}=0.3446[/tex].
Therefore the probability that a trainee earns less than $1,000 a week is [tex]P(x\:<\:1000)=0.3446[/tex].
The correct choice is D.
This question is called "Create equations to solve for missing angles"
Help me!! Its very confusing.
Answer:
A
But it needs explanation.
Step-by-step explanation:
The first one hides the fact, but it is indeed the answer.
6x + 12x = 90 degrees is the way the equation should actually be set up.
A does that by adding 90 to both sides to start with.
6x + 12x + 90 = 90 + 90
The reason it does this is to show that the three angles (6x 12x and 90 make up the entire straight angle shown in the diagram.
The answer is going to be the same.
18x = 90 Combine like terms on the left
18x /18 = 90 / 18 Divide by 18
x = 5
Answer:
A
Step-by-step explanation:
The 3 given angles form a straight angle and sum to 180°, hence
6x + 12x + 90 = 180 ← is the required equation
Rewrite the following linear equation in slope-intercept form. Write your
answer with no spaces
Answer: Y = 4x - 14
Step-by-step explanation:
See paper attached. (:
Evaluate x + 3y, if x = 9 and y = -4.
To solve this you must plug in 9 for x and -4 for y in the equation
X + 3y like so...
9 + 3(-4)
In accordance to the rules of PEMDAS you must multiply first, which will get you...
9 + (-12)
Add these two together and you get:
-3
Hope this helped
~Just a girl in love with Shawn Mendes
Answer:
-2
Step-by-step explanation:
which of the following sets are discrete? check all that apply.
A. {1,3,5,7,...}
B. (-10,20)
C. {5,8}
D. (1,99)
E. {-3,6,9,17,24}
Answer:
All are discrete sets
Step-by-step explanation:
Any set for which you can list the elements is a discrete set, even if that list has "..." (continues in like fashion). Sets that are not discrete are those that are continuous, such as "all real numbers" or "the numbers between 0 and 1".
The discrete sets from the options given are A. {1,3,5,7,...}, C. {5,8}, and E. {-3,6,9,17,24}.
A discrete set is one where the elements are separate and distinct, often meaning each member can be counted and there is no continuous spectrum of values between any two elements.
A. {1,3,5,7,...} - This set represents odd numbers which is discrete because we can identify each individual element.
B. (-10,20) - This is not a set but an interval representing a continuous range of real numbers; therefore, it is not discrete.
C. {5,8} - This set has only two elements, each distinct and countable, making it discrete.
D. (1,99) - Similar to B, this is an interval showing a continuous range of real numbers, and thus not discrete.
E. {-3,6,9,17,24} - This set includes separate, identifiable numbers and is therefore discrete.
Which of the following best describes the graph below?
A. It is a function, but it is not one-to-one.
B. It is a one-to-one function.
C. It is not a function.
D. It is a many-to-one function.
Answer:
B. It is a one-to-one function.
Step-by-step explanation:
Each value of the domain maps to a unique value of the range. It is a one-to-one function.
Answer:
B. It is a one to one function.
Step-by-step explanation:
It is a function, if we trace the vertical line [tex]x=a[/tex] it intersects exactly one point of the graph (in the case that [tex]a\neq0[/tex].Moreover, the line [tex]x=0[/tex] doesn't intersects the graph, hence the given graph is the graph of a function with domain [tex]\mathbb{R}-\{0\}[/tex]. On the other hand, a function f(x) is one to one, if whenever f(x)=f(y) it holds that x=y, in terms of the graph of a function this mean that whenever we trace a vertical line [tex]y=b[/tex] it intersects exactly one point, which is exactly the case fo our given graph. Threfore, it is the graph of a one to one function
A car with 24 in tires in diameter travels at a speed of 60 mph. What is the angular speed of the tires? Express your answer in degrees per second and round to the nearest degree per second
The tire has a circumference [tex]24\pi[/tex] inches, or [tex]2\pi[/tex] feet. It has a linear speed of 60 mph, or 88 feet/second. This means that any point on the rim of the tire will have traveled 88 feet in 1 second. We have
[tex]\dfrac{88}{2\pi}=\dfrac{44}\pi\approx14.006[/tex]
which means the tire completes a little over 14 revolutions in 1 second. One complete revolution corresponds to a rotation of 360º. Then its angular speed in degrees per second is
[tex]\left(\dfrac{44}\pi\dfrac{\rm rev}{\rm s}\right)\dfrac{360\,\rm deg}{1\,\rm rev}}=5042\dfrac{\rm deg}{\rm s}[/tex]
Given the car's speed of 60 mph and the tires' diameter of 24 inches, we can convert them to more standard units of meters and seconds. Using the physical concept that the angular speed equals the rate of change of angular displacement, we calculate the angular speed of the tires in radians per second. The result is then converted back to the desired unit of degrees per second, yielding an approximate angular speed of 5041 deg/sec.
Explanation:To determine the angular speed of the tires, we need to understand some basic physics. First, we should calculate the linear velocity in more standard units. As we know 1 mile is approximately 1609.34 meters, and 1 hour is 3600 seconds, thus we can convert 60 mph into approximately 26.82 meter per second.
Next, the diameter of the tire is given as 24 inches, which is approximately 0.61 meters (as 1 inch = 0.0254 meters), so the radius r of the tire will be half of that, which is about 0.305 meters. The linear speed v of the edge of the tire is equal to the speed of the car, v = 26.82 meter per second.
The angular velocity w is defined as the rate of change of angular displacement with respect to time, which can also be expressed in terms of linear velocity and radius of the circular path as w = v/r. Plugging in our values, we can calculate w to be approximately 87.9 rad/sec.
Now, to convert to degrees per second, we should know that 1 radian is equal to approximately 57.2958 degrees. Therefore, the angular speed of the tire in degree per second is approximately 5041 degrees per second, or rounded to the nearest degree per second, it's approximately 5041 deg/sec.
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Order the polynomial in descending powers of r. Do not repeat terms.
Answer:
[tex]-4r^3-3r^2+2rs-5[/tex]
Step-by-step explanation:
The terms have powers of r that are 2, 0, 1, and 3 (in the order shown here). You want to rearrange those terms so the powers have order 3, 2, 1, 0. The above answer shows that arrangement.
Ordering a polynomial in descending powers of r involves arranging the terms from the highest to the lowest exponent of r. When squaring exponentials, square the digit and double the exponent. For large r compared to d, d can be disregarded.
Explanation:Ordering a polynomial in descending powers of r involves organizing the terms from highest to lowest exponent of the variable r. For example, for a polynomial of r as 6r^4 - 2r + 7r^2 - 3, we would arrange it as 6r^4 + 7r^2 - 2r - 3. Note that the polynomial starts with the term with the highest power of r (r^4), followed by the term with the next highest power (r^2). The process continues down to the term with the lowest power of r (r), and lastly, the constant term (-3). Remember to retain the corresponding coefficients while reordering terms.
When dealing with terms involving the squaring of exponentials, remember to square the digit as usual and double the exponent. For instance, (r^3)^2 would be r^6.
Also, comparisons of terms such as r » d (meaning r is much larger than d), we disregard d as its contribution to the final polynomial will be negligible.
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Chuck is making a salad to go with his soup. The recipe calls for 2.1 cups of lettuce per person and 0.56 ounces of salad dressing per cup of lettuce. If 11 dinner guests want salad, how many ounces of dressing will be necessary? Round the answer to the nearest whole ounce. 1 ounce 2 ounces 6 ounces 13 ounces
The answer is:
There will be necessary 13 ounces of salad dressing.
Why?
Since we already know that there will be needed 0.56 ounces of salad dressing per cup, and the recipe calls 2.1 cups of lettuce per person, we need to calculate the total ounces of salad dressing per each person, and then, calculate it for 11 persons.
So, calculating we have:
[tex]SaladDressingPerPerson=Cups*SaladDressing=2.1*0.56oz\\\\SaladDressingPerPerson=1.176oz[/tex]
Therefore, we know that there will be needed 1.176 ounces of salad dressing per person.
Then, calculating the ounces of dressing for 11 dinner guests, we have:
[tex]TotalOunces=SaladDressingPerPerson*NumberOfPersons\\\\TotalOunces=1.176ounces*11=12.94ounces=13ounces[/tex]
Hence, we have that there will be necessary 13 ounces of salad dressing.
Have a nice day!
Answer:
the answer is D
Step-by-step explanation:
One hundred thirty people were asked to determine how many cups of fruit and water they consumed per day. The results are shown in the frequency table. Identify the conditional relative frequency by row. Round to the nearest percent. The conditional relative frequency that someone ate more than 2 cups of fruit, given the person drank less than or equal to 4 cups of water is approximately . The conditional relative frequency that someone ate less than or equal to 2 cups of fruit, given the person drank more than 4 cups of water is approximately .
Answer:
1. 24%
2.38%
Step-by-step explanation:
Answer:
The first one is 24% and the second one is 38%
Step-by-step explanation:
i did it on egdenuity
Please answer this multiple choice question correctly for 30 points and brainliest!!
Answer:
A. $3.63
Step-by-step explanation:
You can choose the correct answer simply by estimating.
The almonds are about $5.50 for each of the 2 kg, so will total about $11. Since the total amount paid is just over $25, the amount paid for cashews is about $25 -11 = $14.
That amount pays for 4 kg of cashews, so 1 kg will be half of half that amount, or about $3.50 -- certainly, less than $7.26.
_____
If you want to write an equation, you can write ...
2(5.49) +4(c) = 25.50
4c = 14.52 . . . . . . . . . . . . subtract 10.98
14.52/4 = c = 3.63 . . . . . divide by the coefficient of c
1 kg of cashews has a price of $3.63.
Help calculus module 7 DBQ
please show work
1. Filling in the table is just a matter of plugging in the given [tex]x,y[/tex] values into the ODE [tex]\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{xy}3[/tex]:
[tex]\begin{array}{c|ccccccccc}x&-1&-1&-1&0&0&0&1&1&1\\ y&1&2&3&1&2&3&1&2&3\\\frac{\mathrm dy}{\mathrm dx}&-\frac13&-\frac23&-1&0&0&0&\frac13&\frac23&1\end{array}[/tex]
2. I've attached what the slope field should look like. Basically, sketch a line of slope equal to the value of [tex]\dfrac{\mathrm dy}{\mathrm dx}[/tex] at the labeled point (these values are listed in the table).
3. This ODE is separable. We have
[tex]\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{xy}3\implies\dfrac{\mathrm dy}y=\dfrac x3\,\mathrm dx[/tex]
Integrating both sides gives
[tex]\ln|y|=\dfrac{x^2}6+C\implies y=e^{x^2/6+C}=Ce^{x^2/6}[/tex]
With the initial condition [tex]f(0)=4[/tex], we take [tex]x=0[/tex] and [tex]y=4[/tex] to solve for [tex]C[/tex]:
[tex]4=Ce^0\implies C=4[/tex]
Then the particular solution is
[tex]\boxed{y=4e^{x^2/6}}[/tex]
4. First, solve the ODE (also separable):
[tex]\dfrac{\mathrm dT}{\mathrm dt}=k(T-38)\implies\dfrac{\mathrm dT}{T-38}=k\,\mathrm dt[/tex]
Integrating both sides gives
[tex]\ln|T-38|=kt+C\implies T=38+Ce^{kt}[/tex]
Given that [tex]T(0)=75[/tex], we can solve for [tex]C[/tex]:
[tex]75=38+C\implies C=37[/tex]
Then use the other condition, [tex]T(30)=60[/tex], to solve for [tex]k[/tex]:
[tex]60=38+37e^{30k}\implies k=\dfrac1{30}\ln\dfrac{22}{37}[/tex]
Then the particular solution is
[tex]T(t)=38+37e^{\left(\frac1{30}\ln\frac{22}{37}\right)t}[/tex]
Now, you want to know the temperature after an additional 30 minutes, i.e. 60 minutes after having placed the lemonade in the fridge. According to the particular solution, We have
[tex]T(60)=38+37e^{2\ln\frac{22}{37}}\approx\boxed{51^\circ}[/tex]
5. You want to find [tex]t[/tex] such that [tex]T(t)=55[/tex]:
[tex]55=38+37e^{\left(\frac1{30}\ln\frac{22}{37}\right)t}\implies\dfrac{17}{37}=e^{\left(\frac1{30}\ln\frac{22}{37}\right)t}[/tex]
[tex]\implies t=\dfrac{30\ln\frac{17}{37}}{\ln\frac{22}{37}}\approx\boxed{45\,\mathrm{min}}[/tex]
Express tan B as a fraction in simplest form.
Based on the given triangle, tan(B) as a fraction in its simplest form is 3/4. Option 1 (None of the listed answers are correct)
How to calculate angle in a triangle
In a right-angled triangle ABC, where the adjacent side (AC) is 4, the opposite side (BC) is 3, and the hypotenuse side (AB) is 5, use the tangent function to find the value of tan(B).
The tangent function is defined as the ratio of the opposite side to the adjacent side:
tan(B) = BC / AC
tan(B) = 3 / 4
To express tan(B) as a fraction in simplest form, simplify the ratio by dividing both the numerator and denominator by their greatest common divisor, which in this case is 1:
tan(B) = 3 / 4
Therefore, tan(B) is already in its simplest form as the fraction 3/4.
To express tan B as a fraction in its simplest form, you need to have information about the angle B or, if it pertains to a right triangle, you need to know the lengths of the sides of the triangle that form angle B.
The expression for tan B is based on the ratio of the length of the opposite side to the length of the adjacent side in a right-angled triangle. In mathematical terms, this is written as:
\[ \tan(B) = \frac{\text{opposite side}}{\text{adjacent side}} \]
To write this as a fraction in simplest form, you would follow these steps:
1. Identify the lengths of the opposite and adjacent sides relative to angle B.
2. Write the ratio of these lengths as a fraction.
3. Simplify the fraction by dividing both the numerator (opposite side) and the denominator (adjacent side) by their greatest common divisor (GCD).
As an example, suppose in a right triangle the length of the side opposite angle B is 6 units and the length of the side adjacent to angle B is 8 units:
\[ \tan(B) = \frac{6}{8} \]
Now, we simplify the fraction by finding the GCD of 6 and 8:
The GCD of 6 and 8 is 2.
So, we divide both numerator and denominator by 2:
\[ \tan(B) = \frac{6 \div 2}{8 \div 2} = \frac{3}{4} \]
Therefore, in this example, tan B is \( \frac{3}{4} \) in simplest form.
If you do not have the lengths of the opposite and adjacent sides or a specific value for angle B (for example, B is a special angle such as 30°, 45°, or 60° for which the tangent values are known), then you cannot express tan B as a fraction in simplest form without additional information.
A cube with a volume of 64 cubic meters is scaled by a factor of 5. What is the volume of the modified cube in meters
[tex]\bf \textit{volume of a cube}\\ V=s^3~~ \begin{cases} s=&side's\\ &length\\ \cline{1-2} V=&64 \end{cases}\implies 64=s^3\implies \sqrt[3]{64}=s\implies \boxed{4=s} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{scaling all sides by a factor of 5}}{V=s^3\implies V=(4\cdot 5)^3}\implies V=20^3\implies V=8000[/tex]
Answer:
8,000
Step-by-step explanation:
When the sides of the cube are scaled by a factor of k, the volume increases by a factor of k3. Here, the new volume is 64 cubic meters × 53 = 8,000 cubic meters.
Calculate the discriminant to determine the number solutions. y = x ^2 + 3x - 10
Two irrational solutions
Not solutions
two rational solutions
one rational solution
1. The first step is to find the discriminant itself. Now, the discriminant of a quadratic equation in the form y = ax^2 + bx + c is given by:
Δ = b^2 - 4ac
Our equation is y = x^2 + 3x - 10. Thus, if we compare this with the general quadratic equation I outlined in the first line, we would find that a = 1, b = 3 and c = -10. It is easy to see this if we put the two equations right on top of one another:
y = ax^2 + bx + c
y = (1)x^2 + 3x - 10
Now that we know that a = 1, b = 3 and c = -10, we can substitute this into the formula for the discriminant we defined before:
Δ = b^2 - 4ac
Δ = (3)^2 - 4(1)(-10) (Substitute a = 1, b = 3 and c = -10)
Δ = 9 + 40 (-4*(-10) = 40)
Δ = 49 (Evaluate 9 + 40 = 49)
Thus, the discriminant is 49.
2. The question itself asks for the number and nature of the solutions so I will break down each of these in relation to the discriminant below, starting with how to figure out the number of solutions:
• There are no solutions if the discriminant is less than 0 (ie. it is negative).
If you are aware of the quadratic formula (x = (-b ± √(b^2 - 4ac) ) / 2a), then this will make sense since we are unable to evaluate √(b^2 - 4ac) if the discriminant is negative (since we cannot take the square root of a negative number) - this would mean that the quadratic equation has no solutions.
• There is one solution if the discriminant equals 0.
If you are again aware of the quadratic formula then this also makes sense since if √(b^2 - 4ac) = 0, then x = -b ± 0 / 2a = -b / 2a, which would result in only one solution for x.
• There are two solutions if the discriminant is more than 0 (ie. it is positive).
Again, you may apply this to the quadratic formula where if b^2 - 4ac is positive, there will be two distinct solutions for x:
-b + √(b^2 - 4ac) / 2a
-b - √(b^2 - 4ac) / 2a
Our discriminant is equal to 49; since this is more than 0, we know that we will have two solutions.
Now, given that a, b and c in y = ax^2 + bx + c are rational numbers, let us look at how to figure out the number and nature of the solutions:
• There are two rational solutions if the discriminant is more than 0 and is a perfect square (a perfect square is given by an integer squared, eg. 4, 9, 16, 25 are perfect squares given by 2^2, 3^2, 4^2, 5^2).
• There are two irrational solutions if the discriminant is more than 0 but is not a perfect square.
49 = 7^2, and is therefor a perfect square. Thus, the quadratic equation has two rational solutions (third answer).
~ To recap:
1. Finding the number of solutions.
If:
• Δ < 0: no solutions
• Δ = 0: one solution
• Δ > 0 = two solutions
2. Finding the number and nature of solutions.
Given that a, b and c are rational numbers for y = ax^2 + bx + c, then if:
• Δ < 0: no solutions
• Δ = 0: one rational solution
• Δ > 0 and is a perfect square: two rational solutions
• Δ > 0 and is not a perfect square: two irrational solutions
How many blocks are in the 10th figure
Answer:
11 squared, or 121.
Step-by-step explanation:
Fig. 1 = 4 b(locks)
or 2 squared
Fig. 2 = 9 b
or 3 squared
Fig. 3 = 16 b
or 4 squared
Fig. 4 = 25 b
or 5 squared
Fig. 10 would be 11 squared, or 121.
Answer:
The answer is 121
Step-by-step explanation:
what is the perimeter of a triangle with vertices located at (1.4) (2,7) and (0,5)
Answer:
The perimeter of triangle is [tex]P=(\sqrt{10}+3\sqrt{2})\ units[/tex]
Step-by-step explanation:
Let
[tex]A(1.4),B(2,7),C(0,5)[/tex]
we know that
The perimeter of the triangle is equal to
[tex]P=AB+BC+AC[/tex]
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
step 1
Find the distance AB
[tex]A(1.4),B(2,7)[/tex]
substitute the values
[tex]AB=\sqrt{(7-4)^{2}+(2-1)^{2}}[/tex]
[tex]AB=\sqrt{(3)^{2}+(1)^{2}}[/tex]
[tex]AB=\sqrt{10}\ units[/tex]
step 2
Find the distance BC
[tex]B(2,7),C(0,5)[/tex]
substitute the values
[tex]BC=\sqrt{(5-7)^{2}+(0-2)^{2}}[/tex]
[tex]BC=\sqrt{(-2)^{2}+(-2)^{2}}[/tex]
[tex]BC=\sqrt{8}\ units[/tex]
[tex]BC=2\sqrt{2}\ units[/tex]
step 3
Find the distance AC
[tex]A(1.4),C(0,5)[/tex]
substitute the values
[tex]AC=\sqrt{(5-4)^{2}+(0-1)^{2}}[/tex]
[tex]AC=\sqrt{(1)^{2}+(-1)^{2}}[/tex]
[tex]AC=\sqrt{2}\ units[/tex]
step 4
Find the perimeter
[tex]P=AB+BC+AC[/tex]
[tex]P=\sqrt{10}+2\sqrt{2}+\sqrt{2}[/tex]
[tex]P=(\sqrt{10}+3\sqrt{2})\ units[/tex]
8 people went to a football game together in one van they spent $4 to park in the rest on tickets the total spent was $88 what was the cost for each ticket
Answer:
$10.5
Step-by-step explanation:
88-4 = $84
84/8 = 10.5