she travels 5km north 3km east 1km north again what is the distance and displacement she walks 3hrs what is the average speed and average velocity

Explanation:

Wave

It is the periodic disturbance in a medium.

Types of Wave

There are two types of wave in general depending upon their propagation through a substance.

• Mechanical  

• Electromagnetic  

Mechanical Wave

It is the kind of wave which needs medium to travel.

For example: Sound Wave  

Electromagnetic Wave

Is that which can travel through medium as well as through vacuum. For example: Light

Characteristics of Wave

There are certain characteristics that each sound possesses. Let’s see.  

 Oscillation: It is the complete movement of particle about its mean position.

Amplitude: Is the maximum displacement of particle from its mean position in either direction (cm).It is denoted by ‘A’.

Frequency: It is the number of sound waves produced per second (Hertz).It is denoted by υ(nu)

Time Period: The time taken to complete one oscillation (sec).It is denoted by ‘T’.

Wavelength: The distance between two consecutive crest or trough (cm).It is denoted by λ(lambda).

Velocity of Wave: The speed with which sound travel (m/sec).It is denoted by ‘v’.

Relation between time period, frequency and velocity of wave  

We have: frequency =velocity /wavelength  

                υ=c/λ

Velocity of wave depends upon :

frequency of wave

Wavelength of wave

Therefore , with change in wavelength , the velocity of a wave in medium changes .

1) At the top of the building, the ball has more potential energy

2) When the ball is halfway through the fall, the potential energy and the kinetic energy are equal

3) Before hitting the ground, the ball has more kinetic energy

4) The potential energy at the top of the building is 784 J

5) The potential energy halfway through the fall is 392 J

6) The kinetic energy halfway through the fall is 392 J

7) The kinetic energy just before hitting the ground is 784 J

Explanation:

1)

The potential energy of an object is given by

[tex]PE=mgh[/tex]

where

m is the mass

g is the acceleration of gravity

h is the height relative to the ground

While the kinetic energy is given by

[tex]KE=\frac{1}{2}mv^2[/tex]

where v is the speed of the object

When the ball is sitting on the top of the building, we have

This means that the ball has more potential energy than kinetic energy.

2)

When the ball is halfway through the fall, the height is

[tex]h=20 m[/tex]

So, half of its initial height. This also means that the potential energy is now half of the potential energy at the top (because potential energy is directly proportional to the height).

The total mechanical energy of the ball, which is conserved, is the sum of potential and kinetic energy:

[tex]E=PE+KE=const.[/tex]

At the top of the building,

[tex]E=PE_{top}[/tex]

While halfway through the fall,

[tex]PE_{half}=\frac{PE_{top}}{2}=\frac{E}{2}[/tex]

And the mechanical energy is

[tex]E=PE_{half} + KE_{half} = \frac{PE_{top}}{2}+KE_{half}=\frac{E}{2}+KE_{half}[/tex]

which means

[tex]KE_{half}=\frac{E}{2}[/tex]

So, when the ball is halfway through the fall, the potential energy and the kinetic energy are equal, and they are both half of the total energy.

3)

Just before the ball hits the ground, the situation is the following:

Therefore, just before the ball hits the ground, it has more kinetic energy than potential energy.

4)

The potential energy of the ball as it sits on top of the building is given by

[tex]PE=mgh[/tex]

where:

m = 2 kg is the mass of the ball

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

h = 40 m is the height of the building, where the ball is located

Substituting the values, we find the potential energy of the ball at the top of the building:

[tex]PE=(2)(9.8)(40)=784 J[/tex]

5)

The potential energy of the ball as it is halfway through the fall is given by

[tex]PE=mgh[/tex]

where:

m = 2 kg is the mass of the ball

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

h = 20 m is the height of the ball relative to the ground

Substituting the values, we find the potential energy of the ball halfway through the fall:

[tex]PE=(2)(9.8)(20)=392 J[/tex]

6)

The kinetic energy of the ball halfway through the fall is given by

[tex]KE=\frac{1}{2}mv^2[/tex]

where

m = 2 kg is the mass of the ball

v = 19.8 m/s is the speed of the ball when it is halfway through the  fall

Substituting the values into the equation, we find the kinetic energy of the ball when it is halfway through the fall:

[tex]KE=\frac{1}{2}(2)(19.8)^2=392 J[/tex]

We notice that halfway through the fall, half of the initial potential energy has converted into kinetic energy.

7)

The kinetic energy of the ball just before hitting the ground is given by

[tex]KE=\frac{1}{2}mv^2[/tex]

where:

m = 2 kg is the mass of the ball

v = 28 m/s is the speed of the ball just before hitting the ground

Substituting the values into the equation, we find the kinetic energy of the ball just before hitting the ground:

[tex]KE=\frac{1}{2}(2)(28)^2=784 J[/tex]

We notice that when the ball is about to hit the ground, all the potential energy has converted into kinetic energy.

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Answer:

Quest ions

(Score for Question 1: ___ of 7 points)

1. Does the bowling ball have more potential energy or kinetic energy as it sit on top of the building? Why?

Answer: The bowling ball has more potential energy as it sits on top of the building because the force necessary to take the object from greater height will be more than from a lower height. Potential energy is stored energy, so when an object's height changes, its potential falls and becomes lower.

(Score for Question 2: ___ of 7 points)

2. Does the bowling ball have more potential energy or kinetic energy as it is half way through its fall? Why?

Answer: The potential and kinetic energy are the same as it is half way through its fall. The height is 20m half way through the fall, that also means that the potential energy is half of when the ball was at the top of the building.  

E= PE + KE,  

E= PE at the top,  

E= PE half way + KE half way = PE at the top / 2 + KE half way = E / 2 + KE half way,  

PE half way= PE at the top / 2 = KE half way = E / 2,

So when the ball is half way the kinetic energy and potential energy are equal, and each is half of the total energy.

(Score for Question 3: ___ of 7 points)

3. Does the bowling ball have more potential energy or kinetic energy just before it hits the ground? Why?

Answer: The bowling ball has more kinetic energy just before it hits the ground because it’s moving faster, and the faster something moves, the more kinetic energy it has.

(Score for Question 4: ___ of 4 points)

4. What is the potential energy of the bowling ball as it sits on top of the building?  

Answer:  

PE= mgh

Given:

mass= 2 kg,

gravity= 9.8m/s2,

height (where it’s located) = 40m,

PE= (2) (9.8) (40) = 748J

(Score for Question 5: ___ of 4 points)

5. What is the potential energy of the ball as it is half way through the fall, 20 meters high?  

Answer:

PE= mgh

Given:

mass= 2 kg,

gravity= 9.8m/s2,

height (where it’s located) = 20m,

PE= (2) (9.8) (20) = 392J

(Score for Question 6: ___ of 3 points)

6. What is the kinetic energy of the ball as it is half way through the fall?  

Answer:  

KE= ½mv2  

Given:

m= 2kg

v (the speed of the ball when it is halfway through the fall) = 19.8m/s

KE= ½ (2) (19.8)2 = 392J

(Score for Question 7: ___ of 3 points)

7. What is the kinetic energy of the ball just before it hits the ground?  

Answer:

KE= ½mv2  

Given:

m= 2kg

v (the speed of the ball when it is halfway through the fall) = 28m/s

KE= ½ (2) (28)2 = 784J

Answer:

KE = .5(m)(v²) and PE = mgh

Explanation:

m = mass, v = velocity, g = gravity (9.8 on earth), h = height.

Answer:

[tex]\boxed{\bold { \large { \boxed {KE=\frac{1}{2} mv^2 \ , \ PE=mgh}}}}[/tex]

Explanation:

Kinetic energy formula

[tex]\displaystyle KE=\frac{1}{2} mv^2[/tex]

Potential energy formula

[tex]\displaystyle PE=mgh[/tex]

[tex]\displaystyle KE \Rightarrow \sf kinetic \ energy \ (J)[/tex]

[tex]\displaystyle PE \Rightarrow \sf potential \ energy \ (J)[/tex]

[tex]\displaystyle m \Rightarrow \sf mass \ (kg)[/tex]

[tex]\displaystyle v \Rightarrow \sf velocity \ (m/s)[/tex]

[tex]\displaystyle g \Rightarrow \sf acceleration \ of \ gravity\ (m/s^2)[/tex]

[tex]\displaystyle h \Rightarrow \sf height \ (m)[/tex]

Answer:

89.75 J

Explanation:

The motor uses 90.00 J of electrical energy.  Any of that energy that isn't used to do work is converted to heat.

The amount of work done is:

W = mgh

W = (0.2549 kg) (9.81 m/s²) (0.1000 m)

W = 0.2501 J

So the heat generated is:

Q = 90.00 J − 0.2501 J

Q = 89.75 J

Circle graph is the type of graph which most clearly shows the part or percentage related to the whole.

Explanation:

Graphs are the easiest tool to show the change in a given dependent variable with respect to independent variable. The influence or the effects will be seen in the graphs.

There are different kinds of graph like circle graph, bar graph, line graph. Each of these have their own method of showing the change in the dependent variable. Among them, circle graph is the one which will help to show the percentage of each variable related to the whole.

The circle graph, or pie chart, excels in highlighting proportional relationships within a dataset. Its circular format provides an intuitive view of component distribution and significance. Here option C is correct.

A circle graph, also known as a pie chart, is particularly effective in illustrating the proportional relationship between individual components and the entire set. Graphs serve as a valuable tool for visualizing the fluctuations of a dependent variable in relation to an independent one.

Various types of graphs, such as bar graphs, line graphs, and circle graphs, offer distinct approaches to representing these changes. Among these options, the circle graph stands out for its ability to clearly depict the percentage contribution of each variable relative to the whole.

Its circular format allows for an intuitive understanding of the distribution and relative significance of different components within the dataset. By utilizing this visual representation, one can easily grasp the relative importance of each element and how they collectively constitute the entirety of the data. Here option C is correct.

Complete question:

Which type of graph is particularly effective in illustrating the proportional relationship between individual components and the entire set?

A) Bar graph

B) Line graph

C) Circle graph (Pie chart)

D) Scatter plot

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Answer: 1.6 m/s

Explanation: Avg.Speed = total Distance/ Total time

Avg Speed = 0.80 / 0.50

. = 1.6 m/s

Answer: The pressure from the air and force of who or what used effort to make it move. For example you roll a ball it doesn't stop unless it runs out of the force which in this case would be energy.

Explanation:

Knowledge

Camera is an optical instrument that forms images in a way most like human eyes.

Explanation:

The eye consists of a small spherical globe of about 2 cm in diameter, which is free to rotate under the control of 6 extrinsic muscles. Light enters the eye through the transparent cornea, passes through the aqueous humor, the lens, and the vitreous humor, where it finally forms an image on the retina.

In case of a digital camera, CCD is used known as charged coupled device. CCD is actually in the shape of array or a rectangular grid. It is like a matrix with each cell in the matrix contains a censor that senses the intensity of photon. When light falls on the object , the light reflects back after striking the object and allowed to enter inside the camera which is then stored by CCD in the form of electric signals.

Similarities between eye and a camera:

Cornea and Lens - The cornea is the “cap” of the eye. This transparent (like clear jelly) structure sits to the front of the eye. The lens of a camera is also transparent (glass) and sits at the front of the body.  Both allows light to enter and have spherical curvature.

Iris and aperture -The aperture is to the camera as the iris is to the eye. Both control the amount of light allowed to enter the eye or camera.

Retina and Film - The retina sits at the back of the eye and collects the light reflected from the surrounding environment to form the image. The same task in the camera is performed either by film or sensors in digital cameras.

Keywords: eye, camera, CCD, iris, film, aperture, cornea, lens, image formation

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A microscope forms images most similar to the eye due to the use of lenses and focusing techniques.

A microscope forms images in a way most like your eye. Both the eye and the microscope utilize lenses to form images. The method of focusing in the eye, through changes in the curvature of a lens, differs slightly from most optical instruments but is more similar to how a microscope forms images.

C. Circumpolar

Explanation:

Antarctic  circumpolar current (ACC) is an ocean current that flows from west to east around Antarctica, estimated to be over 100 times larger than the waters flowing in the world's rivers.It connects waters of the atlantic, indian and pacific oceans. The current flow is more is several circular fronts extending from the surface of the sea to the sea floor. It transports and store heat a characteristics that majorly influence both world and regional climate.

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Answer:

Let the mass of an object starting from rest be m and the velocity with which it travels be v

Kinetic energy of the object will be K.E = mv^2/2

If the object's velocity increases/decreases then kinetic energy would be K.E = m(v^2-u^2)/2 where u is the initial velocity and v is the final velocity

Hope this helps!

The balanced chemical reaction is

2K + 2H2O--- H2 + 2KOH

A chemical equation is described as the symbolic representation of a chemical reaction in the form of symbols and chemical formulas.

From the example, if we follow the stoichiometry of the reaction , 2 moles of potassium metal reacts with 2 moles of water to give 1 mole of hydrogen gas and 2 mole potassium hydroxide.

The chemical equation is very important as it tells us about the reacting species and resulting product.

The coefficient of the reacting species and resulting products gives information about the mole ratio or molecular ratio of the elements or compounds in the reaction.

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Answer: kinetic energy only

Explanation: kinetic energy only since it's moving

The mass of the iceberg is 71.9 kg

Explanation:

The amount of thermal energy needed to completely melt a substance at its melting point is given by

[tex]Q=\lambda m[/tex]

where

[tex]\lambda[/tex] is the latent heat of fusion

m is the mass of the substance

In this problem, we have a block of ice at its melting point (zero degrees). The amount of heat given to the block is

[tex]Q=2.40\cdot 10^7 J[/tex]

And the latent heat of fusion of ice is

[tex]\lambda = 334 J/g[/tex]

So, we can re-arrange the equation to find m, the amount of ice that will melt:

[tex]m=\frac{Q}{\lambda}=\frac{2.40\cdot 10^7}{334}=71856 g = 71.9 kg[/tex]

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Answer:

600J

Explanation:

work done=newtons×distance

Impulse equals change in momentum.

Answer: Option 2

Explanation:

Option 1 is wrong because there are 2 protons and 2 neutrons in nucleus.

Option 3 is wrong because there are two electrons moving around nucleus.

Option 4 is wrong because electrons are negatively charged and are moving around the nucleus.

Option 5 is wrong because there equal amount of protons and electrons with 2 each.

Explanation:

The 11Ω, 22Ω, and 33Ω resistors are in parallel.  That combination is in series with the 4Ω and 10Ω resistors.

The net resistance is:

R = 4Ω + 10Ω + 1/(1/11Ω + 1/22Ω + 1/33Ω)

R = 20Ω

Using Ohm's law, we can find the current going through the 4Ω and 10Ω resistors:

V = IR

120 V = I (20Ω)

I = 6 A

So the voltage drops are:

V = (4Ω) (6A) = 24 V

V = (10Ω) (6A) = 60 V

That means the voltage drop across the 11Ω, 22Ω, and 33Ω resistors is:

V = 120 V − 24 V − 60 V

V = 36 V

So the currents are:

I = 36 V / 11 Ω = 3.27 A

I = 36 V / 22 Ω = 1.64 A

I = 36 V / 33 Ω = 1.09 A

If we wanted to, we could also show this using Kirchhoff's laws.

The number of electrons attached to your t-shirt is 1442.

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge (commonly carried by protons and electrons respectively).

Unlike charges attract one another while like charges repel one another. Neutral refers to an object that carries no net charge.

Let the total number of electrons is = n.

Total number of proton is = 2850 - n.

Then, total charge on the t-shirt = ( n - (2850- n) ×(-1.6×10⁻¹⁹) C.

= (2n - 2850) ×(-1.6×10⁻¹⁹) C.

So,

(2n - 2850) ×(-1.6×10⁻¹⁹) C = − 5.50×10⁻¹⁸

(2n - 2850) = 34

2n = 2884

n = 1442

Hence, The number of electrons attached to your t-shirt is 1442.

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Final answer:

The number of electrons attached to your t-shirt is 34.

Explanation:

To determine the number of electrons attached to your t-shirt, we need to consider the net charge of the t-shirt and the charge of an electron. The net charge of your t-shirt is −5.50 × 10-18 C. The charge on an electron is -1.6022 × 10-19 C. To find the number of electrons, we divide the net charge of the t-shirt by the charge per electron:

Number of electrons = Net charge / Charge per electron

Number of electrons = -5.50 × 10-18 C / -1.6022 × 10-19 C = 34.28

Since we cannot have a fraction of an electron, the number of electrons attached to your t-shirt is 34.

The average acceleration during this time interval is [tex]-2.67 \mathrm{m} / \mathrm{s}^{2}[/tex]

Explanation:

Average acceleration can be measured as the ratio of change in speed to change in time. As the initial speed at initial time is 30 m/s at t = 0 and then at t = 6 s, the speed is decreased to 14 m/s. Then the average acceleration will be

[tex]Average acceleration =\frac{14-30}{6-0} =-2.67m/s^{2}[/tex]

So the average acceleration is negative which indicates that there is deceleration occurrence in the system.

Work in general  =  (force) x (distance)

Work to lift a weight = (weight of the weight) x (distance lifted)

1500 J = (500 N) x (height)

Divide each side by  500 N :

Height = (1500 J) / (500 N)

Height = 3 meters

Final answer:

Using the work-energy principle, the 500 N weight was raised to a height of 3 meters with 1500 Joules of work done.

Explanation:

To determine how high the 500 N weight was raised using 1500 Joules of work, we can use the work-energy principle, which states that work done (W) is equal to the change in potential energy (PE).

The formula for work when lifting an object vertically is:

W = F × d, where:

W is the work done in joules (J),

F is the force in newtons (N),

d is the distance in meters (m).

Here, we are given that a 500 N weight is lifted, and we have the amount of work 1500 J. We can rearrange the formula to solve for distance (d):

d = W / F

Substituting the given values, we get:

d = 1500 J / 500 N = 3 meters

Therefore, the weight was raised up to 3 meters high as a result of the 1500 J of work.

Answer:

Force = [tex]4.16\times 10^{29}\ N[/tex]

Explanation:

Given:

Mass of Sun (M) = [tex]1.99\times 10^{30}\ kg[/tex]

mass of Jupiter (m) = [tex]7.79\times 10^8\ kg[/tex]

Distance between Sun and Jupiter (d) = [tex]1.90\times 10^{27}\ kg[/tex]

The gravitational force between the two is given as:

[tex]F_g=\frac{GMm}{d^2}[/tex]

Where, [tex]G=6.674\times 10^{-11}\ m^3 kg^{-1} s^{-2}[/tex]

Now, plug in all the given values and solve for [tex]F_g[/tex]. This gives,

[tex]F_g=\frac{6.674\times 10^{-11}\times 1.99\times 10^{30}\times1.90\times 10^{27} }{(7.79\times 10^8)^2}\\\\F_g=4.16\times 10^{29}\ N[/tex]

Therefore, the gravitational force between the Sun and Jupiter to three significant figures is [tex]4.16\times 10^{29}\ N[/tex]

Answer:

C. 4.16

Explanation:

Right on ED2021

The acceleration of snow is 32 m/[tex]s^{2}[/tex].

Explanation:

According to Newton's second law of motion, the force acting on any object is directly proportional to the product of mass and acceleration acting on the object.

So if the object is a snowblower driver with mass 1250 kg and the force acting on it is 40000 N, then the acceleration of the snow can be determined from the ratio of force to mass.

Force = Mass × Acceleration

Acceleration = [tex]\frac{Force}{Mass}[/tex] = [tex]\frac{40000}{1250}=32 m/s^{2}[/tex]

Thus, the acceleration of the snow is 32 m/[tex]s^{2}[/tex].

The angular momentum is 89.6 kg-m^2/s.

The angular velocity is 9.142 rad/s.

Explanation:

Momentum is the product of rotational inertia to the angular velocity.

Angular momentum = m *v = 5.6 * 16 = 89.6 kg-m^2 / s.

Angular velocity is the rate of velocity at which an object is rotating around a center or a specific point in a given time period. It is also known as rotational velocity. Angular velocity is measured in radian per second (rad/s).

angular velocity = angular momentum / rotational inertia

                          = 89.6 / 9.8 = 9.142 rad / s.

Answer:

The height of bridge is [tex]17\ m[/tex]

Explanation:

Given the time taken to reach the ground is [tex]3.4\ second[/tex]

And acceleration of gravity [tex]10\ m/s^2[/tex]

Also the initial velocity of the object [tex]u=0\ m/s[/tex]

The object is falling under the condition of free fall.

So, we can use the following formula for computing the distance when the object is under free fall.

Where [tex]S[/tex] is the height, [tex]t[/tex] is time of fall, and [tex]g[/tex] is acceleration of gravity.

[tex]S=\frac{gt^2}{2}\\\\S=\frac{10\times3.4}{2}\\S=17\ m[/tex]

The height of the bridge is calculated to be 57.8 meters considering the object takes 3.4 seconds to reach the ground when dropped from rest.

To calculate the height of the bridge from which an object is dropped and takes 3.4 seconds to reach the ground, we can use the formula for the distance covered under acceleration due to gravity:

[tex]s = ut + \frac{1}{2} at^2[/tex]

where:
s = distance (height of the bridge in this case)
u = initial velocity (0 m/s, since the object is dropped)
a = acceleration due to gravity (10 m/s^2)
t = time taken to reach the ground (3.4 seconds)

Now, substituting the known values:

s = 5 * 11.56
s = 57.8 meters

Therefore, the height of the bridge is 57.8 meters.

Answer:

number 1 is that the bowling ball has more gravitational potential energy as it sits on top of the building.

Answer:

#2 would be : The bowling ball now has more kinetic energy because it is moving and picking up speed. The potential energy has already been wasted because it has been used as the ball falls.

:)

Answer: 125 m

Explanation:

This problem is related to vertical motion and can be solved with the following equation:

[tex]y-y_{o}=V_{o}t-\frac{1}{2}gt^{2}[/tex] (1)

Where:

[tex]y-y_{o}=\Delta y[/tex] is the difference between the final height [tex]y[/tex] and initial height [tex]y_{o}[/tex]. Let's take into account the initial height is greater than the final height, since the skydiver is descending.

[tex]V_{o}=0 m/s[/tex] Is the skydiver's initial velocity, assuming the plane was not moving at that moment

[tex]t=5 s[/tex] is the time

[tex]g=10 m/s^{2}[/tex] is the acceleration due gravity

Solving the equation:

[tex]\Delta y=-\frac{1}{2}gt^{2}[/tex] (2)

[tex]\Delta y=-\frac{1}{2}(10 m/s^{2})(5 s)^{2}[/tex] (3)

[tex]\Delta y=-125 m[/tex] (4) Here, the negative sign only indicates the position of the skydiver, and remember the initial height is greater than the final height.

In fact, the distance is positive: 125 m

Answer:

I will say that the the potential energy will be at its maximum.

Explanation:

potential energy deals with gravity and gravity deals with height, so when a object is in its maximum height it will have the maximum potential energy.  

Answer:

76200

Explanation:

Answer:

1750 kgm/s

Explanation:

The equation for momentum is p = mv = 70 * 25 = 1750.

The momentum of the bicyclist with the given value of mass travelling at the given velocity is 1750kgm/s.

Momentum is simply the product of the mass of an object and its velocity.

Its is expressed as;

P = m × v

Where m is the mass of the object and v is its velocity.

Given the data in the question;

We substitute the given values into the expression above.

P = m × v

P = 70kg × 25m/s

P = 1750kgm/s

Therefore, the momentum of the bicyclist with the given value of mass travelling at the given velocity is 1750kgm/s.

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