sample of pure water has a hydronium concentration of 1.0 × 10-7 M. What is the pH of the water?

Answers

Answer 1

Answer:

The pH of the water is 7.

Explanation:

The pH of the solution is defined as negative logarithm of H^+ or hydronium ions ions in the solution.

pH=-\log[H^+]

So, H^+ concentration of water = 1.0\times 10^{-7} m

pH=-\log[1.0\times 10^{-7}]=7

The pH of the water is 7.

Answer 2

The pH of pure water with a hydronium concentration of 1.0 × 10⁻⁷ M is 7, indicating that the water is neutral.

The pH of a solution is a measure of its acidity or alkalinity. In the given sample of pure water with a hydronium ion concentration of 1.0×10⁻⁷ M, we calculate the pH by taking the negative logarithm of the hydrogen ion concentration, which here is -(-7), giving us a pH of 7. This pH value indicates that the solution is neutral, since pure water has a pH of 7 at 25 °C.


Related Questions

How much current will flow through a 470-Ohm resistor if a 9-volt battery is used?

Answers

Answer:

For a 470-Ohm resistor connected to a 9-votl battery the current that will flow is 0.019A or 19mA

Explanation:

Ohm's law states that the voltage v along a resistor is directly proportional to the current i flowing through the resistor.

[tex]v = i R[/tex]

Clear i from the equation above

[tex]i = \frac{v}{R}[/tex]

[tex]i = \frac{9volt}{470ohm} =0.019A[/tex]

Final answer:

The current flowing through a 470-Ohm resistor with a 9-volt battery is approximately 0.0191 Amperes.

Explanation:

In order to determine the current flowing through a resistor, we can use Ohm's Law, which relates voltage, current, and resistance. Ohm's Law states that current (I) is equal to the voltage (V) divided by the resistance (R). So, in this case, we can calculate the current flowing through a 470-Ohm resistor with a 9-volt battery using the formula:

I = V / R

Substituting the given values, we have:

I = 9 V / 470 Ohm

Simplifying the expression gives us the current:

I ≈ 0.0191 A

Therefore, approximately 0.0191 Amperes (or 19.1 milliamperes) of current will flow through the 470-Ohm resistor when a 9-volt battery is used.

Learn more about Current flow through a resistor here:

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A little bumblebee accelerates uniformly at 1.5 m/s² from rest to 22 m/s. Immediately upon reaching 22m/s, the brakes are applied, and it stops 2.5 s later. Find the total distance traveled.

Answers

Answer:

190 m

Explanation:

Displacement during acceleration:

v² = v₀² + 2a(x - x₀)

(22 m/s)² = (0 m/s)² + 2(1.5 m/s²)(x - 0 m)

x = 161.333 m

Displacement after deceleration:

x = x₀ + ½ (v + v₀)t

x = 161.333 m + ½ (0 m/s + 22 m/s)(2.5 s)

x = 188.833

Rounded to 2 sig-figs, the bumblebee travels a distance of 190 m.

A brick has a greater mass than a sponge has. Why is the acceleration due to gravity the same for both objects?​

Answers

Answer:Gravity

Explanation: all objects fall at the same time no matter the weight or size

The only thing that would change the time of falling of said object is if the object has greater air resistance like a feather

All objects accelerate at the same rate due to gravity (9.8 m/s^2) because of the equivalence principle, which states that inertial mass and gravitational mass are equal, causing a balance between the gravitational force and inertia.

The acceleration due to gravity is the same for all objects, regardless of their mass, because gravity affects all objects equally. This is a result of what is known as the equivalence principle, which states that the inertial mass (resistance to acceleration) and the gravitational mass (how much force is exerted by gravity) of an object are equivalent. Therefore, when looking at the formula for force (¹Force equals mass times acceleration), a lighter object like a sponge and a heavier object like a brick, when dropped, will both experience the same acceleration of 9.8 m/s2 because the greater gravitational force on the brick is exactly balanced by its greater inertia. This phenomenon dismisses the mass of Earth in calculations as it is significantly larger than that of the objects.

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