Answer:
The rate the swimming pool is filled is 9 gallons of water per minute
Step-by-step explanation:
Let's review the information provided by Ronald to us to help him to find the answer to the question:
Time it takes to fill the swimming pool = 8 minutes
Amount of water the swimming pool can hold = 72 gallons
2. At what rate does the swimming pool fill, in gallons per minute?
Rate the swimming pool is filled = Amount of water the swimming pool can hold /Time it takes to fill the swimming pool
Replacing with the real values, we have:
Rate the swimming pool is filled = 72/8 = 9 gallons of water per minute
Summit learning A Circumference of 44 (7.3.B.8.5) Illustrative Mathematics 8.5: A Circumference of 44 A circle's circumference is approximately 44 cm. Complete each statement using one of these values: 7, 11, 14, 22, 88, 138, 154, 196, 380, 616. The circle's diameter is approximately ________ cm. The circle's radius is approximately ________ cm. The circle's area is approximately ________ .
BRAINIEST TO FIRST CORRECT!
A triangular window broke in Natalia's barn. How large does the piece of glass need to be to replace the window?
Answer: OPTION A.
Step-by-step explanation:
By definition, the area of a triangle can be calculated with the following formula:
[tex]A=\frac{bh}{2}[/tex]
Where "A" is the area of the triangle, "b" is the base of the triangle and "h" is the height of the triangle.
In this case, you need to observe the triangular piece shown in the picture given in the exercise.
You can identify that the base and the height of the triangle are:
[tex]b=3.6\ ft\\\\h=4.8\ ft[/tex]
Therefore, you must substitute those values into the formula. Then:
[tex]A=\frac{(3.6\ ft)(4.8\ ft)}{2}[/tex]
Finally, you must evaluate in order to find the area of the triangle.
You get the following result:
[tex]A=\frac{17.28\ ft^2}{2}\\\\A=8.64\ ft^2[/tex]
When Quentin ordered a tennis racquet recently, he agreed to pay a 7% shipping and handling charge. If Quentin paid 9.45 in shipping and handling, how much must the racquet have cost?
Answer:
Racket must have cost 135.
Step-by-step explanation:
Given:
Percentile amount of shipping and handling charge = 7%
Actual amount of shipping and handling charge= 9.45
we need to find the Cost of racket.
Solution:
Let the cost of racket be 'x'.
Now we can say that:
Percentile amount of shipping and handling charge multiplied by cost of racket and then divided by 100 is equal to actual amount of shipping and handling charge.
framing in equation form we get;
[tex]\frac{7}{100}x=9.45[/tex]
Multiplying both side by [tex]\frac{100}{7}[/tex] we get;
[tex]\frac{7}{100}x\times \frac{100}{7}=9.45\times \frac{100}{7}\\\\x=135[/tex]
hence Racket must have cost 135.
Over the interval from 4 seconds to 10 seconds, the object's speed was calculated to be 3 m/s. What is the object's position after 8 seconds have elapsed.
Answer:
1 meter farther
Step-by-step explanation:
The difference in time from 4 seconds to 10 seconds is 6 seconds.
The speed is half of the difference of time.
That is why the speed is 3 m/s.
The difference in time from 10 to 18 is 8 seconds.
Take the time and divide it by 2 to get the speed.
The speed is 4 m/s.
The object's position is 1 more meter.
4 m/s - 3 m/s = 1 m/s
The object's position after 8 seconds is 24 m to have elapsed.
What is Division method?
Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications.
For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.
Given that;
Over the interval from 4 seconds to 10 seconds, the object's speed was calculated to be 3 m/s.
Now,
Since, Over the interval from 4 seconds to 10 seconds, the object's speed was calculated to be 3 m/s.
That is,
The speed = 3 m/s
Time = 10 - 4 = 6 seconds
So, The distance cover by object's in 6 seconds = 3 x 6
= 18 m
Hence, The object cover the distance in 8 seconds = 18 x 8 / 6
= 24 m
So, The object's position after 8 seconds is 24 m to have elapsed.
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A food truck operator is parked in a lot at the corner of two streets. She wants to be equidistant from both streets. Should she park her truck on a perpendicular bisector, an angle bisector, a median, or an altitude?a) perpendicular bisectorb) angle bisectorc) mediand) altitude
Answer:
Angle bisector
Step-by-step explanation:
median isn't applicable in this case as the roads from the streets are inclined at an angle.
altitude refers to height which is also not applicable
The perpendicular bisector is the locust of points equidistant from two points,
in this question the street are not seen as points but as lines which forms an angle and the bisection of this angle forms a locus where she can park her car. If she parks her car anywhere on the angular bisector of the two streets, she would be at equal distance from both streets.
If a rectangle has an area of 2x^2+7x+3 find the perimeter
Answer:
Perimeter of the rectangle=6x+8 square units
Step-by-step explanation:
Given that area of rectangle is [tex]2x^2+7x+3[/tex]
Area of rectangle=lw square units
[tex]2x^2+7x+3=2x^2+x+6x+3[/tex]
[tex]=x(2x+1)+3(2x+1)[/tex]
[tex]=(x+3)(2x+1)[/tex]
[tex]2x^2+7x+3=(x+3)(2x+1)[/tex]
Comparing the above equation with the given area we get
lw=(x+3)(2x+1)
Therefore length=x+3 and width=2x+1
To find the perimeter :
Perimeter of the rectangle=2(l+w) square units
[tex]=2((x+3)+(2x+1))[/tex]
[tex]=2(x+3+2x+1)[/tex]
[tex]=2(3x+4)[/tex]
[tex]=6x+8[/tex]
Therefore perimeter of the rectangle=6x+8 square units
A plane flies at x miles per hour in still air. Flying with a tailwind, its speed is 485 miles per hour. Against the wind, its air speed is only 445 miles per hour. What is the speed of the wind?
Answer:20mph
Step-by-step explanation:
speed of plane = x mph
Speed of plane with wind = 485 mph
So therefore, speed of wind =
485 - x
Speed of plane against wind = 445 mph
So therefore, speed of wind =
x - 445
So therefore, equating the 2 equations of speed of wind
485 - x = x - 445
Collect like terms
485 + 445 = x + x
930 = 2x
2x = 930
x = 930/2 = 465 mph
Speed of wind = x = 465mph
So we put this value on any of the equations for speed of wind
Speed of wind = x - 445 = 465 - 445
= 20 mph
So therefore, speed of wind = 20mph
A simple reflex requires the nervous system to perform three functions. Two of these functions are to collect and distribute information. What is the third function?
Answer:
Integrate information
Step-by-step explanation:
John wants to find the width of a canyon. He walks along the side for 75 ft and marks a point and then walks 16.5 ft and marks another point. Then he turns at a right angle away from the canyon and walks to a point that is in line with the first point marked and another point perpendicular across the canyon from the starting point.
A) Can he conclude the two triangles are similar? Why or why not?
B) if it was 24 ft that he walked for AB, can the canyon width be found? If so, find it and show all work.
Answer:
A) Yes , the triangles are similar as indicated and shown from the analysis of the diagram.
B) Yes, the canyon width AE can be found and it is calculated and gotten as 109.09ft
Step-by-step explanation:
Attached below is the step by step calculations and explanation of both answers.
According to postal regulations, the girth plus the length of a parcel sent by fourth-class mail may not exceed 108 in. What is the largest possible volume of a rectangular parcel with two square sides that can be sent by fourth-class mail?
Answer:
11,664 in³
Step-by-step explanation:
For a square side length of x, the girth is 4x and the length of the parcel is then allowed to be up to 108-4x.
The total volume is the product of the edge lengths, so is ...
V = (108 -4x)(x²) = -4x³ +108x²
This will be a maximum where its derivative is zero:
dV/dx = -12x² +216x = 0 = -12x(x -18)
This is zero for x=0 and for x=18.
The maximum volume parcel is 18 in by 18 in by 36 in, and has a volume of ...
(18 in)(18 in)(36 in) = 11,664 in³
To find the largest possible volume of a rectangular parcel with two square sides adhering to postal regulations, we use a derived formula V = x²(108 - 4x) and apply optimization to find the maximum volume.
To answer the question about the largest possible volume of a rectangular parcel with two square sides that can be sent by fourth-class mail, we use the given postal regulation that states the girth plus the length of a parcel may not exceed 108 inches. Assuming we have a box with dimensions x (for the length and width of the square sides) and y (for the length), the girth is calculated as 4x (since we have two square sides) and the total allowed measurement is 4x + y <= 108 inches. The volume V of the parcel is x²y.
First, we express y in terms of x: y = 108 - 4x. We can then rewrite the volume formula in terms of x: V = x²(108 - 4x). To maximize the volume, we take the derivative of V with respect to x and set it to zero: dV/dx = 2x(108 - 4x) - 4x². Solving for x, we find the critical points which will give us the value of x that maximizes the volume. Plugging this x value back into V or y = 108 - 4x, we can find the maximum volume and the dimensions of the parcel. Without explicitly solving the calculus problem, the general approach is to use optimization via calculus or other mathematical techniques to maximize the volume function.
On another map, the distance between Saugerties and Kingston is 2 inches. What would the distance form Saugerties to Catskill on the map be?
Missing Portion of actual question:
In actual question, the scale provided on the map is 1 inch = 2.5 miles. (Picture is attached)
Answer:
3 inch
Step-by-step explanation:
Part a):
Actual distance between Saugerties and Kingston is 10 miles (4*2.5) because in map distance is 4 inch while 1 inch is equivalent to 2.5 miles.
Part b):
Actual distance between Saugerties and Catskill is 15 miles hence on this map distance will be 6 inch (15/2.5) because 1 inch is equivalent to 2.5 miles.
Part c):
On another map where distance between Saugerties and Kingston is 2 inches (half of the one shown in the given map), the distance between Saugerties and Catskill will be 3 inches. As the map is scaled double than the map given in the question i.e. 1 inch = 5 miles.
Jonas is jogging from the Park to the school. He has jogged 0.424 miles so far. He has 0.384 mile left to jog. How far is the park located away from the school?
Answer:the park is located 0.808 miles away from the school
Step-by-step explanation:
Jonas is jogging from the Park to the school. The total number of miles that Jonas has jogged so far is 0.424.
He has 0.384 mile left to jog. This means that the distance of the park from the school would be the sum of the distance that he has jogged so far and the distance that he has left to jog. It becomes
0.424 + 0.384 = 0.808 miles
Ann had $198 more than her sister.After their mother gave Ann $20 and her sister $60,Ann had twice as much money as her sister.How much money did Ann have at first?
Answer:
Ann had $296 money at first.
Step-by-step explanation:
Let the money her sister have be 'x'.
Given:
Ann had $198 more than her sister.
So we can say that;
Money Ann had = [tex]x+198[/tex]
Now Given:
mother gave Ann $20 and her sister $60.
Now,
Money Ann had after mother gave her money = [tex]x+198+20 = x+218[/tex]
Money her sister had after mother gave her money = [tex]x+60[/tex]
Also given:
Ann had twice as much money as her sister.
So we can say that Money Ann had after mother gave her money is equal to 2 times Money her sister had after mother gave her money.
framing in equation form we get;
[tex]x+218=2(x+60)[/tex]
Applying Distributive property we get;
[tex]x+218=2x+120[/tex]
Combining like terms we get;
[tex]2x-x=218-120\\\\x = \$98[/tex]
Money sister had first = $98
Money Ann had first = [tex]x+198 = 98+198 = \$296[/tex]
Hence Ann had $296 money at first.
Ari and his 3 brothers want to take a school trip to Washington, D.C. They have $320 saved. Each of them will save $18 a week until they have at least $647 to pay for the trip. How much money will they save after 4 weeks? Will they have enough money to pay for the trip?
Ari and his 3 brothers do not have enough money to take a school trip to Washington, D.C. they are in short of $39.
What is the unitary method?The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
Given that, Ari and his 3 brothers want to take a school trip to Washington, D.C. They have $320 saved.
Ari and his 3 brothers
In total 4 of them saving $18 per week and they saved for 4 weeks
So, total money they saved
= 4×4×18
= $288
Total money they have =288+320
= $608
Difference in money
= 647-608
= $39
Hence, Ari and his 3 brothers do not have enough money to take a school trip to Washington, D.C. they are in short of $39.
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This month kami sold 70 figurines in 2 sizes. The large figurines sold for $12 each and the small figurines sold for $8 each. The amount of money he received from the sales of the large figurines was equal to the amount of money he received from the sales of the small figurines. How many large figurines did Kami sell?
Answer:Kami sold 28 large figurines.
Step-by-step explanation:
Let x represent the number of large figurines that Kami sold.
Let y represent the number of small figurines that Kami sold.
This month kami sold 70 figurines in 2 sizes. This means that
x + y = 70 - - - - - - - - - - 1
The large figurines sold for $12 each and the small figurines sold for $8 each. The amount of money he received from the sales of the large figurines was equal to the amount of money he received from the sales of the small figurines. This means that
12x = 8y
y = 12x/8
y = 1.5x
Substituting y = 1.5x into equation 1, it becomes
x + 1.5x = 70
2.5x = 70
x = 70/2.5 = 28
y = 1.5x = 1.5 × 28 = 42
There were 166 paid admissions to a game. The price was $2 for adults and $.75 for children. The amount of data taken in was $293.25 how many adults and how many children attended.
Answer:the number of adults that attended the game is 135.
the number of children that attended the game is 31
Step-by-step explanation:
Let x represent the number of adults that attended the game.
Let y represent the number of children that attended the game.
There were 166 paid admissions to a game. This means that
x + y = 166
The price was $2 for adults and $.75 for children. The amount of data taken in was $293.25. This means that
2x + 0.75y = 293.25 - - - - - - - - - - 1
Substituting x = 166 - y into equation 1, it becomes
2(166 - y) + 0.75y = 293.25
332 - 2y + 0.75y = 293.25
- 2y + 0.75y = 293.25 - 332
- 1.25y = - 38.75
y = - 38.75/- 1.25
y = 31
x = 166 - y = x = 166 - 31
x = 135
A cone has a diameter of 3 inches. The cone holds 12 cubic inches of water.
To the nearest inch what is the height of the car?
Answer:
The height of the cone is 5.09 inches
Step-by-step explanation:
Given:
The volume of the cone = 12 cubic inches
The diameter of the cone = 3 inches
To Find :
The height of the cone = ?
Solution:
We know that the volume of the cone is
Volume = [tex]\pi r^2\frac{h}{3}[/tex]
where
r is the radius of the cone
h is the height of the cone
Now substituting the given values
[tex]12 = \pi (1.5)^2 \frac{ h }{3}[/tex]
[tex]\frac{12}{\pi 2.25} = \frac{h}{3}[/tex]
[tex]h = \frac{12}{ 2.25 \pi} \times 3[/tex]
[tex]h = \frac{ 12}{7.065} \times 3[/tex]
[tex]h = 1.698 \times 3[/tex]
h = 5.09 inches
During a typical evening, a pizzeria receives phone orders for pizza delivery at a constant rate: 18 orders in a typical 4 minute period. How many pies are sold in 4 hours?
_______pies
Assume the pizzeria starts taking orders at 4:00 PM and the profit is a constant rate of $11 on 10 orders. When will phone order profit exceed $1,000? (Round your answer to the nearest minute.)
: PM
Answer:
1080 orders is made after 4hours
When profit exceeds $1000, the time will be 7:22 PM
Step-by-step explanation:
1. Let No of order be O and time be T
O ∝ T
O = KT
K = O ÷ T
K = 18 ÷ 4 = 4.5
Total no of orders in 4hrs (240min) will be
O = 4.5 × 240 = 1080 orders
2. Total orders made from profit of $1000 is evaluated.
10 orders give $11
x orders will give 909.09091 orders
time required to reach 909.09091 orders is then evaluated
1080 orders is placed in 4hrs
909.09091 orders will be placed in x hours
upon cross multiplication
x = 3.3670034 hours which is equivalent to 202.020202 minutes
When that's added to 4:00 PM, the answer is 7:22PM minutes to the nearest minute.
1080 pies are sold in 4 hours based on their order rate, and the phone order profit will exceed $1,000 around 7:22 PM, assuming a constant profit rate.
The student asked two questions related to pizza orders.
Firstly, they wanted to know how many pies are sold in 4 hours based on a constant rate of 18 orders in a 4-minute period.
Secondly, they asked when phone order profit would exceed $1,000 assuming a profit of $11 on 10 orders.
Calculating Pies Sold in 4 Hours
To calculate the number of pies sold in 4 hours (240 minutes) when 18 orders are received every 4 minutes, we need to determine how many 4-minute periods are in 240 minutes.
This is 240 minutes / 4 minutes = 60 periods.
Since 18 orders are received per period, the total number of pies sold is 18 orders × 60 periods = 1080 pies.
Calculating When Phone Order Profit Exceeds $1,000
To calculate when the profit exceeds $1,000, note that for every 10 orders, a profit of $11 is made.
First, calculate the total number of orders needed to exceed $1,000 profit.
Given: $1,000 / $11 = approximately 91 sets of 10 orders.
Therefore, total orders needed = 91 sets × 10
= 910 orders.
Since 18 orders are taken every 4 minutes, we find the total time by dividing 910 orders by the rate of 4.5 orders per minute (18 orders / 4 minutes).
This gives approximately 202.2 minutes from the start time (4:00 PM), which rounds to 7:22 PM when the profit exceeds $1,000.
HELP! What does X equal? WILL GIVE BRAINLIEST!
Need help with special right triangles
Step-by-step explanation:
For solving this, it's important to know basic trigonometric functions:
sin = opposite side / hypotenuse
cos = adjacent side / hypotenuse
tan = opposite side / adjacent side
It's also important to know that it is necessary to know their values for special right triangles and angles of 30°, 45° and 60°
1. We are given angle if 45° and its adjacent side of 13. We want to know the opposite side (x) and hypotenuse (y). So:
tan = opposite side / adjacent side
tan 45 = x / 13
1 = x / 13
x = 13
Remember that tangent of 45° angle is 1.
We found the opposite side to be also 13.
To find y we can use:
sin = opposite side / hypotenuse
sin 45 = 13 / y
(√2)/2 = 13 / y
y = 13√2
Important to remember, sin 45 and cos 45 are (√2)/2
2. We are given 45° angle and hypotenuse of 30. We need to find opposite side (x) and adjacent side (y).
sin = opposite side / hypotenuse
sin 45 = x / 30
(√2)/2 = x / 30
x = 15√2
Also:
cos = adjacent side / hypotenuse
cos 45 = y / 30
(√2)/2 = y / 30
y = 15√2
We can conclude that in the right triangle, when angle is 45°, opposite and adjacent sides are equal.
3. We are given angle of 60° and adjacent side of 3. We need to find opposite side (y) and hypotenuse (x).
cos = adjacent side / hypotenuse
cos 60° = 3 / x
1/2 = 3 / x
x = 6
Note that cos 60° equals 1/2.
sin = opposite side / hypotenuse
sin 60° = y / 6
(√3)/2 = y / 6
y = 3√3
Note that sin 60° equals (√3)/2.
4. We are given angle of 30° and hypotenuse of 34. We need to find opposite side (y) and adjacent side (x).
sin = opposite side / hypotenuse
sin 30° = y / 34
1/2 = y / 34
y = 17
Note that sin 30° equals to cos 60° equals 1/2.
cos = adjacent side / hypotenuse
cos 30° = x / 34
(√3)/2 = x / 34
x = 17√3
Remember that cos 30° equals to sin 60° which is (√3)/2.
5. We are given an angle of 45° and hypotenuse of 10√2. We need to find the opposite side (y) and adjacent side (x).
sin = opposite side / hypotenuse
sin 45° = y / 10√2
(√2)/2 = y / 10√2
y = 10
To save time, we already said that opposite and adjacent sides are equal in right triangle with 45° angle, so x = y = 10.
6. We are given angle of 60° and opposite side of 25√3. We need to find adjacent side (y) and hypotenuse (x).
sin = opposite side / hypotenuse
sin 60° = 25√3 / x
(√3)/2 = 25√3 / x
x = 50.
tan = opposite side / adjacent side
tan 60° = 25√3 / y
√3 = 25√3 / y
y = 25.
Remember that tangent of 60° angle is √3.
7. We are given angle of 45° and hypotenuse of 2√14. We need to find adjacent side (x) and opposite side (y).
cos = adjacent side / hypotenuse
cos 45° = x / 2√14
(√2)/2 = x / 2√14
x = √28
Again, adjacent and opposite sides are equal in 45° right triangle, so x = y = √28.
8. We are given an angle of 30° and an adjacent side of 24. We need to find the opposite side (y) and hypotenuse (x).
tan = opposite side / adjacent side
tan 30° = y / 24
(√3)/3 = y / 24
y = 8√3
sin = opposite side / hypotenuse
sin 30° = 8√3 / x
1/2 = 8√3 / x
x = 16√3
Note that tan = sin/cos, so tan 30° = sin 30° / cos 30°
tan 30° = 1/2 / (√3)/2 = (√3)/3
I'm showing you this, so you don't have to memorize tan for special angles, you can find it from sin and cos.
9. We are given an angle of 60° and hypotenuse of 22√3. We need to find the opposite side (y) and adjacent side (x).
sin = opposite side / hypotenuse
sin 60° = y / 22√3
(√3)/2 = y / 22√3
y = 33
cos = adjacent side / hypotenuse
cos 60° = x / 22√3
1/2 = x / 22√3
x = 11√3
10. We are given an angle of 30° and the opposite side of √6. We need to find the adjacent side (x) and hypotenuse (y).
sin = opposite side / hypotenuse
sin 30° = √6 / y
1/2 = √6 / y
y = 2√6
tan = opposite side / adjacent side
tan 30° = √6 / x
(√3)/3 = √6 / x
x = √18
11. We are given an angle of 45° and an adjacent side of √10. We need to find the opposite side (x) and hypotenuse (y).
In this triangle opposite and adjacent sides are equal (45° angle), so x = √10
sin = opposite side / hypotenuse
sin 45° = √10 / y
(√2)/2 = √10 / y
y = √20 = 2√5
12. We are given an angle of 60° and the opposite side of 4√21. We need to find the adjacent side (x) and hypotenuse (y).
sin = opposite side / hypotenuse
sin 60° = 4√21 / y
(√3)/2 = 4√21 / y
y = 8√7
tan = opposite side / adjacent side
tan 60° = 4√21 / x
√3 = 4√21 / x
x = 4√7
13. Now things get a little trickier. We are given an angle of 30° and the opposite side of 17. We need to find the adjacent side (x).
Note that, at the moment, we are only dealing with this smaller triangle.
tan = opposite side / adjacent side
tan 30° = 17 / x
(√3)/3 = 17 / x
x = 17√3
Now, note that hypotenuse of the smaller triangle is the same length as the side z (adjacent and opposite side of 45° angle)
With Pythagorean theorem, we can find the hypotenuse of the smaller triangle, which equals to z.
z = √(17^2 + (17√3)^2)
z = 34
And now, finally to find y (hypotenuse of bigger triangle). We are given 45° angle and adjacent side z (34).
cos = adjacent side / hypotenuse
cos 45° = 34 / y
(√2)/2 = 34 / y
y = 34√2
14. Photo added
Correct responses;
x = 13, y = 13·√2x = 15·√2, y = 15·√2x = 6, y = 3·√3x = 17·√3, y = 17x = 10, y = 10x = 50, y = 25x = 2·√17, y = 2·√17x = 16·√3, y = 8·√3x = 33, y = 11·√3x = 3·√2, y = 2·√6x = √10, y = 2·√5x = 4·√7, y = 8·√7x = 17·√3, y = 34·√2, z = 34x = 18·√3, y = 18, z = 9Methods used for finding the above valuesSolutions:
1. An acute angle of the right triangle is 45°, therefore, the triangle is an isosceles triangle, and the leg lengths are equal.
Therefore;
x = 13The length of the hypotenuse side of an isosceles right triangle = A leg length × √2
Therefore;
The length of the hypotenuse side, y = 13·√22. An interior angle of the triangle = 45°
Therefore;
x = y
30 = x·√2
Which gives;
[tex]x = \dfrac{30}{\sqrt{2} } = \dfrac{30 \cdot \sqrt{2} }{2} = \mathbf{15 \cdot \sqrt{2}} = y[/tex]
x = y = 15·√23. The interior angle adjacent to the leg of length 3 = 60°
Therefore;
The hypotenuse side, x = 2 × adjacent leg length
Which gives;
x = 2 × 3 = 6In a right triangle having an interior angle of 60°, we have;
2 × Opposite leg length = √3 × The length of the hypotenuse
Therefore;
2 × y = √3 × x
Which gives;
2 × y = √3 × 6
y = 3·√34. The leg lengths are, x and y
An interior angle opposite to the leg length y is 30°
The hypotenuse side = 34
The length of the hypotenuse side = 2 × The leg length opposite the 30° angle
Therefore;
34 = 2 × y
[tex]y = \dfrac{34}{2} = \mathbf{17}[/tex]
y = 17The leg with length x is adjacent to the 30° angle, which gives;
2·x = √3 × 34
x = 17·√35. An acute interior angle is 45°
Therefore, the relationship are;
x = y
x·√2 = 10·√2
Which gives;
x = 10 = y6. An acute interior angle is 60°, which in relation to the position of the sides gives;
x·√3 = 2 × 25·√3
Therefore;
x = 2 × 25 = 50
x = 50
y = x ÷ 2
Therefore;
y = 50 ÷ 2 = 25
y = 257. An acute interior angle is 45°, which gives;
x·√2 = 2·√14
[tex]x = \dfrac{2 \cdot \sqrt{14} }{\sqrt{2} } = \sqrt{2} \times \sqrt{14} = \sqrt{28} = 2 \cdot \sqrt{7} [/tex]
x = 2·√7y = 2·√78. An interior angle is 30°
With regards to the location of the variables, we have;
2 × 24 = x·√3
Therefore;
x = 16·√32·y = x
Therefore;
[tex]y = \dfrac{x}{2} [/tex]
Which gives;
[tex]y = \dfrac{16 \cdot \sqrt{2} }{2} = \mathbf{8 \cdot \sqrt{2} }[/tex]
y = 8·√29. An interior angle is 60°, which gives;
[tex]y = \dfrac{22 \cdot \sqrt{3} }{2} = 11 \cdot \sqrt{3} [/tex]
y = 11·√3√3 × 22·√3 = 2 × x
x = 11·√3 × √3 = 33
x = 3310. An angle of the right triangle is 30°
With respect to the location of the variables, we have;
y = 2 × √6 = 2·√6
y = 2·√6y·√3 = 2 × x
Therefore;
2·√6 × √3 = 2 × x
x = √(18) = 3·√2
x = 3·√211. Right triangle with a 45° interior angle
x = [tex]\underline{\sqrt{10} }[/tex]y = √(10) × √2 = √(20) = 2·√5
y = 2·√512. Interior angle of the right triangle is 60°
y·√3 = 2 × 4·√(21) = 8 × √7 × √3
y = 8·√7[tex]x = \dfrac{y}{2} [/tex]
Therefore;
[tex]x = \dfrac{8 \cdot \sqrt{7} }{2} = \mathbf{ 4 \cdot \sqrt{7} }[/tex]
x = 4·√713. The ratio of the adjacent leg to the opposite leg to the 30° angle is √3, therefore;
x = 17·√3The hypotenuse side = 2 × 17 = 34
The hypotenuse side of the right triangle having a 30° angle is a leg in
the right triangle that has the 45° angle, therefore;
z = 34y = 34·√214. In the 60° right triangle, we have;
x·√3 = 2 × 27 = 54 = 18 × 3
x = 18·√3[tex]Length \ of \ the \ common \ side = \dfrac{x}{2} [/tex]
Which gives;
[tex]Length \ of \ the \ common \ side = \dfrac{18 \cdot \sqrt{3} }{2} = 9 \cdot \sqrt{3} [/tex]
Length of the common side = 9·√3
In the 30° right triangle, we have;
x·√3 = 9·√3
Therefore;
z = 9y = 2·x
Therefore;
y = 2 × 9 = 18Learn more about special right triangles here:
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The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radius of the sphere is 3m?
The rate at which the surface area of the sphere is increasing can be found using related rates in calculus. By differentiating the volume formula with respect to time, we relate the rates of change for the radius and surface area, and then plug in the given volume increase rate when the radius is 3m.
Explanation:The problem requires the application of related rates in calculus to find the rate at which the surface area of a sphere is increasing. To calculate this, we can use the formula for the volume of a sphere, which is V = \frac{4}{3}\pi r^3, and the formula for the surface area, which is S = 4\pi r^2. Given a rate of volume increase, \frac{dV}{dt} = 10 m^3/sec, we can differentiate the volume with respect to time to find the relationship between the rates of change of the radius and volume. Then we use the rate of change of the radius to find the rate of change of the surface area.
Step 1: Differentiate the volume with respect to time.
\frac{dV}{dt} = 4\pi r^2 \frac{dr}{dt}
Step 2: Solve for \frac{dr}{dt} when the radius is 3m.
Step 3: Use the value of \frac{dr}{dt} to find \frac{dS}{dt} (the rate of surface area increase).
Step 4: \frac{dS}{dt} = 8\pi r \frac{dr}{dt}
A volleyball reaches its maximum of 13 feet, 3 seconds after it is served. What quadratic formula could model the height of the volleyball over time after it is served.
Answer:
[tex]H=-(t-3)^2+13[/tex]
Step-by-step explanation:
The path covered by the volleyball will be a downward parabola with the vertex being the highest point of the ball.
A general form of a downward parabola is given as:
[tex]y=-a(x-h)^2+k[/tex]
Where [tex](h,k)[/tex] is the vertex of the parabola and 'a' is a constant.
Now, let 'h' be the vertical height and 't' be the time taken.
So, the equation would be of the form:
[tex]H=-a(t-h)^2+k[/tex]
Now, as per question:
h = 2 seconds, k = 13 feet.
[tex]H=-a(t-3)^2+13[/tex]
Now, taking a = 1. So, the formula that can be used is:
[tex]H=-(t-3)^2+13[/tex]
For a boat to float in a tidal bay, the water must be at least 2.5 meters deep. The depth of water around the boat, ????(????), in meters, where ???? is measured in hours since midnight, is____________.
Final answer:
The depth of water around the boat, d(t), varies based on the tidal patterns. Tides are influenced by various factors including the moon's gravity, ocean depth, and local geography. Accurate prediction requires tidal charts and local data.
Explanation:
The depth of water around the boat, represented as d(t), varies based on time due to the tidal patterns. The tides are influenced by numerous factors such as the alignment and gravitational pull of the moon and sun, the depth of the ocean, and local geographical features like bays and estuaries. In the case of the Bay of Fundy, the tides can have an exceptionally large range due to its shape and the resonance of the tidal forces.
The frequency and height of tides will determine how often and to what extent the water level rises and falls, thus affecting the depth at any given hour. To forecast these tidal levels and ensure safe boating conditions, experts create tidal charts with high accuracy, taking into account local bathymetry and global tidal patterns. However, the actual mathematical representation of d(t) would require access to these local tidal patterns and data from the mentioned charts or measurement systems to create a function that accurately represents the changing water depth around the boat.
What does the computer do when it executes the following statement: x = y + 5 A. retrieves the value of y B. calculates the total of 5 and the value of y C. stores the result of the calculation in the variable x D. all of the above
Answer:
D. all of the above
Step-by-step explanation:
In a programming software, depending on the type of input or coding given, the software application has the power to executes the following statement:
when the coding/input state x = y + 5
the computer will
A. retrieves the value of y (the value of y will have been stated earlier)
B. calculates the total of 5 and the value of y (sum the value of y with 5)
C. stores the result of the calculation in the variable x (store the result of value of x in case if it is been call for again, or store nit until a new value is gotten for x)
them, the computer can either print out the result of xor wait for the next action.
the correct option for this question is D. all of the above
If A = {x | x is an even integer}, B = {x | x is an odd integer}, C = {2, 3, 4, 5}, and D = {9, 10, 11, 12}, list the element(s) of the following set.
C ∪ D = _________.
Final answer:
To find the union of sets C and D, you combine the elements of both sets without repeating any elements. The union, C ∪ D, is therefore {2, 3, 4, 5, 9, 10, 11, 12}.
Explanation:
The question asks to list the elements of the set that is the union of two sets C and D. The union of two sets contains all the elements that are in either set. Therefore, C ∪ D is the set that includes all the elements from both sets C and D without duplication.
Set C contains the integers {2, 3, 4, 5} and set D contains the integers {9, 10, 11, 12}. Hence, the union of sets C and D, denoted C ∪ D, would be {2, 3, 4, 5, 9, 10, 11, 12}. This combines all the unique elements from both sets.
The demand function for a product is given by p = −0.05x2− 0.3x + 8 where p is the unit price in dollars and x is the weekly demand for the product each week, measured in thousands of units. Find the consumer’s surplus if the market price for the product is $5.
Answer:
The answer is 5300 units.
Step-by-step explanation:
The equation will be exactly lie below if the price is 5$:
[tex]5=-0.05x^2-0.3x + 8\\0=-0.05x^2-0.3x+3[/tex]
Roots of the parabol will be:
[tex]x_{1}=-11.3\\x_{2}=5.3[/tex]
In fact that there will be no negative production, The consumer surplus will be 5300 units
The Department of Education wishes to estimate the proportion of all college students who have a job off-campus. It surveyed 1600 randomly selected students, 451 had such jobs. The population of interest to the Department of education is: 1. All 1600 students surveyed 2. All college students o some of college students who have off-campus jobs 3. All college students who have off-campus jobs 4. The 451 students in the survey who had off-campus jobs
Answer: 2. All college students
Step-by-step explanation:
A population is a large group of individuals that have some common feature by the researcher's point of interest.
Herero , the Department of Education wishes to estimate the proportion of all college students who have a job off-campus.
So , he need data of all students to compute the exact proportion.
But instead of that he surveyed 1600 randomly selected students which determine the sample.
Sample just gives the estimate of the parameter.
Hence, the population of interest to the Department of education is " All college students" .
The population of interest to the Department of Education, which wants to estimate the proportion of all college students who have a job off-campus, is all college students, not just the ones surveyed or who have off-campus jobs.
Explanation:In the context of this question asked by the Department of Education, the population of interest refers to the group about which the Department wants to draw conclusions. The Department is looking for a proportion, specifically the proportion of all college students who have a job off-campus. Therefore, the population of interest to the Department of Education is option 2: all college students. This is because the Department wants to estimate a characteristic (having a job off-campus) of this entire group, not just of the students in the sample or of students who have off-campus jobs.
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If an object is propelled straight up weed from ground level with an initial velocity of 176 ft./s its height H in feet three seconds later is given by the equation H equals -16 T squared +1 7060 after how many seconds is a high 288 feet
Answer:
the object is at 288 feet 2 seconds and 9 seconds after launch
Step-by-step explanation:
The equation of motion is given as ...
h(t) = -16t² +176t
and we are asked to find when the object is at height 288 ft. Putting that number into the equation, we have ...
288 = -16t² +176t
-18 = t² -11t . . . . . . . . divide by -16
-18 +30.25 = t² -11t +30.25 . . . . . . add (11/2)² to complete the square
12.25 = (t -5.5)² . . . . . . simplify a bit
±3.5 = t -5.5 . . . . . . . . .square root
t = 5.5 ± 3.5 = {2, 9}
The object is 288 feet high after 2 seconds or 9 seconds.
Easy Slider Inc. sold a 15-year $1,000 face value bond with a 10% coupon rate. Interest is paid annually. After flotation costs, Easy Slider received $928 per bond. Compute the after-tax cost of debt for these bonds if the firm's marginal tax rate is 40%?
Answer:
6.6%
Step-by-step explanation:
We find the cost of the bond. Yield to maturity is the yield for bond holder but cost for the issuer like Easy Slider.
Formula is
P=CP(1-(1+x)^-n)/x + FV/(1+x)^n
where P is the price of bond in the market. So, the selling price of Easy Slider Inc bond is 928
CP= coupon payment. Here, CP is 10% of 1000. So, $100
FV= Face value. Here, FV is $1000
n= maturity of the bond. Here, n=15
x= cost of the bond before tax
putting the value in the equation
928=100(1-(1+x)^-15)/x + 1000/(1+x)^15
solving for x, we get 0.1100
Now, if we find out after tax then
0.1100(1-T)= After tax cost
0.1100(1-0.4)
0.066 or 6.66%
A Plane flies at x miles per hour in still air. Flying with a tailwind, it's speed is 485 miles per hour. Against the wind, it's air speed is only 445 miles per hour. What is the speed of the wind
Answer:the speed of the wind is 20 miles per hour.
Step-by-step explanation:
A Plane flies at x miles per hour in still air. This means that the normal speed of the plane is x miles per hour.
Let y represent the speed of the wind.
Flying with a tailwind, it's speed is 485 miles per hour. This means that
the total speed of the plane would be x + y. Therefore
x + y = 485 - - - - - - - - 1
Against the wind, it's air speed is only 445 miles per hour. This means that
the total speed of the plane would be x - y. Therefore
x - y = 445 - - - - - - - - - 2
Adding equation 1 and equation 2, it becomes
2x = 930
x = 930/2 = 465
Substituting x = 465 into equation 1, it becomes
465 + y = 485
y = 485 - 465
y = 20 miles per hour