A matching side of Polygon A measures 5 inches if it is 4 times smaller than a side of Polygon B that measures 20 inches.
Explanation:If Polygon A is 4 times smaller than Polygon B, and a side of Polygon B measures 20 inches, then the matching side of Polygon A measures 5 inches. This is because when an object is said to be 'x times smaller' than another, you divide the original size by 'x' to find the new size. Therefore, the matching side length of Polygon A would be 20 inches ÷ 4 = 5 inches.
Example related to area comparison between two squares: Marta has a square with a side length of 4 inches. She has another square with side lengths that are twice as long. The side length of the larger square would be 4 inches x 2 = 8 inches. Since the area of a square is the side length squared, the area of the larger square would be 8 inches x 8 inches = 64 square inches, which is 4 times the area of the smaller square (16 square inches).
What is the product of (5r+2)(3r-4)
Answer:
[tex]\large\boxed{(5r+2)(3r-4)=15r^2-14r-8}[/tex]
Step-by-step explanation:
[tex](5r+2)(3r-4)\qquad\text{use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(5r)(3r)+(5r)(-4)+(2)(3r)+(2)(-4)\\\\=15r^2-20r+6r-8\qquad\text{combine like terms}\\\\=15r^2+(-20r+6r)-8\\\\=15r^2-14r-8[/tex]
In the diagram,the dashed figure is the image of the solid figure.What is the image of
Answer:
<R It rotates than flips look at the corners
Step-by-step explanation:
Look at the corners
Rewrite the parametric equation by eliminating the parameter x=4t+1 and y=t-3
Answer:
The equation is x = 4y + 13
Step-by-step explanation:
* Lets talk about the parametric equations
- Parametric equations are a set of equations that express a set
of quantities as explicit functions of a number of independent
variables
- Ex: x = at + b and y = ct + d are parametric equations
- We use them to find relation between the variables x and y
* Lets solve the problem
∵ x = 4t + 1 ⇒ (1)
∵ y = t - 3 ⇒ (2)
- The parameter is t to eliminate it find t in terms of x or y
- We will use equation (2) to find t in terms of y
∵ y = t - 3 ⇒ add 3 to both sides
∴ t = y + 3 ⇒ (3)
- Substitute the value of t in equation (3) in equation (1)
∵ x = 4t + 1
∵ t = y + 3
∴ x = 4(y + 3) + 1 ⇒ open the bracket
∴ x = 4y + 12 + 1 ⇒ add like term
∴ x = 4y + 13
* The equation is x = 4y + 13
To eliminate the parameter t from the parametric equations x=4t+1 and y=t-3, solve for t in one equation and substitute into the other. This results in a linear equation y=(1/4)x-13/4, revealing a linear relationship between x and y.
To rewrite the parametric equation by eliminating the parameter, we start with the given equations x=4t+1 and y=t-3. To eliminate the parameter t, we solve one of the equations for t and substitute into the other. From the first equation, we express t as t=(x-1)/4.
We can now substitute this expression for t into the second equation to get y=((x-1)/4)-3. With further simplification, we find the relationship between x and y to be y=(1/4)x-(1+12)/4, which simplifies to y=(1/4)x-13/4. This is a linear equation in x and y showing that the set of points defined by the parametric equations lies on a line.
Help please ASAP !!! It’s worth 15 points!!!!!
The answer is A. The new weight room has an area of 480 ft.
Since the area of the gym is 4x^2, they are adding 480 ft^2, which is the area of the new weight room.
Hope this helps!
Answer:
A. The new weight room has an area of 480ft^2
Step-by-step explanation:
Area of gym = 4x^2
Area of weight room = 480
Area of gym + weight room = 4x^2 + 480
480 is a constant because its value cannot and will not change whereas x is an unknown
Find x in the following right triangle.
Helppppp
12 dm.
The key to solve this problem is using the Pythagoras theorem given by the formula c² = a² + b², where a, b, and c are the sides of the right triangle.
Solving with the values given in the image:
With a = x , b = 5 dm, and c = 13 dm
(13dm)² = (x)² + (5 dm)²
169 dm² = (x)² + 25 dm²
(x)² = 169 dm² - 25 dm²
(x)² = 144 dm²
x = √144 dm²
x = 12 dm
What is the value of x?
Enter your answer in the box.
Answer:
x = 5
Step-by-step explanation:
Since the triangle is right with hypotenuse of 13
Use Pythagoras' identity to solve for x
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 12² = 13²
x² + 144 = 169 ( subtract 144 from both sides )
x² = 25 ( take the square root of both sides )
x = [tex]\sqrt{25}[/tex] = 5
What's the common difference of the sequence 0, 5, 10, 15, 20, . . . ?
A. d = –5
B. d = 3
C. d = –2
D. d = 5
Common difference of a sequence is difference between any two consecutive terms in the sequence.
So let's pick up any two consecutive terms,
0 and 5,
difference between 0 and 5 is 5-0 = 5
so common difference is 5
The function (x)=1 xl written as a piecewise function looks like
Answer:
False.
Step-by-step explanation:
This is the absolute value of x so if x < 0 then f(x) will be x not -x.
The function f(x) = 1/x can be represented as a piecewise function with different cases for x > 0, x < 0, and x = 0. It is not defined at x = 0, and it approaches positive or negative infinity as x approaches 0 from either side.
To represent the function f(x) = 1/x as a piecewise function, we need to consider the nature of the function around x = 0. The function is undefined at x = 0, and it approaches positive infinity as x approaches zero from the negative side and negative infinity from the positive side.
Piecewise Representation:
When x > 0, the function is f(x) = 1/x.When x < 0, the function is also f(x) = 1/x.When x = 0, the function is not defined.This can be written as a piecewise function:
f(x) = { 1/x, x > 0two secants meet outside the circle, forming an angle of 42 degrees. if the larger intercepted arc is 120 degrees, find the smaller intercepted arc
Answer:
36°
Step-by-step explanation:
An angle whose vertex lies outside a circle whose sides are 2 secants of the circle is
angle = [tex]\frac{1}{2}[/tex] ( larger arc - smaller arc ), that is
42 = [tex]\frac{1}{2}[/tex] ( 120 - smaller ) ← multiply both sides by 2
84 = 120 - smaller, hence
smaller = 120 - 84 = 36°
Speed typist #1 can type 95 words each minute. Speed typist #2 can type 98 words each minute. Working together, how many minutes will it take them to type 2,895 words?
Answer:
It will take them 15 minutes.
Step-by-step explanation:
1. Since you are given the information that the two typists are typing a certain amount of words in the same time frame (ie. one minute), you can add the two values together to obtain the total number of words the typists would type together in one minute:
95 + 98 = 193 words
2. To calculate how many minutes it would take them to type 2,895 words, you would simply take this total number of words and divide it by the number of words they collectively type in one minute (found in 1.). Thus:
2895/193 = 15
Therefor, it will take them 15 minutes to type 2,895 words.
Final answer:
To type 2,895 words, they would need approximately 15 minutes.
Explanation:
To solve this problem, we must first find the combined typing speed of both typists when working together.
Speed typist #1 can type 95 words per minute, and speed typist #2 can type 98 words per minute.
Together, they can type 95 + 98 = 193 words per minute.
Next, we need to calculate how many minutes it will take for them to type 2,895 words at this combined rate.
So, we divide the total number of words by the words per minute:
2,895 / 193 = 15 minutes
Therefore, it will take both typists working together approximately 15 minutes to type 2,895 words.
What is the slope of the line represented by the equation below?y=-2/3x+3 A-2/3 B. 2/3 C.2 D.x
ANSWER
A.
[tex] - \frac{2}{3} [/tex]
EXPLANATION
The given equation is
[tex]y = - \frac{2}{3}x + 3[/tex]
This equation is already in the form:
[tex]y =mx + b[/tex]
This is called the slope-intercept form.
The slope is
[tex]m = - \frac{2}{3} [/tex]
and the y-intercept is 3.
The correct answer is A.
In a situation where the line is not given in the slope intercept form, then you must rewrite in this form before comparing.
Help!! Which angle is a vertical angle with ∠AOF??
(A)∠DOE
(B)∠COD
(C)∠BOC
(D)∠FOE
use the diagram.
Answer:
angle COD
Step-by-step explanation: vertical angles share the same vertacy and are opposite of each other. They are created by two intersecting lines.
Click through and select the graph of y=-5x+1.
Answer:
The Graph Should Be Going Down Pretty Sharp and Intersects the Y-Axis at 1
Step-by-step explanation:
There isn't a visual graph so I can't directly pick which one, but I can describe it to you.
Answer: There should be a point at (6, -1), (0, 1), (4, 1)
Step-by-step explanation:
Graph the line using the slope and y-intercept, or two points.
− 5
y-intercept:
( 0,1)
x y
0 1
1 −4
Hope this helps!
Please mark brainiest!:)
solve for n 25/n = 5/8
Answer:
n=40
Step-by-step explanation:
25/n=5/8
25/5=5
n/5=8
n=40
Answer:
N= 40.
Hope that helps!
Point K(-2,1) is rotated 90 degrees about the origin. What are the coordinates of k'?
The coordinates of k' after k is rotated 90 degrees about the origin is (-1, -2)
How to determine the coordinates of k'?From the question, we have the following parameters that can be used in our computation:
K = (-2, 1)
Transformation:
rotated 90 degrees about the origin
The rule of rotation by 90 degrees about the origin is represented as
(x,y)→(−y,x) .
Substitute the known values in the above equation, so, we have the following representation
K' = (-1, -2)
Hence, the image of K is (-1, -2)
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I have like no idea how to do any of this please help!
Tan(angle) = Opposite leg / Adjacent leg
Tan (Angle) = 50/30
Angle = arctan(50/30)
Angle = 59.0 degrees.
Find the length of the ladder using the Pythagorean theorem:
50^2 + 30^2 = X^2
2500 + 900 = x^2
x^2 = 3400
x = √3400
x = 58.3 inches.
Answer:
59.03 deg
58.31 in
Step-by-step explanation:
The wall and the floor form a right angle. The parts of the wall and the floor from the corner until they intersect the ladder are the legs of a right angle. The ladder is the hypotenuse of the right angle.
You can use trigonometry to find the measure of the angle.
For the angle where the ladder touches the floor, the leg along the wall is the opposite leg, and the leg along the floor is the adjacent leg.
Use the tangent ratio.
[tex] \tan A = \dfrac{opp}{adj} [/tex]
[tex] \tan A = \dfrac{50}{30} = \dfrac{5}{3} [/tex]
[tex] A = \tan^{-1} \dfrac{5}{3} [/tex]
[tex] A = 59.03^\circ [/tex]
To find the length of the ladder, which is the hypotenuse of the triangle, you can use trigonometry again or the Pythagorean Theorem.
I'll use the Pythagorean Theorem.
[tex] a^2 + b^2 = c^2 [/tex]
[tex] (50~in)^2 + (30~in)^2 = c^2 [/tex]
[tex] 2500~in^2 + 900~in^2 = c^2 [/tex]
[tex] c^2 = 3400~in^2 [/tex]
[tex] c = \sqrt{3400~in^2} [/tex]
[tex] c = 10\sqrt{34}~in [/tex]
[tex] c \approx 58.31~in [/tex]
The cost of a jacket increased from $95.00 to $112.10. What is the percentage increase of the cost of the jacket?
Answer:
18%
Step-by-step explanation:
We are given that the cost of a jacket increased from $95.00 to $112.10 and we are to find the percentage increase in the cost of the jacket.
We know that the formula of percentage increase if given by:
Percentage increase = (new value - initial value)/initial value × 100
So substituting the given values to get:
Percentage increase = [tex] \frac { 1 1 2 . 1 0 - 9 5 . 0 0 } { 9 5 . 0 0 } \times 1 0 0 [/tex] = 18%
An unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds. What is the approximate average weight of one pallet of cargo?
Answer:
The approximate average weight of 1 pallet is 1131 pounds.
Step-by-step explanation:
Given is - the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.
So, total weight bore by 18 tires = [tex]18\times3300=59400[/tex] pounds
Now given that the fully loaded truck holds 26 pallets.
And the unloaded truck weighs = 30000 pounds
So, weight of the load = [tex]59400-30000=29400[/tex] pounds
This is the weight of 26 pallets.
So, weight of 1 pallet = [tex]29400/26=1130.76[/tex] pounds
Hence, the approximate average weight of 1 pallet is 1131 pounds.
The approximate average weight of one pallet of cargo is 1,130.76 pounds.
To find the approximate average weight of one pallet of cargo, we first need to determine the total weight of the fully loaded truck and trailer. We know that the unloaded truck and trailer weigh 30,000 pounds.
Each of the 18 tires bears approximately 3,300 pounds when the truck is fully loaded.
The weight borne by the tires includes the weight of the truck, trailer, cargo, and the weight that would be supported by the 18th tire if it were present.
First, we calculate the total weight supported by the 18 tires:
[tex]\[ 18 \text{ tires} \times 3,300 \text{ pounds/tire} = 59,400 \text{ pounds} \][/tex]
However, this total includes the weight of the truck and trailer without the cargo.
To find the weight of the cargo alone, we need to subtract the weight of the unloaded truck and trailer from the total weight supported by the tires:
[tex]\[ 59,400 \text{ pounds} - 30,000 \text{ pounds} = 29,400 \text{ pounds} \][/tex]
This 29,400 pounds is the total weight of the cargo carried by the 18 tires.
Since there are 26 pallets of cargo, we divide the total cargo weight by the number of pallets to find the average weight per pallet:
[tex]\[ \frac{29,400 \text{ pounds}}{26 \text{ pallets}} = 1,130.76\\[/tex]
Therefore, the approximate average weight of one pallet of cargo is 1,130.76 pounds.
Which of the following is an equivalent form of the compound inequality −33 > −3x − 6 ≥ −6?
The given compound inequality doesn't have any solutions because it creates a contradictory situation where x needs to be both greater than 9 and less than 0 at the same time, which is not possible.
Explanation:The given compound inequality is −33 > −3x − 6 ≥ −6. To find the equivalent form, let's solve it step by step.
First, add 6 to all sides, resulting in -27 > -3x > 0.
Then, divide by -3. Remember that when dividing by a negative number, the direction of the inequality changes. So, we get 9 < x < 0.
This indicates that x is greater than 9 but x also needs to be less than 0. This, however, is a contradictory situation because a number cannot be both greater than 9 and less than 0 at the same time. So, there are no solutions for this inequality.
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An equivalent form of the compound inequality −33 > −3x − 6 ≥ −6 is x > 9.5 or x ≤ 0.
To find an equivalent form of the compound inequality −33 > −3x − 6 ≥ −6, we can break it down into two separate inequalities:
−33 > −3x − 6
−3x − 6 ≥ −6
To simplify the first inequality, we can add 6 to both sides: −27 > −3x. Then, we can divide both sides by -3, remembering to flip the inequality sign since we are dividing by a negative number: x > 9.5.
To simplify the second inequality, we can add 6 to both sides: −3x ≥ 0. Then, we can divide both sides by -3, remembering to flip the inequality sign: x ≤ 0.
Therefore, an equivalent form of the compound inequality −33 > −3x − 6 ≥ −6 is x > 9.5 or x ≤ 0.
Can someone help me please
Answer:
3
Step-by-step explanation:
There are 13 dots, so we need to find the value of the median, or middle dot. The middle dot is the 7th dot which has the value of 3. The median of the set must be 3
As a laboratory assistant, you measure chemicals using the metric system. For your current research, you need to measure out 45 grams of sodium chloride. The bottle you are using lists the amount in ounces. About how many ounces of sodium chloride will you need?
Answer: 1.587 ounces of sodium chloride
Step-by-step explanation:
We know that 1 ounce is equivalent to 28.35 gr.
So we use this as a conversion factor to find the equivalent amount of sodium chloride in ounces.
If we need 45 grams of sodium chloride then this equals to:
[tex]45\ g* \frac{1\ ounces}{28.35\ gr} = 1.587\ ounces[/tex]
Finally you need 1.587 ounces of sodium chloride
Answer:
1.587 ounces
Step-by-step explanation:
We need to measure out 45 grams of sodium chloride using the bottle mentioning units of measure in units.
We are to find the number of ounces of sodium chloride that we will need.
We know that:
1 ounce = 28.35 grams
So using the ratio method to find the number of ounces of Sodium Chloride needed.
[tex]\frac{1 ounce}{x} =\frac{28.35 g}{45 g}[/tex]
[tex]= \frac{45}{28.35} = [/tex] 1.587 ounces
Craig has 72 feet of material to build a fence around a rectangular flower bed on his property. If the width of the fence must be 3 feet, what is the length of the fence in yards if he uses all 72 feet of material
Answer:
33 feet.
Step-by-step explanation:
Perimeter of a rectangle = 2*width + 2*length.
So here we have:
2*3 + 2*L = 72 where L = the length.
2L = 72 - 6 = 66
L = 33 feet.
Craig has 72 feet or 24 yards of material, with a stated width of 3 feet (1 yard). Subtracting the width of two sides from the total perimeter (24 yards), we find that the length of Craig's fence is 22 yards.
Explanation:Craig has 72 feet of material to build a fence around a rectangular flower bed, with the width required to be 3 feet. To calculate the length of the fence in yards, we first need to find out the total perimeter in yards. Since Craig is using all 72 feet of material, this is the perimeter of the fence. We know that 1 yard is equal to 3 feet, so we convert 72 feet to yards.
To do this division, 72 feet ÷ 3 feet per yard = 24 yards. So, Craig has 24 yards of fencing material in total.
If one side (width) of the flower bed is 3 feet, which is equivalent to 1 yard, we must subtract the width of the two opposite sides from the total perimeter to find the total length of the fence. 24 yards total perimeter - 2 yards total width = 22 yards total length. Therefore, the length of Craig’s fence in yards is 22 yards.
On the coordinate plane below, quadrilaterals TRAP and HELP are similar to each other.
Which of the following options best describes the relationship of the areas of the quadrilaterals?
Quadrilateral TRAP has an area that is half the area of quadrilateral HELP.
Quadrilateral TRAP has an area that is one-fourth the area of quadrilateral HELP.
Quadrilateral TRAP has an area that is twice the area of quadrilateral HELP.
Quadrilateral TRAP has an area that is four times the area of quadrilateral HELP.
Answer:Quadrilateral TRAP has an area that is one-fourth the area of quadrilateral HELP.
Step-by-step explanation: Because you rearrange the squares and it is 1/4
Answer:
Quadrilateral TRAP has an area that is one-fourth the area of quadrilateral HELP.
Step-by-step explanation:
Adimas found the mean of her 11 math test scores for the first semester.
x = ≈ 81
Using 81 as the mean, find the variance of her grades rounded to the nearest hundredth.
σ2 =
Find the standard deviation of her grades rounded to the nearest hundredth.
σ =
Answer: O^2= 71.36
O=8.45
Answer:
The complete question is attached.
To find the variance and deviation, we have to use their definition or formulas:
Standard deviation.[tex]\sigma=\sqrt{\frac{\sum (x- \mu)^{2} }{N}}[/tex]
So, first we have to find the difference between each number and the mean:
76-81=-5
87-81=6
65-81=-16
88-81=7
67-81=-14
84-81=3
77-81=-4
82-81=1
91-81=10
85-81=4
90-81=9
Now, we have to elevate each difference to the squared power and then sum all:
[tex]25+36+256+49+196+9+16+1+100+16+81=785[/tex]
Then, we replace in the formula:
[tex]\sigma=\sqrt{\frac{785}{11}} \approx 8.45[/tex]
Variance.The variance is just the squared power of the standard deviation. So:
[tex]\sigma^{2}=(8.45)^{2}=71.40[/tex]
what is measure of egf?
Answer:
∠EGF = 65°
Step-by-step explanation:
Since EF = EG the triangle is isosceles and the base angles are equal, that is
∠EGF = ∠GEF
∠EGF = [tex]\frac{180-50}{2}[/tex] = [tex]\frac{130}{2}[/tex] = 65°
Sam predicted that he would sell 15 mugs, but he actually sold 20 mugs, which expression would find the percent error? Use
the table below to help answer the question
Percent Error
Answer:
A
Step-by-step explanation:
The percentage error is 25%.
We have,
The percent error can be calculated using the following expression:
Percent Error = (|Predicted Value - Actual Value| / Actual Value) * 100%
In this case,
Sam predicted he would sell 15 mugs, but he actually sold 20 mugs.
Plugging these values into the expression, we get:
Percent Error = (|15 - 20| / 20) * 100%
Simplifying further:
Percent Error = (5 / 20) * 100%
Percent Error = (1/4) * 100%
Percent Error = 25%
Therefore,
The percent error is 25%.
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if the standard deviation of data values in a sample is 17, what is the varience of the data values
Answer:
Step-by-step explanation:
The variance is the square of the standard deviation. Here, the variance is 17^2, or 289.
The quotient of five and seven
Answer: The quotient of 5 & 7 is approximately 0.714
Step-by-step explanation:
First you divide 5 by 7, teachers typically want a simple form so instead of putting the whole answer we can give them a short answer and say it's approximately.714! Hope this helped out!!
What is the equation for the hyperbola shown? PLEASE HELP
ANSWER
[tex]\frac{ {y}^{2} }{ 25} - \frac{ {x}^{2} }{ 64} = 1 [/tex]
EXPLANATION
The given hyperbola has a vertical transverse axis and its center is at the origin.
The standard equation of such a parabola is:
[tex] \frac{ {y}^{2} }{ {a}^{2} } - \frac{ {x}^{2} }{ {b}^{2} } = 1 [/tex]
Where 2a=10 is the length of the transverse axis and 2b=16 is the length of the conjugate axis.
This implies that
[tex]a = 5 \: \: and \: \: b = 8[/tex]
Hence the required equation of the hyperbola is:
[tex]\frac{ {y}^{2} }{ {5}^{2} } - \frac{ {x}^{2} }{ {8}^{2} } = 1 [/tex]
This simplifies to,
[tex]\frac{ {y}^{2} }{ 25} - \frac{ {x}^{2} }{ 64} = 1 [/tex]
Answer:
[tex]\frac{(y^2}{25}-\frac{x^2}{64}=1[/tex]
Step-by-step explanation:
We have been given an image of a hyperbola. We are asked to write an equation for our given hyperbola.
We can see that our given hyperbola is a vertical hyperbola as it opens upwards and downwards.
We know that equation of a vertical hyperbola is in form [tex]\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1[/tex], where, [tex](h,k)[/tex] represents center of hyperbola.
'a' is vertex of hyperbola and 'b' is co-vertex.
We can see that center of parabola is at origin (0,0).
We can see that vertex of parabola is at point [tex](0,5)\text{ and }(0,-5)[/tex], so value of a is 5.
We can see that co-vertex of parabola is at point [tex](8,0)\text{ and }(-8,0)[/tex], so value of b is 8.
[tex]\frac{(y-0)^2}{5^2}-\frac{(x-0)^2}{8^2}=1[/tex]
Therefore, our required equation would be [tex]\frac{(y^2}{25}-\frac{x^2}{64}=1[/tex].
The hypotenuse of right triangle ABC, line segment AC, measures 13 cm. The length of line segment BC is 5 cm.
What is the approximate difference between m∠C and m∠A?
Answer:
The approximate difference between m∠C and m∠A is 45° to the nearest degree
Step-by-step explanation:
* Lets talk about the right triangle
- It has one right angle and two acute angles
- The side opposite the the right angle is called hypotenuse
- The other sides are called the legs of the right angle
- In ΔABC
∵ AC is the hypotenuse
∴ ∠B is the right angle
∴ AB and BC are the legs of the right angle
∴ Angles A and C are the acute angles
∵ m∠B = 90°
- The sum of the measures of the interior angles of a Δ is 180°
∴ m∠A + m∠C = 180° - 90° = 90°
- We will use trigonometry to find the measures of angles A and C
- sin A is the ratio between the opposite side to angle ∠A and the
hypotenuse
∵ BC is the opposite side of angle A
∴ sin A = BC/AC
∵ BC = 5 cm
∵ AC = 13 cm
∴ sin A = 5/13
- Lets find m∠∠A by using sin ^-1
∴ m∠A = [tex]sin^{-1}\frac{5}{13}=22.62[/tex]
- Lets use the rule of the sum of angles A and C to find the measure
of the angle C
∵ m∠A + m∠C = 90°
∴ 22.62° + m∠C = 90 ⇒ subtract 22.62 from both sides
∴ m∠C = 67.38°
- Lets find the difference between m∠C and m∠A
∴ The approximate difference between m∠C and m∠A is:
67.38° - 22.62° = 44.78° ≅ 45° to the nearest degree