To find out how far the man drives, multiply his speed (45.8 m/s) by the time (362 s) to get a distance of 16,579.6 meters, or 16.5796 kilometers to the south.
Explanation:Calculating Distance TraveledTo calculate how far the man gets when driving south at 45.8 m/s for 362 seconds, you use the formula for distance:
Distance = Speed × Time
In this case, the speed is 45.8 meters per second (m/s), and the time is 362 seconds. Thus, the distance traveled is:
Distance = 45.8 m/s × 362 s
After calculating this, you'll find that the man covers a distance of:
16,579.6 meters, which can be converted to kilometers (km) by dividing by 1000:
16.5796 kilometers (km)
This is the total distance traveled by the man to the south.
Final answer:
To determine how far the man drives, multiply his speed by the time traveled. Driving at 45.8 m/s for 362 seconds, he would travel 16565.6 meters, which is 16.566 kilometers south.
Explanation:
The question requires the calculation of distance traveled based on the given speed and time duration. To find the distance, one must use the formula for constant velocity, which is distance = speed × time. Since the man drives south for 362 seconds at 45.8 m/s, the calculation will be as follows:
Distance = Speed × Time
Distance = 45.8 m/s × 362 s
Distance = 16565.6 m
To convert meters to kilometers, divide by 1000:
Distance = 16565.6 m / 1000
Distance = 16.566 km
Therefore, the man gets 16.566 kilometers south.
How does secondhand smoke affect children?
It increases their asthma rates.
It increases their attention span.
It increases their learning ability.
It increases their chance of obesity.
Answer:
It increases asthma rates
Explanation:
A hydraulic lift is used to lift a heavy box that is pushing down on a 1.5-m2 piston with a force of 1,700 N. What force needs to be exerted on a 0.12-m2 piston to lift the box?
Answer:
136 N
Explanation:
Pressure on large piston = pressure on small piston
F₁ / A₁ = F₂ / A₂
1700 N / 1.5 m² = F / 0.12 m²
F = 136 N
Select all the correct answers.
Which three statements about electromagnetic radiation are true?
0
Light is a kind of electromagnetic radiation.
0
Electromagnetic radiation can travel only short distances.
O
Electromagnetic radiation has no mass.
O
Electromagnetic radiation can travel through a vacuum.
All kinds of electromagnetic radiation are invisible.
Yo sup??
the 1st, 3rs and 4th statement are true because electromagnetic waves can travel large distances and electromagnetic waves are visible (only 400-700 nm wavelenght)
Hope this helps
A pendulum consisting of a sphere suspended from a light string is oscillating with a small angle with respect to
the vertical. The sphere is then replaced with a new sphere of the same size but greater density and is set into
oscillation with the same angle. How do the period and maximum acceleration of the new pendulum compare to
those of the original?
Period
Acceleration
a. Larger
Smaller
b. Smaller
Larger
C. The same
The same
d. The same
Smaller
Answer:
Explanation:
The time period of a simple pendulum: It is defined as the time taken by the pendulum to finish one full oscillation and is denoted by “T”.
The period of simple pendulum is given as
T=2π√l/g
Increasing the density of the object implies that the mass has increased
Because density is mass/volume
The period is independent on the density of the object, it depends on the length of the string and the acceleration due to gravity. So the period remains the same.
2. Acceleration
The acceleration of a simple pendulum is given as
a=-gSin θ
Therefore the acceleration is independent on the density of the object, it depends on the acceleration due to gravity and the angle of displacement.
Then, the acceleration remains the same.
So the answer is Option C,
Same
Same
Final answer:
Replacing a sphere with another of greater density in a pendulum, without changing the oscillation angle, does not affect the pendulum's period or maximum acceleration. Both remain the same because they are independent of the pendulum bob's mass or density.
Explanation:
The period of a pendulum is given by the formula T = 2π√(l/g), where T is the period, l is the length of the pendulum, and g is the acceleration due to gravity. This formula shows that the period is independent of the mass or density of the pendulum bob. Hence, replacing a sphere in a pendulum with another sphere of greater density but the same size, and oscillating both at the same angle, does not change the period of the pendulum's oscillation. The maximum acceleration of a pendulum occurs at its lowest point and is given by a = g√(sinθ), where θ is the oscillation angle. Since the acceleration depends only on gravity and the angle of oscillation, which remain constant, the maximum acceleration of the pendulum will also remain the same irrespective of the mass or density of the bob.
Charles' Law
4. A gas has a volume of 4 liters at 50 °C. What will its volume be in liters) at 100°C?
Therefore, the volume of the gas at temperature 100°C is 4.62L
Explanation:
Given-
Volume, V1 = 4L
Temperature, T1 = 50°C = 50 + 273K = 323K
Temperature, T2 = 100°C = 100 + 273K = 373K
Volume, V2 = ?
Using Charles law:
V1/T1 = V2/T2
4/323 = V2/373
V2 = 4.62L
Therefore, the volume of the gas at temperature 100°C is 4.62L
a man lifts a 2.5kg stone vertically with his hand at a constant velocity of 1.2m/s. what is the magnitude of the total force of the man's hand on the stone.
Answer:
Zero
Explanation:
According to Newton's second law of motion, the net force on an object is equal to the product of its mass and its acceleration:
[tex]F=ma[/tex] (1)
where
F is the net force
m is the mass
a is the acceleration
For the stone in this problem, we have:
m = 2.5 kg is its mass
We are also told that the velocity of the stone is constant (1.2 m/s): we know that the acceleration is equal to the rate of change of velocity, therefore, this means that the acceleration (because the change in velocity is zero):
[tex]a=0[/tex]
Therefore, from equation (1), we get that the total net force on the stone is zero:
[tex]F=0[/tex]
Which means that the upward force on the stone balances the downward force of gravity.
Final answer:
To lift a 2.5kg stone at a constant velocity, the man's hand must apply a force equal to the weight of the stone, which is 24.5 N, countering the gravitational pull without causing any acceleration.
Explanation:
The magnitude of the total force of the man's hand on the stone can be determined by Newton's second law of motion which states that the force is equal to mass times acceleration (F=ma). However, since the stone is moving at a constant velocity, the acceleration is zero, and thus the only force exerted by the man would be to counteract the force of gravity on the stone. The force of gravity is calculated as the mass of the stone multiplied by the acceleration due to gravity (g = 9.8 m/s2).
The force of gravity (also known as weight) on the stone can be calculated as follows:
Fg = m × g = 2.5 kg × 9.8 m/s2 = 24.5 N.
Therefore, the magnitude of the total force that the man's hand must apply on the stone to lift it at a constant velocity is 24.5 N, which is exactly the same as the gravitational force acting on the stone.
6. Water flows through a 9,6-cm-diameter fire hose with a speed of 1.3 m/s. At the end of
the hose, the water flows out through a nozzle whose diameter is 2.5 cm. What is the
speed of water coming out of the nozzle?
A) 4.99cm/s
B) 0.339m/s
C) 0.088m/s
D) 19.2m/s
Can someone please answer this question
Answer:
D) 19.2 m/s
Explanation:
We can solve this problem by using the continuity equation: in fact, the flow rate a fluid through a pipe must remain constant.
Therefore, we can write:
[tex]A_1 v_1 = A_2 v_2[/tex]
where
[tex]A_1[/tex] is the cross-sectional area of the 1st section of the pipe
[tex]A_2[/tex] is the cross-sectional area of the 2nd section of the pipe
[tex]v_1[/tex] is the velocity of the water in section 1
[tex]v_2[/tex] is the velocity of the water in section 2
For the pipe in the problem we have:
[tex]d_1=9.6 cm = 0.096 m[/tex] is the diameter of the hose, so the area is
[tex]A_1=\pi (\frac{d_1}{2})^2[/tex]
[tex]d_2=2.5 cm = 0.025 m[/tex] is the diameter of the nozzle, so the area is
[tex]A_2=\pi (\frac{d_2}{2})^2[/tex]
[tex]v_1=1.3 m/s[/tex] is the velocity of water in the hose
Solving the equation for v2, we find the speed of water in the nozzle:
[tex]v_2=v_1\frac{A_1}{A_2}=v_1 \frac{d_1^2}{d_2^2}=(1.3)\frac{(0.096)^2}{(0.025)^2}=19.2 m/s[/tex]
When a train first starts going down the railroad, it is very difficult for it to get going. When it comes to a stop, it has a hard time slowing down. Why is this?
A: balanced forces
B: unbalanced forces
C: inertia
Explanation:
When we apply the force on any body , the inertia comes into play . It is the tenancy of the the body to oppose the force which tends to change its state .
In first case the train tries to change its state from rest to motion . Thus the inertia of rest opposes this tendency.
In the second case , the train tries to come from motion to the state of rest . Thus again , inertia opposes it .
Therefore inertia is the factor which creates difficulty in both case . Hence option ( c ) is correct
Which motion maps show an object in uniform circular motion? Check all that apply.
V
W
X
Y
Z
Answer:
V, since all the directions are uniform
W, since all the directions are uniform
Y, since all the directions are uniform
hope this helps :)
Jimmy has two options for moving a piano up to the second floor of a hotel, which is 10 m above his current position. He can push the piano up 50 m ramp or lift the piano up with a rope wrapped around a pulley. Which option will require him to exert a greater average force? Neglecting friction, which option will require more work?
Answer:
Lifting straight up, even with a rope and pulley, always takes more force than going up a slanted ramp to the same height.
But if you use the ramp, then you have to exert the force over a greater distance (pull more rope to lift to the same height).
Astonishingly, the product of (force) x (distance) is the same number either way. So without friction, the total amount of work required is the SAME whichever way the piano is lifted.
Alice builds an electric motor by positioning an electromagnet between the poles of a permanent magnet. When the electromagnet turns, the current through it switches direction because its connections to the voltage source are reversed. The repeated switching of the electromagnet's poles causes it to spin. This particular motor is used to turn the wheels of a toy car.
Which of the following actions would increase the amount of force applied to the wheels of the toy car?
A.
replacing the magnet with a stronger magnet
B.
increasing the distance between the magnet's poles and the electromagnet
C.
decreasing the number of loops in the electromagnet's coil
D.
decreasing the electric current running through the electromagnet
Answer:
A. replacing the magnet with a stronger magnet
Explanation:
In order to increase the force on the wheels, Alice needs to increase the force acting between the magnet and the electromagnet. There are several ways that she could do this:
replace the magnet with stronger magnet
increase the number of loops in the electromagnet's coil
increase the electric current running through the electromagnet
decrease the distance between the magnet's poles and the electromagnet
Two colours of light which mix to make white light are called
a) primary colours
b) secondry colous
c) complementary colours
d) dye
Complementary colors are pairs of colors that, when mixed together, produce white light. They are located opposite each other on the color wheel.
Explanation:The correct answer is c) complementary colours. Complementary colors are pairs of colors that, when mixed together, produce white light. These colors are located opposite each other on the color wheel. For example, red and cyan, green and magenta, and blue and yellow are complementary color pairs.
Mixing complementary colors can be observed in additive color mixing, which is the process of combining different colors of light. For instance, if you mix red and cyan lights together, you will see white light.
Complementary colors are also used to create contrast and make colors stand out when they are placed next to each other. This concept is often used in design and visual arts.
A youngster having a mass of 50.0 kg steps off a 1.00 m high platform. If she keeps her legs fairly rigid and comes to rest in 10.0 ms, what is her momentum just as she hits the floor? What average force acts on her during the deceleration?
The youngster's momentum just before hitting the floor is -500 kg*m/s, and the average force acting on her during deceleration is 25,000 N.
Explanation:To calculate momentum before hitting the floor, we use the formula: momentum = mass × velocity. Given the mass (m) as 50.0 kg and the height (h) as 1.00 m, we can find the initial velocity (v) using the equation for gravitational potential energy (PE = mgh) and converting it into kinetic energy (KE = 1/2mv^2). Solving for velocity, we get v = √(2gh) = √(2 × 9.81 m/s^2 × 1.00 m) ≈ 4.43 m/s.
Momentum = mass × velocity = 50.0 kg × 4.43 m/s = 221.5 kg*m/s. As she comes to rest, the change in momentum is Δp = final momentum - initial momentum = 0 - 221.5 kg*m/s = -221.5 kg*m/s. However, as the motion direction changes, the momentum also changes direction, so we take -221.5 kg*m/s as the momentum just before hitting the floor.
The average force during deceleration can be found using the impulse-momentum theorem, which states that impulse (change in momentum) is equal to force × time. Impulse = Δp = force × time. Rearranging the formula to solve for force, we get force = Δp / time. Substituting the values, force = -221.5 kg*m/s / (10.0 ms) = -22,150 N.
However, force is a vector quantity, and its direction opposes the motion, so the magnitude of the force is 22,150 N. As the force acts over 10.0 ms, the average force is 22,150 N / 10.0 ms = 25,000 N. Thus, the average force exerted on the youngster during deceleration is 25,000 N, with the negative sign indicating it opposes the motion.
An instrument that measures atmospheric pressure
Answer:
barometer
Explanation:barometer
A barometer is a scientific instrument used in meteorology to measure atmospheric pressure. A simple barometer consists of a long glass tube (closed at one end, open at the other) filled with mercury and turned upside down into a container of mercury.
brainliestA barometer is the instrument that measures atmospheric pressure. It operates by counterbalancing the weight of a column of mercury against the atmospheric pressure. The level of mercury changes based on the atmospheric pressure.
Explanation:The instrument that measures atmospheric pressure is called a barometer. This device was invented in the 17th century by the Italian scientist Evangelista Torricelli. It works by balancing the weight of a column of mercury against the atmospheric pressure. When the pressure is high, it pushes the mercury higher up the tube, and when it is low, the mercury drops. Digitals variations exist now and are widely used also.
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At 15°C air is transmitted
at 340 m/s. Express this speed
in Kilometers per hour.
Answer:
1224km/hr
Explanation:
To convert from m/s to km/hr
1000m = 1km
Divide both sides by 1000
1m = 1/1000 km................. (1)
60×60 seconds = 1 hr
3600s = 1hr
Divide both sides by 3600
1s = 1/3600 .............(2)
Divide (2) by (1)
1m/s = 1/1000 ÷ 1/3600 km/hr
1m/s = 1/1000 × 3600/1 km/hr
1m/s = 3600/1000 km/hr
1m/s = 3.6 km/hr .............(3)
To convert 340m/s to km/hr
Multiply (3) by 340
1× 340m/s = 3.6 × 340 km/hr
340m/s = 1224km/hr
I hope this was helpful, please mark as brainliest
Answer:
1224 km/hr
Explanation:
Method 1to convert m/s to km/hrrecall that :
1km = 1000m
firstly lets convert m to km
340 m to km
340 / 1000
= 0.34 km
recall that :
1hr = 60 min
1 min = 60 seconds
hence 1 hr = 60*60
1 hr = 3600 seconds
now to convert seconds to hr :1 second / 3600
=1/3600 hours
hence to get the answer you say :
[tex]\frac{0.34}{\frac{1}{3600} }[/tex]
= 1224 Method 2recall : 1km = 1000m
recall: 1hr = 60 min
1 min = 60 seconds
hence 1 hr = 60*60
1 hr = 3600 seconds
now to get this answer you have to divide m by 1000 to get km
and you have to divide seconds by 3600 to get hours
= [tex]\frac{340 / 1000}{1/3600}[/tex]
= 1224How many dwarf planets are there in the solar system
Answer: 5
Explanation: There are 5 recognized dwarf planets in our solar system; Ceres, Pluto, Haumea, Makemake and Eris.
Answer:
5
Explanation:
There are only 5 dwarf planets that are officially recognized and they are Ceres, Pluto, Haumea, Makemake and Eris.
What are the answer for the blanks
What is the oscillation period of your eardrum when you are listening to the A4 note on a piano (frequency 440 Hz)?
The period is the inverse of the frequence:
[tex]T=\dfrac{1}{f}=\dfrac{1}{440}=0.0022\overline{72}[/tex]
Answer:
T = 0.002 s.
Explanation:
Given data:
Frequency, [tex]f = 440 \ \rm Hz[/tex]
The time period of oscillation of the eardrum can be expressed as,
[tex]T = \frac{1}{f}[/tex]
[tex]T = \frac{1}{440 \ \rm Hz}[/tex]
[tex]T = 0.002 \ s.[/tex]
a heavy object falls with the acceleration as a light object during free fall. why?
A heavy object falls with the acceleration as a light object during free fall because:
Heavy things have a large gravitational force and also have less acceleration. So both the effects exactly cancel and make the falling objects to have the same acceleration irrespective of mass.
Free fall is a unique motion which has only gravitational force that acts on an object. Objects that undergo free fall experience only have the influence of gravity and not any other force.
So when we apply newton's second law of gravity which is:
[tex]\text {acceleration}=\frac{\text {Force}}{\text {mass}}[/tex]
where,
F is the force
m is the mass
a is the acceleration
For example: When a 1000 kg elephant and a 1 kg rat fall from the same height,
The acceleration can be calculated as follows:
For elephant: F = 10000 N and m = 1000 kg. So,
[tex]\text {acceleration}=\frac{10000}{1000}=10\ \mathrm{m} / \mathrm{s}^{2}[/tex]
For rat : F = 10 N and m = 1 kg
Thus, [tex]\text {acceleration}=\frac{10}{1}=1\ \mathrm{m} / \mathrm{s}^{2}[/tex]
Hence, it shows that both the animals have the same acceleration irrespective of their mass.
1. If a model train car with a momentum of 12 kg•m/s collides with a 2 kg model train car that is not moving, what is the total momentum of both cars after the collision?
Answer:
[tex]P_{f} = 12 \ kg.m/s[/tex]
Explanation:
Given data:
Momentum of moving model train, [tex]P_{1} = 12 \ kg.m/s[/tex]
Mass of the stationary model train, [tex]m = 2 \ kg[/tex]
Initial speed of the stationary model train, [tex]v = 0[/tex]
Assume there is no external force is acting on the given train system.
In this case, the total linear momentum of the trains would be conserved.
Let the final linear momentum of the trains be [tex]P_{f}.[/tex]
Thus,
[tex]P_{i} = P_{f}[/tex]
[tex]P_{1} + P_{2} = P_{f}[/tex]
[tex]P_{1} + mv = P_{f}[/tex]
[tex]12 + 2 \times 0 = P_{f}[/tex]
[tex]\Rightarrow \ P_{f} = 12 \ kg.m/s.[/tex]
The total momentum of both cars after the collision is 12 kg•m/s.
Explanation:The momentum of an object is the product of its mass and velocity. In this case, the initial momentum of the moving model train car is 12 kg•m/s while the other car is stationary, so its initial momentum is 0 kg•m/s.
According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Therefore, the total momentum of both cars after the collision is 12 kg•m/s.
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The force needed to lift an object is equal in size to the gravitational force on the object. How much work is done in lifting an object that has a mass of 5 kg a vertical distance of 2 m?
Answer:
Work done in lifting the object = 98 J
Explanation:
Work: Work can be defined as the product of force and distance.
The S.I unit of work is Joules (J).
Mathematically it can be expressed as
W = F × d................. Equation 1
Where W = work done, F = force needed to lift the object, d = distance
The gravitational force on the object = Weight of the object
Weight of the object = mg .................. Equation 2
Where m = mass of the object, g = acceleration due to gravity
Given: m = 5 kg,
Constant: g = 9.8 m/s²
Substituting these values into equation 2
Weight of the object = 5 × 9.8
Weight of the object = 49 N
Since weight of the object = force needed to lift the object,
F = 49 N
Also Given: d = 2 m
Substituting these values into equation 1
W = 49 × 2
W = 98 J
Work done in lifting the object = 98 J
hope this helps
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A wave with a frequency of 17 Hz has a wavelength of 4 meters. At what speed (in m/s) will this wave travel?
Answer:68m/s
Explanation:
Frequency=17Hz
Wavelength=4metre
Wave speed=frequency x wavelength
Wave speed =17 x 4
Wave speed =68m/s
2. What is the speed (v) of a wave that has a wavelength (a)
of 2 m and a frequency (f) of 6 Hz?
Answer:12m/s
Explanation:
Frequency=6Hz
Wavelength=2m
Wave speed=frequency x Wavelength
Wave speed=6 x 2
Wave speed=12m/s
The speed of a wave with a frequency of 6 Hz and a wavelength of 2 m is 12 m/s.
Explanation:The speed (v) of a wave is calculated by the formula v = fλ, where 'f' is the frequency and 'λ' (lambda) is the wavelength. Given the frequency (f) of 6 Hz and a wavelength ('λ') of 2 m, we can compute the speed of the wave using this formula:
v = 6 Hz × 2 m = 12 m/s.
Therefore, the speed of the wave is 12 meters per second (12 m/s).
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A circuit has a voltage drop of 24.0 V across a 30.0 resistor that carries a
current of 0.800 A. What is the power conducted by the resistor? Use P = VI.
O A. 19.2 W
O B. 1.25 W
O c. 24.0 W
O
D. 720.0 W
(A) 19.2 W
Explanation:
Given-
Voltage drop, V = 24 V
Resistor = 30Ω
Current, I = 0.8 A
Power, P = ?
We know,
P = VI
P = 24 (0.8)
P = 19.2 W
Therefore, the power conducted by the resistor is 19.2 W
Answer:
19.2
Explanation:
Select the correct answer.
Which statement best explains that sound waves are pressure waves?
A.
Sound waves have regions of compressions and rarefactions.
B. Sound waves cannot propagate through metals.
C. Sound waves move perpendicular to the medium particles.
D. Sound waves cannot propagate through water.
Answer:
C
Explanation:
Sound waves move perpendicular to the medium particles.
Answer:
its c for sure
Explanation:
How does Mercury's close proximity to the sun and thin atmosphere affect its ability to maintain liquid water
on its surface?
Answer
A thin atmosphere does not supply much oxygen, and the heat from the sun would evaporate it, because mercury is close to the sun.
Final answer:
Mercury's close proximity to the Sun and thin atmosphere prevent it from maintaining liquid water. Its lack of substantial atmosphere and the intense solar radiation lead to extreme temperatures and no significant greenhouse effect, which are necessary for liquid water to exist.
Explanation:
Mercury's close proximity to the Sun and its thin atmosphere contribute to conditions that are not conducive to maintaining liquid water on its surface. Due to its small size and weak gravity, Mercury cannot retain a substantial atmosphere, which would be necessary to create a greenhouse effect to keep the heat in. Additionally, the intense solar radiation that Mercury receives results in surface temperatures that can reach up to 800 degrees Fahrenheit (427 degrees Celsius) during the day, which is far too hot for liquid water to exist.
The lack of a significant atmosphere means there is no atmospheric pressure to prevent water from boiling away. Without an atmosphere similar to Earth's, which includes water vapor and carbon dioxide, Mercury is unable to trap heat and maintain steady surface temperatures. Its tenuous atmosphere, composed mainly of trace gases, is incapable of supporting a cycle that would retain liquid water. Therefore, Mercury's environment does not allow for the presence of stable bodies of liquid water on its surface.
Please Answer this....
Class 10 science board cbse 2020
Qn. 29
a) See attachment
b) -180 cm, virtual image
c) Magnification: 10, image is 10 times the size of the object, upright
Explanation:
a)
The ray diagram for this situation is shown in attachment.
In order to find the position of the image, we proceed as follows:
- We draw a ray of light going from the tip of the object towards the lens, parallel to the principal axis - this ray is refracted towards the principal focus on the other side
- We draw another ray of light going from the tip of the object towards the centre of the lens
- We prolong both rays: we see that they don't meet on the right side of the lens. Therefore, we prolong them on the left side, where they meet - this means that the image is virtual, because it cannot be projected on a real screen (it is formed on the same side as the object).
b)
To find the nature and the position of the image, we use the lens equation:
[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]
where:
f is the focal length
p is the distance of the object from the lens
q is the distance of the image from the lens
In this problem:
[tex]f=20 cm[/tex] is the focal length
[tex]p=18 cm[/tex] is the object distance
Solving for q, we find the position of the image:
[tex]\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{20}-\frac{1}{18}=-0.00555 cm^{-1}\\q=\frac{1}{-0.00555}=-180 cm[/tex]
The negative sign indicates that the image is virtual (on the same side of the object).
c)
The magnification is given by:
[tex]M=-\frac{q}{p}[/tex]
where
q is the image distance from the lens
p is the object distance from the lens
Here we have
[tex]q=-180 cm[/tex]
[tex]p=18 cm[/tex]
So the magnification is:
[tex]M=-\frac{-180}{18}=10[/tex]
This means that the image size is a factor 10 times the object size. In fact, we can write
[tex]y'=My[/tex]
where
y' is the image size
y is the object size
Substituting,
[tex]y'=10y[/tex]
So, the image is 10 times the object (in size), and it has the same orientation, upright (because of the positive sign).
Which products rely on the ability of ionic compounds to conduct electricity?
Cell phones and remote control toys are the products which rely on the ability of ionic compounds to conduct electricity.
Explanation:
Ionic compounds are those which are formed between electronegative and electropositive elements. So some of the electrons will be always free in these compounds. Among the options given in the question, cell phones and remote control toys are the products which uses ionic products. As most of the semiconducting compounds or electronic compounds are ionic in nature. And cell phones and remote control toys uses the movement of electrons from ionic compounds to do the work.
Thus, cell phones and remote control toys are the products which rely on the ability of ionic compounds to conduct electricity.
Answer:
(B) cell phones
Explanation:
jus took the quiz
Monochromatic radiation of frequency greater than the threshold frequency is incident on a metal do all the electrons emitted by photoelectric emission have the same kinetic energy.
Yo sup??
No it isn't necessary that they will have the same Kinetic energy.
Hope this helps
Which of the following is a speed, not a velocity?
A. 35 m/s east
B. 0-35 m/s
C. 035 m/s
D. 35 m/s south
Answer:
B. 0-35 m/s
Explanation:
Because speed does not need a direction so it would be 0-35 m/s A and B has a direction, velocity needs a direction and the question ask not velocity. C technically it does not have a speed