Answer:
There were 28.75 large boxes and 96.25 small boxes.
Step-by-step explanation:
Create a system of equations to solve.
State your variables
let x be the number of small boxes
let y be the number of large boxes
35x + 55y = 4950 Equation for weight
x + y = 125 Equation for number of boxes
Rearrange equation for number of boxes to isolate "x".
x = 125 - y
Substitute the new equation into the equation for weight
35x + 55y = 4950
35(125 - y) + 55y = 4950
Expand the brackets
4375 - 35y + 55y = 4950 Combine like terms
4375 + 20y = 4950
Start isolating "y"
4375 + 20y = 4950
4375 - 4375 + 20y = 4950 - 4375 subtract 4375 from both sides
20y = 575
20y/20 = 575/20 divide both sides by 20
y = 28.75 number of large boxes
Calculate "x". Rearrange the equation for number of boxes to isolate "y".
y = 125 - x Substitute this expression
35x + 55y = 4950 equation for weight
35x + 55(125 - x) = 4950 expand the brackets
35x + 6875 - 55x = 4950 combine like terms
6875 - 20x = 4950 start isolating "x"
6875 - 6875 - 20x = 4950 - 6875 subtract 6875 on both sides
-20x = -1925
-20x/-20 = -1925/-20 divide both sides by -20
x = 96.25 number of small boxes
There is a mistake with this question because you should not be able to have partial boxes. However, the answer is:
There were 28.75 large boxes and 96.25 small boxes.
What is the difference in mass between a nickel that weighs 4.7 g and a nickel that weighs 4.874 g ?
Nickel a: 4.874
Nickel b: 4.7
The difference will be:
Higher- lower
4.874 - 4.7
0.174
So the difference is 0.174g
The difference in mass between the two nickels is 0.174 grams.
Given that:
Weight of first nickel, n = 4.7 g
Weight of second nickel, N = 4.7 g
To find the difference in mass between the two nickels, subtract the weight of one nickel from the weight of the other nickel:
Difference in mass = Weight of the second nickel - Weight of the first nickel
Let's calculate the difference:
Weight of the second nickel = 4.874 g
Weight of the first nickel = 4.7 g
Difference in mass = 4.874 g - 4.7 g
Difference in mass = 0.174 g
Hence, the difference in mass between the two nickels is 0.174 grams.
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Which of the following values cannot be probabilities? 0.04, 5 divided by 3, 1, 0, 3 divided by 5, StartRoot 2 EndRoot, negative 0.59, 1.49 Select all the values that cannot be probabilities. A. 1.49 B. 1 C. three fifths D. StartRoot 2 EndRoot E. five thirds F. 0 G. negative 0.59 H. 0.04
Answer:
A. 1.49
D. √2
E. five thirds
G. - 0.59
Step-by-step explanation:
In order to be a probability, a value must be at least zero, or at most 1:
[tex]0 \leq P\leq 1[/tex]
Evaluating each of the given values:
A. 1.49
1.49 is at least zero but it is greater than one, therefore 1.49 cannot be a probability.
B. 1
1 represents a probability of 100%, therefore this value can be a probability
C. three fifths
[tex]0\leq \frac{3}{5} \leq 1[/tex]
Can be a probability
D. √2
[tex]\sqrt 2 =1.41 > 1[/tex]
Cannot be a probability
E. five thirds
[tex]\frac{5}{3}=1.67>1[/tex]
Cannot be a probability
F. 0
0 represents a probability of 0%, therefore this value can be a probability
G. - 0.59
Negative values cannot be probabilities.
H. 0.04
[tex]0\leq 0.04 \leq 1[/tex]
Can be a probability
Probabilities are values ranging from 0 to 1, inclusive. With this in mind, values 5/3, √2, -0.59, and 1.49 cannot be probabilities as they're either below 0 or above 1.
Explanation:In the field of mathematics, specifically in statistics, a probability represents the likelihood of an event occurring and is always a value between 0 and 1, inclusively. The value 0 means that an event will not happen, whilst 1 means the event is certain to happen. Therefore, any value less than 0 or greater than 1 cannot be a probability.
Given the values: 0.04, 5 divided by 3, 1, 0, 3 divided by 5, √2, negative 0.59, and 1.49, the values that cannot be probabilities are:
Value 5 divided by 3 (which equals approximately 1.67)Value √2 (which equals approximately 1.41)Negative 0.591.49These numbers do not lie within the range of 0 to 1, and hence, cannot represent probabilities.
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A local ice cream shop kept track of the number of cans of cold soda it sold each day, and the temperature that day, for two months during the summer. The data are displayed in the scatterplot below:A local ice cream shop kept track of the number of
The one outlier corresponds to a day on which the refrigerator for the soda was broken. Which of the following is true?
(a) A reasonable value of the correlation coefficient r for these data is 1.2.
(b) If the temperature were measured in degrees Celsius (C = 5/9*(F-32)), the value of r would change accordingly.
(c) If the outlier were removed, r would increase.
(d) If the outlier were removed, r would decrease.
(e) Both (b) and (c) are correct.
Final answer:
Option (a) is incorrect because the value of r cannot exceed the range of -1 to +1. Option (b) is incorrect as changing units does not alter the value of r. Option (c) is most likely correct because removing an outlier typically leads to an increased value of r.
Explanation:
The student's question pertains to the transformation of a scatterplot and the effects on the Pearson correlation coefficient, symbolized by the letter r, which measures the strength and direction of a linear relationship between two variables. The value of r ranges from -1.00 to +1.00, with positive values indicating a positive linear relationship and negative values indicating a negative linear relationship. The closer the value of r is to -1 or +1, the stronger the linear relationship is.
For option (a), it is not possible for r to have a value of 1.2 as it must be within the range of -1.00 to +1.00, making option (a) incorrect. Option (b) is also incorrect because changing the scale of the temperature from Fahrenheit to Celsius does not affect the value of r; the strength and direction of the correlation remain the same regardless of the units used. Regarding options (c) and (d), usually when an outlier that does not follow the overall pattern of the data is removed, the absolute value of r tends to increase, which means that if the outlier was negatively influencing the correlation, r would increase, indicating option (c) is correct. In the event the outlier has a positive influence on the correlation, r would decrease but this specific information is not provided.
A CAT scan produces equally spaced cross-sectional views of a human organ that provide information about the organ otherwise obtained only by surgery. Suppose that a CAT scan of a human liver shows cross-sections spaced 1.5 cm apart. The liver is 15 cm long and the cross-sectional areas, in square centimeters,are 0,17,58,77,95,106,118,127,63,,40 and 0. Use the Midpoint Rule with n = 5 to estimate the volume V of the liver.
Answer:
X XCX X X C C C C C CC C C C C C C C C C C C C C CC C C SC S DCSD VSDCS CS CSDV SD SDC D D D VD DFV DF DFV DF
Step-by-step explanation:
The estimated volume of the liver using the Midpoint Rule with n = 5 is approximately 1051.5 cubic centimeters.
To estimate the volume V of the liver using the Midpoint Rule with n = 5 , we need to first find the average area of adjacent cross-sections and then multiply it by the distance between these cross-sections.
Given the cross-sectional areas: 0, 17, 58, 77, 95, 106, 118, 127, 63, 40, and 0.
We will partition these areas into 5 equal intervals and use the midpoint of each interval to estimate the average area.
Interval 1: 0, 17
Interval 2: 17, 58
Interval 3: 58, 77
Interval 4: 77, 95
Interval 5: 95, 106
Interval 6: 106, 118
Interval 7: 118, 127
Interval 8: 127, 63
Interval 9: 63, 40
Interval 10: 40, 0
Now, we calculate the midpoints of each interval:
Midpoint 1: (0 + 17)/2 = 8.5
Midpoint 2: (17 + 58)/2 = 37.5
Midpoint 3: (58 + 77)/2 = 67.5
Midpoint 4: (77 + 95)/2 = 86
Midpoint 5: (95 + 106)/2 = 100.5
Midpoint 6: (106 + 118)/2 = 112
Midpoint 7: (118 + 127)/2 = 122.5
Midpoint 8: (127 + 63)/2 = 95
Midpoint 9: (63 + 40)/2 = 51.5
Midpoint 10: (40 + 0)/2 = 20
Next, we find the average area of these intervals:
[tex]\( A_1 = 8.5 \)[/tex], [tex]\( A_2 = 37.5 \)[/tex], [tex]\( A_3 = 67.5 \)[/tex], [tex]\( A_4 = 86 \)[/tex], [tex]\( A_5 = 100.5 \)[/tex], [tex]\( A_6 = 112 \)[/tex], [tex]\( A_7 = 122.5 \)[/tex], [tex]\( A_8 = 95 \)[/tex], [tex]\( A_9 = 51.5 \)[/tex], [tex]\( A_{10} = 20 \)[/tex]
Now, we use the Midpoint Rule formula to estimate the volume:
[tex]\[ V \approx \Delta x \sum_{i=1}^{n} A_i \][/tex]
Where [tex]\( \Delta x \)[/tex] is the distance between cross-sections, given as 1.5 cm, and n = 5 intervals.
V [tex]\approx[/tex] 1.5 * (8.5 + 37.5 + 67.5 + 86 + 100.5 + 112 + 122.5 + 95 + 51.5 + 20) \]
[tex]\[ V \approx 1.5 \times (701) \][/tex]
[tex]\[ V \approx 1051.5 \][/tex]
So, the estimated volume of the liver using the Midpoint Rule with n = 5 is approximately 1051.5 cubic centimeters.
A factory makes rectangular sheets of cardboard, each with an area 2 1/2 square feet. Each sheet of cardboard can be cut into smaller pieces of cardboard measuring 1 1/6 square feet. How many smaller pieces of cardboard does each sheet of cardboard provide?
Answer:
Step-by-step explanation:
The area of each rectangular sheet of cardboard made by the factory is is 2 1/2 square feet. Converting
2 1/2 to improper fraction, it becomes 5/2 square feet.
Each sheet of cardboard can be cut into smaller pieces of cardboard measuring 1 1/6 square feet. Converting 1 1/6 to improper fraction, it becomes 7/6 square feet.
Therefore, the number of smaller pieces of cardboard that each sheet of cardboard provides is
5/2 ÷ 7/6 = 5/2 × 6/7 = 30/14
= 2.14 pieces
Let A = {•, □, ⊗} and B = {□, ⊖, •}. (a) List the elements of A×B and B ×A. The parentheses and comma in an ordered pair are not necessary in cases such as this where the elements of each set are individual symbols.
Answer:
Elements of AxBb and BxA have been listed in the attached file
Step-by-step explanation:
The concept applied is that of binary operation and generally using the rule of combining more than one operations sign in either communitative or associative property as shown in the attachment.
Assume that a procedure yields a binomial distribution with a trial repeated n times. Using the binomial probability formula, what is the probability of x successes given the probability p of success on a single trial? Round your answer to three decimal places.
Answer:
[tex]P(X=5)=(30C5)(0.2)^5 (1-0.2)^{30-5}=0.172[/tex]
Step-by-step explanation:
Assuming this complete question :"Assume that a procedure yields a binomial distribution with a trial repeated n times. Using the binomial probability formula, what is the probability of x successes given the probability p of success on a single trial? Round your answer to three decimal places.
n=30, x= 5, p=1/5"
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Solution to the problem
Let X the random variable of interest, on this case we know that:
[tex]X \sim Binom(n=30, p=0.2)[/tex]
The probability mass function for the Binomial distribution is given as:
[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]
Where (nCx) means combinatory and it's given by this formula:
[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]
And for this case if we find the probability for x=5 we got:
[tex]P(X=5)=(30C5)(0.2)^5 (1-0.2)^{30-5}=0.172[/tex]
Madison is carrying a 11.3 liter jug of sports drink that weighs 7 kg.
What is the constant multiple of liters in a jug to the weight in kilograms?
Incorrect
Note: The constant multiple should be a reduced fraction,
not a mixed number.
Answer:
[tex]\large\boxed{\large\boxed{constat\text{ }multiple=\frac{113liter}{70kg}}}[/tex]
Explanation:
The constant multiple of liters in a jug to the weight in kilograms is the ratio or fraction that represents the number of liters of the sports drink in a jug to the weight.
[tex]constat\text{ }multiple=ratio=\frac{number\text{ }of\text{ }liters}{weight\text{ }in\text{ }kg}[/tex]
[tex]constat\text{ }multiple=\frac{11.3liter}{7kg}[/tex]
Convert the fraction into an equivalent fraction with integer numbers:
[tex]constat\text{ }multiple=\frac{11.3liter\times 10}{7kg\times 10}=\frac{113liter}{70kg}[/tex]
Since, the fraction cannot be reduced, that is the answer.
From a sample with n = 32, the mean number of televisions per household is 4 with a standard deviation of 1 television. UsingChebychev's Theorem, determine at least how many of the households have between 2 and 6 televisions.At least ____ of the households have between 2 and 6 televisions.
Answer:
Atleast, 88.9% of the households have between 2 and 6 televisions.
Step-by-step explanation:
We are given the following in he question:
Sample size, n = 32
Mean, μ = 4
Standard Deviation, σ = 1
Chebychev's Theorem:
I states that atleast [tex]1 - \dfrac{1}{k^2}[/tex] percent of data lies within k standard deviations for a non normal data.For k = 2[tex]1-\dfrac{1}{2^2} = 0.75[/tex]
Atleast 75% of data lies within 2 standard deviation of mean.
For k = 3[tex]1-\dfrac{1}{3^2} = 0.889[/tex]
Atleast 88.9% of data lies within 3 standard deviation of mean.
[tex]2 = \mu - 2\sigma = 4 - 2(1)\\6 = \mu + 2\sigma = 4 +2(1)[/tex]
Thus, we have to find data within two standard deviations.
Atleast, 88.9% of the households have between 2 and 6 televisions.
Chebychev's Theorem allows us to determine the proportion of data within a certain number of standard deviations from the mean. In this case, using the formula z = (x - μ) / σ, we find that at least 75% of the households have between 2 and 6 televisions.
Explanation:Chebychev's Theorem allows us to determine the proportion of data within a certain number of standard deviations from the mean.
In this case, we want to find the proportion of households with between 2 and 6 televisions. To do this, we need to find out how many standard deviations away from the mean these values are.
The number of standard deviations away from the mean can be calculated using the formula z = (x - μ) / σ, where z is the number of standard deviations from the mean, x is the value we're interested in, μ is the mean, and σ is the standard deviation.
For x = 2, z = (2 - 4) / 1 = -2
For x = 6, z = (6 - 4) / 1 = 2
According to Chebychev's Theorem, no less than 1 - 1/k^2 of the data falls within k standard deviations from the mean. In this case, we're interested in the proportion of data between -2 and 2 standard deviations from the mean.
k = 2 (the distance between -2 and 2), so k^2 = 4.
Thus, the proportion of data within -2 and 2 standard deviations from the mean is equal to 1 - 1/4 = 3/4 = 0.75.
Therefore, at least 75% of the households have between 2 and 6 televisions.
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Find the domain of f and f −1 and its domain. f(x) = ln(ex − 3). (a) Find the domain of f. (Enter your answer using interval notation.) (−2,[infinity]) (b) Find f −1. f −1(x) = x+ln(3)
Answer:
a.Domain of f=(1.099,[tex]\infty)[/tex]
b.[tex]f^{-1}(x)=ln(e^x+3)[/tex]
Step-by-step explanation:
Let [tex]y=f(x)=ln(e^x-3)[/tex]
We know that domain of ln x is greater than zero
[tex]e^x-3>0[/tex]
Adding 3 on both sides of inequality
[tex]e^x-3+3>0+3[/tex]
[tex]e^x>3[/tex]
Taking on both sides of inequality
[tex]lne^x>ln 3[/tex]
[tex]x>ln 3[/tex]=1.099
By using [tex]lne^x=x[/tex]
Domain of f=(1.099,[tex]\infty)[/tex]
Let [tex]y=f^{-1}(x)=ln(e^x-3)[/tex]
[tex]e^y=e^x-3[/tex]
By using property [tex]lnx=y\implies x=e^y[/tex]
[tex]e^x=e^y+3[/tex]
Taking ln on both sides of equality '
[tex]lne^x=ln(e^y+3)[/tex]
[tex]x=ln(e^y+3)[/tex]
Replace x by y and y by x
[tex]y=ln(e^x+3)[/tex]
Substitute y=[tex]f^{-1}(x)[/tex]
[tex]f^{-1}(x)=ln(e^x+3)[/tex]
In expanded notation, the hexadecimal 74AF16 is (7*4096) + (4*256) + (A*16) + (F*1). When converting from hexadecimal to decimal, what value is assigned to F?
Answer:
F is assigned the value of 15
[tex]74AF_{16} = 29871_{10}[/tex]
Step-by-step explanation:
Hexadecimal number system is base 16 and it contain the following numbers:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F
A has a value of 10
B has a value of 11
C has a value of 12
D has a value of 13
E has a value of 14
F has a value of 15
By completing the expanded notation:
[tex](7*4096) + (4*256) + (A * 16) + (F *1)\\= (7*4096) + (4*256) + (10 * 16) + (15 *1)\\= 28672 + 1024 + 160 + 15\\= 29871[/tex]
In hexadecimal notation, the letter 'F' corresponds to the decimal value 15. Therefore, when converting from hexadecimal to decimal, you would assign the value 15 to 'F'.
Explanation:In hexadecimal notation, the letters A through F correspond to the decimal values 10 through 15, respectively. When converting from hexadecimal to decimal, you would replace the hexadecimal digit 'F' with its decimal equivalent. Therefore, in the hexadecimal system, the letter 'F' signifies the decimal number 15. To calculate the value of 74AF16 in decimal, you replace 'F' with 15 and compute the expression (7*4096) + (4*256) + (10*16) + (15*1).
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Ask Your Teacher Write out the form of the partial fraction decomposition of the function (See Example). Do not determine the numerical values of the coefficients. (If the partial fraction decomposition does not exist, enter DNE.) (a) x x2 + x − 20 (b) x2 x2 + x + 2
The partial fraction are:
a) [tex](x / (x^2 + x - 20))[/tex] = [tex]\dfrac{x}{x^2 + x - 20} = \dfrac{A}{(x - 4)} + \dfrac{B}{(x + 5)}[/tex]
b) [tex]\dfrac{x}{x^2 + x + 2} = \dfrac{A}{(x +1)} + \dfrac{B}{(x + 2)}[/tex]
(a) The partial fraction decomposition of the function [tex](x / (x^2 + x - 20))[/tex] can be written as:
[tex]\dfrac{x}{x^2 + x - 20} = \dfrac{A}{(x - 4)} + \dfrac{B}{(x + 5)}[/tex]
where A and B are constants.
(b) The partial fraction decomposition of the function [tex]\dfrac{x}{x^2 + x - 20}[/tex] can be written as:
[tex]\dfrac{x}{x^2 + x + 2} = \dfrac{A}{(x +1)} + \dfrac{B}{(x + 2)}[/tex]
where A and B are constants.
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The student is asked to perform partial fraction decomposition for two functions. In the first case, the given rational function decomposes to the form: A/(x - 4) + B/(x + 5). In the second case, the decomposition does not exist as the denominator can't be factored using real numbers.
Explanation:In mathematics, the concept under discussion is the partial fraction decomposition. This is a process used in algebra to break down complex fractions or rational expressions into simpler ones. Given (a) x/(x^2 + x - 20) and (b) x^2/(x^2 + x + 2), you are being asked to perform the decomposition.
For (a), the denominator, x^2 + x - 20, can be factored as (x - 4)(x + 5), so the partial fraction decomposition would have the form: x/(x^2 + x - 20) = A/(x - 4) + B/(x + 5).
For (b), since the denominator x^2 + x + 2 can't be factored using real numbers, the partial fraction decomposition doesn't exist. Here, the answer would be DNE (Does Not Exist).
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Select the null and the alternative hypotheses for the following tests:
a. Test if the mean weight of cereal in a cereal box differs from 18 ounces.
O H0: μ = 18; HA: μ ≠ 18
O H0: μ ≥ 18; HA: μ < 18
O H0: μ ≤ 18; HA: μ > 18
b. Test if the stock price increases on more than 60% of the trading days.
O H0: p ≤ 0.60; HA: p > 0.60
O H0: p ≥ 0.60; HA: p < 0.60
O H0: p = 0.60; HA: p ≠ 0.60
c. Test if Americans get an average of less than seven hours of sleep.
O H0: μ ≥ 7; HA: μ < 7
O H0: μ ≤ 7; HA: μ > 7
O H0: μ = 7; HA: μ ≠ 7
Answer:
Option A)
[tex]H_{0}: \mu = 18\text{ ounces}\\H_A: \mu \neq 18\text{ ounces}[/tex]
Option A)
[tex]H_{0}: p \leq 0.6\\H_A: p > 0.6[/tex]
Option A)
[tex]H_{0}: \mu \geq 7\text{ hours}\\H_A: \mu \leq 7\text{ hours}[/tex]
Step-by-step explanation:
We have to design null and alternate hypothesis for given test:
a) Test if the mean weight of cereal in a cereal box differs from 18 ounces.
Option A)
[tex]H_{0}: \mu = 18\text{ ounces}\\H_A: \mu \neq 18\text{ ounces}[/tex]
The null hypothesis means mean cereal box weight is 18 ounces and the alternate hypothesis state that it is different than 18 ounces.
b) Test if the stock price increases on more than 60% of the trading days.
Option A)
[tex]H_{0}: p \leq 0.6\\H_A: p > 0.6[/tex]
The null hypothesis states that the proportion is less than 0.6 that is stock price is less than or equal to 60% of the trading days and alternate hypothesis states that the proportion is greater than 0.6 that is stock price increases on more than 60% of the trading days.
c) Test if Americans get an average of less than seven hours of sleep.
Option A)
[tex]H_{0}: \mu \geq 7\text{ hours}\\H_A: \mu \leq 7\text{ hours}[/tex]
The null hypothesis states that the Americans get an average of greater than or equal to 7 hours of sleep where as the alternate hypothesis states that the Americans get a sleep less than 7 hours of sleep.
In a normally distributed data set with a mean of 19 and a standard deviation of 2.6, what percentage of the data would be between 16.4 and 21.6?
Answer:
68.26% of the data would be between 16.4 and 21.6.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 19, \sigma = 2.6[/tex]
What percentage of the data would be between 16.4 and 21.6?
This is the pvalue of Z when X = 21.6 subtracted by the pvalue of Z when X = 16.4. So
X = 21.6
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{21.6 - 19}{2.6}[/tex]
[tex]Z = 1[/tex]
[tex]Z = 1[/tex] has a pvalue of 0.8413.
X = 16.4
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{16.4 - 19}{2.6}[/tex]
[tex]Z = -1[/tex]
[tex]Z = -1[/tex] has a pvalue of 0.1587
So 0.8413 - 0.1587 = 0.6826 = 68.26% of the data would be between 16.4 and 21.6.
Answer: Percentage = 0.6826 X 100 = 68.26%
Step-by-step explanation: Please find the attached document for the step by step explanation
Mt. McKinley, in Alaska, is the highest mountain in North America at 20,320
feet. A climbing team made it 5/8 of the way to the summit before a storm forced them to turn back. What was their elevation when the storm hit?
Answer:
12700 feet
Step-by-step explanation:
Do 5/8 of 20,320
Do 20320 divided by 8 which is 2540
Do 2540 times 5 which is 12700
A small radio transmitter broadcasts in a 44 mile radius. If you drive along a straight line from a city 60 miles north of the transmitter to a second city 59 miles east of the transmitter, during how much of the drive will you pick up a signal from the transmitter?
Answer: 87.03
Step-by-step explanation:
The outer parts (2) of the secant line containing α and β refers to the distance travelled where there is no signal. The middle part is where there is signal presence. To get the altitude of the triangle:
Hc= 2(A/c)
To find the area;
A= 1/2(59)(60)
A= 1770
Use Pythagoras theorem to get c:
C= =√(60)^2+(59)^2
=√7081
Hc=2(1770/√7081)
=3540√7081/7081
Solve for x using Pythagoras theorem:
x= (√44^2-Hc^2) + (√44^2-Hc^2)
where Hc= 3540√7081/7081
=87.03
By interpreting the problem geometrically and using Pythagoras' theorem, it can be concluded that for approximately 34 miles of the journey from the city 60 miles north of the transmitter to the city 59 miles east of the transmitter will be in range of the radio signal.
Explanation:This problem can be solved using geometry and the concept of a circle. If we imagine the area the radio transmitter can reach as a circle with the transmitter at the center, any point within a 44-mile radius from the transmitter can pick up its signal. Now, let's analyze the specific scenario proposed.
Firstly, the city 60 miles north is outside the signal range. However, as you drive towards the second city 59 miles east of the transmitter, you'll at some point enter the broadcast range. That's because, at the closest point, you're only about 15 miles away from the transmitter (60 miles - 44 miles), assuming you drive perpendicular to the diameter of the transmission circle.
You need to calculate the intersection of your driving path with the transmission circle. Using Pythagoras' theorem, it can be seen that for about 34 miles of your direct journey from the first city to the second city, you would be in range of the transmitter. The two cities form the hypotenuse of a right triangle, and that hypotenuse intersects the transmission circle creating a segment along which signal will be received.
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Listed below are foot lengths in inches for 11 randomly selected people taken in 1988. Find the range, variance, and standard deviation for the given sample data. Include appropriate units in the results. Are the statistics representative of the current population of all people? 9.9 8.7 10.1 9.2 9.2 9.9 0.1 9.4 9.1 9.3 10.2 The range of the sample data is (Type an integer or a decimal. Do not round.) The standard deviation of the sample data is (Round to two decimal places as needed.) people inches2 inches. people. The variance of the sample data is (Round to two decimal places as needed.) Are the statistics representative of the current por A. Since the measurements were made in 15 le? sarily representative of the population today B. The statistics are representative because te snuaru uevation of the sample data is less than 1 C. The statistics are not representative because a smaller sample is needed to represent the population D. The statistics are representative because they are taken from a random sample
Answer:
[tex] Range= Max-Min= 10.2-8.7=1.5 inches[/tex]
[tex] s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And if we replace we got [tex] s = 0.50 inches[/tex]
[tex] s^2 = 0.503^2 = 0.25 in^2[/tex]
D. The statistics are representative because they are taken from a random sample
Step-by-step explanation:
For this case we have the following data:
9.9 8.7 10.1 9.2 9.2 9.9 10.1 9.4 9.1 9.3 10.2
The data was colledted from a random sample of people selected in 1988.
We can order the dataset on increasing way and we got:
8.7 9.1 9.2 9.2 9.3 9.4 9.9 9.9 10.1 10.1 10.2
The range is defined as [tex] Range= Max-Min= 10.2-8.7=1.5 inches[/tex]
The mean is defined as:
[tex]\bar X =\frac{\sum_{i=1}^n X_i}{n}= 9.555 inches[/tex]
The standard deviation can be calculated with the following formula:
[tex] s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And if we replace we got [tex] s = 0.50 inches[/tex]
The sample variance would be just the deviation squared:
[tex] s^2 = 0.503^2 = 0.25 in^2[/tex]
And since the data comes from a random sample then is representative fo the population data in 1988. So then the best answer for this case would be:
D. The statistics are representative because they are taken from a random sample
Final answer:
The range, variance, and standard deviation must be calculated from the given data, but their representativeness for the current population is not guaranteed, especially due to changes since 1988 and potential sampling issues.
Explanation:
To calculate the range, variance, and standard deviation for the provided sample data of foot lengths, first, we must find the smallest and largest values to determine the range. In this set, the smallest value is 0.1 inches, and the largest is 10.2 inches, so the range is 10.2 - 0.1 = 10.1 inches.
To find the variance and standard deviation, we need the sum of the squared deviations from the mean, divided by the number of observations minus one for the sample variance, and then the square root of the variance for the standard deviation.
The representativeness of these statistics for the current population depends on various factors, including changes in population demographics and sampling methods. A single small sample, especially with an outlying value such as 0.1, may not be indicative of the entire population's foot sizes today.
Hence, the correct answer is A: 'Since the measurements were made in 1988, they may not necessarily be representative of the population today.'
How do I solve this using the substitution method 3x+2y=9 x-5y=4
[tex]\bf \begin{cases} 3x+2y=9\\ x-5y=4 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{solving the 2nd equation for "y"}}{x-5y = 4\implies x-4-5y=0}\implies x-4=5y\implies \cfrac{x-4}{5}=y \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting on the 1st equation}}{3x+2\left(\cfrac{x-4}{5} \right) = 9}\implies 3x+\cfrac{2(x-4)}{5}=9 \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{5}}{5\left( 3x+\cfrac{2(x-4)}{5} \right)=5(9)}\implies 15x+2(x-4)=45[/tex]
[tex]\bf 15x+2x-8=45\implies 17x-8=45\implies 17x=53\implies \boxed{x=\cfrac{53}{17}} \\\\\\ \stackrel{\textit{we know that}}{\cfrac{x-4}{5}=y}\implies \cfrac{\left(\frac{53}{17} -4 \right)}{5}=y\implies \cfrac{\left(\frac{53-68}{17} \right)}{5}=y\implies \cfrac{~~\frac{-15}{17}~~}{5}=y \\\\\\ \cfrac{~~\frac{-15}{17}~~}{\frac{5}{1}}=y\implies \cfrac{-15}{17}\cdot \cfrac{1}{5}=y\implies \boxed{-\cfrac{3}{17}=y} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \left( \frac{53}{17}~~,~~-\frac{3}{17} \right)~\hfill[/tex]
Answer: x = 57/17
y = - 3/17
Step-by-step explanation:
The given system of equations is expressed as
3x + 2y = 9 - - - - - - - - - - - - - -1
x - 5y = 4 - - - - - - - - - - - - - - -2
From equation 2, we would make x the subject of the formula by adding 5y to the left hand side and the right hand side of the equation. It becomes
x - 5y + 5y = 4 + 5y
x = 4 + 5y
Substituting x = 4 + 5y into equation 1, it becomes.
3(4 + 5y) + 2y = 9
12 + 15y + 2y = 9
15y + 2y = 9 - 12
-7y = - 3
y = - 3/17
Substituting y = - 3/17 into equation x = 4 + 5y, it becomes
x = 4 + 5 × - 3/17
x = 4 - 15/17
x = (68 - 15)/17
x = 53/17
A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. The volume of each small box is 7 cubic feet and the volume of each large box is 13 cubic feet. A total of 26 boxes of paper were shipped with a combined volume of 254 cubic feet. Determine the number of small boxes shipped and the number of large boxes shipped.
Step-by-step explanation:
Let's say S is the number of small boxes and L is the number of large boxes.
S + L = 26
7S + 13L = 254
Solve the system of equations using substitution.
7S + 13(26 − S) = 254
7S + 338 − 13S = 254
84 − 6S = 0
S = 14
L = 26 − S
L = 12
The company shipped 14 small boxes and 12 large boxes.
Answer:14 small boxes and 12 large boxes were shipped.
Step-by-step explanation:
Let x represent the number of small boxes of paper that were shipped.
Let y represent the number of large boxes of paper that were shipped.
A total of 26 boxes of paper were shipped. This means that
x + y = 26
The volume of each small box is 7 cubic feet and the volume of each large box is 13 cubic feet. The total number of boxes shipped have a combined volume of 254 cubic feet. This means that
7x + 13y = 254 - - - - - - - - - - - - 1
Substituting x = 26 - y into equation 1, it becomes
7(26 - y) + 13y = 254
182 - 7y + 13y = 254
- 7y + 13y = 254 - 182
6y = 72
y = 72/6 = 12
x = 26 - y = 26 - 12
x = 14
A library wants to determine the effectiveness of their summer literacy program among low-income children. Because surveying the large numbers of students in the program would require too many resources the library staff interviews 30 randomly chosen children among the low-income program attendees. The 30 sampled children are given a reading test before and after the program.A) The difference in the reading test scores (after – before) has mean 10 and standard deviation 4. Assuming the score differences are normally distributed, what percent of the children showed any improvement (difference > 0) in reading ability?B) What percent of children improved by more than 15 points?
Answer:
(A) P (D > 0) = 99.38%
(B) P (D > 15) = 10.56%
Step-by-step explanation:
The random variable D = difference, is defined as the difference between the reading test scores after and before the program.
The random variable D follows a normal distribution with mean, [tex]\mu_{D}=10[/tex] and standard deviation, [tex]\sigma_{D}=4[/tex].
(A)
Compute the probability that the children showed any improvement, i.e.
P (D > 0):
[tex]P(D>0)=P(\frac{D-\mu_{D}}{\sigma_{D}} >\frac{0-10}{4} )=P(Z>-2.5)=P(Z<2.5)[/tex]
Use the standard normal random variable to determine the probability.
[tex]P(D>0)=P(Z<2.5)=0.9938[/tex]
The percentage of children showed any improvement is:
0.9938 × 100 = 99.38%
Thus, 99.38% of children showed improvement.
(B)
Compute the probability that the children improved by more than 15 points, i.e. P (D > 15):
[tex]P(D>15)=P(\frac{D-\mu_{D}}{\sigma_{D}} >\frac{15-10}{4} )=P(Z>1.25)=1-P(Z<1.25)[/tex]
Use the standard normal random variable to determine the probability.
[tex]P(D>0)=1-P(Z<1.25)=1-0.8944=0.1056[/tex]
The percentage of children improved by more than 15 points is:
0.1056 × 100 = 10.56%
Thus, 10.56% of children showed improvement by more than 15 points.
50% of children showed some improvement, while 10.56% improved their reading scores by more than 15 points during the summer literacy program.
Explanation:The library staff is utilizing statistical analysis to assess the effectiveness of their summer literacy program. They have chosen a sample of 30 children out of the many who attended, and provided scores both before and after the program. A mean difference score of 10 and a standard deviation of 4 were determined. This question asks to find out the percentage of students who have improved based on these scores (positive score difference) and those who have improved by more than 15 points.
Firstly, we are assuming that the score differences follow a normal distribution. In a normal distribution, half of the results fall on either side of the mean. Since we are looking for an improvement, we only consider the side above the mean score difference, which is equivalent to 50% of all students.
Secondly, to find the percent of children who improved by more than 15 points, we need to calculate the z-score for the score difference of 15. Z-score is calculated as (X - μ) / σ, where X is the score, μ is the mean, and σ is the standard deviation. So, Z = (15 - 10) / 4 = 1.25.
The z-score of 1.25 corresponds to an area of 0.8944 to the left under a standard table of normal distribution. To get the area to the right (which represents the students who improved by >15), we subtract this from 1. So, 1 - 0.8944 = 0.1056 or 10.56% students improved by more than 15 points.
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The variable c varies directly with a and inversely with b, and c = 3/20 when a = 2 and b =5.
The constant variation is K =
Answer: k = 200/3
Step-by-step explanation:
If a variable, a varies directly with a variable, c, it means that as a increases, c increases and as a decreases, c decreases.
Also, If a variable, a varies inversely with a variable, b, it means that as a increases, b decreases and as a decreases, c increases.
The variable c varies directly with a and inversely with b. We would introduce a constant of variation, k. Therefore
a = kc/b
If c = 3/20 when a = 2 and b =5, then
2 = (k × 3/20)/5 = 3k/100
Cross multiplying, it becomes
3k = 100 × 2 = 200
k = 200/3
Answer: k=3/8 c=3/40
Step-by-step explanation:
just took the assignment on edg
an=an−1−4 a1=15 to explicit formula
The explicit formula for the sequence given by an = an-1 - 4 with a1 = 15 is an = 19 - 4n, which is derived using the general formula for an arithmetic sequence.
Explanation:The question asks to derive the explicit formula for a sequence given by the recursive formula an = an-1 - 4 with the initial term a1 = 15. To find the explicit formula, we recognize this as an arithmetic sequence where the common difference (d) is -4 and the first term (a1) is 15.
The formula for the nth term of an arithmetic sequence is given by an = a1 + (n - 1)d. Substituting a1 = 15 and d = -4 into this formula gives us:
an = 15 + (n - 1)(-4)
Simplifying, we get an = 19 - 4n. This is the explicit formula for the given sequence, allowing us to find any term in the sequence without needing to calculate all the previous terms.
Is there a real number whose square is −1? a. Is there a real number x such that ? b. Does there exist such that x2 = −1?
Answer:
a.[tex]x^2=-1[/tex]
b.a real number x
Step-by-step explanation:
We are given that statement.
We have to rewrite the given statement using variable or variables.
Statement:Is there a real number whose square is -1.
a.Let x bet the real number
The square of real number x written as [tex]x^2[/tex]
According to question
[tex]x^2=-1[/tex]
Therefore,
Is there a real number x such that [tex]x^2=-1[/tex]
b.Does there exist a real number x such that
[tex]x^2=-1[/tex]
There is no real number whose square is -1. However, in the domain of complex numbers, 'i' is defined as the square root of -1. Complex numbers include both real and imaginary parts.
Explanation:In the realm of real numbers, there isn't a real number whose square is -1. In the context of complex numbers, however, 'i' is defined to be the square root of -1. In other words, i2 = -1. It's important to note that complex numbers consist of a real part and an imaginary part (where 'i' is the basis for the imaginary part), and are beyond the usual scope of real numbers.
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We apply the Empirical Rule when the relative frequency distribution of the sample is not bell-shaped or symmetric Group of answer choices True False
Answer:
We can conclude that this statement is False. Because the Empirical Rule does not apply to data sets with severely asymmetric distributions, since by definition the use of the rule is satisfied just for symmetric distributions like the normal distribution.
And if the distribution is not bell shaped or symmetric then we can't use it.
Step-by-step explanation:
Previous concepts
The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). "Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".
Solution to the problem
We can conclude that this statement is False. Because the Empirical Rule does not apply to data sets with severely asymmetric distributions, since by definition the use of the rule is satisfied just for symmetric distributions like the normal distribution.
And if the distribution is not bell shaped or symmetric then we can't use it.
The statement 'We apply the Empirical Rule when the relative frequency distribution of the sample is not bell-shaped or symmetric' is False. The Empirical Rule is applied when the distribution of the data is bell-shaped and symmetric.
The statement 'We apply the Empirical Rule when the relative frequency distribution of the sample is not bell-shaped or symmetric' is False.
The Empirical Rule is applied when the distribution of the data is bell-shaped and symmetric.
It states that approximately 68% of the data is within one standard deviation of the mean, 95% is within two standard deviations, and more than 99% is within three standard deviations.
Therefore, the Empirical Rule is not applied when the data is not bell-shaped or symmetric.
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PLEASE HELP 50 COINS!!!!
Answer: 12.22
Step-by-step explanation:
Since it is a right angled triangle, we use the trigonometry method of solving triangles for this question.
The given angle is 42° and we recall our trigonometry functions of
Sin Φ = opposite/hypotenuse
Cos Φ= adjacent/hypotenuse
tan Φ = opposite/adjacent
Where
Φ =42°
Opposite of the angle = GH = 11
Adjacent of the angle = HI = ?.
Hence we use the tan Formula.
tan 42 = 11/HI
HI = 11/tan42
HI = 11/0.90
HI = 12.22
The position of an object moving vertically along a line is given by the function s(t) = -16t^2 + 128t. Find the average velocity of the object over the following intervals.
a. [1, 4]
b. [1, 3]
c. [1, 2]
d. [1, 1 + h], where h > 0 is a real number
Answer:
a) 48
b) 64
c) 80
d) 96-16h
Step-by-step explanation:
a) s(1)=112 and s(4)=256
average velocity on [1,4] = (256-112)/(4-1) = 48
b) s(1)=112 and s(3)=240
average velocity on [1,3] = (240-112)/(3-1) = 64
c) s(1)=112 and s(2)=192
average velocity on [1,2] = (192-112)/(2-1) = 80
the next one's tricky to type. watch the parentheses carefully:
d) s(1)=112 and s(1+h)= -16(1+h)^2 + 128(1+h)
average velocity on [1,1+h] =
(s(1+h) - s(1))/((1+h)-1) = (-16(1+h)^2 +128(1+h) - (112))/h
= (-16(1+2h+h^2)+128+128h - 112)/h
= ( -16 -32h -16h^2 + 16 + 128h)/h
= ( 96h - 16 h^2)/h
= 96 - 16h
Two birds sit at the top of two different trees. The distance between the first bed and a birdwatcher on the ground is 34 feet the distance between the birdwatcher and the second bird is 47 feet What is the angle measure or angle of
depression between this bed and the birdwatcher? Round your answer to the nearest tenth
Answer:
Step-by-step explanation:
The given triangle is a right angle triangle.
The distance between the first bed and the bird watcher on the ground represents the opposite side of the right angle triangle.
The distance between the birdwatcher and the second bird is 47 feet. This represents the hypotenuse of the right angle triangle. To determine the angle of depression, x degrees, we would apply the Sine trigonometric ratio which is expressed as
Sin θ = opposite side/hypotenuse
Sin x = 34/47 = 0.723
x = Sin^-1(0.723)
x = 46.3 degrees to the nearest tenth.
Answer:
46.3 degrees or answer D
Step-by-step explanation:
lol
What is the surface area of the figure?
240
48
192
Answer:
240 cm²
Step-by-step explanation:
We are required to determine the surface area of the figure;
To get the area we add the are of all the surfaces;
Area of triangle;
Area = 0.5 × b × h
There are two triangles;
Therefore;
Area of the two triangles;
Area = 0.5 × 6 × 8 × 2
= 48 cm²
Area of the rectangles;
Area of a rectangle = Length × width
Area of the first rectangle;
= 6 cm × 8 cm
= 48 cm²
Area of the second rectangle
= 8 cm × 8 cm
= 64 cm²
Area of the third rectangle
= 10 cm × 8 cm
= 80 cm²
The total surface area will be;
Area = 48 cm² + 48 cm² + 64 cm² + 80 cm²
= 240 cm²
Beverages account for about ________ of the added sugars consumed in the U.S. a. 50% b. 90% c. 10% d. 75% e. 25%
Answer:
The answer is a. 50%
Explanation:
Beverages (which include energy drinks, fruit drinks, sweetened coffee and tea, soft drinks, energy drinks, alcoholic beverages, etc.) are the major source of added sugars that are being consumed by the population of the United States: it accounts for almost half (around 50%) of added sugars consumed.
Beverages account for about 75% of the added sugars consumed in the U.S.
Explanation:Beverages account for about 75% of the added sugars consumed in the U.S. This includes soda, fruit drinks, sports drinks, and energy drinks. These beverages are often high in sugar and can contribute to weight gain and other health issues.
It's important to be mindful of our consumption of sugary beverages and choose healthier alternatives like water, unsweetened tea, or low-sugar options.
Therefore, The correct answer is d. 75%.
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Verify that y1(t) = 1 and y2(t) = t ^1/2 are solutions of the differential equation:
yy'' + (y')^ 2 = 0, t > 0. (3)
Then show that for any nonzero constants c1 and c2, c1 + c2t^1/2 is not a solution of this equation.
Answer: it is verified that:
* y1 and y2 are solutions to the differential equation,
* c1 + c2t^(1/2) is not a solution.
Step-by-step explanation:
Given the differential equation
yy'' + (y')² = 0
To verify that y1 solutions to the DE, differentiate y1 twice and substitute the values of y1'' for y'', y1' for y', and y1 for y into the DE. If it is equal to 0, then it is a solution. Do this for y2 as well.
Now,
y1 = 1
y1' = 0
y'' = 0
So,
y1y1'' + (y1')² = (1)(0) + (0)² = 0
Hence, y1 is a solution.
y2 = t^(1/2)
y2' = (1/2)t^(-1/2)
y2'' = (-1/4)t^(-3/2)
So,
y2y2'' + (y2')² = t^(1/2)×(-1/4)t^(-3/2) + [(1/2)t^(-1/2)]² = (-1/4)t^(-1) + (1/4)t^(-1) = 0
Hence, y2 is a solution.
Now, for some nonzero constants, c1 and c2, suppose c1 + c2t^(1/2) is a solution, then y = c1 + c2t^(1/2) satisfies the differential equation.
Let us differentiate this twice, and verify if it satisfies the differential equation.
y = c1 + c2t^(1/2)
y' = (1/2)c2t^(-1/2)
y'' = (-1/4)c2t(-3/2)
yy'' + (y')² = [c1 + c2t^(1/2)][(-1/4)c2t(-3/2)] + [(1/2)c2t^(-1/2)]²
= (-1/4)c1c2t(-3/2) + (-1/4)(c2)²t(-3/2) + (1/4)(c2)²t^(-1)
= (-1/4)c1c2t(-3/2)
≠ 0
This clearly doesn't satisfy the differential equation, hence, it is not a solution.
Final answer:
The provided solutions y₁(t) = 1 and y₂(t) = [tex]t^{(1/2)[/tex] satisfy the given differential equation, verified through substitution and simplification. However, a linear combination of the form [tex]c_1 + c_2t^{(1/2)[/tex] is not a solution as it does not satisfy the original equation when its derivatives are substituted.
Explanation:
We are given the second-order differential equation yy'' + (y')² = 0, where y = y(t) is a function of t, and we are asked to verify solutions and understand properties of certain types of solutions to this equation.
To verify that y₁(t) = 1 is a solution, we calculate the derivatives: y₁' = 0 and y₁'' = 0. Substituting these into the differential equation yields (1)(0)+(0)² = 0, which holds true, confirming that y₁(t) = 1 is indeed a solution.
Next, to verify y₂(t) = [tex]t^{(1/2)[/tex], we find y₂' = [tex](1/2)t^{(-1/2)[/tex] and [tex]y_2'' = -(1/4)t^{(-3/2)[/tex]. Substituting these values gives [tex](t^{(1/2)})(-(1/4)t^{(-3/2)}) + ((1/2)t^{(-1/2)})^2 = 0[/tex], which simplifies to 0, showing that y₂(t) is also a solution.
For the linear combination of solutions, we consider [tex]y(t) = c_1 + c_2t^{(1/2)[/tex]. Derivatives are [tex]y' = c_2(1/2)t^{(-1/2)[/tex] and [tex]y'' = -c_2(1/4)t^{(-3/2)[/tex]. Substituting into the given differential equation does not yield zero, thus [tex]c_1 + c_2t^{(1/2)[/tex] is not a solution.