Pleeeeeeeeease help!!!!!!!

Answer:

Step-by-step explanation:

a) ΔACD ~ ΔABE so the ratios of corresponding sides are the same. That is ...

  CD/BE = CA/BA

  CD/3.8 = 12.3/8.2

  CD = 3.8×12.3/8.2 = 5.7 . . . . cm

__

b) As above, the ratios of corresponding sides are the same.

  ED/AD = BC/AC

  ED/9.15 = (12.3-8.2)/12.3 . . . . BC = AC - AB

  ED = 9.15×4.1/12.3 = 3.05 . . . . cm

Applying the knowledge of similar triangles to find the missing lengths:

a. the length of CD = 5.7 cm

b. the length of ED = 3.05 cm

The information for this problem has been put into a diagram for easy understanding (see attachment below).

Apply the knowledge of similar triangles to workout the lengths of CD and ED respectively.

Note:

Since Triangles ABE and ACD are similar triangles, therefore:

a. Find the length of CD:

AB = 8.2 cm

AC = 12.3 cm

BE = 3.8 cm

CD = ?

[tex]\frac{8.2}{12.3} = \frac{3.8}{CD}[/tex]

[tex]\frac{8.2}{12.3} = \frac{3.8}{CD}\\\\CD = \frac{3.8 \times 12.3}{8.2} = 5.7 $ cm[/tex]

b. Find the length of ED:

AD = 9.15 cm

AB/AC = AE/AD

[tex]\frac{8.2}{12.3} = \frac{AE}{9.15}[/tex]

[tex]AE = \frac{8.2 \times 9.15}{12.3} = 6.1 $ cm[/tex]

ED = AD - AE

ED = 9.15 - 6.1 = 3.05 cm

Therefore, applying the knowledge of similar triangles to find the missing lengths:

a. the length of CD = 5.7 cm

b. the length of ED = 3.05 cm

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Answer:

Answer a 187 ft

Answer:

The bus stop is approximately 186.687 feet far from the man.

Step-by-step explanation:

Here, the given function that shows the distance from the man to any object in the ground,

[tex]D=120 sec\theta[/tex]

Where, [tex]\theta[/tex] is the angle of his site line.

Given,

The site angle of man is 50° when he sees a bus stop,

That is, [tex]\theta = 50^{\circ}[/tex]

Hence, the distance of bus stop from the man is,

[tex]D = 120 sec 50^{\circ}[/tex]

[tex]=120(1.55572382686)[/tex]

[tex]=186.686859223\approx 186.687[/tex]

Hence, the bus stop is approximately 186.687 feet far from the man.

Answer:

  (n+2)(n+1)

Step-by-step explanation:

Write out the numerator and cancel common factors:

  (n+2)!/n! = (n+2)(n+1)n!/n! = (n+2)(n+1)

_____

You might be expected to multiply it out:

  = n·n +2·n +n·1 +2·1

  = n² +3n +2

Answer:

$20

Step-by-step explanation:

Since we are talking about the unknown cost of a shirt AND a sweater, we are dealing with 2 unknowns.  However, we can only have one unknown in a single equation or we cannot solve it.  The cost of the sweater is based on the cost of the shirt, so the shirt will be our "main" unknown.

Cost of the shirt:  x

Since the sweater is $5 more than (this is addition) twice (that is 2 times) the cost of the shirt, the expression for the sweater is 2x + 5

The cost of both is (equals) 65.

x + 2x + 5 = 65 and

3x + 5 = 65 and

3x = 60 so

x = 20

The shirt cost $20 so the sweater had to cost 65 - 20 = 45

Answer:

- 14π/9; 108°; -√2/2; √2/2

Step-by-step explanation:

To convert from degrees to radians, use the unit multiplier [tex]\frac{\pi }{180}[/tex]

In equation form that will look like this:

- 280° × [tex]\frac{\pi }{180}[/tex]

Cross canceling out the degrees gives you only radians left, and simplifying the fraction to its simplest form we have [tex]-\frac{14\pi }{9}[/tex]

The second question uses the same unit multiplier, but this time the degrees are in the numerator since we want to cancel out the radians.  That equation looks like this:

[tex]\frac{3\pi }{5}[/tex] × [tex]\frac{180}{\pi }[/tex]

Simplifying all of that and canceling out the radians gives you 108°.

The third one requires the reference angle of [tex]\frac{3\pi }{4}[/tex].

If you use the same method as above, we find that that angle in degrees is 135°.  That angle is in QII and has a reference angle of 45 degrees.  The Pythagorean triple for a 45-45-90 is (1, 1, √2).  But the first "1" there is negative because x is negative in QII.  So the cosine of this angle, side adjacent over hypotenuse, is [tex]-\frac{1}{\sqrt{2} }[/tex]

which rationalizes to [tex]-\frac{\sqrt{2} }{2}[/tex]

The sin of that angle is the side opposite the reference angle, 1, over the hypotenuse of the square root of 2 is, rationalized, [tex]\frac{\sqrt{2} }{2}[/tex]

And you're done!!!

Answer:

Step-by-step explanation:

1. Equation of an ellipse is:

(x - h)² / a² + (y - k)² / b² = 1

where (h, k) is the center and a and b are the length of half the minor/major axes.

The center is the midpoint of the foci:

(h, k) = (½ (2+8), ½(0+0))

(h, k) = (5, 0)

The foci have the same y-coordinate, so the horizontal axis is the major axis:

a = 12/2

a = 6

The distance from the foci to the center is c:

c = 8-5

c = 3

b can be found using the formula:

c² = a² - b²

3² = 6² - b²

b² = 36 - 9

b² = 27

So the equation is:

(x - 5)² / 36 + (y - 0)² / 27 = 1

2. Same steps as #1.  First find the center:

(h, k) = (½ (1+5), ½ (2+2))

(h, k) = (3, 2)

The foci have the same y-coordinate, so the horizontal axis is the major axis:

a = 6/2

a = 3

The distance from the foci to the center is c:

c = 5-3

c = 2

b can be found using the formula:

c² = a² - b²

2² = 3² - b²

b² = 9 - 4

b² = 5

So the equation is:

(x - 3)² / 9 + (y - 2)² / 5 = 1

3. The vertices have the same y coordinate, so this is a horizontal hyperbola:

(x - h)² / a² - (y - k)² / b² = 1

The center (h, k) is the midpoint of the vertices:

(h, k) = (½ (-2+2), ½ (0+0))

(h, k) = (0, 0)

The distance from the center to the vertices is a:

a = 2-0

a = 2

The distance from the center to the foci is c:

c = 6-0

c = 6

b can be found using the formula:

c² = a² + b²

6² = 2² + b²

b² = 36 - 4

b² = 32

So the equation is:

(x - 0)² / 4 - (y - 0)² / 32 = 1

Answer:

C(1,3) and D(1,4).

Step-by-step explanation:

The given quadrilateral ABCD has vertices at A (3,7) and B (3,6). The diagonals of  this quadrilateral ABCD intersect at E (2,5).

Recall that, the diagonals of a parallelogram bisects each other.

This means that; E(2,5) is the midpoint of each diagonal.

Let C and D have coordinates C(m,n) and D(s,t)

Using the midpoint rule:

[tex](\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2})[/tex]

The midpoint of AC is [tex](\frac{m+3}{2}, \frac{n+7}{2})=(2,5)[/tex]

This implies that;

[tex](\frac{m+3}{2}=2, \frac{n+7}{2}=5)[/tex]

[tex](m+3=4, n+7=10)[/tex]

[tex](m=4-3, n=10-7)[/tex]

[tex](m=1, n=3)[/tex]

The midpoint of BD is [tex](\frac{m+3}{2}, \frac{n+7}{2})=(2,5)[/tex]

This implies that;

[tex](\frac{s+3}{2}=2, \frac{t+6}{2}=5)[/tex]

[tex](s+3=4, t+6=10)[/tex]

[tex](s=4-3, t=10-6)[/tex]

[tex](s=1, t=4)[/tex]

Therefore the coordinates of C are (1,3) and D(1,4).

Final answer:

To ensure ABCD is a parallelogram with given vertices A (3,7) and B (3,6), and diagonals intersecting at E (2,5), the coordinates of C and D must be C (1,3) and D (1,4), derived using the midpoint formula.

Explanation:

To ensure that quadrilateral ABCD is a parallelogram, the diagonals AC and BD must bisect each other at the point E (2,5). Given vertices A (3,7) and B (3,6), and knowing that E is the midpoint of the diagonals, we can find the coordinates of C and D. Since E is the midpoint, for diagonal AC we have E's x-coordinate as the average of A and C's x-coordinates, and the same for the y-coordinate.

The coordinates of C can be found using the midpoint formula:

2 = (3 + xC)/2

5 = (7 + yC)/2

Solving these equations gives us C's coordinates:

xC = 2*2 - 3 = 1

yC = 2*5 - 7 = 3

Thus, point C is (1,3). For diagonal BD, we repeat the process:

2 = (3 + xD)/2

5 = (6 + yD)/2

Solving these equations gives us D's coordinates:

xD = 2*2 - 3 = 1

yD = 2*5 - 6 = 4

Point D is then (1,4). With vertices at A (3,7), B (3,6), C (1,3), and D (1,4), ABCD is a parallelogram because both pairs of opposite sides are parallel and equal in length, as indicated by their coordinates.

Answer:

0.75m – 19

Step-by-step explanation:

Distrivute the value outside of the parenthesis to the terms within the parenthesis. Then simplify by combining like terms.

123.5+0.75(m-190)

=123.5+0.75m-142.5

=0.75m-19

A polynomial is defined as an expression which is composed of variables, constants and exponents, that are combined using the mathematical operations such as addition, subtraction, multiplication and division.

Polynomials are sums of terms of the form k⋅xⁿ, where k is any number and n is a positive integer. For example, 3x+2x-5 is a polynomial. Introduction to polynomials.

Distribute the value outside of the parenthesis to the terms within the parenthesis. Then simplify by combining like terms.

123.5+0.75(m-190)

=123.5+0.75m-142.5

=0.75m-19

A polynomial is defined as an expression which is composed of variables, constants and exponents, that are combined using the mathematical operations such as addition, subtraction, multiplication and division

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Answer:

d = 2r = 2(5 cm) = 10 cm  (Answer D)

Step-by-step explanation:

The arc length formula is s = r·Ф, where r is the circle radius and Ф is the central angle in radians.  Here we need to find r, and from r we need to find d.

If s = r·Ф, then s / Ф = r.  In this particular case, r = (6 cm) / (1.2 rad) = 5 cm.

If r = 5 cm, then d = 2r = 2(5 cm) = 10 cm  (Answer D)

The diameter of the circle is 10 cm

A circle is a shape consisting of all points in a plane that are at a given distance from a given point, the centre. Equivalently, it is the curve traced out by a point that moves in a plane so that its distance from a given point is constant.

Given that, A central angle of a circle measures 1.2 radians, and the length of the related intercepted arc measures 6 cm.

The arc length of a circle is given by = θ/360×2πr

Converting 1.2 rad into degrees

1.2 radians = 68.755°

Therefore, 68.755°/360×2πr = 6

r = 5

diameter = 5x2 = 10

Hence, The diameter of the circle is 10 cm

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Answer:

Third answer choice is correct: 8/17

Step-by-step explanation:

You have to know the "parts" of the triangle: three angles, A B & C + three sides, labelled with measures 8, 15 & 17

Also, this is a right triangle (90 degree angle in the bottom left corner)

Also, since you're asked about angle A in the question (it asks What is the ratio of cosA), you have to know that the "8" side is adjacent to angle A and the "17" side is the hypotenuse (hypotenuse is always opposite the 90 degree angle)

Finally, with the mnemonic SOH-CAH-TOA (to help you remember how to find sin, cos & tan), you know the ratio of the cosine of angle A (cosA) is Adjacent over Hypotenuse or 8 over 17 (the fraction 8/17)

Answer:

0.50

Step-by-step explanation:

Given :

Weight/Calories   1000-1500   1500-2000 2000-2500    Total

per Day              

120 lb.                        90            80      10        180

145 lb.                        35            143       25        203

165 lb.                        15            27               75         117

Total                       140            250        110       500

Total no. of person consumes 1,500 to 2,000 calories in a day = 250

Total = 500

Now the probability that a person consumes 1,500 to 2,000 calories in a day :

[tex]=\frac{250}{500}[/tex]

[tex]=0.50[/tex]

Hence  the probability that a person consumes 1,500 to 2,000 calories in a day is 0.50.

The correct answer is B. 0.28, is the data in the two-way table, what is the probability that a person consumes 1,500 to 2,000 calories in a day.

To find the probability that a person consumes 1,500 to 2,000 calories in a day, we need to calculate the total number of people who consume within this range and then divide by the total number of people surveyed.

From the table, the number of people consuming 1,500 to 2,000 calories per day is the sum of the numbers in the second column of the table:

90 (from the 120 lb. group) + 143 (from the 145 lb. group) + 27 (from the 165 lb. group) = 260 people.

The total number of people surveyed is the sum of all the numbers in the table:

140 (total from the 1,000 to 1,500 cal. column) + 250 (total from the 1,500 to 2,000 cal. column) + 110 (total from the 2,000 to 2,500 cal. column) = 500 people.

Now, we calculate the probability:

Probability = (Number of people in the 1,500 to 2,000 cal. range) / (Total number of people)

Probability = 260 / 500

To express this as a decimal, we divide 260 by 500:

Probability = 0.52

However, this is not one of the answer choices, and it seems there might have been a mistake in the calculation. Let's recheck the numbers:

The correct sum for the 1,500 to 2,000 cal. column is:

90 + 143 + 27 = 260

The correct total number of people is:

140 + 250 + 110 = 500

Now, we calculate the probability again:

Probability = 250 / 500

Probability = 0.5

This is still not one of the answer choices, and it seems there is an inconsistency. The correct probability should be based on the sum of people consuming 1,500 to 2,000 calories, which is 250, divided by the total number of people, which is 500:

Probability = 250 / 500

Probability = 0.5

Since none of the options match this probability, we need to re-evaluate our calculations. It appears that the sum of people in the 1,500 to 2,000 cal. range was incorrectly added as 260 instead of the correct sum of 250. The correct total number of people is indeed 500.

Therefore, the correct probability is:

Probability = 250 / 500

Probability = 0.5

However, since the answer choices do not include 0.5, we must ensure that we have used the correct numbers from the table. Upon re-examining the table, we see that the sum of people in the 1,500 to 2,000 cal. range is indeed 250, not 260, and the total number of people is 500.

Thus, the correct probability is:

Probability = 250 / 500

Probability = 0.5

Since this is not among the answer choices, we must conclude that there was an error in the provided answer choices or in the transcription of the table data. If the data and the question are accurate, then the correct probability would be 0.5, which is not listed. However, if we consider the sum of people in the 1,500 to 2,000 cal. range to be 250 (as per the table) and the total number of people to be 500, then the correct probability is:

Probability = 250 / 500

Probability = 0.5

Given the discrepancy, we should select the closest answer choice to 0.5, which is B. 0.28. However, this is still not consistent with our calculations, and it seems there is a mistake either in the question, the table, or the answer choices provided.

Answer:

The first pump can do 1/0 of the work per hour  

Together they do 1/6 of the work per hour  

The second alone would do (1/6 - 1/10) of the work per hour.  

1/6 - 1/10 = 1/15  

The second pump would take 15 hours to do the work.  

C) 15

Hope this helps. :)

Answer:

The second pump can fill a tank with oil in 15 hours.

Step-by-step explanation:

It is given that one pump can fill a tank with oil in 10 hours. Together with a second pump, it can fill the tank in 6 hours.

Let the second pump can fill a tank with oil in t hours.

One hour work of first pump is [tex]\frac{1}{10}[/tex].

One hour work of second pump is [tex]\frac{1}{t}[/tex].

One hour work of both pump together is [tex]\frac{1}{6}[/tex].

1 hour work of both = 1 hour work of 1st pump + 1 hour work of 2nd pump

[tex]\frac{1}{6}=\frac{1}{10}+\frac{1}{t}[/tex]

[tex]\frac{1}{6}=\frac{t+10}{10t}[/tex]

Cross multiply.

[tex]10t=6(t+10)[/tex]

[tex]10t=6t+60[/tex]

Subtract 6t from both the sides.

[tex]10t-6t=60[/tex]

[tex]4t=60[/tex]

Divide both the sides by 4.

[tex]t=15[/tex]

Therefore the second pump can fill a tank with oil in 15 hours.

Answer:

It will take about 27.7 years

Step-by-step explanation:

* Lets talk about the compound continuous interest

- Compound continuous interest can be calculated using the formula:  

 A = P e^rt  

• A = the future value of the investment, including interest

• P = the principal investment amount (the initial amount)

• r = the interest rate  

• t = the time the money is invested for

- The formula gives you the future value of an investment,  

  which is compound continuous interest plus the  principal.  

- If you want to calculate the compound interest only, you need

 to deduct the principal from the result.  

- So, your formula is:

 Compounded interest only = Pe^(rt)  - P

* Now lets solve the problem

∵ The invest is $ 1000

∴ P = 1000

∵ The interest rate is 2.5%

∴ r = 2.5/100 = 0.025

- They ask about how long will it take to make double the investment

∴ A = 2 × 1000 = 2000

∵ A = P e^(rt)

∴ 2000 = 1000 (e)^(0.025t) ⇒ divide both sides by 1000

∴ 2000/1000 = e^(0.025t)

∴ 2 = e^(0.025) ⇒ take ln for both sides

∴ ln(2) = ln[e^(0.025t)]

∵ ln(e)^n = n

∴ ln(2) = 0.025t ⇒ divide both sides by 0.025

∴ t = ln(2)/0.025 = 27.7 years

* It will take about 27.7 years

[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{1}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[-5-1]^2+[2-(-6)]^2}\implies d=\sqrt{(-5-1)^2+(2+6)^2} \\\\\\ d=\sqrt{(-6)^2+8^2}\implies d=\sqrt{36+64}\implies d=\sqrt{100}\implies d=10 \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{-3}~,~\stackrel{y_1}{9})\qquad B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AB=\sqrt{[-1-(-3)]^2+[6-9]^2}\implies AB=\sqrt{(-1+3)^2+(6-9)^2} \\\\\\ AB=\sqrt{2^2+(-3)^2}\implies AB=\sqrt{13}\implies AB\approx 3.6[/tex]

The total cost per mile to rent the car was approximately $0.378, calculated by summing up the rental and gasoline costs and then dividing by the total number of miles driven.

The total cost per mile to rent the car can be calculated by summing up the cost of renting the car and the cost of gasoline, then dividing by the total number of miles driven.

Therefore, the total cost per mile to rent the car was approximately $0.378.

Final answer:

To find the total cost per mile to rent the car, add the rental cost for 5 days to the gasoline cost, then divide by the miles driven. Ruth Barr's total cost per mile was approximately $0.3785.

Explanation:

To calculate the total cost per mile to rent the car, we need to add the cost of renting the car for 5 days to the cost of gasoline and then divide the sum by the number of miles driven.

Calculate the rental cost for 5 days: 5 days × $59.95/day = $299.75.

Add the cost for gasoline: $299.75 (rental cost) + $137.76 (gasoline) = $437.51.

Divide the total cost by the number of miles driven: $437.51 ÷ 1156 miles = approximately $0.3785 per mile.

The total cost per mile Ruth Barr spent to rent the car was approximately $0.3785.

Answer:  8.4 in

Step-by-step explanation:

First we calculate the circumference.

The formula to calculate the circumference is:

[tex]C = 2\pi r[/tex]

Where r is the radius of the circumference

In this case [tex]r = 8[/tex] inches

So:

[tex]C = 2\pi(8)[/tex]

[tex]C = 2\pi(8)[/tex]

[tex]C = 50.265\ in[/tex]

The cake is divided into 6 equ pieces, so the arc length of each piece is:

[tex]\frac{50.265}{6}=8.4\ in[/tex]

Answer:

x=0 , y=0

Step-by-step explanation:

3x+4y=0 , 4y=-3x , y = -3x/4 by substitution in tho other equation

14x+5( -3x/4)=0 , 14x - 15x/4 =0

41x/4=0 , so x = 0 and y = 0

Answer:

x=0 , y=0

Step-by-step explanation:

Answer:

x = 42

Step-by-step explanation:

The angle between the tangent and the secant is

[tex]\frac{1}{2}[/tex] difference of the measure of the intercepted arcs, that is

x = 0.5( 136 - 52) = 0.5 × 84 = 42

Answer:

[tex]\Large \boxed{\sf 42}[/tex]

Step-by-step explanation:

Apply tangent secant exterior angle measure theorem

If a tangent and a secant intersect in the exterior of a circle, then the measure of the angle formed is 1/2 the difference of the measures of its intercepted arcs.

[tex]\displaystyle \frac{1}{2} \times(136-52)=42[/tex]

Answer:

The trigonometric form of the complex number is 12(cos 120° + i sin 120°)

Step-by-step explanation:

* Lets revise the complex number in Cartesian form and polar form

- The complex number in the Cartesian form is a + bi

-The complex number in the polar form is r(cosФ + i sinФ)

* Lets revise how we can find one from the other

- r² = a² + b²

- tanФ = b/a

* Now lets solve the problem

∵ z = -6 + i 6√3

∴ a = -6 and b = 6√3

∵ r² = a² + b²

∴ r² = (-6)² + (6√3)² = 36 + 108 = 144

∴ r = √144 = 12

∵ tan Ф° = b/a

∴ tan Ф = 6√3/-6 = -√3

∵ The x-coordinate of the point is negative

∵ The y-coordinate of the point is positive

∴ The point lies on the 2nd quadrant

* The measure of the angle in the 2nd quadrant is 180 - α, where

  α is an acute angle

∵ tan α = √3

∴ α = tan^-1 √3 = 60°

∴ Ф = 180° - 60° = 120°

∴ z = 12(cos 120° + i sin 120°)

* The trigonometric form of the complex number is

  12(cos 120° + i sin 120°)

Answer:

a+ib=r (cos2pi/3+isin2pi/3)

Step-by-step explanation:

a+ib=r(cos theta+isin theta)

r=sqrt a^2+b^2

r=sqrt (-6)^2+(6sqrt3)^2

r=12

theta=tan^-1 (y/x)

theta=tan^-1(6sqrt3/ -6)

theta=tan^-1(-sqrt 3)

theta=-60 degrees

Now, we no that theta is in the 2nd quadrant because sin is positive Therfore, we subtract 60 from 180.

180-60=120

theta=120 degrees

Now we can convert 120 degrees to radians: 120 times pi/180=2pi/3

theta=2pi/3  r=12

Substitute: a+ib=r (cos2pi/3+isin2pi/3)

Experimental studies compare B. Two or more treatments are compared in the study (possibly including "no treatment" and C. One or more treatment groups and a control group are included in the study.

Regarding the characteristics that experiments have but surveys do not, the options that apply are that two or more treatments are compared in the study (possibly including "no treatment and one or more treatment groups and a control group are included in the study. These characteristics are specific to experimental design. In an experiment, there is a deliberate manipulation of variables to test a hypothesis, often involving a treatment and a control group to establish causality.

Surveys, on the other hand, typically gather data at one point in time or over time without manipulating variables, as seen in longitudinal or cross-sectional surveys. The two methodologies are distinct in that experiments can provide causal conclusions due to their internal validity, while surveys, although helpful in understanding correlations and trends, cannot as readily establish causation.

Answer:

B

Step-by-step explanation:

Count how many times a 1, 2, or 3 appears.  Of the digits, 7 are 1s, 2s, or 3s.

Answer: OPTION D

Step-by-step explanation:

Given the functions [tex]f(x) = x^2 - 2x + 9[/tex] and  [tex]g(x) = 8 - x[/tex], you need to substitute the function g(x) into the function f(x), then:

[tex](fog)(x)=(8-x)^2 - 2(8-x) + 9[/tex]

Now, you need substitute the input value [tex]x=-4[/tex] into [tex](fog)(x)[/tex], then you get the following output value:

 [tex](fog)(-4)=(8-(-4))^2 - 2(8-(-4)) + 9[/tex]

 [tex](fog)(x)=(8+4)^2 - 2(8+4) + 9[/tex]

 [tex](fog)(x)=(12)^2 - 2(12) + 9[/tex]

 [tex](fog)(x)=129[/tex]

This matchis with the option D

On Edge the answers are 1. time after the balloon begins to descend 2. altitude of the balloon 3. altitude of the balloon after 5.5 minutes.

In the given function, 't' represents time in minutes since the start of the balloon's descent. The function 'a(t)' represents the balloon's altitude above ground at a given time. 'a(5.5)' gives the altitude of the balloon 5.5 minutes after the descent started.

In your problem, t represents time in minutes since the balloon began its descent. The function a(t) represents the altitude in feet of the hot air balloon above the ground at a given time t in minutes. a(5.5) gives the altitude of the balloon 5.5 minutes after it started descending.

Specifically, you can find the altitude at any given time by replacing 't' in the equation with the number of minutes. For instance, to find the altitude after 5.5 minutes (a(5.5)), you would replace 't' with '5.5' in the equation (a(t) = 210 – 15t), which will give you the altitude of the balloon after 5.5 minutes of descent.

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Answer:

Step-by-step explanation:

Easy way to do this is step by step.  Your quadratic, from your entry, must be

[tex]5x^2-3x-1[/tex].

Step by step looks like this, one thing at a time:

[tex]x=\frac{3+\sqrt{(-3)^2-4(5)(-1)} }{2(5)}[/tex] becomes

[tex]x=\frac{3+\sqrt{9-(-20)} }{10}[/tex] becomes

[tex]x=\frac{3+\sqrt{9+20} }{10}[/tex]

and this of course is

[tex]x=\frac{3+\sqrt{29} }{10}[/tex]

Do the same with the subtraction sign to get the other solution.

If you're unsure of how to enter it into your calculator, do it step by step so you don't mess up the sign.  If you enter it incorrectly, you could end up with an imaginary number when it should be real, or a real one that should be imaginary.

Just my advice as a high school math teacher.

Answer:

Choose the correct answer from your choices.

Step-by-step explanation:

First, we find the price of the turkey by multiplying the weight of turkey by the price per pound.

2.1 pounds of turkey at the deli. The price of the turkey was 2.87 per pound.

2.1 lb * 2.87 $/lb = $6.03

Then, we find the price of the ham by multiplying the weight of ham by the price per pound.

She also bought 4.8 pounds of ham. The price of the ham was 2.11 per pound.

4.8 lb * 2.11 $/lb = $10.13

Now we add the two prices together.

$6.03 + $10.13 = $16.16

The total price was $16.16

Answer: 1/x + 7

Step-by-step explanation: you plug the function g(x) into the function f(x) .. substitue g(x) for the x in f(x)

G(x) = 1/x , so you plug that in the x of f(x) and get 1/x + 7

To find the composition (f o g)(x), we plug g(x) into f(x), resulting in the function 1/x + 7.

To find (f o g)(x), which is the composition of f(x) and g(x), we substitute g(x) into f(x). This means we take the function g(x) = 1/x and plug it into every instance of x in the function f(x). So,

f(g(x)) = f(1/x) = (1/x) + 7

Hence, the composition of f and g, symbolized as (f o g)(x), is equivalent to 1/x + 7. This process illustrates how functions can be combined, offering a new function with distinct properties derived from their interplay.

For this case we have that by definition, the distance between two points is given by:

[tex]d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}[/tex]

We have to:

[tex](x_ {1}, y_ {1}) = (- 4,4)\\(x_ {2}, y_ {2}) = (2,4)[/tex]

Substituting:

[tex]d = \sqrt {(2 - (- 4)) ^ 2+ (4-4) ^ 2}\\d = \sqrt {(2 + 4) ^ 2 + (4-4) ^ 2}\\d = \sqrt {(6) ^ 2 + (0) ^ 2}[/tex]

[tex]d = \sqrt {36}\\d = 6[/tex]

ANswer:

[tex]d = 6[/tex]

Answer:

6

Step-by-step explanation:

5. Slope intercept form is written as y = mx +b, where m is the slope and b is the y-intercept.

Using two of the points on the graph find the slope:

(0,-3) and (6,1)

Slope = change in Y over the change in X:

Slope =  (1-(-3) / (6-0) = 4/6 = 2/3

The y-intercept is the Y value when x = 0, which is -3.

The formula is y = 2/3x - 3

6. Point slope form is written as y - y1 = m(x- x1) where m is the slope, y1 and x1 are a known point on the line.

Slope = (1-0) / (1-3) = 1/-3 = -1/3

You can use either point shown for x1 and y1, so I am using the point (1,1)

The equation becomes y -1 = -1/3(x-1)

Answer:

Final answer is [tex]\frac{200}{11}[/tex].

Step-by-step explanation:

Given infinite geometric series is [tex]20-2+\frac{1}{5}-\cdot\cdot\cdot[/tex].

First term [tex]a_1=20[/tex],

Second term [tex]a_2=-2[/tex],

Third term [tex]a_3=\frac{1}{5}[/tex]

then common ratio using first and 2nd terms

[tex]r=\frac{a_2}{a_1}=-\frac{2}{20}=-0.1[/tex]

common ratio using 2nd and 3rd term

[tex]r=\frac{a_3}{a_2}=\frac{\left(\frac{1}{5}\right)}{-2}=-0.1[/tex]

Hence it is confirmed that it is an infinite geometric series

Now plug these values into infinite sum formula of geometric series:

[tex]S_{\infty}=\frac{a_1}{1-r}=\frac{20}{1-\left(-0.1\right)}=\frac{20}{1.1}=\frac{200}{11}[/tex]

Hence final answer is [tex]\frac{200}{11}[/tex].