Please someone help me

Answer:

a) 4/11

b) 2/11

c) 1/11

d) 7/11

Answer:

Part 1) The x-component of the vertex is 2 and the y-component of the vertex is -18

Part 2) The discriminant is 144

Step-by-step explanation:

we have

[tex]f(x)=2x^{2}-8x-10[/tex]

step 1

Find the discriminant

The discriminant of a quadratic equation is equal to

[tex]D=b^{2}-4ac[/tex]

in this problem we have

[tex]f(x)=2x^{2}-8x-10[/tex]

so

[tex]a=2\\b=-8\\c=-10[/tex]

substitute

[tex]D=(-8)^{2}-4(2)(-10)[/tex]

[tex]D=64+80=144[/tex]

The discriminant is greater than zero, therefore the quadratic equation has two real solutions

step 2

Find the vertex

Convert the quadratic equation into vertex form

[tex]f(x)+10=2x^{2}-8x[/tex]

[tex]f(x)+10=2(x^{2}-4x)[/tex]

[tex]f(x)+10+8=2(x^{2}-4x+4)[/tex]

[tex]f(x)+18=2(x-2)^{2}[/tex]

[tex]f(x)=2(x-2)^{2}-18[/tex] -----> equation in vertex form

The vertex is the point (2,-18)

therefore

The x-component of the vertex is 2

The y-component of the vertex is -18

Answer:

Consider the quadratic function f(x) = 2x2 – 8x – 10.

The x-component of the vertex is

✔ 2

The y-component of the vertex is

✔ –18

The discriminant is b2 – 4ac = (–8)2 – (4)(2)(–10) =

✔ 144

The figure that is shaded 6/8 is the square.

If you split the square on more time along like a box pizza, you will get 8 slices and 6 of them shaded.

The value of the given expression [tex]\log_{7} e[/tex] will be 0.51, i.e. option C.

Expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

We have,

 [tex]\log_{7} e[/tex]

So,

Using the log rule,

On solving we get,

[tex]\log_{7} e =0.51[/tex]

So,

This the value of the given expression.

Hence, we can say that the value of the given expression [tex]\log_{7} e[/tex] will be 0.51, i.e. option C.

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Final answer:

The given expression Log₇^eA can be simplified and evaluated to approximately 0.43 when rounded to two decimal places.

Explanation:

Logarithms:

The expression Log₇^eA can be rewritten as Log₇(e). Applying the change of base formula to convert it to a common logarithm form, Log₇(e) = ln(e) / ln(7). Since ln(e) = 1, the result is approximately 0.43, rounded to two decimal places.

Answer:

85

Step-by-step explanation:

I assume by 2x3 you mean 2x^3 and 3y2 means 3y^2. If so then just plug in the values:

2x^3 + 3y^2 - 17 = ?

2(3)^3 + 3(4)^2 - 17 = ?

2(27) + 3(16) - 7 = ?

54 + 48 - 17

102 - 17 = ?

85 = ?

A lock with 60 digits and a combination involving turning right to the first number, left to the second number, and right to the third number can have 212,400 possible combinations.

A lock with 60 digits and a combination involving turning right to the first number, left to the second number, and right to the third number can have 60 x 59 x 60 possible combinations.

Here's the explanation:

By multiplying these options together, you get the total number of possible combinations: 60 x 59 x 60 = 212,400.

Final answer:

The total number of possible combinations for a lock with a 60-digit combination, turning right, left, and right is 60 × 60 × 60, leading to 216,000 unique combinations.

Explanation:

To calculate the number of possible combinations for a lock with a 60-digit sequence where you turn right to the first number, left to the second number, and right to the third number, you need to apply the basic principle of counting. Each of the three steps in the combination can be any of the 60 digits, with the choice of one step not affecting the choices for the other steps. Therefore, each step has 60 options, and the total number of possible combinations is the product of these options.

The calculation for the total number of combinations is: 60 × 60 × 60, which simplifies to 60^3. When you calculate that, you get 216,000 possible combinations for the lock.

Answer:

[tex]V=312\pi\ mm^{3}[/tex]

Step-by-step explanation:

we know that

The volume of the composite figure is equal to the volume of a semi-sphere plus the volume of the cone

so

[tex]V=\frac{4}{6}\pi r^{3} +\frac{1}{3} \pi r^{2} h[/tex]

we have

[tex]r=6\ mm[/tex]

[tex]h=14\ mm[/tex]

substitute

[tex]V=\frac{4}{6}\pi (6)^{3} +\frac{1}{3} \pi (6)^{2} (14)[/tex]

[tex]V=144\pi +168\pi[/tex]

[tex]V=312\pi\ mm^{3}[/tex]

Answer:

312 πmm^2

Step-by-step explanation:

On edg

Answer:

Week: $173.25

Month: $693

Year: $8,316

Step-by-step explanation:

Answer:

The domain is all real numbers. The range is {y|y ≤ 16}

Step-by-step explanation:

we have

[tex]f(x)=-x^{2}-2x+15[/tex]

This is the equation of a vertical parabola open downward

The vertex is a maximum

Find the vertex of the quadratic equation

[tex]f(x)-15=-x^{2}-2x[/tex]

[tex]f(x)-15=-(x^{2}+2x)[/tex]

[tex]f(x)-15-1=-(x^{2}+2x+1)[/tex]  

[tex]f(x)-15-1=-(x^{2}+2x+1)[/tex]

[tex]f(x)-16=-(x^{2}+2x+1)[/tex]

[tex]f(x)-16=-(x+1)^{2}[/tex]

[tex]f(x)=-(x+1)^{2}+16[/tex] -----> equation in vertex form

The vertex is the point (-1,16)

therefore

The domain is the interval ----> (-∞,∞)  All real numbers

The range is the interval ----> (-∞,16]  All real numbers less than or equal to 16

Answer:

The Answer Is B

Step-by-step explanation:

domain is all real numbers. The range is {y|y ≤ 16}.

Answer:7/20 = 0.35 = 35%=500x.35 =175 men

40%=.40x500 =200 women

200+170=370

500-370

125 children

Step-by-step explanation:

Answer:

There are 175 men, 200 women, and 125 children.

Step-by-step explanation:

7/20 = M/500; M = 175

0.4 x 500 = W; W = 200

175 + 200 + C = 500; C = 125

Answer:

The figures are not similar

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

so

Verify

BC/JI=AB/FJ=ED/GH

substitute the given values

5.1/3.6=2.8/2.1=3.7/2.7

1.417=1.333=1.370 ------> is not true

therefore

The figures are not similar

Answer:

x = 9.6

Step-by-step explanation:

The figure is a similar figure and the quadrilaterals (4 sides) created are related to each other by the same ratio.

So we can say:

8 goes with x as (8+12) goes with 24

We can setup a ratio and solve for x:

[tex]\frac{8}{x}=\frac{8+12}{24}\\\frac{8}{x}=\frac{20}{24}\\20x=8*24\\20x=192\\x=\frac{192}{20}\\x=9.6[/tex]

So x = 9.6

The value of x in the figure drawn is 9.6

we can create a proportional expression thus :

8 = x

(8 + 12) = 24

This means

8 = x

20 = 24

cross multiply

20x = 24 × 8

20x = 192

divide both sides by 20 to isolate x

x = 192/20

x = 9.6

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Answer:

Option C is correct.

Step-by-step explanation:

We need to find the greatest common factor of the polynomial

10x^5+15x^4-25x^3

The greatest common factor is the number that is divisible by all 3 terms of the polynomial.

so, the common factor is 5x^3 for above polynomial

Taking out the common factor

5x^3(2x^2+3x-5)

Now the term in the bracket has no other common factor

So, the greatest common factor of 10x^5+15x^4-25x^3 is 5x^3

So, Option C is correct.

Answer:

Third option.

Step-by-step explanation:

The greatest common factor (GCF) for a polynomial is defined as the largest monomial that divides each term.

Given the polynomial [tex]10x^5+15x^4-25x^3[/tex], the GCF of the coefficients can be found by descompose each one of them into their prime factors:

[tex]10=2*5\\15=2*5\\25=5*5[/tex]

You can observe that the GCF of the coefficients is:

[tex]GFC_{(coefficients)}=5[/tex]

Now you need to find the GCF of the variables. You can notice that each term has at least one x³, then:

 [tex]GFC_{(variables)}=x^3[/tex]

Threfore, the GCF of the polynomial is:

[tex]GCF=5x^3[/tex]

Answer:

A,D,E

Step-by-step explanation:

If it just lists out the numbers then it is discrete.  So the following are not discrete since it isn't just a list:  B and C.

The following are lists:  A,D,E

Answer:

1. x = -a/6

2. x = 3/a

x = -6/a

Step-by-step explanation:

1. 4 = (6/a)x+5

subtract 5 from both sides

-1 = (6/a)x

divide by 6/a on both sides

x = -a/6

To make that last part simpler, you could think of it as first multiplying by a and then dividing by 6.

2. 7+2ax = 13

subtract 7

2ax = 6

divide by 2

ax = 3

divide by a

x = 3/a

3. -ax-20 = -14

add 20

-ax = 6

divide by -a

x = 6/-a = -6/a

To solve for x in an equation linked with equilibrium concentration and solubility, identify known values, select the right conversion equations, utilize the ICE table method, and substitute the known values into the solubility product expression. Rearrange the equation to solve for x.

In this question, we are looking to solve equations linked with equilibrium concentration and solubility. First, we will identify known values from the problem and list them out. This includes figuring out the terms we need to substitute into the solubility product expression and identifying our unknown, x. Afterwards, we need to select the right conversion equations and substitute the known values.

The chemical reaction gives us an ICE (Initial, Change, Equilibrium) table, which is a simplified method used to solve equilibrium problems. Sometimes it might be necessary to consider momenta in the x and y directions to solve for the unknown. When we have the equilibrium concentrations, we substitute these terms into the solubility product expression and solve for x.

Always remember that the goal is to rearrange the equation so that x is on one side by itself, making it easier to solve for. This kind of problem requires a clear understanding of solubility, equilibrium, and algebraic conventions.

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Recall that

[tex]\cos2\theta=2\cos^2\theta-1[/tex]

and

[tex]\tan^2\theta+1=\sec^2\theta=\dfrac1{\cos^2\theta}[/tex]

Then

[tex]\cos2\theta=\dfrac2{\tan^2\theta+1}-1\implies\cos2\theta=\boxed{\dfrac7{25}}[/tex]

Answer:

[tex]cos2\theta=\frac{7}{25}[/tex]

Step-by-step explanation:

This is a question of Trigonometric Identities. In addition to this, In quadrant IV the cosine of the angle is naturally negative. This explains the negative value for [tex]tan\theta=-3/4[/tex]

The double angle formula

Let's choose a convenient identity, for the double angle [tex]cos2\theta[/tex]

[tex]\\tan \theta=-3/4 \\ cos2\theta =cos^{2}\theta -sen^{2}\theta\\cos2\theta =2cos^{2}\theta-1\\\\1+tan\theta^{2} =sec^{2}\theta\\\\ 1+(\frac{-3}{4})^{2} =\frac{1}{cos^2 \theta} \\\\\frac{25}{16}=\frac{1}{cos^{2}\theta}\\ cos^{2}\theta=\frac{16}{25}[/tex]

Finally, we can plug it in:

[tex]cos2\theta =2cos^{2}\theta -1\\cos2\theta =2\left ( \frac{16}{25} \right )-1 \Rightarrow cos2\theta=\frac{7}{25}[/tex]

Answer:

B: 5^4

Step-by-step explanation:

however many of the same numbers is the little exponent

Exponent means exactly repeated multiplications of the same number: [tex]a^b[/tex] means that you have to multiply [tex]a[/tex] by itself [tex]b[/tex] times.

So, [tex]5\times5\times5\times5[/tex] means to multiply 5 by itself 4 times, which is written as [tex]5^4[/tex].

Answer:

=√18

Step-by-step explanation:

The absolute value of a complex number is its distance from zero on graph. The formula for absolute value of a complex number is:

|a+bi|= √(a^2+b^2 )

where a is the real part of the complex number and b is the imaginary part of the complex number.

So for the given number,

a= -4

b=-√2

Putting in the formula:

|-4-√2 i|= √((-4)^2+(-√2)^2 )

= √(16+2)

=√18  ..

ANSWER

[tex]3 \sqrt{2} \: units[/tex]

EXPLANATION

The absolute value of the complex number

[tex] |a +b i| = \sqrt{ {a}^{2} + {b}^{2} } [/tex]

This is also known as the modulus of the complex number.

This implies that:

[tex]| - 4 - \sqrt{2} i| = \sqrt{ {( - 4)}^{2} + {( - \sqrt{2} )}^{2} } [/tex]

[tex]| - 4 - \sqrt{2} i| = \sqrt{ 16 +2 } [/tex]

We simplify further to get;

[tex]| - 4 - \sqrt{2} i| = \sqrt{ 18 } = 3 \sqrt{2} \: units[/tex]

Answer:

I have put my answer in the form (x,y,z)

One solution (3,2,4)

Another solution (-5,-4,-6)

Step-by-step explanation:

I'm going to try to do this by a bunch of substitution.

I'm going to solve first equation for x, second for y, and third for z.

Commutative property x+xy+y=11

Distributive property x(1+y)+y=11

Subtraction property  x(1+y)=11-y

Division property x=(11-y)/(1+y)

I'm going to do the other 2 equations in a similar way:

So the second equation solving for y:    y=(14-z)/(1+z)

The third equation solving for z:  z=(19-x)/(1+x)

I'm going to plug my new first equation into my third equation giving me:

z=(19-[(11-y)/(1+y)])/(1+[(11-y)/(1+y)]

Now I'm going to clean this up by multiplying by compound fraction by (1+y)/(1+y).

z=(19(1+y)-(11-y)]/[1(1+y)+(11-y)]

z=[19+19y-11+y]/[1+y+11-y]

z=[8+20y]/[12]

Simplify

z=(2+5y)/3

Now I'm going to sub this into my non-rewrite of equation 2:

y+(2+5y)/3+y(2+5y)/3=14

Multiply both sides by 3 to clear fractions

3y+(2+5y)+y(2+5y)=42

3y+2+5y+2y+5y^2=42

5y^2+10y+2=42

Subtract 42 on both sides

5y^2+10y-40=0

Divide both sides by 5

y^2+2y-8=0

Factor

(y+4)(y-2)=0

So y=-4 or y=2

If y=-4  then x=(11-(-4))/(1+(-4))=15/-3=-5 and z=(2+5*-4)/3=-18/3=-6

So one solution is (-5,-4,-6)

If y=2 then x=(11-2)/(1+2)=9/3=3 and z=(2+5*2)/3=12/3=4

So another solution is (3,2,4)

Answer:

option B. the square of the sum of 2 times x and 5

Step-by-step explanation:

we have

[tex](2x+5)^{2}[/tex]

we know that

The algebraic expression [tex](2x)[/tex] is equal to the phrase " Two times x" (the number two multiplied by x)

The algebraic expression [tex](2x+5)[/tex] is equal to the phrase " The sum of two times x and 5" (the number two multiplied by x plus the number 5)

The algebraic expression [tex](2x+5)^{2}[/tex] is equal to the phrase " The square of the sum of two times x and 5"

Answer:

case 1) [tex]2.144*10^{12}[/tex]

case 2) [tex]2.144*10^{8}[/tex]

Step-by-step explanation:

case 1) If we have

[tex]6.7*10^{6}[/tex] and [tex]3.2*10^{5}[/tex]

step 1

Calculate the product of the coefficients and powers separately

[tex]6.7*3.2=21.44[/tex]

[tex]10^{6}*10^{5}[/tex] -----> Apply the product of powers rule to add the exponents

[tex]10^{6}*10^{5}=10^{6+5}=10^{11}[/tex]

step 2

we have

[tex]21.44*10^{11}[/tex]

The product is not in scientific notation because the coefficient is greater than 10

step 3

Change the coefficient by moving the decimal one place to the left and increasing the exponent by one

[tex]2.144*10^{12}[/tex]

case 2) If we have

[tex]6.7*10^{6}[/tex] and [tex]3.2*10^{1}[/tex]

step 1

Calculate the product of the coefficients and powers separately

[tex]6.7*3.2=21.44[/tex]

[tex]10^{6}*10^{1}[/tex] -----> Apply the product of powers rule to add the exponents

[tex]10^{6}*10^{1}=10^{6+1}=10^{7}[/tex]

step 2

we have

[tex]21.44*10^{7}[/tex]

The product is not in scientific notation because the coefficient is greater than 10

step 3

Change the coefficient by moving the decimal one place to the left and increasing the exponent by one

[tex]2.144*10^{8}[/tex]

Answer:

Calculate the product of the coefficients and powers separately. Apply the product of powers rule to add the exponents. The product is not in scientific notation because the coefficient is greater than 10. Change the coefficient by moving the decimal one place to the left and increasing the exponent by one.

Step-by-step explanation:

(sample response from edgenuity)

Answer:

I and III only

Step-by-step explanation:

step 1

we know that

In this problem

A, B and C are collinear

so

A', B' and C' are collinear too

because the transformation is a translation

The translation does not modify the shape or length of the figure

AB=A'B'

AC=A'C'

BC=B'C'

step 2

The distance

AA'=BB'=CC'

because AB and A'B' are parallel

[tex]\boxed{x \approx 3.064}[/tex]

There is no general property  that we can use to rewrite:

[tex]log_{a}(u\pm v)[/tex]

Then, we'll solve this problem graphically. Let's say that we have two functions:

[tex]f(x)=log(x+1) \\ \\ g(x)=-x^2 +10[/tex]

[tex]f(x)[/tex] is a logarithmic function translated one unit to the left of the pattern logarithmic function [tex]log(x)[/tex]. On the other hand, [tex]g(x)[/tex] is a parabola that opens downward and whose vertex is [tex](0,10)[/tex]. So:

[tex]f(x)=g(x)[/tex]

implies that we'll find the value (or values) where these two functions intersect. When graphing them, we get that this x-value is:

[tex]\boxed{x=3.064}[/tex]

Then, for [tex]x=3.064[/tex]:

[tex]f(x)=log(x+1) \\ \\ f(3.064)=log(3.064+1) \\ \\ f(3.064)=log(4.064) \\ \\ Using \ calculator: \\ \\ f(3.064) \approx 0.6 \\ \\ \\ g(x)= -x^2 +10 \\ \\ g(3.064)= -(3.064)^2 +10 \\ \\ g(3.064)=-9.388+10 \\ \\ g(3.064) \approx -0.6[/tex]

Final answer:

Lynda Davis' total expenses for the month are $425. Her expenses for the year are $5100. Her rental income for the year is $14400. Her rate of income is approximately 282.35%.

Explanation:

To calculate Lynda Davis' total expenses for the month, we need to add up all of her monthly expenses. These include $70 for depreciation, $50 for property tax, $25 for insurance, $80 for repairs, and $200 for interest. So her total monthly expenses would be $70 + $50 + $25 + $80 + $200 = $425.

To calculate her expenses for the year, we can multiply her total monthly expenses by 12 since there are 12 months in a year. So her annual expenses would be $425 * 12 = $5100.

Her rental income for the year would be the monthly rental income of $1200 multiplied by 12. So her rental income for the year would be $1200 * 12 = $14400.

To calculate her rate of income, we need to find the percentage of her rental income compared to her total expenses. We can use the formula: (rental income / total expenses) * 100. So her rate of income would be ($14400 / $5100) * 100 ≈ 282.35%.

Answer:

3.

Step-by-step explanation:

Calculate the median, which is the middle number of an ordered range with an odd number. 3.

Calculate the medians of the bottom and top halves, omitting the middle number. Since these are now even-numbered sets, we'll take the average of the middle two numbers of each. Lower is 1.5, upper is 4.5.

Calculate the difference of the upper median and lower median, so 4.5 - 1.5 = 3.

Answer:

3/4x + (7 × Q)

∆

|

That's an x not multiplication

Answer:

[tex]7q + \frac{3}{4}x[/tex]

Step-by-step explanation:

[tex]\begin{array}{rcl}\text{Product of 7 and q} & = & 7q\\\\\text{Three-fourths of x} & = & \frac{3}{4}x \\\\\text{Three fourths of x added to product of 7 and q} & = & 7q + \frac{3}{4}x \\\\\end{array}[/tex]

Answer:

Expressions are not equivalent

Step-by-step explanation:

Given expressions are:

[tex]4(3w+4)\ and\ 16w+12[/tex]

Putting w=1 in both expressions

[tex]4(3w+4)\\=4[3(1)+4]\\=4(3+4)\\=4(7)\\=28\\\\16w+12\\=16(1)+12\\=16+12\\=28[/tex]

Both expression have value 28 on w=1

Putting w=3 in both expressions

[tex]4(3w+4)\\=4[3(3)+4]\\=4(9+4)\\=4(13)\\=52\\\\16w+12\\=16(3)+12\\=48+12\\=60[/tex]

Both expression have different values at w=3

Hence, in order for the expressions to be equivalent they both should produce same value on w=3 too.

So, it can be concluded that both expressions are not equivalent ..

Answer:They are both not equivalent

Step-by-step explanation:

You’re welcome

Answer:

So, Allison averages 1/6 of the route every hour, right?

1/6 + 1/a = 1/4

Once we apply the common denominator, 12a, we only wirk with the numerators.

2a + 12 = 3a

a = 12

Her associate can finish the route in 12 hours by herself.

Step-by-step explanation:

it would take 12 hours for her associate to complete the route by herself

This problem is related to the speed of completing the route.

To solve this problem, we must state the formula for the speed.

[tex]\large {\boxed {v = \frac{x}{t}} }[/tex]

where:

v = speed of completing the route ( m³ / s )

x = route distance ( m³ )

t = time taken ( s )

Let's tackle the problem!

Allison can complete a sales route by herself in 6 hours.

[tex]\text{Allison Speed} = v_a = x \div t_a[/tex]

[tex]v_a = x \div 6[/tex]

Her associate can complete the route by herself in t_s

[tex]\text{Associate Speed} = v_s = x \div t_s[/tex]

[tex]v_s = x \div t_s[/tex]

Working with an associate, she completes the route in 4 hours

[tex]\text{Total Speed} = v = v_a + v_s[/tex]

[tex]\frac{x}{t} = \frac{x}{t_a} + \frac{x}{t_s}[/tex]

[tex]\frac{1}{t} = \frac{1}{t_a} + \frac{1}{t_s}[/tex]

[tex]\frac{1}{4} = \frac{1}{6} + \frac{1}{t_s}[/tex]

[tex]t_s = \frac{ 6 \times 4 }{6 - 4}[/tex]

[tex]t_s = \frac{ 24 }{2}[/tex]

[tex]t_s = 12 ~ \text{hours}[/tex]

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

Answer:

96

Step-by-step explanation:

Answer:

e^x = -3 = -1*3  

x = ln(-3) = ln(-1) + ln(3)  

= (2n+1)iπ + ln(3)  

where n is any integer. For the principal value, choose n=0:  

= iπ + ln(3)

Step-by-step explanation: