Please help me I’ll give brainliest

Consider the molecules HCl, HBr, HF, and HI. Which would you expect to have the highest boiling point, and why?

HBr, because it has the highest mass and the most electrons.
HCl, because it experiences hydrogen bonding.
HF, because it has the strongest intermolecular force.
HI, because it experiences ion-dipole forces.

Answer : The correct option is,

A solid  : a definite volume and  a definite shape.

Explanation :

As we know that there are 3 states of matter :

Solid state : It is defined as a state in which the particles are closely packed and does not have any space between them. This state have a definite shape and volume.  For example : iron metal

Liquid state : It is defined as a state in which the particles are present in random and irregular pattern. The particles are closely arranged but they can move from one place to another. This state have a definite volume but does not have a fixed shape.  For example : water

Gaseous state : It is defined as a state in which the particles are loosely arranged and have a lot of space between them. This state have indefinite volume as well as shape.  For example : Any type of gas like, helium gas.

Hence, the correct answer is, a solid  has a definite volume and  a definite shape.

Answer:

[tex]\boxed{\text{ 86.00\,\%}}[/tex]

Explanation:

[tex]\text{\% yield} = \dfrac{\text{actual yield}}{\text {theoretical yield}} \times\text{100 \%}[/tex]

Data:

       Actual yield = 430.0 g

Theoretical yield = 500.0 g

Calculation:

[tex]\text{\% yield} = \dfrac{\text{430.0 g}}{\text {500.0 g}} \times\text{100 \%} = \boxed{\text{86.00 \%}}[/tex]

A substance used to remove Sulphur from coal is a desulfurizing agent, commonly a limestone slurry. It chemically reacts with the Sulphur emissions, creating less harmful substances like Gypsum.

A substance used in the final stages to remove Sulphur from coal is called a desulfurizing agent or a scrubber. One technique includes the use of a limestone slurry, which reacts chemically with the sulphur emissions and converts them into less harmful substances, such as gypsum. Gypsum, or calcium sulfate, is a beneficial byproduct because it can be used in the manufacture of wallboard and other building materials. Thus, the process not only removes pollutants like sulfur from the coal but also creates a valuable byproduct.

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Answer:

The bond polarities are polar, the molecular shape is trigonal pyramidal, and the molecule is polar.

Explanation:

Answer:

100 degree celsius

Explanation:

Answer:

A

Explanation:

Ohm's law is stated as E = current * resistance (E = I * R)

When you rearrange the formula, you get R = E/I

The answer is current -- A

Answer:

a

Explanation:

Final answer:

An automotive engineer would most likely use chemistry to design and improve automobile catalytic converters, ensuring efficient combustion and reduced toxic emissions. They also work on reformulating gasoline to meet environmental standards and improve engine performance.

Explanation:

The most likely way an automotive engineer would use chemistry is through the design and development of automobile catalytic converters. Scientists have engineered catalytic converters to significantly reduce the toxic emissions resulting from gasoline burned in internal combustion engines. By implementing a blend of catalytically active metals, these converters facilitate the complete combustion of carbon-containing compounds into carbon dioxide, while also diminishing the output of nitrogen oxides.

Another aspect of chemistry in automotive engineering involves the reformulation of gasoline. Removing substances like tetraethyllead, which hampers exhaust catalysts, and decreasing the presence of highly volatile and unsaturated hydrocarbons are critical to reduce photochemical smog and increase engine efficiency.

Answer:

He used the X-ray tool

Explanation:

Answer:

a x ray

Explanation: mark me brainliest plzzz

Answer:

Line or a bar graph

Explanation:

Answer:

I'm pretty sure it's the pie chart

Explanation:

Answer:

whats the statment sis

Explanation:

Answer:B

Answer:

Methane

Choice B is correct

Explanation:

Methane is a key byproduct of the bacterial breakdown in the gut.

Therefore, Methane is most likely to be found around cows

Answer:

Calcium bromide

Explanation:

When naming compounds, the use of prefixes depend on the type of bond made. In this case, calcium and bromine form a ionic bond because calcium is a metal and bromine is a non-metal.

Ionic bonds are not named using prefixes. So no matter how many atoms there are, you will simply write the name of the element for the first element.

For the second element, you name it as well, but only use the root name and end it with -ide.

Answer:

If, for example, we want to know how many moles of oxygen will react with 17.6 mol ... Write the balanced chemical reaction for the combustion of C 5H 12

Explanation:

Answer:

D. C=O

Explanation:

Esters are formed by the condensation of alcohols and acids with minus water. During the reaction, at least one -OH group is replaced by an O- alkyl group. The resulting compound is an ester and has a characteristic fruity smell. Its functional group is C=O

Answer: A. -COO-

Explanation:

Functional groups are specific group of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules.

A. Esters have functional group [tex]-O=C-OR[/tex].

Example: methyl ethanoate with molecular formula [tex]CH_3COOCH_3[/tex]

B. Aledydes have functional group [tex]-O=CH[/tex].

Example: Ethanal with molecular formula [tex]CH_3CHO[/tex]

C. Acids have functional group [tex]-O=C-OH[/tex].

Example: Ethanoic acid with molecular formula [tex]CH_3COOH[/tex]

D. Ketones have functional group [tex]-C=O[/tex].

Example: Propanone with molecular formula [tex]CH_3COCH_3[/tex]

Answer:

If I brush my teeth, I will get fewer cavities than if I don't brush my teeth.

Explanation:

apex

Answer: A new substance(product) is made from different elements(reactants) joined by chemical bonds

Explanation: To have a chemical reaction the chemical properties must change. Atoms are never created or destroyed during chemical reaction but at least one chemical bond is broken or formed. Evidence of a chemical change include: change of odor, change of color (for example, silver to reddish-brown when iron rusts), and change in temperature or energy, such as the production (exothermic) or loss (endothermic) of heat.

Answer:

[tex]\boxed{\text{7.50 L}}[/tex]

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

[tex]p_{1}V_{1} = p_{2}V_{2}[/tex]

Data:

[tex]\begin{array}{rclrcl}p_{1}& =& \text{3.00 atm}\qquad & V_{1} &= & \text{2.50 L} \\p_{2}& =& \text{1.00 atm}\qquad & V_{2} &= & ?\\\end{array}[/tex]

Calculations:

[tex]\begin{array}{rcl}3.00 \times 2.50 & =& 1.00V_{2}\\7.500 & = & 1.00V_{2}\\V_{2} & = &\textbf{7.50 L}\\\end{array}\\\text{The volume of the gas is } \boxed{\textbf{7.50 L}}[/tex]

Using Boyle's law, which states that pressure and volume are inversely related at a constant temperature, we find that the volume of the dry air sample increases to 7.50 L when the pressure is reduced to 1.00 atm.

The question you asked involves the property of gases described by Boyle's law. This law states that at a constant temperature, the pressure and volume of a gas are inversely proportional. In other words, if the pressure of a fixed amount of gas is decreased, its volume will increase accordingly, assuming the temperature remains the same.

To find the new volume of the gas, we can use the formula P1V1 = P2V2, where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume we're looking for. We know that P1 = 3.00 atm, V1 = 2.50 L, and P2 = 1.00 atm. Plugging these values into the equation, we get: 3.00 atm * 2.50 L = 1.00 atm * V2. Solving for V2, we find that V2 = 7.50 L. So, the volume of the gas after reducing the pressure to 1.00 atm, without changing the temperature, is 7.50 L.

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Answer:

The correct answer is True.

Explanation:

An acid is a molecule that has the property of donating a proton or accepting a pair of electrons during a reaction.

The strength of an acid is related to their tendency to lose a proton. A strong acid is one that separates all its components when it comes into contact with water.

As its composition includes hydrogen ions, the more its concentration, the higher the acidity will be, and the lower the pH of the solution.

Its main characteristic is that on contact with water they produce a sour taste.

An acid is a substance that donates protons. Therefore, this given statement is very true.

Acid is any material that when dissolved in water has a sour taste, alters the colour of some indicators (blue litmus paper turns red, for example), combines with some metals (like iron) to release hydrogen, reacts chemically bases to produce salts, and catalyses various chemical reactions. Acids are examples of both organic chemicals that belong to the acid group, carboxylic acid, sulfonic acids, or phenol groups as well as the inorganic substances that comprise the mineral acids, such as sulfuric, nitric, hydrochloric, etc phosphoric acids. An acid is a substance that donates protons. Therefore, this given statement is very true.

To know more about acid, here:

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Answer:

A

Explanation:

Chemicals are repeatedly tested, even those that have existed for

a long time.

Answer:

[tex]\boxed{\text{a) 1.78 MJ; b) 1.25 MJ}}[/tex]

Explanation:

[tex]\rm CH$_4$ + 2O$_2 \longrightarrow \,$ CO$_2$ + 2H$_2$O; \Delta H = - 890.4 \text{ kJ}$\cdot$\text{mol}$^{-1}$[/tex]

a) Energy from 1 mol

[tex]\Delta_{\text{c}}H^{\circ} = \text{2.00 mol} \times \dfrac{\text{-890.4 kJ}}{\text{1 mol}}=\text{-1780 kJ} = \textbf{-1.78 MJ}\\\\\text{The reaction gives off } \boxed{\textbf{1.78 MJ}}[/tex]

b) Energy from 22.4 g

(i) Convert grams to moles

[tex]n = \text{22.4 g } \times \dfrac{\text{1 mol }}{\text{16.04 g}} = \text{1.399 mol}[/tex]

(ii) Convert moles to energy

[tex]\Delta_{\text{c}}H^{\circ} = \text{1.399 mol} \times \dfrac{\text{-890.4 kJ}}{\text{1 mol}}=\text{-1250 kJ} = \textbf{-1.25 MJ}\\\\\text{The reaction releases } \boxed{\textbf{1.25 MJ}}[/tex]

Answer:

number 2 is the answer my friend said

Explanation:

Answer:

Magnesium sulfate monohydrate

Explanation:

The compound is a salt, we have a metal connected to an ion.

To name a salt, first of all, we put the name of the cation, which is the first elemental in the compound. It is followed by the name of the anion.

In this case, the cation is the Magnesium and the anion is the anion sulfate. When the cation can have more than one oxidation number, we need to put this number in parenthesis, like this:

Iron (II) sulfate (FeSO4)

Iron (III) sulfate (Fe2(SO4)3)

However, magnesium can only have 2 as oxidation number, because it's from family 2 in the periodic table. So it's unnecessary to put this information.

As the salt has water in its structure, it's a hydrated salt, and this information needed to be in its name. Because it has only one molecule of water, we put the name monohydrate.

Answer:

117 g  

Explanation:

We are given the amounts of two reactants, so this is a limiting reactant problem.

1. We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:       63.55      32.00                    18.02

             2C₄H₁₀  +  13O₂  ⟶ 8CO₂ + 10H₂O

n/mol:     352         8.47

2. Calculate the amount of water that each reactant can produce

(a) From C₄H₁₀

Moles of H₂O = 352 mol C₄H₁₀ × (10 mol H₂O/2 mol C₄H₁₀) = 704 mol H₂O

(b) From O₂:

Moles of H₂O = 8.47 mol O₂ × (10 mol H₂O/13 mol O₂) = 6.515 mol H₂O

3. Identify the limiting reactant

The limiting reactant is O₂, because it gives fewer moles of H₂O.

4. Calculate the mass of water

Mass of H₂ = 5.515 mol H₂O × (18.02 g H₂)/(1 mol H₂O) = 117 g H₂O

The reaction produces 117 g H₂O.

This calculation yields 1.506 × 10²³ molecules of CO₂.

Calculating the Number of CO₂ Molecules in 0.250 mol of CO₂

To determine the number of CO₂ molecules in 0.250 mol of CO₂, we can use Avogadro's number, which is the number of particles (atoms, molecules, ions, etc.) in one mole of a substance.

Step-by-Step Explanation:

Avogadro's number is 6.022 × 10²³ molecules/mol.

We are given 0.250 mol of CO₂.

Multiply the number of moles by Avogadro's number to find the number of molecules:

Calculation:

0.250 mol × 6.022 × 10²³ molecules/mol

= 1.506 × 10²³ molecules

Therefore, there are 1.506 × 10²³ molecules of CO₂ in 0.250 mol of CO₂.

Answer:

[tex](x-5)^{2}+(y+4)^{2}=100[/tex]

Explanation:

We have been given the center of the circle as (5, -4) and a point on the circumference as (-3, 2). We first determine the radius of the circle. The radius is the distance from the center to any point on the circumference. Using the distance formula, we have;

[tex]radius=\sqrt{(5--3)^{2}+(-4-2)^{2}}\\radius=\sqrt{64+36}=10[/tex]

The radius of the circle is thus 10 units.

The equation of a circle with center (a,b) and radius r units is given as;

[tex](x-a)^{2}+(y-b)^{2}=r^{2}[/tex]

Plugging in the values given we have;

[tex](x-5)^{2}+(y+4)^{2}=100[/tex]

Stanley and his parents had tried to pretend that he was just going away like rich kids do ( A ) is an implied personality trait

Although the excerpt from Holes is missing from your question an answer is provided based on the principle of implied personality trait

An implied personality trait is used to describe the character of a person based on his actions and thought. also implied personality trait are used to make inferences about an individual.

As seen in the sentence " Stanley and his parents had tried to pretend that he was just going away like rich kids do " the inference /conclusion contained in this sentence is that Stanley and his parents are pretending

Hence we can conclude that ; Stanley and his parents had tried to pretend that he was just going away like rich kids do ( A ) is an implied personality trait

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Answer:

Using the molarity of the solution

Explanation:

The concentration of the two solutions can be compared by the use of the number of moles of solute present in each of the solutions. The solution with a higher molarity will be concentrated while the solution with a lower molarity will be dilute.

To compare concentrated and dilute solutions, one looks at the amount of solute in relation to the solvent for the same volume. Calculation of the new concentration after dilution can use the [tex]M_1 \times V_1 = M_2 \times V_2[/tex] equation, applying to stock solutions to reach desired dilutions.

To compare a concentrated solution to a dilute solution while maintaining the same volume, one should examine the ratio of solute to solvent present in the solution. A concentrated solution has a higher concentration of solute, meaning there is a large amount of solute relative to the solvent.

On the other hand, a dilute solution contains a smaller amount of solute hence a lower concentration. This concept can be analogous to the process of making juice from concentrate; you add water to the concentrated juice, thereby increasing the volume while reducing the solute-to-solvent ratio.

When performing calculations, you can use the dilution equation [tex]M_1 \times V_1 = M_2 \times V_2[/tex], where M represents molarity and V represents volume, to determine the new concentration after dilution. For instance, if you have 100 mL of a 2.0 M HCl and dilute it to 500 mL, you can calculate the new molarity ([tex]M_2[/tex]) by applying this equation.

The methodology of dilution typically involves taking a measured volume of a stock solution and adding solvent to reach the desired concentration. This process of diluting adjusts the ratio of solute to solvent, creating a solution of lesser concentration.

Answer:

The rate at which the solute dissolves will increase.

Explanation:

If a solution is stirred, the rate at which a solute dissolves would increase substantially provided the solution is not yet saturated.

Stiring would cause more of the solution to come in contact with every part of the solute. It will increase the surface area of contact for the solution to act which will shoot up the rate of reaction. Stiring helps to bring solutes in solutions into a more close contact with the molecules or compounds of the medium.

Answer:

The molecular formula for Sulfur Dioxide is SO2. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Sulfur Dioxide, or 64.0638 grams.

So yes it is a unit

Explanation:

Answer:

It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams + 16 grams = 18 grams. Since we only have 0.001 grams, that means that we have NA * = 3.35*1019 molecules of water!

Explanation:

I'm just smart.

Answer:

The rate law or rate equation for a chemical reaction is an equation that links the reaction rate with the concentrations or pressures of the reactants and constant parameters. For many reactions the rate is given by a power law such as.

Explanation:

The other person Goggled it. So, pick me as Brainliest.

The primary purpose of a rate law is to provide a mathematical framework that links the rate of a chemical reaction to the concentration of its reactants.

The primary purpose of a rate law is to provide a mathematical expression that describes the relationship between the rate of a chemical reaction and the concentration of its reactants. Through rate laws, scientists can calculate expected yields, determine optimum conditions for economic chemical processes, and understand the course of individual reactions. The derivation of rate laws is essential as they are not directly obtained from chemical equations for ordinary reactions but rather determined from experimental data involving the measurement of concentrations over time.

To ascertain a rate law, the method of initial rates is commonly employed. This involves conducting experiments under varying reactant concentrations and measuring the reaction rates to deduce the reaction order and rate constant. These parameters are indispensable for formulating a rate law, which in turn allows for the calculation of reaction rates under different conditions and aids in the identification of the reaction mechanism.