please help me asap

afraid to fail

Answer:

2 miles

Step-by-step explanation:

Their combined speed (speed of closure) is 80 mph + 40 mph = 120 mph.

120 mi/h = 120 mi/(60 min) = 2 mi/min

The distance between the trains at the 1-minute mark is ...

(1 min) · (2 mi/min) = 2 mi

They were warned when two miles apart.

Answer:

either 76 or 19

Step-by-step explanation:

76 if it's 1/5 of the original amount as well as 3/4 the original amount

1/5+3/4=19/20

3.80=1/20x

3.80+19/20x=76

3.8*20=76

19 if it's 1/5 of the original amount and 3/4 of the new amount

3.80=1/4y

3.80+3/4y=15.20

15.20=4/5x

15.20+1/5x=19

Answer:

The flux of F across S is 8.627.

Step-by-step explanation:

Given,

F(x, y, z) = xy i + yz j + zx k

or F=(xy, yz, zx)

S is the part of the paraboloid [tex]z=8-x^{2} -y^{2}[/tex] above the square 0 ≤ x ≤ 1, 0 ≤ y ≤ 1

By differentiating z with respect to x we get:

fx=-2x

By differentiating z with respect to y we get:

fy=-2y

So, Surface integral is given by:

[tex]=\int\limits^1_0\int\limits^1_0( {(xy)*(2x)+y(8-x^{2} -y^{2} *(2y)+x(8-x^{2} -y^{2})} \, )dx \, dy[/tex][tex]=\int\limits^1_0\int\limits^1_0 (2x^{2} y+16y^{2} -2x^{2} y^{2} -2y^{4}+8x-x^{3}-xy^{2} } \,) dx \, dy[/tex]

Integrating with respect y:

[tex]=\int\limits^1_0(x^{2} y^{2} +\frac{16}{3} y^{3} -\frac{2}{3} x^{2} y^{3} -\frac{2}{5} y^{5}+8xy-x^{3}y-\frac{1}{3} xy^{3} } \, )dx \,[/tex]

After Substituting limits of y, we get:

[tex]=\int\limits^1_0(x^{2} +\frac{16}{3} -\frac{2}{3} x^{2} -\frac{2}{5}+8x-x^{3}-\frac{1}{3} x } \,) dx \,[/tex]

Integrating with respect x:

[tex]=(\frac{1}{3} x^{3} +\frac{16}{3}x -\frac{2}{9} x^{3} -\frac{2}{5}x+4 x^{2} -\frac{1}{4} x^{4}-\frac{1}{6} x^{2} } \,)[/tex]

After Substituting limits of x, we get:

[tex]=(\frac{1}{3} +\frac{16}{3} -\frac{2}{9} -\frac{2}{5}+4 -\frac{1}{4} -\frac{1}{6} } \,)\\\\=\frac{1553}{180}[/tex]

[tex]= 8.627[/tex]

Learn more: https://brainly.com/question/3607066

To evaluate the surface integral of the given vector field F across the given surface S, we need to use the formula: Φ = ∫∫S F · dS. In this case, the vector field F(x, y, z) = xy i + yz j + zx k and the surface S is the part of the paraboloid z = 8 - x^2 - y^2 that lies above the square 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, with upward orientation. We can parametrize the surface S and calculate the normal vector to evaluate the surface integral using the given formula.

To evaluate the surface integral of the given vector field F across the given surface S, we need to use the formula:

Φ = ∫∫S F · dS

In this case, the vector field F(x, y, z) = xy i + yz j + zx k and the surface S is the part of the paraboloid z = 8 - x2 - y2 that lies above the square 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, with upward orientation.

We can parametrize the surface S as r(u, v) = (u, v, 8 - u2 - v2), where 0 ≤ u ≤ 1 and 0 ≤ v ≤ 1.

Next, we calculate the normal vector to S by taking the cross product of the partial derivatives of r(u, v) with respect to u and v: N = (-∂r/∂u) x (-∂r/∂v) = (2u, 2v, 1).

Now, we can evaluate the surface integral using the formula:

Φ = ∫∫S F · dS = ∫∫R F(r(u, v)) · (N · (∂r/∂u) x (∂r/∂v)) du dv

Substituting the values for F and N, we get:

Φ = ∫∫R (u2v + 4uv + 4uv) (2u, 2v, 1) · (2u, 2v, 1) du dv

Calculating this integral over the region R: 0 ≤ u ≤ 1 and 0 ≤ v ≤ 1, we find the flux of F across S.

Answer:

  25,133 m^2

Step-by-step explanation:

The lateral area of a cone is found using the slant height (s) and the radius (r) in the formula ...

  A = πrs

So, we need to know the radius and the slant height.

The radius is half the diameter, so is (160 m)/2 = 80 m.

The slant height can be found using the Pythagorean theorem:

  s^2 = r^2 + (60 m)^2 = (80 m)^2 +(60 m)^2 = (6400 +3600) m^2

  s = √(10,000 m^2) = 100 m

Now, we can put these values into the formula to find the lateral area:

  A = π(80 m)(100 m) = 8000π m^2 ≈ 25,133 m^2

Answer:

c. zero

Step-by-step explanation:

The expression on the left of the equal sign is a polynomial of degree 2. (The highest power of x is 2.) A polynomial of degree 2 is called a "quadratic." Values of the variable (x, in this case) that make the value of the quadratic be zero are called "zeros" or "roots" of the quadratic.

Every polynomial has as many roots as its degree. So, a second degree polynomial (quadratic) will have two roots. The roots may be real numbers, or they may be complex numbers. For polynomials of degree higher than 2, there may be some roots of each kind.

This question is asking, "How many roots of this quadratic are real numbers?"

___

There are several different ways you can figure out the answer to this question. One of the simplest is to graph the quadratic. (See attached.) You can see that the graph of the quadratic never has a y-value of zero, so there are no (real) values of x that will be solutions to this equation.

The two solutions are -0.25±i√1.1875. The "i" indicates that portion of the number is imaginary, and the entire number (real part plus imaginary part) is called a "complex" number. Both solutions for this quadratic are complex, not real.

__

Another way you can answer this question is to compute what is called the "discriminant." The roots of every quadratic of the form ax^2+bx+c can be found using the formula ...

x = (-b±√(b^2-4ac))/(2a)

For this quadratic, the values of a, b, and c are 4, 2, and 5, respectively. Then the formula becomes ...

x = (-2±√(2^2 -4·4·5))/(2·4) = (-2±√-76)/8

The value under the radical sign is the "discriminant." When it is negative, as here, the value of the square root is an imaginary number (not a real number), so the roots are complex. When the discriminant is zero, the two roots have the same value; when it is positive, there are two distinct roots.

There are zero real number solutions to this equation.

Answer:

the left curve is: y=(x+2)³-1;

the right curve is: y=3(x-2)³-1

x(x-7)=8

x^2-7x-8=0

(x-8)(x+1)=0

so x=8 (and -1 but width can’t be negative)

So your answer is C. 8

Answer:

  f(x) = (x -(-3))(x -(-4))

Step-by-step explanation:

The function can be written as the product of binomial terms whose values are zero at the given zeros.

  (x -(-3)) is one such term

  (x -(-4)) is another such term

The product of these is the desired quadratic function. In the form easiest to write, it is ...

  f(x) = (x -(-3))(x -(-4))

This can be "simplified" to ...

  f(x) = (x +3)(x +4) . . . . simplifying the signs

  f(x) = x^2 +7x +12 . . . . multiplying it out

ANSWER

The population in 2000 is 525.5

EXPLANATION

The population is modeled by the equation:

[tex]y=525.5e^{-0.01t}[/tex]

Where y=population (in thousands)

t=the time (in years) with t=0 for the year 2000.

To find the population in the year 2000, we substitite t=0 into the equation to get:

[tex]y=525.5e^{-0.01 \times 0}[/tex]

Perform the multiplication in the exponent:

[tex]y=525.5e^{0}[/tex]

Note that any non-zero number exponent zero is 1.

[tex]y=525.5(1)[/tex]

Any number multiplied by 1 is the same number;

[tex]y=525.5[/tex]

The population in 2000 is 525.5

Answer:

The probability that it will snow and Amy will be late for school is 6%

Step-by-step explanation:

The answer is:

The probability that it will snow and Amy will be late for school is 6%

Step-by-step explanation:

I did the question in the quiz and I got it right soo… ^0^

Answer:

20 years

Step-by-step explanation:

9=x

8=x+15

7=x+15+15

6=x+15+15+15

5=x+15+15+15+15

4=x+15+15+15+15+15

3=x+15+15+15+15+15+15

2=x+15+15+15+15+15+15+15

1=x+15+15+15+15+15+15+15+15

Xx6=6x

6x=x+15+15+15+15+15+15+15+15

6x=120

divide both sides by 6 to get X as 20

we had written the age of the youngest son as X so the youngest son is 20 years old.

Answer:

The weight of the sphere = 2947 pounds

Step-by-step explanation:

* Lets revise the volume of the sphere

- The volume of the sphere is 4/3 π r³, where r is the radius of

  the sphere

- Density = mass ÷ volume

- Mass is the weight and volume is the size, so density is weight

 divided through size

- Density = weight ÷ volume

* Now lets solve the problem

∵ The clay's density ≅ 88 pounds/cubic foot

∵ The radius of the sphere is 2 feet

∵ The volume of the sphere = 4/3 π r³

∴ The volume of the sphere = 4/3 π (2)³ = 32/3 π feet³

∵ Density = weight/volume ⇒ by using cross multiply

∴ Weight = density × volume

∵ Density = 88 pounds/foot³

∵ Volume = 32/3 π feet³

∵ π = 3.14

∴ The weight of the sphere = 88 × 32/3 × 3.14 = 2947 pounds

Answer:

16 cm

Step-by-step explanation:

Consider isosceles triangle ABC with vertex angle ACB of 120° and legs AC=CB=8 cm.

CD is the median of the triangle ABC. Since triangle ABC is isosceles triangle, then median CD is also angle ACB bisector and is the height drawn to the base AB. Thus,

∠DCB=60°

Consider triangle OBC. This triangle is isoscels triangle, because OC=OB=R of the circumscribed about  triangle ABC circle. Thus,

∠OCB=∠OBC=60°

So, ∠COB=180°-60°-60°=60°.

Therefore, triangle OCB is equilateral triangle.

This gives that

OC+OB=BC=8 cm.

The diameter of the circumscribed circle is 16 cm.

Answer:

16 cm

Step-by-step explanation:

Answer:

i belive its 100

Step-by-step explanation:

Answer:

hes right its 100

Step-by-step explanation:

Answer:

t=5.1 days

Step-by-step explanation:

We know that the formula is:

[tex]N = N_0e^{-kt}[/tex]

Where N is the amount of substance after a time t, [tex]N_0[/tex] is the initial amount of substance, k is the rate of decrease, t is the time in days.

[tex]k=0.1368\\N_0 =32[/tex]

We want to find the average life of the substance in days

The half-life of the substance is the time it takes for half the substance to disintegrate.

Then we equal N to 16 gr and solve the equation for t

[tex]16= 32e^{-0.1368t}[/tex]

[tex]0.5= e^{-0.1368t}[/tex]

[tex]ln(0.5)= ln(e^{-0.1368t})[/tex]

[tex]ln(0.5)= -0.1368t[/tex]

[tex]t= \frac{ln(0.5)}{-0.1368}\\\\t=5.1\ days[/tex]

Answer:

5.1

PLATO answer

Step-by-step explanation:

Answer:

I think it is A. But i'm not 100% sure.

Step-by-step explanation:

Hope my answer has helped you!

The answer is:

[tex]FirstCarSpeed=41mph\\SecondCarSpeed=55mph[/tex]

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

[tex]x_{FirstCar}=x_o+v*t[/tex]

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

[tex]x_{SecondCar}=x_o+(v+14mph)*t[/tex]

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them.

If the cars are moving towards each other the relative speed will be:

[tex]RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph[/tex]

Then, since from the statement we know that the cars covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we have:

[tex]2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours[/tex]

Writing the equation, we have:

[tex]264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph[/tex]

So, we have that the speed of the first car is equal to 41 mph.

Now, substituting the speed of the first car in the second equation, we have:

[tex]SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph[/tex]

Hence, we have that:

[tex]FirstCarSpeed=41mph\\SecondCarSpeed=55mph[/tex]

Have a nice day!

Answer:

3 v (v - 7) (w - 1) thus the answer is B:

Step-by-step explanation:

Factor the following:

3 v^2 w - 21 v w - 3 v^2 + 21 v

Factor 3 v out of 3 v^2 w - 21 v w - 3 v^2 + 21 v:

3 v (v w - 7 w - v + 7)

Factor terms by grouping. v w - 7 w - v + 7 = (v w - 7 w) + (7 - v) = w (v - 7) - (v - 7):

3 v w (v - 7) - (v - 7)

Factor v - 7 from w (v - 7) - (v - 7):

Answer:  3 v (v - 7) (w - 1)

Final answer:

To find out how long it will take for an investment to grow with compound interest, we use the formula A = P(1 + r/n)^(nt). Substitute the given values into the formula and solve for t using logarithms to find the time needed for the investment to reach the desired amount.

Explanation:

To determine how long it will take for $1000 invested in an account earning 3% compounded monthly to grow to $1500, we use the formula for compound interest:

[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]

Where:

We want to solve for t when A is $1500, P is $1000, r is 0.03 (3%), and n is 12 (since interest is compounded monthly). Substituting these values into the formula we have:

Dividing both sides by $1000 and using algebra, we can solve for t:

[tex]1.5 = (1 + \frac{0.03}{12})^{12t}[/tex]

To solve for t, we take the natural logarithm of both sides:

[tex]ln(1.5) = ln((1 + \frac{0.03}{12})^{12t})[/tex]

[tex]ln(1.5) = 12t * ln(1 + \frac{0.03}{12})[/tex]

[tex]t = \frac{ln(1.5)}{12 * ln(1 + \frac{0.03}{12})}[/tex]

After calculating the above expression using a calculator, you will find the value of t, which is the time in years it will take for the investment to grow to $1500.

Answer: Last Option

[tex]4x^5\sqrt[3]{3x}[/tex]

Step-by-step explanation:

To make the product of these expressions you must use the property of multiplication of roots:

[tex]\sqrt[n]{x^m}*\sqrt[n]{x^b} = \sqrt[n]{x^{m+b}}[/tex]

we also know that:

[tex]\sqrt[3]{x^3} = x[/tex]

So

[tex]\sqrt[3]{16x^7}*\sqrt[3]{12x^9}\\\\\sqrt[3]{16x^3x^3x}*\sqrt[3]{12(x^3)^3}\\\\x^2\sqrt[3]{16x}*x^3\sqrt[3]{12}\\\\x^5\sqrt[3]{16x*12}\\\\x^5\sqrt[3]{2^4x*2^2*3}\\\\x^5\sqrt[3]{2^6x*3}\\\\4x^5\sqrt[3]{3x}[/tex]

Answer:

Step-by-step explanation:

The probability would be twice as large for eight coins I think

The probability distribution of flipping coins changes as the number of coins increases due to the law of large numbers. The probability of getting half heads is the highest when flipping four coins, whereas the probability distribution broadens with eight coins, making specific outcomes less likely.

When analyzing the probability of outcomes when flipping coins, we can compare the cases of flipping four coins to flipping eight coins. When flipping four coins, the most likely outcome is two heads, with a probability of 0.38. The probability of getting one head, which is one-fourth of the coins, has a probability of 0.25. However, these probabilities might change when flipping eight coins because as the number of coin flips increases, the distribution of outcomes tends to become more even due to the law of large numbers.

Tossing a fair coin should theoretically result in 50 percent heads over the long term, as demonstrated by Karl Pearson's experiment which approximated the theoretical probability after 24,000 coin tosses. When moving to eight coins, the probability distribution for getting different fractions of heads will widen, meaning that it's less likely to get a specific outcome (in terms of fractions of heads) because there are more possible combinations (microstates).

Overall, while the exact probabilities for eight coins are not provided, we can expect that the probability of getting exactly half heads will decrease since there are more total combinations possible, and the probability for one-fourth heads will also change but without specific numbers, we cannot determine the precise probabilities.

Completing the square gives

[tex]y=8x-x^2=16-(x-4)^2[/tex]

and

[tex]16=16-(x-4)^2\implies(x-4)^2=0\implies x=4[/tex]

tells us the parabola intersect the line [tex]y=16[/tex] at one point, (4, 16).

Then the volume of the solid obtained by revolving shells about [tex]x=0[/tex] is

[tex]\displaystyle\pi\int_0^4x(16-(8x-x^2))\,\mathrm dx=\pi\int_0^4(x-4)^2\,\mathrm dx[/tex]

[tex]=\pi\dfrac{(x-4)^3}3\bigg|_{x=0}^{x=4}=\boxed{\dfrac{64\pi}3}[/tex]

Answer:

0, 1/3

Step-by-step explanation:

The equation can be factored as ...

4x(3x -1) = 0

The values of x that will satisfy this equation are the values of x that make the factors be 0.

x = 0 . . . . . . when x=0

3x -1 = 0 . . . when x = 1/3

The values of x that will satisfy the equation are 0 and 1/3.

Answer:

0, 1/3

Step-by-step explanation:

The equation can be factored as ...

4x(3x -1) = 0

The values of x that will satisfy this equation are the values of x that make the factors be 0.

x = 0 . . . . . . when x=0

3x -1 = 0 . . . when x = 1/3

The values of x that will satisfy the equation are 0 and 1/3

Answer:

Sheridan is correct.

Step-by-step explanation:

She is correct because there is no B squared listed only A and C are provided, Jayden put 13 cm as B instead of listing it as C but she listed it correctly and answered everything else correctly.

Hope this helps!

Answer:

5676.16 cm^3

Step-by-step explanation:

The volume of any prism is given by the formula ...

V = Bh

where B is the area of one of the parallel bases and h is the perpendicular distance between them. Here, the base is a triangle, so its area will be ...

B = 1/2·bh

where the b and h in this formula are the base and height of the triangle, 28 cm and 22.4 cm.

Then the volume is ...

V = (1/2·(28 cm)(22.4 cm))·(18.1 cm) = 5676.16 cm^3

_____

You will note that this is half the product of the three dimensions, so is half the volume of a cuboid with those dimensions. Perhaps you can see that if you took another such prism and placed the faces having the largest area against each other, you would have a cuboid of the dimensions shown.

Answer:

[tex]V=5,676.16\ cm^{3}[/tex]

Step-by-step explanation:

we know that

The volume of the triangular prism is equal to

[tex]V=BL[/tex]

where

B is the area of the triangular face

L is the length of the triangular prism

Find the area of the triangular face B

[tex]B=\frac{1}{2}(28*22.4)= 313.6\ cm^{2}[/tex]

we have

[tex]L=18.1\ cm[/tex]

substitute the values

[tex]V=313.6*18.1=5,676.16\ cm^{3}[/tex]

Let's analyse the function

[tex]y = f(x) = A\sin(\omega x)[/tex]

The amplitude is A, so we want A=1.5

Now, we start at x=0, and we have [tex]1.5\sin(0)=0[/tex]

After one second, i.e. x=1, we want this sine function to make 330 cycles, i.e. the argument must be [tex]330\cdot 2\pi[/tex]

So, we have

[tex]f(1)=1.5\sin(\omega) = 1.5\sin(660\pi)[/tex]

so, the function is

[tex]f(x) = 1.5\sin(660\pi x)[/tex]

Answer:

f(x) = 1.5\sin(660\pi x)

Step-by-step explanation:

Answer:

g(x) is translated down 2 units from f(x)

Step-by-step explanation:

Adding -2 to the function value moves it down 2 units.

Answer:

The graph of f(x) is shifted to right by 2 units to get graph of g(x).

Step-by-step explanation:

We have been given two functions [tex]f(x)=4^x[/tex] and [tex]g(x)=4^{x-2}[/tex]. We are asked to find the graph of g(x) is related to the parent function f(x).

Let us recall transformation rules.

[tex]f(x)\rightarrow f(x-a)=\text{Graph shifted to right by a units}[/tex]

[tex]f(x)\rightarrow f(x+a)=\text{Graph shifted to left by a units}[/tex]

[tex]f(x)\rightarrow f(x)-a=\text{Graph shifted downwards by a units}[/tex]

[tex]f(x)\rightarrow f(x)+a=\text{Graph shifted upwards by a units}[/tex]

Upon comparing the graph of f(x) to g(x), we can see that [tex]g(x)=f(x-2)[/tex], therefore, the graph of f(x) is shifted to right by 2 units to get graph of g(x).

Answer:

The triangle should be 4 inches tall

Step-by-step explanation:

We can write a proportion to solve.  Put the height over the width

20           x

------- = -----------

5              1

Using cross products

20*1 = 5*x

20 = 5x

Divide by 5

20/5 = 5x/5

4 =x

The triangle should be 4 inches tall

To find the new height when the width of a triangle is reduced, you can use the concept of similar triangles and ratios.

To determine the new height of the triangle, we can use the concept of similar triangles. Similar triangles have proportional sides. So, if the width of the triangle is reduced from 5 in to 1 in, the height will also be reduced proportionally. Using the ratio of the new width to the original width, we can find the new height:

New height = (new width / original width) * original height = (1 / 5) * 20 = 4 in

https://brainly.com/question/32489731

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Answer:

The measure of arc DC is [tex]11\°[/tex]

Step-by-step explanation:

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

[tex]m\angle ATB=\frac{1}{2}[arc\ AB+arc\ DC][/tex]

substitute the given values

[tex]63\°=\frac{1}{2}[115\°+arc\ DC][/tex]

[tex]126\°=[115\°+arc\ DC][/tex]

[tex]arc\ DC=126\°-115\°=11\°[/tex]

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite. Then the arc DC will be 11°.

The angle is the distance between the intersecting lines or surfaces. The angle is also expressed in degrees. The angle is 360 degrees for one complete spin.

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

 ∠ATB = 1/2 [arc AB + arc DC]

     63° = 1/2 [115° + arc DC]

arc DC = 11°

More about the angled link is given below.

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For this case we have the following expression:

[tex]\sqrt {29-12 \sqrt {5}}[/tex]

The expression can not be simplified, we can write its decimal form.

We have to:

[tex]12 \sqrt {5} = 26.83281572[/tex]

Then, replacing:

[tex]\sqrt {29-26.83281572} =\\\sqrt {2,16718428} =\\1.4721359584[/tex]

If we round up we have:

[tex]\sqrt {29-12 \sqrt {5}} = 1.47[/tex]

ANswer:

[tex]\sqrt {29-12 \sqrt {5}} = 1.47[/tex]