PLEASE HELP < I NEED HELP, TRYING TO MAKE HONOR ROLL

Translate the sentence into an equation.
Nine less than the product of 3 and a number is 4 .
Use the variable w for the unknown number.

Answer:

Step-by-step explanation:

The only possible simplification of the slope -5/1 is -5.

Answer:

54

Step-by-step explanation:

4.5x=3(x+27)

4.5x=3x+81

1.5x=81

x=54

Answer:
it is proportional

Step-by-step explanation:

Proportional functions will be in the form y = kx and non-proportional functions will be in the form y = mx + b

Answer:

12

Step-by-step explanation:

0.8 is equal to 80%

you need to figure out 80% of 15

100% = 15

10% = 1.5

(x8)

80% = 12

you would need to shade 12 out of 15 boxes which gives 0.8 chance of picking a shaded one

Answer:

Sample answer: The number of squares that are shaded divided by 15 must equal 0.8, so the number of squares must be 0.8(15), which equals 12. The fraction 12/15 reduces to 4/5 which is equal to 8/10.

Step-by-step explanation:

The sample answer on edge

A) No, the probability of getting a 3 on a fair die does not change. It will always be 1/6  no matter what she got on the previous roll.

Step-by-step explanation:

Lets define probability first

"Probability is the likeliness of occurrence of an event"

When we call a die fair, that means that each number on the die has an equal chance of occurrence when rolled.

If on 7 rolls, the outcomes were 7 each time, this doesn't mean that the chances of rolling a specific number on a fair die is changed. On the next roll, 3 will have the same probability as before that is 1/6

So,

The correct answer is:

A) No, the probability of getting a 3 on a fair die does not change. It will always be 1/6  no matter what she got on the previous roll.

Keywords: Probability, die roll

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Answer:

your answer is 70

Step-by-step explanation:

Final answer:

The greatest common factor of 75 and 20 is 5, and by applying the distributive property, the expression 75+20 can be factored as 5(19).

Explanation:

The greatest common factor (GCD) of 75 and 20 is 5. Applying the distributive property to factor out 5, we get:

75 + 20 = 5 × (15 + 4)

Here's the breakdown:

Find the GCD: The largest factor that divides both 75 and 20 is 5.

Divide each term by the GCD: Divide 75 by 5 to get 15 and divide 20 by 5 to get 4.

Rewrite with the GCD factored out: Combine the results from step 2 and multiply by the GCD: 5 × (15 + 4).

Therefore, the factored expression using the distributive property is 5 × (15 + 4).

Thus, the factored form of the expression 75+20 is 5(19).

Answer:

Step-by-step explanation:

17/333 11/120 7/99 4/52 3/50

Answer:

The Proof is below.

Therefore the Perimeter of Christmas paper is 32 feet  ..Proved

Step-by-step explanation:

Let the Christmas Paper have Dimensions as

Length = 8 feet

Width = 8 feet

To Show:

Perimeter of Christmas Paper = 32

Solution:

Christmas Paper is in Rectangle  Shape,

Therefore Perimeter of a Rectangle is given as

[tex]Perimeter\ of\ Rectangle=2(Length+Width)[/tex]

Substituting the values we get

[tex]Perimeter=2(8+8)=2\times 16=32\ feet[/tex]

Therefore the Perimeter of Christmas paper is 32 feet  ..Proved

The perimeter of a square is calculated by adding the lengths of all four sides. An 8 ft by 8 ft square has a perimeter of 32 ft, because 8 ft multiplied by 4 (the number of sides in a square) equals 32 ft.

This question involves understanding the concept of perimeter in the context of a square. If you have a piece of Christmas paper that is 8 feet long and 8 feet wide, you actually have a square because all sides are of equal length. To calculate the perimeter of a square, you simply add up the lengths of all four sides.

Since each side is 8 feet, the perimeter P is given by:

P = side + side + side + side
P = 8 ft + 8 ft + 8 ft + 8 ft
P = 32 ft

So, the perimeter of the Christmas paper, if shaped like a square, is 32 feet, which is simply four times the length of one side.

Answer:

The change in her speed is 7 m/s - 4 m/s = 3 m/s.

Step-by-step explanation:

Speed is defined as the rate of change of distance with time.

i) Let the total distance of the cross country be x meters.

ii) The change in her speed is 7 m/s - 4 m/s = 3 m/s.

The percent of the market will teddy bears occupy in November is 28.47%.

To determine the quantity or percentage of something in terms of 100, use the percentage formula. Per cent simply means one in a hundred. With the percentage formula, a number between 0 and 1 can be expressed. A number that is expressed as a fraction of 100 is what it is. It is mostly used to compare and determine ratios and is represented by the symbol %.

Form a table as shown

Months         Teddy Bears    Rabbits     Cats    Horses    Others    Totals toys

September      225                275           245      260          199        1204

October           346                 308           186      297          285       1422

November       467                 341            127       334          371         1640

So, the percent of the market will teddy bears occupy in November

= 467 / 1640 x 100

= 0.2847 x 100

= 28.47%

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Answer:

14/25

Step-by-step explanation:

p(red or blue)=6/(6+8+11) +8/(6+8+11)=6/25+8/25=14/25

Answer:

56% yall

Step-by-step explanation:

Answer:

by definition

The coordinates of point A are:

(cosθ , sinθ)

Answer:

Therefore the scale used is 1 inch : 6.667 inches

Step-by-step explanation:

i) Scale used is 9 inches = 5 feet

ii) Scale used 9 inches = 5 [tex]\times[/tex] 12 inches = 60 inches

iii) Scale used is 1 inch  [tex]= \dfrac{60}{9}\hspace{0.2cm} = \hspace{0.2cm}\dfrac{20}{3} \hspace{0.2cm} = 6.667\hspace{0.2cm} inches[/tex]

iv) Therefore the scale used is 1 inch : 6.667 inches

The radius of circle is 12 inches

Solution:

Given that,

Consider circle c with angle [tex]\frac{3 \pi }{4} \text{ radians }[/tex]

Minor arc AB measures [tex]9 \pi[/tex] inches

Therefore, we can say,

[tex]Central\ angle\ in\ radians = \frac{3 \pi }{4}\\\\Arc\ length = 9 \pi[/tex]

To find: Radius of circle

The length of arc when angle given in radians is:

[tex]s = r \times \theta[/tex]

Where,

"s" is the arc length and "r" is the radius and [tex]\theta[/tex] is the central angle in radians

[tex]9 \pi = r \times \frac{3 \pi }{4}\\\\r = 9 \times \frac{4}{3}\\\\r = 12[/tex]

Thus the radius of circle is 12 inches

Answer:

B.) 12 inches

Step-by-step explanation:

Answer:

y + 3 = (-5/2)(x - 2)

Step-by-step explanation:

First look at y =5x + 2.  It's immediately apparent that the y-intercept is 2, or (0, 2).  (0, 2) must then be a point on the new line, and we are told that (2, -3) is also on this new line.

The general point-slope equation is y - k = m(x - h).

We need to determine the slope of the new line.

Let h = 2, k = -3, x = 0 and y = 2.  Then:

2 + 3 = m(0 - 2).  Therefore, -2m = 5, and m = -5/2.

Then the equation of the new line, in point-slope form, is

y + 3 = (-5/2)(x - 2)

Let's check this result.  Do the coordinates of the y-intercept, (0, 2) satisfy this equation?

Is 2 + 3 = (-5/2)(0 - 2) true?

Is 5       = (-5/2)(-2) true?  YES

The equation of line is 2y = -5x+ 4.

A line's slope is determined by how its y coordinate changes in relation to how its x coordinate changes. y and x are the net changes in the y and x coordinates, respectively. The slope of the line is the ratio of the rise to the run, or the rise divided by the run, therefore the change in y coordinate with regard to the change in x coordinate may be expressed as follows

m = Δy/Δx

where, m is the slope

In the coordinate plane, it describes the slope of the line.

Given:

passes through the point (2,-3) and has the same y intercept as y =5×+2

The, the intercept for the required line is 2.

Now, using y= mx+b

-3 = m(2) + 2

2m = -5

m= -5/2

Now, the equation of line passes through (2, -3)

y - y1 = m(x- x1)

y + 3= -5/2( x-2)

2y + 6= -5x+ 10

2y = -5x+ 4

Hence, the equation of line is 2y = -5x+ 4.

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Answer:

Investor invested $7,800 at 8% and $6,200 at 6.5%

Step-by-step explanation:

Use formula

[tex]I=P\cdot r\cdot t,[/tex]

where

I = interest

P = principal

r = rate (as decimal)

t = time

First investment:

[tex]P_1=x\\ \\r_1=0.08\\ \\t_1=1[/tex]

then

[tex]I_1=x\cdot 0.08\cdot 1\\ \\I_1=0.08x[/tex]

Second investment:

[tex]P_2=14,000-x\\ \\r_2=0.065\\ \\t_2=1[/tex]

then

[tex]I_2=(14,000-x)\cdot 0.065\cdot 1\\ \\I_2=0.065(14,000-x)[/tex]

The amount of interest earned for 1 year was $1,027, then

[tex]I_1+I_2=1,027\\ \\0.08x+0.065(14,000-x)=1,027\\ \\0.08x+910-0.065x=1,027\\ \\0.08x-0.065x=1,027-910\\ \\0.015x=117\\ \\x=7,800\\ \\14,000-x=6,200[/tex]

Investor invested $7,800 at 8% and $6,200 at 6.5%

Answer: A. -14

Step-by-step explanation:

Answer: A. -14

Step-by-step explanation: Use PEMDAS

(5+4-2) x (-2)

= (9-2) x (-2)

= 7 x (-2)

= -14

Answer:

Step-by-step explanation:

6x + 4y = 2                              3x + 2y = 1

4y = -6x + 2                             2y = -3x + 1

y = - 3/2x + 1/2                        y = -3/2x + 1/2

same line, infinite solutions.....Consistent and dependent

Answer:

Consistent and dependent

Step-by-step explanation:

Answer:

-$336.00

Step-by-step explanation:

-$248.00+-$73.00+-$15.00=-$336.00

Answer:

The hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be [tex]x.[/tex]

And the hotel charge in second city before tax be [tex]y.[/tex]

So, as the hotel charge of the second city was 1500 higher than the first.

Thus,

[tex]y=x-1500[/tex]   ........(1)

And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.

6% of [tex]x[/tex] + 10% of [tex]y[/tex] = $670.

[tex]\frac{6x}{100} +\frac{10y}{100} =670[/tex]

[tex]0.06x+0.10y=670[/tex]

Substituting the value of [tex]y[/tex] from equation (1) we get:

[tex]0.06x+0.10(x-1500)=670[/tex]

[tex]0.06x+0.10x-150=670[/tex]

[tex]0.16x-150=670[/tex]

Adding both sides by 150 we get:

[tex]0.16x=820[/tex]

Dividing both sides by 0.16 we get:

[tex]x=5125.[/tex]

The hotel charge in first city before tax = $5125.

Now, substituting the value of [tex]x[/tex] in equation (1) we get:

[tex]y=x-1500[/tex]

[tex]y=5125-1500[/tex]

[tex]y=3625.[/tex]

The hotel charge in second city before tax = $3625.

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

m x H = [tex]\left[\begin{array}{ccc}-25&37.5&-12.5\\\9\end{array}\right][/tex]

Step-by-step explanation:

Step 1; Multiply 5 with this matrix  [tex]\left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right][/tex] and we get a matrix [tex]\left[\begin{array}{ccc}-5&10\\20&40\\\end{array}\right][/tex]

Multiply the fraction  [tex]\frac{2}{5}[/tex] with the matrix  [tex]\left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right][/tex] and we get [tex]\left[\begin{array}{ccc}-\frac{2m}{5} &\frac{4m}{5} \\\frac{8m}{5} &\frac{16m}{5} \\\end{array}\right][/tex]

Step2; Now equate corresponding values of the matrices with each other.

-5 = [tex]\frac{-2m}{5}[/tex] and so on. By equating we get the value of m as [tex]\frac{25}{2}[/tex]

Step 3; Add the matrices to get the value of matrix m.

Adding the three matrices on the RHS we get  [tex]\left[\begin{array}{ccc}2&9&-9\\\end{array}\right][/tex].

Step 4; Adding the matrices on the LHS we get the resulting matrix as H +

[tex]\left[\begin{array}{ccc}4&6&-8\\\9\end{array}\right][/tex]. Equating the matrices from step 3 and 4 we get the value of H as [tex]\left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right][/tex]

Step 5; Now to find the value of m x H we need to multiply the value of [tex]\frac{25}{2}[/tex] with the matrix [tex]\left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right][/tex]

Step 6; Multiplying we get the matrix m x H = [ -25  [tex]\frac{75}{2}[/tex]  [tex]\frac{-25}{2}[/tex] ]

Answer:

y = 5x - 10 and y = 5(x + 2) are the system of equations that has no solution.

Step-by-step explanation:

The slope-intercept form of a straight line equation is given by, y = mx + c, where m is the slope and c is the y-intercept.

Now, only a system of parallel straight lines has no solution.

And the parallel straight lines have an equal slope and different y-intercept.

Hence, the given equation, y = 5x - 10 has slope equals to 5 and y-intercept - 10.

And the lines given in the options, only the second line i.e. y = 5(x + 2) has the same slope i.e. 5 and different y-intercept i.e. 10 ≠ - 10.

So, y = 5x - 10 and y = 5(x + 2) are the system of equations that has no solution. (Answer)

Answer:

B: y=5(x+2)

Step-by-step explanation:

Answer:

7

Explanation:

(3)(3)+(4)(2) − 10

(3)(3)

= 9

(4)(2)

= 8

9 + 8 = 17

17 - 10 = 7

Answer:

7

Step-by-step explanation:

3(3)+4(2)-10

9+8-10

17-10

7

[tex]-2\frac{1}{2} +1\frac{1}{3}=\frac{-1}{6}[/tex]

Solution:

Given expression is [tex]-2\frac{1}{2} +1\frac{1}{3}[/tex].

Let us first convert mixed fraction into improper fraction.

[tex]-2\frac{1}{2} +1\frac{1}{3}=\frac{(-2\times 2) +1}{2} +\frac{(1\times 3) + 1}{3}[/tex]

              [tex]=\frac{-4 +1}{2} +\frac{3 + 1}{3}[/tex]

              [tex]=\frac{-3}{2} +\frac{4}{3}[/tex]

Take LCM for the denominators (LCM of 2, 3 = 6) and make the same.

              [tex]=\frac{-3\times3}{2\times3} +\frac{4\times2}{3\times2}[/tex]

              [tex]=\frac{-9}{6} +\frac{8}{6}[/tex]

              [tex]=\frac{-1}{6}[/tex]

[tex]-2\frac{1}{2} +1\frac{1}{3}=\frac{-1}{6}[/tex]

Hence the fraction form of [tex]-2\frac{1}{2} +1\frac{1}{3}[/tex] is [tex]\frac{-1}{6}[/tex].

Answer:

5) The correct answer is D.

6) The correct answer is A.

7) m = (10 - 6)/(1 - 0) = 4/1 = 4

The correct answer is C.

8) The correct answer is B.

Answer:

5 feet long

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Answer:

The equation of the required line in the slope-intercept form is

y = -3x + 10

Step-by-step explanation:

i) the required line passes through the point (5, -5)

ii) the required line is also parallel to the line 3x + y = -2 ⇒ y = -3x - 2

  Therefore the slope of the given line is -3.

  Therefore the slope of the required line is also -3

  The equation of the required line in the slope-intercept form is

  y - (-5) = -3(x - 5) ⇒ y + 5 = -3x + 15    ⇒      y = -3x + 10   ∴ 3x + y = 10.