Answer:
Step-by-step explanation:
Distribute...
6x^2-3x-6x+3
6x^2-9x+3 is the expanded equation
The solution....
(3x-3)=0
(2x-1)=0
3x=3
2x=1
x=1
x=1/2
Solve for x.
x2 + 9x = 0
Answer:
0,-9
Step-by-step explanation:
To solve [tex]x^2[/tex] + 9x = 0, we factor out the common x to get x(x + 9) = 0 and set each factor equal to zero, which gives us the solutions x = 0 and x = -9.
To solve the equation x2 + 9x = 0, we can apply factoring techniques. The first step is to factor out the common factor x from both terms in the equation. This yields:
x(x + 9) = 0
Then you have to realize that a product of two multiplicands is equal to zero if either multiplicand is equal to zero. Setting either multiplicand equal to zero and solving for x yields the solutions. Therefore, we have two multiplicands:
x = 0
x + 9 = 0, which simplifies to x = -9
The solutions to the equation are x = 0 and x = -9. As a check, we can substitute these values back into the original equation and confirm that both satisfy the equation.
Solve the following inequality-3.55g<-28.4
Answer:
B (the second graph)
Step-by-step explanation:
3.55g<-28.4
Divide each side by 3.55
3.55g/3.55<-28.4/3.55
g < -8
This would be an open circle at 8 (because g is less than not less than or equal to) and it goes to the left ( since g is less than)
What is the standard form equation of the line shown below?
Answer:
maybe
[tex] y = \frac{1}{2} x + 0.5[/tex]
Answer:
x - 2y = - 1
Step-by-step explanation:
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
Obtain the equation in slope- intercept form
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 3, - 1) and (x₂, y₂ ) = (3, 2) ← 2 points on the line
m = [tex]\frac{2+1}{3+3}[/tex] = [tex]\frac{3}{6}[/tex] = [tex]\frac{1}{2}[/tex]
y = [tex]\frac{1}{2}[/tex] x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (3, 2), then
2 = [tex]\frac{3}{2}[/tex] + c ⇒ c = [tex]\frac{1}{2}[/tex]
y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{1}{2}[/tex] ← in slope- intercept form
Multiply all terms by 2
2y = x + 1 ( subtract 2y from both sides )
0 = x - 2y + 1 ( subtract 1 from both sides )
- 1 = x - 2y , that is
x - 2y = - 1 ← in standard form
solve for Z- 2 + 8 = 24 show work
Answer:
z = 18Step-by-step explanation:
[tex]z-2+8=24\\\\z+(-2+8)=24\\\\z+6=24\qquad\text{subtract 6 from both sides}\\\\z+6-6=24-6\\\\z=18[/tex]
Answer:
Z = 18
Step-by-step explanation:
Z- 2 + 8 = 24
Combine like terms
Z +6 = 24
Subtract 6 from each side
Z+6-6 =24-6
Z = 18
i will give brainliest A whole number is 6 more than 2 times another number. The sum of the two numbers is less than 50. This can be written in an inequality as x + 2x + 6 < 50, where x represents the smaller number.
From the set {13, 14, 15, 16, 17}, the values of x for which the inequality holds true are .
Answer:
13 and 14
Step-by-step explanation:
13+ (2*13) +6= 45 which is less than 50
14+ (2*14) +6= 48 which is also less than 50.
When you do the same with 15,16, and 17 the answers all come out to be 51, 54, and 57 which are all greater than 50
Answer:
13 and 14
Step-by-step explanation:
Given : [tex]x + 2x + 6 < 50[/tex]
To Find : From the set {13, 14, 15, 16, 17}, the values of x for which the inequality holds true are .
Solution:
Inequality : [tex]x + 2x + 6 < 50[/tex]
Substitute x = 13
[tex]13 + 2(13) + 6 < 50[/tex]
[tex]45 < 50[/tex]
Substitute x = 14
[tex]14 + 2(14) + 6 < 50[/tex]
[tex]48 < 50[/tex]
Substitute x = 15
[tex]15 + 2(15) + 6 < 50[/tex]
[tex]51 > 50[/tex]
Substitute x = 16
[tex]16+ 2(16) + 6 < 50[/tex]
[tex]54 > 50[/tex]
Substitute x = 17
[tex]17+ 2(17) + 6 < 50[/tex]
[tex]57 > 50[/tex]
So, the values of x for which the inequality holds true are 13 and 14.
Find the inverse function of g(x) = 2x + 4. g -1(x) = 4x + 2 g -1(x) = 2x + g -1(x) = x - 2 g -1(x) = 2x - 4
For this case we must find the inverse of the following function:
[tex]g (x) = 2x + 4[/tex]
Replace g(x) with y:
[tex]y = 2x + 4[/tex]
We exchange the variables:
[tex]x = 2y + 4[/tex]
We solve for "y":
We subtract 4 on both sides of the equation:
[tex]x-4 = 2y[/tex]
We divide between 2 on both sides of the equation:
[tex]y = \frac {x} {2} -2[/tex]
We change y by [tex]g ^ {-1} (x)[/tex]:
[tex]g ^ {- 1} (x) = \frac {x} {2} -2[/tex]
Answer:
[tex]g ^ {- 1} (x) = \frac {x} {2} -2[/tex]
Answer:
[tex]f^{-1}=\frac{x}{2} -2[/tex]
Step-by-step explanation:
the inverse function of g(x) = 2x + 4
To find the inverse of a function we replace g(x) with y
[tex]y=2x+4[/tex]
Replace x with y and y with x
[tex]x=2y+4[/tex]
Solve the equation for y
Subtract 4 from both sides
[tex]x-4= 2y[/tex]
Divide both sides by 2
[tex]\frac{x}{2} -2=y[/tex]
[tex]y=\frac{x}{2} -2[/tex]
Replace y with f inverse
[tex]f^{-1}=\frac{x}{2} -2[/tex]
If f(9)=7, then the point ___________ is on the graph of f.
Answer:
(9,7)
Step-by-step explanation:
F(a)=b means the point (a,b) is on the graph of F
The point that is on the graph of the function f, given f(9)=7, is (9, 7). This results because 9 is the input (x-coordinate) and 7 is the output (y-coordinate) of the function.
Explanation:In mathematics, particularly in graphing functions, each point on the graph of a function f is represented by an ordered pair: the input (x-coordinate) and the output (y-coordinate). When you are given that f(9)=7, this essentially means that when the input is 9, the output is 7. Therefore, the point that is on the graph of the function f is (9, 7).
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What is 6 consecutive integers starting with -3
Answer:
-3, -2, -1, 0, 1, 2
Step-by-step explanation:
Note that "integer" means whole numbers, and "consecutive" means continuously following. Also, note that you are starting with -3:
-3 , -2 , -1 , 0 , 1 , 2, is your answer, because you just need to add 1 each time until you have 6 numbers.
~
Assume x > 0 and y 0.
algebra II engenuity
Answer:
Third Option
Step-by-step explanation:
Given expression is:
[tex]\sqrt{\frac{55x^7y^6}{11x^11y^8}}[/tex]
Simplifying
[tex]=\sqrt{\frac{11*5*x^7*y^6}{11*x^11*y^8}}\\=\sqrt{\frac{5*x^7*y^6}{x^11*y^8}}\\Combining\ exponents\ with\ same\ base\\=\sqrt{\frac{5}{11*x^{(11-7)}*y^{(8-6)}}}\\=\sqrt{\frac{5}{x^{4}*y^{2}}}\\Applying\ radical\\=\frac{5^{\frac{1}{2}}}{x^{(4*\frac{1}{2})}*y^{(2*\frac{1}{2})}}}\\=\frac{\sqrt{5}}{x^2y}[/tex]
As 5 cannot be taken out of the square root, it will remain inside the square root.
Hence, Third option is the correct answer ..
I WILL AWARD BRAINLIEST!!! PLEASE HELP!!!
Given: ∠AOC, ∠BOC - linear pair
OM - ∠ bisector of ∠ AOC
ON - ∠ bisector of ∠ BOC
Find: m∠MON
Fill in the blanks for the Statement and Reason below :
Statement Reason
1.m∠AOC +m∠______ = 180° | ______________________
2. m∠AOC = 2·m∠_______ |______________________
3. m∠BOC = 2·m∠_______ |______________________
4. m∠MOC +m∠_____ = |
1/2(m∠AOC +m∠_____) = ___ | Algebra, transitivity
5. m∠MON = ____ | Algebra
Check the picture below.
recall that OM is an angle bisector, so those two "green" angles are equal, the same goes for ON which is also an angle bisector, those two "red" angles are also equal.
Answer:
hello
Step-by-step explanation:
i'm just making this answer so the other guy who obviously worked VERY hard on his answer can get a brainliest. :) don't mind me
What is the quotient?
Answer:
D) 5 7/9
Work Shown:
-52/-9 = 5 7/9 = 5.7777777778
find the exact value of cos(sin^-1(-5/13))
bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.
[tex]\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}[/tex]
[tex]\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}[/tex]
le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.
How long will it take to earn $1800 in interest if $6000 is invested at a 6% annual interest rate?
Answer:
It will take 5 years.
Step-by-step explanation:
Let's find how long it will take, but first let's understand the equation.
For simple interest, we use the equation:
T=(1/R)*(((A+B)/B)-1) where,
A= interest amount
B=invested money
R=interest rate (in decimal form)
T=time
Because we want to earn $1800 in interest, then A=1800.
Because we invested $6000, then B=6000.
Because we are investing under an interest rate of 6%, then R=0.06.
'How long will it take' means that T= not given, but its value is in 'years', since an annual rate was given.
Using the equation for simple interest we write:
T=(1/0.06)*(((1800+6000)/6000)-1), the solution is then:
T=5; remember, because is an annual rate, T solution means 5 years.
Find the length of arc YXZ.
A. s=3
B. s= 60
C. s= 75
D. s= 236
Answer:
C. s= 75
Step-by-step explanation:
One radian is the angle subtended by an arc length equal to the radius of the circle.
∅=s/r where s is the arc length ∅ the angle and r the radius of the circle.
Thus s=∅×r
In the circle provided arc s subtends and angle of 5 radians.
s= 5 radians× 15
=75
Which equation shows the point slope form of the line that passes through (3, 2) and has a slope of
2
y + 2 =
(x + 3)
Oy-2=3(x-3)
y+3= }(x+2)
©y-3=2x-2)
Save and Exit
Markthandie
Answer:
y - 2 = 2(x - 3).
Step-by-step explanation:
The point -slope form of a line is:
y - y1 = m(x - x1) where m = the slope and (x1, y1) is a point on the line.
Here m = 2, x1 = 3 and y1 = 2. So we have the equation:
y - 2 = 2(x - 3).
Answer:
[tex]y=2x-4[/tex]
Step-by-step explanation:
Given: The line passes through (3, 2) and has a slope of 2.
To find: Point slope form of the equation.
Solution: We know that the point slope form of the line passing through [tex]\left ( x_{1},y_{1}\right )[/tex] and slope m is [tex]y-y_{1}=m\left ( x-x_{1} \right )[/tex]
Here, [tex]x_{1}=3,\ y_{1}=2, \text{and} \:\:m=2[/tex]
So we have,
[tex]y-2=2(x-3)[/tex]
[tex]y-2=2x-6[/tex]
[tex]y=2x-4[/tex]
Hence, the point slope form of the line is [tex]y=2x-4[/tex].
At the beginning of year 1, Josie invests $400 at an annual compound interest
rate of 5%. She makes no deposits to or withdrawals from the account.
Which explicit formula can be used to find the account's balance at the
beginning of year 3?
The balance in Josie's account at the beginning of year 3, with a $400 investment at 5% annual compound interest, can be calculated using the compound interest formula A = P(1 + r)^n, which results in $441.
Explanation:The explicit formula to find the account's balance at the beginning of year 3 for Josie's investment with an annual compound interest rate can be determined using the compound interest formula:
A = P(1 + r)^n
Where:
A is the amount of money accumulated after n years, including interest.P is the principal amount (the initial amount of money).r is the annual interest rate (decimal).n is the number of years the money is invested.In Josie's case, she invested $400 at a 5% annual interest rate for 2 years. The formula will look like this:
A = 400(1 + 0.05)^2
Now, calculate the amount:
A = 400(1 + 0.05)^2
A = 400(1.05)^2
A = 400(1.1025)
A = $441
Hence, the balance in Josie's account at the beginning of year 3 would be $441.
Use the given parent function f(x) = |x| to graph g(x) = |x| -4.
Use the ray tool and select two points to graph each ray.
Can somebody help me please I hate graphs
Answer:
Look to the attached graph
Step-by-step explanation:
* Lets explain the difference between the graphs of f(x) and g(x)
∵ f(x) = IxI
∵ g(x) = IxI - 4
- If we add are subtract f(x) by k, where k is a constant that means
we translate f(x) vertically
- If g(x) = f(x) + k
∴ f(x) translated vertically k units up
- If g(x) = f(x) - k
∴ f(x) translated vertically k units down
∵ g(x) = IxI - 4
∵ f(x) = IxI
∴ g(x) = f(x) - 4
∴ f(x) translated vertically 4 units down
∴ The graph of f(x) will translate down 4 units
∵ The origin point (0 , 0) lies on f(x)
∴ The origin point (0 , 0) will translate down by 4 units
∴ Its image will be point (0 , -4)
∴ Point (0 , -4) lies on the graph of g(x)
- So you can translate each point on the graph of f(x) 4 units down to
graph g(x)
# Two point on the left part
∵ Point (-2 , 2) lies on f(x)
∴ Its image after translation 4 units down will be (-2 , -2)
∴ Point (-2 , 2) lies on g(x)
∵ Point (-7 , 7) lies on f(x)
∴ Its image after translation 4 units down will be (-7 , 3)
∴ Point (-7 , 3) lies on g(x)
# Two point on the right part
∵ Point (3 , 3) lies on f(x)
∴ Its image after translation 4 units down will be (3 , -1)
∴ Point (3 , -1) lies on g(x)
∵ Point (8 , 8) lies on f(x)
∴ Its image after translation 4 units down will be (8 , 4)
∴ Point (8 , 4) lies on g(x)
* Now you can draw the graph with these 5 points
which point on the number line represent the product of (-4)(-2)(-1)
-4 times -2 equals 8.
8 times -1 equals -8.
Therefore, the point on your number line that is on -8 is your answer!
Generalize the pattern by finding the nth term.
6, 10, 14, 18, ....
Question 1 options:
2n + 4
4n + 2
4n + 6
Answer:
4n+2
Step-by-step explanation:
The common difference between the terms is 4 which means that the sequence is an arithmetic sequence.
The general formula for arithmetic sequence is:
[tex]a_{n}=a_{0}+(n-1)d[/tex]
where a_n is the nth term, a_0 is the first term and d is the common difference between them.
We know that
[tex]a_{0}=6\\d=4[/tex]
Putting the value in general formula:
[tex]a_{n}=6+4(n-1)\\a_{n}=6+4n-4\\a_{n}=4n+6-4\\a_{n}=4n+2\\[/tex]
So the generalized pattern is 4n+2 ..
Remove the largest possible common factor check your answer by multiplication
[tex]10x {}^{2} - 15x[/tex]
A.
[tex]10x {}^{2}(5x - 3)[/tex]
B.
[tex]5x(2x - 3)[/tex]
C.
[tex] - 5x(2x + 3)[/tex]
D.
[tex]5x(2x + 3)[/tex]
The greater common divisor between 10 and 15 is 5, so we can factor it out:
[tex]10x^2-15x = 5(2x^2-3x)[/tex]
The greater common exponent between 1 and 2 is 1, so we can factor x out:
[tex]10x^2-15x = 5x(2x-3)[/tex]
Which describes the scatter plot of a car’s value compared to the age of the car ?
So the x-axis represents the age of the car and the y represents the value of the car
As you can see as the x values increase the y value decreases
This means that the answer is C. As the age of the car increases the value of the car decreases
Hope this helped!
~Just a girl in love with Shawn Mendes
Answer:
3
Step-by-step explanation:
Please answer ASAP and if you do you will get Brainliest. Catherine buys a gallon of ice cream from the store. After taking it home, she eats a fifth of a gallon of ice cream. Her sister eats some of the ice cream as well. If two-thirds of the original amount of ice cream is left, then what fraction of a gallon of ice cream did her sister eat?
Answer:
Catherine's sister ate 2/15 gallons of the ice cream.
[tex]\displaystyle \frac{2}{15}[/tex].
Step-by-step explanation:
Let [tex]x[/tex] be the amount of ice cream that Catherine's sister ate, in gallons.
Original amount: 1 gallon.What Catherine ate: [tex]\displaystyle \frac{1}{5}[/tex] gallons.What Catherine's sister ate is assumed to be [tex]x[/tex] gallons.What's left: [tex]\displaystyle \frac{2}{3}[/tex] gallons.Consider the relationship:
[tex]\text{Original amount - What Catherine ate - What Catherine's Sister ate}\\ =\text{ What's left.}[/tex].
That is:
[tex]\displaystyle 1- \frac{1}{5} - x = \frac{2}{3}[/tex].
Add [tex]x[/tex] to both sides of this equation:
[tex]\displaystyle 1 - \frac{1}{5} = \frac{2}{3} +x[/tex]
Substract [tex]\displaystyle \frac{2}{3}[/tex] from both sides:
[tex]\displaystyle 1 - \frac{1}{5} - \frac{2}{3} = x[/tex].
Convert the denominator of all three numbers on the left-hand side to [tex]3 \times 5 = 15[/tex]
[tex]\displaystyle \frac{15}{15} - \frac{3}{15} - \frac{10}{15} = x[/tex].
[tex]\displaystyle x = \frac{2}{15}[/tex].
In other words, Catherine's sister ate [tex]\displaystyle \frac{2}{15}[/tex] gallons of the ice cream.
To solve this, we need to add the 1/5 of the ice cream to the 2/3 left of ice cream to find out how much her sister ate.
First, we need a common denominator. We can multiply 3 by 5 to get a common denominator easiest, since they are both multiples of it.
3*5=15
Now multiply the numerators by the amount the denominators were multiplied by.
1*3=3 so 3/15
2*5=10 so 10/15
Now, add them together.
10/15+3/15= 13/15.
Finally, subtract that amount from the original full amount of ice cream (15/15) to get the amount her sister ate, since that is the only unknown value left.
15/15-13/15=2/15.
Because 15 isn’t divisible by 2, we can’t simplify this fraction anymore.
Her sister ate 2/15 of a gallon of ice cream.
Hope this helps!
Given AABC - AXYZ, what is the value of cos(z)?
Answer:
C
Step-by-step explanation:
Given that the triangles are congruent then corresponding sides are congruent.
YZ = BC = 12 and XZ = AC = 13, thus
cosZ = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{YZ}{XZ}[/tex] = [tex]\frac{12}{13}[/tex]
The solution is, the value of cos(z) is C.) 12/13.
What are trigonometric relations?Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles
here, we have,
The six trigonometric functions are sin , cos , tan , cosec , sec and cot
Let the angle be θ , such that
sin θ = opposite / hypotenuse
cos θ = adjacent / hypotenuse
tan θ = opposite / adjacent
here, we have,
Given that the triangles are congruent then corresponding sides are congruent.
YZ = BC = 12
and XZ = AC = 13,
thus,
we get,
cosZ = base/hypotenuse
=YZ/XZ
= 12/13
Hence, The solution is, the value of cos(z) is C.) 12/13.
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Please help me I’m terrible at math I’ll brainliest as soon as possible and if answer is right
Answer:
1.25
Step-by-step explanation:
Calculate the scale factor as the ratio of the corresponding sides of the image to the original.
here the image is 6.25 and the original is 5
scale factor = [tex]\frac{6.25}{5}[/tex] = 1.25
This represents an enlargement
complete the synthetic division problem below x^3-2x^2-14x+3/x+3
The steps are shown below. From here, we can write:
[tex]\frac{x^3-2x^2-14x+3}{x+3}=x^2-5x+1+\frac{0}{x+3} \\ \\ \therefore \boxed{\frac{x^3-2x^2-14x+3}{x+3}=x^2-5x+1}[/tex]
Answer:
x^2-5x+1
Step-by-step explanation:
this is correct
Which is a true statement about the number 1
Your answer is the first option, "One is a factor of every whole number since every number is divisible by itself".
This is true because whenever you multiply 1 by anything you always get the thing you multiplied by, which makes it a factor of every number.
You can also find this by eliminating the other options, for example a prime number is any number whose factors are 1 and itself, 2 factors, so since 1 only has 1 factor it is not prime and option 3 is eliminated.
This also eliminates option 4 because 1 cannot be a composite number if it only has 1 factor.
I hope this helps!
The true statement among the given options is that one is a factor of every whole number since every number is divisible by itself.
What is a prime number?
A prime number is that number that is only fully divisible by 1 and that number itself.
Since we know that every number is divisible by 1. Thus 1 is also a factor of every number.
Thus one is a factor of every number.
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At a carnival, a toy boat race costs $4 to enter. Second place earns a prize worth $8, and third place earns a prize worth $5. If the probability of winning any of the prizes is [tex]\frac{1}{12}[/tex], what should the first place prize be worth for the game to be fair?
(a) $35
(b) $23
(c) $31
(d) $41
The requried, to make the game fair, the first place prize should be worth 4n - 13 dollars. None of the options are correct.
What is probability?Probability can be defined as the ratio of favorable outcomes to the total number of events.
Here,
The second place prize is worth $8 and the third place prize is worth $5, so the total value of these two prizes is $8 + $5 = $13.
If the game is fair, then the total amount of prize money awarded should be equal to the total amount of entry fees collected. If n players enter the game, then the total entry fees collected will be 4n.
Let x be the value of the first-place prize, which we want to find. The probability of winning any of the three prizes is 1/n, so the total amount of prize money awarded is,
1/n × x + 1/n × $8 + 1/n × $5 = ($4)n
x + 8 + 5 = 4n
x = 4n - 13
Therefore, to make the game fair, the first place prize should be worth 4n - 13 dollars.
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Yumi wants to make 12 cups of party mix using candies and nuts. Her budget requires the party mix to cost her $1.29 per cup. The candies are $2.49 per cup, and the nuts are $0.69 per cup. How many cups of candies and how many cups of nuts should she use?
Answer:
4 cups of candies and 8 cups of nuts
Step-by-step explanation:
Cost per cup = $1.29
Total number of cups = 12
Total cost of cups = 12 x $1.29
= $15.48
Cost of candies = $2.49 per cup
Total number of candies = x
Cost of nuts = $0.69 per cup
Total number of nuts = y
Equations :
x + y = 12 (because total cups of nuts and candies will be equal to 12)
2.49x + 0.69y = 15.48 (Total cost of the 12 cups should be 15.48)
Step 1 : Find x in terms of y
x = 12 - y
Step 2 : substitute x in terms of y from step 1 in the second equation
2.49x + 0.69y = 15.48
2.49 ( 12 - y) + 0.69y = 15.48
29.88 - 2.49y + 0.69y = 15.48
-1.8y = -14.4
y = 14.4/1.8
y = 8
Step 3 : Find x
x + y = 12
x = 12 - y
x = 12- 8
x = 4
Yumi should use 4 cups of candies and 8 cups of nuts.
!!
The number of cups of candies and nuts, Yumi should use is 4 and 8 cups respectively.
Let the candies be C.Let the nuts be N.Given the following data:
Cost of candies per cup = $2.49Cost of nuts per cup = $0.69Translating the word problem into an algebraic expression, we have;
For total number of cups:
[tex]C + N = 12[/tex] .....equation 1
For cost of candies and nuts:
[tex]2.49C + 0.69N = 1.29(12)\\\\2.49C + 0.69N = 15.48[/tex].....equation 2
From equation1:
[tex]C = 12 - N[/tex] ....equation 3
Substituting eqn 3 into eqn 1, we have:
[tex]2.49(12 - N) + 0.69N = 15.48\\\\29.88 - 2.49N + 0.69N = 15.48\\\\1.8N = 29.88 - 15.48\\\\1.8N = 14.4\\\\N = \frac{14.4}{1.8}[/tex]
Number of nuts, N = 8 cups
For candies:
[tex]C = 12 - N\\\\C = 12 - 8[/tex]
Number of candies, N = 4 cups
Find more information: https://brainly.com/question/596290
Write the equation in vertex form and then find the vertex, focus, and directrix of a parabola with equation x=y^2+18y-2
Answer:
Part 1) The vertex is the point (-83,-9)
Part 2) The focus is the point (-82.75,-9)
Part 3) The directrix is [tex]x=-83.25[/tex]
Step-by-step explanation:
step 1
Find the vertex
we know that
The equation of a horizontal parabola in the standard form is equal to
[tex](y - k)^{2}=4p(x - h)[/tex]
where
p≠ 0.
(h,k) is the vertex
(h + p, k) is the focus
x=h-p is the directrix
In this problem we have
[tex]x=y^{2} +18y-2[/tex]
Convert to standard form
[tex]x+2=y^{2} +18y[/tex]
[tex]x+2+81=y^{2} +18y+81[/tex]
[tex]x+83=(y+9)^{2}[/tex]
so
This is a horizontal parabola open to the right
(h,k) is the point (-83,-9)
so
The vertex is the point (-83,-9)
step 2
we have
[tex]x+83=(y+9)^{2}[/tex]
Find the value of p
[tex]4p=1[/tex]
[tex]p=1/4[/tex]
Find the focus
(h + p, k) is the focus
substitute
(-83+1/4,-9)
The focus is the point (-82.75,-9)
step 3
Find the directrix
The directrix of a horizontal parabola is
[tex]x=h-p[/tex]
substitute
[tex]x=-83-1/4[/tex]
[tex]x=-83.25[/tex]
Which module represents that equation?
Answer:
the one on the bottom left
Step-by-step explanation:
Note that the cube on the bottom left is composed of
4 × 4 × 4 = 64 ← unit cubes
Thus the volume of the cube = 64 units³
The volume of a cube = s³ ← where s is the side length
Thus s³ = 64
To find s given the volume take the cube root of both sides, that is
s = [tex]\sqrt[3]{64}[/tex] = 4