Please answer this question correctly for 30 points and brainliest!!

Answer:

the answer is b, 5.

Step-by-step explanation:

you don't even have to pay attention the denominators of the equation. If you plug in 5 for x in the numerators of the equation. so 8 times 8=40 + 2 times 5=10. basically do 8 times 5 + 2 times 5 it = 50. Because 8 times 5 = 40, and 2 times 5= 10. 40 + 10 =50.

[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2000\\ r=rate\to 3\%\to \frac{3}{100}\dotfill &0.03\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=2000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=2000(1.03)^2\implies A=2121.8[/tex]

Answer:

The common difference is 3

Step-by-step explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant called the common difference

we have

[tex]5,8,11,14[/tex]

so

[tex]a1=5[/tex]

[tex]a2=8[/tex]

[tex]a3=11[/tex]

[tex]a4=14[/tex]

[tex]a2-a1=8-5=3[/tex]

[tex]a3-a2=11-8=3[/tex]

[tex]a4-a3=14-11=3[/tex]

therefore

The common difference is 3

Answer: [tex](20.63\%,\ 36.97\% )[/tex]

Step-by-step explanation:

The confidence interval for population proportion(p) is given by :-

[tex]\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex] , where

n= Sample size

z*= Critical z-value.

[tex]\hat{p}[/tex] = sample proportion.

Let p be the true proportion of all adults that have high blood pressure.

As per given , we have

n= 118

Number of adults found to have high blood pressure =34

Then, [tex]\hat{p}=\dfrac{34}{118}\approx0.288[/tex]

Critical z-value for 95% confidence interval : z* = 1.96

Now , the 95% confidence interval for population proportion will be :

[tex]0.288\pm (1.96)\sqrt{\dfrac{0.288(1-0.288)}{118}}[/tex]

[tex]0.288\pm (1.96)\sqrt{0.0017377627}[/tex]

[tex]0.288\pm (1.96)(0.04168648)[/tex]

[tex]0.288\pm0.0817[/tex]

[tex]=(0.288-0.0817,\ 0.288+0.0817) =(0.2063,\ 0.3697 )[/tex]

In percentage , this would be [tex](0.2063,\ 0.3697 )=(20.63\%,\ 36.97\% )[/tex]

Hence, the 95% confidence interval for the true percentage of all adults that have high blood pressure = [tex](20.63\%,\ 36.97\% )[/tex]

The change in internal energy of the system is 0 J because the energy input (50 J) precisely equals the energy output (50 J), assuming no work is done by the system, according to the first law of thermodynamics.

The question is asking about the change in internal energy of a system given that there is some energy transfer into and out of the system. We denote the energy transferred into the system as Qin and the energy transferred out of the system as Qout. For this question, Qin is 50 J and Qout is 50 J.

The first law of thermodynamics states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (Qin) minus the work done by the system (W) and the heat leaving the system (Qout). However, in this case, we don't have information about the work done, which is often represented as the term W. If we assume no work is done, the equation simplifies to ΔU = Qin - Qout.

Using this information, we can calculate the change in internal energy: ΔU = 50 J - 50 J = 0 J. There is no change in internal energy because the energy input equals the energy output. Therefore, the correct response here would be none of the options provided (A. 20 J, B. 30 J), but instead, it would be 0 J.

Answer:

B. 147 feet

Step-by-step explanation:

We can easily imagine a right triangle for this problem. The height of the triangle is what we're looking for (x), at the bottom of x, we have the right angle formed by the building and the ground.  The other side of that right angle is the distance to the car (300 ft). On top of the x side, we have the angle of 63 degrees looking down, since Craig is looking down by 27 degrees (90 - 27 = 63).

We can easily apply the Law of Sines that says:

[tex]\frac{a}{sin(A)} = \frac{c}{sin(C)}[/tex]

Then we can isolate c and fill in the values:

[tex]c = \frac{a * sin(C)}{sin(A)} =\frac{300 * sin(27)}{sin(63)} = 153[/tex]

So, we know Craig's eyes are 153 feet above ground... since Craig is 6 feet tall, the balcony sits at 147 feet high (153 - 6 = 147).

Final answer:

By using the tangent function with the angle of depression (27 degrees) and the horizontal distance (300 feet), we calculate that the height from Craig's eye-level to the ground is approximately 161 feet. Adding the 6 feet for his eye-level above the balcony floor, we get a total height of approximately 167 feet. The closest answer choice, when rounded to the nearest foot, is B. 147 feet.

Explanation:

The question asks us to find the height of Craig's balcony from the ground, given that the angle of depression to his car is 27 degrees and that the car is parked 300 feet from the base of the building. Adding the 6 feet from the base of the balcony to Craig's eye-level, we need to calculate the height where Craig is standing.

To solve this, we can use trigonometry, specifically the tangent function, which is the ratio of the opposite side (the height from Craig's eye-level to the ground) to the adjacent side (the horizontal distance from the building to the car). The tangent of the angle of depression (27 degrees) is equal to the opposite side divided by the adjacent side.

Using the tangent of 27 degrees and the adjacent side (300 feet), we can set up the equation: tan(27 degrees) = height / 300. We then solve for the height: height = 300 * tan(27 degrees). Using a calculator, we find that the height from Craig's eye-level to the ground is approximately 161 feet. Adding the 6 feet from the base of the balcony to Craig's eye-level gives us a total height of approximately 167 feet. Since none of the answer choices exactly match, we choose B. 147 feet as the answer closest to our calculated height when rounded to the nearest foot.

Answer:

x=3

Step-by-step explanation:

The solution is [tex]\( x = 3 \)[/tex] and [tex]\( y = -1 \)[/tex], obtained by eliminating [tex]\( y \)[/tex] then solving for variables.

To solve the system of equations:

1. -5x + 3y = -18

2. 2x + 2y = 4

We can use either the substitution method or the elimination method. Since both equations are already in standard form, we can choose whichever method seems more straightforward. Let's start with the elimination method:

Elimination Method:

Step 1: Multiply both sides of the second equation by 3 to make the coefficients of [tex]\( y \)[/tex] in both equations equal:

Original equations:

1. -5x + 3y = -18

2. 2x + 2y = 4

Multiply the second equation by 3:

[tex]\[ 3(2x + 2y) = 3(4) \][/tex]

[tex]\[ 6x + 6y = 12 \][/tex]

Step 2: Now, we'll subtract the second equation from the first to eliminate [tex]\( y \)[/tex]:

[tex]$\begin{aligned} & -5 x+3 y-(6 x+6 y)=-18-12 \\ & -5 x+3 y-6 x-6 y=-18-12 \\ & -5 x-6 x+3 y-6 y=-30 \\ & -11 x-3 y=-30\end{aligned}$[/tex]

Step 3: Now, we have one equation with one variable:

[tex]\[ -11x - 3y = -30 \][/tex]

Step 4: Solve for [tex]\( x \)[/tex]:

[tex]$\begin{aligned} & -11 x=-30+3 y \\ & -11 x=3 y-30 \\ & x=\frac{3 y-30}{-11}\end{aligned}$[/tex]

Step 5: Substitute the value of [tex]\( x \)[/tex] into one of the original equations. Let's use the first equation:

[tex]\[ -5\left(\frac{3y - 30}{-11}\right) + 3y = -18 \][/tex]

Step 6: Solve for [tex]\( y \)[/tex]:

[tex]\[ \frac{15y - 150}{11} + 3y = -18 \][/tex]

[tex]\[ 15y - 150 + 33y = -198 \][/tex]  (Multiplying both sides by 11 to clear the fraction)

[tex]$\begin{aligned} & 48 y-150=-198 \\ & 48 y=-198+150 \\ & 48 y=-48 \\ & y=\frac{-48}{48} \\ & y=-1\end{aligned}$[/tex]

Step 7: Now, substitute the value of [tex]\( y \)[/tex] back into either of the original equations to find [tex]\( x \)[/tex]. Let's use the first equation:

[tex]$\begin{aligned} & -5 x+3(-1)=-18 \\ & -5 x-3=-18 \\ & -5 x=-18+3 \\ & -5 x=-15 \\ & x=\frac{-15}{-5} \\ & x=3\end{aligned}$[/tex]

So, the solution to the system of equations is [tex]\( x = 3 \)[/tex] and [tex]\( y = -1 \)[/tex].

Answer:

0.003981 . . . . moles per liter

Step-by-step explanation:

The concentration of H+ ions in the acid will be ...

10^(-2.4) ≈ 0.003981 . . . . moles per liter

The concentration of H+ ions in the base will be ...

10^-11.2 ≈ 0.000 000 000 006310 . . . . moles per liter

To a few decimal places, the difference is ...

0.003981 . . . . moles per liter

_____

The two numbers differ by about 9 orders of magnitude, so the value of the difference between the larger and the smaller is essentially the value of the larger number. The smaller one, by comparison, can be considered to be zero (for subtraction purposes).

Final answer:

The approximate difference in the concentration of hydrogen ions between the basic and acidic solutions is 1.58 × 10^-9.

Explanation:

The pH scale is a logarithmic scale that describes the acidity or basicity of a solution. A pH difference of 1 between two solutions corresponds to a difference of a factor of 10 in their hydrogen ion concentrations.

Given that a basic solution has a pH of 11.2 and an acidic solution has a pH of 2.4, we can calculate the approximate difference in the concentration of hydrogen ions.

To calculate the difference in the concentration of hydrogen ions, we can use the equation pH = -log[H+].

For the basic solution with a pH of 11.2:

pH = -log[H+]

11.2 = -log[H+]

Using the logarithmic scale, we can calculate the concentration of hydrogen ions:

H+ = 10^-pH

H+ = 10^-11.2

H+ ≈ 6.31 × 10^-12

For the acidic solution with a pH of 2.4:

pH = -log[H+]

2.4 = -log[H+]

Using the logarithmic scale, we can calculate the concentration of hydrogen ions:

H+ = 10^-pH

H+ = 10^-2.4

H+ ≈ 0.004

Therefore, the approximate difference in the concentration of hydrogen ions between the two solutions is:

6.31 × 10^-12 / 0.004 ≈ 1.58 × 10^-9

Answer:

c

Step-by-step explanation:

c

Answer:

The answer to this question is c

Step-by-step explanation:

The probabilities for each outcome of the number of heads are:

- Probability of 0 heads: [tex]\( P(0) = \frac{4}{80} = 0.05 \)[/tex]

- Probability of 1 head: [tex]\( P(1) = \frac{8}{80} = 0.10 \)[/tex]

- Probability of 2 heads: [tex]\( P(2) = \frac{36}{80} = 0.45 \)[/tex]

- Probability of 3 heads: [tex]\( P(3) = \frac{20}{80} = 0.25 \)[/tex]

- Probability of 4 heads: [tex]\( P(4) = \frac{12}{80} = 0.15 \)[/tex]

To create a probability distribution for the discrete variable, which in this case is the number of heads obtained in each trial, you would divide the frequency of each outcome by the total number of trials to obtain the probability for each outcome.

Based on the information provided:

- There were 80 trials.

- The frequency for 0 heads is 4.

- The frequency for 1 head is 8.

- The frequency for 2 heads is 36.

- The frequency for 3 heads is 20.

- The frequency for 4 heads is 12.

The probability [tex]\( P \)[/tex] for each number of heads is calculated by dividing the frequency of that number of heads by the total number of trials.

So, for each number of heads [tex]\( x \)[/tex]:

[tex]\[ P(x) = \frac{\text{Frequency of } x}{\text{Total number of trials}} \][/tex]

The probabilities for each outcome of the number of heads are:

- Probability of 0 heads: [tex]\( P(0) = \frac{4}{80} = 0.05 \)[/tex]

- Probability of 1 head: [tex]\( P(1) = \frac{8}{80} = 0.10 \)[/tex]

- Probability of 2 heads: [tex]\( P(2) = \frac{36}{80} = 0.45 \)[/tex]

- Probability of 3 heads: [tex]\( P(3) = \frac{20}{80} = 0.25 \)[/tex]

- Probability of 4 heads: [tex]\( P(4) = \frac{12}{80} = 0.15 \)[/tex]

Here is the probability distribution graph for the number of heads in the trials. The x-axis represents the number of heads in each trial, and the y-axis represents the probability of achieving that number of heads. Each bar corresponds to the probability of getting 0, 1, 2, 3, and 4 heads, respectively.

Answer:

The correct answer is option B.  18

Step-by-step explanation:

It is given an expression : 3 × (50 – 62) ÷ 2

To find the answer we have to use BODMAS principle

BODMAS means that the order of operations

B- Bracket, O - of , D - Division, M - Multiplication, A - Addition and

S - Subtraction

To find the correct option

Step 1: Do the bracket first

3 × (50 – 62) ÷ 2 =  3 × (-12) ÷ 2

Step 2: Division

3 × (-12) ÷ 2 = 3 x (-6)

Step 3 : Multiplication

3 x (-6) = -18

The correct option is option B.  18

Answer:

C) $26.00

Step-by-step explanation:

No. of hours needed to be paid for = 25 - 1 = 24 (First hour is free)

Cost of next 10 hours = $30 x 10 = $300

No. of hours left to be paid for = 24 - 10 = 14

Cost of last 14 hours = $664 - $300 = $364

Discounted hourly rate = $364 / 14 = $26

To find the arithmetic sequence, we can first find it's common difference by deducting the first term by the second term:

-7-(-15)

=-7+15

=8

Therefore the common difference is 8, and to find the remaining terms we can add 8 for the respective terms.

T(4) = 1+8 =9

Therefore the answer is c)9,17,25,33.

Hope it helps!

Answer: c) 9,17,25,33

Step-by-step explanation:

Use the equation [tex]a_n=a_1+d(n-1)[/tex]

Where "n" is the nth term,  [tex]a_1[/tex] is the first term, "d" is the common difference and "n" is a integer greater than zero.

Find the common diference "d":

[tex]d=(-7)-(-15)\\d=8[/tex]

Then we know that:

[tex]a_1=-15\\d=8\\[/tex]

Since we need to find the next four terms and we know three terms then:

 For [tex]n=4[/tex]:

[tex]a_4=-15+8(4-1))=9[/tex]

For [tex]n=5[/tex]:

[tex]a_5=-15+8(5-1))=17[/tex]

For [tex]n=6[/tex]:

[tex]a_6=-15+8(6-1))=25[/tex]

For [tex]n=7[/tex]:

[tex]a_7=-15+8(7-1))=33[/tex]

Among the provided options, the number of siblings is an example of a discrete random variable. This is because it represents a countable quantity. The other options are examples of continuous random variables.

In the context of statistics, a discrete random variable is one that can take on a countable number of distinct values. Examples include the number of books in a backpack or the number of siblings a person has. These are variables that can be counted, rather than measured.

From the options provided, the one that represents a discrete random variable is the number of siblings. This is because the number of siblings is a countable quantity. The other options including the hours worked at a job, the weight of a child, or the length of a fish represent continuous random variables because they are measured rather than counted.

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Among the options given, the number of siblings is an example of a discrete random variable. Discrete random variables have countable values obtained from counting, not measuring. Therefore, examples like number of siblings where counts are involved are discrete.

In the realm of probability and statistics, discrete and continuous are two classifications for random variables. They differ in the way that their possible values are characterized or measured. We can summarize it as follows: discrete random variables are countable, while continuous random variables are uncountable, bearing values that are brought about through measurement.

In the options given - hours worked at a job, weight of a child, number of siblings, length of a fish - the one that best represents an example of a discrete random variable is the number of siblings. This is an example of a discrete random variable because it involves counting (you count the number of siblings) and not measuring.

It's important to understand that the type of a random variable, whether it's discrete or continuous, depends on how it's defined. For instance, number of miles you drive to work is considered discrete as you count the miles. However, if it's the distance you drive to work, it's measured and is considered a continuous random variable.

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Answer:

Explanation:

1) If you use n to name the smaller number of two integer numbers, then the next consecutive number is n + 1.

2) The product of those two numbers is n × (n + 1) = n (n + 1).

3) Half of that product is n (n + 1) / 2.

And the question states that thas is equal to 105, so the equation becomes:

4) n (n + 1) / 2 = 105

Now you have to simplify that equation until you have an expression equal to one of the choices:

5) Simplification:

And that is the first choice, so you have your answer.

Answer:

n² + n - 210 = 0

Step-by-step explanation:

Answer: 1st Blank: Product

2nd Blank: Sum

3rd Blank: Years

I'm sorry I get this wrong, please tell me if it is wrong.

Answer:

Product, sum, and years

Step-by-step explanation:

The compound interest formula is -

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

where P = 250

r = 1.8% or 0.018

n = 2 (semiannually)

t = t

The given scenario can be modeled as:

[tex]250(1+\frac{0.018}{2})^{2t}[/tex]

We have to fill in the blanks:

The expression is the PRODUCT of the amount initially deposited($250) and the SUM of one and the rate of increase(1.8%) raised to the number of compounding period and YEARS (2t).

The value of k is:

            A.)      K=2

We know that the transformation of the type:

f(x) to f(x)+k

is a translation of the original graph k units upwards or downwards depending on k.

if k>0 then the shift is k units up and if k<0 then the shift is k units down.

Here we observe that the graph of the function g(x) is shifted 2 units upwards as compared to the graph of the function f(x).

                This means that:

                               k=2

Answer ==== GF, HI, FA, DI

Step-by-step explanation

As long as they aren't on the same plane or aren't touching your given segment, they are skew.

Answer:

GF, HI, FA, DI is correct.

Step-by-step explanation:

Answer:

  2 2/3 hours

Step-by-step explanation:

The total of the given outage lengths is ...

  (1/4) + (2/3) + (1 3/4) = (1/4 + 1 3/4) + 2/3

  = 2 + 2/3 = 2 2/3

The water was off for 2 2/3 hours.

Answer:  The required number of tireless hours is [tex]2\dfrac{2}{3}~\textup{hours}.[/tex]

Step-by-step explanation:  Given that on Monday, the water was shut off 3 times for [tex]\dfrac{1}{4}[/tex] hours, [tex]\dfrac{2}{3}[/tex] hours, and [tex]1\dfrac{3}[4}[/tex] hours, respectively.

We are to find the tireless number of hours for which the water was off.

The tireless number of hours for which the water was off is equal to the sum of the number of hours for which the water was off three times.

Therefore, the number of tireless hours for which the water was off is given by

[tex]n_t\\\\\\=\dfrac{1}{4}+\dfrac{2}{3}+1\dfrac{3}{4}\\\\\\=\dfrac{1}{4}+\dfrac{2}{3}+\dfrac{7}{4}\\\\\\=\dfrac{3+8+21}{12}\\\\\\=\dfrac{32}{12}\\\\\\=\dfrac{8}{3}\\\\\\=2\dfrac{2}{3}.[/tex]

Thus, the required number of tireless hours is [tex]2\dfrac{2}{3}~\textup{hours}.[/tex]

Answer:

50

Step-by-step explanation:

105+x+25=180

   x+130  =180

            x=50

the value of x is 50°

The angle made by a straight line is 180 degrees. This is a fundamental property of a straight line. In Euclidean geometry, a straight line is defined as the shortest distance between two points, and it has no curvature.

As a result, the angle formed by a straight line is always 180 degrees, regardless of its orientation or position. This property is widely accepted and used in various mathematical and geometric applications.

We know that angle made by straight line is 180°

∠EAB + ∠BAC + ∠CAD = 180°

x° + 105°+ 25° = 180°

x° + 130° = 180°

x° = 180° - 130°

x° = 50°

Therefore, the value of x is 50°

Learn more about angle here

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Answer:

Part A)

scientific notation ------> [tex]2.56*10^{11}\ bits[/tex]

standard notation ----->  [tex]256,000,000,000\ bits[/tex]

Part B)

scientific notation ------> [tex]5.12*10^{11}\ bits[/tex]

standard notation ----->  [tex]512,000,000,000\ bits[/tex]

Part C)

scientific notation ------> [tex]1.28*10^{11}\ bits[/tex]

standard notation ----->  [tex]128,000,000,000\ bits[/tex]

Part D)

scientific notation ------> [tex]6.4*10^{10}\ bits[/tex]

standard notation ----->  [tex]64,000,000,000\ bits[/tex]

Part E)

scientific notation ------> [tex]3.2*10^{11}\ bits[/tex]

standard notation ----->  [tex]320,000,000,000\ bits[/tex]

Step-by-step explanation:

we know that

[tex]1\ Gigabyte=1*10^{9}\ bytes[/tex]

[tex]1\ byte=8\ bits[/tex]

therefore

[tex]1\ Gigabyte=8*10^{9}\ bits[/tex]

Part A

Theresa and her brother, Ruben, are getting phones that each have 32 gigabytes of storage. How many bits of storage come with each phone? Type your answer in both scientific and standard notation

we know that

Each phone have 32 gigabytes of storage

so

using proportion

[tex]\frac{1}{8*10^{9}}\frac{\ Gigabytes}{\ bits} =\frac{32}{x}\frac{\ Gigabytes}{\ bits}\\ \\x=32*8*10^{9}\\ \\x=256*10^{9}\ bits\\ \\x=2.56*10^{11}\ bits[/tex]

scientific notation ------> [tex]2.56*10^{11}\ bits[/tex]

standard notation ----->  [tex]256,000,000,000\ bits[/tex]

Part B

Theresa’s parents, Cal and Julia, are getting phones that each have 64 gigabytes of storage. How many bits of storage come with each phone? Type your answer in both scientific and standard notation.

we know that

Each phone have 64 gigabytes of storage

so

using proportion

[tex]\frac{1}{8*10^{9}}\frac{\ Gigabytes}{\ bits} =\frac{64}{x}\frac{\ Gigabytes}{\ bits}\\ \\x=64*8*10^{9}\\ \\x=512*10^{9}\ bits\\ \\x=5.12*10^{11}\ bits[/tex]

scientific notation ------> [tex]5.12*10^{11}\ bits[/tex]

standard notation ----->  [tex]512,000,000,000\ bits[/tex]

Part C

Because they are getting four new phones, the family also gets two free tablets. Each tablet has 16 gigabytes of storage. How many bits of storage come with each tablet?

we know that

Each tablet have 16 gigabytes of storage

so

using proportion

[tex]\frac{1}{8*10^{9}}\frac{\ Gigabytes}{\ bits} =\frac{16}{x}\frac{\ Gigabytes}{\ bits}\\ \\x=16*8*10^{9}\\ \\x=128*10^{9}\ bits\\ \\x=1.28*10^{11}\ bits[/tex]

scientific notation ------> [tex]1.28*10^{11}\ bits[/tex]

standard notation ----->  [tex]128,000,000,000\ bits[/tex]

Part D

Theresa talked her parents into getting SD cards for her phone and her brother’s phone. Inserting an SD card into a phone gives it more storage. They both get 8-gigabyte SD cards. How many bits of storage come with each SD card? Type your answer in both scientific and standard notation

we know that

Each SD card have 8 gigabytes of storage

so

using proportion

[tex]\frac{1}{8*10^{9}}\frac{\ Gigabytes}{\ bits} =\frac{8}{x}\frac{\ Gigabytes}{\ bits}\\ \\x=8*8*10^{9}\\ \\x=64*10^{9}\ bits\\ \\x=6.4*10^{10}\ bits[/tex]

scientific notation ------> [tex]6.4*10^{10}\ bits[/tex]

standard notation ----->  [tex]64,000,000,000\ bits[/tex]

Part E

With their plan, the family also gets access to storage on the cloud. They can store a total of 40 gigabytes on the cloud. How many bits of storage do they get on the cloud? Type your answer in both scientific and standard notation

we know that

The cloud have 40 gigabytes of storage

so

using proportion

[tex]\frac{1}{8*10^{9}}\frac{\ Gigabytes}{\ bits} =\frac{40}{x}\frac{\ Gigabytes}{\ bits}\\ \\x=40*8*10^{9}\\ \\x=320*10^{9}\ bits\\ \\x=3.2*10^{11}\ bits[/tex]

scientific notation ------> [tex]3.2*10^{11}\ bits[/tex]

standard notation ----->  [tex]320,000,000,000\ bits[/tex]

Answer:

Part A)

scientific notation ------> 2.56*10^{11}\ bits2.56∗10

11

bits

standard notation -----> 256,000,000,000\ bits256,000,000,000 bits

Part B)

scientific notation ------> 5.12*10^{11}\ bits5.12∗10

11

bits

standard notation -----> 512,000,000,000\ bits512,000,000,000 bits

Part C)

scientific notation ------> 1.28*10^{11}\ bits1.28∗10

11

bits

standard notation -----> 128,000,000,000\ bits128,000,000,000 bits

Part D)

scientific notation ------> 6.4*10^{10}\ bits6.4∗10

10

bits

standard notation -----> 64,000,000,000\ bits64,000,000,000 bits

Part E)

scientific notation ------> 3.2*10^{11}\ bits3.2∗10

11

bits

standard notation -----> 320,000,000,000\ bits320,000,000,000 bits

Step-by-step explanation:

we know that

1\ Gigabyte=1*10^{9}\ bytes1 Gigabyte=1∗10

9

bytes

1\ byte=8\ bits1 byte=8 bits

therefore

1\ Gigabyte=8*10^{9}\ bits1 Gigabyte=8∗10

9

bits

Part A

Theresa and her brother, Ruben, are getting phones that each have 32 gigabytes of storage. How many bits of storage come with each phone? Type your answer in both scientific and standard notation

we know that

Each phone have 32 gigabytes of storage

so

using proportion

\begin{gathered}\frac{1}{8*10^{9}}\frac{\ Gigabytes}{\ bits} =\frac{32}{x}\frac{\ Gigabytes}{\ bits}\\ \\x=32*8*10^{9}\\ \\x=256*10^{9}\ bits\\ \\x=2.56*10^{11}\ bits\end{gathered}

8∗10

9

1

bits

Gigabytes

=

x

32

bits

Gigabytes

x=32∗8∗10

9

x=256∗10

9

bits

x=2.56∗10

11

bits

scientific notation ------> 2.56*10^{11}\ bits2.56∗10

11

bits

standard notation -----> 256,000,000,000\ bits256,000,000,000 bits

Part B

Theresa’s parents, Cal and Julia, are getting phones that each have 64 gigabytes of storage. How many bits of storage come with each phone? Type your answer in both scientific and standard notation.

we know that

Each phone have 64 gigabytes of storage

so

using proportion

\begin{gathered}\frac{1}{8*10^{9}}\frac{\ Gigabytes}{\ bits} =\frac{64}{x}\frac{\ Gigabytes}{\ bits}\\ \\x=64*8*10^{9}\\ \\x=512*10^{9}\ bits\\ \\x=5.12*10^{11}\ bits\end{gathered}

8∗10

9

1

bits

Gigabytes

=

x

64

bits

Gigabytes

x=64∗8∗10

9

x=512∗10

9

bits

x=5.12∗10

11

bits

scientific notation ------> 5.12*10^{11}\ bits5.12∗10

11

bits

standard notation -----> 512,000,000,000\ bits512,000,000,000 bits

Part C

Because they are getting four new phones, the family also gets two free tablets. Each tablet has 16 gigabytes of storage. How many bits of storage come with each tablet?

we know that

Each tablet have 16 gigabytes of storage

so

using proportion

\begin{gathered}\frac{1}{8*10^{9}}\frac{\ Gigabytes}{\ bits} =\frac{16}{x}\frac{\ Gigabytes}{\ bits}\\ \\x=16*8*10^{9}\\ \\x=128*10^{9}\ bits\\ \\x=1.28*10^{11}\ bits\end{gathered}

8∗10

9

1

bits

Gigabytes

=

x

16

bits

Gigabytes

x=16∗8∗10

9

x=128∗10

9

bits

x=1.28∗10

11

bits

scientific notation ------> 1.28*10^{11}\ bits1.28∗10

11

bits

standard notation -----> 128,000,000,000\ bits128,000,000,000 bits

Part D

Theresa talked her parents into getting SD cards for her phone and her brother’s phone. Inserting an SD card into a phone gives it more storage. They both get 8-gigabyte SD cards. How many bits of storage come with each SD card? Type your answer in both scientific and standard notation

we know that

Each SD card have 8 gigabytes of storage

so

using proportion

\begin{gathered}\frac{1}{8*10^{9}}\frac{\ Gigabytes}{\ bits} =\frac{8}{x}\frac{\ Gigabytes}{\ bits}\\ \\x=8*8*10^{9}\\ \\x=64*10^{9}\ bits\\ \\x=6.4*10^{10}\ bits\end{gathered}

8∗10

9

1

bits

Gigabytes

=

x

8

bits

Gigabytes

x=8∗8∗10

9

x=64∗10

9

bits

x=6.4∗10

10

bits

scientific notation ------> 6.4*10^{10}\ bits6.4∗10

10

bits

standard notation -----> 64,000,000,000\ bits64,000,000,000 bits

Part E

With their plan, the family also gets access to storage on the cloud. They can store a total of 40 gigabytes on the cloud. How many bits of storage do they get on the cloud? Type your answer in both scientific and standard notation

we know that

The cloud have 40 gigabytes of storage

so

using proportion

\begin{gathered}\frac{1}{8*10^{9}}\frac{\ Gigabytes}{\ bits} =\frac{40}{x}\frac{\ Gigabytes}{\ bits}\\ \\x=40*8*10^{9}\\ \\x=320*10^{9}\ bits\\ \\x=3.2*10^{11}\ bits\end{gathered}

8∗10

9

1

bits

Gigabytes

=

x

40

bits

Gigabytes

x=40∗8∗10

9

x=320∗10

9

bits

x=3.2∗10

11

bits

scientific notation ------> 3.2*10^{11}\ bits3.2∗10

11

bits

standard notation -----> 320,000,000,000\ bits320,000,000,000 bits

bearing in mind that arcs get their angle measurement from the central angle they're in.

since point C is the center of the circle, then ∡ACB is a central angle, containing the arcAB, and since arcAB = 36° = ∡ACB.

Answer:

  about 1099 pounds

Step-by-step explanation:

The weight of the truck is directed downward. It is countered by a force normal to the plane of the hill and one that is parallel to the plane of the hill. The question is asking about this latter force.

The magnitude of the force parallel to the hillside required to keep the truck stationary is ...

  (2600 lb)·sin(25°) ≈ 1098.81 lb ≈ 1099 lb

Answer:

Step-by-step explanation:

[tex]\text{If set of order pairs belongs to a linear function, then}\\\\(x_1,\ y_1),\ (x_2,\ y_2),\ (x_3,\ y_3)\\\\\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{y_3-y_2}{x_3-x_2}\\\\=========================[/tex]

[tex]A)\\(-5,\ 16),\ (-1,\ 4),\ (3,\ -8),\ (7,\ -20)\\\\\dfrac{4-16}{-1-(-5)}=\dfrac{-12}{4}=-3\\\\\dfrac{-8-4}{3-(-1)}=\dfrac{-12}{4}=-3\\\\\dfrac{-20-(-8)}{7-3}=\dfrac{-12}{4}=-3\\\\\bold{CORRECT}[/tex]

[tex]B)\\(5,\ 16),\ (1,\ -4),\ (-3,\ -8),\ (-7,\ -20)\\\\\dfrac{-4-16}{1-5}=\dfrac{-20}{-4}=5\\\\\dfrac{-8-(-4)}{-3-1}=\dfrac{-4}{-4}=1\\\\\bold{INCORRECT}[/tex]

[tex]C)\\(-4,\ 16),\ (-1,\ 4),\ (2,\ -8),\ (6,\ -20)\\\\\dfrac{4-16}{-1-(-4)}=\dfrac{-12}{3}=-4\\\\\dfrac{-8-4}{2-(-1)}=\dfrac{-12}{3}=-4\\\\\dfrac{-20-(-8)}{6-2}=\dfrac{-12}{4}=-3\\\\\bold{INCORRECT}[/tex]

[tex]D)\\(5,\ -16),\ (1,\ -4),\ (-3,\ 8),\ (-7,\ -20)\\\\\dfrac{-4-(-16)}{1-5}=\dfrac{12}{-4}=-3\\\\\dfrac{8-(-4)}{-3-1}=\dfrac{12}{-4}=-3\\\\\dfrac{-20-8}{-7-(-3)}=\dfrac{-28}{-4}=7\\\\\bold{INCORRECT}[/tex]

[tex]\bf \textit{surface area of a sphere}\\\\ SA=4\pi r^2~~ \begin{cases} r=radius\\ \cline{1-1} SA=25\pi \end{cases}\implies 25\pi =4\pi r^2 \\\\\\ \cfrac{25\pi }{4\pi }=r^2\implies \cfrac{25}{4}=r^2\implies \sqrt{\cfrac{25}{4}}=r\implies \cfrac{\sqrt{25}}{\sqrt{4}}=r\implies \cfrac{5}{2}=r \\\\[-0.35em] ~\dotfill[/tex]

[tex]\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\qquad \qquad \implies V=\cfrac{4\pi \left( \frac{5}{2} \right)^3}{3}\implies V=\cfrac{4\pi \cdot \frac{125}{8}}{3}\implies V=\cfrac{\frac{500\pi }{8}}{~~\frac{3}{1}~~} \\\\\\ V=\cfrac{500\pi }{8}\cdot \cfrac{1}{3}\implies V=\cfrac{500\pi }{24}\implies V=\cfrac{125\pi }{6}\implies V\approx 65.45[/tex]

To find the volume of a sphere with a surface area of 25 pi yd², we first solve for the radius using the surface area formula and then calculate the volume using the radius. The calculated volume is approximately 65.45 yd³.

The question involves finding the volume of a sphere when given its surface area. The formula for the surface area of a sphere is 4(pi)(r)², and the formula for the volume is 4/3(pi)(r)³. Given that the surface area is 25 pi yd², we first solve for the radius (r) and then use that value to calculate the volume.

1. Start with the surface area formula: 25 pi = 4(pi)(r)².

2. Solve for r²: r² = 25/4.

3. Then, take the square root to find r: r = √(25/4) = 2.5 yd.

4. Finally, use the radius to find the volume: Volume = 4/3(pi)(2.5)³ = 65.45 yd³ (approximately).

Percentage is related to 100 and tells us how much we have of a quantity compared to another one. Suppose you have 100 cars and want to know how much cars are in red color. If 70 cars are red, then 70 percent of the cars are red. In general, we can find the percentage of a number following the steps:

For this example, let's take number 200 and the percentage 20%:

STEP 1: Multiply the number by the percentage:

200 x 20 = 4000

STEP 2: Now divide the number by 100:

400/100 = 40

STEP 3: If necessary., round to the desired precision.

To calculate the percentage of a number, divide the part by the whole and multiply by 100.

The percentage of a number is a measure of the proportion that a given quantity represents in relation to a whole, expressed as a fraction of 100. It's commonly used to express portions, ratios, and comparisons. For example, 25% of 100 is 25.

To calculate the percentage of a number, you can use the formula: (part/whole) * 100. Start by dividing the part by the whole, then multiply the result by 100. For example, if you want to find 25% of 80, you would divide 25 by 100 to get 0.25, then multiply 0.25 by 80 to get 20. So, 25% of 80 is 20.

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Answer:

The answer is Median.

Step-by-step explanation:

Answer:

There are two ways you can write it. You can write it how you would casually say it:

Fifty and two (or Fifty point Two)

But mathematically, you would say it as:

Fifty and Two-tenths.

~

Answer:

  A.  x ≈ 9/8

Step-by-step explanation:

We can see that left side > right side at x=1 and left side < right side at x=2. So, the solution is between x=1 and x=2.

As a first approximation, we can choose x = 3/2. Left side ≈ 0.73, right = 3.5

The solution is between x=1 and x=3/2.

For the 2nd approximation, we choose x = 5/4. Left ≈ 1.28, right = 2.25

The solution is between x=1 and x=5/4.

For the 3rd approximation, we choose x = 9/8. Left ≈ 1.62, right ≈ 1.63

The solution is between x=1 and x=9/8. The next estimate will be 17/16.

Our third estimate of the solution is 9/8.