TRUE its glucose if they have sunlight
Hi There,
The answer is:
True
Hope this helps have a great day :)
The term “ average atomic mass “ is a ______average so is calculator different Lee from a normal average
Average atomic mass of an element is a sum of the product of the isotope mass and its relative abundance.
For example: Chlorine has 2 isotopes with the following abundances
Cl(35): Atomic mass = 34.9688 amu; Abundance = 75.78%
Cl(37): Atomic mass = 36.9659 amu; Abundance = 24.22 %
Average atomic mass of Cl = 34.9688(0.7578) + 36.9659(0.2422) =
= 26.4993 + 8.9531 = 35.4524 amu
Thus, the term “ average atomic mass “ is a weighted average so it is calculated differently from a normal average
They lymphatic system’s function is to --------.
A) Transport fluid
B) Breathe
C) Digest food
D) Remove waste.
The correct answer is option A, that is, transport fluid.
The lymphatic system refers to a network of organs and tissues, which helps in getting rid of the body wastes, toxins, and other undesired elements. However, the main activity of the lymphatic system is to transport lymph, that is, a fluid comprising infection-fighting white blood cells, all through the body.
The lymphatic system mainly comprises of lymphatic vessels that are identical to the circulatory system's capillaries and veins. The vessels are associated with lymph nodes, where the filtration of lymph is done. The adenoids, tonsils, thymus, and spleen are all the components of the lymphatic system.
an air sample consists of 99.6% of nitrogen-14 and 0.4% of nitrogen-15. what is the average mass of nitrogen in this sample?
The average mass of nitrogen is 14
calculation
step 1 : multiply each percentage by mass number
14 x 99.6 =1394
15 x 0.4 = 6
Step 2: add them up
1394 + 6 = 1400
step 3: Then divide by 100
= 1400/100 = 14
Answer:The average atomic mass of nitrogen is 14.004
Explanation:
Abundance of nitrogen-14 = 99.6 %
Fractional abundance[tex]=\frac{99.6}{100}=0.996[/tex]
Abundance of nitrogen-15 = 0.4 %
Fractional abundance[tex]=\frac{0.4}{100}=0.004[/tex]
Average atomic mass of an element =
[tex]\sum(\text{atomic mass of an isotopes}\times (\text{fractional abundance}))[/tex]
Average atomic mass of nitrogen =
[tex]14\times 0.996+15\times 0.004amu=14.004[/tex]
The approximate atomic mass of nitrogen is 14.004
The electronic configuration of an element is given below.
1s22s22p63s1
Which statement about the reactivity of the element is true?
A. It is reactive because it has a full outermost energy level.
B. It is unreactive because it has a full outermost energy level.
C. It is reactive because it has to lose one electron to have a full outermost energy level.
D. It is unreactive because it has to gain one electron to have a full outermost energy level.
The statement which is true about the reactivity of element with 1S²2S²2P⁶3S¹ is
it is reactive because it has to lose one electron to have a full outermost energy level.
Explanation
Element with 1S²2S²2P⁶3S¹ electron configuration is a sodium metal. sodium has one electron in the outermost energy level. for sodium to have a full outermost energy level ( 8 electrons) it loses the 1 electron in 3S¹ to form a positively charged ion. (Na⁺)Answer:
C. It is reactive because it has to lose one electron to have a full outermost energy level.
How many milliliters of C5H8 can be made from 366 mL C5H12 ?
density of C5H12 = 0.620 g/mL
density of C5H8 = 0.681 g/mL
density of H2= 0.0899g/L
Please explain
The number of Ml of C₅H₈ that can be made from 366 ml C₅H₁₂ is 314.7 ml of C₅H₈
calculation
step 1: write the equation for formation of C₅H₈
C₅H₁₂ → C₅H₈ + 2 H₂
Step 2: find the mass of C₅H₁₂
mass = density × volume
= 0.620 g/ml × 366 ml =226.92 g
Step 3: find moles Of C₅H₁₂
moles = mass÷ molar mass
from periodic table the molar mass of C₅H₁₂ = (12 x5) +( 1 x12) = 72 g/mol
moles = 226.92 g÷ 72 g/mol =3.152 moles
Step 4: use the mole ratio to determine the moles of C₅H₈
C₅H₁₂:C₅H₈ is 1:1 from equation above
Therefore the moles of C₅H₈ is also = 3.152 moles
Step 5: find the mass of C₅H₈
mass = moles x molar mass
from periodic table the molar mass of C₅H₈ = (12 x5) +( 1 x8) = 68 g/mol
= 3.152 moles x 68 g/mol = 214.34 g
Step 6: find Ml of C₅H₈
=mass / density
= 214.34 g/0.681 g/ml = 314.7 ml
You can produce approximately 2.144 mL of C₅H₈ from 366 mL of C₅H₁₂.
This is calculated through conversion of mass using densities of the two substances.
The assumption is a 1:1 molar conversion for simplicity.To find out how many milliliters of C₅H₈ can be made from 366 mL of C₅H₁₂, you need to follow these steps:
First, determine the mass of C₅H₁₂ using its volume and density. Mass (C₅H₁₂) = Volume × Density Mass = 366 mL × 0.620 g/mL = 226.92 gAssume a 1:1 molar conversion between C₅H₁₂ and C₅H₈, given that they have similar formulas, C₅H₁₂ → C₅H₈ + H₂ The density of C₅H₈ is given, so you use it to convert the mass back to volume. Volume (C₅H₈) = [tex]\frac{mass}{density}[/tex]Volume = [tex]\frac{226.92 g}{0.681 ml}[/tex] = 2.144 mLTherefore, you can produce approximately 2.144 mL of C₅H₈ from 366 mL of C₅H₁₂.
Correct question is: How many milliliters of C₅H₈ can be made from 366 mL C₅H₁₂ ?
density of C₅H₁₂ = 0.620 g/mL
density of C₅H₈ = 0.681 g/mL
density of H₂ = 0.0899g/L
Early models of our solar system were usually based on experimentation
the best science of the time
the discoveries
of the best scientists
philosophy and religion
Based on the question and the given data, philosophy and religion.
What is the Lewis structure for H2Se
The requirements of atoms to be able to participate in hydrogen bonding with a hydrogen atom include all of the following except A. atoms must not be able to closely approach the hydrogen. B. atoms must be electronegative. C. atoms must have one lone pair of electrons. D. atoms must be small.
B. atoms must be electro negative.
Answer:
The answer is A.
Explanation:
This is a specific type of polar interaction that is established between two atoms with high electronegativity, usually between O or N, and an atom of H. In the case of oxygen, with a total of 8 electrons, two pairs of solitary electrons are presented and can act as acceptors of two hydrogen bridges. Nitrogen has one less electron and therefore has only one pair of solitary electrons to form a hydrogen bridge. These orbitals have a high negative charge density, and can, therefore, bind to the positive charge of hydrogen.
The interatomic distance between the hydrogen and the acceptor is less than the sum of its Van der Waals radius. The atomic radius of N and O are relatively small.
Have a nice day!
Give the electron configuration for the chloride ion. (please show the process!) =)
Answer:- [tex]1s^22s^22p^63s^23p^6[/tex]
Explanations:- Atomic number of chlrone(Cl) is 17 it means it has 17 electrons. It's electron configuration is: [tex]1s^22s^22p^63s^23p^5[/tex] .
Chloride ion is formed when Cl accepts one electron:
[tex]Cl+e^-\rightarrow Cl^-[/tex]
So, electrons for the chloride ion = 17+1 = 18
If we look at the electron configuration of Cl then 3p is still vacant as there are 5 electrons in it and it could have maximum 6 electrons. So, this 18th electron goes to 3p and the electron configuration of chloride ion becomes:
[tex]1s^22s^22p^63s^23p^6[/tex] .
which of the following elements has the highest first ionization energy? strontium calcium magnesium or beryllium
Beryllium.
ExplanationAll four elements are found in the second column to the left of a periodic table. They are group 2 elements.
The 1st ionization energy generally decrease down each group.
Elements in each group have the same number of electrons in the outermost occupied electron shell. Electrons in the inner shell shield those in the outer shell from attractions from the nucleus, known as the shielding effect. The number of protons in each atom increase by more than 8 in each period. However, due to this effect, electrons in the outermost shell experience a far weaker force pulling them towards the center of the atom. For atoms of the four group 2 elements, electrons in the outermost layer would behave as if there's only two protons inside their nucleus. As a result, their end up with rather similar ionization energies.
Despite the same effective charge on each electron, the mean radius of the electrons increase down the group. Beryllium is in the second period; its electrons occupy only two electron shells in the ground state. On the contrary, strontium is in the fifth period; its electrons occupy up to five electrons shells in its ground state. The strength of electrostatic attraction decreases as the two charges move apart. As a result, outermost electrons in beryllium are way more attached to the nucleus than those in strontium.
FYI, the 1st ionization energy of the four elements are shown below:
Be: 899.50 kJ/molMg: 737.750 kJ/molCa: 589.830 kJ/molSr: 549.470 kJ/molThe element with the highest first ionization energy among the choices is; Beryllium, Be
The ionization energy of an element is the energy required to remove one of the electrons in its outermost shell.
The first ionization energy of elements is inversely proportional to the atomic radii of elements.
This is so because a lesser atomic radius corresponds to greater electrostatic attraction between the electron and the nucleus of the atom.
We must also state that the atomic radius of elements in the periodic table increases down a group and decreases across a period.
In essence, the smaller the atom of an element, the larger is its first ionization energy.
Strontium --Period 6, group 1Calcium --Period 4, group 2Magnesium --Period 3, group 2Beryllium -- period 2, group 2The element with the highest first ionization energy is the smallest element and is therefore Beryllium, Be.
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how would you measure density of a rock
Use the D = M/V equation, in which Density can be found by dividing Mass/Volume.
To solve, first find a rectangular prism tub that is filled to a certain level. Next, place the rock inside to find the amount of displacement (or how high the water level goes up.) In this way, you can find the volume of the rock.
Next, solve for the Mass. This can be found by dividing the total weight from the gravitational pull. This would give you the mass.
Finally, to find Density, divide the Mass found with the Volume. This would give you your final answer
~
HURRY 10 POINTS!!!
Earth’s magnetic field is formed mostly by:
A. Molten iron alloy
B. solar wind
C. solar plasma
Iron(III) oxide is formed when iron combines with oxygen in the air. How many grams of Fe2O3 are formed when 33.4 g of Fe reacts completely with oxygen?
Molar Mass information: Iron = 55.8 g/mol, Oxygen= 15.9 g/mol
The grams of Fe₂O₃ that are formed is 47.68 g
calculation
Step 1: write the equation for reaction
4 Fe +3O₂ → 2 Fe₂O₃
Step 2: find the moles of Fe
moles = mass÷ molar mass
= 33.4 g÷55.8 g/mol =0.5986 moles
Step 3 : use the mole ratio to determine the moles of Fe₂O₃
That is from equation above Fe:Fe₂O₃ is 4:2 therefore the moles of Fe₂O₃ is = 0.5986 moles x 2/4 =0.2993 moles
Step 4 : find the mass of Fe₂O₃
mass = mass x molar mass
The molar mass of Fe₂O₃ = (55.8 x 2 +(15.9 x3) = 159.3 g/mol
mass is therefore = 0.2993 moles x 159.3 g/mol =47.68 g
Answer:
47.8 g
Explanation:
in the process of electricity, what flows through the wires?A) protons B)neutronsC)electronsD)positrons
Electrons is your answer
Answer: C.
electrons
Explanation: edmentum
How many molecules of isopently acetate C7H1402 are released (1x10^ -6g) in a typical bee sting
The number of molecules of isopently acetate is 4.63 x 10¹⁵ molecules
calculation
Step 1: find the moles of isopently acetate( C₇H₁₄O₂)
moles = mass÷ molar mass
From periodic table the molar mass of C₇H₁₄O₂
= (12 x7 ) + (1 x14) +(16 x2) =130 g/mol
moles = 1 x10⁻⁶ g÷ 130 g/mol = 7 x 10⁻⁹ moles
step 2 ; use the Avogadro's law constant to calculate the number of molecules
That is according to Avogadro's law 1 mole = 6.02 x 10²³ molecules
7 x 10⁻⁹ moles = ? molecules
by cross multiplication
= { (7 x 10⁻⁹ moles x 6.02 x10²³ molecules) / 1 mole} = 4.63 x 10¹⁵ molecules
To determine the number of molecules of isoamyl acetate in a 1x10⁻⁶g bee sting, calculate the molar mass, convert mass to moles, and multiply by Avogadro's number to find approximately 4.625x10¹⁵ molecules.
To determine how many molecules of isoamyl acetate (isopentyl acetate) C₇H₁₄O₂ are released in 1x10⁻⁶g during a typical bee sting, we first need to calculate the molar mass of C₇H₁₄O₂. The molar mass is given by the sum of the atomic masses of all the atoms in one molecule of the substance. This is calculated as:
7 carbons (C) times 12.01 g/mol = 84.07 g/mol
14 hydrogens (H) times 1.008 g/mol = 14.112 g/mol
2 oxygens (O) times 16.00 g/mol = 32.00 g/mol
Adding these together gives a molar mass of 130.182 g/mol for isoamyl acetate.
Next, we use the following formula to convert the mass of the substance to moles:
moles = mass (g) / molar mass (g/mol)
= 1x10⁻⁶g / 130.182 g/mol
moles = 7.68x10⁻⁹ moles of C₇H₁₄O₂.
Finally, to find the number of molecules, we multiply the moles of the substance by Avogadro's number (6.022x10²³ molecules/mol):
number of molecules = 7.68x10⁻⁹ moles x 6.022x10²³ molecules/mol
number of molecules = 4.625x10¹⁵ molecules of C₇H₁₄O₂.
The number of molecules of isoamyl acetate released in 1x10⁻⁶g during a typical bee sting is approximately 4.625x10¹⁵.
A _____ is a mountain created from eruptions of lava, ash, rocks, and hot gases.
Valcano i your answer i believe
Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)
1. How many milliliters of a 0.255 MAgNO3 solution are required to react with 31.1 mL of 0.135 MNa3PO4 solution?
2. How many grams of silver phosphate are produced from the reaction of 23.0 mL of a 0.195 MAgNO3 solution and excess Na3PO4?
Answer:1) Volume of [tex]AgNO_3[/tex] required is 55.98 mL.
2) 0.62577 grams of [tex]Ag_3PO_4[/tex] is produced.
Explanation:
[tex]3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)[/tex]
1) Molarity of [tex]AgNO_3,M_1=0.225 M[/tex]
Volume of [tex]AgNO_3.V_1=?[/tex]
Molarity of [tex]Na_3PO_4,M_2=0.135 M[/tex]
Volume of [tex]Na_3PO_4,V_2=31.1 mL=0.0311 L[/tex]
[tex]Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}[/tex]
[tex]\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles[/tex]
According to reaction, 1 mole of [tex]Na_3PO_4[/tex] reacts with 3 mole of [tex]AgNO_3[/tex], then, 0.0041985 moles of [tex]Na_3PO_4[/tex] will react with:
[tex]\frac{3}{1}\times 0.0041985[/tex] moles of [tex]AgNO_3[/tex] that is 0.0125955 moles.
[tex]M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}[/tex]
[tex]V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL[/tex]
Volume of [tex]AgNO_3[/tex] required is 55.98 mL.
2)
[tex]Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}[/tex]
Number of moles of [tex]AgNO_3=0.195\times 0.023 L=0.004485 moles[/tex]
According to reaction, 3 moles of [tex]AgNO_3[/tex] gives 1 mole of [tex]Ag_3PO_4[/tex], then 0.004485 moles of [tex]AgNO_3[/tex] will give:[tex]\frac{1}{3}\times 0.004485[/tex] moles of [tex]Ag_3PO_4[/tex] that is 0.001495 moles.
Mass of [tex]Ag_3PO_4[/tex] =
Moles of [tex]Ag_3PO_4[/tex] × Molar Mass of [tex]Ag_3PO_4[/tex]
= 0.001495 moles × 418.58 g/mol = 0.62577 g
0.62577 grams of [tex]Ag_3PO_4[/tex] is produced.
Discuss the shapes of s- orbitals, p-orbitals and d-orbitals.
The azimuthal quantum number (l) determines its orbital angular momentum and describes the shape of the orbital.
s-orbitals (for example 1s, 2s) are spherically symmetric around the nucleus of the atom.
p-orbitals are dumb-bell shaped. l = 0,1...n-1, when l = 1, that is p subshell.
d-orbitals are butterfly shaped.
if a and b are inversely proportional and the value of a becomes 3 times as big what happens to b
Answer: 3 times lesser
a and b are inversely proportional,
a ∝ (1/b)
or a = k/b where k =constant ,
if a is 3 times increased what happens to b ?
b is 3 times less.
Which of the following types of electromagnetic waves has a frequency greater than ultraviolet waves?
A) X rays
B) infrared waves
C) microwaves
D)visible light
Answer:
A) X-rays
Step-by-step explanation:
Ultraviolet rays have a frequency range of 10¹⁵ Hz to 10¹⁷ Hz.
X-rays have a frequency range of 10¹⁷ Hz to 10²⁰ Hz, so they have a higher frequency than UV waves.
B) is wrong. The frequency range of infrared light is 10¹³ Hz to 4 × 10¹⁴ Hz.
C) is wrong. The frequency range of microwaves is 3 ×10¹¹ Hz to 10¹³ Hz.
D) is wrong. The frequency range of microwaves is 4 ×10¹⁴ Hz to 7.5 × 10¹⁴ Hz.
The X-rays has a frequency greater than ultraviolet waves.
• The range of all the kinds of electromagnetic radiation is known as the electromagnetic spectrum.
• The types of the electromagnetic waves, which makes up the electromagnetic spectrum are the visible light, microwaves, infrared light, UV rays, X-rays, and gamma rays.
• The energy of the waves is directly proportional to its frequency and inversely proportional to their wavelengths.
• The radiowaves exhibits the photons with least energies, followed by microwaves, infrared rays, visible, UV rays, X-rays, and the most energetic of all the waves is the gamma rays.
• The wavelengths of the UV rays is smaller than infrared waves, microwaves, and visible light, however, it is greater than X-rays and gamma rays.
• Thus, the frequencies of UV rays is more than the infrared waves, microwaves, and visible light, but is lesser than the frequencies of X-rays and gamma rays.
Thus, of the mentioned options, X-rays will possess greater frequency than UV rays.
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2 H2 + O2 → 2 H2O What is the product of this chemical reaction
The product of the chemical reaction 2 H₂ + O₂ → 2 H₂O is water (H₂O), which is a result of two moles of hydrogen reacting with one mole of oxygen.
Explanation:The product of the chemical reaction 2 H₂ + O₂ → 2 H₂O is water (H₂O). This represents a composition reaction where two molecules of hydrogen gas (H₂) react with one molecule of oxygen gas (O₂) to produce two molecules of water (H₂O). A key point to remember is that balanced chemical equations reflect not only the molecular count but also the molar amounts of the substances involved. Hence, we can say that two moles of hydrogen react with one mole of oxygen to yield two moles of water.
Abdid is an astronomer who has been observing objects that orbit the sun in the Astro belt . He finds a previously undiscovered round rocky object that is not similar in shape to the rest of the asteroids what has abdid most likely found
Since it is round, and in the asteroid belt, he has most likely found a Dwarf planet. This is because it is round, so it might be round because of it's gravity.
Answer:
A. a new dwarf planet
Explanation:
what is happening with the valence electrons of two atoms in a covalent bond?
A pair of oxygen atoms can form an O2 molecule in which each atom has a total of eight valence electrons by sharing two pairs of electrons. The term covalent bond is used to describe the bonds in compounds that result from the sharing of one or more pairs of electrons.
What air moves horizontally or parallel to the ground?
Wind, air that moves to the ground
Two 20.0-g ice cubes at –15.0 °C are placed into 265 g of water at 25.0 °C. Assuming no energy is transferred to or from the surroundings, calculate the final temperature, Tf, of the water after all the ice melts. heat capacity of h20(s) is 37.7j/kmol. heat capacity of h20(l) is 75.3j/kmol. enthalpy of fusion of h20 is 6.01j/kmol.
Answer:
10.3 °C
Step-by-step explanation:
This is an isolated system so
heat gained by ice + heat lost by water = 0
Heat to warm ice + heat to melt ice + heat to warm melt + heat lost by water = 0
q₁ + q₂ + q₃ + q₄ = 0
n₁C₁ΔT₁ + n₁ΔH_fus + n₁C₃ΔT₃ + n₄C₃ΔT₄ = 0
Step 1: Calculate q₁
n₁ = 40.0 g × 1/18.02
n₁ = 2.220 mol
C₁ = 37.7 J·K⁻¹mol⁻¹
ΔT₁ = T_f – T_i
ΔT₁ = 0.0 – (-15)
ΔT₁ = 15 °C = 15 K
q₁ = 2.220 × 37.7 × 15
q₁ = 1255 J
q₁ = 1.255 kJ
===============
Step 2. Calculate q₂
ΔH_fus = 6.01 kJ·mol⁻¹
q₂ = 2.220 × 6.01
q₂ = 13.34 kJ
===============
Step 3: Calculate q₃
C₃ = 75.3 J·K⁻¹mol⁻¹
ΔT₃ = T_f – T_i = x – 0 °C
ΔT₃ = x °C = x K
q₃ = 2.220 × 75.3 × x
q₃ = 167x J
q₃ = 0.167x kJ
===============
Step 4. Calculate q₄
n₄ = 265 × 1/18.02
n₄ = 14.71 mol
ΔT₄ = T_f – T_i = x – 25.0 °C
q₄ = 14.71 × 75.3 × (x – 25.0)
q₄ = 1107 × (x – 25.0)
q₄ = 1107x – 27 680 J
q₄ = 1.107x – 27.68 kJ
===============
Step 5. Solve for x
1.255 + 13.34 + 0.167x + 1.107x - 27.68 = 0
1.274x - 13.08 = 0
1.274x = 13.08
x = 13.08/1.274
x = 10.3 °C
The final temperature is -10.3 °C.
What does graphite contain that is similar to metals
which of the following is mixture backi g soda or carbon or honey or orange juice
Answer:
Honey
Explanation:
Backing soda:
Backing soda is a compound that is made up of only one kind of salt called NaHCO3 or sodium hydrogen carbonate. All the molecules of NaHCO3 are identical and we know that a mixture is something made up of two or more than two kinds of things, therefore baking soda cannot be referred to as mixture.
Carbon:
Carbon is not a mixture because its just an element that composed diffreent compounds by reacting with different other elements. In its oure form carbon is not a mixture, but if it is combined with some other substance it can form mixture.
Orange juice:
It depends on what kind of orange juice we are talking about. If we are talking about pure orange juice that is made from fresh oranges,then no - it cannot be called as mixture. However, if sugars,flavors and other preservatives are added like those available in market then it can be a mixture.
Honey:
Honey is a mixture of at-least 181 types of components in which most of all are sugars. These components mix through complex process and give the honey its specific sugary taste. You can see some of the constituent components of honey in attached figure.
Hope it help!
A child is male because he has one X chromosome and one Y chromosome where did these chromosomes come from
it would come from your mom and dad
Structural formulas are like models because they show _[blank]_.
Which answer best completes this statement?
a condensed way of writing a compound
how elements arrange within a compound
how electrons arrange within a compound
the three-dimensional shape of a compound
The correct option is:
how elements arrange within a compound
Structural formula are like models because they show how elements arrange within a compound.
1) What is the mole ratio of D to A in the generic chemical reaction? (2 points) Page 390 helps with understanding mole ratios. Be sure you’re only looking at the ratio of D to A. You can ignore B & C. 2A+ B C + 3D
Answer:- The mole ratio of D to A is 3:2.
Explanations:- Mole ratio for a chemical equation is the ratio of the coefficients of the molecules. Coefficients are the numbers used to balance the chemical equations.
For the given generic chemical equation, the coefficient of molecule A is 2 and the coefficient of D is 3. It means 2 molecules of A react with 3 molecules of D. So, the mole ratio of A to D is 2:3.
Since, we are asked about the mole ratio of D to A so we will write the coefficient of D first and hence the mole ratio of D to A is 3:2.