Final answer:
To compare the heights of Peter and Paul, we convert their heights to the same unit. Peter is taller with a height of 71 inches compared to Paul's height of approximately 69.29 inches.
Explanation:
In order to compare the heights of Peter and Paul, we need to convert their heights to the same unit. Peter's height is given in feet and inches, so we need to convert it to inches. Since there are 12 inches in a foot, Peter's height is 5 ft * 12 inches/ft + 11 inches = 60 inches + 11 inches = 71 inches.
Now we can compare Peter's height of 71 inches with Paul's height of 176 cm. In order to convert centimeters to inches, we need to know that 1 inch is approximately equal to 2.54 centimeters. So, Paul's height is 176 cm * 1 inch/2.54 cm = 69.29 inches (approximately).
Comparing the heights, we can see that Peter is taller with a height of 71 inches compared to Paul's height of approximately 69.29 inches.
The following chemical reaction takes place in aqueous solution: 2FeBr3 (aq) + 3Na2S (aq) → Fe2S3 (s) + 6NaBr (aq) Write the net ionic equation for this reaction.
In the reaction given, the net ionic equation is derived by removing the spectator ions, resulting in the net ionic equation: 2Fe3+ (aq) + 3S2- (aq) → Fe2S3 (s).
Explanation:The net ionic equation is derived by eliminating the spectator ions from the total ionic equation. The first step is to break all the strong electrolytes into their ions. In the reaction 2FeBr3 (aq) + 3Na2S (aq) → Fe2S3 (s) + 6NaBr (aq), we have the following ions:
2Fe3+ (aq) + 6Br- (aq)6Na+ (aq) + 3S2- (aq)These combine to form Fe2S3 (s) and 6Na+ (aq) + 6Br- (aq). The ions that appear on both sides of the equation are the spectator ions (Na+ and Br-), and we can remove them to get the net ionic equation:
2Fe3+ (aq) + 3S2- (aq) → Fe2S3 (s)
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Retry: 1.Examine Record A. Use the three basic rules to figure out the ages of the layers. In Chart A, list the layers from youngest to oldest with the youngest layer in the first row.
Answer:
C, E, H, A, B, F, K, D, L, G, J, I.
Explanation:
Hello,
In this case we are dating each layer based on its deepness as the deeper the layer is, the farther back in time it is (older). In such a way, the youngest layer is C and henceforth by going down, we find older and older layers no matter if the layer is horizontal or diagonal, we just go down by straight line, therefore, from youngest to oldest, the order turn out into:
C, E, H, A, B, F, K, D, L, G, J, I.
Best regards.
Which statement is true according to the quantum model of the atom?
Which of the following is a branch of chemistry? biology microbiology all of the above none of the above biophysics
You have a stock solution of 15.8 m nh3. how many milliliters of this solution should you dilute to make 1000.0 ml of 0.250 m nh3?
Which laws can be combined to form the ideal gas law?
A. Boyle’s law and Charles’s law
B. Gay-Lussac’s law and Avogadro’s law
C. Charles’s law, Avogadro’s law, and Boyle’s law
D. Dalton’s law, Gay-Lussac’s law, and Avogadro’s law
Answer:
Charles's law, Avogadro's law and Boyle's law.
Explanation:
I think
How many grams of chlorine gas must react to give 3.52g of BiCl3 according to the equation in exercise 23?
2Bi+3Cl2---->2BiCl3
The correct answer is 1.19 g of chlorine.
The following reaction is:
2Bi (s) + 3Cl₂ (g) ⇒ 2BiCl₃ (s)
In the reaction, it can be witnessed that 3 mol Cl₂ is equal to 2 mol BiCl₃
The molecular weight of BiCl₃ = 315.33
Thus,
3.52 g BiCl₃ = 3.52 g BiCl₃ × 1.00 mol BiCl₃ / 315.33 g BiCl₃
= 0.0112 mol BiCl₃
The mole ratio of Cl₂ and BiCl₃ is,
3 mol Cl₂ / 2 mol BiCl₃
Therefore, the amount of chlorine needed to form 0.0112 mol BiCl₃ is,
0.0112 mol BiCl₃ × 3 mol Cl₂ / 2 mol BiCl₃ = 0.0168 mol Cl₂
Now, the molecular weight of Cl₂ = 70.90
Thus,
0.0168 mol Cl₂ = 0.0168 mol Cl₂ × 70.90 g Cl₂ / 1.00 mol Cl₂
= 1.19 gm Cl₂
Hence, in the mentioned reaction, there is a need of 1.19 g of chlorine to react to produce 3.52 g of BiCl₃.
The diagram shows the movement of particles from one end of the container to the opposite end of the container.
Which event is most likely occurring?
diffusion because particles move from regions of high concentration to regions of low concentration
diffusion because particles move from regions of low concentration to regions of high concentration
effusion because there is a movement of a gas through a small opening into a larger volume
effusion because there is a movement of a gas through a large opening into a smaller volume
Problem 5.32 - enhanced - with feedback the rolling resistance for steel on steel is quite low; the coefficient of rolling friction is typically μr=0.002. suppose a 180,000 kg locomotive is rolling at 22 m/s on level rails. you may want to review ( pages 138 - 142) . part a if the engineer disengages the engine, how much time will it take the locomotive to coast to a stop?
The frictional force can be calculate as:
Ff = μr * N
where μr is the frictional constant while N is the normal force which is also equivalent to weight, hence:
Ff = 0.002 * 180,000 kg * 9.81 m/s^2
Ff = 3,531.6 N
The frictional force is also equivalent to the product of mass and acceleration, so we can find a:
Ff = m * a
a = 3,531.6 N / 180,000 kg
a = 0.01962 m/s^2 (in negative direction)
We can solve for time using the formula:
v = vi + a t
where v is final velocity = 0, vi is initial velocity = 22 m/s, t is time
0 = 22 - 0.01962 * t
t = 1,121.3 seconds
A sample of br2(g) takes 48.0 min to effuse through a membrane. how long would it take the same number of moles of ar(g) to effuse through the same membrane?
Using Graham's law of effusion, it can be calculated that it would take 24.0 minutes for the same number of moles of Argon gas to effuse through the same membrane as compared to Bromine gas.
Explanation:The question is asking how long it would take for an equal amount of argon gas to effuse compared to bromine gas. This is related to Graham's law of effusion, which says that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.
Thus, in accordance with this law, the effusion rate of a gas is given by the formula: Rate = √(M2/M1), where M1 and M2 are the molar masses of the two gases involved. For Argon (Ar) and Bromine (Br2), their molar masses are 39.95 g/mol and approximately 159.8 g/mol respectively. Plugging these values into Graham's equation, the rate at which Argon effuses as compared to Bromine would be √(159.8 g/mol / 39.95 g/mol) = √(4) = 2. Given that Bromine takes 48.0 minutes to effuse, Argon, effusing at twice the rate, would take half the time - 48.0 minutes / 2 = 24.0 minutes to effuse through the same membrane.Learn more about Graham's Law of Effusion here:https://brainly.com/question/34146005
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A container filled with gas is connected to an open-end manometer that is filled with mineral oil. the pressure in the gas container is 753 mm hg and atmospheric pressure is 724 mm. how high will the level rise in the manometer if the densities of hg and mineral oil are 13.6 g/ml and 0.822 g/ml respectively?
To calculate the height mineral oil will rise in a manometer to balance a pressure difference of 29 mm Hg, we use the ratio of densities between mercury and mineral oil. The mineral oil level will rise approximately 479.82 mm to balance the pressure difference.
To find out how high the level will rise in the manometer when it is filled with mineral oil instead of mercury, we must first understand the relationship between pressure, height, and density in a manometer. Given that the pressure of the gas is 753 mm Hg and atmospheric pressure is 724 mm Hg, the pressure difference that the mineral oil needs to balance is the pressure of the gas minus the atmospheric pressure (753 mm Hg - 724 mm Hg = 29 mm Hg).
Since mercury has a density of 13.6 g/ml, the same pressure difference can be formulated in terms of the mineral oil by using the following ratio:
Pressure difference in terms of mercury (mm Hg) = Pressure difference in terms of mineral oil (height in mm) * (Density of mineral oil / Density of mercury)
Substituting the given density values:
29 mm Hg = height in mm × (0.822 g/ml / 13.6 g/ml)
height in mm = 29 mm Hg / (0.822 g/ml / 13.6 g/ml)
height in mm = 29 mm Hg × (13.6 g/ml / 0.822 g/ml)
height in mm = 29 mm Hg × (13.6 / 0.822)
height in mm = 29 mm Hg × 16.5455
height in mm = 479.82 mm
The level of mineral oil in the manometer will rise approximately 479.82 mm to balance the pressure difference.
To find the height mineral oil will rise in the manometer, calculate the pressure difference between the gas and atmosphere, convert it to mercury's equivalent, and then find the corresponding height in mineral oil based on its density. The mineral oil level will rise approximately 479.8 mm in the manometer.
The student is asking about the rise in mineral oil level in an open-end manometer connected to a gas container when the pressure inside the container and the atmospheric pressure are known. To find the height that the mineral oil would rise in the manometer, we need to equalize the pressures exerted by the mineral oil and mercury (Hg), given that the mercury pressure is 753 mmHg and the atmospheric pressure is 724 mmHg.
First, we calculate the pressure difference the gas is exerting over atmospheric pressure:
Pressure difference = Pressure of gas - Atmospheric pressurePressure difference = 753 mmHg - 724 mmHgPressure difference = 29 mmHgNext, we convert this pressure difference to the equivalent height of mineral oil, using the densities provided:
Height in mineral oil = (Pressure difference in mmHg * Density of Hg) / Density of mineral oilHeight in mineral oil = (29 mmHg * 13.6 g/ml) / 0.822 g/mlHeight in mineral oil = (394.4 g/ml) / 0.822 g/mlHeight in mineral oil = 479.8 mmSo, the mineral oil level will rise approximately 479.8 mm in the open-end manometer.
What is the molecular formula of a compound with the empirical formula C13H19O2 and molar mass of 414.64 g?
The molecular formula of a compound with the empirical formula C13H19O2 and molar mass of 414.64 g/mol is C26H38O4.
Explanation:To find the molecular formula of a compound with the empirical formula C13H19O2 and a molar mass of 414.64 g/mol, we first need to calculate the empirical formula mass. The empirical formula mass of C13H19O2 is (13 × 12.01 g/mol for carbon) + (19 × 1.01 g/mol for hydrogen) + (2 × 16.00 g/mol for oxygen), which equals 205.32 g/mol. Then, we divide the given molar mass by the empirical formula mass to determine how many times the empirical formula fits into the molar mass.
414.64 g/mol ÷ 205.32 g/mol ≈ 2
Since the result is approximately 2, we multiply the subscripts in the empirical formula by 2 to obtain the molecular formula, resulting in C26H38O4 as the molecular formula of the compound.
Charcoal is primarily carbon. what mass of co2 is produced if you burn enough carbon (in the form of charcoal) to produce 4.60kj×102kj of heat? the balanced chemical equation is as follows:c(s)+o2(g)→co2(g),δh∘rxn=−393.5kj
The combustion of carbon in forms like charcoal to release a specific amount of heat, based on the chemical reaction and heat change, allows us to calculate the resulting mass of carbon dioxide. To produce 4.60x102 kJ heat, approximately 51.4 g of carbon dioxide would be generated.
Explanation:In the provided chemical reaction, C(s) + O₂(g) CO₂(g), with the heat change (ΔH°) being -393.5 kJ, we interpret that the combustion of one mole of carbon (charcoal form) releases 393.5 kJ of heat. We know that the heat release comes from the formation of carbon dioxide (CO2). So, for 4.60x102 kJ, the moles of CO2 produced can be calculated by using the ratio rule for mole and energy. So, the number of moles of CO2 produced = 4.60x102 kJ * (1 mole CO2/-393.5kJ) = 1.17 moles. The
mass of CO2
is the number of moles * molecular weight of CO2 = 1.17 mol * 44 g/mol = 51.4 g. Hence, the combustion of sufficient carbon (charcoal form) to produce 4.60x102 kJ of heat generates 51.4 g of carbon dioxide.
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A sample of a chromium-containing alloy weighing 3.450 g was dissolved in acid, and all the chromium in the sample was oxidized to 2cro42–. it was then found that 3.18 g of na2so3 was required to reduce the 2cro42– to cro2– in a basic solution, with the so32– being oxidized to so42–. write a balanced equation for the reaction of 2cro42– with so32- in a basic solution.
The balanced equation for the reaction of chromate ion (CrO4^2-) with sulfite ion (SO3^2-) in a basic solution where the sulfite is oxidized to sulfate and the chromate is reduced to chromite is 3SO3^2-(aq) + 2CrO4^2-(aq) + 2OH^-(aq) → 3SO4^2-(aq) + 2CrO2^-(aq) + H2O(l).
Explanation:The question asks for a balanced chemical reaction between chromate ion (CrO42-) and sulfite ion (SO32-) in basic solution. To balance this redox reaction, we must consider both the oxidation and reduction half-reactions and ensure that the number of electrons lost in oxidation equals the number gained in reduction, also making sure to balance other elements and charges, particularly in a basic solution.
In the basic solution, hydroxide ions (OH-) will participate in the balancing process. The sulfite ion (SO32-) is oxidized to sulfate ion (SO42-), and the chromate ion (CrO42-) is reduced to chromite ion (CrO2-).
The balanced equation for the reaction is:
3SO32-(aq) + 2CrO42-(aq) + 2OH-(aq) → 3SO42-(aq) + 2CrO2-(aq) + H2O(l).
Solid potassium hydroxide koh decomposes into gaseous water and solid potassium oxide . write a balanced chemical equation for this reaction.
Answer:
2KOH(s) ---> K2O(s) + H2O(g)
Explanation:
potassium hydroxide = KOH
water = H2O
potassium oxide = K2O
since KOH decomposes into H2O and K2O there is an arrow after KOH then after that you balance it. Without doing anything, KOH ----> H2O + K2O on the left side of the arrow there is only one K, one O, and one H atoms while on the other side there are 2 H, 2O, and 2K which means we have to put the two in front of the KOH. so then you will have 2K, 2O, 2H on the left-handed side which will equal the number of atoms there are on the right-handed side.
Also dont forget to put whether it is g, s, or aq.
In the instructions it tells you which one is s , g, or aq.
The balanced chemical equation for the decomposition of solid potassium hydroxide (KOH) into solid potassium oxide (K2O) and gaseous water (H2O) is: 4 KOH(s) → 2 K2O(s) + 2 H2O(g).
Explanation:The balanced chemical equation for the decomposition of solid potassium hydroxide (KOH) into gaseous water (H2O) and solid potassium oxide (K2O) is:
4 KOH(s) → 2 K2O(s) + 2 H2O(g)
This reaction showcases the breakdown of potassium hydroxide into simpler substances when it decomposes. Notice that the total number of atoms for each element is conserved on both sides of the equation, fulfilling the Law of Conservation of Mass.
Each degree on the Kelvin scale equals:
1°C
10°C
no relationship (different scale)
100°C
Answer is: 1°C.
A change of 1 Kelvin is the same as a change of 1 degree Celsius.
The temperature T in degrees Celsius (°C) is equal to the temperature T in Kelvin (K) minus 273,15: T(°C) = T(K) - 273.15.
For example:
T(He) = 4,2 K.
T(He) = 4,2 K - 273,15.
T(He) = -268,95°C.
The Celsius scale was based on 0°C for the freezing point of water and 100°C for the boiling point of water at 1 atm pressure.
If 78.5 mol of an ideal gas occupies 40.5 l at 83.00 °c, what is the pressure of the gas?
Write orbital diagrams (boxes with arrows in them) to represent the electron configurations of carbon before and after sp hybridization.
The electron configuration of carbon atom in its ground state is 1s² 2s² 2p². After sp hybridization, one 2s electron gets excited to the 2p orbital forming four unpaired electrons ready for bonding. These form two sp hybrid orbitals, leaving the remaining two 2p orbitals with single electrons.
Explanation:The electron configuration for a carbon atom (C) in its ground state is 1s² 2s² 2p², represented by an orbital diagram with two arrows in the 1s box, two in the 2s, and two single arrows in two of the three 2p boxes, indicating paired and unpaired electrons respectively.
During sp hybridization, one of the 2s electrons gets excited and moves to the 2p orbital, leading to four unpaired electrons ready for bonding. These mix to form two sp orbitals. In the electron configuration diagram, the two sp hybrid orbitals would have a single electron each, leaving the remain two 2p orbitals also with single electrons. Remember, these are depicted as boxes, each with a single upward arrow.
The distinction between the carbon atom's electron configurations before and after sp hybridization is essential in understanding its bonding behaviour and the formation of diverse organic compounds.
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Identify the statement that correctly describes light and how it travels? (2 points)
Select one:
a. Light waves can travel in a vacuum and travel at a constant speed even if the light source is moving.
b. Light waves can travel in a vacuum and will travel faster if the light source is moving forward.
c. Light waves need a medium to travel, and they travel faster if the light source is moving forward.
d. Light waves need a medium to travel, and they travel at the same speed even if the light source is moving.
When a soda is poured into a glass and the soda bubbles, is it the result of a chemical change? explain your answer?
Which forces involve nonpolar molecules?
hydrogen bonds and London dispersion forces
London dispersion forces and dipole-induced dipole forces
dipole-dipole forces and hydrogen bonds
dipole-induced dipole forces and dipole-dipole forces
The most common cooling mechanism for cloud formation is ________.
Classify these atomic orbitals as sp, or d according to their shape.
s and p orbitals do not have sp or d designations, while d orbitals are classified as d based on their shape and angular momentum quantum number. sp orbitals are formed by hybridization and are not based solely on the shape of individual atomic orbitals.
Atomic orbitals are regions in space where electrons are likely to be found around an atomic nucleus. They have specific shapes associated with their quantum numbers, which describe their size, shape, and orientation. The classification of atomic orbitals as sp or d depends on their shape and the angular momentum quantum number, l.
s Orbitals: These are spherical in shape and have l = 0. They are associated with the azimuthal quantum number (angular momentum) and are not divided into subshells. In terms of classification, s orbitals are not denoted as sp or d.
p Orbitals: These are -shaped and come in sets of three, oriented along the x, y, and z axes. They have l = 1. P orbitals are not denoted as sp or d; they are simply labeled as px, py, and pz.
d Orbitals: These have complex, multi-lobed shapes with five different orientations. They have l = 2 and are further divided into subshells, which can be labeled as dxy, dxz, dyz, dx²-y², and dz².
sp Orbitals: These are hybrid orbitals formed by mixing one s orbital and one p orbital. They have a linear shape and are typically found in molecules with sp hybridization, such as linear molecules like BeH2 or CO2.
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Find the total number of atoms in a sample of cocaine hydrochloride, c17h22clno4, of mass 20.5 mg .
Final answer:
The total number of atoms in a 20.5 mg sample of cocaine hydrochloride (C17H22ClNO4) is approximately 1.83 × [tex]10^2^1[/tex] atoms, calculated by determining the number of moles in the sample first and then using Avogadro's number to find the number of molecules and atoms.
Explanation:
To find the total number of atoms in a 20.5 mg sample of cocaine hydrochloride (C17H22ClNO4), you first need to calculate the number of moles in the sample and then use Avogadro's number to convert it to the number of molecules, and finally multiply by the total atoms in one molecule of the compound.
First, calculate the molar mass of cocaine hydrochloride:
C (12.01 g/mol) × 17 + H (1.01 g/mol) × 22 + Cl (35.45 g/mol) × 1 + N (14.01 g/mol) × 1 + O (16.00 g/mol) × 4 = 303.36 g/mol
Next, determine the number of moles in the 20.5 mg sample:
20.5 mg × (1 g / 1000 mg) / 303.36 g/mol = 6.76 × [tex]10^-^5[/tex] moles
Now, utilizing Avogadro's number (6.02 × 10^23 molecules/mol), calculate the number of molecules in the sample:
6.76 × 10^-5 moles × 6.02 × 10^23 molecules/mol = 4.07 × [tex]10^1^9[/tex] molecules
Since each molecule of cocaine hydrochloride contains 45 atoms (17 C + 22 H + 1 Cl + 1 N + 4 O), multiply the number of molecules by the number of atoms per molecule:
4.07 × [tex]10^1^9[/tex] molecules × 45 atoms/molecule = 1.83 × [tex]10^2^1[/tex] atoms
Therefore, a 20.5 mg sample of cocaine hydrochloride contains approximately 1.83 × [tex]10^2^1[/tex] atoms.
G oil of wintergreen, c8h8o3 is prepared when methanol, ch3oh, is reacted with salicylic acid, c7h6o3. what is the percent yield of a reaction in which 15.3 g of oil of wintergreen is collected after 16.3 g salicylic acid is reacted with an excess of methanol? ch3oh + c7h6o3 c8h8o3 + h2o
One mole or 138 g of salicylic acid produces one mole or 152 g of wintergreen oil. Thus, theoretically 16.3 g of the acid will produce 17.9 g of oil but only 15.3 g is produced. Therefore, the percent yield of the reaction is 85.4 %.
What is percent yield?Percent yield of a reaction is the ratio of the actual yield to the theoretical yield of the product in a reaction multiplied by 100.
Molar mass of salicylic acid = 138 g/mol
Molar mass of winter green oil = 153=2 g/mol
one mole of salicylic acid produces one mole of oil. Thus, mass of oil produced from 16.3 g of acid = (16.3 × 152 )/ 138 = 17.9g
Thus, theoretical yield = 17.9 g.
Actual yield = 15.3 g
Percent yield = actual / theoretical yield × 100
= 15.3 /17.9 × 100 = 85.4 %.
Therefore, the percent yield of the reaction is 85.4%.
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The per cent yield of the reaction to produce oil of wintergreen from salicylic acid and methanol is approximately 93.87% given that 15.3 g of the product is collected and 16.3 g of the reactant is used.
The per cent yield of oil of wintergreen (methyl salicylate) reaction can be calculated using the formula: per cent yield = (actual yield / theoretical yield) imes 100%. To find the theoretical yield, we would first need the balanced chemical equation for the reaction, which is CH₃OH + C₇H₆O₃------>C₈H₈O₃ + H₂O. Given that 16.3 g of salicylic acid is reacted, we assume a 100% conversion based on the stoichiometry of the reaction, which yields 16.3 g of oil of wintergreen. Therefore, the per cent yield (15.3 g actual / 16.3 g theoretical) imes 100%, which equals approximately 93.87%.
If 32.0 g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?
After heating, approximately 15.65 g of anhydrous magnesium sulfate will remain from the original 32.0 g of magnesium sulfate heptahydrate.
Identify the Molar Masses:
Molar mass of MgSO₄ = 24.31 (Mg) + 32.07 (S) + 4 × 16.00 (O) = 120.37 g/molMolar mass of 7H₂O = 7 × 18.02 (H₂O) = 126.14 g/molTherefore, the molar mass of MgSO₄·7H₂O = 120.37 g/mol + 126.14 g/mol = 246.51 g/molCalculate the Moles of MgSO₄·7H₂O:
Moles of MgSO₄·7H₂O =Determine the Moles of Anhydrous MgSO₄:
Upon heating, all the water is removed, leaving anhydrous MgSO₄.The moles of anhydrous MgSO₄ are equal to the moles of MgSO₄·7H₂O because heating just removes water.Calculate the Mass of Anhydrous MgSO₄:
Mass of MgSO₄ = Moles × Molar MassThe light emitted by an incandescent element produces:
~a unique continuous spectrum
~an emission line spectrum
~a spectrum identical to the hydrogen atom
~a spectrum of one unique wavelength
Answer: an emission line spectrum
Explanation: An emission line spectrum is produced form the light emitted by the incandescent lamp.
Line Spectrum is produced when the electron that has been excited to the higher energy state levels moves between the molecular energy levels while returning to the ground state.
Incandescent lamp is the lam that generates electricity when electrical current runs through it.
What are the benefits of stationary weather collection
What is the process that changes the composition of rocks by dissolving them called?
Arrange the following in order of increasing boiling point: RbF, CO2, CH3OH, CH3Br. Explain your reasoning.
We can arrange the given compound in order of increasing boiling point as CO2 <CH3Br <CH3OH <RbF.
The compound with the highest boiling point is RbF, since it has the strongest intermolecular force.
CH3OH, CH3Br can doesn't posses strong intermolecular force compare to RbF, and they can form hydrogen bond.
CO2 can form weak dispersion force and it's a non polar compound and it posses the boiling point.
What is boiling point?This is the temperature at whereby the vapor pressure of a liquid equals the pressure.
At this temperature, the liquid changes into a vapor and the weaker the force of attraction the lower the boiling point.
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