Payton wrote a 4-page paper in 5 hours. How long would it take for her to write a 7-page paper?

Answers

Answer 1

Answer:

8.75 hours

Step-by-step explanation:

We can use ratios to solve.  Put the pages over the time and set them equal.

4 pages       7 pages

------------- = ---------------

5 hours        x hours

Using cross products

4 * x = 5 *7

4x =35

Divide by 4 on each side

4x/4 = 35/4

x =8.75 hours


Related Questions

Reflection Lines
A reflection line is equidistant from a pre-image point and its image.


Therefore, in segment AA’, point M is the

Answers

Answer:

Midpoint

Step-by-step explanation:

Equidistant from the pre = image AA would be the middle

Answer:

Mid Point, thats all there is, its the answer, just that

Step-by-step explanation:

Find the arc length of the partial circle

Answers

Answer:

7pi/2

Step-by-step explanation:

If was a full, the circumference or the arc length would be 2pi*r where r in this case is 7 so it would be 14pi.

Now this only a quarter of that, so this arc length is actually 14pi/4.

This can be reduced 14pi/4 =7pi/2

Answer:

3.5pi

Step-by-step explanation:

KA


Based on the graph below, how would you describe the curve?

A. The curve is a 'one-to-one' function

B. The curve is a linear function

c. The curve is not a function

D. The curve is a 'many-to-one" function

Answers

D. is the correct answer

Hopes this helps

Mrs. Culland is finding the center of a circle whose equation
is x2 + y2 + 6x + 4y - 3 = 0 by completing the square. Her
work is shown.
x2 + y2 + 6x + 4y – 3 = 0
x2 + 6x + y2 + 4y - 3 = 0
(x2 + 6x) + (y2 + 4y) = 3
(x2 + 6x + 9) + (x2 + 4y + 4) = 3 + 9 + 4

Answers

Answer:

The center of the circle is (-3,-2)

Step-by-step explanation:

we know that

The equation of a circle in standard form is equal to

[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]

where

(h,k) is the center

r is the radius

In this problem we have

[tex]x^{2} +y^{2}+6x+4y-3=0[/tex]

Completing the square

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex](x^{2}+6x) +(y^{2}+4y)=3[/tex]

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

[tex](x^{2}+6x+9) +(y^{2}+4y+4)=3+9+4[/tex]

[tex](x^{2}+6x+9) +(y^{2}+4y+4)=16[/tex]

Rewrite as perfect squares

[tex](x+3)^{2} +(y+2)^{2}=16[/tex]

therefore

The center of the circle is (-3,-2)

Answer: ITS D !! ON EDGE

Step-by-step explanation:

A roller coaster can take 162 passengers around the track in 9
minutes. The roller coaster operates at a constant rate.
How many passengers can the roller coaster take around the track per minute?

Answers

Answer: 18 people per minute

Step-by-step explanation: 162 divide by 9 equals 18

To find the answer, divide 162 by 9, since you divide 9 by 9 to get 1 minute.

162/9=18

The roller coaster takes 18 passengers around the track per minute.

Hope this helps!

Sienna has $8 and is saving $3 per week. Jacob has $6 and is saving $4 per week. Which model represents the equatio
that can determine when Sienna will have the same amount of money as Jacob?​

Answers

Let the amount saving by Sienna and Jacob be x

Sienna has $8 and is saving $3 per week

So the equation will be 3x + 8

Jacob has $6 and is saving $4 per week

So the equation will be 4x + 6

Sienna will have same amount as Jacob, so

3x + 8 = 4x + 6

So the model two will represents the equation that Sienna will have same amount as Jacob.

Answer:

Model B

Step-by-step explanation:

Model B correctly displays sienna's and jacob's equations.

For sienna, the $8 can be represented as 8 unit blocks, which is displayed in model 2. The $3 per week can be represented as 3 x tiles, as shown in the picture, because it represents how many weeks.

For jacob, the model shows 6 unit blocks which represents his 6 dollars. The $4 per week is represented with the 4 x tiles, and we use x tiles because we are calculating how many weeks.

The given graph represents the function f(x) = 2(5)
How will the appearance of the graph change if the a
value in the function is decreased, but rerrains greater
than 0?
The graph will increase at a slower rate.
The graph will show a decreasing, rather than
increasing, function.
The graph will show an initial value that is lower on
the y-axis
The graph will increase at a constant additive rate,
rather than a multiplicative rate.
What’s the awnser

Answers

The answer is I’m
Not sure but like 5

Answer:

It's C on e2020

Step-by-step explanation:

what is the sum of 12x^2+3x+6 and -7x^2-4x-2

Answers

Answer: [tex]5x^2-x+4[/tex]

 

Step-by-step explanation:

In addition of polynomials, you only have to add the like terms.

Remember the multiplication of signs:

[tex](+)(+)=+\\(-)(-)=+\\(-)(+)=-[/tex]

Then, given the polynomial [tex]12x^2+3x+6[/tex] and the polynomial [tex]-7x^2-4x-2[/tex], you can find the sum of them by adding the like terms.

Observe the procedure below:

[tex](12x^2+3x+6)+(-7x^2-4x-2)=12x^2+3x+6-7x^2-4x-2=5x^2-x+4[/tex]

Therefore, the sum is:

[tex]5x^2-x+4[/tex]

 

45+45-6+122/5+92-35*9+12-10/2+19-25?

Answers

Answer:-568/5

Step-by-step explanation:

Answer:

-568/5 is the answer

Yesterday, a factory used 2/3 of a tub of peanut butter. They use 1/6 of a tub of peanut butter for each batch of peanut butter cookies. How many batches of peanut butter cookies did the factory make yesterday?​

Answers

The number of batches is 4.

What is the unitary method?

When a problem arises if 4 is required for 2 of these things then how many things does 20 require?

We use the unitary method to solve the problem where we find how much is required for one thing and then multiply it by the required.

Solving the given problem.

1/6 tub of peanut butter is used for one batch of cookies.

2/3 of it was used for the whole day.

So to find the total number of batches we divide the total tub used by the amount of tub used for one batch of cookies hence = 2/3/(1/6) = 4

Hence the answer to the given problem is 4.

Learn more about the Unitary method here

https://brainly.com/question/19423643

#SPJ2

For f(x) = 2x+1 and g(x)=x^2-7, find (f*g)(x).

Answers

Answer:

[tex](f*g) (x) =2x^3-13x^2-7 [/tex]

Step-by-step explanation:

We have the following functions

[tex]f (x) = 2x+1[/tex]

[tex]g (x) = x^2-7[/tex]

To find [tex](f*g)(x)[/tex] we must multiply the function f (x) with the function g (x)

Then we perform the following operation

[tex](f*g) (x) =(2x+1)(x^2-7)[/tex]

Apply the distributive property

[tex](f*g) (x) =2x^3-14x^2+x^2-7 [/tex]

[tex](f*g) (x) =2x^3-13x^2-7 [/tex]

Finally we have that:

[tex](f*g) (x) =2x^3-13x^2-7 [/tex]

What is the other solution?

Answers

Answer:

-6

Step-by-step explanation:

m^2 - 36 = 0

Add 36 to each side

m^2 -36+36 = 0+36

m^2 = 36

Take the square root of each side

sqrt( m^2) = ± sqrt(36)

m = ±6

We know one root is 6

The other root is -6

Paula Pruitt invested $4,334 in the stock market. The investment has declined 7% in value. Determine the worth of the investment now

Answers

Answer:

(4334/100)*93 = $ 4,030.62

Step-by-step explanation:

N/A

which equation is in quadratic form?

a)4(x-2)^2+3x-2+1=0

b)8x^5+4x^3+1=0

c)10x^8+7x^4+1=0

d)9x^16+6x^4+1=0

Answers

The answerrrrrrrrrrr is a

If you apply the below transformations to the square root parent function,
F(x) = VX, what is the equation of the new function?
• Shift 12 units right.
• Shift seven units down.

Answers

Answer:

We have the following function: [tex]f(x) =\sqrt{x}[/tex]

We know that given a function f(x), the function g(x) = f(x+m) is exactly the same function f(x) but shifted m units to the left.

Therefore, to shift the function 12 units right we should:

[tex]f(x) =\sqrt{x}[/tex] ⇒ [tex]f(x-12) =\sqrt{x-12}[/tex]

We know that given a function f(x), the function g(x) = f(x)+m is exactly the same function f(x) but shifted m units up.

Therefore, to shift seven units down we should:

[tex]f(x) =\sqrt{x}[/tex] ⇒ [tex]f(x) =\sqrt{x}-7[/tex]

write the equation of the line that passes through the points (7,-4) and (-1,3), first in point slope form​

Answers

The given line that passes through the points (7,-4) and (-1,3).

The slope is

[tex]m = \frac{3 - - 4}{ - 1 - 7} = - \frac{7}{8} [/tex]

The point-slope form is obtained using:

[tex]y-y_1= m (x-x_1) [/tex]

When (7,-4) is used the point-slope form is

[tex]y + 4= - \frac{7}{8} (x - 7) [/tex]

We expand now to get;

[tex]y = - \frac{7}{8}x + \frac{49}{8} - 4[/tex]

This implies that,

[tex]y = - \frac{7}{8}x + \frac{17}{8}[/tex]

The difference of 2 numbers is 21 and the quotient of the equation is 4 then what are the two numbers?

Answers

Answer:

The two numbers are 28 and 7.

Step-by-step explanation:

Let the first number be x

Let the second number be y

The difference of x and y is x-y=21

The quotient of two numbers is x/y = 4

x-y =21    (This is equation 1)

x/y=4    (This is equation 2)  

By solving equation 2 we will get the value of x.

x/y=4

x=4y (Lets call it equation 3)

Now, put the value of x(equation 3) in (equation 1)

x-y=21

4y-y=21

3y=21

y=21/3

y=7

Now put the value of y in equation 3 to get the value of x

x=4y

x=4(7)

x=28

Solution Set {(x,y)(28,7)}

Answer:

28 and 7

Step-by-step explanation:

Let ​ f(x)=x2+4x+12 ​ . What is the vertex form of f(x)? What is the minimum value of f(x)?

Answers

[tex]\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ f(x)=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+4}x\stackrel{\stackrel{c}{\downarrow }}{+12} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{4}{2(1)}~~,~~12-\cfrac{4^2}{4(1)} \right)\implies (-2~~,~~12-4)\implies (-2~,~8)[/tex]

well, the quadratic has a leading term with a positive coefficient, meaning is a parabola opening upwards, like a "bowl", comes from above down down down, reaches a U-turn, namely the vertex, and goes back up up up.

so the minimum value is at the vertex of course, and the minumum is well, just the y-coordinate of the vertex, 8.

find the quotient 16 2/3 ÷ 5 5/7​

Answers

Answer:

2 11/12

Step-by-step explanation:

(50/3)/(40/7)

=50/3*7/40

=5/3*7/4

=35/12

=2 11/12

let's convert firstly, the mixed fractions to improper fractions and then divide.

[tex]\bf \stackrel{mixed}{16\frac{2}{3}}\implies \cfrac{16\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{50}{3}}~\hfill \stackrel{mixed}{5\frac{5}{7}}\implies \cfrac{5\cdot 7+5}{7}\implies \stackrel{improper}{\cfrac{40}{7}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{50}{3}\div\cfrac{40}{7}\implies \cfrac{\stackrel{5}{\begin{matrix} 50 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}}{3}\cdot \cfrac{7}{\underset{4}{\begin{matrix} 40 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}}\implies \cfrac{35}{12}\implies 2\frac{11}{12}[/tex]

Please explain how this function behaves when it approaches the given x values!

Answers

Answer and Step-by-step explanation:

This is a piecewise function because it is defined by more than two functions. Basically, we want to take the limit here. Recall that if a function [tex]f(x)[/tex]  approaches some value [tex]L[/tex]  as [tex]x[/tex]  approaches [tex]a[/tex]  from both the right and the left, then the limit of [tex]f(x)[/tex] exists and equals  [tex]L[/tex]. Here we won't calculate the limit, but apply some concepts of it. So:

a. [tex]as \ x \rightarrow +\infty, \ k(x) \rightarrow +\infty[/tex]

Move on the x-axis from the left to the right and you realize that as x increases y also increases without bound.

b. [tex]as \ x \rightarrow -\infty, \ k(x) \rightarrow 0[/tex]

Move on the x-axis from the right to the left and you realize that as x decreases to negative values y approaches zero.

c. [tex]as \ x \rightarrow 2, \ k(x) \rightarrow 0[/tex]

Since the function is continuous here, we can say that [tex]k(2)=0[/tex]

d. [tex]as \ x \rightarrow -2, \ k(x) \rightarrow 0[/tex]

The function is discontinuous here, but [tex]k(-2)[/tex] exists and equals 0 as the black hole indicates at [tex]x=-2[/tex].

e. [tex]as \ x \rightarrow -4, \ k(x) \rightarrow 2[/tex]

The function is also discontinuous here, but the black hole indicates that this exists at [tex]x=-4[/tex], so [tex]k(-4)=2[/tex]

f. [tex]as \ x \rightarrow 0, \ k(x) \rightarrow 4[/tex]

Since the function is continuous here, we can say that [tex]k(0)=4[/tex]

Find the missing factor.
4b2 + 17b + 15 = (b + 3)(
)

Answers

Answer:

(4b + 5)

Step-by-step explanation:

To get 4b^2 you already have b^2 if you put b  inside the second set of brackets. But that would mean you don't have 4 anywhere to get 4b^2.

So the first step has to be

(b + 3)(4b

Now look at the 15 for a moment. It is plus 15. The only way you can get a plus 15 is if both signs are plus (after the b terms) or both terms are minus.

The middle term (17b) is plus so both terms after b are plus.

(b + 3)(4b +

Now we need something that multiplies to 15. 3*5 = 15. So the term you want is 5.

(b + 3)(4b + 5)

Does the middle term work?

5*b + 3*4b = 5b + 12b = 17b

Everything looks fine.

The second factor is 17b.

(25 points) Can someone please solve this I just need to see how its solved to understand

Answers

x = total amount of students in 8th Grade.

we know only one-thrid of the class went, so (1/3)x or x/3 went.

we also know 5 coaches went too, and that the total amount of that is 41.

[tex]\bf \stackrel{\textit{one third of all students}}{\cfrac{1}{3}x}+\stackrel{\textit{coaches}}{5}=\stackrel{\textit{total}}{41}\implies \cfrac{x}{3}+5=41\implies \cfrac{x}{3}=41-5 \\\\\\ \cfrac{x}{3}=36\implies x=3(36)\implies x=108[/tex]

now, to verify, well, what do you get for (108/3) + 5?

Question 101 points)
Which equation in slope-intercept form represents the line that passes through (5, 1) and
(-4,7)


Answers

Answer:

[tex]\large\boxed{y=-\dfrac{2}{3}x+\dfrac{13}{3}}[/tex]

Step-by-step explanation:

[tex]\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-slope\\b-y-intercept\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\===============================[/tex]

[tex]\text{We have the point:}\\\\(5,\ 1)\ \text{and}\ (-4,\ 7).\ \text{Substitute:}\\\\m=\dfrac{7-1}{-4-5}=\dfrac{6}{-9}=-\dfrac{6:3}{9:3}=-\dfrac{2}{3}\\\\\text{We have the equation in form:}\\\\y=-\dfrac{2}{3}x+b\\\\\text{Put the coordinates of the point (5, 1) to the equation:}\\\\1=-\dfrac{2}{3}(5)+b\\\\1=-\dfrac{10}{3}+b\qquad\text{add}\ \dfrac{10}{3}\ \text{to the both sides}\\\\\dfrac{3}{3}+\dfrac{10}{3}=b\to b=\dfrac{13}{3}\\\\\text{Finally:}\\\\y=-\dfrac{2}{3}x+\dfrac{13}{3}[/tex]

Please answer this question in the picture!
Ignore the writing over it and the answer! It’s probably wrong.

Answers

Answer:

c [tex]113\:m[/tex]

Step-by-step explanation:

[tex]113,391 = 4\frac{9}{10}[2\frac{1}{10}]^{2} + 135 \\ \\ 113 ≈ h[/tex]

I am joyous to assist you anytime.

Factoring Trinomials (
Factor each completely.
1) 3p² – 2p - 5

Answers

3p^2 - 2p - 5
3p^2 -5p+3p-5 (5 times 3 equals 15)
p(3p-5) +1(3p-5)
Answer:
(3p - 5)(p + 1)

Answer:

factors (3p - 5) and (p + 1)

Step-by-step explanation:

The quadratic formula always "works" when you're looking to factor a quadratic expression or equation.  Here, the coefficients are a = 3, b = -2 and c = -5.  The discriminant is thus b²-4ac, which here is (-2)²-4(3)(-5), or 4+60, or 64.  Because this discriminant is positive, we know that the quadratic has two real, unequal roots.  These roots are:

        -(-2)±√64          2 ± 8

p = ------------------- = --------------- = 10/6 and -1, or 5/3 and -1.

           2(3)                      6

These roots correspond to the factors (3p - 5) and (p + 1).

How can △WXY be mapped to △MNQ?

First, translate vertex w to vertex M. Next, reflect △WXY across the line containing

1) line segment WX
2) line segment WY
3) line segment XY
4) line segment MQ

Answers

Answer:

A: Line Segment WX

Step-by-step explanation:

100% on edge 2020

Answer:

WX is correct

Step-by-step explanation:

Got a 100 in edge quiz.

To the nearest hundredth of a centimeter, what is the length of the hypotenuse?
[1] cm
92.58 cm

Answers

Answer:

106.90 cm

Step-by-step explanation:

Given

Angle=30 degrees

Base=92.58 cm

So,

We will have to use the triangular ratios to find the hypotenuse.

The triangular ratio that will be used for this will be cosine because we know the value of angle and base since it involves both cosine will be used.

cos⁡θ=Base/Hypotense

cos⁡30=92.58/Hypotenuse

0.8660=92.58/Hypotenuse

Hypotenuse=92.58/0.8660

=106.90 cm ..

Answer:

Hypotenuse = 107.02

Step-by-step explanation:

Points to remember

If angles of a triangle are 30°, 60° and 90° then the sides are  in the ratio

1 : √3 : 2

It is given a right angled  triangle with angles 30°, 60°, 90°

and height = 95.58 cm

To find the hypotenuse

From the figure we can write,

Base : Height : Hypotenuse = 1 : √3 : 2 = Base : 92.58 : Hypotenuse

Therefore Hypotenuse = (92.58 * 2)/√3

  = 107.02 cm

Martha is training for a duathlon, which includes biking and running. She knows that yesterday she covered a total distance of over 55.5 miles in more than than 4.5 hours of training. Martha runs at a speed of 6 mph and bikes at a rate of 15.5 mph.

Answers

Answer:

Distance: 6x + 15.5y > 55.5

Time: x + y > 4.5

Step-by-step explanation:

We are given that Martha is training for a duathlon and she covered a total distance of over 55.5 miles in more than than 4.5 hours of training.

Also, she runs at a speed of 6 mph and bikes at a rate of 15.5 mph.

We are to write inequalities representing the distance she traveled and the total time she spent training.

Distance: 6x + 15.5y > 55.5

(formula for distance = speed x time so speeds for running and biking are multiplied by their number of hours)

Time: x + y > 4.5

(she trained for more than 4.5 hours, x hours for running and y hours for biking.

Ms. Cole has 4 yards of string. She cuts the string into pieces that are each 1/2 yard long. How many pieces of string does Ms. Cole have?

Answers

Answer:

8

Step-by-step explanation:

got it right

Answer:

8

Step-by-step explanation:

got it right in Ed

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
A(n) = -6 + (1 - 1)(1)

Answers

Answer:

-6

Step-by-step explanation:

A(n)=-6+(1-1)(1)

simplified, this equals:

A(n) = -6+(0)(1)

A(n)=-6+0

A(n) = -6, for any given n term.

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