Orange juice, a raisin bagel, and a cup of coffee from kelly's koffee kart cost a total of $2.40. Kelly posts a notice announcing that, effective the following week, the price of orange juice will increase 50% and the price of bagels will increase 20%. After the increase, the same purchase will cost a total of $3.00, and the orange juice will cost twice as much as coffee. find the price of each.
A. What was the cost of a glass of orange juice before the increase?
B. what was the cost of a raisin bagel before the increase?
C. what was the cost of a cup of coffee before the increase?

To maximize the area of the Norman window, solve for the dimensions of the rectangle. Substitute the expression for 'h' in terms of 'w' into the area formula. Take the derivative of A with respect to 'w', set it equal to zero, and solve for 'w'.

To maximize the area of the Norman window, we need to find the dimensions of the rectangle. Let's denote the width of the rectangle as 'w' and the height as 'h'. The perimeter of the rectangle can be expressed as 2w + h + πh = 24 feet. Rearranging the equation, we have (2 + π)h + 2w = 24. Since we want to maximize the area, we can solve for 'h' in terms of 'w' using this equation.

Next, we can substitute the expression for 'h' in terms of 'w' into the area formula for the window, which is A = wh + (π/4)w^2. Simplifying this expression, we get A = (w(2 + πw))/4. To find the dimensions that maximize the area, we can take the derivative of A with respect to 'w', set it equal to zero, and solve for 'w'. This will give us the width of the rectangle. Once we have the width, we can substitute it back into the equation for 'h' to find the height.

By solving these equations, we can find the dimensions of the rectangle that will maximize the area of the Norman window, allowing in as much light as possible.

The money after 10 years is $ 13591.4091

Solution:

Given that,

If you have a bank account that is modeled by the following equation:

[tex]A = 5000e^{0.10t}[/tex]

To find: Money after 10 years

How much money would you have after 10 years

Substitute t = 10 in above given equation

[tex]A = 5000 \times e^{0.10 \times 10}\\\\A = 5000 \times e^{1}\\\\A = 5000 \times 2.71828\\\\A = 13591.4091[/tex]

Thus money after 10 years is $ 13591.4091

The statement "Every elementary row operation is​ reversible" is true because interchanging can be reversed by​ scaling, and scaling can be reversed by replacement (Option A is correct).

The statement "Every elementary row operation is​ reversible" is true.

The correct choice is: A. True, because interchanging can be reversed by​ scaling, and scaling can be reversed by replacement.

- Interchanging rows (row swapping) can be reversed by another interchange.

- Scaling a row by a non-zero scalar can be reversed by scaling it by the reciprocal of that scalar.

- Replacement operations (adding or subtracting multiples of one row from another) can also be reversed by adding or subtracting the same multiples in the opposite direction.

So, all three elementary row operations (replacement, interchanging, and scaling) are reversible, which makes option A the correct choice.

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The statement 'Every elementary row operation is reversible' is true. All the three types of elementary row operations, i.e., scaling, interchanging, and replacement, can be reversed using appropriate methods.

The statement 'Every elementary row operation is reversible' is indeed true. The three types of elementary row operations, i.e., scaling, interchanging, and replacement, are all reversible. Scaling can be reversed by multiplying the row by the reciprocal of the scale factor. Interchanging rows can be undone by simply interchanging them again. Replacement can be reversed by applying a replacement operation with the opposite sign.

For example, if you multiply a row by a factor of 3 (scaling), you can reverse this by multiplying the row by 1/3. If you interchange row 1 and row 2, you can reverse this by interchanging these two rows again. Finally, if you replaced row 1 by adding 2*row 2 to it, you could reverse this by replacing row 1 by subtracting the same 2*row 2 from it.

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This is an incomplete question, here is a complete question.

A hurricane wind blows across a 7.00 m × 12.0 m flat roof at a speed of 150 km/h.

What is the pressure difference Δp = p(inside)-p(outside)? Use 1.28 kg/m³ for the density of air. Treat the air as an ideal fluid obeying Bernoulli's equation.

Answer : The pressure difference will be, [tex]1.11\times 10^3Pa[/tex]

Step-by-step explanation :

As we are given:

Speed = 150 km/h = 41.66 m/s

Density = [tex]\rho=1.28kg/m^3[/tex]

Area = A = 7.00 m × 12.0 m

Formula used :

[tex]\Delta P=\frac{1}{2}\times \rho \times v^2[/tex]

Now put all the given values in this formula, we get:

[tex]\Delta P=\frac{1}{2}\times (1.28kg/m^3)\times (41.66m/s)^2[/tex]

[tex]\Delta P=1.11\times 10^3Pa[/tex]

Thus, the pressure difference will be, [tex]1.11\times 10^3Pa[/tex]

Answer:

x=42

Step-by-step explanation:

x-12=30

x=30+12

x=42

To solve for x in this equation, we want to get x by itself on the left side of the equation. Since 12 is being subtracted from x, to get x by itself, we need to add 12 to the left side of the equation. If we add 12 to the left side, we must also add 12 to the right side.

On the left side, -12 and +12 cancel each other out so we are simply left with x. On the right side, 30 + 12 is 42 so we have x = 42.

It's important to understand that we can check our answer by substituting 42 back into the original equation.

So we have (42) - 12 = 30.

42 - 12 is 30 so we have 30 = 30 which is a true statement so our answer, x = 42, is correct.

Answer:

$774

Step-by-step explanation:

We have been given that from January to June, a company spent $60 per month on office supplies. In July the price of office supplies increased by 15% and remained the same for the rest of the year.

Let us find increased cost of supplies as shown below:

[tex]\text{Increased cost of supplies}=60+\frac{15}{100}\times 60[/tex]

[tex]\text{Increased cost of supplies}=60+0.15\times 60[/tex]

[tex]\text{Increased cost of supplies}=60+9[/tex]

[tex]\text{Increased cost of supplies}=69[/tex]

There are 6 months from January to June, so cost of supplies on these 6 months would be 6 times $60.

There are 6 months from July to December, so cost of these months would be 6 times $69.

Total cost will be equal to sum of these two amounts.

[tex]\text{Amount spent on office supply in the year}=6\times \$60+6\times \$69[/tex]

[tex]\text{Amount spent on office supply in the year}=6( \$60+\$69)[/tex]

[tex]\text{Amount spent on office supply in the year}=6( \$129)[/tex]

[tex]\text{Amount spent on office supply in the year}=\$774[/tex]

Therefore, $774 were spent on office supplies.

Answer:

x = 0 , y = 0 , z = -3

Step-by-step explanation:

Solve the following system:

{x - 6 y + 4 z = -12 | (equation 1)

x + y - 4 z = 12 | (equation 2)

2 x + 2 y + 5 z = -15 | (equation 3)

Swap equation 1 with equation 3:

{2 x + 2 y + 5 z = -15 | (equation 1)

x + y - 4 z = 12 | (equation 2)

x - 6 y + 4 z = -12 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - (13 z)/2 = 39/2 | (equation 2)

x - 6 y + 4 z = -12 | (equation 3)

Multiply equation 2 by 2/13:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - z = 3 | (equation 2)

x - 6 y + 4 z = -12 | (equation 3)

Subtract 1/2 × (equation 1) from equation 3:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - z = 3 | (equation 2)

0 x - 7 y + (3 z)/2 = -9/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - z = 3 | (equation 2)

0 x - 14 y + 3 z = -9 | (equation 3)

Swap equation 2 with equation 3:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x - 14 y + 3 z = -9 | (equation 2)

0 x+0 y - z = 3 | (equation 3)

Multiply equation 3 by -1:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x - 14 y + 3 z = -9 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 3 × (equation 3) from equation 2:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x - 14 y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 2 by -14:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{2 x + 0 y+5 z = -15 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 5 × (equation 3) from equation 1:

{2 x+0 y+0 z = 0 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 0 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Collect results:

Answer: {x = 0 , y = 0 , z = -3

To solve the given system of equations, use the method of elimination to eliminate one variable at a time and solve for the remaining variables.

To solve the system of equations:

x - 6y + 4z = -12

x + y - 4z = 12

2x + 2y + 5z = -15

We can use the method of substitution or elimination. Let's use the method of elimination:

Therefore, the solution is x = -5, y = 4, and z = 1.

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Yo sup??

From Newton's 2nd law of motion

F*t=Δp

=mv-mu

mu=0.4*15

=6

t=0.2

mv=0

Therefore

F*0.2=6

F=30 N

Hope this helps.

Answer:

a.) 23

b.) y=14

c.) 23

d.) -23

e.) T=8

f.) f=1/8

Step-by-step explanation:

a.) general equation is Asin((2π/T))

A is the amplitude. It's A value is 23

b.)  Midline = vertical_shift = 14

c.) max = positive amplitude value = 23

d.) min = negative amplitude = -23

e.) Factor out 2π from your angular frequency to get the period.

ω = π/4 = (2π)/8 = (2π)/T

Period = 8

f.) Frequency is just the inverse of the period.

f = 1/T = 1/8

Answer:

True, the scores are not valid.

Step-by-step explanation:

The test supposed to be measuring intelligence. We can assume that the intelligence of most people relatively stable (will not change too much over a short amount of time), and can expect it should go upward with brain growth and education. But the test seems to give a huge decrease from the first and second results. Then the third result is a huge increase that even higher than the first test.  

We don't know the true value of the subject, but seeing the huge gap for every repetition we can tell that the test result lacks precision.

Answer:

1st it: g(2)=1/3(2)+1=0.67+1=1.67

2nd it: g^2(2)=1/3(1.67)+1=0.56+1=1.56

3rd it: g^3(2)=1/3(1.56)+1=0.52+1=1.52

Answer:

The first three iterations are 1.67, 1.56 and 1.52

Step-by-step explanation:

Given the function g(x)=1/3x+1

To get the first threw iteration with initial value of x = 2

First iteration at x= 2:

g(2) = 2/3+1

g(2) = (2+3)/3

g(2) = 5/3 = 1.67

Second iteration will be when x = g(2) = 5/3

g²(2) = g(5/3) = 1/3(5/3) + 1

g²(2) = g(5/3) = 5/9 + 1

g²(2) = g(5/3) = 14/9 = 1.56

Third iteration will be at when

x = g²(2) = 14/9

g³(2) = g(14/9) = 1/3(14/9) + 1

g³(2) = g(14/9) = 14/27 + 1

g³(2) = g(14/9) = 41/27 = 1.52

The first three iterations are 1.67, 1.56 and 1.52

Answer: 20 feet

Step-by-step explanation:

in the attachment

The ladder reaches approximately 19.8 feet up the side of the house, as determined using the Pythagorean theorem.

The question is asking us to find the height the ladder reaches up the side of the house. This is a problem dealing with right triangles and can be solved using the Pythagorean theorem, which is a^2 + b^2 = c^2, where 'a' and 'b' are the shorter sides (base and height of the house) and 'c' is the hypotenuse (the ladder).

In this case, the ladder is 24 feet long (this is our c), and the base of the ladder is 13 feet from the house (this is our a). We are trying to find b (the height of the house the ladder reaches).

Substitute these values into the Pythagorean theorem and solve for 'b':

13^2 + b^2 = 24^2
b^2 = 24^2 - 13^2
b = sqrt(24^2 - 13^2)

So, the height that the ladder reaches up the side of the house is approximately 19.8 feet.

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Answer:

  D. The second route, in 1.18 hours

Step-by-step explanation:

The appropriate relation is ...

  time = distance/speed

The time required on the first route is ...

  time1 = (40 mi)/(25 mi/h) = 40/25 h = 1.6 h

The time required on the second route is ...

  time2 = (65 mi)/(55 mi/h) = 65/55 h = 1 2/11 h ≈ 1.18 h

__

The second route requires a shorter time, so will get you there faster. The second route will get you there in 1.18 hours.

Answer: 6x^13-1.5w+156x+13 is the answer to the first equation and is that another equation?

The expression 13 - 0.5w + 6x evaluates to 11 when substituting w=10 and x=1/2.

The problem is to evaluate the expression 13 - 0.5w + 6x given the values w=10 and x=1/2. Following the order of operations, we first substitute the given values into the expression.

13 - 0.5(10) + 6(1/2) = 13 - 5 + 3 = 11.

The result of the evaluated expression is 11.

Answer:

A: -4,3 The x coordinate of the vertex is given by x = -b/2a and the y coordinate of the vertex is given by y= f( -b/2a), we need to transform the equation to the form ax^2 + bx + c We have: 5(x+4)^2+3 = 5x^2+ 20x + 23 Then we substitute x= -20/2*5 y= f(-20/2*5) = -4 = f(-4) =3 So V(-4,3)

Step-by-step explanation:

Answer:

I still dont get what the answer is

Step-by-step explanation:

See picture for solution and answer.

The probability that both the woman and her husband fail to get the correct brand of paint is 4/9.

To determine the probability that both the woman and her husband fail to get the correct brand of paint, we need to consider the probability of each event happening independently. Since the woman selects two brands at random out of the three available, the probability of her not getting the correct brand is 2/3. Similarly, the husband also selects two brands at random out of the three, so his probability of not getting the correct brand is also 2/3. Since the events are independent, we can multiply the probabilities together to get the probability that both fail to get the correct brand. Therefore, the probability is (2/3) * (2/3) = 4/9.

The husband's selections are independent of his wife's selections because each brand he chooses is not influenced by the brands his wife chooses. Regardless of what she selects, he still has three brands to choose from and selects two at random. This means that his probability of not getting the correct brand is the same regardless of his wife's choices.

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Answer:

a) Rate of brightness after t days = B(t) = 2.6 + 0.6sin(2×3.142 t /6.6)

b) 0.57

Step-by-step explanation:

Given

Number of days=6,6 days

Average brightness =2.6

B(t)= 2.6 + 0.6 sin (2× 3.142t/6.6)

b) B(1day) = 0.6 ×(2×3.142/6.6)cos (2×3.142/6.6)

B(1 day) = 0.6 × (6.248/6.6)cos 0.952

B(1 day) =0.6 × 0.952 ×0.9999

B(1day) = 0.5711

= 0.57

Answer:

The distance from P to origin is approximately 40.82 units.                                  

Step-by-step explanation:

We are given the following in the data:

The point P(21,35)

We have to find the distance of point P from the origin.

Coordinates of origin: (0,0)

Distance formula:

[tex](x_1,y_1),(x_2,y_2)\\\\d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]

Putting the values, we get,

[tex](21,35), (0,0)\\\\d = \sqrt{(0-21)^2 + (0-35)^2} = \sqrt{1666} = 7\sqrt{34} \approx 40.82\text{ units}[/tex]

The distance from P to origin is approximately 40.82 units.

Answer:

1. 1.76x10^13,

2. 3.20x10^8,

3. 5.5x10^4

Step-by-step explanation:

Answer:

Step-by-step explanation:

GDP/POPULATION

1755x10^13/3.2x10^8 = .05484x10^5

=5.484x10^4

= 5.49x10^4

Answer:

The number of small mowers are 19 and the large mowers are 11.

Step-by-step explanation:

Given:

A garden supply store sells two types of lawn mowers. Total sales of mowers for the year were $8379.70. The total number of mowers sold the 30. The small mower cost $249.99 and the large mower costs $329.99.

Now, to find the number of each type of mower sold.

Let the number of small mower be [tex]x.[/tex]

And the number of large mower be  [tex]y.[/tex]

So, total number of mowers are:

[tex]x+y=30[/tex]

[tex]x=30-y\ \ \ ....(1)[/tex]

Now, the total sales of mowers are:

[tex]249.99(x)+329.99(y)=8379.70[/tex]

Substituting the value of [tex]x[/tex] from equation (1) we get:

[tex]249.99(30-y)+329.99y=8379.70[/tex]

[tex]7499.7-249.99y+329.99y=8379.70[/tex]

[tex]7499.7+80y=8379.70[/tex]

Subtracting both sides by 7499.7 we get:

[tex]80y=880[/tex]

Dividing both sides by 80 we get:

[tex]y=11.[/tex]

The number of large mower = 11.

Now, to get the number of small mowers we substitute the value of [tex]y[/tex]  in equation ( 1 ):

[tex]x=30-y\\x=30-11\\x=19.[/tex]

The number of small mower = 19.

Therefore, the number of small mowers are 19 and the large mowers are 11.

Answer:

Total cost of the survey = $450

Step-by-step explanation:

Given:

Cost for each person = $1

Liked thin crust = 200 people

Liked thick crust = 270 people

Both crust like = 70 people

50 people did not like either type of crust.

We need to find the total cost of the survey.

Solution:

Number of people who like thin crust or thick crust.

⇒ 200 + 270 - 70

⇒ 470 - 70

⇒ 400

So, 400 people likes thin crust OR thick crust.

And, also 50 peoples did not likes either thin crust OR thick crust.

So, we add 50 people who did not like any type of pizza.

⇒ 400 + 50

Therefore, total cost of the survey = $450

Answer

7.5 pounds

Step-by-step explanation:

Since adding x grams of salt will bring th percentage of the salt to 25

Hence. 10% of the 50 gram gives. 5 gram initial salt before it is added.

5+ x/ 50 * 100= 25/

5+x /50 = 0.25

5+x = 12.5

X= 12.5- 5

X= 7.5pounds

Answer: The density of the paper clips is 0.64 g/ml.

Step-by-step explanation:

Given : Volume of water = 10.0 mL

mass of water =  25.0 g

After 51 clips added to water , the total mass = 28 g

Total volume = 14.7

Mass of clips =  total mass - mass of water

= 28 g-25g = 3g

Volume of clips = Total volume- Volume of water

= 14.7- 10.0 = 4.7 ml

Density of paper clips =[tex]\dfrac{\text{Mass of paper clips}}{\text{Volume of paper clips}}[/tex]

[tex]=\dfrac{3}{4.7}=0.638297\approx0.64\ g/ml[/tex]

Hence, the density of the paper clips is 0.64 g/ml.

Answer:

The density of the paper clips is 0.64 g/m

Step-by-step explanation:

hope this helps :)

P(A) =0.54

P(B)= 0.68

P'(A)= 1-0.54 = 0.46

P'(B)= 1- 0.68 = 0.32

The probability of neither of both event will occur:

= P'(A)×P'(B)

=0.46 × 0.32

=0.1472

Continuous compound is e^rate x time

The formula would be D. 1200e^0.04t

Answer:  OPTION D A = 1200.e(0.04)(t)

Step-by-step explanation:

If the interest is compounded continuously for t years at a rate of r per year, then the compounded amount is given by:

A = P. e rt

P =$1200, r = 4% , t = t years

A = 1200.e(0.04)(t)

Answer:

A) Be sure the task is understood.

Step-by-step explanation:

The principle "Make sure the mission is understood, performed, and achieved."

Another way we talk about this principle in the Navy is through the idea of "intrusive leadership." In some respects both "micromanagement" and "intrusive leadership" sound terrible.

Think about certain great managers and leaders you have had in your career yet again. Probability are they will be the ones who asked you those difficult questions, too.

They moved everyone to new technical levels, and eye for detail. When you said you knew what you were doing or when you announced the progress of a project, they didn't necessarily take it to face value.

Answer:

[tex]\frac{16}{21}=\frac{8}{10.5}[/tex]

or

[tex]\frac{16}{8}=\frac{21}{10.5}[/tex]

Step-by-step explanation:

we know that

If two figures are similar then the ratio of its corresponding sides is proportional

In this problem

triangle YPQ and triangle YXZ are similar by AA Similarity Theorem

so

[tex]\frac{YP}{YX}=\frac{YQ}{YZ}[/tex]

substitute the given values

[tex]\frac{16}{21}=\frac{8}{10.5}[/tex]

Rewrite

[tex]\frac{16}{8}=\frac{21}{10.5}[/tex]

The boxes should be filled with [tex]\frac{16}{21} = \frac{8}{10.5}\\\\\frac{16}{8} = \frac{21}{10.5}[/tex]

As we know that

In the case when two figures are similar so the ratio of its corresponding sides is proportional

In this given situation  

triangle YPQ and triangle YXZ are similar by AA Similarity Theorem

So,

[tex]\frac{YP}{YX} = \frac{YQ}{YZ}[/tex]

[tex]\frac{16}{21} = \frac{8}{10.5}\\\\\frac{16}{8} = \frac{21}{10.5}[/tex]

It can be any of the both.

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Answer:

Step-by-step explanation:

Please refer to the picture below